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• Lost Page Write I/O Errors on CentOS LVM setup

  - by Gregg Leventhal

  I have a CentOS 6 box with LVM setup and one of the PVs is a USB disk (I know). One of them is getting the error: Oct 30 10:57:07 alpha01 kernel: lost page write due to I/O error on dm-3 Oct 30 10:57:07 alpha01 kernel: Buffer I/O error on device dm-3, logical block 4 Which is causing problems with all of the LVs on it. pvs shows the PV as unknown device. I can ls to the logical volumes and they show up in lvdisplay, but first I get a bunch of IO errors. I made sure the cables are secure between the USB drive. What should I do to get this back up and running for the meanwhile? Should I unmount each LV and run an fsck.ext4 on each one like fsck.ext4 -y /dev/vg1/lv_logvolname ?

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• High Lock Wait ratio in MySQL

  - by FunkyChicken

  on my site I log every pageview (date,ip,referrer,page,etc) in a simple mysql table. This table gets very little selects (3 per minute), but a lot of inserts. (about 100 per second) Today I changed this table from an InnoDB table to a MEMORY table, this made sense to me to prevent unnecessary hard disk IO. I also prune this table once per minute, to make sure it never get's too big. -- Performance wise, things are running fine. But I noticed that while running tuning-primer, that my Current Lock Wait ratio is quite high. Current Lock Wait ratio = 1 : 561 My question: Should I worry about this Lock Wait Ratio? And is there something I can change in my my.cnf to improve things so that the lock wait ratio isn't so high?

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• Mamimum page fetch with maximum bandwith

  - by Ehsan

  Hi I want to create an application like a spider I've implement fetching page as the following code in multi-thread application but there is two problem 1) I want to use my maximum bandwidth to send/receive request, how should I config my request to do so (Like Download Accelerator application and the like) cause I heard the normal application will use 66% of the available bandwidth. 2) I don't know what exactly HttpWebRequest.KeepAlive do, but as its name implies I think i can create a connection to a website and without closing the connection sending another request to that web site using existing connection. does it boost performance or Im wrong public PageFetchResult Fetch() { PageFetchResult fetchResult = new PageFetchResult(); try { HttpWebRequest req = (HttpWebRequest)HttpWebRequest.Create(URLAddress); HttpWebResponse resp = (HttpWebResponse)req.GetResponse(); Uri requestedURI = new Uri(URLAddress); Uri responseURI = resp.ResponseUri; if (Uri.Equals(requestedURI, responseURI)) { string resultHTML = ""; byte[] reqHTML = ResponseAsBytes(resp); if (!string.IsNullOrEmpty(FetchingEncoding)) resultHTML = Encoding.GetEncoding(FetchingEncoding).GetString(reqHTML); else if (!string.IsNullOrEmpty(resp.CharacterSet)) resultHTML = Encoding.GetEncoding(resp.CharacterSet).GetString(reqHTML); req.Abort(); resp.Close(); fetchResult.IsOK = true; fetchResult.ResultHTML = resultHTML; } else { URLAddress = responseURI.AbsoluteUri; relayPageCount++; if (relayPageCount > 5) { fetchResult.IsOK = false; fetchResult.ErrorMessage = "Maximum page redirection occured."; relayPageCount = 0; return fetchResult; } req.Abort(); resp.Close(); return Fetch(); } } catch (Exception ex) { fetchResult.IsOK = false; fetchResult.ErrorMessage = ex.Message; } return fetchResult; }

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• Eclipse: Help with EGit

  - by someguy

  I want to be able to use a version control system. Although Eclipse comes with CVS, I think it's better that I use a distributed version control system, such as GIT. I was pretty much sold after reading this article. Anyway, I installed EGit and followed this guide on how to set it up. However, I ran in to a few problems: Adding .project and .classpath inside .gitignore did not seem to work. When I try to open a committed file, it throws an error, saying: "IO error reading Git blob [...]" What am I doing wrong? If more information is needed, please specify and I will give.

