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  • "Address of" (&) an array / address of being ignored be gcc?

    - by dbarbosa
    Hi, I am a teaching assistant of a introductory programming course, and some students made this type of error: char name[20]; scanf("%s",&name); which is not surprising as they are learning... What is surprising is that, besides gcc warning, the code works (at least this part). I have been trying to understand and I wrote the following code: void foo(int *str1, int *str2) { if (str1 == str2) printf("Both pointers are the same\n"); else printf("They are not the same\n"); } int main() { int test[50]; foo(&test, test); if (&test == test) printf("Both pointers are the same\n"); else printf("They are not the same\n"); } Compiling and executing: $ gcc test.c -g test.c: In function ‘main’: test.c:12: warning: passing argument 1 of ‘foo’ from incompatible pointer type test.c:13: warning: comparison of distinct pointer types lacks a cast $ ./a.out Both pointers are the same Both pointers are the same Can anyone explain why they are not different? I suspect it is because I cannot get the address of an array (as I cannot have & &x), but in this case the code should not compile.

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  • Simulation tree command in C

    - by Ecle
    I have to create the simulation of tree command in C, this is my current code: #include <stdio.h> #include <sys/types.h> #include <sys/stat.h> #include <dirent.h> #include <string.h> main(int argc, char *argv[]){ int i; if(argc < 2){ printf("\nError. Use: %s directory\n", argv[0]); system("exit"); } for(i=1;i<argc;i++) //if(argv[i][0] != '-') tree(argv[i]); } tree(char *ruta){ DIR *dirp; struct dirent *dp; static nivel = 0; struct stat buf; char fichero[256]; int i; if((dirp = opendir(path)) == NULL){ perror(path); return; } while((dp = readdir(dirp)) != NULL){ printf(fichero, "%s/%s", path, dp->d_name); if((buf.st_mode & S_IFMT) == S_IFDIR){ for(i=0;i<nivel;i++) printf("\t"); printf("%s\n", dp->d_name); ++nivel; tree(fichero); --nivel; } } } Apparently, it works! (due to it compiles correctly) But I don't why. I can't pass the correct arguments to execute this. Thank you so much, people.

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  • Using the read function to read in a file.

    - by robUK
    Hello, gcc 4.4.1 I am using the read function to read in a wave file. However, when it gets to the read function. Execution seems to stop and freezes. I am wondering if I am doing anything wrong with this. The file size test-short.wave is: 514K. What I am aiming for is to read the file into the memory buffer chunks at a time. Currently I just testing this. Many thanks for any suggestions, #include <stdio.h> #include <stdlib.h> #include <errno.h> #include <fcntl.h> #include <string.h> #include <unistd.h> int main(void) { char buff = malloc(10240); int32_t fd = 0; int32_t bytes_read = 0; char *filename = "test-short.wav"; /* open wave file */ if((fd = (open(filename, O_RDWR)) == -1)) { fprintf(stderr, "open [ %s ]\n", strerror(errno)); return 1; } printf("Opened file [ %s ]\n", filename); printf("sizeof(buff) [ %d ]\n", sizeof(buff)); printf("strlen(buff) [ %d ]\n", strlen(buff)); bytes_read = read(fd, buff, sizeof(buff)); printf("Bytes read [ %d ]\n", bytes_read); return 0; }

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  • Storing "binary" data type in C program

    - by puchu
    I need to create a program that converts one number system to other number systems. I used itoa in Windows (Dev C++) and my only problem is that I do not know how to convert binary numbers to other number systems. All the other number systems conversion work accordingly. Does this involve something like storing the input to be converted using %? Here is a snippet of my work: case 2: { printf("\nEnter a binary number: "); scanf("%d", &num); itoa(num,buffer,8); printf("\nOctal %s",buffer); itoa(num,buffer,10); printf("\nDecimal %s",buffer); itoa(num,buffer,16); printf("\nHexadecimal %s \n",buffer); break; } For decimal I used %d, for octal I used %o and for hexadecimal I used %x. What could be the correct one for binary? Thanks for future answers!

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  • Using functions and arrays

    - by Ordo
    Hello! My little program below shall take 5 numbers from the user, store them into an array of integers and use a function to print them out. Sincerly it doesn't work and my output is always "00000". I can't find a mistake, so i would be glad about any advice. Thanks. #include <stdio.h> void printarray(int intarray[], int n) { int i; for(i = 0; i < n; i ++) { printf("%d", intarray[i]); } } int main () { const int n = 5; int temp = 0; int i; int intarray [n]; char check; printf("Please type in your numbers!\n"); for(i = 0; i < n; i ++) { printf(""); scanf("&d", &temp); intarray[i] = temp; getchar(); getchar(); } printf("Do you want to print them out? (yes/no): "); scanf("%c", &check); if (check == 'y') printarray(intarray, n); getchar(); getchar(); return 0; }

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  • Can somebody please explain this recursive function for me?

    - by capncoolio
    #include <stdio.h> #include <stdlib.h> void reprint(char *a[]) { if(*a) { printf("%d ",a); reprint(a+1); printf("%s ",*a); } } int main() { char *coll[] = {"C", "Objective", "like", "don't", "I", NULL}; reprint(coll); printf("\n"); return EXIT_SUCCESS; } As the more experienced will know, this prints the array in reverse. I don't quite understand how! I need help understanding what reprint(char *a[]) does. I understand pointer arithmetic to a degree, but from inserting printf's here and there, I've determined that the function increments up to the array end, and then back down to the start, only printing on the way down. However, I do not understand how it does this; all I've managed to understand by looking at the actual code is that if *a isn't NULL, then call reprint again, at the next index. Thanks guys!

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  • dividing two array elements

    - by pradeep
    main() { int prime_array[2339],prime1_count=0,mul1_count=0; int i, prime, lim_up, lim_low, n,j=0; int mul,count=0; int mul_count[65026]={0},number[7096]; printf("\n ENTER THE LOWER LIMIT…: "); scanf("%d", &lim_low); printf("\n ENTER THE UPPER LIMIT…: "); scanf("%d", &lim_up); for(n=lim_low+1; n<lim_up; n++) { prime = 1; for(i=2; i<n; i++) if(n%i == 0) { prime = 0; break; } if(prime) { prime_array[j]=n; j++; } } for(i=1;i<=255;i++) { for(j=1;j<=255;j++) { mul = j*i; mul_count[mul]++; } } for(i=1;i<=65025;i++) if( mul_count[i]!=2 && mul_count[i]!=0 ) { number[count]=i; count++; } for(prime1_count=0;prime1_count<2339;prime1_count++) { printf("\nprime number used is:%d",prime_array[prime1_count]); for(mul1_count=0;mul1_count<7096;mul1_count++) { printf("\n%d\t",number[mul1_count] % prime_array[prime1_count]); } } } I want to find the modulus of (number[mul1_count] % prime_array[prime1_count] ), but the output which I get is wrong. What is the mistake here. The prime number should be in the range 40000 to 65025. What changes should i make here?

