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  • Exadata???DiskGroup

    - by Liu Maclean(???)
    Exadata???Asm Diskgroup ???????: 1.??dcli -g /home/oracle/cell_group -l root cellcli -e list griddisk ????active?griddisk [root@dm01db01 ~]# dcli -g /home/oracle/cell_group -l root cellcli -e list griddisk dm01cel01: DATA_DM01_CD_00_dm01cel01 active dm01cel01: DATA_DM01_CD_01_dm01cel01 active dm01cel01: DATA_DM01_CD_02_dm01cel01 active dm01cel01: DATA_DM01_CD_03_dm01cel01 active dm01cel01: DATA_DM01_CD_04_dm01cel01 active dm01cel01: DATA_DM01_CD_05_dm01cel01 active dm01cel01: DATA_DM01_CD_06_dm01cel01 active dm01cel01: DATA_DM01_CD_07_dm01cel01 active dm01cel01: DATA_DM01_CD_08_dm01cel01 active dm01cel01: DATA_DM01_CD_09_dm01cel01 active dm01cel01: DATA_DM01_CD_10_dm01cel01 active dm01cel01: DATA_DM01_CD_11_dm01cel01 active dm01cel01: DBFS_DG_CD_02_dm01cel01 active dm01cel01: DBFS_DG_CD_03_dm01cel01 active dm01cel01: DBFS_DG_CD_04_dm01cel01 active dm01cel01: DBFS_DG_CD_05_dm01cel01 active dm01cel01: DBFS_DG_CD_06_dm01cel01 active dm01cel01: DBFS_DG_CD_07_dm01cel01 active dm01cel01: DBFS_DG_CD_08_dm01cel01 active dm01cel01: DBFS_DG_CD_09_dm01cel01 active dm01cel01: DBFS_DG_CD_10_dm01cel01 active dm01cel01: DBFS_DG_CD_11_dm01cel01 active dm01cel01: RECO_DM01_CD_00_dm01cel01 active dm01cel01: RECO_DM01_CD_01_dm01cel01 active dm01cel01: RECO_DM01_CD_02_dm01cel01 active dm01cel01: RECO_DM01_CD_03_dm01cel01 active dm01cel01: RECO_DM01_CD_04_dm01cel01 active dm01cel01: RECO_DM01_CD_05_dm01cel01 active dm01cel01: RECO_DM01_CD_06_dm01cel01 active dm01cel01: RECO_DM01_CD_07_dm01cel01 active dm01cel01: RECO_DM01_CD_08_dm01cel01 active dm01cel01: RECO_DM01_CD_09_dm01cel01 active dm01cel01: RECO_DM01_CD_10_dm01cel01 active dm01cel01: RECO_DM01_CD_11_dm01cel01 active dm01cel02: DATA_DM01_CD_00_dm01cel02 active dm01cel02: DATA_DM01_CD_01_dm01cel02 active dm01cel02: DATA_DM01_CD_02_dm01cel02 active dm01cel02: DATA_DM01_CD_03_dm01cel02 active dm01cel02: DATA_DM01_CD_04_dm01cel02 active dm01cel02: DATA_DM01_CD_05_dm01cel02 active dm01cel02: DATA_DM01_CD_06_dm01cel02 active dm01cel02: DATA_DM01_CD_07_dm01cel02 active dm01cel02: DATA_DM01_CD_08_dm01cel02 active dm01cel02: DATA_DM01_CD_09_dm01cel02 active dm01cel02: DATA_DM01_CD_10_dm01cel02 active dm01cel02: DATA_DM01_CD_11_dm01cel02 active dm01cel02: DBFS_DG_CD_02_dm01cel02 active dm01cel02: DBFS_DG_CD_03_dm01cel02 active dm01cel02: DBFS_DG_CD_04_dm01cel02 active dm01cel02: DBFS_DG_CD_05_dm01cel02 active dm01cel02: DBFS_DG_CD_06_dm01cel02 active dm01cel02: DBFS_DG_CD_07_dm01cel02 active dm01cel02: DBFS_DG_CD_08_dm01cel02 active dm01cel02: DBFS_DG_CD_09_dm01cel02 active dm01cel02: DBFS_DG_CD_10_dm01cel02 active dm01cel02: DBFS_DG_CD_11_dm01cel02 active dm01cel02: RECO_DM01_CD_00_dm01cel02 active dm01cel02: RECO_DM01_CD_01_dm01cel02 active dm01cel02: RECO_DM01_CD_02_dm01cel02 active dm01cel02: RECO_DM01_CD_03_dm01cel02 active dm01cel02: RECO_DM01_CD_04_dm01cel02 active dm01cel02: RECO_DM01_CD_05_dm01cel02 active dm01cel02: RECO_DM01_CD_06_dm01cel02 active dm01cel02: RECO_DM01_CD_07_dm01cel02 active dm01cel02: RECO_DM01_CD_08_dm01cel02 active dm01cel02: RECO_DM01_CD_09_dm01cel02 active dm01cel02: RECO_DM01_CD_10_dm01cel02 active dm01cel02: RECO_DM01_CD_11_dm01cel02 active dm01cel03: DATA_DM01_CD_00_dm01cel03 active dm01cel03: DATA_DM01_CD_01_dm01cel03 active dm01cel03: DATA_DM01_CD_02_dm01cel03 active dm01cel03: DATA_DM01_CD_03_dm01cel03 active dm01cel03: DATA_DM01_CD_04_dm01cel03 active dm01cel03: DATA_DM01_CD_05_dm01cel03 active dm01cel03: DATA_DM01_CD_06_dm01cel03 active dm01cel03: DATA_DM01_CD_07_dm01cel03 active dm01cel03: DATA_DM01_CD_08_dm01cel03 active dm01cel03: DATA_DM01_CD_09_dm01cel03 active dm01cel03: DATA_DM01_CD_10_dm01cel03 active dm01cel03: DATA_DM01_CD_11_dm01cel03 active dm01cel03: DBFS_DG_CD_02_dm01cel03 active dm01cel03: DBFS_DG_CD_03_dm01cel03 active dm01cel03: DBFS_DG_CD_04_dm01cel03 active dm01cel03: DBFS_DG_CD_05_dm01cel03 active dm01cel03: DBFS_DG_CD_06_dm01cel03 active dm01cel03: DBFS_DG_CD_07_dm01cel03 active dm01cel03: DBFS_DG_CD_08_dm01cel03 active dm01cel03: DBFS_DG_CD_09_dm01cel03 active dm01cel03: DBFS_DG_CD_10_dm01cel03 active dm01cel03: DBFS_DG_CD_11_dm01cel03 active dm01cel03: RECO_DM01_CD_00_dm01cel03 active dm01cel03: RECO_DM01_CD_01_dm01cel03 active dm01cel03: RECO_DM01_CD_02_dm01cel03 active dm01cel03: RECO_DM01_CD_03_dm01cel03 active dm01cel03: RECO_DM01_CD_04_dm01cel03 active dm01cel03: RECO_DM01_CD_05_dm01cel03 active dm01cel03: RECO_DM01_CD_06_dm01cel03 active dm01cel03: RECO_DM01_CD_07_dm01cel03 active dm01cel03: RECO_DM01_CD_08_dm01cel03 active dm01cel03: RECO_DM01_CD_09_dm01cel03 active dm01cel03: RECO_DM01_CD_10_dm01cel03 active dm01cel03: RECO_DM01_CD_11_dm01cel03 active ??????????griddisk, ?????’cellcli -e drop griddisk’ ?’cellcli -e create griddisk’????griddisk ,??????drop DBFS_DG???griddisk 2.??ASM???create disk group ?????CELL?IP,????????????? [root@dm01db02 ~]# cat /etc/oracle/cell/network-config/cellip.ora cell="192.168.64.131" cell="192.168.64.132" cell="192.168.64.133" SQL> create diskgroup DATA_MAC normal redundancy 2 DISK 3 'o/192.168.64.131/RECO_DM01_CD_*_dm01cel01' 4 ,'o/192.168.64.132/RECO_DM01_CD_*_dm01cel02' 5 ,'o/192.168.64.133/RECO_DM01_CD_*_dm01cel03' 6 attribute 7 'AU_SIZE'='4M', 8 'CELL.SMART_SCAN_CAPABLE'='TRUE', 9 'compatible.rdbms'='11.2.0.2', 10 'compatible.asm'='11.2.0.2' 11 / 3. MOUNT ???DISKGROUP ALTER DISKGROUP DATA_MAC mount ; 4.???crsctl start/stop resource ora.DATA_MAC.dg ?????

