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  • Problem with between join for sqlalchemy orm relation.

    - by Gary van der Merwe
    I'm trying to create a relation that has a between join. Here is a shortish example of what I'm trying to do: #!/usr/bin/env python import sqlalchemy as sa from sqlalchemy import orm from sqlalchemy.engine.base import Engine from sqlalchemy.ext.declarative import declarative_base metadata = sa.MetaData() Base = declarative_base(metadata=metadata) engine = sa.create_engine('sqlite:///:memory:') class Network(Base): __tablename__ = "network" id = sa.Column(sa.Integer, primary_key=True) ip_net_addr_db = sa.Column('ip_net_addr', sa.Integer, index=True) ip_broadcast_addr_db = sa.Column('ip_broadcast_addr', sa.Integer, index=True) # This can be determined from the net address and the net mask, but we store # it in the db so that we can join with the address table. ip_net_mask_len = sa.Column(sa.SmallInteger) class Address(Base): __tablename__ = "address" ip_addr_db = sa.Column('ip_addr', sa.Integer, primary_key=True, index=True, unique=True) Network.addresses = orm.relation(Address, primaryjoin=Address.ip_addr_db.between( Network.ip_net_addr_db, Network.ip_broadcast_addr_db), foreign_keys=[Address.ip_addr_db]) metadata.create_all(engine) Session = orm.sessionmaker(bind=engine) Network() I you run this, you get this error: ArgumentError: Could not determine relation direction for primaryjoin condition 'address.ip_addr BETWEEN network.ip_net_addr AND network.ip_broadcast_addr', on relation Network.addresses. Do the columns in 'foreign_keys' represent only the 'foreign' columns in this join condition ? The answer to that question is Yes, but I cant figure out how to tell it that

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  • PHPMyAdmin: "General relation features: Disabled"

    - by Simón
    I've been looking around for something like this for a while, and I've found some tips on similar issues, but not exactly the same. I really don't know what to do. I downloaded and installed WAMP, and I have a MySQL and PHPMyAdmin setup according to common indications that can be found everywhere (securing MySQL root account, etc.). When I log into PHPMyAdmin (either as root or as pma), I see the following message at the bottom of the page: The additional features for working with linked tables have been deactivated. To find out why click here. And when following the link, got a page with the following: Server: localhost $cfg['Servers'][$i]['pmadb'] ... OK $cfg['Servers'][$i]['relation'] ... OK General relation features: Disabled $cfg['Servers'][$i]['table_info'] ... OK Display Features: Disabled $cfg['Servers'][$i]['table_coords'] ... OK $cfg['Servers'][$i]['pdf_pages'] ... OK Creation of PDFs: Disabled $cfg['Servers'][$i]['column_info'] ... OK Displaying Column Comments: Disabled Bookmarked SQL query: Disabled Browser transformation: Disabled $cfg['Servers'][$i]['history'] ... OK SQL history: Disabled $cfg['Servers'][$i]['designer_coords'] ... OK Designer: Disabled Somebody please explain to me, why the heck if all settings are "OK" the features remain "Disabled"? Note: at first all the settings were "not OK" and I managed to add the settings to config.inc.php, and then created the tables using scripts/create_tables.php. Of course I have already tried restarting the server or clearing the browser cache (several times, so I am sure the problem comes elsewhere).

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  • inverse relation to multiple inheriting classes in django

    - by Ofri Raviv
    Here are my schematic models: class Law(models.Model): ... class Bill(models.Model): ... # data for a proposed law, or change of an existing law class PrivateBill(Bill): ... # data for a Bill that was initiated by a parliament member class GovernmentBill(Bill): ... # data for a Bill that was initiated by the government It is possible and likely that in the future I (or maybe someone else) would want to add more Bill types. Every Bill should point to a Law (indicating what law this bill is going to change) and my question is: What is the best way to implement this? If I add the ForeignKey(Law) to Bill, I'll have a relation from every Bill to Law, but a Law would only have an inverse relation to Bills (bill_set), and not a different inverse relation to each type of bill. Of course I'll be able to filter each type of bill to get only the ones pointing to a specific Law, but this is something I think I'll need to use often, so I think having privatebill_set, governmentbill_set etc would make the code more readable. Another possible solution is to add the foreign key to each of the inheriting classes (this would give me a privatebill_set, governmentbill_set, futurebill_set), but that seems hairy because I would be relying on future programmers to remember to add that relation. How would you solve this?