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  • how to count multiples of numbers in an input file?

    - by user292489
    i was trying to count the number of multiples of 2, 3, and 6 respectielly from the users input file. but for some reason, my counter is not working. can any bosy hep me please. my code: #include <stdio.h> int main (void) { int num[12]; int i; int counttwo; int countthree; int countsix; int total=0; printf("enter 12 integer numbers:\n"); for(i=0;i<12;i++){ scanf("%d", &num[i]); } for(i=0;i<12;i++){ counttwo=0; if(num[i]%2==0){ counttwo++; } countthree=0; if(num[i]%3==0) { countthree++; } countsix=0; if(num[i]%6==0) { countsix++; } printf("There are %d multiples of 2:\n", counttwo); printf("There are %d multiples of 3:\n", countthree); printf("There are %d multiples of 6:\n", countsix); } return 0; }

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  • Without LIB And String file how can i write this code??

    - by muhammadlodhi
    #include<stdio.h> #include<conio.h> #include<stdlib.h> #include<string.h> struct Node; typedef struct Node * PtrToNode; struct Node { char element; PtrToNode Next; }; PtrToNode MakeEmpty(PtrToNode L) { L= new(Node); L->Next=NULL; return L; } void Push(PtrToNode L,char x) { PtrToNode S; S= new(Node); S->element=x; S->Next=L->Next; L->Next=S; } char Pop(PtrToNode L) { PtrToNode P; P=L->Next; char x=P->element; L->Next=P->Next; free(P); return x; } int main() { PtrToNode L; L= MakeEmpty(NULL); char Input[1000]; int i; printf("please enter your equation:"); scanf("%s",Input); for (i = 0;i<strlen(Input);i++) { if (Input[i]=='(') { Push(L,Input[i]); } if (Input[i]==')') { if (L->Next==NULL) { printf("incorrect"); return 0; } else Pop(L); } } if (L->Next==NULL) printf("correct"); else printf("incorrect"); getch(); return 0; }

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  • Can I access type int (*)[] with [][]?

    - by Framester
    Hi coming from this question "What does (int (*)[])var1 stand for?" I tried to access the result of the cast like a multidimensional array. But I get following error: "assignment from incompatible pointer type" followed by a segmentation fault. I tried also some other variations, but none of them worked. How can I access the elements in var1 in the function example directly? Thank you! #include <stdlib.h> int i(int n,int m,int var1[n][m]) { var1[0][0]=5; return var1[0][0]; } int example() { int *var1 = malloc(100); // works int var2; var2 = i(10,10,(int (*)[])var1); printf("var2=%i",var2); //doesn't work I int *var3; var3=(int (*)[])var1; //"assignment from incompatible pointer type" printf("var3[0][0]=%i",var3[0][0]); //doesn't work II int *var4; var4=var1; printf("var4[0][0]=%i",var4[0][0]); //" error: subscripted value is neither array nor pointer" //doesn't work III int **var5; var5=var1; printf("var5[0][0]=%i",var5[0][0]); // assignment from incompatible pointer type return(1); } int main(){ int a; a=example(); return(1); }

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  • Calling recursive function twice consecutively

    - by Zack
    #include <stdio.h> #define LENGTH 16 void makeBranches(int, int); void display(int, int); int main(){ makeBranches(0, LENGTH-1); } void makeBranches(int left, int right){ if(left >= right){ return; } else{ display(left, right); makeBranches(left, (right+left)/2); makeBranches((right+left/2)+1, right); } } void display(int left, int right){ printf("%d, %d", left, right); int mid = (left+right)/2; int i; for(i = left; i <= right; i++){ if(i == mid) printf("X"); else printf("-"); } if(right == LENGTH-1) printf("\n"); } The problem that I am having is the second call of makeBranches only executes with the values that caused the first call of makeBranches to return and not the original values that the first call used.

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  • Adding DTrace Probes to PHP Extensions

