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  • Fatal error: Call to a member function item() on a non-object

    - by Andree
    Hi there! I have a weird problem. I have a PHP class with the following method: public function __construct() { parent::__construct(); $this->CI =& get_instance(); $this->log(method_exists($this->CI->config, 'item')); // Outputs TRUE $firephp_enabled = $this->CI->config->item('firephp_enabled'); // Error point $this->setEnabled($firephp_enabled); } $this->CI->config has a method item, and it has been verified using method_exists(). But when I call $this->CI->config->item(), I got the following error: Fatal error: Call to a member function item() on a non-object Can anyone tell me what might be the problem here? Thanks, Andree.

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  • BadAlloc X Error

    - by paultop6
    Hi Guys, Im having some problems with a GTK program im trying to build. When i compile it i keep getting this error: This probably reflects a bug in the program. The error was 'BadAlloc (insufficient resources for operation)'. (Details: serial 195 error_code 11 request_code 53 minor_code 0) Ive traced it down to the following command that appears to be causing it: gtk_box_pack_start(GTK_BOX (Top_Graph), Widget_Get (Graph_Cpu), TRUE, TRUE, 0); Now Top_Graph and Graph_Cpu are both GtkVbox Widgets. Has anyone ever seen an error like this, and could they give me some advice as to how it is caused Regards Paul

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  • How to find the latest row for each group of data

    - by Jason
    Hi All, I have a tricky problem that I'm trying to find the most effective method to solve. Here's a simplified version of my View structure. Table: Audits AuditID | PublicationID | AuditEndDate | AuditStartDate 1 | 3 | 13/05/2010 | 01/01/2010 2 | 1 | 31/12/2009 | 01/10/2009 3 | 3 | 31/03/2010 | 01/01/2010 4 | 3 | 31/12/2009 | 01/10/2009 5 | 2 | 31/03/2010 | 01/01/2010 6 | 2 | 31/12/2009 | 01/10/2009 7 | 1 | 30/09/2009 | 01/01/2009 There's 3 query's that I need from this. I need to one to get all the data. The next to get only the history data (that is, everything but exclude the latest data item by AuditEndDate) and then the last query is to obtain the latest data item (by AuditEndDate). There's an added layer of complexity that I have a date restriction (This is on a per user/group basis) where certain user groups can only see between certain dates. You'll notice this in the where clause as AuditEndDate<=blah and AuditStartDate=blah Foreach publication, select all the data available. select * from Audits Where auditEndDate<='31/03/10' and AuditStartDate='06/06/2009'; foreach publication, select all the data but Exclude the latest data available (by AuditEndDate) select * from Audits left join (select AuditId as aid, publicationID as pid and max(auditEndDate) as pend from Audit where auditenddate <= '31/03/2009' /* user restrict / group by pid) Ax on Ax.pid=Audit.pubid where pend!=Audits.auditenddate AND auditEndDate<='31/03/10' and AuditStartDate='06/06/2009' / user restrict */ Foreach publication, select only the latest data available (by AuditEndDate) select * from Audits left join (select AuditId as aid, publicationID as pid and max(auditEndDate) as pend from Audit where auditenddate <= '31/03/2009'/* user restrict / group by pid) Ax on Ax.pid=Audit.pubid where pend=Audits.auditenddate AND auditEndDate<='31/03/10' and AuditStartDate='06/06/2009' / user restrict */ So at the moment, query 1 and 3 work fine, but query 2 just returns all the data instead of the restriction. Can anyone help me? Thanks jason

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  • SQL Count Query with Grouping by multiple Rows

    - by Christian
    I have a table with three filled rows named "Name", "City" and "Occupation". I want to create a new row in the same table that contains the number of people who have the same occupation. "Name" | "City" | "Occupation" ------------------------------ Amy | Berlin | Plumber Bob | Berlin | Plumber Carol | Berlin | Lawyer David | London | Plumber I want to have a table that contains: "Name" | "City" | "Occupation" | "Number" --------------------------------------- Amy | Berlin | Plumber | 2 Bob | Berlin | Plumber | 2 Carol | Berlin | Lawyer | 1 David | London | Plumber | 1 How does the SQL Query that creates the new row have to look like? I want to actually create a new row in the database that I can access later.