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  • What strategy should be employed to access Facebook data offline?

    - by user686021
    I'm working on a project similar to Klout which provides detail about how you influence other people and who influenced you. We'll be fetching data from few social networking sites (i.e linked in, facebook, twitter etc) to analyze how users interacts with one another. For that we need to parse the data and store it in db and have to analyze it so that strength of relation of two user can be decided. We'll be accessing data offline as well to provide them with accurate results. If we consider facebook activities, we need to have access to Facebook users' news feed, wall data which includes likes,comments,shares etc. To decide how one user influence other, we'll store all the data and analyze it. I need suggestions on what steps need to be taken for great performance. We'll be using ASP.Net(C#) Web forms, SQL Server, jQuery. Main concern is parsing of data, it's storage and retrieval with least overhead. For that I've summarized few points as below : Should we switch over to document-oriented database, like MongoDB or RavenDB for the whole app or part of it even though none of team member have experience with them? Should we use SQL Server Analysis service? Is there any other library than Json.NET for parsing data? Is it advisable to use any C# library over FQL + GET Request ? I've tried to provide as much info as possible. Please share your views for the same.

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  • Cloning from a given point in the snapshot tree

    - by Fat Bloke
    Although we have just released VirtualBox 4.3, this quick blog entry is about a longer standing ability of VirtualBox when it comes to Snapshots and Cloning, and was prompted by a question posed internally, here in Oracle: "Is there a way I can create a new VM from a point in my snapshot tree?". Here's the scenario: Let's say you have your favourite work VM which is Oracle Linux based and as you installed different packages, such as database, middleware, and the apps, you took snapshots at each point like this: But you then need to create a new VM for some other testing or to share with a colleague who will be using the same Linux and Database layers but may want to reconfigure the Middleware tier, and may want to install his own Apps. All you have to do is right click on the snapshot that you're happy with and clone: Give the VM that you are about to create a name, and if you plan to use it on the same host machine as the original VM, it's a good idea to "Reinitialize the MAC address" so there's no clash on the same network: Now choose the Clone type. If you plan to use this new VM on the same host as the original, you can use Linked Cloning else choose Full.  At this point you now have a choice about what to do about your snapshot tree. In our example, we're happy with the Linux and Database layers, but we may want to allow our colleague to change the upper tiers, with the option of reverting back to our known-good state, so we'll retain the snapshot data in the new VM from this point on: The cloning process then chugs along and may take a while if you chose a Full Clone: Finally, the newly cloned VM is ready with the subset of the Snapshot tree that we wanted to retain: Pretty powerful, and very useful.  Cheers, -FB 

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  • What would be the fastest way of storing or calculating legal move sets for chess pieces?

