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  • mysql_connect()

    - by Jacksta
    I am trying to connect to mysql and am getting an error. I put my servers ip address in and used port 3306 whihch post should be used? <?php $connection = mysql_connect("serer.ip:port", "user", "pass") or die(mysql_error()); if ($connection) {$msg = "success";} ?> <html> <head> </head> <body> <? echo "$msg"; ?> </body> </html> Here is the error its producing Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'admin'@'server1.myserver.com' (using password: YES) in /home/admin/domains/mydomain.com.au/public_html/db_connect.php on line 3 Access denied for user 'admin'@'server1.myserver.com' (using password: YES)

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  • Writing a line in a JTextArea from another class

    - by Christopher Nastovski
    I'm trying to use a Method in my class 'Visual' to write a line of code into a JTextArea and it prints when I call it from 'Visual' but when I call it from 'Login' It only prints Text into the Console, not to the TextArea. private static Visual Visual; Visual.WriteLine("I'm sorry, your username or password is incorrect. Please try again."); or private static Visual Visual = new Visual(); Visual.WriteLine("I'm sorry, your username or password is incorrect. Please try again."); Dont work form 'Login' But, WriteLine("Test"); works from 'Visual', the class that the method is in. Here's the method in 'Visual' public void WriteLine(String Text) { System.out.println(Text); SystemFeed.append(Text.toString() + "\n"); SystemFeed.setCaretPosition(SystemFeed.getDocument().getLength()); }

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  • Connecting form to database errors

    - by Russell Ehrnsberger
    Hello I am trying to connect a page to a MySQL database for newsletter signup. I have the database with 3 fields, id, name, email. The database is named newsletter and the table is named newsletter. Everything seems to be fine but I am getting this error Notice: Undefined index: Name in C:\wamp\www\insert.php on line 12 Notice: Undefined index: Name in C:\wamp\www\insert.php on line 13 Here is my form code. <form action="insert.php" method="post"> <input type="text" value="Name" name="Name" id="Name" class="txtfield" onblur="javascript:if(this.value==''){this.value=this.defaultValue;}" onfocus="javascript:if(this.value==this.defaultValue){this.value='';}" /> <input type="text" value="Enter Email Address" name="Email" id="Email" class="txtfield" onblur="javascript:if(this.value==''){this.value=this.defaultValue;}" onfocus="javascript:if(this.value==this.defaultValue){this.value='';}" /> <input type="submit" value="" class="button" /> </form> Here is my insert.php file. <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="newsletter"; // Database name $tbl_name="newsletter"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // Get values from form $name=$_POST['Name']; $email=$_POST['Email']; // Insert data into mysql $sql="INSERT INTO $tbl_name(name, email)VALUES('$name', '$email')"; $result=mysql_query($sql); // if successfully insert data into database, displays message "Successful". if($result){ echo "Successful"; echo "<BR>"; echo "<a href='index.html'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?>

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  • python + auto ssh proccess to get date info

    - by david
    I need to perform on my linux 5.3 ssh [Linux machine red hat 5.3] date in order to get the date results , during ssh need to answer on the following question (yes/no)? -- yes password: -- diana_123 and then I will get the date results please advice how to do this automated process with python? ( on my Linux I have Python 2.2.3 ) python script should get the IP address number , and perform automatically ssh to 103.116.140.151 and return the date results as --> Fri Nov 18 11:25:18 IST 2011 example of manual proccess: # ssh 103.116.140.151 date The authenticity of host '103.116.140.151 (103.116.140.151)' can't be established. RSA key fingerprint is ad:7e:df:9b:53:86:9f:98:17:70:2f:58:c2:5b:e2:e7. Are you sure you want to continue connecting (yes/no)? yes Warning: Permanently added '103.116.140.151' (RSA) to the list of known hosts. [email protected]'s password: Fri Nov 18 11:25:18 IST 2011

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  • VisualSVN Server + Trac Authentication Problems

    - by danscott
    I have Trac set up on my VisualSVN server (using Subversion authentication), however every time I navigate to the Trac home page after opening the browser, I get the basic authentication dialog asking me for my username/password. What I would like to do is have a login form in Trac, which would allow me to log in forever using cookies. I have tried installing the AccountManagerPlugin, but I am completely unsure of how to correctly set it up. (I am used to working with IIS on corporate intranets, so this is kind of alien to me) I have managed to bypass the basic authentication dialog by setting this in my httpd-custom.conf: AuthName "Trac" AuthType Basic AuthBasicProvider file AuthUserFile "E:/Repositories/htpasswd" #Require valid-user I have tried using SvnServePasswordStore as my password store but I do not know which of the files in the repository directory to point it at. Help would be appreciated!

