Search Results

Search found 1848 results on 74 pages for 'printf'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 21/74 | < Previous Page | 17 18 19 20 21 22 23 24 25 26 27 28  | Next Page >

  • Problem with signal handlers being called too many times [closed]

    - by Hristo
    how can something print 3 times when it only goes the printing code twice? I'm coding in C and the code is in a SIGCHLD signal handler I created. void chld_signalHandler() { int pidadf = (int) getpid(); printf("pidafdfaddf: %d\n", pidadf); while (1) { int termChildPID = waitpid(-1, NULL, WNOHANG); if (termChildPID == 0 || termChildPID == -1) { break; } dll_node_t *temp = head; while (temp != NULL) { printf("stuff\n"); if (temp->pid == termChildPID && temp->type == WORK) { printf("inside if\n"); // read memory mapped file b/w WORKER and MAIN // get statistics and write results to pipe char resultString[256]; // printing TIME int i; for (i = 0; i < 24; i++) { sprintf(resultString, "TIME; %d ; %d ; %d ; %s\n",i,1,2,temp->stats->mboxFileName); fwrite(resultString, strlen(resultString), 1, pipeFD); } remove_node(temp); break; } temp = temp->next; } printf("done printing from sigchld \n"); } return; } the output for my MAIN process is this: MAIN PROCESS 16214 created WORKER PROCESS 16220 for file class.sp10.cs241.mbox pidafdfaddf: 16214 stuff stuff inside if done printing from sigchld MAIN PROCESS 16214 created WORKER PROCESS 16221 for file class.sp10.cs225.mbox pidafdfaddf: 16214 stuff stuff inside if done printing from sigchld and the output for the MONITOR process is this: MONITOR: pipe is open for reading MONITOR PIPE: TIME; 0 ; 1 ; 2 ; class.sp10.cs225.mbox MONITOR PIPE: TIME; 0 ; 1 ; 2 ; class.sp10.cs225.mbox MONITOR PIPE: TIME; 0 ; 1 ; 2 ; class.sp10.cs241.mbox MONITOR: end of readpipe ( I've taken out repeating lines so I don't take up so much space ) Thanks, Hristo

    Read the article

  • Signal Handling in C

    - by Dave
    How can I implement signal Handling for Ctrl-C and Ctrl-D in C....So If Ctrl-C is pressed then the program will ignore and try to get the input from the user again...If Ctrl-D is pressed then the program will terminate... My program follows: int main(){ char msg[400]; while(1){ printf("Enter: "); fgets(msg,400,stdin); printf("%s\n",msg); } } Thanks, Dave

    Read the article

  • using php's libcurl to register user and upload file to server

    - by tunpishuang
    here is a site http://www.lyrkjsw.gov.cn that can let the registered user to upload file (e.g. images or office files) to the site. i want to register user and upload image to this site using libcurl binding with php. only registered user can upload image. so i use cookiejar stored in c:\cookie.txt after register and use c:\cookie.txt in uploadImg() function . register user is valid but failed to upload image , can anybody know is there any mistake of my code: <? /* options */ //the list url $expUrl='http://www.lyrkjsw.gov.cn/hbcms/user/list_resource.php'; //the user info to be registered $regUser='jiong'; $regPass='jiong'; $regMail='[email protected]'; $regUrl=str_replace('list_resource.php','register.php',$expUrl); // options for image upload $fileDir='@D:\img\b.jpg'; $fileTitle='aaaaaaaaaaaaa'; $fileDesc='aaaaaaaaaaaaadesc'; $uploadImgUrl=str_replace('list_resource.php','add_resource.php',$expUrl); /* register function */ function reg($regurl,$u,$p,$m) { $ch = curl_init(); $options=array( CURLOPT_URL=>$regurl, CURLOPT_RETURNTRANSFER=>true, CURLOPT_POST=>true, CURLOPT_POSTFIELDS=>'mod=register_now&next_url=index.php&addon_app=&referrer_id=&login_name='.$u.'&login_pass='.$p.'&confirm_login_pass='.$p.'&login_email='.$m.'&nickname=&gender=0&qq=&mobile=&telephone=&true_name=&website_name=&website_url=&my_question=&my_answer=', CURLOPT_COOKIESESSION=>true, CURLOPT_HEADER=>true, CURLOPT_COOKIEJAR=>'c:\cookie.txt' ); curl_setopt_array($ch,$options); $data = curl_exec($ch); if(strpos($data,'??')){ printf("register ok :)\n"); curl_close($ch); return true; }else{ printf("register failed:(\n"); curl_close($ch); return false; } } /* image uploading function */ function uploadImg($uploadimgurl,$filedir,$filetitle,$filedesc) { $ch = curl_init(); $options=array( CURLOPT_COOKIEFILE=>'c:\cookie.txt', CURLOPT_URL=>$uploadimgurl, CURLOPT_RETURNTRANSFER=>1, CURLOPT_POST=>1, CURLOPT_POSTFIELDS=>" 'MAX_FILE_SIZE'='33554432'& 'preview_area_id'='upload_file'& 'editor_area_id'='body'& 'js_function'=''& 'resource_id'=''& 'show_top_part'='no'& 'file_1'=$filedir& 'file_title_1'=$filetitle& 'file_desc_1'=$filedesc " ); curl_setopt_array($ch,$options); $data = curl_exec($ch); if(strpos($data,'??')){ printf("upload ok :)\n"); }else{ printf("upload failed :(\n"); } curl_close($ch); } if(reg($regUrl,$regUser,$regPass,$regMail) != false) { uploadImg($uploadImgUrl,$fileDir,$fileTitle,$fileDesc); } http://www.lyrkjsw.gov.cn/hbcms/user/list_resource.php (list file page) http://www.lyrkjsw.gov.cn/hbcms/user/register.php (register page) http://www.lyrkjsw.gov.cn/hbcms/user/add_resource.php (image uploading page)

