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  • How to fix this Timer Tick Error in C#?

    - by Iman Hejazi
    I use this code to receive data from a internet address by a Timer in defined period of times. But when the timer ticks in second time an error will raised from this line: HttpWebResponse response = (HttpWebResponse)request.GetResponse(); I want to know how to fix this problem. Timer Interval: 30secs private void timer1_Tick(object sender, EventArgs e) { WebRequest request = WebRequest.Create("http://localhost/go/online.asp?prog=y&rln=" + Properties.Settings.Default.cos); request.Credentials = CredentialCache.DefaultCredentials; HttpWebResponse response = (HttpWebResponse)request.GetResponse(); Stream dataStream = response.GetResponseStream(); StreamReader reader = new StreamReader(dataStream); string responseFromServer = reader.ReadToEnd(); reader.Close(); dataStream.Close(); response.Close(); }

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  • Is there a way to implement Caliburn-like co-routines in VB.NET since there's no yield keyword

    - by Miroslav Popovic
    Note that I'm aware of other yield in vb.net questions here on SO. I'm playing around with Caliburn lately. Bunch of great stuff there, including co-routines implementation. Most of the work I'm doing is C# based, but now I'm also creating an architecture guideline for a VB.NET only shop, based on Rob's small MVVM framework. Everything looks very well except using co-routines from VB. Since VB 10 is used, we can try something like Bill McCarthy's suggestion: Public Function Lines(ByVal rdr as TextReader) As IEnumerable(Of String) Return New GenericIterator(Of String) (Function(ByRef nextItem As String) As Boolean nextItem = rdr.ReadLine Return nextItem IsNot Nothing End Function) End Function I'm just failing to comprehend how a little more complex co-routine method like the one below (taken from Rob's GameLibrary) could be written in VB: public IEnumerable<IResult> ExecuteSearch() { var search = new SearchGames { SearchText = SearchText }.AsResult(); yield return Show.Busy(); yield return search; var resultCount = search.Response.Count(); if (resultCount == 0) SearchResults = _noResults.WithTitle(SearchText); else if (resultCount == 1 && search.Response.First().Title == SearchText) { var getGame = new GetGame { Id = search.Response.First().Id }.AsResult(); yield return getGame; yield return Show.Screen<ExploreGameViewModel>() .Configured(x => x.WithGame(getGame.Response)); } else SearchResults = _results.With(search.Response); yield return Show.NotBusy(); } Any idea how to achieve that, or any thoughts on using Caliburn co-routines in VB?

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  • Path issue in wordpress blog

    - by vsingh
    We are having some issue with our relative path in wordpress. Earlier our application was like http://www.skill-guru.com/skill . So if we type the blog address as http://www.skill-guru.com/blog it would add a / at end and open it as http://www.skill-guru.com/blog/ Now our application opens as root in domain http://www.skill-guru.com. Our blog is opening as http://www.skill-guru.com/blog/ but not as http://www.skill-guru.com/blog. I am not able to understand the reason. because of this issue , search is also not working. Can anyone please help me understand what has changed and how it can be fixed ?

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  • How does this If conditional work in Python?

    - by Sergio Boombastic
    from google.appengine.api import users from google.appengine.ext import webapp from google.appengine.ext.webapp.util import run_wsgi_app class MainPage(webapp.RequestHandler): def get(self): user = users.get_current_user() if user: self.response.headers['Content-Type'] = 'text/plain' self.response.out.write('Hello, ' + user.nickname()) else: self.redirect(users.create_login_url(self.request.uri)) application = webapp.WSGIApplication( [('/', MainPage)], debug=True) def main(): run_wsgi_app(application) if __name__ == "__main__": main() I don't understand how this line works: if user: self.response.headers['Content-Type'] = 'text/plain' self.response.out.write('Hello, ' + user.nickname()) else: self.redirect(users.create_login_url(self.request.uri)) I'm guessing the users.get_current_user() return a boolean? Then, if that is the case how can it get a .nickname() method? Thanks for the guidance.

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  • Facebook JS SDK FB.logout() doesn't terminate user session

    - by Casey Flynn
    I'm attempting to log a user out of facebook with the Facebook JS SDK, however calling: FB.logout(function(response){ console.log(response); }); returns: response.status == "connected" And only after refreshing the page does the SDK realize that the session has ended. Anyone know what could be causing this behavior? This code previously worked in my application and has recently started behaving this way. Another example using FireBug:

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  • Can I get the original page source (vs current DOM) with phantomjs/casperjs?