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  • Simple ASP function question

    - by J Harley
    Good Morning, I have got the following function: FUNCTION queryDatabaseCount(sqlStr) SET queryDatabaseCountRecordSet = databaseConnection.Execute(sqlStr) If queryDatabaseCountRecordSet.EOF Then queryDatabaseCountRecordSet.Close queryDatabaseCount = 0 Else QueryArray = queryDatabaseCountRecordSet.GetRows queryDatabaseCountRecordSet.Close queryDatabaseCount = UBound(QueryArray,2) + 1 End If END FUNCTION And the following dbConnect: SET databaseConnection = Server.CreateObject("ADODB.Connection") databaseConnection.Open "Provider=SQLOLEDB; Data Source ="&dataSource&"; Initial Catalog ="&initialCatalog&"; User Id ="&userID&"; Password="&password&"" But for some reason I get the following error: ADODB.Recordset error '800a0e78' Operation is not allowed when the object is closed. /UBS/DBMS/includes/blocks/block_databaseoverview.asp, line 30 Does anyone have any suggestions? Many Thanks, Joel

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  • Java DriverManager Always Assigns My Driver

    - by JGB146
    I am writing a driver to act as a wrapper around two separate MySQL connections (to distributed databases). Basically, the goal is to enable interaction with my driver for all applications instead of requiring the application to sort out which database holds the desired data. Most of the code for this is in place, but I'm having a problem in that when I attempt to create connections via the MySQL Driver, the DriverManager is returning an instance of my driver instead of the MySQL Driver. I'd appreciate any tips on what could be causing this and what could be done to fix it! Below is a few relevant snippets of code. I can provide more, but there's a lot, so I'd need to know what else you want to see. First, from MyDriver.java: public MyDriver() throws SQLException { DriverManager.registerDriver(this); } public Connection connect(String url, Properties info) throws SQLException { try { return new MyConnection(info); } catch (Exception e) { return null; } } public boolean acceptsURL(String url) throws SQLException { if (url.contains("jdbc:jgb://")) { return true; } return false; } It is my understanding that this acceptsURL function will dictate whether or not the DriverManager deems my driver a suitable fit for a given URL. Hence it should only be passing connections from my driver if the URL contains "jdbc:jgb://" right? Here's code from MyConnection.java: Connection c1 = null; Connection c2 = null; /** *Constructors */ public DDBSConnection (Properties info) throws SQLException, Exception { info.list(System.out); //included for testing Class.forName("com.mysql.jdbc.Driver").newInstance(); String url1 = "jdbc:mysql://server1.com/jgb"; String url2 = "jdbc:mysql://server2.com/jgb"; this.c1 = DriverManager.getConnection( url1, info.getProperty("username"), info.getProperty("password")); this.c2 = DriverManager.getConnection( url2, info.getProperty("username"), info.getProperty("password")); } And this tells me two things. First, the info.list() call confirms that the correct user and password are being sent. Second, because we enter an infinite loop, we see that the DriverManager is providing new instances of my connection as matches for the mysql URLs instead of the desired mysql driver/connection. FWIW, I have separately tested implementations that go straight to the mysql driver using this exact syntax (al beit only one at a time), and was able to successfully interact with each database individually from a test application outside of my driver.

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  • Computer Invisible On Domain

    - by Giawa
    Good afternoon, I'm sorry that this isn't a programming question specifically, but stackoverflow has been great at answering questions in the past, so I thought I'd give it a shot. One of our Linux users attempted to install Cygwin on our Windows Server 2008 Domain Controller. Now it is no longer possible to browse the domain and see all of the computers. For example, \\my_domain_name will just bring up a username/password dialog box (that will not accept any username or password, even the domain administrator) and no computers will ever be listed. However, I can still connect to computers based on their name or IP address. So \\eridanus or \\192.168.1.85 still work to connect to the shared directories of computers on our network. Does anyone know where I can find these settings? and how I can fix this problem? Thanks, Giawa

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  • TFS Check in rules

    - by NPehrsson
    Hi I'm out of setting up an TFS server and I want to set some check-in rules. I for example want to be able to set rules about method lenght, complexity and so on, I found NDepend very convenient can I somehow use NDepend to run some rules on the files trying to check in. I also want to be able to bypass the rules sometimes. Are there any blogs or discussions around this, if it wont work with NDepend are there any other tools or ways I can use?

