Search Results

Search found 40248 results on 1610 pages for 'php mysql'.

Page 96/1610 | < Previous Page | 92 93 94 95 96 97 98 99 100 101 102 103  | Next Page >

  • count and fetch rows in php

    - by Mac Taylor
    hey guys i have a table in my mysql database named (names) now everyone can save their real names now i want to query this table and find out how many times these names used forexample the output should be : Jakob (20) Jenny (17) now this is my own code : list($usernames) =mysql_fetch_row(mysql_query('SELECT name FROM table_user GROUP BY name ORDER BY COUNT(name) DESC LIMIT 50 ')); list($c) =mysql_num_rows(mysql_query('SELECT COUNT(name) FROM table_user GROUP BY name ')); print $usernames.'('.$c.')' is this a correct approach ?!

    Read the article

  • Mysql syntax using IN help!

    - by Axel
    Hi, i have a pictures table : pictures(articleid,pictureurl) And an articles table : articles(id,title,category) So, briefly, every article has a picture, and i link pictures with article using articleid column. now i want to select 5 pictures of articles in politic category. i think that can be done using IN but i can't figure out how to do it. Note: Please only one query, because i can do it by selecting articles firstly then getting the pictures. Thanks

    Read the article

  • Help with MySQL query

    - by Michael S.
    I have a table that contains the next columns: ip(varchar 255), index(bigint 20), time(timestamp) each time something is inserted there, the time column gets current timestamp. I want to run a query that returns all the rows that have been added in the last 24 hours. This is what I try to execute: SELECT ip, index FROM users WHERE ip = 'some ip' AND TIMESTAMPDIFF(HOURS,time,NOW()) < 24 And it doesn't work. Can someone help me out? Thanks :)

    Read the article

  • how to use a MySql database within Eclipse

    - by aadersh patel
    I am very new to programming, so please bear with me, and apologies in advance if at first I dont make sense...! I am doing an undergrad programming project, and need to make some databases within a Java program. I am using eclipse (galilo) to write my program. I have downloaded a connector/J, but havent the foggiest how i should use it! Anyone out there able to give me a step by step approach?! Many thanks!

    Read the article

  • PHP 5: What DAL are you using?

    - by overthetop
    hello I'm new to PHP and I recently started learning Zend Framework. What DAL are you using? Do you think that Zend_Db_* can do the magic? I need it mainly for MySql db. Does it have any limitations and can I use it in big project without any problems because I don't want to go the wrong way. 10x

    Read the article

  • php / mysql - select id from one table excepting ids which are in second table

    - by John
    hello. for example i have 2 tables: 1 . users: id Name 1 Mike 2 Adam 3 Tom 4 John 5 Andy 6 Ray 2 . visits: userID date 1 ... 3 ... 6 ... i want to make a page which can be visited once in 12 hours, when user visits that page his id is included in database ( visits ), how i can select all users ( from database users) excepting users who visited page in <= 12 hours ( users from database visits )?

    Read the article

  • MySQL limit from descending order

    - by faya
    Hello, Is it available to write a query to use same "LIMIT (from), (count)", but get result in backwards? In example if I have 8 rows in the table and I want to get 5 rows in two steps I would: first step query: select * from table limit 0, 5 first step result: first 5 rows; second step query: select * from table limit 5, 5 second step result: last 3 rows; But I want to get it vice versa. I mean from the first step I want last 3 rows and from the second I want 5 first rows. Thank you for your answer

    Read the article

  • MySQL easy question CURDATE()

    - by Tristan
    I want to compare two results one is stored in the first query, and the other is exactly the same as the first, but i want only to recieve data < today "SELECT s.GSP_nom as nom, timestamp, COUNT(s.GSP_nom) as nb_votes, AVG(v.vote+v.prix+v.serviceClient+v.interface+v.interface+v.services)/6 as moy FROM votes_serveur AS v INNER JOIN serveur AS s ON v.idServ = s.idServ WHERE s.valide = 1 AND v.date < CURDATE() ROUP BY s.GSP_nom HAVING nb_votes > 9 ORDER BY moy DESC LIMIT 0,15"; is that correct ? thank you

    Read the article

  • PHP/MYSQL Year Month table for news archive

    - by ee12csvt
    Hi all, I am creating a news archive for my site and want to create an overview page from the following DB table id - Unique identifier newsDate - in a format XXXX-XX-XX title - News Item title details - News item photo - News Item Photo caption - News Item Photo caption update - Timestamp for record The news on the site is current but I hope to add some data from years gone by over the next few months and years. What I want to do is create a new line for each year and highlight the month which corresponds to a record in the DB table, similar to that below. 2002 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2004 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2005 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2008 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC Any help or advice would be much appreciated Cheers

