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  • Next and Previous MySQL row based on name

    - by NightMICU
    Hi everyone, I have a table with details on personnel. I would like to create a Next/Previous link based on the individual's last name. Since personnel were not added in alphabetical order, selecting the next or previous row based on its ID does not work. It is a hefty table - the pertinent fields are id, name_l, and name_f. I would like to order by name_l, the individuals' last name. How would I go about accomplishing this task? Thanks!

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  • Rails/mysql SUM distinct records - optimization

    - by pepernik
    Hey. How would you optimize this SQL SELECT SUM(tmp.cost) FROM ( SELECT DISTINCT clients.id as client, countries.credits_cost AS cost FROM countries INNER JOIN clients ON clients.country_id = countries.id INNER JOIN clients_groups ON clients_groups.client_id=clients.id WHERE clients_groups.group_id IN (1,2,3,4,5,6,7,8,9) GROUP BY clients.id ) AS tmp; I'm using this example as part of my Ruby on Rails project. Note that my nested SQL (tmp) can have more then 10 milion records. You can split that in more SQLs if the performance is better. Should I add any indexes to make it quicker (i have it on IDs)?

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  • Using a comma seperated data in MYSQL "IN" clause

    - by Sashi Kant
    I have a column in one of my table where I store multiple ids seperated by comma's. Is there a way in which I can use this column's value in the "IN" clause of a query. The column(city) has values like 6,7,8,16,21,2 I need to use as Select * from table where e_ID in (Select city from locations where e_Id=?) I am satisfied with Crozin's answer, but I am open to suggestions, views and options. Feel free to share your views.

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  • Creating a Mysql view to SELECT coloumns from different tables

    - by user330429
    I need help in constructing a VIEW on 4 tables. The view should contain coloumns: ER.ID, ER.EMPID, ER.CUSTID, ER.STATUS, ER.DATEREPORTED, ER.REPORT, EB.NAME, CR.CUSTNAME, CR.LOCID, CL.LOCNAME, DI.DEPTNAME ALIASES EMP_REPORT ER , EMP_BIO EB, CUST_RECORD CR, CUST_LOC CL, DEPT_ID DI THE DATA MODELS ARE: describe EMP_REPORT; +--------------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +--------------+-------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | empid | int(11) | NO | | NULL | | | custid | int(11) | NO | | NULL | | | status | varchar(32) | NO | | NULL | | | datereported | bigint(20) | NO | | NULL | | | report | text | YES | | NULL | | +--------------+-------------+------+-----+---------+----------------+ describe EMP_BIO; +--------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +--------+-------------+------+-----+---------+-------+ | empid | int(11) | NO | PRI | NULL | | | name | varchar(56) | NO | | NULL | | | sex | char(1) | NO | | NULL | | | deptid | int(11) | NO | | NULL | | | email | varchar(32) | NO | | NULL | | | mobile | bigint(20) | YES | | NULL | | | gtlk | varchar(32) | YES | | NULL | | | skype | varchar(32) | YES | | NULL | | | cvid | int(11) | YES | | NULL | | +--------+-------------+------+-----+---------+-------+ describe CUST_RECORD; +----------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +----------+--------------+------+-----+---------+----------------+ | custid | int(11) | NO | PRI | NULL | auto_increment | | custname | varchar(32) | NO | | NULL | | | address | varchar(255) | YES | | NULL | | | contactp | varchar(32) | YES | | NULL | | | mobile | bigint(20) | YES | | NULL | | | locid | int(11) | NO | | NULL | | | remarks | text | YES | | NULL | | | date | int(11) | YES | | NULL | | | addedby | int(11) | YES | | NULL | | +----------+--------------+------+-----+---------+----------------+ describe CUST_LOC; +---------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +---------+-------------+------+-----+---------+-------+ | locid | int(11) | NO | PRI | 0 | | | locname | varchar(32) | NO | | NULL | | +---------+-------------+------+-----+---------+-------+ describe DEPT_ID; +----------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +----------+-------------+------+-----+---------+-------+ | deptid | int(11) | NO | | NULL | | | deptname | varchar(32) | YES | | NULL | | +----------+-------------+------+-----+---------+-------+ The table EMP_REPORT contains reports submitted by employees, all the coloumns in it needs to be fetched. The empid in this table should be used to fetch corresponding name in EMP_BIO (employee biodata) table. The custid in EMP_REPORT should be used to fetch corresponding locid in CUST_RECORD(customer record) which is used to fetch locname in CUST_LOC(customer location) table. The empid in EMP_REPORT is used to fetch corresponding deptid in EMP_BIO table which is then used to fetch corresponding deptname from DEPT_ID(department id) table. I tried constructing view using union of different select queries, but dint get proper results. Please help me. Thanks in advance. PS: sorry for my poor english

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  • MySQL select two tables at the same time...