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  • "SQLSTATE[23000]: Integrity constraint violation" in Doctrine

    - by rags
    Hi, i do get an Integrity constraint violation for Doctrine though i really can't see why. Schema.yml User: columns: id: type: integer primary: true autoincrement: true username: type: varchar(64) notnull: true email: type: varchar(128) notnull: true password: type: varchar(128) notnull: true relations: Websites: class: Website local: id foreign: owner type: many foreignType: one onDelete: CASCADE Website: columns: id: type: integer primary: true autoincrement: true active: type: bool owner: type: integer notnull: true plz: type: integer notnull: true longitude: type: double(10,6) notnull: true latitude: type: double(10,6) notnull: true relations: Owner: type: one foreignType: many class: User local: owner foreign: id And here's my data Fixtures (data.yml) Model_User: User_1: username: as email: as****.com password: ***** Model_Website: Website_1: active: true plz: 34222 latitude: 13.12 longitude: 3.56 Owner: User_1

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  • App Engine - Objectify - Storing a byte[]

    - by Spines
    I'm using the Objectify library for interfacing with the app engine datastore. In my User class, I store the hashed password as a byte[]. When I put it in the datastore, it is correctly stored as a blob. When I try to load the User object back out I get this error: java.lang.IllegalStateException: Cannot load non-collection value '<Blob: 40 bytes>' into private byte[] How do I fix this? Do I have to change my User class to have the hashed password be of type ShortBlob?

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  • Option Value Changed - ODBC Error 2169

    - by fredrick-ughimi
    Hello Edgar, Thank you for your response. I am using Powerbasic (www.powerbasic.com) as my compiler and SQLTools as a third party tool to access ADS through ODBC. I must stat that this error also appers when I take other actions like Update, Delete, Find, etc. But I don't get this error when I am using MS Access. Here is my save routine: [Code] Local sUsername As String Local sPassword As String Local sStatus As String Local sSQLStatement1 As String sUsername = VD_GetText (nCbHndl, %ID_FRMUPDATEUSERS_TXTUSERNAME) If Trim$(sUsername) = "" Then MsgBox "Please, enter Username", %MB_ICONINFORMATION Or %MB_TASKMODAL, VD_App.Title Control Set Focus nCbHndl, %ID_FRMUPDATEUSERS_TXTUSERNAME Exit Function End If sPassword = VD_GetText (nCbHndl, %ID_FRMUPDATEUSERS_TXTPASSWORD) If Trim$(sPassword) = "" Then MsgBox "Please, enter Password", %MB_ICONINFORMATION Or %MB_TASKMODAL, VD_App.Title Control Set Focus nCbHndl, %ID_FRMUPDATEUSERS_TXTPASSWORD Exit Function End If sStatus = VD_GetText (nCbHndl, %ID_FRMUPDATEUSERS_CBOSTATUS) sSQLStatement1 = "INSERT INTO [tblUsers] (Username, Password, Status) " + _ "VALUES ('" + sUsername + "','" + sPassword + "','" + sStatus +"')" 'Submit the SQL Statement to the database SQL_Stmt %SQL_STMT_IMMEDIATE, sSQLStatement1 'Check for errors If SQL_ErrorPending Then SQL_MsgBox SQL_ErrorQuickAll, %MSGBOX_OK End If [/code] Best regards,

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  • What does Apache need to support both mysqli and PDO?