    - by ioSamurai
    For example if a move is attempted I could just loop through a list of legal moves and compare the x,y but I have to write logic to calculate those at least every time the piece is moved. Or, I can store in an array [,] and then check if x and y are not 0 then it is a legal move and then I save the data like this [0][1][0][0] etc etc for each row where 1 is a legal move, but I still have to populate it. I wonder what the fastest way to store and read a legal move on a piece object for calculation. I could use matrix math as well I suppose but I don't know. Basically I want to persist the rules for a given piece so I can assign a piece object a little template of all it's possible moves considering it is starting from it's current location, which should be just one table of data. But is it faster to loop or write LINQ queries or store arrays and matrices? public class Move { public int x; public int y; } public class ChessPiece : Move { private List<Move> possibleMoves { get; set; } public bool LegalMove(int x, int y){ foreach(var p in possibleMoves) { if(p.x == x && p.y == y) { return true; } } } } Anyone know?

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  • HTML Manifest for Content Folios

    - by Kyle Hatlestad
    I recently worked on a project to create a custom content folio renderer in WebCenter Content. It needed to output the native files in the folio along with a manifest file in HTML format which would list the contents of the folio along with any designated metadata and a relative link to the file within the download.  This way a person could hand someone the folio download and it would be a self-contained package with all of the content and a single file to display the information on the contents.  The default Zip rendition of the folio will output the web-viewable version of the file with an HDA formatted file for each one. And unless you are fluent in HDA or have a tool to read them, they are difficult to consume. I thought this might be useful for others, so I'm posting a copy of the component here. Beyond the standard instructions for installing a component, there is an environment configuration file (folionativezipwithmanifestrenderer_environment.cfg) which has a couple of options. FolioMetadataManifestList - This is a comma separated list of metadata fields (system or custom) that should be included in the manifest file. FolioMetadataManifestUseOriginalFilename - (True or False) If set to True, the filenames in the zip file will be based on the original filename as it was checked into WebCenter Content.  If False, it will use the 'Name' of the item as defined within the Folio.  This is usually the Title of the item. The component also includes the source code, so feel free to use this as a reference for creating other interesting folios. 

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  • OBIEE 10g premier support ends Mid 2013

    - by THE
    To give all OBIEE users a fair warning ahead of time. Please be aware that the Premier Support product lifecycle for Oracle Business Intelligence Enterprise Edition and Oracle Business Intelligence Publisher 10.1.3.4.x is ending in July 2013 as of the  lifetime Support policy. Oracle Business Intelligence Enterprise Edition and Oracle Business Intelligence Publisher 10.1.3.4.x will be in Sustaining Support phase. "Sustaining Support" does NOT include: New program updates, fixes, security alerts, and critical patch updates New tax, legal and regulatory updates New upgrade scripts Certification with new third party products/versions 24 hour commitment and response guidelines for Severity 1 service requests as defined in the Severity Level section in the Oracle Technical Support Policies document linked below. We are encouraging you to move to OBIEE 11gR1. For more details please see the following documents on My Oracle Support ( https://support.oracle.com):"Premier Support Ends Dec 31 2011 for Oracle Fusion Middleware 10g 10.1.2 & 10.1.4" (  Doc ID 1290974.1)

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  • Efficient Algorithm for Recording gameplay's objects positions

    - by Scorch
    So, I have a game idea in mind, and for that I need to record the game around the player. I'me not talking about recording it as video, but rather recording the scene objects, and their positions within the game, and then render them, giving the player the ability to go back and forth, to stop time and move around. I've made a prototype with some data structures in C#, since this is going to be the programming language we'll be using in our game, but if we want the player to be able to go back just five minutes back with the data of just 100 NPC's, it takes almost 1GB of RAM. Right now, I'm just storing a Doubly linked list, each item with the object position. In the game, I'll need to store even more data in each node, so I need something even more ligher. Of course, this algorithm is zero optimized, but still, that is a lot. The alternatives would be create the NPC's that aren't really important to the game when the user is viewing the past, but I don't really like it very much for the sake of realism. I wonder if there is a better way to store this? Thanks in advance, Scorch

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  • Most efficient way to store this collection of moduli and remainders?

    - by Bryan
    I have a huge collection of different moduli and associated with each modulus a fairly large list of remainders. I want to store these values so that I can efficiently determine whether an integer is equivalent to any one of the remainders with respect to any of the moduli (it doesn't matter which, I just want a true/false return). I thought about storing these values as a linked-list of balanced binary trees, but I was wondering if there is a better way? EDIT Perhaps a little more detail would be helpful. As for the size of this structure, it will be holding about 10s of thousands of (prime-1) moduli and associated to each modulus will be a variable amount of remainders. Most moduli will only have one or two remainders associated to it, but a very rare few will have a couple hundred associated to it. This is part of a larger program which handles numbers with a couple thousand (decimal) digits. This program will benefit more from this table being as large as possible and being able to be searched quickly. Here's a small part of the dataset where the moduli are in parentheses and the remainders are comma separated: (46) k = 20 (58) k = 15, 44 (70) k = 57 (102) k = 36, 87 (106) k = 66 (156) k = 20, 59, 98, 137 (190) k = 11, 30, 68, 87, 125, 144, 182 (430) k = 234 (520) k = 152, 282 (576) k = 2, 11, 20, 29, 38, 47, 56, 65, 74, ...(add 9 each time), 569 I had said that the moduli were prime, but I was wrong they are each one below a prime.

