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  • PHP - Search array in array

    - by Anonymous2011
    I have tried googling for the past one hour straight now and tried many ways to search for an array, in an array. My objective is, to find a keyword in the URL, and the keywords are in a txt file. This is what i have so far - but doesn't work. $file = "keywords.txt"; $open = fopen($file,'r'); $data = fread($open,filesize($file)); $data = explode(" ",$data); $url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; $url = parse_url($url); //parse the URL into an array foreach($data as $d) { if(strstr($d,$url)) { echo "yes"; } } This works WITHOUT the text file, or array - but that's not what i want. I'd appreciate it if anyone can assist me.

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  • Reformat a date in PHP

    - by Kreker
    I have a date/time string like this: 180510_112440 in this format ddmmyy_hhmmss I need a snippet for having a string formatted like this way: 2010-05-18 11:24:40 Thanks for help.

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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • Fetch multiple rows from SQL in PHP foreach item in array

    - by TrySpace
    I try to request an array of IDs, to return each row with that ID, and push each into an Array $finalArray But only the first result from the Query will output, and at the second foreach, it skips the while loop. I have this working in another script, so I don't understand where it's going wrong. The $arrayItems is an array containing: "home, info" $finalArray = array(); foreach ($arrayItems as $UID_get) { $Query = "SELECT * FROM items WHERE (uid = '" . cleanQuery($UID_get) . "' ) ORDER BY uid"; if($Result = $mysqli->query($Query)) { print_r($UID_get); echo "<BR><-><BR>"; while ($Row = $Result->fetch_assoc()) { array_push($finalArray , $Row); print_r($finalArray ); echo "<BR><><BR>"; } } else { echo '{ "returned" : "FAIL" }'; //. mysqli_connect_errno() . ' ' . mysqli_connect_error() . "<BR>"; } } (the cleanQuery is to escape and stripslashes) What I'm trying to get is an array of multiple rows (after i json_encoded it, like: {"finalArray" : { "home": {"id":"1","created":"0000-00-00 00:00:00","css":"{ \"background-color\" : \"red\" }"} }, { "info": {"id":"2","created":"0000-00-00 00:00:00","css":"{ \"background-color\" : \"blue\" }"} } } But that's after I get both, or more results from the db. the print_r($UID_get); does print info, but then nothing.. So, why am I not getting the second row from info? I am essentially re-querying foreach $arrayItem right?

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  • Saving PHP Table as CSV

    - by user2403705
    I have been looking everywhere for a way to do this. There are a lot of people that have asked the questions but when I try myself i cant seem to get it to work. Often I get the format correct but it inputs the information into a new page instead of saving it. I did manage to get one to work for google chrome but when i ran it in internet explorer it didnt work. I have a table being created from a MYSQL query and i would like the table to be able to be saved as a CSV. Could anyone help me out?

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  • PHP & MySQL query value question.

    - by space
    How can I use the first query's id value $row['id'] again after I run a second query inside the while loop statement? To show you what I mean here is a sample code below of what I'm trying to do. I hope I explained it right. Here is the code. $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id = 4"); if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); } while($row = mysqli_fetch_assoc($dbc)) { echo '<div>User: ' . $row['id'] . '</div>'; echo '<div>Link To User' . $row['id'] . '</div>'; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc2 = mysqli_query($mysqli,"SELECT COUNT(cid) as num FROM comments WHERE comments_id = $row[id]"); if (!$dbc2) { // There was an error...do something about it here... print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc2)){ $num = $row['num']; } } echo '<div>User ' . $row['id'] . ' Comments# ' . $num . '</div>'; }

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  • SFTP not supported error with PHP & cURL

    - by Bad Programmer
    I followed the advice from this Stack Overflow question thread, but I keep hitting a snag. I am receiving the following error message: Unsupported protocol: sftp Here is my code: $ch = curl_init(); if(!$ch) { $error = curl_error($ch); die("cURL session could not be initiated. ERROR: $error.""); } $fp = fopen($docname, 'r'); if(!$fp) { $error = curl_error($ch); die("$docname could not be read."); } curl_setopt($ch, CURLOPT_URL, "sftp://$user_name:$user_pass@$server:22/$docname"); curl_setopt($ch, CURLOPT_UPLOAD, 1); curl_setopt($ch, CURLOPT_PROTOCOLS, CURLPROTO_SFTP); curl_setopt($ch, CURLOPT_INFILE, $fp); curl_setopt($ch, CURLOPT_INFILESIZE, filesize($docname)); //this is where I get the failure $exec = curl_exec ($ch); if(!$exec) { $error = curl_error($ch); die("File $docname could not be uploaded. ERROR: $error."); } curl_close ($ch); I used the curl_version() function to see my curl information, and found that sftp doesn't seem to be in the array of supported protocols: [version_number] => 462597 [age] => 2 [features] => 1597 [ssl_version_number] => 0 [version] => 7.15.5 [host] => x86_64-redhat-linux-gnu [ssl_version] => OpenSSL/0.9.8b [libz_version] => 1.2.3 [protocols] => Array ( [0] => tftp [1] => ftp [2] => telnet [3] => dict [4] => ldap [5] => http [6] => file [7] => https [8] => ftps ) Is this a matter of my version of cURL being outdated, or is the SFTP protocol simply not supported at all? Any advice is greatly appreciated.