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  • How to configure Hibernate database reverse engineering tool to map database table relation as a ent

    - by Piotr Kochanski
    Is it possible to configure Hibernate reverse engineering and code generation tool in such a way that one-to-many relation between tables is mapped to entities inheritance instead of enrites relation? I have Person table and Employee table, which are related with the foreign key (Person contains basic information, Employee the rest). In my Java code I would like this relation mapped to inheritance Employee extends Person. This can be done by hand, but maybe I missed some custom configuration parameter that I can use. I couldn't find any official documentation - docs link on RedHat Hibernate page (http://www.hibernate.org/5.html#A10) is broken...

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  • Parent-Child relation while using object data source

    - by Saba
    Hello guys I am experiencing with a class generator I've written, which generates a class for each table in database with each table field as a property and such. Before that, I used to add a typed dataset to the project and add some tables to it. It automatically detected the relationship between tables and when I added a parent table as data source of a datagrid, I could add another datagrid and use the foreing key data member of it's bindingsource to fill it, and when someone moved the focus on parent datagrid, the data in child datagrid would change accordingly. Now that I have my classes, I add an object as data source for my 2 datagrids, but obviously it doesn't detect a parent child relation. But It'd really help if I could have that foreign key relation in my object datasources. Is there any way to have that relation in object datasource?

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  • Rails: Modeling an optional relation in ActiveRecord

    - by Hassinus
    I would like to map a relation between two Rails models, where one side can be optionnal. Let's me be more precise... I have two models: Profile that stores user profile information (name, age,...) and User model that stores user access to the application (email, password,...). To give you more information, User model is handled by Devise gem for signup/signin. Here is the scenario of my app: 1/ When a user register, a new row is created in User table and there is an equivalent in Profile table. This leads to the following script: class User < ActiveRecord::Base belongs_to :profile end 2/ A user can create it's profile without registering (kind of public profile with public information), so a row in Profile doesn't have necessarily a User row equivalent (here is the optional relation, the 0..1 relation in UML). Question: What is the corresponding script to put in class Profile < AR::Base to map optionally with User? Thanks in advance.

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  • Relation between .p7b and .spc digital certificate files

    - by Frederick
    My company have just renewed their digital certificate from Thawte. The previous certificate I was using had an 'spc' extension. The new certificate I've been handed ends in a 'p7b'. Although I can use this p7b file directly for signing, I was just wondering whether there's some way to convert this to an spc file which I can then sign with as I was doing previously. Is it a recommended practice to use p7b directly for signing? Secondly, what exactly is the relation, if any, between the two types of files?

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  • Why do i get a circular reference exception when calling to_json on an ActiveRecord::Relation

    - by midas06
    In Rails 3 (beta 3 on 1.8.7), when calling to_json on a relation i get a circular reference exception. Converting that relation to an array first, and THEN calling to_json works. Code That fails: Model.where().to_json (Where model is any model in your Rails 3 app) Code that works: Model.where().to_a.to_json This can be reproed on the console. Has anyone else run in to this? Is this expected?

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  • Are there known problems with >= and <= and the eval function in JS?

