Search Results

Search found 9235 results on 370 pages for 'social networking'.

Page 234/370 | < Previous Page | 230 231 232 233 234 235 236 237 238 239 240 241  | Next Page >

  • How to access a web service behind a NAT?

    - by jr
    We have a product we are deploying to some small businesses. It is basically a RESTful API over SSL using Tomcat. This is installed on the server in the small business and is accessed via an iPhone or other device portable device. So, the devices connecting to the server could come from any number of IP addresses. The problem comes with the installation. When we install this service, it seems to always become a problem when doing port forwarding so the outside world can gain access to tomcat. It seems most time the owner doesn't know router password, etc, etc. I am trying to research other ways we can accomplish this. I've come up with the following and would like to hear other thoughts on the topic. Setup a SSH tunnel from each client office to a central server. Basically the remote devices would connect to that central server on a port and that traffic would be tunneled back to Tomcat in the office. Seems kind of redundant to have SSH and then SSL, but really no other way to accomplish it since end-to-end I need SSL (from device to office). Not sure of performance implications here, but I know it would work. Would need to monitor the tunnel and bring it back up if it goes done, would need to handle SSH key exchanges, etc. Setup uPNP to try and configure the hole for me. Would likely work most of the time, but uPNP isn't guaranteed to be turned on. May be a good next step. Come up with some type of NAT transversal scheme. I'm just not familiar with these and uncertain of how they exactly work. We have access to a centralized server which is required for the authentication if that makes it any easier. What else should I be looking at to get this accomplished?

    Read the article

  • Paramiko ssh output stops at --more--

    - by Anesh
    The output stops printing at --more-- any idea how to get the end of the output >>> import paramiko >>> ssh = paramiko.SSHClient() >>> ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy()) >>> conn=ssh.connect("ipaddress",username="user", password="pass") >>> channel = ssh.invoke_shell() >>> channel.send("en\n") 3 >>> channel.send("password\n") 9 >>> channel.send("show security local-user-list\n") 30 >>> results = '' >>> channel.send("\n") 1 >>> results += channel.recv(5000) >>> print results bluecoat>en Password: bluecoat#show security local-user-list Default List: local_user_database Append users loaded from file to default list: false local_user_database Lockout parameters: Max failed attempts: 60 Lockout duration: 3600 Reset interval: 7200 Users: Groups: admin_local Lockout parameters: Max failed attempts: 60 Lockout duration: 3600 Reset interval: 7200 Users: <username> Hashed Password: Enabled: true Groups: <username> Hashed Password: Enabled: true **--More--** As you can see above the output stops printing at --more-- any idea how to get the output to print till the end.

    Read the article

  • Depmod - unresolved symbols in rt73 module

    - by Xolstice
    I'm trying to install a linux driver for my wireless network card (D-Link DWL-G510) on my Red Hat Linux 7.1 machine with a 2.4.37.9 kernel. I downloaded the serial monkey driver from the sourceforge site and was able to successfully compile the module. However, whenever I do a "make install", the make script executes a "depmod -a" command which then complains with the message: "Unresolved symbols in /lib/modules/2.4.37.9/extra/rt73.o". I then executed a "depmod -e" command to show unresolved symbols and it indicates the following information: request_firmware_Rsmp_38ce5074 release_firmware_Rsmp_33934162 I did a grep on the above information and it showed no source files making reference to it. I searched for it on google and it returned no results. Can anyone help?

    Read the article

  • How do I find the IP address of a GPRS modem?

    - by Hanno Fietz
    I want to pull data from a device that is accessed via a serial protocol and has a GPRS modem attached which should allow transparent access over an IP connection. It seems to me that this approach is upside down, because how should I know at which IP address the device currently is? Unfortunately, the device itself is rather dumb, so I can't make it send something to my server, which would reveal the current IP. For home routers on dialup lines, there's dynamic DNS services. Is there something equivalent in the mobile world? Each modem would, of course, have its phone number as a reliable address, but how does that help me? Practically all material on GPRS etc. that I can find online seems to be concerned with initiating the connection from the modem side, since that's what the system is designed for.

    Read the article

  • Python - network buffer handling question...