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  • Checking inherited attributes in an 'ancestry' based SQL table

    - by Brendon Muir
    I'm using the ancestry gem to help organise my app's tree structure in the database. It basically writes a childs ancestor information to a special column called 'ancestry'. The ancestry column for a particular child might look like '1/34/87' where the parent of this child is 87, and then 87's parent is 34 and 34's is 1. It seems possible that we could select rows from this table each with a subquery that checks all the ancestors to see if a certain attribute it set. E.g. in my app you can hide an item and its children just by setting the parent element's visibility column to 0. I want to be able to find all the items where none of their ancestors are hidden. I tried converting the slashes to comma's with the REPLACE command but IN required a set of comma separated integers rather than one string with comma separated string numbers. It's funny, because I can do this query in two steps, e.g. retrieve the row, then take its ancestry column, split out the id's and make another query that checks that the id is IN that set of id's and that visibility isn't ever 0 and whala! But joining these into one query seems to be quite a task. Much searching has shown a few answers but none really do what I want. SELECT * FROM t1 WHERE id = 99; 99's ancestry column reads '1/34/87' SELECT * FROM t1 WHERE visibility = 0 AND id IN (1,34,87); kind of backwards, but if this returns no rows then the item is visible. Has anyone come across this before and come up with a solution. I don't really want to go the stored procedure route. It's for a rails app.

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  • Validate Canadian Postal Code Regex

    - by Alex Block
    I have a script written in JavaScript to Validate Canadian Postal Codes using Regex, however it does not seem to be working. Here is the script: If statement: if (myform.zip.value == "" || myform.zip.value == null || myform.zip.value == "Postal Code" || myform.zip.value.length < 12 ) { alert("Please fill in field Postal Code. You should only enter 7 characters"); myform.zip.focus(); return false; } Function: function okNumber(myform) { var regex = /^[ABCEGHJKLMNPRSTVXY]{1}\d{1}[A-Z]{1} *\d{1}[A-Z]{1}\d{1}$/; if (regex.test(myform.zip.value) == false) { alert("Input Valid Postal Code"); myform.zip.focus(); return false; } return true; }

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  • How would I UPDATE these table entries with SQL and PHP?

    - by CT
    I am working on an Asset Database problem. I enter assets into a database. Every object is an asset and has variables within the asset table. An object is also a type of asset. In this example the type is server. Here is the Query to retrieve all necessary data: SELECT asset.id ,asset.company ,asset.location ,asset.purchaseDate ,asset.purchaseOrder ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serialNumber ,server.esc ,server.warranty ,server.user ,server.prevUser ,server.cpu ,server.memory ,server.hardDrive FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = '$id' I then assign all results into single php variables. How would I write a query/script to update an asset?

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  • Search 2 Columns with 1 Input Field

    - by Norbert
    I have a db with two columns: first name and last name. The first name can have multiple words. Last name can contain hyphenated words. Is there a way to search both columns with only one input box? Database ID `First Name` `Last Name` 1 John Peter Doe 2 John Fubar 3 Michael Doe Search john peter returns id 1 john returns id 1,2 doe returns id 1,3 john doe returns id 1 peter john returns id 1 peter doe returns id 1 doe john returns id 1 I previously tried the following. Searching for John Doe: SELECT * FROM names WHERE ( `first` LIKE '%john%' OR `first` LIKE '%doe%' OR `last` LIKE '%john%' OR `last` LIKE '%doe%' ) which returns both 1 and 3

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  • SELECT a list of elements and 5 tags for each one

    - by Vittorio Vittori
    Hi, I'm trying to query a set of buldings listed on a table, these buildings are linked with tags. I'm able to do it, but my problem is how limit the number of tags to see: table buildings id building_name style 1 Pompidou bla 2 Alcatraz bla 3 etc. etc. table tags // they can be 50 or more per building id tag_name 1 minimal 2 gothic 3 classical 4 modern 5 etc. table buildings_tags id building_id tag_id I though to do something like this to retrieve the list, but this isn't compplete: SELECT DISTINCT(tag), bulding_name FROM buldings INNER JOIN buildings_tags ON buildings.id = buildings_tags.building_id INNER JOIN tags ON tags.id = buildings_tags.tag_id LIMIT 0, 20 // result building tag Pompidou great Pompidou france Pompidou paris Pompidou industrial Pompidou renzo piano <= How to stop at the 5th result? Pompidou hi-tech Pompidou famous place Pompidou wtf etc.. etc... this query loads the buildings, but this query loads all the tags linked for the building, and not only 5 of them?

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  • A generic error occurred in GDI+.

    - by Pinu
    A generic error occurred in GDI+ [ExternalException (0x80004005): A generic error occurred in GDI+.] System.Drawing.Image.Save(Stream stream, ImageCodecInfo encoder, EncoderParameters encoderParams) +615257 I have a webpage in which a pdf is converted to png, and using the response.outputstream it is displayed. when i run this on my local machine is works fine. but when i run the same code on server is throws this exception. my question is , where i could look in for error. as there is no inner exception or any other information provided. only clue is that it's happening on Image.Save , but the same code works perfectly fine on my local machine , then y is it not working on production???