    - by Augier
    I am currently writing a JS rules engine which at one point needs to evaluate boolean expressions using the eval() function. Firstly I construct an equation as such: var equation = "relation.relatedTrigger.previousValue" + " " + relation.operator + " " + "relation.value"; relation.relatedTrigger.previousValue is the value I want to compare. relation.operator is the operator (either "==", "!=", <=, "<", "", ="). relation.value is the value I want to compare with. I then simply pass this string to the eval function and it returns true or false as such: return eval(equation); This works absolutely fine (with words and numbers) or all of the operators except for = and <=. E.g. When evaluating the equation: relation.relatedTrigger.previousValue <= 100 It returns true when previousValue = 0,1,10,100 & all negative numbers but false for everything in between. I would greatly appreciate the help of anyone to either answer my question or to help me find an alternative solution. Regards, Augier. P.S. I don't need a speech on the insecurities of the eval() function. Any value given to relation.relatedTrigger.previousValue is predefined. edit: Here is the full function: function evaluateRelation(relation) { console.log("Evaluating relation") var currentValue; //if multiple values if(relation.value.indexOf(";") != -1) { var values = relation.value.split(";"); for (x in values) { var equation = "relation.relatedTrigger.previousValue" + " " + relation.operator + " " + "values[x]"; currentValue = eval(equation); if (currentValue) return true; } return false; } //if single value else { //Evaluate the relation and get boolean var equation = "relation.relatedTrigger.previousValue" + " " + relation.operator + " " + "relation.value"; console.log("relation.relatedTrigger.previousValue " + relation.relatedTrigger.previousValue); console.log(equation); return eval(equation); } } Answer: Provided by KennyTM below. A string comparison doesn't work. Converting to a numerical was needed.

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  • iphone coredata removing records between two entities connected by relation ship

    - by satyam
    I'm implementing core data in my iphone app. It has two entities. Entity1: LatestData Entity2: LatestDetailedData LatestData has URL, publishedDate, heading LatestDetailedData has URL, NewsDescription, PublishedDate, Author Both entities have same URL for a record. Both the entities are connected with inverse relation ship. And the relation ship is "delete-Cascaded" What I want: If I remove a record in LatestData, I want the record with same URL in LatestDetailedData must also be deleted. How?

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  • A many-to-many relation joined disallows intellisense/lookup in joined table

    - by BerggreenDK
    I want to be able to select a product and retrieve all sub-parts(products) within it. My approach is to find the Product id and then retrieve the list of ProductParts with that as a parent and while fetching those, follow the key back to the Product child to get the name and details of each Part. I was hoping to use something similar to: part.linked_product_id.name I have two tables. One for [Product] and and a relation [ProductPart] that has two FK ID's to [Product] Table Product() { int ID; // (PRIMARY, NOT NULL) String Name; ... details removed for overview purpose... } Table ProductPart() { int Product_ID; // FK (linked with relation to Product/parent) int Part_Product_ID; // FK (linked with relation to Product/childen) ... details removed for overview purpose... } I have checked the SQL-diagram and it shows the two relations (both are one to many) and in my DBML they also looks right. Here is my LINQ to SQL snippet that doesnt work for me... wondering why my joins dont work as supposed. FaultySnippet() { ProductDataContext db = new ProductDataContext(); var list = ( from part in db.ProductParts join prod in db.Products on part.Part_Product_ID equals prod.ID where (part.Product_ID == product_ID) select new { Name = part.Part_Product_ID. ?? // <-- NO details from Joined table? ... rest of properties from ProductPart join... I hoped... } ); }

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  • doctrine findby relation

    - by iggnition
    I'm having trouble selecting a subset of data with doctrine. I have 3 tables Location Contact Contact_location The contact and location tables hold a name and an id the other table holds only ID's. For instance: Location loc_id: 1 name: detroit Contact contact_id: 1 name: Mike Contact_location loc_id: 1 contact_id: 1 In doctrine there is a many to many relation between the location and contact tables with contact_location as the ref_class. What i want to do is on my location page i want to find all contacts where for instance the loc_id = 1. I tried: $this->installedbases = Doctrine::getTable('contact')->findByloc_id(1); hoping doctrine would see the relation and get it, but it does not. How can i make doctrine search in relevant related tables? I read it can be done using Findby but i find the documentation unclear.

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  • When to use memberEnd and when navigableOwnedEnd in an UML class diagram?