    Read the article

  • Comparing an id to id of different tables rows mysql

    - by jett
    So I am trying to retrieve all interests from someone, and be able to list them. This works with the following query. SELECT *,( SELECT GROUP_CONCAT(interest_id SEPARATOR ",") FROM people_interests WHERE person_id = people.id ) AS interests FROM people WHERE id IN ( SELECT person_id FROM people_interests WHERE interest_id = '.$site->db->clean($_POST['showinterest_id']).' ) ORDER BY lastname, firstname In this one which I am having trouble with, I want to select only those who happen to have their id in the table named volleyballplayers. The table just has an id, person_id, team_id, and date fields. SELECT *,( SELECT GROUP_CONCAT(interest_id SEPARATOR ",") FROM people_interests WHERE person_id = people.id ) AS interests FROM people WHERE id IN ( SELECT person_id FROM people_interests WHERE volleyballplayers.person_id = person_id ) ORDER BY lastname, firstname I just want to make sure that only the people who are in the volleyballplayers table show up, but I am getting an error saying that Unknown column 'volleyballplayers.person_id' in 'where clause' although I am quite sure of the name of table and I know the column is named person_id.

    Read the article

  • mysql insert multiple rows, return rows that failed

    - by Glenn
    When I try to insert (lets say) 30 rows in my table. For example INSERT INTO customers(cust_name, cust_address, cust_city, cust_state, cust_zip, cust_country) VALUES( 'Pep E. LaPew', '100 Main Street', 'Los Angeles', 'CA', '90046', 'USA' ), ( 'M. Martian', '42 Galaxy Way', 'New York', 'NY', '11213', 'USA' ), ... ; And cust_name has to be unique. How can I then identify the records that failed to insert because their cust_name already exists? Is it possible to return them?

    Read the article

  • MySQL - Structure for Permissions to Objects

    - by Kerry
    What would be an ideal structure for users permissions of objects. I've seen many related posts for general permissions, or what sections a user can access, which consists of a users, userGroups and userGroupRelations or something of that nature. In my system there are many different objects that can get created, and each one has to be able to be turned on or off. For instance, take a password manager that has groups and sub groups. Group 1 Group 2 Group 3 Group 4 Group 5 Group 6 Group 7 Group 8 Group 9 Group 10 Each group can contain a set of passwords. A user can be given read, write, edit and delete permissions to any group. More groups can get created at any point in time. If someone has permission to a group, I should be able to make him have permissions to all sub groups OR restrict it to just that group. My current thought is to have a users table, and then a permissions table with columns like: permission_id (int) PRIMARY_KEY user_id (int) INDEX object_id (int) INDEX type (varchar) INDEX read (bool) write (bool) edit (bool) delete (bool) This has worked in the past, but the new system I'm building needs to be able to scale rapidly, and I am unsure if this is the best structure. It also makes the idea of having someone with all subgroup permissions of a group more difficult. So, as a question, should I use the above structure? Or can someone point me in the direction of a better one?

    Read the article

  • Php function available on other php page

    - by Vafello
    I have a function that I use on index.php page and I would like to call it from other php page (other.php). How to make this function available without redeclaration? I think it's achievable using sessions, but I am not sure how to do it exactly.

    Read the article

  • How to build unlimited level of menu through PHP and mysql

    - by Starx
    Well, to build my menu my menu I use a db similar structure like this To assign another submenu for existing submenu I simply assign its parent's id as its value of parent field. parent 0 means top menu now there is not problem while creating submenu inside another submenu now this is way I fetch the submenu for the top menu <ul class="topmenu"> <? $list = $obj -> childmenu($parentid); //this list contains the array of submenu under $parendid foreach($list as $menu) { extract($menu); echo '<li><a href="#">'.$name.'</a></li>'; } ?> </ul> What I want to do is. I want to check if a new menu has other child menu and I want to keep on checking until it searches every child menu that is available and I want to display its child menu inside its particular list item like this Home ........

    Read the article

  • MySQL parameter resource error

    - by Derek
    Here is my error: Warning: mysql_query() expects parameter 2 to be resource, null given... This refers to line 23 of my code which is: $result = mysql_query($sql, $connection) My entire query code looks like this: $query = "SELECT * from users WHERE userid='".intval( $_SESSION['SESS_USERID'] )."'"; $result = mysql_query($query, $connection) or die ("Couldn't perform query $query <br />".mysql_error()); $row = mysql_fetch_array($result); I don't have a clue what has happpened here. All I wanted to do was to have the value of the users 'fullname' displayed in the header section of my web page. So I am outputting this code immediately after to try and achieve this: echo 'Hello '; echo $row['fullname']; Before this change, I had it working perfectly, where the session variable of fullname was echoed $_SESSION['SESS_NAME']. However, because my user can update their information (including their name), I wanted the name displayed in the header to be updated accordingly, and not displaying the session value.

