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  • Incrementing through mysql PHP

    - by Rawdon
    I am looking at try to increment and decrement by three records through a table and present those records. Say if the id '4' is currently active. I want the to be display the ID's and category of 3.2.1 and 5.6.7 from an increment and decrement So far I have: $stmt = $db->query("SELECT id, category FROM test"); $stmt->execute(); while ($results = $stmt->fetch(PDO::FETCH_ASSOC)) { $current = $results['id']; $category = $results['category']; $next = array(array('slide_no' => $current, 'category' => $category)); } print_r($next); Now with this, I am getting back every row in the table. I'm now getting confused on how I could increment and decrement the records by 3 and make sure that the category will also increment correctly. Thank you very much.

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  • PHP Magento get customers last order total

    - by simian
    I am working outside of magento store root folder (1.4) and I would like to get customers order totals, and date of last order. I have started with this: $customer = Mage::getModel('customer/customer')->load($entity_id); $customerTotals =Mage::getResourceModel('sales/sale_collection') ->setCustomerFilter($customer) ->load() ->getTotals(); echo $customerTotals->getNumOrders(); echo money_format('$%i',$customerTotals->getLifetime()); This seems to be giving me totals from the wrong customer... Also, can't quite figure out how to get customers last order day. any help would be appreciated.

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  • php - using file() incrementally?

    - by NeedBeerStat
    I'm not sure if this is possible, I've been googling for a solution... But, essentially, I have a very large file, the lines of which I want to store in an array. Thus, I'm using file(), but is there a way to do that in batches? So that every,say, 100 lines it creates, it "pauses"? I think there's likely to be something I can do with a foreach loop or something, but I'm not sure that I'm thinking about it the right way... Like $i=0; $j=0; $throttle=100; foreach($files as $k => $v) { if($i < $j+$throttle && $i > $j) { $lines[] = file($v); //Do some other stuff, like importing into a db } $i++; $j++; } But, I think that won't really work because $i & $j will always be equal... Anyway, feeling muddled... Can someone help me think a lil' clearer?

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  • PHP GD Incredibly Strange Problem

    - by ThinkingInBits
    if ($img = imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { die("success"); } if ($img = imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { $image_width = imagesx($img); $image_height = imagesy($img); $target_width = 150; $target_height = 150; if ($image_width > $image_height) { $percentage = ($target_width / $image_width); } else { $percentage = ($target_height / $image_height); } $new_image_width = round($image_width * $percentage); $new_image_height = round($image_height * $percentage); $imgResized = imagecreatetruecolor($new_image_width, $new_image_height); imagecopyresampled($imgResized, $img, 0, 0, 0, 0, $new_image_width, $new_image_height, $image_width, $image_height); imagejpeg($imgResized, $this->path, 100); imagedestroy($img); imagedestroy($imgResized); $this->storeThumbnailLocation(); } else { die ("image was not created or saved"); } The first if statement dies and echos success. If I take out the first if statement, the second one echos "image could not be created or saved" If honestly run out of ideas on this one, the code is identical

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  • Need help with transferring data between MySQL db's using PHP

    - by JM4
    In one of the sites I manage, the client has decided to take on ACH/Bank Account administration where it was previously outsourced. As a result, the information submitted in our online form which used to simply store in a single database for processing now must sit in 'limbo' until the funds used for payment have been verified. My original plan is as follows: At the end of an enrollment, all form data is collected and stored in a single MySQL database. Our internal administrator will receive an email notification reminding him enrollments have taken place. He will process the ACH information collected and wait the 3-4 business days needed for payment to clear. Once the payment information has been returned as Good (haven't considered what I will do with the 'bad' yet), the administrator can log into a secure portal which allows him to click a button to 'process' the full information once compared and verified. the process is simplified as: Enrollment complete: data stored in DB 'A' Funds verified and link clicked: data from 'A' is copied to DB 'B' and 'A' is deleted. I have run similar processes with CSV output before and simply used //transfers old data to archive $transfer = mysql_query('INSERT INTO '.$archive.' SELECT * FROM '.$table) or die(mysql_error()); //empties existing table $query = mysql_query('TRUNCATE TABLE '.$table) or die(mysql_error()); but in those cases, ALL data returned was copied and deleted. I only want to copy and delete a single record. Any idea how to accomplish this?