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  • Role based access to resources for a RESTful service

    - by mutex
    I'm still wrapping my head around REST, but I wonder if someone can help with any suggestions or approaches to role based access control for a RESTful service, particularly from the point of view of securing the data and how the URLs might look. It's probably best to consider an example: Say I have a REST service for Customers, and want to split the users of this REST service into Admin, Editor and Reader roles: Admins can change all attributes of a Customer resource Editors can change only some Readers can only view them. Access control rights are assigned to the Customers entities individually. So for example a user of the service might have admin rights to Customers 1,2 and 3 but Editor access to 4,5 and Reader access to 7,8,9. Now consider the user calling the service. What is a good way to seperate the list of Customers for the current User? GET /Customer - this might get a list of all customers that the current user has Admin\Editor\Reader access to. But then on each Customer the consumer would need an indication of what role they have. Or would it be "better" having something like GET /Customer/Admin - return all customers the current user has Admin access to. Just looking for some high level pointers or reading on a decent way to secure\filter the resources based on roles of the current user.

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  • Storing large array of tiles, but allowing easy access to data

    - by Cyral
    I've been thinking about this for a while. I have a 2D tile bases platformer in XNA with a large array of tile data, I've been running into memory problems with large maps. (I will add chunks soon!) Currently, Each tile contains an Item along with other properties like how its rotated, if it has forground / background, etc. An Item is static and has properties like the name, tooltip, type of item, how much light it emits, the collision it does to player, etc. Examples: public class Item { public static List<Item> Items; public Collision blockCollisionType; public string nameOfItem; public bool someOtherVariable,etc,etc public static Item Air public static Item Stone; public static Item Dirt; static Item() { Items = new List<Item>() { (Stone = new Item() { nameOfItem = "Stone", blockCollisionType = Collision.Solid, }), (Air = new Item() { nameOfItem = "Air", blockCollisionType = Collision.Passable, }), }; } } Would be an Item, The array of Tiles would contain a Tile for each point, public class Tile { public Item item; //What type it is public bool onBackground; public int someOtherVariables,etc,etc } Now, Most would probably use an enum, or a form of ID to identify blocks. Well my system is really nice just to find out about an item. I can simply do tiles[x,y].item.Name To get the name for example. I realized my Item property of the tile is over 1000 Bytes! Wow! What I'm looking for is a way to use an ID (Int or byte depending on how many items) instead of an Item but still have a method for retreiving data about the type of item a tile contains.