    - by Jerry
    Hi all I have two tables and want to make a query. I tried to get team AA and team BB's image base on table A. I used: SELECT tableA.team1, tableA.team2, tableB.team, tableB.image, FROM tableA LEFT JOIN tableB ON tableA.team1=tableB.team The result only display imageA on the column. Are there any ways to select imageA and image B without using the second query? I appreciate any helps! Thanks a lot! My table structure are: table A team1 team2 ------------ AA BB table B team image ------------- AA imagaA BB imageB

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  • Validate a date range within MySQL query

    - by fishcracker
    (This question may seem easy or kind of noobish, by that I pardon my ignorance.) I used PDO query to use SELECT then fetch some values, it comes to a point that I need to fetch only some entries that within its start date and end date. My database +----------+-----------------+----------------------+--------------------+ | id (INT) | title (VARCHAR) | start_date (VARCHAR) | end_date (VARCHAR) | +----------+-----------------+----------------------+--------------------+ | 1 | buddy | 2012-11-26 | 2012-11-30 | | 2 | metro | 2012-12-05 | 2012-12-20 | | 3 | justin | 2012-11-28 | 2012-12-01 | +----------+-----------------+----------------------+--------------------+ My query is as follows: $query = "SELECT title, start_date, end_date FROM debts WHERE start_date >= CURDATE() AND end_date >= CURDATE()"; What I want to achieve is whenever the start_date is today or greater but not exceeding the end_date it will be valid. This will return the row for id 1, however if I change the start_date to 2012-11-25, it will fail due to the first condition on AND. I'm really confuse on this since I am new to this, is there any built-in function to handle this kind of situation?

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  • How to return array of C++ objects from a PHP extension

    - by John Factorial
    I need to have my PHP extension return an array of objects, but I can't seem to figure out how to do this. I have a Graph object written in C++. Graph.getNodes() returns a std::map<int, Node*>. Here's the code I have currently: struct node_object { zend_object std; Node *node; }; zend_class_entry *node_ce; then PHP_METHOD(Graph, getNodes) { Graph *graph; GET_GRAPH(graph, obj) // a macro I wrote to populate graph node_object* n; zval* node_zval; if (obj == NULL) { RETURN_NULL(); } if (object_init_ex(node_zval, node_ce) != SUCCESS) { RETURN_NULL(); } std::map nodes = graph-getNodes(); array_init(return_value); for (std::map::iterator i = nodes.begin(); i != nodes.end(); ++i) { php_printf("X"); n = (node_object*) zend_object_store_get_object(node_zval TSRMLS_CC); n-node = i-second; add_index_zval(return_value, i-first, node_zval); } php_printf("]"); } When i run php -r '$g = new Graph(); $g->getNodes();' I get the output XX]Segmentation fault meaning the getNodes() function loops successfully through my 2-node list, returns, then segfaults. What am I doing wrong?

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  • MySQL: fetching a null or an empty string

    - by Oden
    Hey, I know whats the difference between a NULL value and an empty string ("") value, but if I want to get a value by using the OR keyword, I get no result for a NULL value The table i want to query looks like this: titles_and_tags +----+----------+------+ | id | title | tag | +----+----------+------+ | 1 | title1 | NULL | | 2 | title2 | tag1 | | 3 | title3 | tag2 | +----+----------+------+ The query i use looks like this: select * from `titles_and_tags` WHERE `title` LIKE "title" AND `tag` = "tag1" OR `tag` IS NULL So i want to get here a rows (id: 1,2), BUT this results 0 rows. What have i done wrong?

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  • Multiple OR Clauses in MySQL

    - by Grant
    I'm trying to grab content where id = 3 OR id = 9 OR id = 100... Keep in mind, I can have a few hundred of these ids. What is the most efficient way to write my query? $sql = "SELECT name FROM artists WHERE (id=3 OR id=9 OR .... id-100)"

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  • mysql query that has array

    - by Xainee Khan
    //get all id's of ur friend that has installed your application $friend_pics=$facebook->api( array( 'method' => 'fql.query', 'query' => "SELECT uid FROM user WHERE uid IN(SELECT uid2 from friend WHERE uid1='$user') AND is_app_user = 1" ) ); // this query work fine //your top10 friends in app $result="SELECT * FROM fb_user WHERE user_id IN($friend_pics) ORDER BY oldscore DESC LIMIT 0,10"; db_execute($result); i want to retrive ten top scorer from my database stored in oldscore but in my second query the array name $friend_pics is not working i guess,plz help me thanks

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  • Timeout on Large mySQL Query

    - by Bob Stewart
    I have this query: $theQuery = mysql_query("SELECT phrase, date from wordList WHERE group='nouns'"); while($getWords=mysql_fetch_array($theQuery)) { echo "$getWords[phrase] created on $getWords[date]<br>"; } The data table "wordList" contains 75,000 records in the group "nouns" and every time I load the code I am returned an error. Help!

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  • MySQL: selecting all but one field?

    - by gsquare567
    instead of SELECT * FROM mytable, i would like to select all fields EXCEPT one (namely, the 'serialized' field, which stores a serialized object). this is because i think that losing that field will speed up my query by a lot. however, i have so many fields and am quite the lazy guy. is there a way to say... `SELECT ALL_ROWS_EXCEPT(serialized) FROM mytable` ? thanks!