    - by cj
    The powerful DTrace tracing facility has some PHP-specific probes that can be enabled with --enable-dtrace. DTrace for Linux is being created by Oracle and is currently in tech preview. Currently it doesn't support userspace tracing so, in the meantime, Systemtap can be used to monitor the probes implemented in PHP. This was recently outlined in David Soria Parra's post Probing PHP with Systemtap on Linux. My post shows how DTrace probes can be added to PHP extensions and traced on Linux. I was using Oracle Linux 6.3. Not all Linux kernels are built with Systemtap, since this can impact stability. Check whether your running kernel (or others installed) have Systemtap enabled, and reboot with such a kernel: # grep CONFIG_UTRACE /boot/config-`uname -r` # grep CONFIG_UTRACE /boot/config-* When you install Systemtap itself, the package systemtap-sdt-devel is needed since it provides the sdt.h header file: # yum install systemtap-sdt-devel You can now install and build PHP as shown in David's article. Basically the build is with: $ cd ~/php-src $ ./configure --disable-all --enable-dtrace $ make (For me, running 'make' a second time failed with an error. The workaround is to do 'git checkout Zend/zend_dtrace.d' and then rerun 'make'. See PHP Bug 63704) David's article shows how to trace the probes already implemented in PHP. You can also use Systemtap to trace things like userspace PHP function calls. For example, create test.php: <?php $c = oci_connect('hr', 'welcome', 'localhost/orcl'); $s = oci_parse($c, "select dbms_xmlgen.getxml('select * from dual') xml from dual"); $r = oci_execute($s); $row = oci_fetch_array($s, OCI_NUM); $x = $row[0]->load(); $row[0]->free(); echo $x; ?> The normal output of this file is the XML form of Oracle's DUAL table: $ ./sapi/cli/php ~/test.php <?xml version="1.0"?> <ROWSET> <ROW> <DUMMY>X</DUMMY> </ROW> </ROWSET> To trace the PHP function calls, create the tracing file functrace.stp: probe process("sapi/cli/php").function("zif_*") { printf("Started function %s\n", probefunc()); } probe process("sapi/cli/php").function("zif_*").return { printf("Ended function %s\n", probefunc()); } This makes use of the way PHP userspace functions (not builtins) like oci_connect() map to C functions with a "zif_" prefix. Login as root, and run System tap on the PHP script: # cd ~cjones/php-src # stap -c 'sapi/cli/php ~cjones/test.php' ~cjones/functrace.stp Started function zif_oci_connect Ended function zif_oci_connect Started function zif_oci_parse Ended function zif_oci_parse Started function zif_oci_execute Ended function zif_oci_execute Started function zif_oci_fetch_array Ended function zif_oci_fetch_array Started function zif_oci_lob_load <?xml version="1.0"?> <ROWSET> <ROW> <DUMMY>X</DUMMY> </ROW> </ROWSET> Ended function zif_oci_lob_load Started function zif_oci_free_descriptor Ended function zif_oci_free_descriptor Each call and return is logged. The Systemtap scripting language allows complex scripts to be built. There are many examples on the web. To augment this generic capability and the PHP probes in PHP, other extensions can have probes too. Below are the steps I used to add probes to OCI8: I created a provider file ext/oci8/oci8_dtrace.d, enabling three probes. The first one will accept a parameter that runtime tracing can later display: provider php { probe oci8__connect(char *username); probe oci8__nls_start(); probe oci8__nls_done(); }; I updated ext/oci8/config.m4 with the PHP_INIT_DTRACE macro. The patch is at the end of config.m4. The macro takes the provider prototype file, a name of the header file that 'dtrace' will generate, and a list of sources files with probes. When --enable-dtrace is used during PHP configuration, then the outer $PHP_DTRACE check is true and my new probes will be enabled. I've chosen to define an OCI8 specific macro, HAVE_OCI8_DTRACE, which can be used in the OCI8 source code: diff --git a/ext/oci8/config.m4 b/ext/oci8/config.m4 index 34ae76c..f3e583d 100644 --- a/ext/oci8/config.m4 +++ b/ext/oci8/config.m4 @@ -341,4 +341,17 @@ if test "$PHP_OCI8" != "no"; then PHP_SUBST_OLD(OCI8_ORACLE_VERSION) fi + + if test "$PHP_DTRACE" = "yes"; then + AC_CHECK_HEADERS([sys/sdt.h], [ + PHP_INIT_DTRACE([ext/oci8/oci8_dtrace.d], + [ext/oci8/oci8_dtrace_gen.h],[ext/oci8/oci8.c]) + AC_DEFINE(HAVE_OCI8_DTRACE,1, + [Whether to enable DTrace support for OCI8 ]) + ], [ + AC_MSG_ERROR( + [Cannot find sys/sdt.h which is required for DTrace support]) + ]) + fi + fi In ext/oci8/oci8.c, I added the probes at, for this example, semi-arbitrary places: diff --git a/ext/oci8/oci8.c b/ext/oci8/oci8.c index e2241cf..ffa0168 100644 --- a/ext/oci8/oci8.c +++ b/ext/oci8/oci8.c @@ -1811,6 +1811,12 @@ php_oci_connection *php_oci_do_connect_ex(char *username, int username_len, char } } +#ifdef HAVE_OCI8_DTRACE + if (DTRACE_OCI8_CONNECT_ENABLED()) { + DTRACE_OCI8_CONNECT(username); + } +#endif + /* Initialize global handles if they weren't initialized before */ if (OCI_G(env) == NULL) { php_oci_init_global_handles(TSRMLS_C); @@ -1870,11 +1876,22 @@ php_oci_connection *php_oci_do_connect_ex(char *username, int username_len, char size_t rsize = 0; sword result; +#ifdef HAVE_OCI8_DTRACE + if (DTRACE_OCI8_NLS_START_ENABLED()) { + DTRACE_OCI8_NLS_START(); + } +#endif PHP_OCI_CALL_RETURN(result, OCINlsEnvironmentVariableGet, (&charsetid_nls_lang, 0, OCI_NLS_CHARSET_ID, 0, &rsize)); if (result != OCI_SUCCESS) { charsetid_nls_lang = 0; } smart_str_append_unsigned_ex(&hashed_details, charsetid_nls_lang, 0); + +#ifdef HAVE_OCI8_DTRACE + if (DTRACE_OCI8_NLS_DONE_ENABLED()) { + DTRACE_OCI8_NLS_DONE(); + } +#endif } timestamp = time(NULL); The oci_connect(), oci_pconnect() and oci_new_connect() calls all use php_oci_do_connect_ex() internally. The first probe simply records that the PHP application made a connection call. I already showed a way to do this without needing a probe, but adding a specific probe lets me record the username. The other two probes can be used to time how long the globalization initialization takes. The relationships between the oci8_dtrace.d names like oci8__connect, the probe guards like DTRACE_OCI8_CONNECT_ENABLED() and probe names like DTRACE_OCI8_CONNECT() are obvious after seeing the pattern of all three probes. I included the new header that will be automatically created by the dtrace tool when PHP is built. I did this in ext/oci8/php_oci8_int.h: diff --git a/ext/oci8/php_oci8_int.h b/ext/oci8/php_oci8_int.h index b0d6516..c81fc5a 100644 --- a/ext/oci8/php_oci8_int.h +++ b/ext/oci8/php_oci8_int.h @@ -44,6 +44,10 @@ # endif # endif /* osf alpha */ +#ifdef HAVE_OCI8_DTRACE +#include "oci8_dtrace_gen.h" +#endif + #if defined(min) #undef min #endif Now PHP can be rebuilt: $ cd ~/php-src $ rm configure && ./buildconf --force $ ./configure --disable-all --enable-dtrace \ --with-oci8=instantclient,/home/cjones/instantclient $ make If 'make' fails, do the 'git checkout Zend/zend_dtrace.d' trick I mentioned. The new probes can be seen by logging in as root and running: # stap -l 'process.provider("php").mark("oci8*")' -c 'sapi/cli/php -i' process("sapi/cli/php").provider("php").mark("oci8__connect") process("sapi/cli/php").provider("php").mark("oci8__nls_done") process("sapi/cli/php").provider("php").mark("oci8__nls_start") To test them out, create a new trace file, oci.stp: global numconnects; global start; global numcharlookups = 0; global tottime = 0; probe process.provider("php").mark("oci8-connect") { printf("Connected as %s\n", user_string($arg1)); numconnects += 1; } probe process.provider("php").mark("oci8-nls_start") { start = gettimeofday_us(); numcharlookups++; } probe process.provider("php").mark("oci8-nls_done") { tottime += gettimeofday_us() - start; } probe end { printf("Connects: %d, Charset lookups: %ld\n", numconnects, numcharlookups); printf("Total NLS charset initalization time: %ld usecs/connect\n", (numcharlookups 0 ? tottime/numcharlookups : 0)); } This calculates the average time that the NLS character set lookup takes. It also prints out the username of each connection, as an example of using parameters. Login as root and run Systemtap over the PHP script: # cd ~cjones/php-src # stap -c 'sapi/cli/php ~cjones/test.php' ~cjones/oci.stp Connected as cj <?xml version="1.0"?> <ROWSET> <ROW> <DUMMY>X</DUMMY> </ROW> </ROWSET> Connects: 1, Charset lookups: 1 Total NLS charset initalization time: 164 usecs/connect This shows the time penalty of making OCI8 look up the default character set. This time would be zero if a character set had been passed as the fourth argument to oci_connect() in test.php.