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  • PHP: parse $_FILES[] data in multidimesional array

    - by superUntitled
    I having been looking around for an answer to this and have not found an answer anywhere, I am hoping someone has done this before! I have a form that allows for dynamic duplication of the form fields. The form allows for file uploads and text input, so the data is sent in both $_POST and $_FILES arrays. The the initial set of inputs look like this: <input type="text" name="primary[1][text]" /> <input type="file" name="primary[1][file]" /> <input type="text" class="a" name="secondary[1][text][]" /> <input type="file" name="secondary[1][file][]" /> When duplicated the fields are incremented, they look like this: <input type="text" name="primary[2][text]" /> <input type="file" name="primary[2][file]" /> <input type="text" class="a" name="secondary[2][text][]" /> <input type="file" name="secondary[2][file][]" /> To complicate matters, the "secondary" form fields can also be duplicated (thus the [] at the end of the secondary name array. How can I parse the posted $_FILES array? I have tried something like this: foreach ($_FILES['question'] as $f_num) { echo $f['file']['name']; } but I get an "Undefined index: file... " error.

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  • PHP Sort Array By SubArray Value

    - by Sjwdavies
    I've got the following structue of array: Array ( [0] => Array ( [configuration_id] => 10 [id] => 1 [optionNumber] => 3 [optionActive] => 1 [lastUpdated] => 2010-03-17 15:44:12 ) [1] => Array ( [configuration_id] => 9 [id] => 1 [optionNumber] => 2 [optionActive] => 1 [lastUpdated] => 2010-03-17 15:44:12 ) [2] => Array ( [configuration_id] => 8 [id] => 1 [optionNumber] => 1 [optionActive] => 1 [lastUpdated] => 2010-03-17 15:44:12 ) ) What's the best way for order the array, in an incremental way based on the optionNumber? So the results look like: Array ( [0] => Array ( [configuration_id] => 8 [id] => 1 [optionNumber] => 1 [optionActive] => 1 [lastUpdated] => 2010-03-17 15:44:12 ) [1] => Array ( [configuration_id] => 9 [id] => 1 [optionNumber] => 2 [optionActive] => 1 [lastUpdated] => 2010-03-17 15:44:12 ) [2] => Array ( [configuration_id] => 10 [id] => 1 [optionNumber] => 3 [optionActive] => 1 [lastUpdated] => 2010-03-17 15:44:12 ) )

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  • PHP: Remove blank line before text

    - by Bailey
    Occasionally, my email-to-support-ticket system catches an extra line break before the message itself, thus my messages look like this: " Hello. I have been wondering if y..." What can I use to get rid of that line before the text? It is on random occasion due to email providers and the way they format their emails using mime. I have already tried the trim functions but no luck. (Yes, I also tried ltrim) Once processed it should look like: "Hello. I have been wondering if y..."

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  • PHP SDK Requires two logins...doesn't recognize first

    - by Jay Konieczny
    I am using the following code to authenticate whether users are logged in or not. While users can log in, they have to click the login button twice. Additionally, sometimes even after they click the log-in button twice, my "user info" part of the page (earlier in the page than the content) shows them as logged out while the actual page shows them as logged in. Here is the code. Could someone suggest a better way of handling log-ins? function isLoggedIn($facebook) { if (isset($facebook) and $facebook->getUser() != 0) { // UserID exists, but user may still not be logged in. Let's check: try { $facebook->api('/me', 'GET'); // If this succeeds, then they are logged in. return true; } catch(FacebookApiException $e) { // Some kind of error, so not logged in. if(session_id() === '') session_destroy(); return false; } } else { if(session_id() === '') session_destroy(); return false; } } Thanks!

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  • php weeks between 2 dates

    - by Arun
    hi i want to find how to find no of weeks and each mondays date between 2 dates. for ex 10-07-2009 to today . Note :consider leap year and other date related constrains also.

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  • PHP Session Array Value keeps showing as "Array"

    - by Nerathas
    Hello, When sending data from a form to a second page, the value of the session is always with the name "Array" insteed of the expected number. The data should get displayed in a table, but insteed of example 1, 2, 3 , 4 i get : Array, Array, Array. (A 2-Dimensional Table is used) Is the following code below a proper way to "call" upon the stored values on the 2nd page from the array ? $test1 = $_SESSION["table"][0]; $test2 = $_SESSION["table"][1]; $test3 = $_SESSION["table"][2]; $test4 = $_SESSION["table"][3]; $test5 = $_SESSION["table"][4]; What exactly is this, and how can i fix this? Is it some sort of override that needs to happen? Best Regards.