    Read the article

  • Problem with signal handlers

    - by Hristo
    how can something print 3 times when it only goes the printing code twice? I'm coding in C and the code is in a SIGCHLD signal handler I created. void chld_signalHandler() { int pidadf = (int) getpid(); printf("pidafdfaddf: %d\n", pidadf); while (1) { int termChildPID = waitpid(-1, NULL, WNOHANG); if (termChildPID == 0 || termChildPID == -1) { break; } dll_node_t *temp = head; while (temp != NULL) { printf("stuff\n"); if (temp->pid == termChildPID && temp->type == WORK) { printf("inside if\n"); // read memory mapped file b/w WORKER and MAIN // get statistics and write results to pipe char resultString[256]; // printing TIME int i; for (i = 0; i < 24; i++) { sprintf(resultString, "TIME; %d ; %d ; %d ; %s\n",i,1,2,temp->stats->mboxFileName); fwrite(resultString, strlen(resultString), 1, pipeFD); } remove_node(temp); break; } temp = temp->next; } printf("done printing from sigchld \n"); } return; } the output for my MAIN process is this: MAIN PROCESS 16214 created WORKER PROCESS 16220 for file class.sp10.cs241.mbox pidafdfaddf: 16214 stuff stuff inside if done printing from sigchld MAIN PROCESS 16214 created WORKER PROCESS 16221 for file class.sp10.cs225.mbox pidafdfaddf: 16214 stuff stuff inside if done printing from sigchld and the output for the MONITOR process is this: MONITOR: pipe is open for reading MONITOR PIPE: TIME; 0 ; 1 ; 2 ; class.sp10.cs225.mbox MONITOR PIPE: TIME; 0 ; 1 ; 2 ; class.sp10.cs225.mbox MONITOR PIPE: TIME; 0 ; 1 ; 2 ; class.sp10.cs241.mbox MONITOR: end of readpipe ( I've taken out repeating lines so I don't take up so much space ) Thanks, Hristo

    Read the article

  • How do I make a module in PLT Scheme?

    - by kunjaan
    I tried doing this: #lang scheme (module duck scheme/base (provide num-eggs quack) (define num-eggs 2) (define (quack n) (unless (zero? n) (printf "quack\n") (quack (sub1 n))))) But I get this error: module: illegal use (not at top-level) in: (module duck scheme/base (provide num-eggs quack) (define num-eggs 2) (define (quack n) (unless (zero? n) (printf "quack\n") (quack (sub1 n))))) what is the correct way?

    Read the article

  • GCC, -O2, and bitfields - is this a bug or a feature?