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  • Modifying records in my migration throws an authlogic error

    - by nfm
    I'm adding some columns to one of my database tables, and then populating those columns: def self.up add_column :contacts, :business_id, :integer add_column :contacts, :business_type, :string Contact.reset_column_information Contact.all.each do |contact| contact.update_attributes(:business_id => contact.client_id, :business_type => 'Client') end remove_column :contacts, :client_id end The line contact.update_attributes is causing the following Authlogic error: You must activate the Authlogic::Session::Base.controller with a controller object before creating objects I have no idea what is going on here - I'm not using a controller method to modify each row in the table. Nor am I creating new objects. The error doesn't occur if the contacts table is empty. I've had a google and it seems like this error can occur when you run your controller tests, and is fixed by adding before_filter :activate_authlogic to them, but this doesn't seem relevant in my case. Any ideas? I'm stumped.

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  • Sql query listing Fathers and childs with joins, how to distinct them?

    - by DaNieL
    Having those tables: table_n1: | t1_id | t1_name | | 1 | foo | table_n2: | t2_id | t1_id | t2_name | | 1 | 1 | bar | I need a query that gives me two result: | names | | foo | | foo / bar | But i cant figure out the right way. I wrote this one: SELECT CONCAT_WS(' / ', table_n1.t1_name, table_n2.t2_name) AS names FROM table_n1 LEFT JOIN table_n2 ON table_n2.t1_id = table_n1.t1_id that works for an half: this only return the 2° row (in the example above): | names | | foo - bar | This query return the 'father' (table_n1) name only when it doesnt have 'childs' (table_n2). How can i fix it?

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  • SQL joining 3 tables when 1 table is emty

    - by AdRock
    I am trying to write a query that connects 3 tables. The first table is info about each festival The second table is the number of votes for each festival The third table is reviews for each festival I want to join all 3 tables so i get all the feilds from table1, join table1 with table2 on the festivalid but i also need to count the number of records in table 3 that applys to each festival. The first 2 tables give me a result becuase they both have data in them but table 3 is empty becuase there are no reviews yet so adding that to my query fives me no results SELECT f.*, v.total, v.votes, v.festivalid, r.reviewcount as count FROM festivals f INNER JOIN vote v ON f.festivalid = v.festivalid INNER JOIN (SELECT festivalid, count(*) as reviewcount FROM reviews) GROUP BY festivalid) as r on r.festivalid = v.festivalid

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  • How to write stored procedures to separate files with mysqldump?

    - by Jader Dias
    The mysqldump option --tab=path writes the creation script of each table in a separate file. But I can't find the stored procedures, except in the screen dump. I need to have the stored procedures also in separate files. The current solution I am working on is to split the screen dump programatically. Is there a easier way? The code I am using so far is: mysqldump -p$PASSWORD --routines --skip-dump-date --no-create-info --no-data --skip-opt $DATABASE > $BACKUP_PATH/$DATABASE.sql mysqldump -p$PASSWORD --tab=$BACKUP_PATH --skip-dump-date --no-data --skip-opt $DATABASE

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  • Is there any way to simplify a verbose SQL INSERT INTO(..) query?

    - by Soundar Rajan
    I have a table with one id (autonumber) field and 50 other fields. The table is normalized, these are 50 material properties etc. I want to copy a record from this table into the same table - only the autoincrement id will be different. The query I am using now is INSERT INTO tableName (field1,field2,....field50) SELECT field1,field2,....field50 from tableName WHERE autoid=1234; Note that I have to type in ALL the 50 field names, twice! Is there any way to shorten this query so I don't have to type all of them? Thanks.

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  • Hibernate error: cannot resolve table

