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  • PHP: How to forward on $_FILES using cURL

    - by Toby
    Hi. I'm trying to use cURL to forward on a http request from a form in a web application I'm developing. Essentially I need to submit the same form twice on different servers, for the second server I'm adding some security measures to the post data. I can receive $_POST information on the second form perfectly fine, however I'm having major troubles with my $_FILES - I've tried separating the two so there's a separate request for post and files data but still no luck. Is this possible?

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  • declare or convert a string to array format PHP

    - by Jamex
    How to convert a string format into an array format? I have a string, $string = 'abcde' I want to convert it to a 1 element array $string[0] = 'abcde' Is there a built in function for this task? Or the shortest way is to $string = 'abcde'; $array[0] = $string; $string = $array; TIA

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  • populating on the basis of array elements in php

    - by Avinash
    This is my code. if(in_array("1", $mod)){ $res=array('First Name','Insertion','Last Name','Lead Country');} if(in_array("2", $mod)){ $res=array('Landline No:','Mobile No:','Lead Country');} if(in_array("3", $mod)){ $res=array('City','State','Country','Lead Country');} if(in_array("4", $mod)){ $res=array('Email','Lead Country');} return $res; Upto this it works fine. But if the array contains more than one value say (1,3) I need to return both results of 1 and 3. eg: if the array is like this array([0]=>1 [1]=>3) then $res=array('First Name','Insertion','Last Name','City','State','Country','Lead Country') But if there are 2 lead country only one should be displayed how to do this? Pls help me.

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  • PHP Count the lenght of each value in a array/string (tags)

    - by 2by
    Users writing an article have the option to write some tags, tags are written like this: tag1, tag2, tag3 So tags are stored like: $tags = "tag1, tag2, tag3"; I want to make sure, every tag has a minimum of 3 characters, so i need to validate the tags. I have tried this: $tagsstring = explode(",", $tags); $tagslength = array_map('strlen', $tagsstring); if (min($tagslength) < 3) { echo "Error... Each tag has to be at least 3 characters."; } It seems to work, sometimes... But of you write: tag1, df It wont give an error. Any suggestions?

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  • How to pass parameters dynamically in PHP?

    - by user198729
    I need to pass the $route to its inner function,but failed: function compilePath( $route ) { preg_replace( '$:([a-z]+)$i', 'pathOption' , $route['path'] ); function pathOption($matches) { global $route;//fail to get the $route } } I'm using php5.3,is there some feature that can help?

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  • PHP sleep accuracy

    - by Abs
    Hello all, I use the following code to see how long a user is on a particular page. I use a hidden image with a src attribute to this script: $timer_seconds = 1; while(!connection_aborted()) { echo "\n"; flush(); sleep(1); $timer_seconds++; } I sometimes find this can be off by 5-10 seconds! I am guessing its the load of the server that effects the timing?? Is there anyway I can make this accurate? Thanks all for any help.

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  • Display PHP Query Array in the table

    - by Jerry
    Hi all I would like to display my Query from Mysql on the table. However, my data is like this: Array([0]=>data1, [1]=>data2, [2]=>data3,[3]=>data4,[4]=>pic1,[5]=>pic2,[6]=>pic3,[7]=>pic4); I want to display my table as |data1 | data2 |data3 |data4 |pic1 | pic2 |pic3 |pic4 I know how to display the data in the single ling like td or tr but not sure how to do tr and td on the same loop. Any helps? Thanks in advance! while($query=mysql_fetch_array($dataQuery)){ //not sure what to do here. }

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  • Sum of a PHP Array

    - by user1879415
    The following code displays the ordered products individual weight: $weightsql = 'select op.products_name, op.products_quantity , p.products_weight from ' . TABLE_ORDERS_PRODUCTS . ' op left join ' . TABLE_PRODUCTS . ' p on op.products_id = p.products_id where op.products_id = '.$pro['products_id']; $weightq = tep_db_query( $weightsql ); while ($weight = tep_db_fetch_array( $weightq )){ if($category_parent_id != 0)$list_items[] = $weight['products_weight'].'&nbsp;&nbsp;&nbsp;'; } This shows the wieght for each of the products ordered. What I am stuck on is instead of showing seperate weights, I need to show a total weight. For example, if the product was ordered three times, and it weighs 7kg, the code at the moment is showing: Product 7.00 7.00 7.00 How would I make it show the total weight, 21kg?