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• ScrollPanel in java does not appear JTextarea resizes instead

  - by Casper Marcussen

  Hello everyone My program is finished, but testing it out, i found out that the scrollpanel does not appear, it just resizes the JTextarea instead. The code is provided below: package javaapplication15; import java.awt.Container; import java.awt.FlowLayout; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.io.*; import java.io.IOException; import javax.swing.*; public class Tekstprogram extends JFrame { public Tekstprogram() { setSize(400, 600); setDefaultCloseOperation(EXIT_ON_CLOSE); setResizable(false); Container Indhold = getContentPane(); Indhold.setLayout(new FlowLayout()); JButton openButton = new JButton("Open"); JButton saveButton = new JButton("Save"); final JLabel statusbar = new JLabel("Output of your selection will go here"); final JTextArea TekstOmråde = new JTextArea(29, 30); JScrollPane scrollText = new JScrollPane(TekstOmråde); openButton.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent ae) { JFileChooser chooser = new JFileChooser(); chooser.setMultiSelectionEnabled(true); int option = chooser.showOpenDialog(Tekstprogram.this); if (option == JFileChooser.APPROVE_OPTION) { File[] sf = chooser.getSelectedFiles(); String filelist = "nothing"; if (sf.length > 0) { filelist = sf[0].getName(); } for (int i = 1; i < sf.length; i++) { filelist = filelist + ", " + sf[i].getName(); } try { String strLine; File selectedFile = chooser.getSelectedFile(); FileInputStream in = new FileInputStream(selectedFile); BufferedReader br = new BufferedReader(new InputStreamReader(in)); while ((strLine = br.readLine()) != null) { TekstOmråde.append(strLine + "\n"); } } catch (Exception e) { System.out.println("En fejl opstod ved" + e); } } } }); saveButton.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent ae) { JFileChooser chooser = new JFileChooser(); int option = chooser.showSaveDialog(Tekstprogram.this); if (option == JFileChooser.APPROVE_OPTION) { File file = chooser.getSelectedFile(); try { BufferedWriter out = new BufferedWriter(new FileWriter(file)); out.write(TekstOmråde.getText()); out.close(); } catch (IOException e) { System.out.println("IOException fejl opstod :"); e.printStackTrace(); } } } }); Indhold.add(openButton); Indhold.add(saveButton); Indhold.add(TekstOmråde); Indhold.add(scrollText); Indhold.add(statusbar); } public static void main(String args[]) { Tekstprogram sfc = new Tekstprogram(); sfc.setVisible(true); } } Is there anyway to make the JTexarea static?

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• Paging not working in my wordpress installation

  - by Bootcamp

  I recently started a blog site and wanted to give it a magazine look. I used Wordpress for my blog and used the Arthemia theme with it. I also changed the permalink structure to point to /%year%/%monthnum%/%day%/%postname%/ structure. Now the problem that i have is that the paging has stopped working on my home page. When i click on the next page link i get a 404 error. My /page/2 url does not show the next page. I check on google and found out that it was due to the redirection that is being performed due to the permalink change. The solution given was that i need to skip the url rewriting for the /page/* urls. This is the link to an article which said this http://www.yoursearchadvisor.com/blog/wordpress-next_posts_link-broken/ . I was not able to follow this article and solve my problem, as i could not find the permanent redirect manager under the settings section as said in this article. Can somebody please guide me how to solve this problem. I am using the latest Wordpress version and Arthemia theme with it. Thanks.

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• Am I using too much memory? (Rails on EC2 with Resque)

  - by Stpn

  I am looking at the memory usage of the Rails application (it uses background processes via Resque) and since the common answer to the question, "how many workers is too many" was "test and see", I ran some memory commands and wonder if someone can help figuring if the memory usage is high enough already, or I can still add some extra workers.. so (this is all under the maximum load): $ free -t -m total used free shared buffers cached Mem: 1756 1532 223 0 12 229 -/+ buffers/cache: 1291 464 Swap: 895 10 885 Total: 2652 1543 1108 $ vmstat procs -----------memory---------- ---swap-- -----io---- -system-- ----cpu---- r b swpd free buff cache si so bi bo in cs us sy id wa 0 0 10588 156172 13400 326476 1 6 4 0 5 4 1 0 99 0 If there is any extra info I can provide to help answer this, I would be happy to do so. If the question is strange in some way, please let me know I'd be glad to fix etc..