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  • Compare images after canny edge detection in OpenCV (C++)

    - by typoknig
    Hi all, I am working on an OpenCV project and I need to compare some images after canny has been applied to both of them. Before the canny was applied I had the gray scale images populating a histogram and then I compared the histograms, but when canny is added to the images the histogram does not populate. I have read that a canny image can populate a histogram, but have not found a way to make it happen. I do not necessairly need to keep using the histograms, I just want to know the best way to compare two canny images. SSCCE below for you to chew on. I have poached and patched about 75% of this code from books and various sites on the internet, so props to those guys... // SLC (Histogram).cpp : Defines the entry point for the console application. #include "stdafx.h" #include <cxcore.h> #include <cv.h> #include <cvaux.h> #include <highgui.h> #include <stdio.h> #include <sstream> #include <iostream> using namespace std; IplImage* image1= 0; IplImage* imgHistogram1 = 0; IplImage* gray1= 0; CvHistogram* hist1; int main(){ CvCapture* capture = cvCaptureFromCAM(0); if(!cvQueryFrame(capture)){ cout<<"Video capture failed, please check the camera."<<endl; } else{ cout<<"Video camera capture successful!"<<endl; }; CvSize sz = cvGetSize(cvQueryFrame(capture)); IplImage* image = cvCreateImage(sz, 8, 3); IplImage* imgHistogram = 0; IplImage* gray = 0; CvHistogram* hist; cvNamedWindow("Image Source",1); cvNamedWindow("gray", 1); cvNamedWindow("Histogram",1); cvNamedWindow("BG", 1); cvNamedWindow("FG", 1); cvNamedWindow("Canny",1); cvNamedWindow("Canny1", 1); image1 = cvLoadImage("image bin/use this image.jpg");// an image has to load here or the program will not run //size of the histogram -1D histogram int bins1 = 256; int hsize1[] = {bins1}; //max and min value of the histogram float max_value1 = 0, min_value1 = 0; //value and normalized value float value1; int normalized1; //ranges - grayscale 0 to 256 float xranges1[] = { 0, 256 }; float* ranges1[] = { xranges1 }; //create an 8 bit single channel image to hold a //grayscale version of the original picture gray1 = cvCreateImage( cvGetSize(image1), 8, 1 ); cvCvtColor( image1, gray1, CV_BGR2GRAY ); IplImage* canny1 = cvCreateImage(cvGetSize(gray1), 8, 1 ); cvCanny( gray1, canny1, 55, 175, 3 ); //Create 3 windows to show the results cvNamedWindow("original1",1); cvNamedWindow("gray1",1); cvNamedWindow("histogram1",1); //planes to obtain the histogram, in this case just one IplImage* planes1[] = { canny1 }; //get the histogram and some info about it hist1 = cvCreateHist( 1, hsize1, CV_HIST_ARRAY, ranges1,1); cvCalcHist( planes1, hist1, 0, NULL); cvGetMinMaxHistValue( hist1, &min_value1, &max_value1); printf("min: %f, max: %f\n", min_value1, max_value1); //create an 8 bits single channel image to hold the histogram //paint it white imgHistogram1 = cvCreateImage(cvSize(bins1, 50),8,1); cvRectangle(imgHistogram1, cvPoint(0,0), cvPoint(256,50), CV_RGB(255,255,255),-1); //draw the histogram :P for(int i=0; i < bins1; i++){ value1 = cvQueryHistValue_1D( hist1, i); normalized1 = cvRound(value1*50/max_value1); cvLine(imgHistogram1,cvPoint(i,50), cvPoint(i,50-normalized1), CV_RGB(0,0,0)); } //show the image results cvShowImage( "original1", image1 ); cvShowImage( "gray1", gray1 ); cvShowImage( "histogram1", imgHistogram1 ); cvShowImage( "Canny1", canny1); CvBGStatModel* bg_model = cvCreateFGDStatModel( image ); for(;;){ image = cvQueryFrame(capture); cvUpdateBGStatModel( image, bg_model ); //Size of the histogram -1D histogram int bins = 256; int hsize[] = {bins}; //Max and min value of the histogram float max_value = 0, min_value = 0; //Value and normalized value float value; int normalized; //Ranges - grayscale 0 to 256 float xranges[] = {0, 256}; float* ranges[] = {xranges}; //Create an 8 bit single channel image to hold a grayscale version of the original picture gray = cvCreateImage(cvGetSize(image), 8, 1); cvCvtColor(image, gray, CV_BGR2GRAY); IplImage* canny = cvCreateImage(cvGetSize(gray), 8, 1 ); cvCanny( gray, canny, 55, 175, 3 );//55, 175, 3 with direct light //Planes to obtain the histogram, in this case just one IplImage* planes[] = {canny}; //Get the histogram and some info about it hist = cvCreateHist(1, hsize, CV_HIST_ARRAY, ranges,1); cvCalcHist(planes, hist, 0, NULL); cvGetMinMaxHistValue(hist, &min_value, &max_value); //printf("Minimum Histogram Value: %f, Maximum Histogram Value: %f\n", min_value, max_value); //Create an 8 bits single channel image to hold the histogram and paint it white imgHistogram = cvCreateImage(cvSize(bins, 50),8,3); cvRectangle(imgHistogram, cvPoint(0,0), cvPoint(256,50), CV_RGB(255,255,255),-1); //Draw the histogram for(int i=0; i < bins; i++){ value = cvQueryHistValue_1D(hist, i); normalized = cvRound(value*50/max_value); cvLine(imgHistogram,cvPoint(i,50), cvPoint(i,50-normalized), CV_RGB(0,0,0)); } double correlation = cvCompareHist (hist1, hist, CV_COMP_CORREL); double chisquare = cvCompareHist (hist1, hist, CV_COMP_CHISQR); double intersection = cvCompareHist (hist1, hist, CV_COMP_INTERSECT); double bhattacharyya = cvCompareHist (hist1, hist, CV_COMP_BHATTACHARYYA); double difference = (1 - correlation) + chisquare + (1 - intersection) + bhattacharyya; printf("correlation: %f\n", correlation); printf("chi-square: %f\n", chisquare); printf("intersection: %f\n", intersection); printf("bhattacharyya: %f\n", bhattacharyya); printf("difference: %f\n", difference); cvShowImage("Image Source", image); cvShowImage("gray", gray); cvShowImage("Histogram", imgHistogram); cvShowImage( "Canny", canny); cvShowImage("BG", bg_model->background); cvShowImage("FG", bg_model->foreground); //Page 19 paragraph 3 of "Learning OpenCV" tells us why we DO NOT use "cvReleaseImage(&image)" in this section cvReleaseImage(&imgHistogram); cvReleaseImage(&gray); cvReleaseHist(&hist); cvReleaseImage(&canny); char c = cvWaitKey(10); //if ASCII key 27 (esc) is pressed then loop breaks if(c==27) break; } cvReleaseBGStatModel( &bg_model ); cvReleaseImage(&image); cvReleaseCapture(&capture); cvDestroyAllWindows(); }