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  • Php read directory file

    - by kwek-kwek
    I have a script that goes through a directory that has 3 images $imglist=''; $img_folder = "path to my image"; //use the directory class $imgs = dir($img_folder); //read all files from the directory, checks if are images and ads them to a list while ($file = $imgs->read()) { if (eregi("gif", $file) || eregi("jpg", $file) || eregi("png", $file)) $imglist .= "$file "; } closedir($imgs->handle); //put all images into an array $imglist = explode(" ", $imglist); //display image foreach($imglist as $image) { echo '<img src="'.$img_folder.$image.'">'; } but the problem that I am having is it display a 4th img with no image.. yet I only have 3 image in that folder.

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  • php strtotime() some help

    - by sea_1987
    Hi there, I am taking credit card details and I am taking the expiration date in two form field, one for the expiration month and one for the expiration year, I am wanting to store the expiration date as timestamp. Will strtotime("05/2010") create a time stamp or do I need to pass a day as well or is there an alternative? Thanks

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  • PHP using count() with array

    - by seb
    Hi there, Im trying to get the amount of elements in an array using the count() function, the result is a bit puzzling to me, considere the following example. Assume that the user ID provided is wrong, and therefore had no matches, wouldnt then the result of the count function be 0? yet it is 1. can you explain to me why? thanks $q = mysql_query("select password from users where user_name = '" . $userID . "'"); $check = mysql_fetch_array($q); $result = count($check); echo "RESULT:" . $result;

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  • php and SQL_CALC_FOUND_ROWS

    - by Lizard
    I am trying to add the SQL_CALC_FOUND_ROWS into a query (Please note this isn't for pagination) please note I am trying to add this to a cakePHP query the code I currently have is below: return $this->find('all', array( 'conditions' => $conditions, 'fields'=>array('SQL_CALC_FOUND_ROWS','Category.*','COUNT(`Entity`.`id`) as `entity_count`'), 'joins' => array('LEFT JOIN `entities` AS Entity ON `Entity`.`category_id` = `Category`.`id`'), 'group' => '`Category`.`id`', 'order' => $sort, 'limit'=>$params['limit'], 'offset'=>$params['start'], 'contain' => array('Domain' => array('fields' => array('title'))) )); Note the 'fields'=>array('SQL_CALC_FOUND_ROWS',' this obviously doesn't work as It tries to apply the SQL_CALC_FOUND_ROWS to the table e.g. SELECTCategory.SQL_CALC_FOUND_ROWS, Is there anyway of doing this? Any help would be greatly appreciated, thanks.

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  • num_rows is 0 when it should be >0 for php mysqli code

    - by jpporterVA
    My num_rows is coming back as 0, and I've tried calling it several ways, but I'm stuck. Here is my code: $conn = new mysqli($dbserver, "dbuser", "dbpass", $dbname); // get the data $sql = 'SELECT AT.activityName, AT.createdOn FROM userActivity UA, users U, activityType AT WHERE U.userId = UA.userId and AT.activityType = UA.activityType and U.username = ? order by AT.createdOn'; $stmt = $conn->stmt_init(); $stmt->prepare($sql); $stmt->bind_param('s', $requestedUsername); $stmt->bind_result($activityName, $createdOn); $stmt->execute(); // display the data $numrows = $stmt->num_rows; $result=array("user activity report for: " . $requestedUsername . " with " . $numrows . " rows:"); $result[]="Created On --- Activity Name"; while ($stmt->fetch()) { $msg = " " . $createdOn . " --- " . $activityName . " "; $result[] = $msg; } $stmt->close(); There are multiple rows found, and the fetch loop process them just fine. Any suggestions on what will enable me to get the number of rows returned in the query? Suggestions are much appreciated. Thanks in advance.

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  • Get websites title and description, save to utf8 table, php/mysql

    - by Geteburg
    Hi guys, I've been trying today all day to figure this out and I have no idea. What I want: Get the title and meta description of any kind of website. Save this info to utf table in mysql. What the problem is? Different sites have different charsets which results in that some have chinese, some contain umlauts (german), then we have russian and so on.. I've tried preg_match which works for some while not for others, i've tried DOMdocument which is the same as preg_match. Is there any class available that will do this? Hope someone can help, thanks.