    - by Patrick Moriarty
    Hi, I want to design a game server in python. The game will mostly just be passing small packets filled with ints, strings, and bytes stuffed into one message. As I'm using a different language to write the game, a normal packet would be sent like so: Writebyte(buffer, 5); // Delimit type of message Writestring(buffer, "Hello"); Sendmessage(buffer, socket); As you can see, it writes the bytes to the buffer, and sends the buffer. Is there any way to read something like this in python? I am aware of the struct module, and I've used it to pack things, but I've never used it to actually read something with mixed types stuck into one message. Thanks for the help.

    Read the article

  • What to do when ServerSocket throws IOException

    - by s5804
    Basically I want to create a rock solid server. while (keepRunning.get()) { try { Socket clientSocket = serverSocket.accept(); ... spawn a new thread to handle the client ... } catch (IOException e) { e.printStackTrace(); // NOW WHAT? } } In the IOException block, what to do? Is the Server socket at fault so it need to be recreated? For example wait a few seconds and then serverSocket = ServerSocketFactory.getDefault().createServerSocket(MY_PORT); However if the server socket is still OK, then it is a pity to close it and kill all previously accepted connections that are still communicating.

    Read the article

  • What happens when we say "listen to a port" ?

    - by smwikipedia
    Hi, When we start a server application, we always need to speicify the port number it listens to. But how is this "listening mechanism" implemented under the hood? My current imagination is like this: The operating system associate the port number with some buffer. The server application's responsibiligy is to monitor this buffer. If there's no data in this buffer, the server application's listen operation will just block the application. When some data arrives from the wire, the operating system will know that check the data and see if it is targed at this port number. And then it will fill the buffer. And then OS will notify the blocked server application and the server application will get the data and continue to run. Question is: If the above scenario is correct, how could the opearting system know there's data arriving from wire? It cannot be a busy pooling. Is it some kind of interrupt-based mechanism? If there's too much data arriving and the buffer is not big enough, will there be data loss? Is the "listen to a port" operation really a blocking operation? Many thanks.

    Read the article

  • How to transfer large files from desktop to server ( .NET)

    - by rahulchandran
    I am writing a .NET 2.0 based desktop client that will send large files ( well largish under 2GB) to a server. Need to develop the server as well. Server can be on any technology It should be secure so an underlying SSL stream is needed What are my options. Any obvious caveats etc I should be aware of To my mind the simplest solution is to open a tcp\ip connection over SSL to the server and send n packets each of size M bytes and then have the server append the chunks to the file and finally send an EOF packet as well IS this horrible. Will the perf suck on the server with all these disk writes What are any other clever options. I am limited to .NET 2.0 on the client if I did move to a WCF client will it buy be something magical and cool for this scenario Thanks

    Read the article

  • SslStream.ReadByte() blocks thread?

    - by alex
    I'm trying to write an Imap4 client. For that I use a SslStream to Connect to the Server. Everything's fine until I send the "Login" command. When I try to get an Answer to it, SslStream.ReadByte() block the thread. The result is that my programm crashes always. Whats happening here?? Code: if (ssl) { s = stream; } int cc = 0; MessageBox.Show("entered"); while (true) { int xs = s.ReadByte(); MessageBox.Show(xs.ToString()); if (xs > 0) { buf.Add((byte)xs); cc++; if (xs == '\n') { break; } if (cc > 10) MessageBox.Show(en.GetString(buf.ToArray())); } else { break; } } MessageBox.Show("left");

    Read the article

  • How do I get current network location name?

    - by Devara Gudda
    In system network preference there are some location names.How to get the current or active network location name and list of all network locations? I guess SystemConfiguration.framework supports this but i didn't get exactly which API to use.Thanks in advance for your answer. RegardsDevara Gudda

    Read the article

  • Get local network interface addresses using only proc?

    - by Matt Joiner
    How can I obtain the (IPv4) addresses for all network interfaces using only proc? After some extensive investigation I've discovered the following: ifconfig makes use of SIOCGIFADDR, which requires open sockets and advance knowledge of all the interface names. It also isn't documented in any manual pages on Linux. proc contains /proc/net/dev, but this is a list of interface statistics. proc contains /proc/net/if_inet6, which is exactly what I need but for IPv6. Generally interfaces are easy to find in proc, but actual addresses are very rarely used except where explicitly part of some connection. There's a system call called getifaddrs, which is very much a "magical" function you'd expect to see in Windows. It's also implemented on BSD. However it's not very text-oriented, which makes it difficult to use from non-C languages.

