Search Results

Search found 36756 results on 1471 pages for 'mysql real query'.

Page 537/1471 | < Previous Page | 533 534 535 536 537 538 539 540 541 542 543 544  | Next Page >

  • Is this possible with sql?

    - by Andrew
    Is it possible to do something like this: INSERT INTO table(col1, col2) VALUES(something_from_another_table, value); With something_from_another_table being a SQL command? Like, is there something I can do that's equivelant to: INSERT INTO table(col1, col2) VALUES((SELECT value FROM table2 WHERE id = 3), value);

    Read the article

  • Tracking Votes and only allowing 1 vote per member

    - by MikeAdams
    What I'm trying to do is count the votes when someone votes on a "page". I think I lost myself trying to figure out how to track when a member votes or not. I can't seem to get the code to tell when a member has voted. //Generate code ID $useXID = intval($_GET['id']); $useXrank = $_GET['rank']; //if($useXrank!=null && $useXID!=null) { $rankcheck = mysql_query('SELECT member_id,code_id FROM code_votes WHERE member_id="'.$_MEMBERINFO_ID.'" AND WHERE code_id="'.$useXID.'"'); if(!mysql_fetch_array($rankcheck) && $useXrank=="up"){ $rankset = mysql_query('SELECT * FROM code_votes WHERE member_id="'.$_MEMBERINFO_ID.'"'); $ranksetfetch = mysql_fetch_array($rankset); $rankit = htmlentities($ranksetfetch['ranking']); $rankit+="1"; mysql_query("INSERT INTO code_votes (member_id,code_id) VALUES ('$_MEMBERINFO_ID','$useXID')") or die(mysql_error()); mysql_query("UPDATE code SET ranking = '".$rankit."' WHERE ID = '".$useXID."'"); } elseif(!mysql_fetch_array($rankcheck) && $useXrank=="down"){ $rankset = mysql_query('SELECT * FROM code_votes WHERE member_id="'.$_MEMBERINFO_ID.'"'); $ranksetfetch = mysql_fetch_array($rankset); $rankit = htmlentities($ranksetfetch['ranking']); $rankit-="1"; mysql_query("INSERT INTO code_votes (member_id,code_id) VALUES ('$_MEMBERINFO_ID','$useXID')") or die(mysql_error()); mysql_query("UPDATE code SET ranking = '".$rankit."' WHERE ID = '".$useXID."'"); } // hide vote links since already voted elseif(mysql_fetch_array($rankcheck)){$voted="true";} //}

    Read the article

  • Inserting Record into multiple tables No Common ID

    - by the_
    OK so I have two tables, MEDIA and BUSINESS. I want it set up so the forms to input into them are on the same page. MEDIA has a row that is biz_id that is the id of BUSINESS. So MEDIA is really a part of BUSINESS. HOW do I insert/add these into their tables without a common ID because I haven't yet made the record for business? I'm sorry I didn't really word this very much... You might need more clarification to answer properly and I'll be glad to give any more info. Any help would be greatly appreciated, thanks!

    Read the article

  • PHP & HTML Purifier Error: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given

    - by TaG
    I'm trying to Integrate HTML Purifier http://htmlpurifier.org/ to filter my user submitted data but I get the following error below. And I was wondering how can I fix this problem? I get the following error. on line 22: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given line 22 is. if (mysqli_num_rows($dbc) == 0) { Here is the php code. if (isset($_POST['submitted'])) { // Handle the form. require_once '../../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype $purifier = new HTMLPurifier($config); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, profile.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $about_me = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['about_me'])); $interests = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['interests'])); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) VALUES ('$user_id', '$about_me', '$interests')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE profile SET about_me = '$about_me', interests = '$interests' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } }

    Read the article

  • How would I go about writing a conditional statement to check if visitor is coming from a particular

    - by Matthew
    Hello guys, What I have in mind is this... We are going to have people come from a particular site during a acquisition campaign and was wondering how I could conditionalize a certain section of my site to display a thank you message instead of the sign up form as they would have had the opportunity to fill this out before coming to my landing page. I have seen solutions like: $referal = mysql_real_escape_string($_SERVER['HTTP_REFERER']); I would like to know if this is the best way to get this to work??? - okay this is what i think might work. The third party website that is referring people to our landing page once the form on that site has been filled out can push into the record a hidden input value of "www.sample.com" or whatever... then I can have something check the for that particular value and fire off the conidtional. Does that even sound right?

    Read the article

  • checkbox checked with php form post?