    - by Ivan
    I've download a trial of Altova UModel and am starting using UML. As a practical beginning I am modelling a personal information manager application, which includes a web bookmark managing. A Bookmark can belong to many (or no) Tags at once and a Tag can contain many (or no if all the bookmarks it contained were deleted) bookmarks. The relation has to be both-way navigable - a user has to be able to see all Bookmarks with a particular Tags ans all Tags of a Bookmark. What is the correct UML relation between Bookmark and Tag classes? As far as I understand UML now, it is an Association (not an Aggregation). But for a 2-way navigable many-to-many relation I can specify ends roles as "memberEnd" or "when navigableOwnedEnd", graphically the connection looks the same in both cases (an arrow) (which as I understand means navigability) but a property appears in the class box in case only when "memberEnd" is used. How should I specif it in the model If I mean both-way navigable many-to-many relation there?

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  • Relation/Sort not working in rails controller?

    - by Elliot
    I have the following relation in my rails app: genre - has many - authors authors - belong to genre and has many books books - belongs to authors and belongs to users (users can add books to the db) in my controller I have: @books=current_user.books(:include => [:author => :genre], :order => 'created_at DESC') While I am able to use the @books variable in my views - nothing is done correctly (i.e. its not showing me only books added by that user, and its not descending by created_at)... any ideas? -- Also I'm using clearance for the user auth, so current_user without the @ in the controller seems to work fine Actually, I think the relation is working, only the sort might not be working...

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  • When to use memberEnd and when navigableOwnedEnd (in Altova notation) in an UML class diagram?

    - by Ivan
    I've download a trial of Altova UModel and am starting using UML. As a practical beginning I am modelling a personal information manager application, which includes a web bookmark managing. A Bookmark can belong to many (or no) Tags at once and a Tag can contain many (or no if all the bookmarks it contained were deleted) bookmarks. The relation has to be both-way navigable - a user has to be able to see all Bookmarks with a particular Tags ans all Tags of a Bookmark. What is the correct UML relation between Bookmark and Tag classes? As far as I understand UML now, it is an Association (not an Aggregation). But for a 2-way navigable many-to-many relation I can specify ends roles as "memberEnd" or "when navigableOwnedEnd", graphically the connection looks the same in both cases (an arrow) (which as I understand means navigability) but a property appears in the class box in case only when "memberEnd" is used. How should I specif it in the model If I mean both-way navigable many-to-many relation there?

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  • Network ActiveRecord relation with Rails

    - by Zag zag..
    Hi, I have a has and belongs to many relation between User and Article models, and I would like to link them even if an article if not hosted on the same database then a user. For example, If an article exists at foo.com/articles/3 and a user exists at bar.com/users/1, If would like to be able to do from foo.com web interface or bar.com web interface this kind of query: a_user.articles (or an_article.users). I think this can be possible adding a field like "url" in users and articles tables. But I don't know how to process for ActiveRecord. My Article model looks like this: class Article < ActiveRecord::Base has_and_belongs_to_many :users end Is there yet some example of project using this kind of relation over internet? Many thanks

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  • One on One table relation - is it harmful to keep relation in both tables?

    - by EBAGHAKI
    I have 2 tables that their rows have one on one relation.. For you to understand the situation, suppose there is one table with user informations and there is another table that contains a very specific informations and each user can only link to one these specific kind of informations ( suppose second table as characters ) And that character can only assign to the user who grabs it, Is it against the rules of designing clean databases to hold the relation key in both tables? User Table: user_id, name, age, character_id Character Table: character_id, shape, user_id I have to do it for performance, how do you think about it?

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  • La réponse d’Oracle aux nouveaux enjeux de la Grande Distribution Catégorie Apps

    - by Valérie De Montvallon
    Retrouvez l'interview de Franck Westrelin, Directeur Associé Oracle Retail, lors du Retail Business Technologie Forum du 20 novembre 2012 à Paris. Résumé de l'interview : Franck Westerlin discute des grandes tendances de la distribution : les changements du comportement client, l'étendu des outils d’achat et d’interactions clients, l'environnement concurrentiel et saturé… Il présente aussi les attentes des consommateurs actuels : une expérience d’achat de qualité, l'homogénéité et la cohérence par rapport aux points d’interactions avec les distributeurs. Enfin, il démontre comment Oracle répond à ces enjeux grâce à l'innovation : optimisation des interactions client et des processus métier (Gestion commerciale, eCommerce, planifications, CRM, back office magasin, supply chain…) Retrouvez l'interview sur notre Chaine Youtube Oracle Applications France ! 