    - by Roman
    I'm trying to make work the example from hibernate reference. I've got simple table Pupil with id, name and age fields. I've created correct (as I think) java-class for it according to all java-beans rules. I've created configuration file - hibernate.cfg.xml, just like in the example from reference. I've created hibernate mapping for one class Pupil, and here is the error occured. <hibernate-mapping> <class name="Pupil" table="pupils"> ... </class> </hibernate-mapping> table="pupils" is red in my IDE and I see message "cannot resolve table pupils". I've also founded very strange note in reference which says that most users fail with the same problem trying to run the example. Ah.. I'm very angry with this example.. IMHO if authors know that there is such problem they should add some information about it. But, how should I fix it? I don't want to deal with Ant here and with other instruments used in example. I'm using MySql 5.0, but I think it doesn't matter. UPD: source code Pupil.java - my persistent class package domain; public class Pupil { private Integer id; private String name; private Integer age; protected Pupil () { } public Pupil (String name, int age) { this.age = age; this.name = name; } public Integer getId () { return id; } public void setId (Integer id) { this.id = id; } public String getName () { return name; } public void setName (String name) { this.name = name; } public Integer getAge () { return age; } public void setAge (Integer age) { this.age = age; } public String toString () { return "Pupil [ name = " + name + ", age = " + age + " ]"; } } Pupil.hbm.xml is mapping for this class <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="domain" > <class name="Pupil" table="pupils"> <id name="id"> <generator class="native" /> </id> <property name="name" not-null="true"/> <property name="age"/> </class> </hibernate-mapping> hibernate.cfg.xml - configuration for hibernate <hibernate-configuration> <session-factory> <!-- Database connection settings --> <property name="connection.driver_class">com.mysql.jdbc.Driver</property> <property name="connection.url">jdbc:mysql://localhost/hbm_test</property> <property name="connection.username">root</property> <property name="connection.password">root</property> <property name="connection.pool_size">1</property> <property name="dialect">org.hibernate.dialect.MySQL5Dialect</property> <property name="current_session_context_class">thread</property> <property name="show_sql">true</property> <mapping resource="domain/Pupil.hbm.xml"/> </session-factory> </hibernate-configuration> HibernateUtils.java package utils; import org.hibernate.SessionFactory; import org.hibernate.HibernateException; import org.hibernate.cfg.Configuration; public class HibernateUtils { private static final SessionFactory sessionFactory; static { try { sessionFactory = new Configuration ().configure ().buildSessionFactory (); } catch (HibernateException he) { System.err.println (he); throw new ExceptionInInitializerError (he); } } public static SessionFactory getSessionFactory () { return sessionFactory; } } Runner.java - class for testing hibernate import org.hibernate.Session; import java.util.*; import utils.HibernateUtils; import domain.Pupil; public class Runner { public static void main (String[] args) { Session s = HibernateUtils.getSessionFactory ().getCurrentSession (); s.beginTransaction (); List pups = s.createQuery ("from Pupil").list (); for (Object obj : pups) { System.out.println (obj); } s.getTransaction ().commit (); HibernateUtils.getSessionFactory ().close (); } } My libs: antlr-2.7.6.jar, asm.jar, asm-attrs.jar, cglib-2.1.3.jar, commons-collections-2.1.1.jar, commons-logging-1.0.4.jar, dom4j-1.6.1.jar, hibernate3.jar, jta.jar, log4j-1.2.11.jar, mysql-connector-java-5.1.7-bin.jar Compile error: cannot resolve table pupils

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  • Enter ID instead of name on submit (form)

    - by Derek
    In my activities table, I have a user ID and a project ID. When a user (of admin level) creates an activity they select from a drop down menu a project. Here is the select query to draw up appropriate values: $sql = "SELECT usersprojects_tb.projectid, projects.projectname FROM projects INNER JOIN usersprojects on projects.projectid = usersprojects.projectid WHERE usersprojects.userid = '".$_SESSION['SESS_USERID']."'"; And for the tag with the dropdown menu, I have this: <?php echo $row['projectname']?> I have tried submitting the form with 'projectid' here instead and the project ID is stored successfully in my activies table. However, the user needs to see the project names (IDs arent exactly user-friendly!) And with 'projectname' as displayed, they can select the names of the available projects (to associate an activity with) but the project ID is not stored, how I link this up, so that when the project name is sent, the ID for this project is stored properly in my activities table. I'm also having the exact same problem with the users drop down. As the admin user selects a user from the drop down to assign the task to. I exactly what I want, but I think I may be using the wrong syntax! Any help is much appreciated. Thanks.

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  • Weird mapping error in linq-to-sql dbml file in VS2010

    - by rwwilden
    Since I switched to VS2010, several times a day I get a compilation error in my dbml file: DBML1005: Mapping between DbType 'bigint' and Type 'MyNamespace.SecurityToken' in Column 'SecurityToken' of Type 'Employee' is not supported When I restart VS2010 the error disappears. I have no problems running my application using this dbml file (specifically, there are no problems getting correct values inside the SecurityToken property of Employee objects). The SecurityToken property is of an enum type defined as follows: [Flags] public enum SecurityToken : long { None = 1, Admin = 2, ...... } The SecurityToken column in the database is of type bigint. Am I missing something? It's especially weird that the error only happens sometimes, when I'm writing code that isn't related at all to the LINQ model.