    Read the article

  • Cannot connect to Github?

    - by user2973438
    so I tried to push some updates onto my repo on github via terminal on Mac OSX 10.8.4 and it doesn't work. I've been getting the same error many times: Lillys-MacBook-Air:Yuewei Lilly$ git push origin master error: Failed connect to github.com:443; Operation timed out while accessing https://github.com/lillybeans/Yuewei.git/info/refs?service=git-receive-pack fatal: HTTP request failed Some background: I've pushed many projects onto github before using terminal (when I was in Canada). I am currently in Shanghai, China, could it be the GFW? But when I was in Beijing, I was able to push projects onto github still. when I do ping github.com: Lillys-MacBook-Air:Yuewei Lilly$ ping github.com PING github.com (192.30.252.131): 56 data bytes Request timeout for icmp_seq 0 Request timeout for icmp_seq 1 ping: sendto: No route to host Request timeout for icmp_seq 2 ping: sendto: Host is down Request timeout for icmp_seq 3 ping: sendto: Host is down Request timeout for icmp_seq 4 ping: sendto: Host is down Request timeout for icmp_seq 5 ping: sendto: Host is down Request timeout for icmp_seq 6 ping: sendto: Host is down Request timeout for icmp_seq 7 ^C --- github.com ping statistics --- 9 packets transmitted, 0 packets received, 100.0% packet loss Lillys-MacBook-Air:Yuewei Lilly$ I have ShadowSocks (proxy) turned on. Without it I can't access github.com via browser, with it, I can. also when I do "git remote -v" I see both my pull and push remote repos correctly listed. Thank you in advance!

    Read the article

  • Strange IP addresses in tomcat

    - by mdev
    Some where I have this in some generic class. public static String getRequestIp (HttpServletRequest request){ String ipaddr = request.getHeader("X-FORWARDED-FOR"); if (ipaddr == null)ipaddr = request.getRemoteAddr(); return ipaddr; } For every request i call that method and in a certain moment i insert a record in a mysql database. In most cases it works normally and i can see a record for every request with a valid ip address in the right field. But sometimes where the IP should be there is something like this. "unknown, 93.186.30.120" or "10.0.1.169, 186.38.84.3" Apache is at the front listening at port 80 and used as proxy to Tomcat that listens at port 8081. My router config would not allow to pass any conection that come by any port other than 80. Any Help? Thanks in advance.

    Read the article

  • S3 file Uploading from Mac app though PHP?

    - by Ilija Tovilo
    I have asked this question before, but it was deleted due too little information. I'll try to be more concrete this time. I have an Objective-C mac application, which should allow users to upload files to S3-storage. The s3 storage is mine, the users don't have an Amazon account. Until now, the files were uploaded directly to the amazon servers. After thinking some more about it, it wasn't really a great concept, regarding security and flexibility. I want to add a server in between. The user should authenticate with my server, the server would open a session if the authentication was successful, and the file-sharing could begin. Now my question. I want to upload the files to S3. One option would be to make a POST-request and wait until the server would receive the file. Problems here are, that there would be a delay, when the file is being uploaded from my server to the S3 servers, and it would double the uploading time. Best would be, if I could validate the request, and then redirecting it, so the client uploads it directly to the s3-storage. Not sure if this is possible somehow. Uploading directly to S3 doesn't seem to be very smart. After looking into other apps like Droplr and Dropmark, it looks like they don't do this. Btw. I did this using Little Snitch. They have their api on their own web-server, and that's it. Could someone clear things up for me? EDIT How should I transmit my files to S3? Is there a way to "forward" it, or do I have to upload it to my server and then upload it from there to S3? Like I said, other apps can do this efficiently and without the need of communicating with S3 directly.

