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  • Multiple levels of 'collection.defaultdict' in Python

    - by Morlock
    Thanks to some great folks on SO, I discovered the possibilities offered by collections.defaultdict, notably in readability and speed. I have put them to use with success. Now I would like to implement three levels of dictionaries, the two top ones being defaultdict and the lowest one being int. I don't find the appropriate way to do this. Here is my attempt: from collections import defaultdict d = defaultdict(defaultdict) a = [("key1", {"a1":22, "a2":33}), ("key2", {"a1":32, "a2":55}), ("key3", {"a1":43, "a2":44})] for i in a: d[i[0]] = i[1] Now this works, but the following, which is the desired behavior, doesn't: d["key4"]["a1"] + 1 I suspect that I should have declared somewhere that the second level defaultdict is of type int, but I didn't find where or how to do so. The reason I am using defaultdict in the first place is to avoid having to initialize the dictionary for each new key. Any more elegant suggestion? Thanks pythoneers!

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  • Visual-C++ Linker Error

    - by LordByron
    I have a class called MODEL in which public static int theMaxFrames resides. The class is defined in its own header file. theMaxFrames is accessed by a class within the MODEL class and by one function, void set_up(), which is also in the MODEL class. The Render.cpp source file contains a function which calls a function in the Direct3D.cpp source file which in turn calls the set_up() function through a MODEL object. This is the only connection between these two source files and theMaxFrames. When I try to compile my code I get the following error messages: 1Direct3D.obj : error LNK2001: unresolved external symbol "public: static int MODEL::theMaxFrames" (?theMaxFrames@MODEL@@2HA) 1Render.obj : error LNK2001: unresolved external symbol "public: static int MODEL::theMaxFrames" (?theMaxFrames@MODEL@@2HA) 1C:\Users\Byron\Documents\Visual Studio 2008\Projects\xFileViewer\Debug\xFileViewer.exe : fatal error LNK1120: 1 unresolved externals

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  • Visual Studio 2010 doesn't install the editor

    - by MoJo
    For some reason when I install Visual Studio 2010 Ultimate using the web installer the actual editor (the IDE) doesn't get installed! Can't post images so here are the install options: http://img17.imageshack.us/img17/9223/clipboardimagez.jpg Start menu: http://img856.imageshack.us/img856/2503/80767250.png I only want C++ and C#, nothing else... What am I missing? If it helps this is a Windows 7 x64 machine. Thanks. Update: I tried doing a full uninstall and full re-install and still didn't get the editor. I do have the Stand Alone Shell (Isolated) installed for Atmel Studio 6, but it shouldn't be a problem.

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  • how to write or create (when no exist) a file using python and Google AppEngine

    - by zjm1126
    this is my code: f = open('text/a.log', 'wb') f.write('hahaha') f.close() and it is not create a new file when not exist how to do this , thanks updated class MyThread(threading.Thread): def run(self): f = open('a.log', 'w') f.write('hahaha') f.close() error is : Traceback (most recent call last): File "D:\Python25\lib\threading.py", line 486, in __bootstrap_inner self.run() File "D:\zjm_code\helloworld\views.py", line 15, in run f = open('a.log', 'w') File "d:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 1188, in __init__ raise IOError('invalid mode: %s' % mode) IOError: invalid mode: w

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  • Association end is not mapped in ADO entity framework

    - by Sean
    I am just starting out with ADO.net Entity Framework I have mapped two tables together and receive the following error: Error 1 Error 11010: Association End 'OperatorAccess' is not mapped. E:\Visual Studio\projects\Brandi II\Brandi II\Hospitals.edmx 390 11 Brandi II Not sure what it is I am doing wrong

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  • Python: Regex outputs 12_34 - I need 1234

    - by Guy F-W
    So I have input coming in like: 12_34 5_6_8_2 4___3 1234 and the output I need from it is: 1234, 5682, 43, 1234 I'm currently working with r'[0-9]+[0-9_]*'.replace('_','') which (as far as I can tell) successfully rejects any input which is not a combination of numeric digits and under-scores, where the underscore cannot be the first character. However, replacing the _ with the empty string causes 12_34 to come out as 12 and 34. Is there a better method than 'replace' for this? Or could I adapt my regex to deal with this problem?

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  • Assistance with regular expressions in Python

    - by da5id
    I am still learning REGEX, and I've run into an issue ... I am trying to separate a string that is composed of a mixture of letters and numbers that are in decimal format: AB0.500CD1.05EF2.29 Into something like this: list1 = AB,CD,EF list2 = 0.500,1.05,2.29 A complication to all this is that I also have strings that look like this: AB1CD2EF3 Which I'd also like to separate into this: list1 = AB,CD,EF list2 = 1,2,3 A previous inquiry yielded the following snippet, import re pattern = re.compile(r'([a-zA-Z]+)([0-9]+)') for (letters, numbers) in re.findall(pattern,cmpnd): print numbers print letters This example works fine for strings of the 2nd kind, but only "finds" the leading digit in the numbers that contain decimal places in the strings of the first kind. I've attempted an approach using the following line: pattern = re.compile(r'([a-zA-Z]+)([0-9]+(\.[0-9]))') But this results in an error: "ValueError: too many values to unpack" Thanks for any and all assistance!