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  • Euler Problem 13

    - by MarkPearl
    The Problem Work out the first ten digits of the sum of the following one-hundred 50-digit numbers. 37107287533902102798797998220837590246510135740250 46376937677490009712648124896970078050417018260538 74324986199524741059474233309513058123726617309629 91942213363574161572522430563301811072406154908250 23067588207539346171171980310421047513778063246676 89261670696623633820136378418383684178734361726757 28112879812849979408065481931592621691275889832738 44274228917432520321923589422876796487670272189318 47451445736001306439091167216856844588711603153276 70386486105843025439939619828917593665686757934951 62176457141856560629502157223196586755079324193331 64906352462741904929101432445813822663347944758178 92575867718337217661963751590579239728245598838407 58203565325359399008402633568948830189458628227828 80181199384826282014278194139940567587151170094390 35398664372827112653829987240784473053190104293586 86515506006295864861532075273371959191420517255829 71693888707715466499115593487603532921714970056938 54370070576826684624621495650076471787294438377604 53282654108756828443191190634694037855217779295145 36123272525000296071075082563815656710885258350721 45876576172410976447339110607218265236877223636045 17423706905851860660448207621209813287860733969412 81142660418086830619328460811191061556940512689692 51934325451728388641918047049293215058642563049483 62467221648435076201727918039944693004732956340691 15732444386908125794514089057706229429197107928209 55037687525678773091862540744969844508330393682126 18336384825330154686196124348767681297534375946515 80386287592878490201521685554828717201219257766954 78182833757993103614740356856449095527097864797581 16726320100436897842553539920931837441497806860984 48403098129077791799088218795327364475675590848030 87086987551392711854517078544161852424320693150332 59959406895756536782107074926966537676326235447210 69793950679652694742597709739166693763042633987085 41052684708299085211399427365734116182760315001271 65378607361501080857009149939512557028198746004375 35829035317434717326932123578154982629742552737307 94953759765105305946966067683156574377167401875275 88902802571733229619176668713819931811048770190271 25267680276078003013678680992525463401061632866526 36270218540497705585629946580636237993140746255962 24074486908231174977792365466257246923322810917141 91430288197103288597806669760892938638285025333403 34413065578016127815921815005561868836468420090470 23053081172816430487623791969842487255036638784583 11487696932154902810424020138335124462181441773470 63783299490636259666498587618221225225512486764533 67720186971698544312419572409913959008952310058822 95548255300263520781532296796249481641953868218774 76085327132285723110424803456124867697064507995236 37774242535411291684276865538926205024910326572967 23701913275725675285653248258265463092207058596522 29798860272258331913126375147341994889534765745501 18495701454879288984856827726077713721403798879715 38298203783031473527721580348144513491373226651381 34829543829199918180278916522431027392251122869539 40957953066405232632538044100059654939159879593635 29746152185502371307642255121183693803580388584903 41698116222072977186158236678424689157993532961922 62467957194401269043877107275048102390895523597457 23189706772547915061505504953922979530901129967519 86188088225875314529584099251203829009407770775672 11306739708304724483816533873502340845647058077308 82959174767140363198008187129011875491310547126581 97623331044818386269515456334926366572897563400500 42846280183517070527831839425882145521227251250327 55121603546981200581762165212827652751691296897789 32238195734329339946437501907836945765883352399886 75506164965184775180738168837861091527357929701337 62177842752192623401942399639168044983993173312731 32924185707147349566916674687634660915035914677504 99518671430235219628894890102423325116913619626622 73267460800591547471830798392868535206946944540724 76841822524674417161514036427982273348055556214818 97142617910342598647204516893989422179826088076852 87783646182799346313767754307809363333018982642090 10848802521674670883215120185883543223812876952786 71329612474782464538636993009049310363619763878039 62184073572399794223406235393808339651327408011116 66627891981488087797941876876144230030984490851411 60661826293682836764744779239180335110989069790714 85786944089552990653640447425576083659976645795096 66024396409905389607120198219976047599490197230297 64913982680032973156037120041377903785566085089252 16730939319872750275468906903707539413042652315011 94809377245048795150954100921645863754710598436791 78639167021187492431995700641917969777599028300699 15368713711936614952811305876380278410754449733078 40789923115535562561142322423255033685442488917353 44889911501440648020369068063960672322193204149535 41503128880339536053299340368006977710650566631954 81234880673210146739058568557934581403627822703280 82616570773948327592232845941706525094512325230608 22918802058777319719839450180888072429661980811197 77158542502016545090413245809786882778948721859617 72107838435069186155435662884062257473692284509516 20849603980134001723930671666823555245252804609722 53503534226472524250874054075591789781264330331690   The Solution private static List<string> table = new List<string> { "37107287533902102798797998220837590246510135740250", "46376937677490009712648124896970078050417018260538", "74324986199524741059474233309513058123726617309629", "91942213363574161572522430563301811072406154908250", "23067588207539346171171980310421047513778063246676", "89261670696623633820136378418383684178734361726757", "28112879812849979408065481931592621691275889832738", "44274228917432520321923589422876796487670272189318", "47451445736001306439091167216856844588711603153276", "70386486105843025439939619828917593665686757934951", "62176457141856560629502157223196586755079324193331", "64906352462741904929101432445813822663347944758178", "92575867718337217661963751590579239728245598838407", "58203565325359399008402633568948830189458628227828", "80181199384826282014278194139940567587151170094390", "35398664372827112653829987240784473053190104293586", "86515506006295864861532075273371959191420517255829", "71693888707715466499115593487603532921714970056938", "54370070576826684624621495650076471787294438377604", "53282654108756828443191190634694037855217779295145", "36123272525000296071075082563815656710885258350721", "45876576172410976447339110607218265236877223636045", "17423706905851860660448207621209813287860733969412", "81142660418086830619328460811191061556940512689692", "51934325451728388641918047049293215058642563049483", "62467221648435076201727918039944693004732956340691", "15732444386908125794514089057706229429197107928209", "55037687525678773091862540744969844508330393682126", "18336384825330154686196124348767681297534375946515", "80386287592878490201521685554828717201219257766954", "78182833757993103614740356856449095527097864797581", "16726320100436897842553539920931837441497806860984", "48403098129077791799088218795327364475675590848030", "87086987551392711854517078544161852424320693150332", "59959406895756536782107074926966537676326235447210", "69793950679652694742597709739166693763042633987085", "41052684708299085211399427365734116182760315001271", "65378607361501080857009149939512557028198746004375", "35829035317434717326932123578154982629742552737307", "94953759765105305946966067683156574377167401875275", "88902802571733229619176668713819931811048770190271", "25267680276078003013678680992525463401061632866526", "36270218540497705585629946580636237993140746255962", "24074486908231174977792365466257246923322810917141", "91430288197103288597806669760892938638285025333403", "34413065578016127815921815005561868836468420090470", "23053081172816430487623791969842487255036638784583", "11487696932154902810424020138335124462181441773470", "63783299490636259666498587618221225225512486764533", "67720186971698544312419572409913959008952310058822", "95548255300263520781532296796249481641953868218774", "76085327132285723110424803456124867697064507995236", "37774242535411291684276865538926205024910326572967", "23701913275725675285653248258265463092207058596522", "29798860272258331913126375147341994889534765745501", "18495701454879288984856827726077713721403798879715", "38298203783031473527721580348144513491373226651381", "34829543829199918180278916522431027392251122869539", "40957953066405232632538044100059654939159879593635", "29746152185502371307642255121183693803580388584903", "41698116222072977186158236678424689157993532961922", "62467957194401269043877107275048102390895523597457", "23189706772547915061505504953922979530901129967519", "86188088225875314529584099251203829009407770775672", "11306739708304724483816533873502340845647058077308", "82959174767140363198008187129011875491310547126581", "97623331044818386269515456334926366572897563400500", "42846280183517070527831839425882145521227251250327", "55121603546981200581762165212827652751691296897789", "32238195734329339946437501907836945765883352399886", "75506164965184775180738168837861091527357929701337", "62177842752192623401942399639168044983993173312731", "32924185707147349566916674687634660915035914677504", "99518671430235219628894890102423325116913619626622", "73267460800591547471830798392868535206946944540724", "76841822524674417161514036427982273348055556214818", "97142617910342598647204516893989422179826088076852", "87783646182799346313767754307809363333018982642090", "10848802521674670883215120185883543223812876952786", "71329612474782464538636993009049310363619763878039", "62184073572399794223406235393808339651327408011116", "66627891981488087797941876876144230030984490851411", "60661826293682836764744779239180335110989069790714", "85786944089552990653640447425576083659976645795096", "66024396409905389607120198219976047599490197230297", "64913982680032973156037120041377903785566085089252", "16730939319872750275468906903707539413042652315011", "94809377245048795150954100921645863754710598436791", "78639167021187492431995700641917969777599028300699", "15368713711936614952811305876380278410754449733078", "40789923115535562561142322423255033685442488917353", "44889911501440648020369068063960672322193204149535", "41503128880339536053299340368006977710650566631954", "81234880673210146739058568557934581403627822703280", "82616570773948327592232845941706525094512325230608", "22918802058777319719839450180888072429661980811197", "77158542502016545090413245809786882778948721859617", "72107838435069186155435662884062257473692284509516", "20849603980134001723930671666823555245252804609722", "53503534226472524250874054075591789781264330331690"}; static void Main(string[] args) { BigInteger result = 0; table.ForEach(x => result += BigInteger.Parse(x)); Console.WriteLine(result.ToString().Substring(0,10)); Console.ReadLine(); }

