JavaScript: Is there a better way to retain your array but efficiently concat or replace items?

Posted by Michael Mikowski on Stack Overflow See other posts from Stack Overflow or by Michael Mikowski
Published on 2013-10-30T02:38:03Z Indexed on 2013/10/30 3:54 UTC
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I am looking for the best way to replace or add to elements of an array without deleting the original reference. Here is the set up:

var a = [], b = [], c, i, obj;
for ( i = 0; i < 100000; i++ ) { a[ i ] = i; b[ i ] = 10000 - i; }
obj.data_list = a;

Now we want to concatenate b INTO a without changing the reference to a, since it is used in obj.data_list. Here is one method:

for ( i = 0; i < b.length; i++ ) { a.push( b[ i ] ); }

This seems to be a somewhat terser and 8x (on V8) faster method:

a.splice.apply( a, [ a.length, 0 ].concat( b ) );

I have found this useful when iterating over an "in-place" array and don't want to touch the elements as I go (a good practice). I start a new array (let's call it keep_list) with the initial arguments and then add the elements I wish to retain. Finally I use this apply method to quickly replace the truncated array:

var keep_list = [ 0, 0 ];
for ( i = 0; i < a.length; i++ ){ 
  if ( some_condition ){ keep_list.push( a[ i ] );
}

// truncate array
a.length = 0;

// And replace contents
a.splice.apply( a, keep_list );

There are a few problems with this solution:

  • there is a max call stack size limit of around 50k on V8
  • I have not tested on other JS engines yet.
  • This solution is a bit cryptic

Has anyone found a better way?

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