    - by Rooke
    Today I discovered alarming behavior when experimenting with bit fields. For the sake of discussion and simplicity, here's an example program: #include <stdio.h> struct Node { int a:16 __attribute__ ((packed)); int b:16 __attribute__ ((packed)); unsigned int c:27 __attribute__ ((packed)); unsigned int d:3 __attribute__ ((packed)); unsigned int e:2 __attribute__ ((packed)); }; int main (int argc, char *argv[]) { Node n; n.a = 12345; n.b = -23456; n.c = 0x7ffffff; n.d = 0x7; n.e = 0x3; printf("3-bit field cast to int: %d\n",(int)n.d); n.d++; printf("3-bit field cast to int: %d\n",(int)n.d); } The program is purposely causing the 3-bit bit-field to overflow. Here's the (correct) output when compiled using "g++ -O0": 3-bit field cast to int: 7 3-bit field cast to int: 0 Here's the output when compiled using "g++ -O2" (and -O3): 3-bit field cast to int: 7 3-bit field cast to int: 8 Checking the assembly of the latter example, I found this: movl $7, %esi movl $.LC1, %edi xorl %eax, %eax call printf movl $8, %esi movl $.LC1, %edi xorl %eax, %eax call printf xorl %eax, %eax addq $8, %rsp The optimizations have just inserted "8", assuming 7+1=8 when in fact the number overflows and is zero. Fortunately the code I care about doesn't overflow as far as I know, but this situation scares me - is this a known bug, a feature, or is this expected behavior? When can I expect gcc to be right about this? Edit (re: signed/unsigned) : It's being treated as unsigned because it's declared as unsigned. Declaring it as int you get the output (with O0): 3-bit field cast to int: -1 3-bit field cast to int: 0 An even funnier thing happens with -O2 in this case: 3-bit field cast to int: 7 3-bit field cast to int: 8 I admit that attribute is a fishy thing to use; in this case it's a difference in optimization settings I'm concerned about.

    Read the article

  • The MYSTERY SPIRAL

    - by CVS26
    Problem statement: Given a integer N, print N*N numbers in a N x N spiral Detailed problem description: http://2600hertz.wordpress.com/2010/03/20/the-mystery-spiral/ Solution: Recently posted the following code. (managed to compress it into as few as 99 lines...) //File : spiral.c // //INPUT : Size of spiral (N) //OUTPUT : Numbers printed in a N x N spiral #include <stdio.h> #include <conio.h> #include <stdlib.h> void main() { int N; clrscr(); //get input no. N printf("\nEnter size of Matrix: "); scanf("%d",&N); //Allocate reqd. memory int* matrix_ptr= (int*)malloc(N*N); //Filling the Matrix spirally int curr_val=N*N; int* curr_ptr=matrix_ptr; int curr_level=N; while(curr_level>1) { //curr_level-1 elements horizontally //from left to right for(int x=0;x<curr_level-1;x++) { *curr_ptr=curr_val; curr_val--; curr_ptr++; } //curr_level-1 elements vertically //from top to bottom for(int y=0;y<curr_level-1;y++) { *curr_ptr=curr_val; curr_val--; curr_ptr+=N; } //curr_level-1 elements horizontally //from right to left for(int z=0;z<curr_level-1;z++) { *curr_ptr=curr_val; curr_val--; curr_ptr--; } //curr_level-1 element vertically //from bottom to top for(int w=0;w<curr_level-1;w++) { *curr_ptr=curr_val; curr_val--; curr_ptr-=N; } //Next curr_ptr+=N+1; curr_level-=2; } *curr_ptr=curr_val; //routine to print the matrix printf("\n\n\n\n\n"); for( int i=0;i<N;i++) { for( int j=0;j<N;j++) { printf("%d\t",*(matrix_ptr+(i*N+j))); } printf("\n"); } getch(); } Please comment on further optimisations (if any)...

    Read the article

  • Endian check in C

    - by webgenius
    Got this code snippet from some website: int num = 1; if(*(char *)&num == 1) { printf("\nLittle-Endian\n"); } else { printf("Big-Endian\n"); } Can anyone explain this step-by-step? &num - Adress of a (char *)&num - Type-cast address of a into a string *(char *)&num - Points to the first character of the string Am I missing anything here?