    - by supercoco
    I am trying to get the original source for a particular web page. The page executes some scripts that modify the DOM as soon as it loads. I would like to get the source before any script or user changes any object in the document. With Chrome or Firefox (and probably most browsers) I can either look at the DOM (debug utility F12) or look at the original source (right-click, view source). The latter is what I want to accomplish. Is it possible to do this with phantomjs/casperjs? Before getting to the page I have to log in. This is working fine with casperjs. If I browse to the page and render the results I know I am on the right page. casper.thenOpen('http://'+customUrl, function(response) { this.page.render('example.png'); // *** Renders correct page (current DOM) *** console.log(this.page.content); // *** Gets current DOM *** casper.download('view-source:'+customUrl, 'b.html', 'GET'); // *** Blank page *** console.log(this.getHTML()); // *** Gets current DOM *** this.debugPage(); // *** Gets current DOM *** utils.dump(response); // *** No BODY *** casper.download('http://'+customUrl, 'a.html', 'GET'); // *** Not logged in ?! *** }); I've tried this.download(url, 'a.html') but it doesn't seem to share the same context since it returns HTML as if I was not logged in, even if I run with cookies casperjs test.casper.js --cookies-file=cookies.txt. I believe I should keep analyzing this option. I have also tried casper.open('view-source:url') instead of casper.open('http://url') but it seems it doesn't recognize the url since I just get a blank page. I have looked at the raw HTTP Response I get from the server with a utility I have and the body of this message (which is HTML) is what I need but when the page loads in the browser the DOM has already been modified. I tried: casper.thenOpen('http://'+url, function(response) { ... } But the response object only contains the headers and some other information but not the body. ¿Any ideas? Here is the full code: phantom.casperTest = true; phantom.cookiesEnabled = true; var utils = require('utils'); var casper = require('casper').create({ clientScripts: [], pageSettings: { loadImages: false, loadPlugins: false, javascriptEnabled: true, webSecurityEnabled: false }, logLevel: "error", verbose: true }); casper.userAgent('Mozilla/5.0 (Macintosh; Intel Mac OS X)'); casper.start('http://www.xxxxxxx.xxx/login'); casper.waitForSelector('input#login', function() { this.evaluate(function(customLogin, customPassword) { document.getElementById("login").value = customLogin; document.getElementById("password").value = customPassword; document.getElementById("button").click(); }, { "customLogin": customLogin, "customPassword": customPassword }); }, function() { console.log('Can't login.'); }, 15000 ); casper.waitForSelector('div#home', function() { console.log('Login successfull.'); }, function() { console.log('Login failed.'); }, 15000 ); casper.thenOpen('http://'+customUrl, function(response) { this.page.render('example.png'); // *** Renders correct page (current DOM) *** console.log(this.page.content); // *** Gets current DOM *** casper.download('view-source:'+customUrl, 'b.html', 'GET'); // *** Blank page *** console.log(this.getHTML()); // *** Gets current DOM *** this.debugPage(); // *** Gets current DOM *** utils.dump(response); // *** No BODY *** casper.download('http://'+customUrl, 'a.html', 'GET'); // *** Not logged in ?! *** });

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  • IIS7 unchecked in windows component list yet when go to http://localhost still directs me to IIS7. How to get to Apache?

    - by Ed Hancock
    IIS7 was turned off on my Windows 7 system, Under control panel services and applications no web publishing appears. Have Apache, et. al. installed with Wampserver. Yet when I try to access the local server astill get directed to IIS7 welcome page. After turning off IIS7 restarted computer, no help, eliminated history, no help, deleted IIS7 folders, no help. It is hiding somewhere and I can not find it. Any suggestions/help would be appreciated. Ed

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  • JavaScript To Strip Page For URL

    - by Russell C.
    We have a javascript function we use to track page stats internally. However, the URLs it reports many times include the page numbers for search results pages which we would rather not be reported. The pages that are reports are of the form: http://www.test.com/directory1/2 http://www.test.com/directory1/subdirectory1/15 http://www.test.com/directory3/1113 Instead we'd like the above reported as: http://www.test.com/directory1 http://www.test.com/directory1/subdirectory1 http://www.test.com/directory3 Please note that the numbered 'directory' and 'subdirectory' names above are just for example purposes and that the actual subdirectory names are all different, don't necessarily include numbers at the end of the directory name, and can be many levels deep. Currently our JavaScript function produces these URLs using the code: var page = location.hostname+document.location.pathname; I believe we need to use the JavaScript replace function in combination with some regex but I'm at a complete loss as to what that would look like. Any help would be much appreciated! Thanks in advance!

