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  • Pagination links broken - php/jquery

    - by ClarkSKent
    Hey, I'm still trying to get my pagination links to load properly dynamically. But I can't seem to find a solution to this one problem. vote down star Hi everyone, I am still trying to figure out how to fix my pagination script to work properly. the problem I am having is when I click any of the pagination number links to go the next page, the new content does not load. literally nothing happens and when looking at the console in Firebug, nothing is sent or loaded. I have on the main page 3 links to filter the content and display it. When any of these links are clicked the results are loaded and displayed along with the associated pagination numbers for that specific content. I believe the problem is coming from the sql query in generate_pagination.php (seen below). When I hard code the sql category part it works, but is not dynamic at all. This is why I'm calling $ids=$_GET['ids']; and trying to put that into the category section but then the numbers don't display at all. If I echo out the $ids variable and click on a filter it does display the correct name/id, so I don't know why this doesn't work Here is the main page so you can see how I am including and starting the function(I'm new to php): <?php include_once('generate_pagination.php'); ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_pagination.js"></script> <div id="loading" ></div> <div id="content" data-page="1"></div> <ul id="pagination"> <?php //Pagination Numbers for($i=1; $i<=$pages; $i++) { echo '<li class="page_numbers" id="page'.$i.'">'.$i.'</li>'; } ?> </ul> <br /> <br /> <a href="#" class="category" id="marketing">Marketing</a> <a href="#" class="category" id="automotive">Automotive</a> <a href="#" class="category" id="sports">Sports</a> Here is the generate pagination where the problem seems to occur: <?php $ids=$_GET['ids']; include_once('config.php'); $per_page = 3; //Calculating no of pages $sql = "SELECT COUNT(*) FROM explore WHERE category='$ids'"; $result = mysql_query($sql); $count = mysql_fetch_row($result); $pages = ceil($count[0]/$per_page); ?> I thought I might as well post the jquery script if someone wants to see: $(document).ready(function(){ //Display Loading Image function Display_Load() { $("#loading").fadeIn(900,0); $("#loading").html("<img src='bigLoader.gif' />"); } //Hide Loading Image function Hide_Load() { $("#loading").fadeOut('slow'); }; //Default Starting Page Results $("#pagination li:first").css({'color' : '#FF0084'}).css({'border' : 'none'}); Display_Load(); $("#content").load("pagination_data.php?page=1", Hide_Load()); // Editing below. // Sort content Marketing $("a.category").click(function() { Display_Load(); var this_id = $(this).attr('id'); $.get("pagination.php", { category: this.id }, function(data){ //Load your results into the page var pageNum = $('#content').attr('data-page'); $("#pagination").load('generate_pagination.php?category=' + pageNum +'&ids='+ this_id ); $("#content").load("filter_marketing.php?page=" + pageNum +'&id='+ this_id, Hide_Load()); }); }); //Pagination Click $("#pagination li").click(function(){ Display_Load(); //CSS Styles $("#pagination li") .css({'border' : 'solid #dddddd 1px'}) .css({'color' : '#0063DC'}); $(this) .css({'color' : '#FF0084'}) .css({'border' : 'none'}); //Loading Data var pageNum = $(this).attr("id").replace("page",""); $("#content").load("pagination_data.php?page=" + pageNum, function(){ $(this).attr('data-page', pageNum); Hide_Load(); }); }); }); If any could assist me on solving this problem that would be great, thanks.

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  • Explore a COM Object in PHP

    - by shaiss
    What would be the proper way to explode a COM object for debugging? I have a 3rd party function that returns a multilevel object. The documentation is non existant, so I'd like to be able to echo everything out of the object or debug it in Komodo IDE. Komodo just says Object and nothing else. Maybe convert to array? I know some of the existing options such as $com->Status, but there are more variables returned that I'd like to know what they are.