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  • connecting to phpMyAdmin database with PHP/MySQL

    - by user303955
    I've made a database using phpMyAdmin , now I want to make a register form for my site where peaple can register .I know how to work with input tags in HTML and I know how to insert data into a database but my problem is that I don't know how I can connect to the database that is already made in phpMyAdmin.

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  • mysql IF EXISTS

    - by cosy
    What is wrong with this ? mysql_query("IF EXISTS(SELECT * FROM y where 1=1 ) THEN do something ELSE do something END IF"); Thanks!

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  • PHP file outside doc root needs files outside and inside the document root

    - by jax
    I have a library of classes, all interrelated. Some files are inside the document root and some are outside using the <Directory> and Alias features in httpd.conf Assuming I have 3 files: webroot.php (Inside the document root) alias_directory.php (Inside a folder outside the doc root) alias_directory2.php (Inside a **different** folder outside the doc root) If alias_directory2.php needs both webroot.php and alias_directory.php, This does not work. (Remember alias_directory.php and alias_directory2.php are not in the same locations) require_once $_SERVER['DOCUMENT_ROOT'].'/webroot.php'; //(ok) require_once $_SERVER['DOCUMENT_ROOT'].'/alias_directory.php'; //(not ok) This does not work because alias_directory.php is not in the doc root. Similarly require_once $_SERVER['DOCUMENT_ROOT'].'/webroot.php'; //(ok) require_once dirname(__FILE__).'/alias_directory.php'; //(not ok) The problem here is that dirname(__FILE__) will return the path for alias_directory2.php not alias_directory.php. This works: require_once $_SERVER['DOCUMENT_ROOT'].'/webroot.php'; //(ok) require_once '/full/path/to/directory/alias_directory.php'; //(ok) But is very nasty and is a maintenance nightmare if I decide to move my library to another location. How do I solve this problem, is seems that I need a way to resolve an Alias folder properly.

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  • php cookies block access to directories

    - by user342391
    I have a mysql database of users that can login to my site and view content. I would like to block a couple of directories from certain users. What is the best way to do this. Currently when a user logs in a cookie is created with their customer id and the customer is is used to display their content. How would I block entire directories from my users???

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  • MySQL query : all records of one table plus count of another table

    - by Ricardo
    Hello Guys! I have 2 tables: User and Picture. The Picture table has the key of the user. So basically each user can have multiple pictures, and each picture belongs to one user. Now, I am trying to make the following query: I want to select all the user info plus the total number of pictures that he has (even if it's 0). How can I do that? Probably it sounds quite simple, but I am trying and trying and can't seem to find the right query. The only thing I could select is this info, but only for users that have at least 1 picture, meaning that the Pictures table has at least one record for that key... But I also wanna consider the users that don't have any. Any idea? Thanks!

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  • Input questions mysql php html

    - by Marcelo
    (Q1)Hi I'm using textbox in my project and I can't receive the values that are typed <textarea rows="5" cols="60"> Type your suggestion </textarea> <br> <input type="submit" name="sugestao" value="Submit" /> Sorry I don't know how to 'kill' html code, that's why < is missing. All I'm getting in the column of the database from this text box is "Submit", I'd like to receive whatever is written in the text area. How can I make the value equal whaterever is typed? (Q2) How can I make sure that I'll only store the same type(int,varchar,text) that I setted,declared in the database. For example: age(int), but if someone types "abc" in the input it will be stored in my database as the value 0 . How can I forbid this, and only save the age when it's just int and all the other fields(like name, email) are filled ?. And if is still possible warn the user that he is typing something wrong, don't need to say where. Sorry for any mistake in English and Thanks for the attention.

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  • how can I select data from MySQL based on date (unix time record)

    - by bn
    I have a record of data with unix time date in it i want to select the row based on the date/month/year only (not with time) currently Im using something like this select * from tablename where date > '$today' and date < '$tomorow' LIMIT 1; how ever this is not that accurate if the $today and $tomorrow have different time (but same date) is there any better way to do this?

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  • MySql - set of time stamped data (timestamp,event) calculating events per day

    - by Kevin Ohashi
    I have a table: id, datetime, event i also have table dates: date (Y-m-d format) the problem is some days don't have any events, I would like them to show 0 (or null) SELECT DATE_FORMAT(table.timestamp, '%Y-%m-%d') ydm, count(table.fkUID) FROM `table` where table.fkUID=$var group by ydm; is there some way to join or use conditional statements to make the result show: date|count ---------- 2010-05-23| 5 2010-05-24| 0 <--- this line just doesn't exist in my query. 2010-05-26| 3

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  • mySQL: Joining three tables - how?

    - by Industrial
    Hi everybody, I have the following query in my application. It works well, but I need it to also contain the number of products that are associated with each manufacturer. The current query: SELECT * FROM (`manufacturers`) JOIN `languages` ON `manufacturers`.`lang` = `languages`.`id` ORDER BY `languages`.`id` asc, `id` asc My products table looks like this: id | name | manufacturerid 0 | Product1 | 0

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