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  • urllib2.Request() with data returns empty url

    - by Mr. Polywhirl
    My main concern is the function: getUrlAndHtml() If I manually build and append the query to the end of the uri, I can get the response.url(), but if I pass a dictionary as the request data, the url does not come back. Is there anyway to guarantee the redirected url? In my example below, if thisWorks = True I get back a url, but the returned url is the request url as opposed to a redirect link. On a sidenote, the encoding for .E2.80.93 does not translate to - for some reason? #!/usr/bin/python import pprint import urllib import urllib2 from bs4 import BeautifulSoup from sys import argv URL = 'http://en.wikipedia.org/w/index.php?' def yesOrNo(boolVal): return 'yes' if boolVal else 'no' def getTitleFromRaw(page): return page.strip().replace(' ', '_') def getUrlAndHtml(title, printable=False): thisWorks = False if thisWorks: query = 'title={:s}&printable={:s}'.format(title, yesOrNo(printable)) opener = urllib2.build_opener() opener.addheaders = [('User-agent', 'Mozilla/5.0')] response = opener.open(URL + query) else: params = {'title':title,'printable':yesOrNo(printable)} data = urllib.urlencode(params) headers = {'User-agent':'Mozilla/5.0'}; request = urllib2.Request(URL, data, headers) response = urllib2.urlopen(request) return response.geturl(), response.read() def getSoup(html, name=None, attrs=None): soup = BeautifulSoup(html) if name is None: return None return soup.find(name, attrs) def setTitle(soup, newTitle): title = soup.find('div', {'id':'toctitle'}) h2 = title.find('h2') h2.contents[0].replaceWith('{:s} for {:s}'.format(h2.getText(), newTitle)) def updateLinks(soup, url): fragment = '#' for a in soup.findAll('a', href=True): a['href'] = a['href'].replace(fragment, url + fragment) def writeToFile(soup, filename='out.html', indentLevel=2): with open(filename, 'wt') as out: pp = pprint.PrettyPrinter(indent=indentLevel, stream=out) pp.pprint(soup) print('Wrote {:s} successfully.'.format(filename)) if __name__ == '__main__': def exitPgrm(): print('usage: {:s} "<PAGE>" <FILE>'.format(argv[0])) exit(0) if len(argv) == 2: help = argv[1] if help == '-h' or help == '--help': exitPgrm() if False:''' if not len(argv) == 3: exitPgrm() ''' page = 'Led Zeppelin' # argv[1] filename = 'test.html' # argv[2] title = getTitleFromRaw(page) url, html = getUrlAndHtml(title) soup = getSoup(html, 'div', {'id':'toc'}) setTitle(soup, page) updateLinks(soup, url) writeToFile(soup, filename)

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  • Parsing raw apache logs

    - by MB34
    I need some php code for parsing raw apache logs. In particular, I want the number of times mode=search and the term used for searching. Here is an example: 207.46.195.228 - - [30/Apr/2010:03:24:26 -0700] "GET /index.php?mode=search&term=AE1008787E0174 HTTP/1.1" 200 13047 "-" "msnbot/2.0b (+http://search.msn.com/msnbot.htm)" 212.81.200.167 - - [30/Apr/2010:04:21:43 -0700] "GET /index.php?mode=search&term=WH2002D-YYH HTTP/1.1" 200 12079 "http://www.mysite.com/SearchGBY.php?page=81" "Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 5.1; GTB6.4; .NET CLR 1.1.4322; .NET CLR 2.0.50727; WinuE v6; InfoPath.2; WinuE v6)" 212.81.200.167 - - [30/Apr/2010:04:21:44 -0700] "GET /file_uploads/banners/banner.swf HTTP/1.1" 200 50487 "-" "contype" 66.249.68.168 - - [30/Apr/2010:04:21:45 -0700] "GET /index.php?mode=search&term=WH2002D-YYH HTTP/1.1" 200 12079 "-" "Mediapartners-Google"

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  • Print XML file and download it

    - by Pankaj
    I am create xml using serialization and trying to print them using this code string xmlDate = xml.GetXML(); string name = string.Format("{0}_HighEST", ProjectName); Response.AddHeader("Content-disposition", "attachment; filename=\"" + name + "_HighEST.xml\""); Response.ContentType = string.Format("application/.xml", name); how can assign my xmldata to Response so that data will write on downloaded xml?