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  • jquery repeat process once get reply from php file

    - by air
    i have one php file which process adding of record in Database fro array. for example in array i have 5 items aray an='abc','xyz','ert','wer','oiu' i want to call one php file in j query ajax method um = an.split(','); var counter = 0; if(counter < uemail.length) { $("#sending_count").html("Processing Record "+ ecounter +" of " + an.length); var data = {uid: um[counter] $.ajax({ type: "POST", url: "save.php", data: data, success: function(html){ echo "added"; counter++; } what it do, it complete all the prcess but save.php is still working what i want after one process it stop untill process of save.php complete then it wait for next 10 sec and start adding of 2nd element. Thanks

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  • PHP CLI application debug in ZendStudio (STDIN)

    - by Yuriy
    0 I am trying to debug php CLI using Zend Studio. My problem: I can't get user input from keyboard. This is part of code (method in some class): public function getInput($promt = null, $defaultValue = null) { if(!isset($promt)){ $promt = self::$DEFAULT_PROMPT; } echo $promt; $stdin = fopen ( "php://stdin", "r" ); $val = fgets ( $stdin ); return $val; } So ZS walks through code quite ok, but it stops at $val=fgets() And I have no clue where am I supposed to enter something from keyboard. I tried in console, and everywhere, I chacked debug configuration (Allocate console = on) etc. HELP!

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  • jQuery - ajax page load - php scope

    - by Develman
    I am using jquery.tabs() and want to load the pages of the tabs with ajax. I am using MVC pattern with PHP and used a frontcontroller / pagecontroller pattern. The templating is done by PHP, e.g.: <?php if($this->userLoggedIn == TRUE): ?> <span>Herzlich Willkommen <?php echo $this->userName; ?>! [<a href="logout">Ausloggen</a>] </span> <?php endif; ?> The variables ($this-userName) are injected by the pagecontroller class. The problem is, that when I load a page via ajax, the variables are not known. Following PHP error is coming up: Fatal error: Using $this when not in object context.... Any idea, how to use / load the variables and using it in the template files.

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  • Simple PHP Regex question

    - by Dave Kiss
    Hi all, I'd like to validate a field in a form to make sure it contains the proper formatting for a URL linking to a Vimeo video. Below is what I have in Javascript, but I need to convert this over to PHP (not my forte) Basically, I need to check the field and if it is incorrectly formatted, I need to store an error message as a variable.. if it is correct, i store the variable empty. // Parse the URL var PreviewID = jQuery("#customfields-tf-1-tf").val().match(/http:\/\/(www.vimeo|vimeo)\.com(\/|\/clip:)(\d+)(.*?)/); if ( !PreviewID ) { jQuery("#cleaner").html('<div id="vvqvideopreview"><?php echo $this->js_escape( __("Unable to parse preview URL. Please make sure it's the <strong>full</strong> URL and a valid one at that.", 'vipers-video-quicktags') ); ?></div>'); return; } The traditional vimeo url looks like this: http://www.vimeo.com/10793773 Thanks!

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  • PHP Simple modification/correction

    - by Adrian M.
    Hello, I got this code from someone, it's almost perfect to create a dynamic breadcrumb, but there just a little glitch because it echoes two dividers before the breadcrumb: $crumbs = explode("/",$_SERVER["REQUEST_URI"]); foreach($crumbs as $crumb){ echo ucfirst(str_replace(array(".php","_"),array(""," "),'>' . $crumb)); } it echoes: "contentcommonfile" what I want it to look like is "contentcommon1" and also I will deeply appreciate if someone can tell me how can I add links for all the items in the array except the last one (file)? Thank you so much everybody, this website really helped me a lot to learn php by examples!

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  • Where is my classpath being set?

    - by Nimnio
    Whenever I open a Bash shell, my classpath is "someProgram". I know that adding an export entry to ".bashrc" changes my classpath, but I want to know where "someProgram" is being added to the classpath (it's not in ".bashrc"). Is there a way to track down where this is being set, or some typical spots I should be checking besides ".bashrc"? Details: I'm using Ubuntu 9.10. Eclipse Version: 3.5.1 is installed. echo $SHELL /bin/bash java -version java version "1.6.0_0" OpenJDK Runtime Environment (IcedTea6 1.6.1) (6b16-1.6.1-3ubuntu1) OpenJDK Server VM (build 14.0-b16, mixed mode) javac -version javac 1.6.0_15 More details if requested.