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  • escaping query string with special characters with python

    - by that_guy
    I got some pretty messy urls that i got via scraping here, problem is that they contain spaces or other special characters in the path and query string, here is some example http://www.example.com/some path/to the/file.html http://www.example.com/some path/?file=path to/file name.png&name=name.me so, is there an easy and robust way to escape the urls so that i can pass them to urlopen? i tried urlib.quote, but it seems to escape the '?', '&', and '=' in the query string as well, and it seems to escape the protocol as well, currently, what i am trying to do is use regex to separate the protocol, path name, and query string and escape them separately, but there are cases where they arent separated properly any advice is appreciated

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  • python matrices - list index out of range

    - by user1888493
    I am writing a function, that takes a matrix as input, such as the one below. Then the it returns the matrix' inverse, where all the 1s are changed to 0s and all the 0s changed to 1s, while keeping the diagonal from top left to bottom right 0s. An example input: g1 = [[0, 1, 1, 0], [1, 0, 0, 1], [1, 0, 0, 1], [0, 1, 1, 0]] the function should output this: g1 = [[0, 0, 0, 1], [0, 0, 1, 0], [0, 1, 0, 0], [1, 0, 0, 0]] When I run the program, it raises a list index out of range error. I'm sure this happens, because the loops I have set up are trying to access values that do not exist. But how do I allow an input of unknown row and column size? I only know how to do this with a single list, but a list of lists? Following you see the transforming function, but not the test function that calls it: def inverse_graph(graph): # take in graph # change all zeros to ones and ones to zeros r, c = 0, 0 # row, column equal zero while (graph[r][c] == 0 or graph[r][c] == 1): # while the current row has a value. while (graph[r][c] == 0 or graph[r][c] == 1): # while the current column has a value if (graph[r][c] == 0): graph[r][c] = 1 elif (graph[r][c] == 1): graph[r][c] = 0 c+=1 c=0 r+=1 c=0 r=0 # sets diagonal to zeros while (g1[r][c] == 0 or g1[r][c] == 1): g1[r][c]=0 c+=1 r+=1 return graph

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  • customizing Django look and feel in Python

    - by user248237
    I am learning Django and got it to work with wsgi. I'm following the tutorial here: http://docs.djangoproject.com/en/1.1/intro/tutorial01/ My question is: how can I customize the look and feel of Django? Is there a repository of templates that "look good", kind of like there are for Wordpress, that I can start from? I find the tutorial counterintuitive in that it goes immediately toward customizing the admin page of Django, rather than the main pages visible to users of the site. Is there an example of a "typical" Django site, with a decent template, that I can look at and built on/modify? The polls application is again not very representative since it's so specialized. any references on this would be greatly appreciated. thanks.

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  • Python List length as a string

    - by mvid
    Is there a preferred (not ugly) way of outputting a list length as a string? Currently I am nesting function calls like so: print "Length: %s" % str(len(self.listOfThings)) This seems like a hack solution, is there a more graceful way of achieving the same result?

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  • how to init binary buffer in python

    - by ace
    so, I read from DB binary field i.e. 'field1' to var Buf1, and then do something like: unpack_from('I', Buf1, 0) so, all is ok. but question is how can I ini Buf1 without going to DB? I can get value from DB manually and init my var statically, but how? in DB field 'field1' I see something like '0x7B0500000100000064000000B80100006'. and how can I init valid binary buffer from it?

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  • python-McNuggets

    - by challarao
    I have created some program for this.But printed a,b,c values are not correct.Please check this weather it is correct or not? n=input("Enter the no.of McNuggets:") a,b,c=0,0,0 count=0 for a in range(n): if 6*a+9*b+20*c==n: count=count+1 break else: for b in range(n): if 6*a+9*b+20*c==n: count=count+1 break else: for c in range(n): if 6*a+9*b+20*c==n: count=count+1 break if count>0: print "It is possible to buy exactly",n,"packs of McNuggetss",a,b,c else: print "It is not possible to buy"

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  • regular expression not behaving as expected - Python

    - by philippe
    I have the following function which is supposed to read a .html file and search for <input> tags, and inject a <input type='hidden' > tag into the string to be shown into the page. However, that condition is never met:( e.g the if statement is never executed. ) What's wrong with my regex? def print_choose( params, name ): filename = path + name f = open( filename, 'r' ) records = f.readlines() print "Content-Type: text/html" print page = "" flag = True for record in records: if re.match( '<input*', str(record) ) != None: print record page += record page += "<input type='hidden' name='pagename' value='psychology' />" else: page += record print page Thank you

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