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  • Découvrir la nouvelle génération CRM ? Connectez-vous au Customer Concepts TV le 24 april 2012

    - by Kinoa
    Accélérer votre stratégie commerciale  Les entreprises doivent repenser leurs processus de vente, optimiser leur performance, augmenter la productivité des équipes et se concentrer sur les opportunités à plus fort potentiel. Danny Rippon, Oracle CRM Solutions Sales Development Director, souhaite partager avec vous la stratégie gagnante dans cette video : la nouvelle génération de CRM. Vous y trouverez des conseils avisés pour tirer au maximum profit de votre CRM. Rejoignez-nous sur Customer Concepts TV ! Pour en savoir plus, visionnez cette video :

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  • Join the Customer Revolution – 25 oct 2012 - Paris

    - by Valérie De Montvallon
    Faites redécouvrir votre marque à vos clients !   Rendez-vous le 25 octobre à 19h pour découvrir comment les outils de nouvelle génération peuvent permettre à vos équipes de proposer une nouvelle expérience client.   Table ronde animée par Arnaud le Gal, rédacteur en chef des Echos Avec les témoignages d’ACCOR et Bouygues Telecom. Informations, inscriptions sur la page Oracle Customer Experience

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  • At what size of data does it become beneficial to move from SQL to NoSQL?

    - by wobbily_col
    As a relational database programmer (most of the time), I read articles about how relational databases don't scale, and NoSQL solutions such as MongoDB do. As most of the databases I have developed so far have been small to mid scale, I have never had a problem that hasn't been solved by some indexing, query optimization or schema redesign. What sort of size would I expect to see MySQL struggling with. How many rows? (I know this is going to depend on the application, and type of data stored. the one that got me thing was basically a genetics database, so would have one main table, with 3 or 4 lookup tables. The main table will contain amongst other things, a chromosome reference, and a position coordinate. It will likely get queried for a number of entries between two potions on a chromosome, to see what is stored there).

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  • Django Admin: OneToOne Relation as an Inline?

    - by Jim Robert
    I am putting together the admin for a satchmo application. Satchmo uses OneToOne relations to extend the base Product model, and I'd like to edit it all on one page. It is possible to have a OneToOne relation as an Inline? If not, what is the best way to add a few fields to a given page of my admin that will eventually be saved into the OneToOne relation? for example: class Product(models.Model): name = models.CharField(max_length=100) ... class MyProduct(models.Model): product = models.OneToOne(Product) ... I tried this for my admin but it does not work, and seems to expect a Foreign Key: class ProductInline(admin.StackedInline): model = Product fields = ('name',) class MyProductAdmin(admin.ModelAdmin): inlines = (AlbumProductInline,) admin.site.register(MyProduct, MyProductAdmin) Which throws this error: <class 'satchmo.product.models.Product'> has no ForeignKey to <class 'my_app.models.MyProduct'> Is the only way to do this a Custom Form? edit: Just tried the following code to add the fields directly... also does not work: class AlbumAdmin(admin.ModelAdmin): fields = ('product__name',)

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  • Relation between HTTP Keep Alive duration and TCP timeout duration

    - by Suresh Kumar
    I am trying to understand the relation between TCP/IP and HTTP timeout values. Are these two timeout values different or same? Most Web servers allow users to set the HTTP Keep Alive timeout value through some configuration. How is this value used by the Web servers? is this value just set on the underlying TCP/IP socket i.e is the HTTP Keep Alive timeout and TCP/IP Keep Alive Timeout same? or are they treated differently? My understanding is (maybe incorrect): The Web server uses the default timeout on the underlying TCP socket (i.e. indefinite) regardless of the configured HTTP Keep Alive timeout and creates a Worker thread that counts down the specified HTTP timeout interval. When the Worker thread hits zero, it closes the connection. EDIT: My question is about the relation or difference between the two timeout durations i.e. what will happen when HTTP keep-alive timeout duration and the timeout on the Socket (SO_TIMEOUT) which the Web server uses is different? should I even worry about these two being same or not?

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