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• Reading serialised object from file

  - by nico

  Hi everyone. I'm writing a little Java program (it's an ImageJ plugin, but the problem is not specifically ImageJ related) and I have some problem, most probably due to the fact that I never really programmed in Java before... So, I have a Vector of Vectors and I'm trying to save it to a file and read it. The variable is defined as: Vector <Vector <myROI> > ROIs = new Vector <Vector <myROI> >(); where myROI is a class that I previously defined. Now, to write the vector to a file I use: void saveROIs() { SaveDialog save = new SaveDialog("Save ROIs...", imp.getTitle(), ".xroi"); String name = save.getFileName(); if (name == null) return; String dir = save.getDirectory(); try { FileOutputStream fos = new FileOutputStream(dir+name); ObjectOutputStream oos = new ObjectOutputStream(fos); oos.writeObject(ROIs); oos.close(); } catch (Exception e) { IJ.log(e.toString()); } } This correctly generates a binary file containing (I suppose) the object ROIs. Now, I use a very similar code to read the file: void loadROIs() { OpenDialog open = new OpenDialog("Load ROIs...", imp.getTitle(), ".xroi"); String name = open.getFileName(); if (name == null) return; String dir = open.getDirectory(); try { FileInputStream fin = new FileInputStream(dir+name); ObjectInputStream ois = new ObjectInputStream(fin); ROIs = (Vector <Vector <myROI> >) ois.readObject(); // This gives error ois.close(); } catch (Exception e) { IJ.log(e.toString()); } } But this function does not work. First, I get a warning: warning: [unchecked] unchecked cast found : java.lang.Object required: java.util.Vector<java.util.Vector<myROI>> ROIs = (Vector <Vector <myROI> >) ois.readObject(); ^ I Googled for that and see that I can suppress by prepending @SuppressWarnings("unchecked"), but this just makes things worst, as I get an error: <identifier> expected ROIs = (Vector <Vector <myROI> >) ois.readObject(); ^ In any case, if I omit @SuppressWarnings and ignore the warning, the object is not read and an exception is thrown java.io.WriteAbortedException: writing aborted; java.io.NotSerializableException: myROI Again Google tells me myROI needs to implements Serializable. I tried just adding implements Serializable to the class definition, but it is not sufficient. Can anyone give me some hints on how to procede in this case? Also, how to get rid of the typecast warning?

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• linux + automated rsync command

  - by Diana

  my target is to copy /tmp/my_file from 10.10.10.1 to my Linux machine without login and password , I set the passwords file with the right password - secret123 so rsync should work , please advice why I get Permission denied. Remark - 10.10.10.1 address is linux machine version – red hat 5.3 rsync -WavH --password-file=/tmp/passwords --progress [email protected]:/tmp/my_file . Permission denied. rsync: connection unexpectedly closed (0 bytes read so far) rsync error: error in rsync protocol data stream (code 12) at io.c(165) more /tmp/passwords secret123 ls -ltr passwords -rwxr-xr-x 1 root root 10 Sep 12 17:32 passwords

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• Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

  - by brilliant

  Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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• Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

  - by brilliant

  Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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• how to pass a variable value from one class to another

  - by Arunabha

  I have two packages one is com.firstBooks.series.db.parser which have a java file XMLParser.java, I have another package com.firstBooks.series79 which have a class called AppMain.NW I want to send the value of a variable called _xmlFileName frm AppMain class to the xmlFile variable in XMLParser class, I am posting the code for both the class, kindly help me. package com.firstBooks.series.db.parser; import java.io.IOException; import java.io.InputStream; import java.util.Vector; import net.rim.device.api.xml.parsers.DocumentBuilder; import net.rim.device.api.xml.parsers.DocumentBuilderFactory; import net.rim.device.api.xml.parsers.ParserConfigurationException; import org.w3c.dom.Document; import org.w3c.dom.Element; import org.w3c.dom.NodeList; import org.xml.sax.SAXException; import com.firstBooks.series.db.Question; public class XMLParser { private Document document; public static Vector questionList; public static String xmlFile; public XMLParser() { questionList = new Vector(); } public void parseXMl() throws SAXException, IOException, ParserConfigurationException { // Build a document based on the XML file. DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder(); InputStream inputStream = getClass().getResourceAsStream(xmlFile); document = builder.parse(inputStream); } public void parseDocument() { Element element = document.getDocumentElement(); NodeList nl = element.getElementsByTagName("question"); if (nl != null && nl.getLength() > 0) { for (int i = 0; i < nl.getLength(); i++) { Element ele = (Element) nl.item(i); Question question = getQuestions(ele); questionList.addElement(question); } } } private Question getQuestions(Element element) { String title = getTextValue(element, "title"); String choice1 = getTextValue(element, "choice1"); String choice2 = getTextValue(element, "choice2"); String choice3 = getTextValue(element, "choice3"); String choice4 = getTextValue(element, "choice4"); String answer = getTextValue(element, "answer"); String rationale = getTextValue(element, "rationale"); Question Questions = new Question(title, choice1, choice2, choice3, choice4, answer, rationale); return Questions; } private String getTextValue(Element ele, String tagName) { String textVal = null; NodeList nl = ele.getElementsByTagName(tagName); if (nl != null && nl.getLength() > 0) { Element el = (Element) nl.item(0); textVal = el.getFirstChild().getNodeValue(); } return textVal; } } Nw the code for AppMain class //#preprocess package com.firstBooks.series79; import net.rim.device.api.ui.UiApplication; import com.firstBooks.series.ui.screens.HomeScreen; public class AppMain extends UiApplication { public static String _xmlFileName; public static boolean _Lite; public static int _totalNumofQuestions; public static void initialize(){ //#ifndef FULL /* //#endif _xmlFileName = "/res/Series79_FULL.xml"; _totalNumofQuestions = 50; _Lite = false; //#ifndef FULL */ //#endif //#ifndef LITE /* //#endif _xmlFileName = "/res/Series79_LITE.xml"; _totalNumofQuestions = 10; _Lite = true; //#ifndef LITE */ //#endif } private AppMain() { initialize(); pushScreen(new HomeScreen()); } public static void main(String args[]) { new AppMain().enterEventDispatcher(); } }