    - by Patrick
    how do I check a checkbox? I've tried 1, On, Yes that doesn't work. putting the worked "checked" alone works but then how do I check with php after form post of the checkbox is checked? <input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" />

    Read the article

  • How to find intersect rows when condition depend on some columns in one table

    - by user3695637
    Table subscribe subscriber | subscribeto (columns) 1 | 5 1 | 6 1 | 7 1 | 8 1 | 9 1 | 10 2 | 5 2 | 6 2 | 7 There are two users that have id 1 and 2. They subscribe to various user and I inserted these data to table subscribe. Column subscriber indicates who is subscriber and column subscribeto indicates who they've subscribe to. From the above table can conclude that; user id=1 subscribed to 6 users user id=2 subscribed to 3 users I want to find manual of subscription (like Facebook is manual friends) user 1 subscribe to user 5,6,7,8,9,10 user 2 subscribe to user 5,6,7 So, Manual subscription of user 1 and 2 are: 5,6,7 And I'm trying to create SQL statement.. I give you user table for my SQL statement and I think we can use only subscribe table but I can't figure out. Table user userid (columns) 1 2 3 ... ... SQL "select * from user where (select count( 1 ) from subscribe where subscriber = '1' and subscribeto = user.userid) and (select count( 1 ) from subscribe where subscriber = '2' and subscribeto = user.userid);" This SQL can work correctly, but it very slow for thousands of columns. Please provide better SQL for me, Thanks.

    Read the article

  • Turning user ID into name (seperate tables) in PHP

    - by mobile
    I am currently trying to display the username of people who i am following, the problem is that during the following process, only the ID of me and the person i'm following is stored. I've got it to the point where the ID's are displayed but i'd like to show the names hyperlinked. $p_id is the profile ID. Here's what I've got: $following = mysql_query("SELECT `follower`, `followed` FROM user_follow WHERE follower=$p_id"); I am following: <?php while($apple = mysql_fetch_array($following)){ echo '<a href="'.$apple['followed'].'">+'.$apple['followed'].'</a> '; }?> The usernames are in a different table "users" under the field "username" - I need them to match up with the ID's that are currently displayed, and be displayed. Any help appreciated, thanks guys

    Read the article

  • Get consolidated results with following tables

    - by Ted
    I have a scenario. Here's my table structure is: ID LoginDate RemovalDate ---------------------------------------- 1 2009/08/01 NULL 2 2009/09/12 2010/01/02 3 2009/08/31 2009/10/29 4 2010/02/17 NULL 5 2009/10/18 2009/11/22 I want a consolidated results of how many ID's were not removed in a particular month. So the result set should be Date NotRemoved_ID -------------------------- 2009/08 2 2009/09 3 2009/10 3 [One ID got removed in 2009/10] 2010/02 2 [Two got removed in 2009/11 and 2010/01] Please help.

    Read the article

  • What information about a user is available via PHP?

    - by Camran
    This is about a classifieds website, where anyone may post classifieds. I have a security database which I intend to fill with information about the user who posts the classifieds. I intend to record information such as IP, name, tel, email, classified_text, classified_title etc etc. The reason for all this is that sometimes people become victims of fraud (fake classifieds etc). So I wonder, what information is possible to get from the poster which may help in tracking him/her down? IP is a given, but what else could be useful? And I would much like examples of how it would be useful also, as well as the code for it please, like $_SERVER['REMOTE_ADDR']. And btw, I use PHP and have Sql as a database. Thanks

    Read the article

  • Is this SQL is valid?

    - by Beck
    UPDATE polls_options SET `votes`=`votes`+1, `percent`=ROUND((`votes`+1) / (SELECT voters FROM polls WHERE poll_id=? LIMIT 1) * 100,1) WHERE option_id=? AND poll_id=? Don't have table data yet, to test it properly. :) And by the way, in what type % integers should be stored in database? Thanks for the help!

    Read the article

  • 2 IP are stored for a visitor : PROXY ?

    - by Tristan
    Hello, on my database i've decided to store IP of the visitors who answoers to polls. It's all working, but there is only 2 cases where not only 1 IP is stored, but there is 2 SAME ip for the same visitor MySQLL output (i replaced 2 numbers by XX) 10.188.XX.129, 10.188.XX.129 Here's the script to recieve the IP of the visitor : <?php function realip() { if (isset($_SERVER)) { if (isset($_SERVER["HTTP_X_FORWARDED_FOR"])) { $realip = $_SERVER["HTTP_X_FORWARDED_FOR"]; } elseif (isset($_SERVER["HTTP_CLIENT_IP"])) { $realip = $_SERVER["HTTP_CLIENT_IP"]; } else { $realip = $_SERVER["REMOTE_ADDR"]; } } else { if ( getenv( 'HTTP_X_FORWARDED_FOR' ) ) { $realip = getenv( 'HTTP_X_FORWARDED_FOR' ); } elseif ( getenv( 'HTTP_CLIENT_IP' ) ) { $realip = getenv( 'HTTP_CLIENT_IP' ); } else { $realip = getenv( 'REMOTE_ADDR' ); } } return $realip; } ? Thanks

