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  • Access startup form locked GUI

    - by Brad
    I just had an interesting experience with a startup form in MS Access 2010. I designed a login form and when I thought I was done I set my startup form to be the login form I'd just created. I then closed Access and reopened it but my login form did not appear. Instead the whole GUI was locked. I cannot click on anything. My form was working during my tests before I set it as a startup form and reloaded Access. How can I either remove my form as a startup object or get the use of my GUI back?

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  • Find Upper Right Point of Rotated Rectangle in AS3 (Flex)

    - by coltech
    I have a rectangle of any arbitrary width and height. I know X,Y, width, and height. How do I solve the upper right hand coordinates when the rectangle is rotated N degrees? I realized if it were axis aligned I would simply solve for (x,y+width). Unforunatly this doesn't hold true when I apply a transform matrix on the rectangle to rotate it around its center.

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  • access: control source of textbox

    - by I__
    there is a form where a user enters a date in [Text4] when users clicks OK, the following code is run: DoCmd.OpenReport "All_Ones", acViewPreview the following is the control source of a textbox on the report [Forms]![By Number]![Text4] for some reason after the report is open, it just sayd #?nameor something like that, meaning that it is an invalid parameter. what am i doing wrong?

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  • GLSL point inside box test

    - by wcochran
    Below is a GLSL fragment shader that outputs a texel if the given texture coord is inside a box, otherwise a color is output. This just feels silly and the there must be a way to do this without branching? uniform sampler2D texUnit; varying vec4 color; varying vec2 texCoord; void main() { vec4 texel = texture2D(texUnit, texCoord); if (any(lessThan(texCoord, vec2(0.0, 0.0))) || any(greaterThan(texCoord, vec2(1.0, 1.0)))) gl_FragColor = color; else gl_FragColor = texel; } Below is a version without branching, but it still feels clumsy. What is the best practice for "texture coord clamping"? uniform sampler2D texUnit; varying vec4 color; varying vec4 labelColor; varying vec2 texCoord; void main() { vec4 texel = texture2D(texUnit, texCoord); bool outside = any(lessThan(texCoord, vec2(0.0, 0.0))) || any(greaterThan(texCoord, vec2(1.0, 1.0))); gl_FragColor = mix(texel*labelColor, color, vec4(outside,outside,outside,outside)); } I am clamping texels to the region with the label is -- the texture s & t coordinates will be between 0 and 1 in this case. Otherwise, I use a brown color where the label ain't. Note that I could also construct a branching version of the code that does not perform a texture lookup when it doesn't need to. Would this be faster than a non-branching version that always performed a texture lookup? Maybe time for some tests...

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  • How to set a cell value = to whats looping?

    - by digitalgavakie
    I have this code below. How can I set a cell value to = whats looping through that value? Sub Test2() ' Select cell A2, *first line of data*. Range("A2").Select ' Set Do loop to stop when an empty cell is reached. Do Until IsEmpty(ActiveCell) ' Insert your code here. ' Step down 1 row from present location. ActiveCell.Offset(1, 0).Select Loop End Sub

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  • What is the point of C++/CLI?

    - by Earlz
    Hello, I am wondering what the uses of C++/CLI is. It seems to me that it is basically C++ running on .Net, am I wrong in this thinking? What is it good for? Why not just use C# or some other truly managed language instead?

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  • update record only works when there is no auto_increment

    - by every_answer_gets_a_point
    i am accessing a mysql table through an odbc connection in excel here is how i am updating the table: With rs .AddNew ' create a new record ' add values to each field in the record .Fields("datapath") = dpath .Fields("analysistime") = atime .Fields("reporttime") = rtime .Fields("lastcalib") = lcalib .Fields("analystname") = aname .Fields("reportname") = rname .Fields("batchstate") = "bstate" .Fields("instrument") = "NA" .Update ' stores the new record End With when the schema of the table is this, updating it works: create table batchinfo(datapath text,analysistime text,reporttime text,lastcalib text,analystname text, reportname text, batchstate text, instrument text); but when i have auto_increment in there it does not work: CREATE TABLE batchinfo ( rowid int(11) NOT NULL AUTO_INCREMENT, datapath text, analysistime text, reporttime text, lastcalib text, analystname text, reportname text, batchstate text, instrument text, PRIMARY KEY (rowid) ) ENGINE=InnoDB AUTO_INCREMENT=67 DEFAULT CHARSET=latin1 has anyone experienced a problem like this where updating does not work when there is an auto_increment field involved? connection string: Private Sub ConnectDB() Set oConn = New ADODB.Connection oConn.Open "DRIVER={MySQL ODBC 5.1 Driver};" & _ "SERVER=localhost;" & _ "DATABASE=employees;" & _ "USER=root;" & _ "PASSWORD=pas;" & _ "Option=3" End Sub also here's the rs.open: rs.Open "batchinfo", oConn, adOpenKeyset, adLockOptimistic, adCmdTable

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  • Is there a point creating a site using XSLT

    - by webwise
    Is this technology still popular? I want to make a website which automatically transforms XSLT files. It should work like this: When a user accesses the site, a single handler would accept his request and then find a suitable XML for it (according to the URL requested) and transform it using its attached XSL file. I want to do this in order to make it easy to update the site using plain XML files (instead of using a full-fledged & expensive CMS system). What do you say? good idea? bad idea? anyone has a recommendation? Thanks!