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• Connecting to an RMI object without registry

  - by Mark Probst

  I think I need to connect to a remote RMI object without going through the registry, but I don't know how. My situation is this: I'm implementing a simple job distribution service which consists of one distributor and multiple workers. The distributor has a registered RMI object to which clients connect to send jobs, and workers connect to accept jobs. Unfortunately the distributor and worker hosts are behind a firewall. To get to the distributor host I am tunneling two ports (one for the registry, one for the distributor object) via SSH, so I can get to the registry and the distributor from outside the firewall. To make that work I have to set "-Djava.rmi.server.hostname=localhost" on the distributor JVM so that the clients connect to their local, tunneled port, instead of the port on the actual distributor host, which is blocked. This creates a problem for the workers, though, because they need to connect to the distributor directly, but because of the "localhost" redirection they behave like clients and try to connect to a port on their own host, which is not available, because I'm not tunneling on the workers (it is impractical). Now, if I could connect to a remote object directly by giving the hostname and port, I could do away both with the registry on the distributor and the "localhost" hack, and make the workers connect properly. How do I do that? Or is there a different solution to this problem?

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• pdflush hanging on Amazon EBS drives when using multi-GB files - any workaround?

  - by rhh

  Hello, When I run gunzip on a 1.7GB file (which generates an 8GB file) on an EBS volume, pdflush freezes after gunzip runs and the CPU hangs indefinitely at 100% IO Wait. Here's the output from 'ps aux | grep pdflush'. Note the D status root 87 0.0 0.0 0 0 ? D 06:18 0:00 pdflush root 88 0.0 0.0 0 0 ? D 06:18 0:00 pdflush The only solution is to kill the pdflush processes. The processes don't die immediately either. This problem is repeatable and happens with new instances. I'm running 2xlarge instances and I have way more RAM free than is being used (i.e. /proc/meminfo shows 20+GB MemFree) Has anyone found a workaround to this problem in the past? Thanks for any thoughts. Robert

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• Cherokee high virtual memory usage even after disabling I/O Cache

  - by nidheeshdas

  I've Ubuntu 10.04LTS 64-bit running on a openvz container and Cherokee 1.0.8 compiled from source. The virtual memory usage of cherokee-worker is around 430 MB even after disabling I/O cache from Advanced - I/O Cache - NOT enabled. Is this issue particular to openvz? Because many people reported to have successfully reduced virt memory usage by disabling io cache. htop output: http://imgur.com/z5JEL.jpg (newbies not allowed to post image.) thanks in advance. nidheeshdas

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• How to edit the list of files to download in a .torrent file?