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  • PHP: Find element with certain property value in array

    - by Svish
    I'm sure there is an easy way to do this, but I can't think of it right now. Is there an array function or something that lets me search through an array and find the item that has a certain property value? For example: $people = array( array( 'name' => 'Alice', 'age' => 25, ), array( 'name' => 'Waldo', 'age' => 89, ), array( 'name' => 'Bob', 'age' => 27, ), ); How can I find and get Waldo?

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  • Hi i am creating a php calendar i have a Problem in that

    - by udaya
    Hi i am creating a calendar i which i filled the year and date like this <<<<< Year <<<<< month by clicking on the arrow marks the year and month can be increased and decreased now i have to fill the dates for the year and month selected I calculated the first day of month and last date of the month The dates must be start filling from the first day Say if the first day is thursday the date 1 must be on thursday and the next days must follow that till the last date These are my functions in my controller " function phpcal() { $month=04; $day=01; $year=2010; echo date("D", mktime(0,0,0,$month,$day,$year)); //here i am calculating the first day of the month echo '<br>lastdate'.date("t", strtotime($year . "-" . $month . "-01"));'' here i am calculating the lasdt date of the month //echo '<br>'.$date_end = $this->lastOfMonth(); $this->load->view('phpcal'); } function firstOfMonth($m1,$y1) { return date("m/d/Y", strtotime($m1.'/01/'.$y1.' 00:00:00')); } function lastOfMonth() { return date("m/d/Y", strtotime('-1 second',strtotime('+1 month',strtotime(date('m').'/01/'.date('Y').' 00:00:00')))); } function phpcalview() { $year = $this->input->post('yearvv'); $data['year'] = $this->adminmodel->selectyear(); $data['date'] = $this->adminmodel->selectmonth(); //print_r($data['date'] ); $this->load->view('phpcal',$data); } This is my view page <table cellpadding="2" cellspacing="0" border="1" bgcolor="#CCFFCC" align="center" class="table_Style_Border"> <? if(isset($date)) { foreach($date as $row) {?> <tr> <td><?= $row['dbDate1'];?></td> <td><?= $row['dbDate2'];?></td> <td><?= $row['dbDate3'];?></td> <td><?= $row['dbDate4'];?></td> <td><?= $row['dbDate5'];?></td> <td><?= $row['dbDate6'];?></td> <td><?= $row['dbDate7'];?></td> </tr> <tr bgcolor="#FFFFFF"> <td><?= $row['dbDate8'];?></td> <td><?= $row['dbDate9'];?></td> <td><?= $row['dbDate10'];?></td> <td><?= $row['dbDate11'];?></td> <td><?= $row['dbDate12'];?></td> <td><?= $row['dbDate13'];?></td> <td><?= $row['dbDate14'];?></td> </tr> <tr> <td><?= $row['dbDate15'];?></td> <td><?= $row['dbDate16'];?></td> <td><?= $row['dbDate17'];?></td> <td><?= $row['dbDate18'];?></td> <td><?= $row['dbDate19'];?></td> <td><?= $row['dbDate20'];?></td> <td><?= $row['dbDate21'];?></td> </tr> <tr bgcolor="#FFFFFF"> <td><?= $row['dbDate22'];?></td> <td><?= $row['dbDate23'];?></td> <td><?= $row['dbDate24'];?></td> <td><?= $row['dbDate25'];?></td> <td><?= $row['dbDate26'];?></td> <td><?= $row['dbDate27'];?></td> <td><?= $row['dbDate28'];?></td> </tr> <tr> <td><?= $row['dbDate29'];?></td> <td><?= $row['dbDate30'];?></td> <td><?= $row['dbDate31'];?></td> <td><?= $row['dbDate1'];?></td> <td><?= $row['dbDate1'];?></td> <td><?= $row['dbDate1'];?></td> <td><?= $row['dbDate1'];?></td> </tr> </tr> <? }} ?> </table> How can i insert the dates starting from the day i have calculated in the function phpcal

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  • PHP MySQL Syntax Error 'You have an error in your SQL syntax'

    - by Alec
    I cannot figure out the issue with my code here. I am trying to take info from the table, then subtract 1 second from Current_Time which looks like '2:00'. The problem is, I get: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Current_Time) VALUES('22')' at line 1" I don't even understand where it gets 22 from. Thanks, I really appreciate it. if (isset($_GET['id']) && isset($_GET['time'])) { mysql_select_db("aleckaza_pennyauction", $connection); $query = "SELECT Current_Time FROM Live_Auctions WHERE ID='1'"; $results = mysql_query($query) or die(mysql_error()); while ($row = mysql_fetch_array($results)) { $newTime = $row['Current_Time'] - 1; $query = "INSERT INTO Live_Auctions(Current_Time) VALUES('".$newTime."')"; $results = mysql_query($query) or die(mysql_error()); } }