    Read the article

  • a problem in socks.h

    - by janathan
    i use this (http://www.codeproject.com/KB/IP/Socks.aspx) lib in my socket programing in c++ and copy the socks.h in include folder and write this code: include include include include include include "socks.h" define PORT 1001 // the port client will be connecting to define MAXDATASIZE 100 static void ReadThread(void* lp); int socketId; int main(int argc, char* argv[]) { const char temp[]="GET / HTTP/1.0\r\n\r\n"; CSocks cs; cs.SetVersion(SOCKS_VER4); cs.SetSocksPort(1080); cs.SetDestinationPort(1001); cs.SetDestinationAddress("192.168.11.97"); cs.SetSocksAddress("192.168.11.97"); //cs.SetVersion(SOCKS_VER5); //cs.SetSocksAddress("128.0.21.200"); socketId = cs.Connect(); // if failed if (cs.m_IsError) { printf( "\n%s", cs.GetLastErrorMessage()); getch(); return 0; } // send packet for requesting to a server if(socketId > 0) { send(socketId, temp, strlen(temp), 0); HANDLE ReadThreadID; // handle for read thread id HANDLE handle; // handle for thread handle handle = CreateThread ((LPSECURITY_ATTRIBUTES)NULL, // No security attributes. (DWORD)0, // Use same stack size. (LPTHREAD_START_ROUTINE)ReadThread, // Thread procedure. (LPVOID)(void*)NULL, // Parameter to pass. (DWORD)0, // Run immediately. (LPDWORD)&ReadThreadID); WaitForSingleObject(handle, INFINITE); } else { printf("\nSocks Server / Destination Server not started.."); } closesocket(socketId); getch(); return 0; } // Thread Proc for reading from server socket. static void ReadThread(void* lp) { int numbytes; char buf[MAXDATASIZE]; while(1) { if ((numbytes=recv(socketId, buf, MAXDATASIZE-1, 0)) == -1) { printf("\nServer / Socks Server has been closed Receive thread Closed\0"); break; } if (numbytes == 0) break; buf[numbytes] = '\0'; printf("Received: %s\r\n",buf); send(socketId,buf,strlen(buf),0); } } but when compile this i get an error . pls help me thanks

    Read the article

  • Bidirectional FIFO

    - by nunos
    I would like to implement a bidirectional fifo. The code below is functioning but it is not using bidirectional fifo. I have searched all over the internet, but haven't found any good example... How can I do that? Thanks, WRITER.c: #include <stdio.h> #include <unistd.h> #include <string.h> #include <sys/types.h> #include <sys/wait.h> #include <fcntl.h> #define MAXLINE 4096 #define READ 0 #define WRITE 1 int main (int argc, char** argv) { int a, b, fd; do { fd=open("/tmp/myfifo",O_WRONLY); if (fd==-1) sleep(1); } while (fd==-1); while (1) { scanf("%d", &a); scanf("%d", &b); write(fd,&a,sizeof(int)); write(fd,&b,sizeof(int)); if (a == 0 && b == 0) { break; } } close(fd); return 0; } READER.c: #include <stdio.h> #include <unistd.h> #include <string.h> #include <sys/types.h> #include <sys/wait.h> #include <fcntl.h> #include <sys/stat.h> #define MAXLINE 4096 #define READ 0 #define WRITE 1 int main(void) { int n1, n2; int fd; mkfifo("/tmp/myfifo",0660); fd=open("/tmp/myfifo",O_RDONLY); while(read(fd, &n1, sizeof(int) )) { read(fd, &n2, sizeof(int)); if (n1 == 0 && n2 == 0) { break; } printf("soma: %d\n",n1+n2); printf("diferenca: %d\n", n1-n2); printf("divisao: %f\n", n1/(double)n2); printf("multiplicacao: %d\n", n1*n2); } close(fd); return 0; }

    Read the article

  • i don't understand how...

    - by Hristo
    how can something print 3 times when it only goes the printing code twice? I'm coding in C and the code is in a SIGCHLD signal handler I created. void chld_signalHandler() { int pidadf = (int) getpid(); printf("pidafdfaddf: %d\n", pidadf); while (1) { int termChildPID = waitpid(-1, NULL, WNOHANG); if (termChildPID == 0 || termChildPID == -1) { break; } dll_node_t *temp = head; while (temp != NULL) { printf("stuff\n"); if (temp-pid == termChildPID && temp-type == WORK) { printf("inside if\n"); // read memory mapped file b/w WORKER and MAIN // get statistics and write results to pipe char resultString[256]; // printing TIME int i; for (i = 0; i < 24; i++) { sprintf(resultString, "TIME; %d ; %d ; %d ; %s\n",i,1,2,temp->stats->mboxFileName); fwrite(resultString, strlen(resultString), 1, pipeFD); } remove_node(temp); break; } temp = temp-next; } printf("done printing from sigchld \n"); } return; } the output for my MAIN process is this: MAIN PROCESS 16214 created WORKER PROCESS 16220 for file class.sp10.cs241.mbox pidafdfaddf: 16214 stuff stuff inside if done printing from sigchld MAIN PROCESS 16214 created WORKER PROCESS 16221 for file class.sp10.cs225.mbox pidafdfaddf: 16214 stuff stuff inside if done printing from sigchld and the output for the MONITOR process is this: MONITOR: pipe is open for reading MONITOR PIPE: TIME; 0 ; 1 ; 2 ; class.sp10.cs225.mbox MONITOR PIPE: TIME; 0 ; 1 ; 2 ; class.sp10.cs225.mbox MONITOR PIPE: TIME; 0 ; 1 ; 2 ; class.sp10.cs241.mbox MONITOR: end of readpipe ( I've taken out repeating lines so I don't take up so much space ) Thanks, Hristo