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  • error in coding a lexer in c

    - by mekasperasky
    #include<stdio.h> #include<ctype.h> #include<string.h> /* this is a lexer which recognizes constants , variables ,symbols, identifiers , functions , comments and also header files . It stores the lexemes in 3 different files . One file contains all the headers and the comments . Another file will contain all the variables , another will contain all the symbols. */ int main() { int i=0,j,k,count=0; char a,b[100],c[10000],d[100]; memset ( d, 0, 100 ); j=30; FILE *fp1,*fp2; fp1=fopen("source.txt","r"); //the source file is opened in read only mode which will passed through the lexer fp2=fopen("lext.txt","w"); //now lets remove all the white spaces and store the rest of the words in a file if(fp1==NULL) { perror("failed to open source.txt"); //return EXIT_FAILURE; } i=0; k=0; while(!feof(fp1)) { a=fgetc(fp1); if(a!=' '&&a!='\n') { if (!isalpha(a)) { switch(a) { case '+':{fprintf(fp2,"+ ----> PLUS \n"); i=0;break;} case '-':{fprintf(fp2,"- ---> MINUS \n"); i=0;break;} case '*':{fprintf(fp2, "* --->MULT \n"); i=0;break;} case '/':{fprintf(fp2, "/ --->DIV \n"); i=0;break;} //case '+=':fprintf(fp2, "%.20s\n", "ADD_ASSIGN"); //case '-=':fprintf(fp2, "%.20s\n", "SUB_ASSIGN"); case '=':{fprintf(fp2, "= ---> ASSIGN \n"); i=0;break;} case '%':{fprintf(fp2, "% ---> MOD \n"); i=0;break;} case '<':{fprintf(fp2, "< ---> LESSER_THAN \n"); i=0;break;} case '>':{fprintf(fp2, "> --> GREATER_THAN \n"); i=0;break;} //case '++':fprintf(fp2, "%.20s\n", "INCREMENT"); //case '--':fprintf(fp2, "%.20s\n", "DECREMENT"); //case '==':fprintf(fp2, "%.20s\n", "ASSIGNMENT"); case ';':{fprintf(fp2, "; --->SEMI_COLUMN \n"); i=0;break;} case ':':{fprintf(fp2, ": --->COLUMN \n"); i=0;break;} case '(':{fprintf(fp2, "( --->LPAR \n"); i=0;break;} case ')':{fprintf(fp2, ") --->RPAR \n"); i=0;break;} case '{':{fprintf(fp2, "{ --->LBRACE \n"); i=0;break;} case '}':{fprintf(fp2, "} ---> RBRACE \n"); i=0;break;} } } else { d[i]=a; //printf("%c\n",d[i]); i=i+1; } //} /* we can make the lexer more complex by including even more depths of checks for the symbols*/ } else { d[i+1]='\0'; printf("\n"); if((strcmp(d,"if ")==0)){fprintf(fp2,"if ----> IDENTIFIER \n"); //printf("%s \n",d); memset ( d, 0, 100 ); //printf("%s \n",d); count=count+1;} else if(strcmp(d,"then")==0){fprintf(fp2,"then ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"else")==0){fprintf(fp2,"else ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"switch")==0){fprintf(fp2,"switch ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"printf")==0){fprintf(fp2,"prtintf ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"scanf")==0){fprintf(fp2,"scanf ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"NULL")==0){fprintf(fp2,"NULL ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"int")==0){fprintf(fp2,"INT ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"char")==0){fprintf(fp2,"char ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"float")==0){fprintf(fp2,"float ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"long")==0){fprintf(fp2,"long ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"double")==0){fprintf(fp2,"double ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"const")==0){fprintf(fp2,"const ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"continue")==0)fprintf(fp2,"continue ----> IDENTIFIER \n"); else if(strcmp(d,"size of")==0){fprintf(fp2,"size of ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"register")==0){fprintf(fp2,"register ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"short")==0){fprintf(fp2,"short ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"auto")==0){fprintf(fp2,"auto ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"while")==0){fprintf(fp2,"while ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"do")==0){fprintf(fp2,"do ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"case")==0){fprintf(fp2,"case ----> IDENTIFIER \n"); count=count+1;} else if (isdigit(d[i])) { fprintf(fp2,"%s ---->NUMBER",d); } else if (isalpha(a)) { fprintf(fp2,"%s ----> Variable",d); //printf("%s",d); // memset ( d, 0, 100 );} //fprintf(fp2, "s\n", b); i=0; k=k+1; continue; } i=i+1; k=k+1; } fclose(fp1); fclose(fp2); printf("%d",count); return 0; } In this code , my source.txt has if (a+b) stored . But only ( , + and ) is getting written into lext.txt and not the identifier if or the variable a and b . Any particular reason why?

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  • Why is phpseclib producing incompatible certs?