    - by Nathan Long
    I'm considering changing some PHP code to use PDO for database access instead of mysqli (because the PDO syntax makes more sense to me and is database-agnostic). To do that, I'd need both methods to work while I'm making the changeover. My problem is this: so far, either one or the other method will crash Apache. Right now I'm using XAMPP in Windows XP, and PHP Version 5.2.8. Mysqli works fine, and so does this: $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database'; $sql = "SELECT * FROM `employee`"; But this line makes Apache crash: $dbc->query($sql); I don't want to redo my entire Apache or XAMPP installation, but I'd like for PDO to work. So I tried updating libmysql.dll from here, as oddvibes recommended here. That made my simple PDO query work, but then mysqli queries crashed Apache. (I also tried the suggestion after that one, to update php_pdo_mysql.dll and php_pdo.dll, to no effect.) Test Case I created this test script to compare PDO vs mysqli. With the old copy of libmysql.dll, it crashes if $use_pdo is true and doesn't if it's false. With the new copy of libmysql.dll, it's the opposite. if ($use_pdo){ $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database<br />'; $sql = "SELECT * FROM `employee`"; $dbc->query($sql); foreach ($dbc->query($sql) as $row){ echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } else { $dbc = @mysqli_connect($hostname, $username, $password, $dbname) OR die('Could not connect to MySQL: ' . mysqli_connect_error()); $sql = "SELECT * FROM `employee`"; $result = @mysqli_query($dbc, $sql) or die(mysqli_error($dbc)); while ($row = mysqli_fetch_array($result,MYSQLI_ASSOC)) { echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } What does Apache need in order to support both methods of database query?

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  • SQL Server to manage ASP.NET sessions doesn't work

    - by windforceus
    I follow the direction in here How to configure SQL Server to manage ASP.NET sessions to create ASPState db. I have 2 web application in IIS 7. In IIS web application setting, i go to "Session State" and set session state as "SQL Server" and provide connection string. In each web application web.config, i add <sessionState mode="SQLServer" allowCustomSqlDatabase="false" sqlConnectionString="data source=server;user id=user;password=password" cookieless="false" timeout="7200" /> I create a session , Session["Data"] = "test" in Web App A and go to Web App B in the same browser to print it Response.Write(Session["Data"]); It shows NOTHING. I can see there are data in table : ASPStateTempApplications and ASPStateTempSessions under ASPState Database. Also, i dont see any error in event log. Can anyone think anything i may do wrong? Thanks!!

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  • Is there any problem when I mix JSF with plain HTML?

    - by RhigoHR
    I have the next code: <li> <h:form rendered="#{!loginController.session}"> <h3>Inicio de Sesi&oacute;n</h3> <h:panelGrid columns="2" cellpadding="7"> <h:outputText value="Usuario: " /> <h:inputText id="loginname" value="#{loginController.loginname}" maxlength="16" /> <h:outputText value="Contrase&ntilde;a: " /> <h:inputSecret id="password" value="#{loginController.password}" maxlength="16"/> <h:outputText value="" /> <h:commandButton value="Iniciar Sesi&oacute;n" action="#{loginController.CheckValidUser}" /> </h:panelGrid> </h:form> </li> But when run that the page doesn't render the form, anybody can tell me why?

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  • Rails + facebox + authlogic - how?

    - by Vitaly
    Hello, on my web site I want to have login/registration form in modal window done using facebox (jQuery plugin). What is better: Create view with one method and template that has form and refer facebox to this view. Create static HTML file in public directory and refer facebox to this static page. What I want to achieve is: Easy verification (like "user name already taken", "password confirmation doesn't match password" and stuff like that). Easy submit and redirect I'm new to Rails, I just know about forms verification in Django, so for Django I would probably choose option 1, but it might be another thing in Ruby.

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  • System.ServiceModel.Channels.MessageHeader Error