    Read the article

  • 23warning: assignment makes pointer from integer without a cast

    - by FILIaS
    Im new in programming c with arrays and files. Im just trying to run the following code but i get warnings like that: 23 44 warning: assignment makes pointer from integer without a cast Any help? It might be silly... but I cant find what's wrong. #include<stdio.h> FILE *fp; FILE *cw; char filename_game[40],filename_words[40]; int main() { while(1) { /* Input filenames. */ printf("\n Enter the name of the file with the cryptwords array: \n"); gets(filename_game); printf("\n Give the name of the file with crypted words:\n"); gets(filename_words); /* Try to open the file with the game */ if (fp=fopen("crypt.txt","r")!=NULL) //line23 { printf("\n Successful opening %s \n",filename_game); fclose(fp); puts("\n Enter x to exit,any other to continue! \n "); if ( (getc(stdin))=='x') break; else continue; } else { fprintf(stderr,"ERROR!%s \n",filename_game); puts("\n Enter x to exit,any other to continue! \n"); if (getc(stdin)=='x') break; else continue; } /* Try to open the file with the names. */ if (cw=fopen("words.txt","r")!=NULL) //line 44 { printf("\n Successful opening %s \n",filename_words); fclose(cw); puts("\n Enter x to exit,any other to continue \n "); if ( (getc(stdin))=='x') break; else continue; } else { fprintf(stderr,"ERROR!%s \n",filename_words); puts("\n Enter x to exit,any other to continue! \n"); if (getc(stdin)=='x') break; else continue; } } return 0; }

    Read the article

  • Issue with RegConnectRegistry connecting to 64 bit machines

    - by RA
    I'm seeing a weird thing when connecting to the performance registry on 64 bit editions of Windows. The whole program stalls and callstacks becomes unreadable. After a long timeout, the connection attempts aborts and everything goes back to normal. The only solution is to make sure that only one thread at the time queries the remote registry, unless the remote machine is a 32 bit Windows XP, 2003, 2000 , then you can use as many threads as you like. Have anyone a technical explanation why this might be happening ? I've spent 2-3 days searching the web without coming up with anything. Here is a test program, run it first with one thread (connecting to a 64 bit Windows), then remove the comment in tmain and run it with 4 threads. Running it with one thread works as expected, running with 4, returns ERROR_BUSY (dwRet == 170) after stalling for a while. Remember to set a remote machine correctly in RegConnectRegistry before running the program. #define TOTALBYTES 8192 #define BYTEINCREMENT 4096 void PerfmonThread(void *pData) { DWORD BufferSize = TOTALBYTES; DWORD cbData; DWORD dwRet; PPERF_DATA_BLOCK PerfData = (PPERF_DATA_BLOCK) malloc( BufferSize ); cbData = BufferSize; printf("\nRetrieving the data..."); HKEY hKey; DWORD dwAccessRet = RegConnectRegistry(L"REMOTE_MACHINE",HKEY_PERFORMANCE_DATA,&hKey); dwRet = RegQueryValueEx( hKey,L"global",NULL,NULL,(LPBYTE) PerfData, &cbData ); while( dwRet == ERROR_MORE_DATA ) { // Get a buffer that is big enough. BufferSize += BYTEINCREMENT; PerfData = (PPERF_DATA_BLOCK) realloc( PerfData, BufferSize ); cbData = BufferSize; printf("."); dwRet = RegQueryValueEx( hKey,L"global",NULL,NULL,(LPBYTE) PerfData,&cbData ); } if( dwRet == ERROR_SUCCESS ) printf("\n\nFinal buffer size is %d\n", BufferSize); else printf("\nRegQueryValueEx failed (%d)\n", dwRet); RegCloseKey(hKey); } int _tmain(int argc, _TCHAR* argv[]) { _beginthread(PerfmonThread,0,NULL); /* _beginthread(PerfmonThread,0,NULL); _beginthread(PerfmonThread,0,NULL); _beginthread(PerfmonThread,0,NULL); */ while(1) { Sleep(2000); } }

