When I include only the jQuery 1.4 Library, I get an exception, why?
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by codeninja
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Published on 2010-03-05T17:57:32Z
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2010/04/20
22:13 UTC
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I keep getting this error all over the place where I only have jquery 1.3 or 1.4 included.
"setting a property that has only a getter"
and a long list of warnings in the Firefox Error Console.
What's going on? I can't find any information on this issue =/
<!DOCTYPE HTML PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-US">
<head>
<title>Demo</title>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<link rel="shortcut icon" href="images/favicon.ico">
<link rel="stylesheet" href="css/common.css" type="text/css" />
<link rel="stylesheet" href="css/modules.css" type="text/css" />
<script type="text/javascript" src="js/jquery-1.4.2.min.js"></script>
</head>
Just some Warning snippets:
Warning: reference to undefined property a[++e]
Source File: /js/jquery-1.4.2.min.js
Line: 30
Warning: reference to undefined property a[0]
Source File: /js/jquery-1.4.2.min.js
Line: 30
Warning: function oa does not always return a value
Source File: /js/jquery-1.4.2.min.js Line: 18, Column: 165
Source Code: th;n<r;n++){j=d[n];a.currentTarget=j.elem;a.data=j.handleObj.data;a.handleObj=j.handleObj;if(j.handleObj.origHandler.apply(j.elem,e)===false){b=false;break}}return b}}function pa(a,b){return"live."+(a&&a!=="*"?a+".":"")+b.replace(/\./g,"`").replace(/ /g,
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