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  • Best practice- handling images on website

    - by Steve
    I am porting an old eCommerce site to MVC 3 and would like to take advantage of design improvements. The site currently has product images stored in 3 sizes: thumbnail, medium (for display in a list) and expanded for a zoomed look. Right now we are having to upload 3 separate images that are sized exactly right, provide 3 different names that match what the site expects, etc., it is a pain. I'd like to upload just 1 file, the large one, then let the site reduce it to needed sizes, and I'd like the flexibility to change the thumbnail and list sizes depending on user preferences, form factor (e.g. mobile, iPad, desktop), etc. so might need many copies of the same image. My question is should the image be reduced then saved several times upon upload and if so what is a good storage/naming convention? The other idea is to store just the single image but resize it programmatically before serving it to the client. Has anybody done this and what are the tradeoffs besides a few more machine cycles? How do you pass a temporary image in memory to the client (there is no URL)?

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  • Update-manager fails silently on 14.04

    - by pabuisson
    I recently reinstalled a lubuntu from scratch, to upgrade to 14.04. Everything's working as expected, except for the update-manager that silently fails when trying to upgrade my system's packages. It does correctly list the packages to be upgraded, I can then click on the "Install now" button (or something like this, I'm running a French flavour of Ubuntu). When I click the button, it seems unresponsive for 5 to 10 seconds, then the upgrade dialog with the progress bar appears, displays "Loading package list", then very shortly something about "authentication" (not long enough so that I can read it).. and closes. The install is fresh and I have no idea where to look. I tried launching update-manager in a term but it doesn't display any error when it fails, only this message when the window first shows up : ** (update-manager:3642): WARNING **: Couldn't connect to accessibility bus: Failed to connect to socket /tmp/dbus-m0jkFlZ3yo: Connexion refusée. Any idea where this might come from ? I can upgrade the packages using the command line and sudo apt-get but this is not my computer, and I do not wish its owner to have to do this to upgrade the packages. Thanks for your help !

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  • Can I share data between two users in an ASP.NET Application?

    - by Dave
    I have an issue with Roles.IsUserInRole function. It take hell amount of time to just check if the logged-in user is in particular role(typ 3-9 sec). I searched to find a solution and arrived on this but I am not sure If I have fully grasped it. What I got from the above, A new derived class is created. Inside that class, there is a list which retrieves all user at once. The next time you check IsUserInRole, you do not use the actual IsUserInRole method but rather use the one you overrode in your class. Is this the correct description? Am I on track? My question is, can data be share between two different users in ASP.NET application? If yes, will the shared data exist only if there is at least one user logged in. If all users logs out, that shared data is destroyed? My point is this data will be created only one time whenever a user logs in. For all subsequent users they can use this data and check their roles against the list? I need a detailed answer. My application has users and different roles. We are using ASP.NET roles.

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  • How to embed woff fonts for iframe source pages?

    - by Mon
    I am trying to make and embed a slideshow (of text, photo, audio, video, etc) in my site (HTML5) by loading webpages consecutively inside an iframe embedded in my first page. Most or all of the frame source pages, i.e. pages loaded inside first iframe are mine, but located in many different places. All of these pages are in an Indic language. Although I can use UTF-8 charset and lang="" declaration and that's probably enough functionally, but I also want to embed my preferred Indic unicode font in WOFF format via CSS3 @font-face rule , so the size and look of the text is uniform and the way I want it - throughout the slideshow. Problem is, there are many many pages in the slideshow all located in various places with many more linked pages, and it is next to impossible, or at least would be extremely tedious, to embed my custom WOFF font in every single page (which will also require separate css and uploading of fonts in every single instance). Besides, this may make the slideshow very heavy, sluggish and cumbersome for the user, since it will have to load the custom Indic font again and again everytime a new page is loaded in the iframe. I am not sure about this though. Is that how it works? I ask this, because I noticed that when I embedded my custom WOFF font in the 'first' page, it did not have any effect on the pages loaded inside the iframe. If I embed the font in some of the pages in the iframe, the next pages still don't get my font. Is there a way to embed my custom WOFF font only once, preferably in the first page where the first iframe is, and pass its effect on to all the pages embedded / loaded through the iframe and make their text show up as per my initially embedded woff font - without embedding my font in every single of them? Please help!

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  • How should a team share/store game content during development?