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  • [grails] setting cookies when render type is "contentType: text/json"

    - by Robin Jamieson
    Is it possible to set cookies on response when the return render type is set as json? I can set cookies on the response object when returning with a standard render type and later on, I'm able to get it back on the subsequent request. However, if I were to set the cookies while rendering the return values as json, I can't seem to get back the cookie on the next request object. What's happening here? These two actions work as expected with 'basicForm' performing a regular form post to the action, 'withRegularSubmit', when the user clicks submit. // first action set the cookie and second action yields the originally set cookie def regularAction = { // using cookie plugin response.setCookie("username-regular", "regularCookieUser123",604800); return render(view: "basicForm"); } // called by form post def withRegularSubmit = { def myCookie = request.getCookie("username-regular"); // returns the value 'regularCookieUser123' return render(view: "resultView"); } When I switch to setting the cookie just before returning from the response with json, I don't get the cookie back with the post. The request starts by getting an html document that contains a form and when doc load event is fired, the following request is invoked via javascript with jQuery like this: var someUrl = "http://localhost/jsonAction"; $.get(someUrl, function(jsonData) { // do some work with javascript} The controller work: // this action is called initially and returns an html doc with a form. def loadJsonForm = { return render(view: "jsonForm"); } // called via javascript when the document load event is fired def jsonAction = { response.setCookie("username-json", "jsonCookieUser456",604800); // using cookie plugin return render(contentType:'text/json') { 'pair'('myKey': "someValue") }; } // called by form post def withJsonSubmit = { def myCookie = request.getCookie("username-json"); // got null value, expecting: jsonCookieUser456 return render(view: "resultView"); } The data is returned to the server as a result of the user pressing the 'submit' button and not through a script. Prior to the submit of both 'withRegularSubmit' and 'withJsonSubmit', I see the cookies stored in the browser (Firefox) so I know they reached the client.

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  • Third party multipart request in playframework

    - by Brian
    I'm making an application to post photos to yfrog and twitpic and I am having a little trouble figuring out how to set the parameters. Here is my code: public static Result index() { HttpClient httpclient = new DefaultHttpClient(); WSRequestHolder holder = WS.url("http://api.twitpic.com/2/upload.json"); holder.setHeader("Authorization", ""); return async(holder.post("").map(new Function<WS.Response, Result>() { public Result apply(WS.Response response) { return ok(response.getBody()); } })); } Now, I don't expect this to actually get an ok response from the server, as I am just testing the responses that I get back from the server, and that is one that says I need to provide the api key. I figured as much, but I'm not sure of the syntax for providing that parameter, as I need to also give the name of the file and the file. I tried setting holder.post("key=somekey"), with the hope that I would get a different error message (like the key you provided is invalid) but I just get the same error. I'm assuming that I probably need to send it in the for of a multipart request, but I am not very experienced with this kind of request and can't find any play documentation on how to create a multipart request, other than in an html form. Any suggestions and help will be much appreciated. And fyi, I do know that there are yfrog and twitpic java classes to handle this kind of stuff, but I want to do it myself, more so for learning how to do this kind of stuff. Thanks in advance!

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  • Help ---- SQL Script

    - by Vinoj Nambiar
    Store No Store Name Region Division Q10(response) Q21(response) 2345       ABC              North Test              1                       5 2345                            North Test              6                       3 2345       ABC              North Test              4                       6 1st calculation 1 ) Engaged(%) = Response Greater than 4.5 3 (total response greater than 4.5) / 6 (total count) * 100 = 50% Store No Store Name Region Division Q10 Q21 2345             ABC      North Test           1       5 2345             ABC      North Test           6       3 2345            ABC       North Test           4       6 2) not engaged (%) = Response less than 2 1 (total response less than 2) / 6 (total count) * 100 = 16.66% I should be able to get the table like this Store No Store Name Region Division Engaged(%) Disengaged(%) 2345            ABC     North Test                 50                 16.66

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  • getimagesize on alfresco image