    Read the article

  • Why my shell program wont open the file got as argument in function "cat"

    - by anna karenina
    I included the code below, sorry to bother you with so much code. Argument parsing is ok, i checked it out with watches. I've put some printfs to check out where the problem may be and it seems that it wont open the file cat receives as argument. i called from shell like "cat -b file" #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <string.h> #define TRUE 0 #define FALSE 1 void yes(int argc, char *argv[]); int cat(int argc, char *argv[]); //#include "cat.h" //#include "yes.h" //#include"tee.h" char buf[50],c[10], *p2,*p, *pch; int count; char *matrix[20]; void yes(int argc, char *argv[]) { int i; // if (argc >= 2 && *argv[1] == '-') // { //printf("ERROR!"); //} //if (argc == 1) // { while (1) if (puts("y") == EOF) { perror("yes"); exit(FALSE); } // } while (1) for (i = 1; i < argc; i++) if (fputs(argv[i], stdout) == EOF || putchar(i == argc - 1 ? '\n' : ' ') == EOF) { perror("yes"); exit(FALSE); } //exit(TRUE); } int main(int argc, char *argv[]) { //p=(char *)malloc(sizeof(char)*50); do { fprintf (stderr, "$ "); fgets (buf,50,stdin); p=buf; fprintf (stderr, "Comanda primita de la tastatura: "); fputs (buf, stderr); int i=0,j=0; //strcpy(p,buf); strcpy(c,"\0"); while (buf[i] == ' ') { i++; p++; } if (buf[i] == '#') fprintf (stderr, "Nici o comanda, ci e un comentariu!\n"); else { j=0; while (buf[i] != ' ' && buf[i] != '\n') { i++; j++; } strncpy (c,p,j); fprintf (stderr, "%s\n",c); if (strcmp (c,"yes") == 0) { p2 = p+j+1; pch = strtok (p2," "); count = 0; while (pch != NULL) { //printf ("%s\n",pch); matrix[count] = strdup(pch); pch = strtok (NULL, " "); count++; } yes(count, matrix); fprintf (stderr, "Aici se va executa comanda yes\n"); } else if (strcmp (c,"cat") == 0) { p2 = p+j+1; pch = strtok (p2," "); count = 0; while (pch != NULL) { //printf ("%s\n",pch); matrix[count] = strdup(pch); pch = strtok (NULL, " "); count++; } cat(count,matrix); fprintf (stderr, "Aici se va executa comanda cat \n"); } else if (strcmp (c,"tee") == 0) { //tee(); fprintf(stderr, "Aici se va executa comanda tee\n"); } fprintf (stderr, "Aici se va executa comanda basename\n"); strcpy(buf,"\0"); } } while (strcmp(c, "exit") != 0); fprintf (stderr, "Terminat corect!\n"); return 0; } int cat(int argc, char *argv[]) { int c ; opterr = 0 ; optind = 0 ; char number = 0; char squeeze = 0; char marker = 0; fprintf(stderr,"SALUT< SUNT IN FUNCTIZE>\n"); while ((c = getopt (argc, argv, "bnsE")) != -1) switch (c) { case 'b' : number = 1; break; case 'n' : number = 2; break; case 'm' : marker = 1; break; case 's' : squeeze = 1; break; case 'E' : marker = 1; break; } if (optind + 1 != argc) { fprintf (stderr, "\tWrong arguments!\n") ; return -1 ; } FILE * fd = fopen (argv[optind], "r"); printf("am deschis fisierul %s ",argv[optind]); if (fd == NULL) { printf("FISIER NULL asdasdasdasdasd"); return 1; } char line[1025]; int line_count = 1; while (!feof(fd)) { fgets(line, 1025, fd); printf("sunt in while :> %s",line); int len = strlen(line); if (line[len - 1] == '\n') { if(len - 2 >= 0) { if(line[len - 2] == '\r') { line[len - 2] = '\0'; len -= 2; } else { line[len - 1] = '\0'; len -= 1; } } else { line[len - 1] = '\0'; len -= 1; } } if (squeeze == 1 && len == 0) continue; if (number == 1) { fprintf (stdout, "%4d ", line_count); line_count++; } else if (number == 2) { if (len > 0) { fprintf (stdout, "%4d ", line_count); line_count++; } else fprintf (stdout, " "); } fprintf(stdout, "%s", line); if (marker == 1) fprintf(stdout, "$"); fprintf(stdout, "\n"); } fclose (fd); return 0 ; }