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  • Altering constraint delete action

    - by Hobhouse
    I did this: ALTER TABLE `db`.`my_table` ADD CONSTRAINT FOREIGN KEY (`my_second_table_id`) REFERENCES `my_second_table` (`id`); I should have done this: ALTER TABLE `db`.`my_table` ADD CONSTRAINT FOREIGN KEY (`my_second_table_id`) REFERENCES `my_second_table` (`id`) ON DELETE SET NULL; Is it possible to ALTER this, or do I have to drop the constraint and add again?

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  • SQL finding members who are not friends of another member

    - by thedirktastik
    I'm struggling to find a query which will return members who aren't friends of a certain member. Here is the layout of my tables: member_login: MemberID, email, password member_info: memberID, first_name, last_name member_friends: friendID, req_member, req_date, app_member, app_date, date_deactivated I tried to use NOT IN to run a query that would return the opposite of friends but nothing I try seems to be working. Here's what I thought would work: SELECT Mi.First_Name, Mi.Last_Name FROM Member_Info Mi WHERE Mi.Memberid NOT IN( SELECT Mi.Memberid, Mi.First_Name, Mi.Last_Name FROM Member_Info Mi, Member_Login Ml, Member_Friends Mf WHERE Mi.Memberid = Ml.Memberid AND (Mi.Memberid = Mf.Req_Member AND Mf.App_Member = 1 OR Mi.Memberid = Mf.App_Member AND Mf.Req_Member =1) AND Ml.Date_Deactivated <= 0 AND Mf.App_Date > 0 ); Any ideas?

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  • IF expression in SQL

    - by chupinette
    INSERT INTO item_quotation (item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) SELECT DISTINCT I.item_id," . $quotation_id . ",T.item_name, I.name,I.other_name, INV.selling_price, I.discounted_price FROM temp_quotations T, item I, inventory INV<br/> WHERE ( I.name LIKE CONCAT( '%', T.item_name, '%' ) OR I.other_name LIKE CONCAT( '%', T.item_name, '%' )) AND INV.item_id = I.item_id; I have a table called temp_quotations(temp_item_id,item_name)having values (1,grinder), (2,drill), (3,kit) I have another table called item(item_id,name,other_name,discounted_price) having values (1,grinder A,100),(2,kit A,200) When I execute this sql, it insert values in table item_quotation(item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) for example in this case it will insert (1,1,grinder,grinder A,150,100) (2,1,kit,kit A, 250,200) Since the item drill is not found in table item, it wont display it in table item_quotations. I want to write an if statement within that sql so that when the item_name from temp_quotation does not match the name from item, it displays not found in the place of item_name. This is what i tried but it does not display "not found": INSERT INTO item_quotation (item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) SELECT DISTINCT I.item_id," . $quotation_id . ",T.item_name, IF(I.name LIKE CONCAT( '%', T.item_name, '%' ),I.name,'not found'),I.other_name, INV.selling_price, I.discounted_price FROM temp_quotations T, item I, inventory INV WHERE ( I.name LIKE CONCAT( '%', T.item_name, '%' ) OR I.other_name LIKE CONCAT( '%', T.item_name, '%' )) AND INV.item_id = I.item_id;

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  • Auto deployment of PHP applications

    - by Christopher McCann
    My team currently has a development web/database server and a live deployment web server and a live database server. We use SVN with the repository stored on the development server but the problem is our deployment process. Currently when we need to deploy an update to the live application we simply use SFTP to transfer from the repository to the live web server and then amend the database on the live server to reflect the development database. This is a really slow process as we also minify all javascript and CSS files. I have used Capistrano for Ruby and Cruise Control for java but I have never used anything for PHP. I'd rather not have to build our own if something already existed. Does anyone know of anything?

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  • Establishing persistent connection to a database in Java

    - by gmile
    I've ran through several examples over the web, and found that every single time I need something from the DB, I should write the following code: try { // Step 1: Load the JDBC driver. Class.forName("mysql_driver_name"); // Step 2: Establish the connection to the database. String url = "jdbc:string_to_mysql_server"; Connection conn = DriverManager.getConnection(url,"user1","password"); // fetch from the DB ... } catch (Exception e) { System.err.println("Got an exception! "); System.err.println(e.getMessage()); } It's very annoying to put up this code every time I want something from the DB, so the question is - is there a way to only once connect entirely all my app to the DB somehow at the very start point, avoiding copy-pasting mentioned code, and then be able to do everything I want with DB? I've quickly looked through NetBeans's Project menu, but didn't find any clue on how to configurate a persistent connection to a selected DB. If it's important, i'm writing a purely desktop app, i.e. using Java EE. Also, it's worth mentioning that I'm a kinda beginner in Java.

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