    - by SupFrig
    i'm working on a front display for an alfresco filled with pictures. i'm building my pictures url like this : http://myHost.com:8080/share/proxy/alfresco-noauth/api/node/content/workspace/SpacesStore/bf0a8b21-b8d9-487d-a529-dee8c49d7c6f/filetitle.jpg?alf_ticket=myTicket where myHost is the server and myTicket is the ticket generated at this url : http://myHost.com:8080/alfresco/service/api/login?u=login&pw=password Picture is displaying correctly with this url, but i want to use phpthumb to resize it, and when i try to use it on my picture, i get an http 500 error on the script and the following log : PHP Warning: getimagesize(http://myHost.com:8080/share/proxy/alfresco-noauth/api/node/content/workspace/SpacesStore/bf0a8b21-b8d9-487d-a529-dee8c49d7c6f/filetitle.jpg?alf_ticket=myTicket): failed to open stream: HTTP request failed! HTTP/1.1 401 Non-Autorisé I shouldn't hit the authentification, since my link has a valid ticket (I don't hit authentification when i display normally my picture)

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  • Export GridView to Excel (not working)

    - by Chiramisu
    I've spent the last two days trying to get some bloody data to export to Excel. After much research I determined that the best and most common way is using HttpResponse headers as shown in my code below. After stepping through countless times in debug mode, I have confirmed that the data is in fact there and both filtered and sorted the way I want it. However, it does not download as an Excel file, or do anything at all for that matter. I suspect this may have something to do with my UpdatePanel or perhaps the ImageButton not posting back properly, but I'm not sure. What am I doing wrong? Please help me to debug this issue. I will be eternally grateful. Thank you. :) Markup <asp:UpdatePanel ID="statusUpdatePanel" runat="server" UpdateMode="Conditional"> <Triggers> <asp:AsyncPostBackTrigger ControlID="btnExportXLS" EventName="Click" /> </Triggers> <ContentTemplate> <asp:GridView ID="GridView1" runat="server" AllowPaging="True" PageSize="10" AllowSorting="True" DataSourceID="GridView1SDS" DataKeyNames="ID"> </asp:GridView> <span><asp:ImageButton ID="btnExportXLS" runat="server" /></span> </ContentTemplate> </asp:UpdatePanel> Codebehind Protected Sub ExportToExcel() Handles btnExportXLS.Click Dim dt As New DataTable() Dim da As New SqlDataAdapter(SelectCommand, ConnectionString) da.Fill(dt) Dim gv As New GridView() gv.DataSource = dt gv.DataBind() Dim frm As HtmlForm = New HtmlForm() frm.Controls.Add(gv) Dim sw As New IO.StringWriter() Dim hw As New System.Web.UI.HtmlTextWriter(sw) Response.ContentType = "application/vnd.ms-excel" Response.AddHeader("content-disposition", "attachment;filename=Report.xls") Response.Charset = String.Empty gv.RenderControl(hw) Response.Write(sw.ToString()) Response.End() End Sub

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  • Monotouch/C# version of "stringWithContentsOfUrl"

    - by Pselus
    I'm trying to convert a piece of Objective-C code into C# for use with Monotouch and I have no idea what to use to replace stringWithContentsOfUrl Should I use something like: HttpWebRequest request = (HttpWebRequest) WebRequest.Create("http://www.helephant.com"); HttpWebResponse response = (HttpWebResponse) request.GetResponse(); if (response.StatusCode == HttpStatusCode.OK && response.ContentLength > 0){ TextReader reader = new StreamReader(response.GetResponseStream()); string text = reader.ReadToEnd(); Console.Write(text); } Is that even safe to use in MonoTouch? Will it work for the iPhone?

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  • BlackBerry emulator not connecting to internet

    - by wb
    My BB emulator cannot connect to the internet. I'm behind a proxy and have entered the following in my rimpublic.property under the [HTTP HANDLER] heading. application.handler.http.proxyEnabled = true application.handler.http.proxyHost=PROXY_NAME application.handler.http.proxyPort=PROXY_PORT application.handler.http.proxyUser=PROXY_USER application.handler.http.proxyPass=PROXY_PASSWORD I have BB JDE 5.0.0 installed. I am able to successfully start the MDS service and do get the screen to stay open but do not see any errors. I've read every question on SO regarding similar issues but nothing works. Also, I am starting the MDS service before booting my emulator. If it helps, I'm using the emulator 5.0.0.545 (9700). Thank you.