    - by chacham15
    Why is it that when I try to use a certificate/key pair generated from phpseclib, the OpenSSL server code errors out? Certs/Keys generated from OpenSSL work fine. How do I fix this? Certificate/Key Generation taken straight from phpseclib documentation: <?php include('File/X509.php'); include('Crypt/RSA.php'); // create private key / x.509 cert for stunnel / website $privKey = new Crypt_RSA(); extract($privKey-createKey()); $privKey-loadKey($privatekey); $pubKey = new Crypt_RSA(); $pubKey-loadKey($publickey); $pubKey-setPublicKey(); $subject = new File_X509(); $subject-setDNProp('id-at-organizationName', 'phpseclib demo cert'); //$subject-removeDNProp('id-at-organizationName'); $subject-setPublicKey($pubKey); $issuer = new File_X509(); $issuer-setPrivateKey($privKey); $issuer-setDN($subject-getDN()); $x509 = new File_X509(); //$x509-setStartDate('-1 month'); // default: now //$x509-setEndDate('+1 year'); // default: +1 year $result = $x509-sign($issuer, $subject); echo "the stunnel.pem contents are as follows:\r\n\r\n"; echo $privKey-getPrivateKey(); echo "\r\n"; echo $x509-saveX509($result); echo "\r\n"; ? OpenSSL sample SSL server taken straight from OpenSSL example code: #include <stdio.h #include <unistd.h #include <stdlib.h #include <memory.h #include <errno.h #include <sys/types.h #include <sys/socket.h #include <netinet/in.h #include <arpa/inet.h #include <netdb.h #include <openssl/rsa.h /* SSLeay stuff */ #include <openssl/crypto.h #include <openssl/x509.h #include <openssl/pem.h #include <openssl/ssl.h #include <openssl/err.h #define CHK_NULL(x) if ((x)==NULL) exit (1) #define CHK_ERR(err,s) if ((err)==-1) { perror(s); exit(1); } #define CHK_SSL(err) if ((err)==-1) { ERR_print_errors_fp(stderr); exit(2); } int main (int argc, char *argv[]) { int err; int listen_sd; int sd; struct sockaddr_in sa_serv; struct sockaddr_in sa_cli; size_t client_len; SSL_CTX* ctx; SSL* ssl; X509* client_cert; char* str; char buf [4096]; SSL_METHOD *meth; /* SSL preliminaries. We keep the certificate and key with the context. */ SSL_load_error_strings(); SSLeay_add_ssl_algorithms(); meth = SSLv23_server_method(); ctx = SSL_CTX_new (meth); if (!ctx) { ERR_print_errors_fp(stderr); exit(2); } if (SSL_CTX_use_certificate_file(ctx, argv[1], SSL_FILETYPE_PEM) <= 0) { ERR_print_errors_fp(stderr); exit(3); } if (SSL_CTX_use_PrivateKey_file(ctx, argv[2], SSL_FILETYPE_PEM) <= 0) { ERR_print_errors_fp(stderr); exit(4); } if (!SSL_CTX_check_private_key(ctx)) { fprintf(stderr,"Private key does not match the certificate public key\n"); exit(5); } /* ----------------------------------------------- */ /* Prepare TCP socket for receiving connections */ listen_sd = socket (AF_INET, SOCK_STREAM, 0); CHK_ERR(listen_sd, "socket"); memset (&sa_serv, '\0', sizeof(sa_serv)); sa_serv.sin_family = AF_INET; sa_serv.sin_addr.s_addr = INADDR_ANY; sa_serv.sin_port = htons (1111); /* Server Port number */ err = bind(listen_sd, (struct sockaddr*) &sa_serv, sizeof (sa_serv)); CHK_ERR(err, "bind"); /* Receive a TCP connection. */ err = listen (listen_sd, 5); CHK_ERR(err, "listen"); client_len = sizeof(sa_cli); sd = accept (listen_sd, (struct sockaddr*) &sa_cli, (unsigned int*)&client_len); CHK_ERR(sd, "accept"); close (listen_sd); printf ("Connection from %lx, port %x\n", sa_cli.sin_addr.s_addr, sa_cli.sin_port); /* ----------------------------------------------- */ /* TCP connection is ready. Do server side SSL. */ ssl = SSL_new (ctx); CHK_NULL(ssl); SSL_set_fd (ssl, sd); err = SSL_accept (ssl); CHK_SSL(err); /* Get the cipher - opt */ printf ("SSL connection using %s\n", SSL_get_cipher (ssl)); /* Get client's certificate (note: beware of dynamic allocation) - opt */ client_cert = SSL_get_peer_certificate (ssl); if (client_cert != NULL) { printf ("Client certificate:\n"); str = X509_NAME_oneline (X509_get_subject_name (client_cert), 0, 0); CHK_NULL(str); printf ("\t subject: %s\n", str); OPENSSL_free (str); str = X509_NAME_oneline (X509_get_issuer_name (client_cert), 0, 0); CHK_NULL(str); printf ("\t issuer: %s\n", str); OPENSSL_free (str); /* We could do all sorts of certificate verification stuff here before deallocating the certificate. */ X509_free (client_cert); } else printf ("Client does not have certificate.\n"); /* DATA EXCHANGE - Receive message and send reply. */ err = SSL_read (ssl, buf, sizeof(buf) - 1); CHK_SSL(err); buf[err] = '\0'; printf ("Got %d chars:'%s'\n", err, buf); err = SSL_write (ssl, "I hear you.", strlen("I hear you.")); CHK_SSL(err); /* Clean up. */ close (sd); SSL_free (ssl); SSL_CTX_free (ctx); return 1; } /* EOF - serv.cpp */ This program errors with: (the error is printed out on the call to SSL_write) Connection from 100007f, port a7ff SSL connection using (NONE) Client does not have certificate. Got 0 chars:'' 82673:error:1409E0E5:SSL routines:SSL3_WRITE_BYTES:ssl handshake failure:/SourceCache/OpenSSL098/OpenSSL098-44/src/ssl/s3_pkt.c:539: Here is the relevant code referenced by the error: int ssl3_write_bytes(SSL *s, int type, const void *buf_, int len) { const unsigned char *buf=buf_; unsigned int tot,n,nw; int i; s-rwstate=SSL_NOTHING; tot=s-s3-wnum; s-s3-wnum=0; if (SSL_in_init(s) && !s-in_handshake) { i=s-handshake_func(s); if (i < 0) return(i); if (i == 0) { SSLerr(SSL_F_SSL3_WRITE_BYTES,SSL_R_SSL_HANDSHAKE_FAILURE); return -1; } } ...etc

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  • depth first search graph by using linked list