  - by Forbidden Overseer

  I have a torrent that contains many files in it, but I don't want to download all of them because I need only few files among them. I am not downloading from a torrent client, but I am actually using put.io service that converts torrents into direct downloads for me. I want to edit the .torrent file (or magnet link) in such a way that I get only those files which I need from the torrent. I tried by editing with text editors, but I am getting some crazy hash errors when I did that. I have seen people editing trackers in a torrent file (using online editors and other editors), but none of them edited the list of files in the torrent file. So, the question is: How to edit a .torrent file (and save it back as another .torrent file) such that when you run that torrent file, it only downloads only those files you need?

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• Solution to Manage and Monitor (Ubuntu) Machines

  - by Elmar Weber

  I'm looking for a tool like Canonical (system management and monitoring for Ubuntu) that is Open Source and free. The goal is to manage a dozen or so KVM machines for private testing purposes. I know of puppet and munin or RHQ as separate tools to manage and monitor, but I'd prefer something integrated. Any tips? Basic requirements would be: system package management and update (individual selection for each managed node) configuration of basic system services (Users, NFS, cron, ideally also Apache) monitoring (charting of system resources, disk, io, memory, etc) and alerting, ideally a default configuration with sensible values for alerts

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• How to disable MSBuild's <RegisterOutput> target on a per-user basis?

  - by Roger Lipscombe

  I like to do my development as a normal (non-Admin) user. Our VS2010 project build fails with "Failed to register output. Please try enabling Per-user Redirection or register the component from a command prompt with elevated permissions." Since I'm not at liberty to change the project file, is there any way that I can add user-specific MSBuild targets or properties that disable this step on a specific machine, or for a specific user? I'd prefer not to hack on the core MSBuild files. I don't want to change the project file because I might then accidentally check it back in. Nor do I want to hack on the MSBuild core files, because they might get overwritten by a service pack. Given that the Visual C++ project files (and associated .targets and .props files) have about a million places to alter the build order and to import arbitrary files, I was hoping for something along those lines. MSBuild imports/evaluates the project file as follows (I've only looked down the branches that interest me): Foo.vcxproj Microsoft.Cpp.Default.props Microsoft.Cpp.props $(UserRootDir)\Microsoft.Cpp.$(Platform).user.props Microsoft.Cpp.targets Microsoft.Cpp.$(Platform).targets ImportBefore\* Microsoft.CppCommon.targets The "RegisterOutput" target is defined in Microsoft.CppCommon.targets. I was hoping to replace this by putting a do-nothing "RegisterOutput" target in $(UserRootDir)\Microsoft.Cpp.$(Platform).user.props, which is %LOCALAPPDATA%\MSBuild\v4.0\Microsoft.Cpp.Win32.user.props (UserRootDir is set in Microsoft.Cpp.Default.props if it's not already set). Unfortunately, MSBuild uses the last-defined target, which means that mine gets overridden by the built-in one. Alternatively, I could attempt to set the %(Link.RegisterOutput) metadata, but I'd have to do that on all Link items. Any idea how to do that, or even if it'll work?

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• Is paravirtualization evil?

  - by Daniel

  I have an VMWare ESX Server v3.5 with a few virtualized Debian Lenny VMs (kernel 2.6.22 with vmi) running Apache Tomcat 5.5. I enabled paravirtualization, and Disk IO increased from about 240MB/s to 380MB/s, making me a happy admin. The problem now is that my apache tomcat becomes deadlocked during startup, running with 200% CPU (I have 2 CPUS assigned to the VM), and don't know how to get both: A stable system and a fast system. I somewhere heared that paravirtualization is legacy anyway and won't be available on newer ESX servers. Is there a replacement for this seemingly performance-improving option, or is it discontinued becauses it is just unstable? What is the state of paravirtualization? Should I ignore it completely? Thanks for all answers in advance.

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• server performance metrics report and practicality

  - by Anjesh

  I have a need of preparing web server (apache-php) performance report containing important metrics like CPU usage, disk io, memory usage on user basis. Couple of domains are hosted in the same server and they run from separate users using fcgi. The reason being sometimes some hosted applications take lots of cpu usage, making the server slow for other applications (running as separate users). i am planning to develop scripts for this, as i can't seem to find any simple utilities for this purpose. This script will take snapshots of the user wise metrics at defined periods say 15 minutes and record it. Any abnormalities will be reported via emails. How practical is that? also would be interesting to know what else need to be recorded.