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  • Problem with \' in URLencoding

    - by Bruce
    I am working on Java. Here is my code response = URLEncoder.encode(response, "UTF-8").replaceAll("\\+", "%20"); Problem comes when there is a ' (single quote) in the string response. It gets encoded to \'. eg - 'Collective Dynamics of Complex Networks' comes as \'Collective Dynamics of Complex Networks\' I want it to remain as it is. What should I do?

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  • Call Javascript method from .ashx file

    - by Prasad Jadhav
    From my previous question(Create json using JavaScriptSerializer), In .ashx file I am printing the json object using: context.Response.ContentType = "application/json"; context.Response.Write(json); I am calling this .ashx file from default.aspx which has some javascript function inside its <head> tag. My question is : How will I be able to call the javascript function from .ashx file after context.Response.Write(json);?

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  • Read media stream from servlet in a webpage?

    - by khue
    Hi, I have a servlet that construct response to a media file request by reading the file from server: File uploadFile = new File("C:\TEMP\movie.mov"); FileInputStream in = new FileInputStream(uploadFile); Then write that stream to the response stream. My question is how do I play the media file in the webpage using or tag to read the media stream from the response. Thank you very much. Regards K.

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  • Saving animated GIFs using urllib.urlopen (image saved does not animate)

    - by wenbert
    I have Apache2 + Django + X-sendfile. My problem is that when I upload an animated GIF, it won't "animate" when I output through the browser. Here is my code to display the image located outside the public accessible directory. def raw(request,uuid): target = str(uuid).split('.')[:-1][0] image = Uploads.objects.get(uuid=target) path = image.path filepath = os.path.join(path,"%s.%s" % (image.uuid,image.ext)) response = HttpResponse(mimetype=mimetypes.guess_type(filepath)) response['Content-Disposition']='filename="%s"'\ %smart_str(image.filename) response["X-Sendfile"] = filepath response['Content-length'] = os.stat(filepath).st_size return response UPDATE It turns out that it works. My problem is when I try to upload an image via URL. It probably doesn't save the entire GIF? def handle_url_file(request): """ Open a file from a URL. Split the file to get the filename and extension. Generate a random uuid using rand1() Then save the file. Return the UUID when successful. """ try: file = urllib.urlopen(request.POST['url']) randname = rand1(settings.RANDOM_ID_LENGTH) newfilename = request.POST['url'].split('/')[-1] ext = str(newfilename.split('.')[-1]).lower() im = cStringIO.StringIO(file.read()) # constructs a StringIO holding the image img = Image.open(im) filehash = checkhash(im) image = Uploads.objects.get(filehash=filehash) uuid = image.uuid return "%s" % (uuid) except Uploads.DoesNotExist: img.save(os.path.join(settings.UPLOAD_DIRECTORY,(("%s.%s")%(randname,ext)))) del img filesize = os.stat(os.path.join(settings.UPLOAD_DIRECTORY,(("%s.%s")%(randname,ext)))).st_size upload = Uploads( ip = request.META['REMOTE_ADDR'], filename = newfilename, uuid = randname, ext = ext, path = settings.UPLOAD_DIRECTORY, views = 1, bandwidth = filesize, source = request.POST['url'], size = filesize, filehash = filehash, ) upload.save() #return uuid return "%s" % (upload.uuid) except IOError, e: raise e Any ideas? Thanks! Wenbert

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  • From Servlet to JSP

    - by kawtousse
    When trying to pass a table built with HTML in my servlet like that: response.setContentType("text/html" ); PrintWriter out = response.getWriter(); out.println("<html>" ); out.println("<head>" ); out.println("<title>Imput OPC</title>" ); out.println("</head>" ); out.println("<body>" ); ... and then response.sendRedirect("/xxx.jsp" ); But I did not found any table in the JSP. A friend told me to use a Bean but how can i catch values from the form ( because I have a treatement with the form before constructing table)in a bean.I must use a servlet for that. So what I want is exactly to construct in the response a table then send it to jsp knowing that: .sendRedirect and getServletContext().getRequestDispatcher("/xxx.jsp").forward(request, response); gives nothing at all. Please Help its urgent. Thinks.

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  • Sql query: use where in or foreach?

    - by phenevo
    Hi, I'm using query, where the piece is: ...where code in ('va1','var2'...') I have about 50k of this codes. It was working when I has 30k codes, but know I get: The query processor ran out of internal resources and could not produce a query plan. This is a rare event and only expected for extremely complex queries or queries that reference a very large number of tables or partition I think that problem is related with IN... So now I'm planning use foreach(string code in codes) ...where code =code Is it good Idea ??

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