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  • php - sort the unsorted text file and rewrite to same text file in sorted order

    - by arrgggg
    Hi, I have a question. I am in process of learning how to read/write files, but having little trouble trying to do both at the same time in same php script. I have a text file with words like this, Richmond,Virginia Seattle,Washington Los Angeles,California Dallas,Texas Jacksonville,Florida I wrote a code to sort them in order and this will display in sort order by City. <?php $file = file("states.txt"); sort($file); for($i=0; $i<count($file); $i++) { $states = explode(",", $file[$i]); echo $states[0], $states[1],"<br />"; } ?> From this, how can I rewrite those sorted information back into the states.txt file? Thanks for your help.

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  • Using FTP from PHP CURL

    - by Christian Sciberras
    I can't figure out how to use CURL's FTP, specifically, how to issue FTP commands from my PHP code: <?php $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, 'ftp://ftp.microsoft.com/'); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch,CURLOPT_POSTQUOTE,array('CWD bussys/','LIST')); /* ?!! */ echo '<hr><pre>'.htmlspecialchars(curl_exec($ch)).'</pre><hr>'; ?> In my example above I want to get a directory listing of bussys, but instead I get a listing of the main (FTP root) directory.

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  • retrieving background image from div when dynamically set

    - by tixrus
    I am having an issue with setting the background-image of a #x to the background image of #y. Correct me if I am wrong but I think you would do this in a simple case by saying $('#x').css('background-image',$('#y').css('background-image')); The problem is that when y was initially set up, it was set up like this: <div id='y' style='background-image: url(./randomcolor.php?ibase=<?php echo $entity->name; ?>) .... So when it does it, it is getting the URL of the generator, and javascript is just regarding that as a string. Do I have to do an ajax get here, or is there some kind of eval I could use.

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  • Creating an URL without global variables

    - by dygi
    I have a code like this below, which gives me a $link that equals to: http://mydomain.com/image/photo.JPG if (!empty($_SESSION['item'][$i])) { $path = dirname(__FILE__).'/image/'.basename($_SESSION['item'][$i]); if (move_uploaded_file($_SESSION['item'][$i], $path)) global $url; if ( $url ) { $link = $url.'/image/'.basename($_SESSION['item'][$i]); echo "<td><img src='" . $link . "' width='50' height='50' /></td>"; } } I wonder, how should I properly ommit using global variable here to achieve the same result.

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  • PHP is unable to open a file for writing - but it does exist

    - by asdasdas
    I am trying to write to a file. I do a file_exists check on it before i do fopen and it comes up true: the file does exist. However, the file fails this code and gives me the error every time: $handle = fopen($filename, 'w'); if($handle) { flock($handle, LOCK_EX); fwrite($handle, $contents); } else { echo 'ERROR: Unable to open the file for writing.',PHP_EOL; exit(); } flock($handle, LOCK_UN); fclose($handle); Is there a way I can get more specific error details as to why this file does not let me open it for writing? I know that the filename is legit, but for some reason it just wont let me write to it. I do have write permissions, I was able to write and write over another file.

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  • perl: Run remote perl script through SSH and query environment variables on remote machine

    - by kakyo
    I'm running a perl script through SSH, in the perl script I query environment variables using $ENV{MY_VAR_NAME} and it works fine when run locally. But through SSH, all environment variables become unset. I also tried to run system("source ~/.bash_profile"); at the beginning of my script to no avail. Any tips? EDIT: Rephrasing my question. I have machine A and B. I ran my perl on machine B, trying to get the environment variables on B and it worked. Then I ssh from A to B running the same script, i.e., using this code ssh user@B perl myscript.pl This time the environment variables on B are all blank. Any tips? UPDATE: I found that running the above script, ~/.bashrc on Machine B was invoked, but after setting environment variables in ~/.bashrc, run the above command again and still I don't see any environment variables. Also, if my perl script contains only echo $ENV{PATH} Then I get /usr/bin:/bin:/usr/sbin:/sbin