    - by irwinb
    Other than Dropbox, what out there has been especially useful for storing and sharing game content like images during development (similar feature set to Dropbox like working offline, automatic syncing and support for windows/osx)? We are looking into hosting our own SharePoint server but it seems to be really focused on documents... Maybe Box.net would work? EDIT For code, we are using Git. To be more precise, I was looking for an easy, automatic way for content produced by artists/audio engineers to be available to everyone. Features like approvals of assets don't hurt either. Following the answer linked by Tetrad, Alienbrain looked pretty interesting but..is way out of our budget (may be something to invest in in the future). What ended up doing... We were going to go with Box.net but downloading the sync apps for desktop use required us to wait to be contacted by them for some reason. We did not have much time to wait so we ended up going with Dropbox Teams. Box.net has a nice feature set but we never really felt held back without them. Thanks for the help :).

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  • What's the best way to handle numerous recurring log entries in game loop?

    - by Kaa
    I have a custom logging system, use of which is scattered all over the engine and game. The system is linked to a "LogStore" that has an std::vector<string> logs[NUM_LOG_TYPES] - each vector corresponds with it's log type (info, error, debug, etc.). There's one extra std::vector that has "coordinates" to all log entries in the order they were received. Now, all the logging output is also displayed inside my development console in the game. The game console is handled by HTML-type GUI and therefore requires a new <p> element being added for each log output. My problem is that the log entries that are generated in the main loop each frame freeze the engine, because they continue to add elements to the in-game console, and if the console or guy generates a warning - that creates an infinite logging loop. I want to solve it by handling the recurring log entries in an elegant way that lets you know that something is critically wrong, but won't freeze the engine - like displaying the count of errors in the last 60 frames instead of displaying errors themselves. But how do you guys handle this? Does anyone know any nifty tricks to do this? I understand the question may sound vague, but if someone came across this type of issue I'm sure they would know exactly what's happening. Example problematic log entries: OpenGL warnings (I actually do check for errors every frame in many places) Really any prints anywhere in the main loop (may be debugging, may be warnings)

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  • Is this too much to ask for a game programming and developing enthusiast? Am I doing this wrong?

    - by I_Question_Things_Deeply
    I have been a computer-fanatic for almost a decade now. I've always loved and wondered how computers work, even from the purest, lowest hardware level to the very smallest pixel on the screen, and all the software around that. That seems to be my problem though ... as I try to write code (I'm pretty fluent at C++) I always sit there enormous amounts of time in front of a text-editor wondering how every line, statement, datum, function, etc. will correspond to every Assembly and machine instruction performed to do absolutely everything necessary for the kernel to allocate memory to run my compiled program, and all of the other hardware being used as well. For example ... I would write cout << "Before memory changed" << endl; and run the debugger to get the Assembly for this, and then try and reverse disassemble the Assembly to machine code based on my ISA, and then research every .dll, library file, linked library, linking process, linker source code of the program, the make file, the kernel I'm using's steps of processing this compilation, the hardware's part aside from the processor (e.g. video card, sound card, chipset, cache latency, byte-sized registers, calling convention use, DDR3 RAM and disk drive, filesystem functioning and so many other things). Am I going about programming wrong? I mean I feel I should know everything that goes on underneath English syntax on a computer program. But the problem is that the more I research every little thing the less I actually accomplish at all. I can never finish anything because of this mentality, yet I feel compelled to know everything... what should I do?

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  • knowing all available entity types

    - by plofplof
    I'm making a game where at some point the game will create enemies of random types. Each type of enemy available is defined on its own class derived from an enemy superclass. To do this, obviously the different types of enemies should be known. This is what I have thought of: Just make a list manually. Very simple to do, but I don't like it because I'll be adding more enemy types over time, so any time I add a new class I have to remember to update this (same if I remove an enemy). I would like some kind of auto-updating list. A completely component based system. There are no different classes for each enemy, but definitions of enemies in some file where all enemy types can be found. I really don't need that level of complexity for my game. I'm still using a component based model to some degree, but each Enemy type gets defined on its own class. Java Annotation processing. Give each enemy subclass an annotation like @EnemyType("whatever"), then code an annotation processor that writes in a file all available enemy types. Any time a new class is added the file gets updated after compilation.This gives me a feeling of failure even if its a good solution, it's very dependant on Java, so it means I cant think of a general design good for any kind of language. Also I think that this would be too much work for something so simple. I would like to see comments on these ideas and other possible solutions Thanks

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  • When and how does one become a good programmer these days? [closed]

    - by YoungMoney
    I mean, good enough to make software people want and get paid for it. Maybe even good enough to launch a company or something. I'm also concerned that I'm not applying the finer points of my algorithms/data structures/software design knowledge. Background: I'm 20 and have been struggling with programming for about two years now, trying to become a software engineer. I started with a few university courses that I did quite poorly in. I learned how to make websites with HTML/JavaScript and PHP/MySQL, but feel like I know very relevant theory for making good databases - how does something like Facebook serve hundreds of millions of people? What would be smart ways to store data? I don't know. Now I'm doing some android application development, but again I have no idea about good Java design theory (I use static variables like they're going out of fashion) and feel more like I'm gluing stuff together and letting Eclipse slowly autocomplete my project. In short, I'm not sure if I'm becoming a legitimate software developer or just "doing what's cool". At least I've taken some data structures and Algorithms courses and plan to take more in the next years. But I'm having a really tough time applying this stuff to my fun little apps that I'm building. Every language higher level than C++ seems to have its own quicksort function already built-in, for example. Similarly, I can't remember ever needing to implement a linked-list, heap, binary tree, or or worry about pointers and memory management. But maybe this is a good thing so that I focus on other things? I'm not too sure what those other things are though. Hopefully something more than building another photo sharing app. Anyways that's it for me, I look forward to your responses!