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• Virtualbox, merging snapshots and base disk

  - by Henrik

  Hi, I have a virtual machine with about 30 snapshots in branches. The current development path is 22 snapshots plus the base disk. The amount of files is seemingly having an impact now on IO and the dev laptop I'm using (don't know if it is host disk performance issues with the 140GB total size over a lot of fragments, or just the fact that it is hitting sectors distributed across a lot of files). I would like to merge the current development branch of snapshots together with the base disk, but I am unsure if the following command would produce the correct outcome. I am not able to boot this disk after the procedure completes (5-6 hours). vboxmanage clonehd "C:\VPC-Storage\.VirtualBox\Machines\CRM\Snapshots\{245b27ac-e658-470a-b978-8e62137c33b1}.vhd" "E:\crm-20100624.vhd" --format VHD --type normal Could anyone confirm if this is the correct approach or not?

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• jsp error plz check this code why are not insert my data into database

  - by lekhni

  <%@ page language="java" import="java.util.*" pageEncoding="ISO-8859-1"%> <%@ page import="java.sql.*" %> <%@ page import="java.io.*"%> <%@ page import="java.io.File"%> <%@ page import="java.util.*"%> <%@ page import="java.sql.*"%> <%@ page import="java.sql.Blob"%> <%@ page import="java.sql.PreparedStatement"%> <%@ page import="java.sql.BatchUpdateException"%> <%@ page import="javax.servlet.*"%> <%@ page import="javax.servlet.http.*"%> <% String path = request.getContextPath(); String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/"; %> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <base href="<%=basePath%>"> <title>My JSP 'p.jsp' starting page</title> <meta http-equiv="pragma" content="no-cache"> <meta http-equiv="cache-control" content="no-cache"> <meta http-equiv="expires" content="0"> <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"> <meta http-equiv="description" content="This is my page"> <!-- <link rel="stylesheet" type="text/css" href="styles.css"> --> </head> <body> <% int activityId = Integer.parseInt(request.getParameter("activityId")); String name = request.getParameter("name"); String activityType = request.getParameter("activityType"); int parentId = Integer.parseInt(request.getParameter("parentId")); String description = request.getParameter("description"); %> <% Connection conn=null; PreparedStatement pstatement = null; try{ Class.forName("com.mysql.jdbc.Driver"); conn=DriverManager.getConnection("jdbc:mysql://localhost:3306/pol","root","1234"); Statement st=conn.createStatement(); String queryString = "INSERT INTO activity(activityId,name,activityType,parentId,description)" + " VALUES (?, ?, ?, ?, ?)"; pstatement = conn.prepareStatement(queryString); pstatement.setInt(1, activityId); pstatement.setString(2, name); pstatement.setString(3, activityType); pstatement.setInt(4, parentId); pstatement.setString(5, description); } catch (Exception ex) { out.println("Unable to connect to batabase."); } finally { pstatement.close(); conn.close(); } %> </body> </html>

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• Creating a HTTP handler for IIS that transparently forwards request to different port?

  - by Lasse V. Karlsen

  I have a public web server with the following software installed: IIS7 on port 80 Subversion over apache on port 81 TeamCity over apache on port 82 Unfortunately, both Subversion and TeamCity comes with their own web server installations, and they work flawlessly, so I don't really want to try to move them all to run under IIS, if that is even possible. However, I was looking at IIS and I noticed the HTTP redirect part, and I was wondering... Would it be possible for me to create a HTTP handler, and install it on a sub-domain under IIS7, so that all requests to, say, http://svn.vkarlsen.no/anything/here is passed to my HTTP handler, which then subsequently creates a request to http://localhost:81/anything/here, retrieves the data, and passes it on to the original requestee? In other words, I would like IIS to handle transparent forwards to port 81 and 82, without using the redirection features. For instance, Subversion doesn't like HTTP redirect and just says that the repository has been moved, and I need to relocate my working copy. That's not what I want. If anyone thinks this can be done, does anyone have any links to topics I need to read up on? I think I can manage the actual request parts, even with authentication, but I have no idea how to create a HTTP handler. Also bear in mind that I need to handle sub-paths and documents beneath the top-level domain, so http://svn.vkarlsen.no/whatever/here needs to be handled by a single handler, I cannot create copies of the handler for all sub-directories since paths are created from time to time.

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• C# IOException: The process cannot access the file because it is being used by another process.