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  • Referral System PHP

    - by Liam
    I have a membership based website and im planning on implementing a referral system. My website is credit based, the idea is that if User X refers User Y, then User X gets 100 bonus credits. Has anybody built a referral system before and if so what obstacles should I bear in mind? I've had a snoop round SO tonight but couldn't find any suitable answers. My theory is to give each user a random string which is generated and stored in the DB when they sign up, The user will then be presented with a URL incl. that string which when they pass to somebody (User Z), User Z is then sent to a page, the page then uses the GET method to gather the Random string and update the DB Row they currently occupy, does this sound feasible or could it easily be breached? Thanks

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  • Creating a Calender in PHP

    - by Chris T
    Are there any APIs/Libraries that make it easy to generate a calender for a certain month/year? I need to have some sort of admin interface for a "event planner" part of a CMS for a local youth group and I'm at a loss as to how to generate a decent calender.

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  • PHP: prepared statement, IF statement help needed

    - by JGreig
    I have the following code: $sql = "SELECT name, address, city FROM tableA, tableB WHERE tableA.id = tableB.id"; if (isset($price) ) { $sql = $sql . ' AND price = :price '; } if (isset($sqft) ) { $sql = $sql . ' AND sqft >= :sqft '; } if (isset($bedrooms) ) { $sql = $sql . ' AND bedrooms >= :bedrooms '; } $stmt = $dbh->prepare($sql); if (isset($price) ) { $stmt->bindParam(':price', $price); } if (isset($sqft) ) { $stmt->bindParam(':price', $price); } if (isset($bedrooms) ) { $stmt->bindParam(':bedrooms', $bedrooms); } $stmt->execute(); $result_set = $stmt->fetchAll(PDO::FETCH_ASSOC); What I notice is the redundant multiple IF statements I have. Question: is there any way to clean up my code so that I don't have these multiple IF statements for prepared statements?

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  • PHP array of object(stdClass) fusion/intersect?

    - by Gremo
    $arr1 is an associative array of anonymus objects: array 15898 => object(stdClass)[8] public 'date' => int $arr2 is another associative array with two (or more, it's not fixed) properties: array 15898 => object(stdClass)[10] public 'fruits' public 'drinks' I can't find any function for intersect and content fusion when dealing with objects. Basically i'd like to obtain: array 15898 => object(stdClass)[8] public 'date' => int public 'fruits' public 'drinks' Question is: is this even possible?

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  • JSON Returning Null in PHP

    - by kira423
    Here is the two scripts I have Script 1: if(sha1($json+$secret) == $_POST['signature']) { $conversion_id = md5(($obj['amount'])); echo "OK"; echo $conversion_id; mysql_query("INSERT INTO completed (`id`,`uid`,`completedid`) VALUES ('','".$obj['uid']."','".$conversion_id."')"); } else { } ?> Script 2: <? $json = $_POST['payload']; $secret = "78f12668216b562a79d46b170dc59f695070e532"; $obj = json_decode($json); if(sha1($json+$secret) == $_POST['signature']) { print "OK"; } else { } ?> The problem here is that it is returning all NULL values. I am not an expert with JSON so I have no idea what is going on here. I really have no way of testing it because the information is coming from an outside website sending information such as this: { payload: { uid: "900af657a65e", amount: 50, adjusted_amount: 25 }, signature: "4dd0f5da77ecaf88628967bbd91d9506" } The site allows me to test the script, but because json_decode is providing NULL values it will not get through the signature block. Is there a way I can test it myself? Or is there a simple error in this script that I may have just looked over?

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  • Creating a calendar in PHP

    - by Chris T
    Are there any APIs or libraries that make it easy to generate a calendar for a certain month/year? I need to have some sort of admin interface for a "event planner" part of a CMS for a local youth group and I'm at a loss as to how to generate a decent calendar. Note: I only need something to generate the calendar HTML, not manage events. I'll be coding that part.

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  • Getting information from an XML object in PHP

    - by errata
    Hi! I am using some XML parser to get some information from API, blah blah... :) In one place in my script, I need to convert string to int but I'm not sure how... Here is my object: object(parserXMLElement)#45 (4) { ["name:private"]=> string(7) "balance" ["data:private"]=> object(SimpleXMLElement)#46 (1) { [0]=> string(12) "11426.46" } ["children:private"]=> NULL ["rows:private"]=> NULL } I need to have this string "11426.46" stored in some var as integer. When I echo $parsed->result->balance I get that string, but if I want to cast it as int, the result is: 1. Please help! Thanks a lot!

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