    - by programmerwannabe
    im using mac book and i cannot read the text file using this code. moreover, can you guys please add function(graph is connected?, and is this graph tree?) inputA.txt consist 1 2 1 6 1 5 2 3 2 6 3 4 3 6 4 5 4 6 5 6 #include <stdio.h> #include <memory.h> #include <stdlib.h> #define MAX 10 #define TRUE 1 #define FALSE 0 typedef struct Graph{ int vertex; struct Graph* link; } g_node; typedef struct graphType{ int x; int visited[MAX]; g_node* adjList_H[MAX]; } graphType; typedef struct stack{ int data; struct stack* link; } s_node; s_node* top; void push(int item){ s_node* n=(s_node*)malloc(sizeof(s_node)); n->data = item; n->link = top; top = n; } int pop(){ int item; s_node* n=top; if(top == NULL){ puts("\nstack is empty!\n"); return 0; } else { item = n-> data; top = n->link; free(n); return item; } } void createGraph(graphType* g){ int v; g->x = 1; for(v=1 ; v < MAX ; v++){ g -> visited[v] = FALSE; g -> adjList_H[v] = NULL; } } void insertVertex(graphType* g, int v){ if(((g->x)) > MAX){ puts("\n it has been overed the number of vertex\n"); return ; } g -> x++; } void insertEdge(graphType* g, int u, int v){ g_node* node; if(u >= g -> x || v >= g -> x){ puts("\n no vertex in the graph\n"); return ; } node = (g_node*)malloc(sizeof(g_node)); node -> vertex = v; node -> link = g -> adjList_H[u]; g-> adjList_H[u] = node; } void print_adjList(graphType* g){ int i; g_node *p; for(i=1 ; i<g -> x ; i++){ printf("\n\t\t vertex %d adjacency list ", i); p = g -> adjList_H[i]; while(p){ printf("-> %d", p-> vertex); p = p-> link; } } } void DFS_adjList(graphType* g, int v) { g_node* w; top = NULL; push(v); g->visited[v] = TRUE; printf(" %d", v); while(top != NULL){ w=g->adjList_H[v]; while(w){ if (!g->visited[w->vertex]){ push(w->vertex); g->visited[w->vertex] = TRUE; printf(" %d", w->vertex); v = w->vertex; w=g->adjList_H[v]; } else w= w->link; } v = pop(); } } int main (int argc, const char * argv[]) { FILE *fp; char mychar; char arr[][2]={0, }; int j, k; int i; graphType *G9; G9 = (graphType*)malloc(sizeof(graphType)); createGraph(G9); for(i=1; i<7 ; i++) insertVertex(G9, i); fp = fopen("inputD.txt", "r"); for(j = 0 ; j< 10 ; j++){ for(k = 0 ; k < 2 ; k++){ mychar = fgetc(fp); if(mychar = EOF){ j=10; break; } else if(mychar == ' ') continue; else if(mychar <= '9' || mychar >= '1'){ arr[j][k] = mychar; printf("%d%d", arr[i][k]); } } } insertEdge(G9, 1, 2); insertEdge(G9, 1, 6); insertEdge(G9, 1, 5); insertEdge(G9, 2, 3); insertEdge(G9, 2, 6); insertEdge(G9, 3, 4); insertEdge(G9, 3, 6); insertEdge(G9, 4, 5); insertEdge(G9, 4, 6); insertEdge(G9, 5, 6); insertEdge(G9, 6, 5); insertEdge(G9, 6, 4); insertEdge(G9, 5, 4); insertEdge(G9, 6, 3); insertEdge(G9, 4, 3); insertEdge(G9, 6, 2); insertEdge(G9, 3, 2); insertEdge(G9, 5, 1); insertEdge(G9, 6, 1); insertEdge(G9, 2, 1); printf("\n graph adjacency list "); print_adjList(G9); printf("\n \n//////////////////////////////////////////////\n\n depth fist search >> "); DFS_adjList(G9, 1); return 0; }

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  • How Do I Know the Memory Used by Apps

    - by user176890
    Is it possible to know the memory used by any apps running on my linux server? I'm using the following command to know how much memory used by php-fpm. ps -ylC php5-fpm --sort:rss | awk '!/RSS/ { s+=$8 } END { printf "%s\n", "Total memory used by PHP-FPM child processes: "; printf "%dM\n", s/1024 }' Given the command above, I want to know the memory used by all apps with an example output below: PHP-FPM: 2.3gb MySQL: 5gb nginx: 200mb dovecot: 100mb memcached: 573mb

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  • C command line password

    - by Jack Jacobsen
    So I'm trying to create a C program where you must input the password on the command line, like ./login password1 And if the password is password1, it'll say something. If not, it prints another message. This is the code I have now: #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { if (argc < 2) { printf("usage: %s <password>\n", argv[0]); } char pass = "password"; if (argc == pass) { printf("Right\n"); } else { printf("Wrong\n"); } } But it wont work.

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  • Scanf with Signals

    - by jreid42
    I have a signal that blocks SIGINT and basically says "Sorry, you can't quit.\n" The issue is this can occur during a scanf. When this occurs during a scanf, scanf takes in the printf as input. How can I do a printf that will cause scanf to basically hit the enter key automatically. I don't care that I am getting bad input. I just want to programatically finish that scanf with a printf or something else. Process: scanf("get stuff") - User is able to enter stuff in. - SIGINT occurs and goes to my handler. - Handler says "Blah blah blah" to stdout. - Scanf has taken this blah blah blah and is waiting for more input. How do I make it so that when I return scanf is finished (don't care what it has gathered I just want it to continue without user help).

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  • adding nodes to a binary search tree randomly deletes nodes

    - by SDLFunTimes
    Hi, stack. I've got a binary tree of type TYPE (TYPE is a typedef of data*) that can add and remove elements. However for some reason certain values added will overwrite previous elements. Here's my code with examples of it inserting without overwriting elements and it not overwriting elements. the data I'm storing: struct data { int number; char *name; }; typedef struct data data; # ifndef TYPE # define TYPE data* # define TYPE_SIZE sizeof(data*) # endif The tree struct: struct Node { TYPE val; struct Node *left; struct Node *rght; }; struct BSTree { struct Node *root; int cnt; }; The comparator for the data. int compare(TYPE left, TYPE right) { int left_len; int right_len; int shortest_string; /* find longest string */ left_len = strlen(left->name); right_len = strlen(right->name); if(right_len < left_len) { shortest_string = right_len; } else { shortest_string = left_len; } /* compare strings */ if(strncmp(left->name, right->name, shortest_string) > 1) { return 1; } else if(strncmp(left->name, right->name, shortest_string) < 1) { return -1; } else { /* strings are equal */ if(left->number > right->number) { return 1; } else if(left->number < right->number) { return -1; } else { return 0; } } } And the add method struct Node* _addNode(struct Node* cur, TYPE val) { if(cur == NULL) { /* no root has been made */ cur = _createNode(val); return cur; } else { int cmp; cmp = compare(cur->val, val); if(cmp == -1) { /* go left */ if(cur->left == NULL) { printf("adding on left node val %d\n", cur->val->number); cur->left = _createNode(val); } else { return _addNode(cur->left, val); } } else if(cmp >= 0) { /* go right */ if(cur->rght == NULL) { printf("adding on right node val %d\n", cur->val->number); cur->rght = _createNode(val); } else { return _addNode(cur->rght, val); } } return cur; } } void addBSTree(struct BSTree *tree, TYPE val) { tree->root = _addNode(tree->root, val); tree->cnt++; } The function to print the tree: void printTree(struct Node *cur) { if (cur == 0) { printf("\n"); } else { printf("("); printTree(cur->left); printf(" %s, %d ", cur->val->name, cur->val->number); printTree(cur->rght); printf(")\n"); } } Here's an example of some data that will overwrite previous elements: struct BSTree myTree; struct data myData1, myData2, myData3; myData1.number = 5; myData1.name = "rooty"; myData2.number = 1; myData2.name = "lefty"; myData3.number = 10; myData3.name = "righty"; initBSTree(&myTree); addBSTree(&myTree, &myData1); addBSTree(&myTree, &myData2); addBSTree(&myTree, &myData3); printTree(myTree.root); Which will print: (( righty, 10 ) lefty, 1 ) Finally here's some test data that will go in the exact same spot as the previous data, but this time no data is overwritten: struct BSTree myTree; struct data myData1, myData2, myData3; myData1.number = 5; myData1.name = "i"; myData2.number = 5; myData2.name = "h"; myData3.number = 5; myData3.name = "j"; initBSTree(&myTree); addBSTree(&myTree, &myData1); addBSTree(&myTree, &myData2); addBSTree(&myTree, &myData3); printTree(myTree.root); Which prints: (( j, 5 ) i, 5 ( h, 5 ) ) Does anyone know what might be going wrong? Sorry if this post was kind of long.