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  • optimization math computation (multiplication and summing)

    - by wiso
    Suppose you want to compute the sum of the square of the differences of items: $\sum_{i=1}^{N-1} (x_i - x_{i+1})^2$, the simplest code (the input is std::vector<double> xs, the ouput sum2) is: double sum2 = 0.; double prev = xs[0]; for (vector::const_iterator i = xs.begin() + 1; i != xs.end(); ++i) { sum2 += (prev - (*i)) * (prev - (*i)); // only 1 - with compiler optimization prev = (*i); } I hope that the compiler do the optimization in the comment above. If N is the length of xs you have N-1 multiplications and 2N-3 sums (sums means + or -). Now suppose you know this variable: sum = $x_1^2 + x_N^2 + 2 sum_{i=2}^{N-1} x_i^2$ Expanding the binomial square: $sum_i^{N-1} (x_i-x_{i+1})^2 = sum - 2\sum_{i=1}^{N-1} x_i x_{i+1}$ so the code becomes: double sum2 = 0.; double prev = xs[0]; for (vector::const_iterator i = xs.begin() + 1; i != xs.end(); ++i) { sum2 += (*i) * prev; prev = (*i); } sum2 = -sum2 * 2. + sum; Here I have N multiplications and N-1 additions. In my case N is about 100. Well, compiling with g++ -O2 I got no speed up (I try calling the inlined function 2M times), why?

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  • Excel assign copied sheet name as variable

    - by rach-90
    I'm trying to copy an existing sheet in my workbook and then I want to use the copied sheet to run the rest of my code. (Sheet3 is the existing sheet, S_Temp is the copied sheet) Dim s_Temp as string Sheet3.copy Activesheet.name = S_Temp Sheets("S_Temp").Range("A1").value = "Test" How can I reference to the copied sheet?

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  • comparison between point and integer

    - by LawVS
    Right, basically I want to add two numbers together. It's for a working hours calculator and I've included parameters for a night shift scenario as an if statement. However, it now mucks up the day shift pattern. So I want to sort out that if the start time is below 12, then it'll revert to the original equation shown in the code instead of the if statement. -(IBAction)done:(id)sender { int result = [finishHours.text intValue] - [startHours.text intValue]; totalHours.text = [NSString stringWithFormat:@"%d", result]; if (result < 0) { totalHours.text = [NSString stringWithFormat:@"%d", result * -1]; } if (result < 12) { totalHours.text = [NSString stringWithFormat:@"%d", result + 24]; } if (startHours < 12) { totalHours.text = [NSString stringWithFormat:@"%d", result - 24]; }

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  • Excel: Automating the Selection of an Unknown Number of Cells

    - by user1905080
    I’m trying to automate the formatting of an excel file by a macro and am seeking a solution. I have two columns titled Last Name and First Name which I would like to concatenate into a separate column titled Last Name, First Name. This is simple enough when done by hand: create one cell which does this, then drag that cell to include all cells within the range. The problem appears when trying to automate this. Because I can’t know the number of names that need to be concatenated ahead of time, I can’t automate the selection of cells by dragging. Can you help me automate this? I’ve tried a process of copying the initial concatenated cell, highlighting the column, and then pasting. I’ve also tried to use a formula which returned the concatenation only if there is text in the “Last Name” and “First Name” columns. However, in both cases, I end up with some 100,000 rows, putting a serious cramp on my ability to manipulate the worksheet. The best solution I can think of is to create concatenations within a fixed range of cells. Although this would create useless cells, at least there wouldn’t be 99,900 of them.

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  • what does select @@identity do?

    - by every_answer_gets_a_point
    i am connecting to a mysql database through excel using odbc what does this line do? Set rs = oConn.Execute("SELECT @@identity", , adCmdText) i am having trouble updating the database: With rs .AddNew ' create a new record ' add values to each field in the record .Fields("datapath") = dpath .Fields("analysistime") = atime .Fields("reporttime") = rtime .Fields("lastcalib") = lcalib .Fields("analystname") = aname .Fields("reportname") = rname .Fields("batchstate") = "bstate" .Fields("instrument") = "NA" .Update ' stores the new record End With it is ONLY updating .Fields("instrument") = "NA", but for all other fields it is putting NULL values

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  • How to match data between columns to do the comparasion

    - by NCC
    I do not really know how to explain this in a clear manner. Please see attached image I have a table with 4 different columns, 2 are identical to each other (NAME and QTY). The goal is to compare the differences between the QTY, however, in order to do it. I must: 1. sort the data 2. match the data item by item This is not a big deal with small table but with 10 thousand rows, it takes me a few days to do it. Pleas help me, I appreciate. My logic is: 1. Sorted the first two columns (NAME and QTY) 2. For each value of second two columns (NAME and QTY), check if it match with first two column. If true, the insert the value. 3. For values are not matched, insert to new rows with offset from the rows that are in first two columns but not in second two columns

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  • c++ float subtraction rounding error

    - by Volkan Ozyilmaz
    I have a float value between 0 and 1. I need to convert it with -120 to 80. To do this, first I multiply with 200 after 120 subtract. When subtract is made I had rounding error. Let's look my example. float val = 0.6050f; val *= 200.f; Now val is 121.0 as I expected. val -= 120.0f; Now val is 0.99999992 I thought maybe I can avoid this problem with multiplication and division. float val = 0.6050f; val *= 200.f; val *= 100.f; val -= 12000.0f; val /= 100.f; But it didn't help. I have still 0.99 on my hand. Is there a solution for it? Edit: After with detailed logging, I understand there is no problem with this part of code. Before my log shows me "0.605", after I had detailed log and I saw "0.60499995946884155273437500000000000000000000000000" the problem is in different place.

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  • Scaling vectors from a center point?

    - by user146780
    I'm trying to figure out if I have points that make for example a square: * * * * and let's say I know the center of this square. I want a formula that will make it for eample twice its size but from the center * * * * * * * * Therefore the new shape is twice as large and from the center of the polygon. It has to work for any shape not just squares. I'm looking more for the theory behind it more than the implementation. Thanks

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