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  • Subtype polymorphism and arrays

    - by user133466
    Computer[] labComputers = new Computer[10]; with public class Computer { ... void toString(){ // print computer specs } } public class Notebook extends Computer{ ... void toString(){ // print computer specs + laptop color } } each subscripted variable labComputers[i] can reference either a Computer object or a Notebook object because Notebook is a subclass of Computer. For the method call labComputers[i].toString(), polymorphism ensures that the correct toString method is called. I wonder what if we do Notebook[] labComputers = new Notebook[10]; what kind or error would I get if I reference with Computer object and a Notebook object

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  • Scanner class is skipping lines

    - by user2403304
    I'm new to programing and I'm having a problem with my scanner class. This code is in a loop and when the loop comes around the second, third whatever time I have it set to it skips the first title input. I need help please why is it skipping my title scanner input in the beginning? System.out.println("Title:"); list[i].title=keyboard.nextLine(); System.out.println("Author:"); list[i].author=keyboard.nextLine(); System.out.println("Album:"); list[i].album=keyboard.nextLine(); System.out.println("Filename:"); list[i].filename=keyboard.nextLine();

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  • Interrupt a thread in DatagramSocket.receive

    - by SEK
    I'm building an application that listens on both TCP and UDP, and I've run into some trouble with my shutdown mechanism. When I call Thread.interrupt() on each of the listening threads, the TCP thread is interrupted from listening, whereas the UDP listener isn't. To be specific, the TCP thread uses Socket.accept(), which simply returns (without actually connecting). Whereas the UDP thread uses DatagramSocket.receive, and doesn't exit that method. Is this an issue in my JRE, my OS, or should I just switch to (Datagram)Socket.close()?

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  • Should i use lock.lock(): in this method?

    - by user962800
    I wrote this method whose purpose is to give notice of the fact that a thread is leaving a specific block of code A thread stands for a car which is leaving a bridge so other cars can traverse it . The bridge is accessible to a given number of cars (limited capacity) and it's one way only. public void getout(int diection){ // release the lock semaphore.release(); try{ lock.lock(); //access to shared data if(direction == Car.NORTH) nNordTraversing--; //decreasing traversing threads else nSudTraversing--; bridgeCond.signal(); }finally{ lock.unlock(); } } My question is: should I use lock.lock(); or it's just nonsense? thanks in advance

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  • Is this Leftist Tree piece of code from Wikipedia correct?

    - by they changed my name
    Link public Node merge(Node x, Node y) { if(x == null) return y; if(y == null) return x; // if this was a max height biased leftist tree, then the // next line would be: if(x.element < y.element) if(x.element.compareTo(y.element) > 0) { // x.element > y.element Node temp = x; x = y; y = temp; } x.rightChild = merge(x.rightChild, y); if(x.leftChild == null) { // left child doesn't exist, so move right child to the left side x.leftChild = x.rightChild; x.rightChild = null; x.s = 1; } else { // left child does exist, so compare s-values if(x.leftChild.s < x.rightChild.s) { Node temp = x.leftChild; x.leftChild = x.rightChild; x.rightChild = temp; } // since we know the right child has the lower s-value, we can just // add one to its s-value x.s = x.rightChild.s + 1; } return x; } What makes me ask this question is: if(x.element.compareTo(y.element) > 0) { // x.element > y.element Node temp = x; x = y; y = temp; } Isn't that just not gonna work, since the references are only switched inside the method?

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  • Eclipse and SVN: Missing .project file.

    - by DHC
    Hi, I'm working on a uni project with a few other people using SVN. Much to my annoyance the .project file was removed from the repository since "it contains platform specific information". However, this has obviously broken my setup in Eclipse, giving me the error: Problems occurred opening the selected resources. The project description file (.project) for '___' is missing. This file contains important information about the project. The project will not function properly until this file is restored. Any suggestions? Thank you.

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  • How To Delete objet whit mouse click ?