    - by user220511
    I'm trying to get the following to work on my machine but I get an error (Cannot create an instance of the abstract class or interface 'System.ServiceModel.Channels.MessageHeader') using System; using System.IO; using System.Reflection; namespace com.mycompanyname.business { /// /// Summary description for SessionCreateRQClient. /// class SessionCreateRQClient { /// /// The main entry point. /// [STAThread] static void Main(string[] args) { try { // Set user information, including security credentials and the IPCC. string username = "user"; string password = "password"; string ipcc = "IPCC"; string domain = "DEFAULT"; string temp = Environment.GetEnvironmentVariable("tmp"); // Get temp directory string PropsFileName = temp + "/session.properties"; // Define dir and file name DateTime dt = DateTime.UtcNow; string tstamp = dt.ToString("s") + "Z"; //Create the message header and provide the conversation ID. MessageHeader msgHeader = new MessageHeader(); msgHeader.ConversationId = "TestSession"; // Set the ConversationId From from = new From(); PartyId fromPartyId = new PartyId(); PartyId[] fromPartyIdArr = new PartyId[1]; fromPartyId.Value = "WebServiceClient"; fromPartyIdArr[0] = fromPartyId; from.PartyId = fromPartyIdArr; msgHeader.From = from; To to = new To(); PartyId toPartyId = new PartyId(); PartyId[] toPartyIdArr = new PartyId[1]; toPartyId.Value = "WebServiceSupplier"; toPartyIdArr[0] = toPartyId; to.PartyId = toPartyIdArr; msgHeader.To = to; //Add the value for eb:CPAId, which is the IPCC. //Add the value for the action code of this Web service, SessionCreateRQ. msgHeader.CPAId = ipcc; msgHeader.Action = "SessionCreateRQ"; Service service = new Service(); service.Value = "SessionCreate"; msgHeader.Service = service; MessageData msgData = new MessageData(); msgData.MessageId = "mid:[email protected]"; msgData.Timestamp = tstamp; msgHeader.MessageData = msgData; Security security = new Security(); SecurityUsernameToken securityUserToken = new SecurityUsernameToken(); securityUserToken.Username = username; securityUserToken.Password = password; securityUserToken.Organization = ipcc; securityUserToken.Domain = domain; security.UsernameToken = securityUserToken; SessionCreateRQ req = new SessionCreateRQ(); SessionCreateRQPOS pos = new SessionCreateRQPOS(); SessionCreateRQPOSSource source = new SessionCreateRQPOSSource(); source.PseudoCityCode = ipcc; pos.Source = source; req.POS = pos; SessionCreateRQService serviceObj = new SessionCreateRQService(); serviceObj.MessageHeaderValue = msgHeader; serviceObj.SecurityValue = security; SessionCreateRS resp = serviceObj.SessionCreateRQ(req); // Send the request if (resp.Errors != null && resp.Errors.Error != null) { Console.WriteLine("Error : " + resp.Errors.Error.ErrorInfo.Message); } else { msgHeader = serviceObj.MessageHeaderValue; security = serviceObj.SecurityValue; Console.WriteLine("**********************************************"); Console.WriteLine("Response of SessionCreateRQ service"); Console.WriteLine("BinarySecurityToken returned : " + security.BinarySecurityToken); Console.WriteLine("**********************************************"); string ConvIdLine = "convid="+msgHeader.ConversationId; // ConversationId to a string string TokenLine = "securitytoken="+security.BinarySecurityToken; // BinarySecurityToken to a string string ipccLine = "ipcc="+ipcc; // IPCC to a string File.Delete(PropsFileName); // Clean up TextWriter tw = new StreamWriter(PropsFileName); // Create & open the file tw.WriteLine(DateTime.Now); // Write the date for reference tw.WriteLine(TokenLine); // Write the BinarySecurityToken tw.WriteLine(ConvIdLine); // Write the ConversationId tw.WriteLine(ipccLine); // Write the IPCC tw.Close(); //Console.Read(); } } catch(Exception e) { Console.WriteLine("Exception Message : " + e.Message ); Console.WriteLine("Exception Stack Trace : " + e.StackTrace); Console.Read(); } } } } I have added the reference System.ServiceModel and the lines: using System.ServiceModel; using System.ServiceModel.Channels; but I continue to get that error when trying to compile -- "Cannot create an instance of the abstract class or interface 'System.ServiceModel.Channels.MessageHeader'" I am using Microsoft Visual Studio 2008 Version 9.0.21022.8 RTM Microsoft .NET Framework Version 3.5 SP1 Professional Edition Is there another reference I have to add? Or a dll to move over? I wonder was the code above written for Framework 2.0 only? Thanks for your help.

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  • String Compression using Lempel-Ziv

    - by roybot
    Im looking for a way of compressing a given string using the Lempel-Ziv Algorithm. Preferably there would only be a set of two functions, encoder and decoder. The encoder takes the string and returns an integer. The decoder takes the integer and returns the original string. Time complexity is not important. How would you implement this?

