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  • What's the difference between these LINQ queries ?

    - by SnAzBaZ
    I use LINQ-SQL as my DAL, I then have a project called DB which acts as my BLL. Various applications then access the BLL to read / write data from the SQL Database. I have these methods in my BLL for one particular table: public IEnumerable<SystemSalesTaxList> Get_SystemSalesTaxList() { return from s in db.SystemSalesTaxLists select s; } public SystemSalesTaxList Get_SystemSalesTaxList(string strSalesTaxID) { return Get_SystemSalesTaxList().Where(s => s.SalesTaxID == strSalesTaxID).FirstOrDefault(); } public SystemSalesTaxList Get_SystemSalesTaxListByZipCode(string strZipCode) { return Get_SystemSalesTaxList().Where(s => s.ZipCode == strZipCode).FirstOrDefault(); } All pretty straight forward I thought. Get_SystemSalesTaxListByZipCode is always returning a null value though, even when it has a ZIP Code that exists in that table. If I write the method like this, it returns the row I want: public SystemSalesTaxList Get_SystemSalesTaxListByZipCode(string strZipCode) { var salesTax = from s in db.SystemSalesTaxLists where s.ZipCode == strZipCode select s; return salesTax.FirstOrDefault(); } Why does the other method not return the same, as the query should be identical ? Note that, the overloaded Get_SystemSalesTaxList(string strSalesTaxID) returns a record just fine when I give it a valid SalesTaxID. Is there a more efficient way to write these "helper" type classes ? Thanks!

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  • difference fixed width strings and zero-terminated strings

    - by robUK
    Hello, gcc 4.4.4 c89 I got into a recent discussion about "fixed width strings" and "zero terminated strings". When I think about this. They seem to be the same thing. A string with a terminating null. i.e. char *name = "Joe bloggs"; Is a fixed width string that cannot be changed. And also has a terminating null. Also in the discussion I was told that strncpy should never been used on 'zero terminated strings'. Many thanks for any susgestions,

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  • Difference between internet and Desktop jave EE app server

    - by immer
    Hello. I need some clarification. I know that in order to run a java EE project, one needs a java EE compliant application server, such as tomcat, jboss, glashfish, etc. But, i download these to my desktop, but how about when i run it online? Are Jboss, tomcat, glashfish, etc. application servers just for your desktop, or are these the app server internet service providers have as well. I am trying to use godaddy as my internet service provider; i called them, but the customer service guy didnt know what application server they had, or did i ask the wrong question? Or how can i know waht application server they have? Thank you, any help is greatly appreciated.

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  • Why the difference in speed?

    - by AngryHacker
    Consider this code: function Foo(ds as OtherDLL.BaseObj) dim lngRowIndex as long dim lngColIndex as long for lngRowIndex = 1 to ubound(ds.Data, 2) for lngColIndex = 1 to ds.Columns.Count Debug.Print ds.Data(lngRowIndex, lngColIndex) next next end function OK, a little context. Parameter ds is of type OtherDLL.BaseObj which is defined in a referenced ActiveX DLL. ds.Data is a variant 2-dimensional array (one dimension carries the data, the other one carries the column index. ds.Columns is a Collection of columns in 'ds.Data`. Assuming there are at least 400 rows of data and 25 columns, this code takes about 15 seconds to run on my machine. Kind of unbelievable. However if I copy the variant array to a local variable, so: function Foo(ds as OtherDLL.BaseObj) dim lngRowIndex as long dim lngColIndex as long dim v as variant v = ds.Data for lngRowIndex = 1 to ubound(v, 2) for lngColIndex = 1 to ds.Columns.Count Debug.Print v(lngRowIndex, lngColIndex) next next end function the entire thing processes in barely any noticeable time (basically close to 0). Why?

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  • Difference in clientX and clientY when going out of the browser on ie/ff

    - by Py
    I just ran into a little problem with clientX and clientY. I put a little event to detect if the mouse goes out of the window and to know where it exits. And there come the trouble, it works fine with firefox, but only sends -1 as an answer in IE. Does someone know if there is a way to solve easily that problem and that without using a framework? A little bit of code to reproduce that: <html> <head> <script type="text/javascript"> document.onmouseout=function(e){ if (!e) var e = window.event; var relTarg = e.relatedTarget || e.toElement; if (!relTarg){ document.getElementById('result1').innerHTML="e.clientY:"+e.clientY+" e.clientX:"+e.clientX; } }; </script> </head> <body> <div id="result1">Not Yet</div> </body> </html> the results if I exit through the left of the window are: e.clientY:302 e.clientX:-130 on firefox e.clientY:-1 e.clientX:-1 on ie. Thanks in advance.