    - by Meko
    Hi all. I made a simple FlowChat Editor that creates rectangles and triangles and connect them each other and shows the way from up to down. I can move this elements on screen to .But I am tying to create button to delete element which I clicked. There is problem that I can delete mytriangle object but but I cant delete myRectangle objects.It deletes but not object which i clicked.I delete from first object to last ..Here my code ... if (deleteObj) { if (rectsList.size() != 0) { for (int i = 0; i < rectsList.size(); i++) { MyRect rect = (MyRect) rectsList.get(i); if (e.getX() <= rect.c.x + 50 && e.getX() >= rect.c.x - 50 && e.getY() <= rect.c.y + 15 && e.getY() >= rect.c.y - 15) { rectsList.remove(rect); System.out.println("This is REctangle DELETED\n"); } } } if (triangleList.size() != 0) { for (int j = 0; j < triangleList.size(); j++) { MyTriangle trian = (MyTriangle) triangleList.get(j); if (e.getX() <= trian.c.x + 20 && e.getX() >= trian.c.x - 20 && e.getY() <= trian.c.y + 20 && e.getY() >= trian.c.y - 20) { triangleList.remove(trian); System.out.println("This is Triangle Deleted\n"); } } }

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  • Creating Linear Layout with TextViews using a for loop

    - by cad8
    Hi all, I was wondering if there is a way to dynamically create an additional linear layout with a textview within a predefined liner layout. THis is my code so you get the gist of what I am asking: LinearLayout MainLL= (LinearLayout) findViewById(R.id.myLayoutId); for(int i=0; i<5; i++) { LinearLayout childLL= new LinearLayout(this); childLL.setOrientation(LinearLayout.VERTICAL); childLL.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT)); childLL.setGravity(Gravity.LEFT); TextView text = new TextView(this); text.setText("The Value of i is :"i); text.setTextSize(12); text.setGravity(Gravity.LEFT); text.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT)); childLL.addView(text); MainLL.addView(childLL); } My problem is that I am only getting "The Value of i is :0" as the output, i.e. the first instance. Any help would be much appreciated

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  • Associate activity with database ID

    - by Mohit Deshpande
    I have a main ListView that is based on an adapter from my database. Each database id is "assigned" to an Activity via the ListView. And in my AndroidManifest, each activity has an intent filter with a custom action. Now with this, I have had to create this class: public final class ActivityLauncher { private ActivityLauncher() { } public static void launch(Context c, int id) { switch(id) { case 1: Intent intent = new Intent(); intent.setAction(SomeActivity.ACTION_SOMEACTIVITY); c.startActivity(intent); break; case 2: ... break; ... } } private static void st(Context context, String action) { Intent intent = new Intent(); intent.setAction(action); context.startActivity(intent); } } So I have to manually create a new case for the switch statement. This would get troublesome if I have to rearrange or delete an id. Is there any way to get around this?

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  • How to get the next element of a SortedSet?

    - by Pentium10
    I have a SortedSet holding my ordered data. I use the .first() method to return the first record, and pass it to another window. When the other window finishes I get an event called, and I want to pass the next from the SortedSet to the window, so how to move to the next element? launchWindow(this.set.first()); Then I have this: onActivityResult(...) { if (this.set.hasNext()) launchWindow(this.set.next());//hasNext/next doesn't exists in the current context for SortedSet } What options I have?

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  • problem in jdbc preparestatement

    - by akshay
    i am geting error when i try to use following,why is it so? ResultSet findByUsername(String tablename,String field,String value) { pStmt = cn.prepareStatement("SELECT * FROM" + tablename +" WHERE ? = ? "); pStmt.setString(1, tablename); pStmt.setString(2,field); pStmt.setString(3,value); return(pStmt.executeQuery()); } also i tried following , but its not working too ResultSet findByUsername(String tablename,String field,String value) { String sqlQueryString = " SELECT * FROM " + tablename +" WHERE " + filed + "= ? ") cn.prepareStatement(sqlQuery); pStmt.setString(1, value); return(pStmt.executeQuery()); }

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  • Regular Expression Program

    - by david robers
    Hi I have the following text: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ This method takes a regex in out by the user and SHOULD print out the Strings it applies to but seems to print out something completely different: private void matchIt(String regex) { Pattern p = Pattern.compile(regex); Matcher m = null; boolean found = false; for(int i = 0; i < data.length; i++){ m = p.matcher(data[i]); if(m.find()){ out.println(data[i]); found = true; } } if(!found){ out.println("Pattern Not Found"); } } When inputting "[C]" It outputs: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ Any ideas why? I think I'm using m.find() improperly...