    Read the article

  • How to solve Memory leaks in Lib Xml Parser in objective-C where the list is returned?

    - by Madan Mohan
    Hi Guys, I got leaks in Lib Xml Parser while retrieving the data from the net, Here in the below code, I have allocated the list - (void)getCustomersList { // make an operation so we can push it into the queue SEL method = @selector(parseForData); NSInvocationOperation *op = [[NSInvocationOperation alloc] initWithTarget:self selector:method object:nil]; customersTempList = [[NSMutableArray alloc] initWithCapacity:20];// allocated list [self.retrieverQueue addOperation:op]; [op release]; } // return each recode // in parser .m class one of the condition in endElement where it shows a leak. else if(0 == strncmp((const char *)localname, kCustomerElement, kCustomerElementLength)) { [customersTempList addObject:customer]; printf("\n no of objects in temp list:%d", [customersTempList count]); if ([customersTempList count] == 20) { NSMutableArray* argsList = [customersTempList copy];//////////////////////here it is showing leak. printf("\n Calling reload data with %d new objects", [argsList count]); SEL selector = @selector(parser:addCustomerObject:); NSMethodSignature *sig = [(id)self.delegate methodSignatureForSelector:selector]; if(nil != sig && [self.delegate respondsToSelector:selector]) { NSInvocation *invocation = [NSInvocation invocationWithMethodSignature:sig]; [invocation retainArguments]; [invocation setTarget:self.delegate]; [invocation setSelector:selector]; [invocation setArgument:&self atIndex:2]; [invocation setArgument:&argsList atIndex:3]; [invocation performSelectorOnMainThread:@selector(invoke) withObject:NULL waitUntilDone:NO]; } [customersTempList removeAllObjects]; } } // returned the list after all the records are stored in the list else if(0 == strncmp((const char *)localname, kCustomersElement, kCustomersElementLength)) { printf("\n Calling reload data with %d new objects", [customersTempList count]); NSMutableArray* argsList = [customersTempList copy]; printf("\n Calling reload data with %d new objects", [argsList count]); SEL selector = @selector(parser:addCustomerObject:); NSMethodSignature *sig = [(id)self.delegate methodSignatureForSelector:selector]; if(nil != sig && [self.delegate respondsToSelector:selector]) { NSInvocation *invocation = [NSInvocation invocationWithMethodSignature:sig]; [invocation retainArguments]; [invocation setTarget:self.delegate]; [invocation setSelector:selector]; [invocation setArgument:&self atIndex:2]; [invocation setArgument:&argsList atIndex:3]; [invocation performSelectorOnMainThread:@selector(invoke) withObject:NULL waitUntilDone:NO]; } [customersTempList removeAllObjects]; } } please help me out of this, Thanks, Madan.

    Read the article

  • Is there something like PHP ob_start for C?

    - by echedey lorenzo
    Hi, I have a simple gateway listener which generates a log at the screen output via printf. I would like to record it so I can insert it in a mysql table. printf("\nPacket received!! Decoding..."); I wonder if there is any fast way to do this is C. In case there is, could I get both outputs at the same time? Thanks

    Read the article

  • Arithmetic operators and function calling in C

    - by Robert Dalton
    I'm not quite sure why I can't do double a = (float) my_Function(45) / 2048 / 2340 / 90; printf("%.4",a); // prints out 0.00 But instead I have to use one more variable as: double a = (float) my_Function(45); double b = (float) a / 2048 / 2340 / 90; printf("%.4",b); // prints out the correct value

    Read the article

  • Truncating double without rounding in C

    - by Coder
    Lets consider we have a double R = 99.999999; (which may be obtained by a result of some other computation),now the desired output is 99.99 I tried using printf("%.2lf",R); but it's rounding off the value.How to get the desired output ? (preferably using printf)