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  • Requiring a specific order of compilaiton

    - by Aber Kled
    When designing a compiled programming language, is it a bad idea to require a specific order of compilation of separate units, according to their dependencies? To illustrate what I mean, consider C. C is the opposite of what I'm suggesting. There are multiple .c files, that can all depend on each other, but all of these separate units can be compiled on their own, in no particular order - only to be linked together into a final executable later. This is mostly due to header files. They enable separate units to share information with each other, and thus the units are able to be compiled independently. If a language were to dispose of header files, and only keep source and object files, then the only option would be to actually include the unit's meta-information in the unit's object file. However, this would mean that if the unit A depends on the unit B, then the unit B would need to be compiled before unit A, so unit A could "import" the unit B's object file, thus obtaining the information required for its compilation. Am I missing something here? Is this really the only way to go about removing header files in compiled languages?

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  • Trouble installing Ubuntu.

    - by CV13
    I have a blank 1TB hard drive that I have run ubuntu on before. I recently formatted it and am trying to reinstall Ubuntu 12.04 LTS on there. Using the Universal USB installer and the 64-bit iso file, I booted up my computer with only my 1TB hard drive connected. I go through the installation process normally, until I restart my computer at the end. Once restarted, I start to experience the problem deal with here. When I run it normally, it goes to a black screen with a blinking cursor. When I select the "Recovery Mode" option, a bunch of lines scroll across the screen, the last of which is "hostap_pci: Registered netdevice wifi0". It then stops there with a blinking cursor. When I follow the instructions on the page I linked to (replacing "quiet splash" with "nomodeset") and bunch of lines scroll through after I press Ctrl+x. The last line displayed is Adding 8386556k swap on /dev/sda5. Priority:-1 extents:1 across: 8386556k It then stops there with a blinking cursor. How do I fix this problem?

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  • How should I implement multiple threads in a game? [duplicate]

    - by xerwin
    This question already has an answer here: Multi-threaded games best practices. One thread for 'logic', one for rendering, or more? 6 answers So I recently started learning Java, and having a interest in playing games as well as developing them, naturally I want to create game in Java. I have experience with games in C# and C++ but all of them were single-threaded simple games. But now, I learned how easy it is to make threads in Java, I want to take things to the next level. I started thinking about how would I actually implement threading in a game. I read couple of articles that say the same thing "Usually you have thread for rendering, for updating game logic, for AI, ..." but I haven't (or didn't look hard enough) found example of implementation. My idea how to make implementation is something like this (example for AI) public class AIThread implements Runnable{ private List<AI> ai; private Player player; /*...*/ public void run() { for (int i = 0; i < ai.size(); i++){ ai.get(i).update(player); } Thread.sleep(/* sleep until the next game "tick" */); } } I think this could work. If I also had a rendering and updating thread list of AI in both those threads, since I need to draw the AI and I need to calculate the logic between player and AI(But that could be moved to AIThread, but as an example) . Coming from C++ I'm used to do thing elegantly and efficiently, and this seems like neither of those. So what would be the correct way to handle this? Should I just keep multiple copies of resources in each thread or should I have the resources on one spot, declared with synchronized keyword? I'm afraid that could cause deadlocks, but I'm not yet qualified enough to know when a code will produce deadlock.

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  • How to avoid tons of `instanceof` in collision detection?

    - by Prog
    Consider a simple game with 4 kinds of entities: Robots, Dogs, Missiles, Walls. Here's a simple collision-detection mechanism in psuedocode: (I know, O(n^2). Irrelevant for this question). for(Entity entityA in entities){ for(Entity entityB in entities){ if(collision(entityA, entityB)){ if(entityA instanceof Robot && entityB instanceof Dog) entityB.die(); if(entityA instanceof Robot && entityB instanceof Missile){ entityA.die(); entityB.die(); } if(entityA instanceof Missile && entityB instanceof Wall) entityB.die(); // .. and so on } } } Obviously this is very ugly, and will get bigger and harder to maintain the more entities there are, and the more conditions there are. One option to make this better is to have separate lists for each kind of entity. For example a Robots list, a Dogs list etc. And than check for collisions of all Robots with Dogs, and all Dogs with Walls, etc. This is better, but I still don't think it's good. So my question is: The collision detection system spotted a collision. Now what? What is the common way to react to the collision? Should the system notify the entity itself that it collided with something, and have it decide for itself how to react? E.g. entityA.reactToCollision(entityB). Or is there some other solution?

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  • C programming multiple storage backends

    - by ahjmorton
    I am starting a side project in C which requires multiple storage backends to be driven by a particular piece of logic. These storage backends would each be linked with the decision of which one to use specified at runtime. So for example if I invoke my program with one set of parameters it will perform the operations in memory but if I change the program configuration it would write to disk. The underlying idea is that each storage backend should implement the same protocol. In other words the logic for performing operations should need to know which backend it is operating on. Currently the way I have thought to provide this indirection is to have a struct of function pointers with the logic calling these function pointers. Essentially the struct would contain all the operations needed to implement the higher level logic E.g. struct Context { void (* doPartOfDoOp)(void) int (* getResult)(void); } //logic.h void doOp(Context * context) { //bunch of stuff context->doPartOfDoOp(); } int getResult(Context * context) { //bunch of stuff return context->getResult(); } My questions is if this way of solving the problem is one a C programmer would understand? I am a Java developer by trade but enjoy using C/++. Essentially the Context struct provides an interface like level of indirection. However I would like to know if there is a more idiomatic way of achieving this.

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