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  • Not Recieving JSON object into my Zend Controller

    - by davykiash
    Am am sucessfully parsing and sending json values from my client for my server side controller to recieve and parse $("#test2").click(function() { $.ajax({ type: "POST", url: "<?php echo $this->baseUrl() ?>/expensetypes/add", data: JSON.stringify(wrapFormValues($('#expensetypes'))), contentType: "application/json; charset=utf-8", dataType: "json", success: function(msg){ alert( "Data Saved: " + msg ); } }); }); However in my controller the code $this->getRequest()->getPost() doesnt seem to recieve the json object that my client is sending though firebug clearly shows that my json object is being parsed and sent. What am I missing?

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  • Error code 100 while writing a code for Facebook API

    - by abhishekgupta92
    Error API Error Code: 100 API Error Description: Invalid parameter Error Message: next is not owned by the application. Above it the error that I receives when I write the following code in my index.php file. < ?php $appapikey = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx'; $appsecret = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx'; require_once 'facebook.php'; $facebook = new Facebook ($appapikey, $appsecret); $user = $facebook-require_login(); echo $user; ?

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  • XAMPP is caching .html files running as PHP

    - by Lee
    I have XAMPP (latest version) installed on my Mac OS 10.6.3 I've added the following to .htaccess because I want .html to be interpreted as PHP. AddType application/x-httpd-php .php .html The problem is that the default XAMPP config seems to be caching .html files as static... so even though the PHP statements inside are being called (for example, 'echo time()' in index.html displays the dynamic output)... the actual file is being cached. When I make changes to a .html file, I've having to restart Apache for it to load the newest changes. Looking at httpd.conf, it looks like it's loading the following cache mods.. LoadModule file_cache_module modules/mod_file_cache.so LoadModule cache_module modules/mod_cache.so LoadModule disk_cache_module modules/mod_disk_cache.so LoadModule mem_cache_module modules/mod_mem_cache.so Any idea how to implement a system whereby it checks the timestamp of the file, before loading it from cache? Thanks!

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  • executing two functions with wshshell

    - by sushant
    i have two different functions (copy and zip) to b executed. can i do it with with a single wshshell script.i tried---- Dim WshShell, oExec,g,h h="D:\d" g="xcopy " & h & " " & "D:\y\ /E & cmd /c cd D:\c & D: & winzip32.exe -min -a D:\a" Set WshShell = CreateObject("WScript.Shell") Set oExec = WshShell.Exec(g) Do While oExec.Status = 0 WScript.Sleep 100 Loop WScript.Echo oExec.Status it dint work.though separate programs i.e g="xcopy " & h & " " & "D:\y\ /E" and g="cmd /c cd D:\d & D: & winzip32.exe -min -a D:\a" works. i am sorry for the formatting problem. any help is appreciated.

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  • Why is the same input returning two different MD5 hashes?

    - by Rob
    Alright, I have two files. They are the EXACT SAME. The first file is: http://iadsonline.com/servconfig.php And the second file is: http://xzerox.info/servconfig.php However, when I use md5_file() to get their MD5, They return two different MD5's. The first returns cc7819055cde3194bb3b136bad5cf58d, which is incorrect, and the second returns 96a0cec80eb773687ca28840ecc67ca1, which is correct. The file is simply an &nbsp; To verify, I've used this code: $contents = file_get_contents($URL); echo htmlentities($contents); And they both return &nbsp; So why is it hashing them differently?

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  • How to create a simple server/client application using boost.asio?

    - by the_drow
    I was going over the examples of boost.asio and I am wondering why there isn't an example of a simple server/client example that prints a string on the server and then returns a response to the client. I tried to modify the echo server but I can't really figure out what I'm doing at all. Can anyone find me a template of a client and a template of a server? I would like to eventually create a server/client application that receives binary data and just returns an acknowledgment back to the client that the data is received.