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  • What is the security risk of object reflection?

    - by Legend
    So after a few hours of workaround the limitation of Reflection being currently disabled on the Google App Engine, I was wondering if someone could help me understand why object reflection can be a threat. Is it because I can inspect the private variables of a class or are there any other deeper reasons?

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  • what is difference between JDK 1.4 and JDK1.6.

    - by Vipin Nemade
    hi friend, I have created the project using the JDK 1.4. Now I want to use JDK 1.6 version in my project. for this what steps are required.Means I want to know the what changes is require in code to get a JDK 1.6 feature.Basically I am talking about the features that is added in JDK 1.6. If any one list out that changes it is very helpful. Thanks in advance..............................

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  • Return the difference between the lowest and highest key

    - by stan
    This is a past exam paper i am attempting and have no way to check if the out put is correct as i am not capable of building one of these things the question is in the title class Tree{ Tree left; Tree right; int key; public static int span(Tree tree) { if ( tree == null ){ return null; } if( tree.left != null) int min = span(tree.left); } if( tree.right != null){ int max = span(tree.right); } return max - min; } } Could anyone suggest what i need to change to get 5/5 marks :D - the only thing we have to do is write the span method, the header was given for us Thanks

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  • NHibernate Native SQL multiple joins

    - by Chris
    Hi all, I"m having some problems with Nhibernate and native sql. I've got an entity with alot of collections and I am doing an SQL Fulltext search on it. So when returning 100 or so entities, I dont want all collections be lazy loaded. For this I changed my SQL query: SELECT Query.* FROM (SELECT {spr.*}, {adr.*}, {adrt.*}, {cty.*}, {com.*}, {comt.*}, spft.[Rank] AS [Rak], Row_number() OVER(ORDER BY spft.[Rank] DESC) AS rownum FROM customer spr INNER JOIN CONTAINSTABLE ( customerfulltext , computedfulltextindex , '" + parsedSearchTerm + @"' ) AS spft ON spr.customerid = spft.[Key] LEFT JOIN [Address] adr ON adr.customerid = spr.customerid INNER JOIN [AddressType] adrt ON adrt.addresstypeid = adr.addresstypeid INNER JOIN [City] cty ON cty.cityid = adr.cityid LEFT JOIN [Communication] com ON com.customerid = spr.customerid INNER JOIN [CommunicationType] comt ON comt.communicationtypeid = com.communicationtypeid) as Query ORDER BY Query.[Rank] DESC This is how I setup the query: var items = GetCurrentSession() .CreateSQLQuery(query) .AddEntity("spr", typeof(Customer)) .AddJoin("adr", "spr.addresses") .AddJoin("adrt", "adr.Type") .AddJoin("cty", "adr.City") .AddJoin("com", "spr.communicationItems") .AddJoin("comt", "com.Type") .List<Customer>(); What happens now is, that the query returns customers twice (or more), I assume this is because of the joins since for each customer address, communicationItem (e.g. phone, email), a new sql row is returned. In this case I thought I could use the DistinctRootEntityResultTransformer. var items = GetCurrentSession() .CreateSQLQuery(query) .AddEntity("spr", typeof(Customer)) .AddJoin("adr", "spr.addresses") .AddJoin("adrt", "adr.Type") .AddJoin("cty", "adr.City") .AddJoin("com", "spr.communicationItems") .AddJoin("comt", "com.Type") .SetResultTransformer(new DistinctRootEntityResultTransformer()) .List<Customer>(); Doing so an exception is thrown. This is because I try to list customers .List<Customer>() but the transformer returns only entities of the last join added. E.g. in the case above, the entity with alias "comt" is returned when doing .List() instead of .List(). If I would switch last join with the join alias "cty", then the transformer returns a list of cities only... Anyone knows how I can return a clean list of customers in this case?

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  • Finding the specific type held in an ArrayList<Object> (ie. Object = String, etc.)

    - by Christopher Griffith
    Say I have an ArrayList that I have cast to an ArrayList of objects. I know that all the objects that were in the ArrayList I cast were of the same type, but not what the type was. Now, if the ArrayList is not empty, I could take one of the objects in it and use the instanceof operator to learn what the actual type is. But what of the case where the ArrayList is empty? How do I determine what type Object actually is then? Is it possible?

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