  - by Michiel Bester

  Hi, I have a slight problem. What my application is supose to do, is to watch a folder for any newly copied file with the extention '.XSD' open the file and assign the lines to an array. After that the data from the array should be inserted into a MySQL database, then move the used file to another folder if it's done. The problem is that the application works fine with the first file, but as soon as the next file is copied to the folder I get this exception for example: 'The process cannot access the file 'C:\inetpub\admission\file2.XPD' because it is being used by another process'. If two files on the onther hand is copied at the same time there's no problem at all. The following code is on the main window: public partial class Form1 : Form { static string folder = specified path; static FileProcessor processor; public Form1() { InitializeComponent(); processor = new FileProcessor(); InitializeWatcher(); } static FileSystemWatcher watcher; static void InitializeWatcher() { watcher = new FileSystemWatcher(); watcher.Path = folder; watcher.Created += new FileSystemEventHandler(watcher_Created); watcher.EnableRaisingEvents = true; watcher.Filter = "*.XPD"; } static void watcher_Created(object sender, FileSystemEventArgs e) { processor.QueueInput(e.FullPath); } } As you can see the file's path is entered into a queue for processing which is on another class called FileProcessor: class FileProcessor { private Queue<string> workQueue; private Thread workerThread; private EventWaitHandle waitHandle; public FileProcessor() { workQueue = new Queue<string>(); waitHandle = new AutoResetEvent(true); } public void QueueInput(string filepath) { workQueue.Enqueue(filepath); if (workerThread == null) { workerThread = new Thread(new ThreadStart(Work)); workerThread.Start(); } else if (workerThread.ThreadState == ThreadState.WaitSleepJoin) { waitHandle.Set(); } } private void Work() { while (true) { string filepath = RetrieveFile(); if (filepath != null) ProcessFile(filepath); else waitHandle.WaitOne(); } } private string RetrieveFile() { if (workQueue.Count > 0) return workQueue.Dequeue(); else return null; } private void ProcessFile(string filepath) { string xName = Path.GetFileName(filepath); string fName = Path.GetFileNameWithoutExtension(filepath); string gfolder = specified path; bool fileInUse = true; string line; string[] itemArray = null; int i = 0; #region Declare Db variables //variables for each field of the database is created here #endregion #region Populate array while (fileInUse == true) { FileStream fs = new FileStream(filepath, FileMode.Open, FileAccess.Read, FileShare.ReadWrite); StreamReader reader = new StreamReader(fs); itemArray = new string[75]; while (!reader.EndOfStream == true) { line = reader.ReadLine(); itemArray[i] = line; i++; } fs.Flush(); reader.Close(); reader.Dispose(); i = 0; fileInUse = false; } #endregion #region Assign Db variables //here all the variables get there values from the array #endregion #region MySql Connection //here the connection to mysql is made and the variables are inserted into the db #endregion #region Test and Move file if (System.IO.File.Exists(gfolder + xName)) { System.IO.File.Delete(gfolder + xName); } Directory.Move(filepath, gfolder + xName); #endregion } } The problem I get occurs in the Populate array region. I read alot of other threads and was lead to believe that by flushing the file stream would help... I am also thinking of adding a try..catch for if the file process was successful, the file is moved to gfolder and if it failed, moved to bfolder Any help would be awesome Tx

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• how to append a string to next line in perl

  - by tprayush

  hi all , i have a requirement like this.. this just a sample script... $ cat test.sh #!/bin/bash perl -e ' open(IN,"addrss"); open(out,">>addrss"); @newval; while (<IN>) { @col_val=split(/:/); if ($.==1) { for($i=0;$i<=$#col_val;$i++) { print("Enter value for $col_val[$i] : "); chop($newval[$i]=<STDIN>); } $str=join(":"); $_="$str" print OUT; } else { exit 0; } } close(IN); close(OUT); ' when i run this scipt... $ ./test.sh Enter value for NAME : abc Enter value for ADDRESS : asff35 Enter value for STATE : XYZ Enter value for CITY : EIDHFF Enter value for CONTACT : 234656758 $ cat addrss NAME:ADDRESS:STATE:CITY:CONTACT abc:asff35:XYZ:EIDHFF:234656758 when ran it second time $ cat addrss NAME:ADDRESS:STATE:CITY:CONTACT abc:asff35:XYZ:EIDHFF:234656758ioret:56fgdh:ghdgh:afdfg:987643221 ## it is appended in the same line... i want it to be added to the next line..... NOTE: i want to do this by explitly using the filehandles in perl....and not with redirection operators in shell. please help me!!!

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