How to manually check a YUI radio "button".
- by alex
<script type="text/javascript">
(function () {
var ButtonGroup = YAHOO.widget.ButtonGroup;
var onCheckedButtonChange = function (p_oEvent) {
};
YAHOO.util.Event.onContentReady("mediaFilterButtonsFieldset", function () {
var oButtonGroup = new ButtonGroup("mediaFilterButtons");
oButtonGroup.on("checkedButtonChange", onCheckedButtonChange);
});
}());
</script>
<div id="resultInfo">
<form id="button-example-form" name="button-example-form" method="post">
<fieldset id="mediaFilterButtonsFieldset">
<div id="mediaFilterButtons" class="yui-buttongroup ie7filter" style="z-index:11;">
<div id="mediaFilterLabel">Go to</div>
<input id="radio1" class="filter_but" type="radio" name="0" value="First" checked rel="0" >
<input id="radio2" class="filter_but" type="radio" name="2" value="Second" rel="2">
<input id="radio3" class="filter_but" type="radio" name="1" value="Third" rel="1">
</div>
</fieldset>
</form>
</div>
These are my YUI buttons. They're just 3 radio buttons turned into "buttons"--literally. My question is this:
After people click the third button, I cannot manually check the first button anymore. How can I manually check "radio1"?
I tried JQuery: $("#radio1").attr("checked",true); But this didn't work. The third button still remained pressed down.