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  • Linked lists in Java - help with assignment

    - by user368241
    Representation of a string in linked lists In every intersection in the list there will be 3 fields : The letter itself. The number of times it appears consecutively. A pointer to the next intersection in the list. The following class CharNode represents a intersection in the list : public class CharNode { private char _data; private int _value; private charNode _next; public CharNode (char c, int val, charNode n) { _data = c; _value = val; _next = n; } public charNode getNext() { return _next; } public void setNext (charNode node) { _next = node; } public int getValue() { return _value; } public void setValue (int v) { value = v; } public char getData() { return _data; } public void setData (char c) { _data = c; } } The class StringList represents the whole list : public class StringList { private charNode _head; public StringList() { _head = null; } public StringList (CharNode node) { _head = node; } } Add methods to the class StringList according to the details : (I will add methods gradually according to my specific questions) (Pay attention, these are methods from the class String and we want to fulfill them by the representation of a string by a list as explained above) public int indexOf (int ch) - returns the index in the string it is operated on of the first appeareance of the char "ch". If the char "ch" doesn't appear in the string, returns -1. If the value of fromIndex isn't in the range, returns -1. Pay attention to all the possible error cases. Write what is the time complexity and space complexity of every method that you wrote. Make sure the methods you wrote are effective. It is NOT allowed to use ready classes of Java. It is NOT allowed to move to string and use string operations. Here is my try to write the method indexOf (int ch). Kindly assist me with fixing the bugs so I can move on. public int indexOf (int ch) { int count = 0; charNode pose = _head; if (pose == null ) { return -1; } for (pose = _head; pose!=null && pose.getNext()!='ch'; pose = pose.getNext()) { count++; } if (pose!=null) return count; else return -1; }

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  • JavaScript Validation

    - by Sandeep Pathak
    Have a text field in the jsp which shows and takes input for ftp Url like below : ftp://ftplog:*****@10.203.291.177/abc/DS/Simulator/B11/B11/L2 The password field above is masked . Now when user tries the edit say ftp to sftp or File Path , He should re-type the password too , other wise What I will be getting in server is only "*" . Can somebody suggest the best way of validating this . It has a lot of test cases that has to be taken care of . Thanks .

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  • Insert value in SQL database

    - by littleBrain
    In SQL Server 2005, I'm trying to figure out How to fill up the following fields? Any kind of help will be highly appreciated.. INSERT INTO [Fisharoo].[dbo].[Accounts] ([FirstName] ,[LastName] ,[Email] ,[EmailVerified] ,[Zip] ,[Username] ,[Password] ,[BirthDate] ,[CreateDate] ,[LastUpdateDate] ,[TermID] ,[AgreedToTermsDate]) VALUES (<FirstName, varchar(30),> ,<LastName, varchar(30),> ,<Email, varchar(150),> ,<EmailVerified, bit,> ,<Zip, varchar(15),> ,<Username, varchar(30),> ,<Password, varchar(50),> ,<BirthDate, smalldatetime,> ,<CreateDate, smalldatetime,> ,<LastUpdateDate, smalldatetime,> ,<TermID, int,> ,<AgreedToTermsDate, smalldatetime,>)

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  • PHP with SQL Injection

    - by Scott S
    For our first assignment in a System Security class, we have to hack into the professors "cheaply organized" sql database. I know the only user is "admin" and the select statement generated in the php is: select user_id from user where user_username = 'admin' AND user_password = md5('noob') I am having a number of problems attempting to bypass the password part of this statement as the professor has some javascript embedded in the page to sanitize the username and password of any non-alphanumeric values. This can be bypassed by turning off javascript :P but any values sent still get cleaned by the operating system (some build of Debian 32-bit). I've seen the code for the login request and it does not escape any characters. How do I bypass the operating systems escape sequences?

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  • problems, custum wrap (class) around PDO, doesn't work

    - by Knarf
    DB::construct(); $STH = DB::prepare('INSERT INTO users (username, password, email, activationkey) VALUES (?, UNHEX(?), ?, ?)'); var_dump($STH); $result = $STH->execute(array('test', 'nils', '[email protected]', '227a038fe9c81515b514cb152188e95c')); echo "working? <br />"; if($result == false) echo 'noooo...'; It outputs and doesn't put anything in the database. Works with a similare code with DPO just without my DB class. But I doesn't get any errors. Anyone have an idea what the problem could be? object(PDOStatement)#2 (1) { ["queryString"]=> string(87) "INSERT INTO users (username, password, email, activationkey) VALUES (?, UNHEX(?), ?, ?)" } working? <br /> noooo...

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