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  • ./a.out termniated . Garbage output due to smashing of stack . How to remove this error ?

    - by mekasperasky
    #include <iostream> #include <fstream> #include <cstring> using namespace std; typedef unsigned long int WORD; /* Should be 32-bit = 4 bytes */ #define w 32 /* word size in bits */ #define r 12 /* number of rounds */ #define b 16 /* number of bytes in key */ #define c 4 /* number words in key */ /* c = max(1,ceil(8*b/w)) */ #define t 26 /* size of table S = 2*(r+1) words */ WORD S [t],L[c]; /* expanded key table */ WORD P = 0xb7e15163, Q = 0x9e3779b9; /* magic constants */ /* Rotation operators. x must be unsigned, to get logical right shift*/ #define ROTL(x,y) (((x)<<(y&(w-1))) | ((x)>>(w-(y&(w-1))))) #define ROTR(x,y) (((x)>>(y&(w-1))) | ((x)<<(w-(y&(w-1))))) void RC5_ENCRYPT(WORD *pt, WORD *ct) /* 2 WORD input pt/output ct */ { WORD i, A=pt[0]+S[0], B=pt[1]+S[1]; for (i=1; i<=r; i++) { A = ROTL(A^B,B)+S[2*i]; B = ROTL(B^A,A)+S[2*i+1]; } ct [0] = A ; ct [1] = B ; } void RC5_DECRYPT(WORD *ct, WORD *pt) /* 2 WORD input ct/output pt */ { WORD i, B=ct[1], A=ct[ 0]; for (i=r; i>0; i--) { B = ROTR(B-S [2*i+1],A)^A; A = ROTR(A-S [2*i],B)^B; } pt [1] = B-S [1] ;pt [0] = A-S [0]; } void RC5_SETUP(unsigned char *K) /* secret input key K 0...b-1] */ { WORD i, j, k, u=w/8, A, B, L [c]; /* Initialize L, then S, then mix key into S */ for (i=b-1,L[c-1]=0; i!=-1; i--) L[i/u] = (L[i/u]<<8)+K[ i]; for (S [0]=P,i=1; i<t; i++) S [i] = S [i-1]+Q; for (A=B=i=j=k=0; k<3*t; k++,i=(i+1)%t,j=(j+1)%c) /* 3*t > 3*c */ { A = S[i] = ROTL(S [i]+(A+B),3); B = L[j] = ROTL(L[j]+(A+B),(A+B)); } } void printword(WORD A) { WORD k; for (k=0 ;k<w; k+=8) printf("%c"); } int main() { WORD i, j, k,ptext, pt1 [2], pt2 [2], ct [2] = {0,0}; ifstream in("key1.txt"); ifstream in1("plt.txt"); ofstream out1("cpt.txt"); if(!in) { cout << "Cannot open file.\n"; return 1; } if(!in1) { cout << "Cannot open file.\n"; return 1; } unsigned char key[b]; in >> key; in1 >> pt1[0]; in1 >> pt1[0]; if (sizeof(WORD)!=4) printf("RC5 error: WORD has %d bytes.\n",sizeof(WORD)); RC5_SETUP(key); RC5_ENCRYPT(pt1,ct); printf("\n plaintext "); printword(pt1 [0]); printword(pt1 [1]); printf(" ---> ciphertext "); printword(ct [0]); printword(ct [1]); printf("\n"); RC5_SETUP(key); RC5_DECRYPT(ct,pt2); out1<<ct[0]; out1<<ct[1]; out1 <<"\n"; printf("\n plaintext "); printword(pt1 [0]); printword(pt1 [1]); return 0; } Let the plt.txt file contain 101 100 let the key be 111

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  • how to check if there is a division by zero in c

    - by user244775
    #include<stdio.h> void function(int); int main() { int x; printf("Enter x:"); scanf("%d", &x); function(x); return 0; } void function(int x) { float fx; fx=10/x; if(10 is divided by zero)// I dont know what to put here please help printf("division by zero is not allowed"); else printf("f(x) is: %.5f",fx); }

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  • c printing string syntax

    - by user535256
    Hello guys, Just stuck on c syntax regarding strings. Say I have a string like (name[5]="peter";) in c say if I just wanted to print the last character of string or check the last character of the string, which in this case would be 'r' how can I do this? The way I was thinking does not seem to work name[5]="peter"; if(name[5]=="r") printf("last character of name is r"); Question: is there some sort of function to do this that can check one character of array, is a certain value, like name[5] is 'r' in string peter or likewise name[1] is 'n' Also how do I use printf to print that certain char, having problems using printf("last character of name is %s",name[5]) ??? Thanks

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  • Long Double in C

    - by reubensammut
    I've been reading the C Primer Plus book and got to this example #include <stdio.h> int main(void) { float aboat = 32000.0; double abet = 2.14e9; long double dip = 5.32e-5; printf("%f can be written %e\n", aboat, aboat); printf("%f can be written %e\n", abet, abet); printf("%f can be written %e\n", dip, dip); return 0; } After I ran this on my macbook I was quite shocked at the output: 32000.000000 can be written 3.200000e+04 2140000000.000000 can be written 2.140000e+09 2140000000.000000 can be written 2.140000e+09 So I looked round and found out that the correct format to display long double is to use %Lf. However I still can't understand why I got the double abet value instead of what I got when I ran it on Cygwin, Ubuntu and iDeneb which is roughly -1950228512509697486020297654959439872418023994430148306244153100897726713609 013030397828640261329800797420159101801613476402327600937901161313172717568.0 00000 can be written 2.725000e+02 Any ideas?

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  • Can any genius out there turn this code from generating permutation to generating combination?

    - by mark
    #include <string> int main(int,char**) { std::string default_str = "12345"; int perm=1, digits=default_str.size(); for (int i=1;i<=digits;perm*=i++); for (int a=0;a<perm;a++) { std::string avail=default_str; for (int b=digits,div=perm;b>0; b--) { div/=b; int index = (a/div)%b; printf("%c", avail[index] ); avail.erase(index,1) ; } printf("\n"); } printf("permutations:%d\n",perm); while(1); }

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