    Read the article

  • PHP/mySQL - using result from 'CONCAT' and 'AS' in 'LIKE' clause

    - by Phil Jackson
    Hi I have the following code; if( ! empty( $post['search-bar'] ) ) { $search_data = preg_replace("#\s\s#is", '', preg_replace("#[^\w\d\s+]#is", '', $post['search-bar'] ) ); $data_array = explode( " ", $search_data ); $data_array = "'%" . implode( "%' OR '%", $data_array ) . "%'"; $query = "SELECT CONCAT( PROFILE_PROFFESION, FIRST_NAME, LAST_NAME, DISPLAY_NAME) AS 'STRING' FROM `" . ACCOUNT_TABLE . "` WHERE STRING LIKE ( " . $data_array . " ) AND BUSINESS_POST_CODE LIKE '" . substr(P_BUSINESS_POST_CODE, 0, 4) . "%'"; $q = mysql_query( $query, $CON ) or die( "_error_" . mysql_error() ); if( mysql_num_rows( $q ) != 0 ) { die(); } } Problem is I want to use the temp col 'STRING' in the where clause but is returning 'unknown coloumn STRING Can any one point me in the right direction, regards Phil

    Read the article

  • List hits per hour from a MySQL table

    - by Axel
    I am trying to work out the hits per hour from a database. Data basically is stored as follows (with other columns) : Table Name: Hits ============================ VisitorIP TIMESTAMP ---------------------------- 15.215.65.65 123456789 I want to display total hits per hour (within the last 6 hours ) including the hours that has no hits. Example of the output: // Assuming now : 21:00 21:00 - 0 hits 20:00 - 1 hits 19:00 - 4 hits 18:00 - 0 hits 17:00 - 2 hits 16:00 - 3 hits i would love to get the data as array, Please note that the stored date is in UNIX time stamp format. and there may be some hours without any hits! Thanks

    Read the article

  • Add column from another table matching results from first MySQL query

    - by Nemi
    This is my query for available rooms in choosen period: SELECT rooms.room_id FROM rooms WHERE rooms.room_id NOT IN ( SELECT reservations.room_id FROM reservations WHERE ( reservations.arrivaldate >= $arrival_datetime AND reservations.departuredate <= $departure_datetime) OR ( reservations.arrivaldate <= $arrival_datetime AND reservations.departuredate >= $arrival_datetime ) OR ( reservations.arrivaldate <= $departure_datetime AND reservations.departuredate >= $departure_datetime ) ); How to add average room price column for selected period(from $arrival_datetime to $departure_datetime) from another table (room_prices_table), for every room_id returned from above query. So I need to look in columns whos name is same as room_id... room_prices_table: date room0001 room0002 room0003 ... Something like SELECT AVG(room0003) FROM room_prices_table WHERE datum IS BETWEEN $arrival_datetime AND $departure_datetime ??

    Read the article

  • Strange behavior of MySQL UPDATE query in PHP?

    - by Prashant
    When I am executing following query then its not updating views column by 1 instead sometimes its updating it by 2 or 3. Say currently views count is 24 then after executing this query it becomes 26 or sometimes its 27. $views = $views + 1; $_SQL = ''; $_SQL = 'UPDATE videos SET views = '.$views.' WHERE VideoId= "'.$videoid.'";'; @mysql_query($_SQL); I am not getting why this is happening, am I missing something or the query is executing 2 times automatically? Please help me to figure out the issue. Thanks

    Read the article

  • problem with joomla, php and json

    - by sebastian
    hi, i have a problem with a joomla component. i'm, unsing php and json for some dynamic drop down boxes. here is the code:` jQuery( function () { //jQuery.ajaxSetup({error : function (a,b) {console.dir(a); console.dir(b);}}); jQuery("#util, #loc").change( function() { var locatie = jQuery("#loc").val(); var utilitate = jQuery("#util").val(); if ( (locatie!= '---') && (utilitate!='---') ) jQuery.getJSON( "index.php?option=com_calculator&opt=json_contor&format=raw", { locatie: locatie, utilitate: utilitate }, function (data) { var html = ""; if ( data.success == 'ok' ) for (var i in data.val) html += "<option name=den_contor value ='"+ i+"' >" + data.val[i]+ " </option>"; jQuery("#den_contor").html( html ) } ) }) }); the query works, but only on one PC. we have exactly the same xampp server, exactly the same files. on one pc it works, and on a online server and on my pc it doesn't. EDIT: i have three drop down boxes, the first is populated directly from the database, the second has 4 predefined values. and the third is populated depending on combination of the first two. i have a test site online. http://contor.redxart.com must be logged in to use Calculator in the menu. you can make an new account :) "Adaugare Index" is the part that isn't working any ideas? thanks, sebastian

    Read the article

< Previous Page | 92 93 94 95 96 97 98 99 100 101 102 103  | Next Page >