    Read the article

  • Send and receive data trough the power network

    - by luvieere
    I'm not interested in a hardware solution, I want to know about software that may "read" modulated signal received trough the power supply - some sort of a low-level driver that would access the power signal in a convenient place and demodulate it. Is there a way to receive signal from the computer's power supply? I'm interested in an API or library that would allow the computer to be seen as a node in a Power Line Communication network and receive data directly through the power cable, without the need for a converter. Is there any active research in this field? Edit: There is software that reads monitors and displays internal component voltages - DC voltage after being converted and filtered by the power supply - now I need is a method of data encoding that would be invariant to conversion and filtering, the original signal embedded in AC being present in some form within the converted DC signal.

    Read the article

  • Network message serialization for game

    - by George R
    Exit-games make a network library product called photon, and they have and actively develop a limited mmo demo. Rather than shooting off json or XML, etc. saying "MovePlayer" (with associated params), they nut that message down to a 2 digit int, via an enum - something like Operations.MovePlayer. There's no denying that a 2 digit int is smaller than a longer string, however I really hate the idea of statically burning each and every message into an enum. Would there be an alternative way to have a MessageID property assign itself a unique 2 digit int based on a lookup table or something? Has anyone dealt with this kind of thing before?

    Read the article

  • Ping broadcast on Win XP SP3

    - by PaulH
    I'm trying to ping the broadcast address 255.255.255.255 on WinXP SP3. If I use the command line, I get host error: C:\>ping 255.255.255.255 Ping request could not find host 255.255.255.255. Please check the name and try again. If I try a C++ program using the iphlpapi, IcmpSendEcho() fails and GetLastError returns 11010 IP_REQ_TIMED_OUT. HANDLE h = ::IcmpCreateFile(); IPAddr broadcast = inet_addr( "255.255.255.255" ); BYTE payload[ 32 ] = { 0 }; IP_OPTION_INFORMATION option = { 255, 0, 0, 0, 0 }; // a buffer with room for 32 replies each containing the full payload std::vector< BYTE > replies( 32 * ( sizeof( ICMP_ECHO_REPLY ) + 32 ) ); DWORD res = ::IcmpSendEcho( h, broadcast, payload, sizeof( payload ), &option, &replies[ 0 ], replies.size(), 1000 ); ::IcmpCloseHandle( h ); I can ping the local broadcast 192.168.0.255 with no problem. What do I need to do to ping the global broadcast? Thanks, PaulH

    Read the article

  • Javascript XMLHttpRequest Post method

    - by user535617
    Hey So I have a question about posting using an XMLHttpRequest. In theory, if I am to post a username and password to an https domain (which I have yet to get working, unfortunately) would the responseText then change to the next website, or should the text fields become filled in? What normally happens is you navigate to this page via browser, enter a username and password, and it uses a POST method when the submit button is clicked, doing some authentication under the hood and returning a different page. I feel like maybe the responseText should even stay exactly the same (which is what happens now), but I don't know as I have no experience with this kind of thing. this.requests[1].open("POST", "https://" + this.address, true); var query = "target=%2Fcgi-bin%2FStatusConfig.cgi%3FPage%3Dindex&userfile=&username=user&password=pass&log+in=Log+in"; this.requests[1].setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); this.requests[1].setRequestHeader("Content-length", query.length); this.requests[1].setRequestHeader("Keep-Alive", 115); this.requests[1].setRequestHeader("Connection", "keep-alive"); this.requests[1].setRequestHeader("Host", this.address); this.requests[1].send(query); this.requests[1].onreadystatechange = onReadyStateChange1; Then basically onReadyStateChange1 displays the responseText when ready. Any light that could be shed on what SHOULD be happening with the post and responseText would be very appreciated. As would any advice in getting the new, logged into page. For further clarification, what I'm trying to do is log in and then return the new page, because the login page displays only log in information/functionality and the page after logging in has a lot of relevant information. I'm not trying to check the credentials as much as I'm trying to get it (the script) to log in so it can access the next page. Granted, the credentials will have to be valid for that. Thanks all.