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  • PHP get values from SimpleXMLElement array

    - by seanp2k
    I have this: [1]=> object(SimpleXMLElement)#6 (1) { ["@attributes"]=> array(14) { ["name"]=> string(5) "MySQL" ["acknowledged"]=> string(1) "1" ["comments"]=> string(1) "1" ["current_check_attempt"]=> string(1) "1" ["downtime"]=> string(1) "0" ["last_check"]=> string(19) "2010-05-01 17:57:00" ["markdown_filter"]=> string(1) "0" ["max_check_attempts"]=> string(1) "3" ["output"]=> string(42) "CRITICAL - Socket timeout after 10 seconds" ["perfdata_available"]=> string(1) "1" ["service_object_id"]=> string(3) "580" ["state"]=> string(8) "critical" ["state_duration"]=> string(6) "759439" ["unhandled"]=> string(1) "0" } } (I used var_dump($child) to generate that) How do I get the 'name' attribute out of there as a string? Here is my code: $xml = simplexml_load_string($results); foreach($xml->data->list as $child) { var_dump($child); echo $child->getName() . ": " . $child->name . "<br />"; }

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  • Removing part of a string in PHP

    - by Nik
    I'm trying to take a query: SHOW TABLES; which will display a bunch of tables with the chat_ prefix. I want to remove the chat_ prefix from the string, format the variable (with a link), and display it. How is this accomplished?

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  • PHP while loop, table row

    - by Elliott
    Hi, I'm trying to loop through a database and output data into a div, if there are 3 divs horizontally accross it will the start a new tr until it reaches another 3 etc. It is currently outputted like : [] [] [] [] [] [] Currently I have it working when it reaches 3 it starts a new row, but I don't know how I can only echo a new tr once? As it creates a new table row each time. echo '<table><tr>'; while ($result) { $i ++; if ($i&3) { echo '<td> <div>Row Data</div> </td>'; } else { echo '<tr> <td> <div>Row Data</div> </td></tr>'; } } echo '</tr></table>'; The $result variable is the recordset from my sql query, everything works fine I just don't know how to only create a new table row once? Thanks

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  • php associative array name?

    - by daniel Crabbe
    hello! Just trying to get the name of an assoc array; $test = array('selected' =>$selected, 'sectionList'=>$sectionList, 'categoryList'=>$categoryList); <? foreach($test as $list) { ?> <h3><?=$list?>, <?=$list[id]?>, <?=$list['name']?>, <?=$list['value']?></h3> <? } ?> but either get 'Array' or nothing?! I can see the name when i print_r($test); Do you think this is possible? Thanks in advance, D.

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  • Empty files generated from running `mysqldump` using PHP

    - by alex
    I keep getting empty files generated from running $command = 'mysqldump --opt -h localhost -u username -p \'password\' dbname > \'backup 2009-04-15 09-57-13.sql\''; command($command); Anyone know what might be causing this? My password has strange characters in it, but works fine with connecting to the db. I've ran exec($command, $return) and outputted the $return array and it is finding the command. I've also ran it with mysqldump > file.sql and the file contains Usage: mysqldump [OPTIONS] database [tables] OR mysqldump [OPTIONS] --databases [OPTIONS] DB1 [DB2 DB3...] OR mysqldump [OPTIONS] --all-databases [OPTIONS] For more options, use mysqldump --help So it would seem like the command is working.

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  • php random image file name

    - by bush man
    Okay im using a snippet I found on google to take a users uploaded image and put it in my directory under Content But Im worried about duplicates so I was going have it upload the image as a Random number well here is my code you can probably understand what im going for through it anyways <label for="file">Profile Pic:</label> <input type="file" name="ProfilePic" id="ProfilePic" /><br /> <input type="submit" name="submit" value="Submit" /> $ProfilePicName = $_FILES["ProfilePic"]["name"]; $ProfilePicType = $_FILES["ProfilePic"]["type"]; $ProfilePicSize = $_FILES["ProfilePic"]["size"]; $ProfilePicTemp = $_FILES["ProfilePic"]["tmp_name"]; $ProfilePicError = $_FILES["ProfilePic"]["error"]; $RandomAccountNumber = mt_rand(1, 99999); echo $RandomAccountNumber; move_uploaded_file($ProfilePicTemp, "Content/".$RandomAccountNumber.$ProfilePicType); And then basicly after all this Im going try to get it to put that random number in my database

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  • php web based portal authentication through IP.

    - by user434885
    i have a web portal running which involves basic data entry. The issue being that this is highly sensitive data. And the credibility of the data entry personel is very low. Therefore i have implemented recording of IP when an entry is made. The Problem i am facing is if this if this person starts forwarding his IP from a proxy server then i am unable to track authenticity of the data. How do i detect if the IP forwarding is happening/ get the real ip address of the person.

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  • [PHP] Check Valid date type

    - by yukou
    may be this question had been asked, I've searched but still not confident about my problem.. my problem is checking valid date from string $a='23-June-11'; //valid $b='Normal String';//invalid I want to convert $a and $b using strtotime() before I do that, of course i want to validate whether $a or $b is a valid date format From $a i can get 23, 11 using explode function, but how about 'June'? using function above, 'June' is not numeric

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