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  • PHP - BUG with filter_var and FILTER_VALIDATE_FLOAT

    - by Samuele
    I think there is a bug in this filter_var or maybe I'm doing something wrong: Try this: $options = array( 'options' => array( 'default' => 3, 'min_range' => 1000.0, 'max_range' => 5000.6, ) ); $VariableValue2 = 5698; $VariableValue4 = 5698.2; $chicco3 = filter_var($VariableValue2, FILTER_VALIDATE_INT, $options); $chicco4 = filter_var($VariableValue4, FILTER_VALIDATE_FLOAT, $options); It suppose to don't validate it... Infact the value: 5698 is greater than 5000.6!!!! But with FILTER_VALIDATE_INT it work FINE!! It return 3 that is the default value in case it don't validate it... PERFECT... Instead, with FILTER_VALIDATE_FLOAT it validate it... It return 5698.2!!! I'm doing something wrong??? Thank you to everybody... Samuele

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  • php $_SESSION[document_root] too far down the tree

    - by Idealflip
    Hi, I have multiple sub-domains within the document_root. And multiple folders/classes within those sub-domain folders. I need something that will help me with my include_once paths, but $_SESSION[DOCUMENT_ROOT] goes too far down. And if I were to use this, and transfer the website folder later, all my include_once paths will/might break. Hope my question is clear... Any recommendations?

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  • PHP : If...Else...Query

    - by Rachel
    I am executing this statement under while (($data=fgetcsv($this->fin,5000,";"))!==FALSE) Now what I want in else loop is to throw exception only for data value which did not satisfy the if condition. Right now am displaying the complete row as I am not sure how to throw exception only for data which does not satisfy the value. Code if ((strtotime($data[11]) &&strtotime($data[12])&&strtotime($data[16]))!==FALSE && ctype_digit($data[0]) && ctype_alnum($data[1]) && ctype_digit($data[2]) && ctype_alnum($data[3]) && ctype_alnum($data[4]) && ctype_alnum($data[5]) && ctype_alnum($data[6]) && ctype_alnum($data[7]) && ctype_alnum($data[8]) && $this->_is_valid($data[9]) && ctype_digit($data[10]) && ctype_digit($data[13]) && $this->_is_valid($data[14])) { //Some Logic } else { throw new Exception ("Data {$data[0], $data[1], $data[2], $data[3], $data[4], $data[5], $data[6], $data[7], $data[8], $data[9], $data[10], $data[11], $data[12], $data[13], $data[14], $data[16]} is not in valid format"); } Guidance would be highly appreciated as to how can I throw exception only for data which did not satisfy the if value.

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  • PHP File Upload + jQuery

    - by st4ck0v3rfl0w
    Hello Everyone, So I have my upload script working just fine, but now it's a matter of making it look the way I want for my layout. <input type="file" name="userfile" id="userfile"/> This obviously shows a textbox with a Choose File button. What I really need is my own custom button (which will ultimately be an image) that upon successful file select (not upload quite yet) triggers a jQuery event to show a div. I do NOT want the filename textbox to show. Basic steps outlined below. User clicks on image button to upload their file User selects file jQuery shows a div with more fields User clicks submit and file is uploaded

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  • [PHP] Local/Dev/Live deployment - best workflow

    - by Adam Kiss
    Hello, situation We our little company with 3 people, each has a localhost webserver and most projects (previous and current) are on one PC network shared disk. We have virtual server, where some of our clients' sites and our site. Our standard workflow is: Coder PC ? Programmer localhost ? dev domain (client.company.com) ? live version (client.com) It often happens, that there are two or three guys working on same projects at the same time - one is on dev version, two are on localhost. When finished, we try to synchronize the files on dev version and ideally not to mess up any files, which *knock knock * doesn't happen often. And then one of us deploys dev version on live webserver. question we are looking for a way to simplify this workflow while updating websites - ideally some sort of diff uploader or VCS probably (Git/SVN/VCS/...), but we are not completely sure where to begin or what way would be ideal, therefore I ask you, fellow stackoverflowers for your experience with website / application deployment and recommended workflow. We probably will also need to use Mac in process, so if it won't be a problem, that would be even better. Thank you

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  • PHP: parse $_FILES[] data in multidimesional array

    - by superUntitled
    Example form here: http://jsfiddle.net/superuntitled/uaTtx/1/ I have a form that allows for dynamic duplication of the form fields. The form allows for file uploads and text input, so the data is sent in both $_POST and $_FILES arrays. The the initial set of inputs look like this: <input type="text" name="question[1][text]" /> <input type="file" name="question[1][file]" /> <input type="text" class="a" name="answer[1][text][]" /> <input type="file" name="answer[1][file][]" /> When duplicated the fields are incremented, they look like this: <input type="text" name="question[2][text]" /> <input type="file" name="question[2][file]" /> <input type="text" class="a" name="answer[2][text][]" /> <input type="file" name="answer[2][file][]" /> To complicate matters, the "answer" form fields can also be duplicated (thus the [] at the end of the 'answer' name array. How can I parse the posted $_FILES array? I have tried something like this: foreach ($_FILES['question'] as $p_num) { echo $p_num['file']['name']; foreach ($_FILES['answer'] as $a_num) { echo $a_num['file']['name']; } } but I get an "Undefined index: file... " error. How can I parse out the posted values.