    Read the article

  • Capturing network traffic on Linux

    - by Quandary
    Question: I have one Windows laptop, one Linux laptop and a wireless router. Now I want to "investigate" the hotmail/windows live protocol. What I want to do is route network traffic from the windows laptop via ethernet to the linux laptop, capture it on the Linux computer, forward it wirelessly to the router, receive the hotmail response from the router on the linux computer and forward it to the windows computer. How do I do that? In essence, switching the Linux laptop between the Windows laptop and the router, to capture network traffic ? Which program is best for capturing/analysing ? Please note that for whatever reason, packet capturing with winpcap on the windows computer doesn't work...

    Read the article

  • How can I force the server socket to re-accept a request from a client?

    - by Roman
    For those who does not want to read a long question here is a short version: A server has an opened socket for a client. The server gets a request to open a socket from the same client-IP and client-port. I want to fore the server not to refuse such a request but to close the old socket and open a new one. How can I do ti? And here is a long (original) question: I have the following situation. There is an established connection between a server and client. Then an external software (Bonjour) says to my client the it does not see the server in the local network. Well, client does nothing about that because of the following reasons: If Bonjour does not see the server it does not necessarily means that client cannot see the server. Even if the client trusts the Bonjour and close the socket it does not improve the situation ("to have no open socket" is worser that "to have a potentially bad socket"). So, client do nothing if server becomes invisible to Bonjour. But than the server re-appears in the Bonjour and Bonjour notify the client about that. In this situation the following situations are possible: The server reappears on a new IP address. So, the client needs to open a new socket to be able to communicate with the server. The server reappears on the old IP address. In this case we have two subcases: 2.1. The server was restarted (switched off and then switched on). So, it does not remember the old socket (which is still used by the client). So, client needs to close the old socket and open a new one (on the same server-IP address and the same server-port). 2.2. We had a temporal network problem and the server was running the whole time. So, the old socket is still available for the use. In this case the client does not really need to close the old socket and reopen a new one. But to simplify my life I decide to close and reopen the socket on the client side in any case (in spite on the fact that it is not really needed in the last described situation). But I can have problems with that solution. If I close the socket on the client side and than try to reopen a socket from the same client-IP and client-port, server will not accept the call for a new socket. The server will think that such a socket already exists. Can I write the server in such a way, that it does not refuse such calls. For example, if it (the server) sees that a client send a request for a socket from the same client-IP and client-port, it (server) close the available socket, associated with this client-IP and client-port and than it reopens a new socket.

    Read the article

  • Local Network - Windows 7 and Vista can't see each other

    - by ca8msm
    I've got a strange issue at home that has been bugging me for weeks, but I really need to get it sorted now so I'll detail as much as I can and hopefully someone can spot what might might be wrong. I have a wireless router connected to the internet and 3 devices connected to it. They are: Name OS Network IPv4 PC1 Windows 7 WORKGROUP 192.168.2.2 LAPTOP1 Vista WORKGROUP 192.168.2.3 PS3 192.168.2.4 and they all get their IP addresses dynamically. Both PC1 and LAPTOP1 can ping PS3 and get a response. PC1 and LAPTOP1 are unable to ping each other by ip address unless I ping by their name (which bizarrely shows that it is pinging via the IPv6 address). Also, to confirm this both PC1 and LAPTOP1 can ping each other via the long IPv6 address that they both have so they can obviously see each other just not via IPv4. I've disabled the firewalls on both machines as well to rule that out. I don't really know what IPv6 is used for and I've tried disabling it on both machines but all that happens then is that neither machine can see each other at all then. Does anyone have any idea of what may be stopping them seeing each other, any ways I can look at fixing this, or any network tools that may help identify where it is failing? Thanks, Mark

    Read the article

  • Mac: How to see list of running network services?

    - by Jordan
    I am writing an application that needs to connect with a running network service on a Mac. Problem is, I have no idea what the service is called or even what port it uses. Is there a way to browse all running network services on my Mac? More info: I am connecting to a MIDI network session (found under 'Audio MIDI settings', present on all OSX installs). Am I correct in thinking this is a network service? I am planning to use NSNetServiceBrowser to locate all local computers running this service. (is this the best way to go about it?) Any help is much appreciated - thanks!

    Read the article

< Previous Page | 230 231 232 233 234 235 236 237 238 239 240 241  | Next Page >