    Read the article

  • How to increment counters based on a printed array

    - by Sam Liew
    I managed to developed a simple board of 5x5 using random numbers and array. Big achievement for someone like me! :) Now I have to increment the counters depending on the frequency of the numbers. If the value within 0-49 is printed..then nCounter++ If the value within 50-75 is printed..then pCounter++ something like that. The problem is that I don't know how to increase the counters based on the printed board. Here is the code: #include <stdio.h> #include <stdlib.h> #include <time.h> int main() { //Initialize Variables int randomNumber; int rows; int columns; int hdCounter =0; int hCounter = 0; int cCounter = 0; int pCounter = 0; int nCounter = 0; //Declare board size int board[5][5]; //size of board is 5 x 5 //Create the random number generator seed srand(time(NULL)); //Assign the random numbers from 1 - 25 into variable randomNumber //Create the rows for the board for ( rows = 1; rows <= 5 ; rows++ ) { //Create the colimns for the board for ( columns = 1; columns <= 5 ; columns++ ) { //Assign variable randomNumber into variable board randomNumber = rand() %100 + 1; board[rows][columns] = randomNumber; //print the board printf("%d\t", board[rows][columns]); //calculate the frequency of numbers on the printed board if (randomNumber >= 85 && randomNumber <= 100 ) hdCounter++; else if ( randomNumber >= 75 ) hCounter++; else if ( randomNumber >= 65 ) cCounter++; else if ( randomNumber >= 50 ) pCounter++; else if ( randomNumber >= 1 ) nCounter++; else continue; } //Newline after the end of 5th column. printf("\n\n"); } printf( "N \t P \t C \t H \t HD\n\n" ); printf("%d \t %d \t %d \t %d \t %d \t", nCounter, pCounter, cCounter, hCounter, hdCounter); }//end main I tried replacing randomNumber in the if-statement with board[rows][columns] but I seem to get the same undesired results.

    Read the article

  • Unexpected answer

    - by Sandeep
    #include<stdio.h> int main() { printf("He %c llo",65); } Output: A #include<stdio.h> int main() { printf("He %c llo",13); } Output: llo I can understand that 65 is ascii value for A and hence A is printed in first case but why llo in second case. Thanks

    Read the article

  • ReadFile doesn't work asynchronously on Win7 and Win2k8

    - by f0b0s
    According to MSDN ReadFile can read data 2 different ways: synchronously and asynchronously. I need the second one. The folowing code demonstrates usage with OVERLAPPED struct: #include <windows.h> #include <stdio.h> #include <time.h> void Read() { HANDLE hFile = CreateFileA("c:\\1.avi", GENERIC_READ, 0, NULL, OPEN_EXISTING, FILE_FLAG_OVERLAPPED, NULL); if ( hFile == INVALID_HANDLE_VALUE ) { printf("Failed to open the file\n"); return; } int dataSize = 256 * 1024 * 1024; char* data = (char*)malloc(dataSize); memset(data, 0xFF, dataSize); OVERLAPPED overlapped; memset(&overlapped, 0, sizeof(overlapped)); printf("reading: %d\n", time(NULL)); BOOL result = ReadFile(hFile, data, dataSize, NULL, &overlapped); printf("sent: %d\n", time(NULL)); DWORD bytesRead; result = GetOverlappedResult(hFile, &overlapped, &bytesRead, TRUE); // wait until completion - returns immediately printf("done: %d\n", time(NULL)); CloseHandle(hFile); } int main() { Read(); } On Windows XP output is: reading: 1296651896 sent: 1296651896 done: 1296651899 It means that ReadFile didn't block and returned imediatly at the same second, whereas reading process continued for 3 seconds. It is normal async reading. But on windows 7 and windows 2008 I get following results: reading: 1296661205 sent: 1296661209 done: 1296661209. It is a behavior of sync reading. MSDN says that async ReadFile sometimes can behave as sync (when the file is compressed or encrypted for example). But the return value in this situation should be TRUE and GetLastError() == NO_ERROR. On Windows 7 I get FALSE and GetLastError() == ERROR_IO_PENDING. So WinApi tells me that it is an async call, but when I look at the test I see that it is not! I'm not the only one who found this "bug": read the comment on ReadFile MSDN page. So what's the solution? Does anybody know? It is been 14 months after Denis found this strange behavior.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 17 18 19 20 21 22 23 24 25 26 27 28  | Next Page >