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  • How to format a dos path to a unix path on cygwin command line

    - by Jennette
    When using Cygwin, I frequently copy a Windows path and manually edit all of the slashes to Unix format. For example, if I am using Cygwin and need to change directory I enter: cd C:\windows\path then edit this to cd C:/windows/path (Typically, the path is much longer than that). Is there a way to use sed, or something else to do this automatically? For example, I tried: echo C:\windows\path|sed 's|\|g' but got the following error sed: -e expression #1, char 7: unterminated `s' command My goal is to reduce the typing, so maybe I could write a program which I could call. Ideally I would type: conversionScript cd C:/windows/path and this would be equivalent to typing: cd C:\windows\path

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  • Disabling Xdebug's dumping of caught exceptions

    - by nuqqsa
    By default Xdebug will dump any exception regardless of whether it is caught or not: try { throw new Exception(); } catch (Exception $e) { } echo 'life goes on'; With XDebug enabled and the default settings this piece of code will actually output something like the following (nicely formatted): ( ! ) Exception: in /test.php on line 3 Call Stack # Time Memory Function Location 1 0.0003 52596 {main}( ) ../test.php:0 life goes on Is it possible to disable this behaviour and have it dumping only the uncaught exceptions? Thanks in advance. UPDATE: I'm about to conclude that this is a bug, since xdebug.show_exception_trace is disabled by default yet it doesn't behave as expected (using Xdebug v2.0.5 with PHP 5.2.10 on Ubuntu 9.10).

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  • PHP array taking up too much memory

    - by Dylan Taylor
    I have a multidimensional array. The array itself is fine. My problem is that the script takes up monster amounts of memory, and since I'm running this on my MAMP install on my iBook G4, my computer freezes up. Below is the full script. $query = "SELECT * FROM posts ORDER BY id DESC LIMIT 10"; $result = mysql_query($query); $posts = array(); while($row = mysql_fetch_array($result)){ $posts[$row["id"]]['post_id'] = $row["id"]; $posts[$row["id"]]['post_title'] = $row["title"]; $posts[$row["id"]]['post_text'] = $row["text"]; $posts[$row["id"]]['post_tags'] = $row["tags"]; $posts[$row["id"]]['post_category'] = $row["category"]; foreach ($posts as $post) { echo $post["post_id"]; } Is there a workaround that still achieves my goal (to export the MySQL query rows to an array)? -Dylan

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  • How to make strtotime parse dates in Australian (i.e. UK) format: dd/mm/yyyy?

    - by Iain Fraser
    I can't beleive I've never come across this one before. Basically, I'm parsing the text in human-created text documents and one of the fields I need to parse is a date and time. Because I'm in Australia, dates are formatted like dd/mm/yyyy but strtotime only wants to parse it as a US formatted date. Also, exploding by / isn't going to work because, as I mentioned, these documents are hand-typed and some of them take the form of d M yy. I've tried multiple combinations of setlocale but no matter what I try, the language is always set to US English. I'm fairly sure setlocale is the key here, but I don't seem to be able to strike upon the right code. Tried these: au au-en en_AU australia aus Anything else I can try? Thanks so much :) Iain Example: $mydatetime = strtotime("9/02/10 2.00PM"); echo date('j F Y H:i', $mydatetime); Produces 2 September 2010 14:00 I want it to produce: 9 February 2010 14:00

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  • MySql: Select all entries with count...

    - by Scarface
    Hey guys quick question, I have a query that I want to count all entries it finds, and select all so when I use while($row=mysql_fetch_assoc($query)){ it will list all entries. The problem I am encountering is that while, all the entries are successfully counted and the right number is listed, only the latest entry is select and listed when I echo $row['title']. If I delete , COUNT(*) as total then it selects all but I was wondering if it was possible to use count and select *. I was wondering if anyone knew what I am doing wrong? SELECT *, COUNT(*) as total FROM new_messages WHERE username='$session->username

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