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  • How to change XmlSchemaElement.SchemaType (or: difference between SchemaType and ElementSchemaType)

    - by Gregor
    Hey, I'm working on a XML Editor which gets all his information from the corresponding XSD file. To work with the XSD files I use the System.Xml.Schema Namespace (XmlSchema*). Because of an 'xsi:type' attribute in the XML I've to change the XmlSchemaType of an XmlSchemaElement. Until now I use in my code the 'ElementSchemaType' property of 'XmlSchemaElement'. The nice thing about it: it's read only. There is also in 'XmlSchemaElement' an 'SchemaType' property which is not read only, but always null (yes, XmlSchema and XmlSchemaSet are compiled). So how can I change the type of the 'XmlSchemaElement'? Or, also the same question: What is the diffrence between this two porperties? Some technical data: C#, .NET 3.5 The MSDN documentation is nearly the same for both: SchemaType Documentation: Gets or sets the type of the element. This can either be a complex type or a simple type. ElementSchemaType Documentation: Gets an XmlSchemaType object representing the type of the element based on the SchemaType or SchemaTypeName values of the element.

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  • Difference of two series in MySQL

    - by Brian
    I have a table with the following fields in MySQL: date, Value, Type. Type can be either exports or imports. I want a query that returns the trade deficit (exports-imports) for each month. Is this possible with a single query?

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  • The difference between triangulation and mesh

    - by xiao
    I have done some computer graphical programming recently, and I have no experience before. I used the library call CGAL(computer geometry algorithm library). Also, I noticed that there is class for triangulation and also class for mesh. Is mesh just a kind of triangle net? Do they have any differences? Thanks!

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  • Help Forming An SQL Query That Selects The Max Difference Of Two Fields

    - by Frank
    I'm trying to select a record with the most effective votes. Each record has an id, the number of upvotes (int) and the number of downvotes (int) in a MySQL database. I know basic update, select, insert queries but I'm unsure of how to form a query that looks something like: SELECT * FROM topics WHERE MAX(topic.upvotes - topic.downvotes). Please excuse my made up SQL. The tutorials on SQL I find on the internet cover very basic stuff. Does anyone recommend a good book on this subject?

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  • SQL different joins not making any difference to result

    - by Chrissi
    I'm trying to write a quick (ha!) program to organise some of my financial information. What I ideally want is a query that will return all records with financial information in them from TableA. There should be one row for each month, but in instances where there were no transactions for a month there will be no record. I get results like this: SELECT Period,Year,TotalValue FROM TableA WHERE Year='1997' Result: Period Year TotalValue 1 1997 298.16 2 1997 435.25 4 1997 338.37 8 1997 336.07 9 1997 578.97 11 1997 361.23 By joining on a table (well a View in this instance) which just contains a field Period with values from 1 to 12, I expect to get something like this: SELECT p.Period,a.Year,a.TotalValue FROM Periods AS p LEFT JOIN TableA AS a ON p.Period = a.Period WHERE Year='1997' Result: Period Year TotalValue 1 1997 298.16 2 1997 435.25 3 NULL NULL 4 1997 338.37 5 NULL NULL 6 NULL NULL 7 NULL NULL 8 1997 336.07 9 1997 578.97 10 NULL NULL 11 1997 361.23 12 NULL NULL What I'm actually getting though is the same result no matter how I join it (except CROSS JOIN which goes nuts, but it's really not what I wanted anyway, it was just to see if different joins are even doing anything). LEFT JOIN, RIGHT JOIN, INNER JOIN all fail to provide the NULL records I am expecting. Is there something obvious that I'm doing wrong in the JOIN? Does it matter that I'm joining onto a View?

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  • Difference between Facebook query from iphone and from web

    - by Aashutosh
    Hi, I am creating a iphone application for the existing web application. The fql which is happening at the web is giving me right results but the fql happening at the iphone is not giving all the results. select name, pic_square, pic_big, uid, sex, birthday, relationship_status , current_location, meeting_sex, interests, music, tv, movies, books, quotes, education_history, work_history from user where uid = XXXXXXX is giving me different result in web when compared to the iphone. Thanks, Aashutosh

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  • Java Matcher groups: Understanding The difference between "(?:X|Y)" and "(?:X)|(?:Y)"

    - by user358795
    Can anyone explain: Why the two patterns used below give different results? (answered below) Why the 2nd example gives a group count of 1 but says the start and end of group 1 is -1? public void testGroups() throws Exception { String TEST_STRING = "After Yes is group 1 End"; { Pattern p; Matcher m; String pattern="(?:Yes|No)(.*)End"; p=Pattern.compile(pattern); m=p.matcher(TEST_STRING); boolean f=m.find(); int count=m.groupCount(); int start=m.start(1); int end=m.end(1); System.out.println("Pattern=" + pattern + "\t Found=" + f + " Group count=" + count + " Start of group 1=" + start + " End of group 1=" + end ); } { Pattern p; Matcher m; String pattern="(?:Yes)|(?:No)(.*)End"; p=Pattern.compile(pattern); m=p.matcher(TEST_STRING); boolean f=m.find(); int count=m.groupCount(); int start=m.start(1); int end=m.end(1); System.out.println("Pattern=" + pattern + "\t Found=" + f + " Group count=" + count + " Start of group 1=" + start + " End of group 1=" + end ); } } Which gives the following output: Pattern=(?:Yes|No)(.*)End Found=true Group count=1 Start of group 1=9 End of group 1=21 Pattern=(?:Yes)|(?:No)(.*)End Found=true Group count=1 Start of group 1=-1 End of group 1=-1

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