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  • Leading zeroes in php

    - by sanders
    Hello, I would like to present a list from 0 to 59 of with the numbers 0 to 9 have a leading zero. This is my code but it doesn't work so far. Any idea's? for($i=0; $i<60; $i++){ if($i< 10){ sprintf("%0d",$i); } array_push($this->minutes,$i); }

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  • Simple PHP query question: LIKE

    - by pg
    When I replace $ordering = "apples, bananas, cranberries, grapes"; with $ordering = "apples, bananas, grapes"; I no longer want cranberries to be returned by my query, which I've written out like this: $query = "SELECT * from dbname where FruitName LIKE '$ordering'"; Of Course this doesn't work, because I used LIKE wrong. I've read through various manuals that describe how to use LIKE and it doesn't quite make sense to me. If I change the end of the db to "LIKE "apples"" that works for limiting it to just apples. Do I have to explode the ordering on the ", " or is there a way to do this in the query?

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  • Php random row help...

    - by Skillman
    I've created some code that will return a random row, (well, all the rows in a random order) But i'm assuming its VERY uneffiecent and is gonna be a problem in a big database... Anyone know of a better way? Here is my current code: $count3 = 1; $count4 = 1; //Civilian stuff... $query = ("SELECT * FROM `*Table Name*` ORDER BY `Id` ASC"); $result = mysql_query($query); while($row = mysql_fetch_array($result)) { $count = $count + 1; $civilianid = $row['Id']; $arrayofids[$count] = $civilianid; //echo $arrayofids[$count]; } while($alldone != true) { $randomnum = (rand()%$count) + 1; //echo $randomnum . "<br>"; //echo $arrayofids[$randomnum] . "<br>"; $currentuserid = $arrayofids[$randomnum]; $count3 += 1; while($count4 < $count3) { $count4 += 1; $currentarrayid = $listdone[$count4]; //echo "<b>" . $currentarrayid . ":" . $currentuserid . "</b> "; if ($currentarrayid == $currentuserid){ $found = true; //echo " '" .$found. "' "; } } if ($found == true) { //Reset array/variables... $count4 = 1; $found = false; } else { $listdone[$count3] = $currentuserid; //echo "<u>" . $count3 .";". $listdone[$count3] . "</u> "; $query = ("SELECT * FROM `*Tablesname*` WHERE Id = '$currentuserid'"); $result = mysql_query($query); $row = mysql_fetch_array($result); $username = $row['Username']; echo $username . "<br>"; $count4 = 1; $amountdone += 1; if ($amountdone == $count) { //$count $alldone = true; } } } Basically it will loop until its gets an id (randomly) that hasnt been chosen yet. -So the last username could take hours :P Is this 'bad' code? :P :(

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  • php - How do I get rid of this strange "empty delimiter" message

    - by Steven
    I have some code that uses the stristr function to extract data I need. It works, in that it gives me the results I'm looking for. BUT (you knew there was a but), it gives me this error message for every iteration of the loop: Warning: stristr() [function.stristr]: Empty delimiter in ... line 55 Like I said, the code works apart from this error. Can anyone suggest how i could amend this code to get rid of the message? Thanks in advance $data = stristr("$text", "$key"); $result = string_limit_words($data,2); print "$result<BR>";

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  • What are the PHP "encryption" functions?

    - by Rob
    Looking for built in encryption functions, not to hide the string from the clever programmer, but instead just to obfuscate it a bit. Looking for functions such as str_rot13 and base64_encode, but I can't seem to locate any. Surely there are more?

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  • REST Authentication in PHP (CodeIgniter)

    - by zidane
    I writing REST API form my web application. Application is written using CodeIgniter framework. Application itself is working fine, but I'm stuck on making REST Authentication. I think that basic Http Authentication will be good enough for some time. Public API is not yet planned. Is there any code example how to achieve REST Authentication so after user is authenticated he can freely call all protected methods.

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