    Read the article

  • SQL ENQUIRY In how to Get defined number of records

    - by ramadan2050
    I have a select statement, retrieve about 1000 record I want to modify it to return only some records defined by @startIndex and @count e.g. : If I said @startIndex=20 and @count=20 the result will be : from the 21th record to 40th I try to make it, but it take the same time as if I retrieve the 1000 record what is the best way to do that

    Read the article

  • You can't specify target table 'b' for update in FROM clause

    - by elo
    I need to know where did i do wrong in this sql statement. I try to find solution in previous threads with similar problem but none can solve my problem. so i think maybe my statement is actually wrong. update table1 b left join table2 m on b.ICNO=m.ICNO set b.SalMoveMth = '01' where m.Status!='6' and (DATE_FORMAT(startDateSand,'%m')='10' or DATE_FORMAT(startDateSand,'%m')='11' or DATE_FORMAT(startDateSand,'%m')='12') and ((select SalMoveMth from table1 where ICNO=table2.ICNO order by SalMoveMthStDt desc limit 1)!='10'). Thank You.

    Read the article

  • Does Doctrine 1.2 support importing indexes with Doctrine_Core::generateModelsFromDb function?

    - by Coagulant
    Does Doctrine 1.2 support importing indexes with Doctrine_Core::generateModelsFromDb() function? I need to make a migration between 2 database connections, one of them having unique index on 2 fields and one doesn't. And my migration is empty. It looks like Doctrine doesn't support indexes when importing from databae, other than those tied to relationship foreign keys. $changes = Doctrine_Core::generateMigrationsFromDiff($migrationsPath, array('doctrineOld'), array('doctrine'));

    Read the article

  • Obtaining a timestamp every minute from a database

    - by soumen
    This is my table structure: +------------+-----------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +------------+-----------+------+-----+---------+-------+ | uid | char(255) | NO | MUL | NULL | | | cid | char(255) | NO | MUL | NULL | | | ip_address | char(15) | NO | | NULL | | | user_agent | char(255) | YES | | NULL | | | open_date | datetime | NO | MUL | NULL | | | referrer | char(255) | YES | | NULL | | | environ | text | YES | | NULL | | | country | char(255) | NO | MUL | NULL | | +------------+-----------+------+-----+---------+-------+ I want to get a timestamp every minute within a range. select DATE_ADD(open_date,interval 1 minute) as m from open_track.camp_open where open_date between "2009-05-13 00:00:00" and "2009-05-13 23:59:59" limit 10; outputs +---------------------+ | m | +---------------------+ | 2009-05-13 00:01:01 | | 2009-05-13 00:01:02 | | 2009-05-13 00:01:03 | | 2009-05-13 00:01:03 | | 2009-05-13 00:01:04 | | 2009-05-13 00:01:05 | | 2009-05-13 00:01:06 | | 2009-05-13 00:01:08 | | 2009-05-13 00:01:08 | | 2009-05-13 00:01:09 | +---------------------+ Please advise me.

    Read the article

  • Running a sharded DB from a single machine

    - by ming yeow
    This sounds kinda dumb, but I have a sharded DB that I no longer think I need to run on 2 machines, and would like to run on one single machine instead. Any ideas on how that can potentially be done? There are lots of resources on how i can achieve the converse, but very little on how this can be done

    Read the article

  • Drupal 6: moving localhost to server | clear cached data

    - by artmania
    Hi friends, I worked on localhost to build my drupal site. then, I moved to server. Steps: Clear cache tables (Site Configuration Performance Clear Cached Data button) on localhost Export db and then import on live server Move files/folders to live server Edit settings.php to reflect live server config everything is working great until I make Clear Cached Data on Server. than my custom theme, custom front page, etc... all mess up :( What can be the problem? I appreciate helps so much!! Thanks! !!SORTED!! I used a subtheme for Zen, named mgf . then I had taken a back-up as mgf- somehow after I make Clear Cached Data, Drupal links to this mgf- which is old and doesnt have latest stylings. I just removed this folder from themes, and it linked to the right-latest mgf.

    Read the article

  • Basic SQL Query, I am newbie

    - by user3530547
    I just started my database and query class on Monday. We met on Monday and just went over the syllabus, and on Wednesday the network at school was down so we couldn't even do the power point lecture. Right now I am working on my first homework assignment and I am almost finished but I am having trouble on one question. Here is is... Write a SELECT statement that returns one column from the Customers table named FullName that joins the LastName and FirstName columns. Format the columns with the last name, a comma, a space, and the first name like this: Doe, John Sort the result set by last name in ascending sequence. Return only the contacts whose last name begins with letters from M to Z. Here is what I have so far... USE md0577283 SELECT FirstName,LastName FROM Customers ORDER BY LastName,FirstName My question is how do I format is Lastname, FirstName like the professor wants and how do I only select names M-Z? If someone could point me in the right direction I would greatly appreciate it. Thank you. PS With all do respect, I didn't ask for the answer I asked for a nudge in the right direction so why the down vote guys?

    Read the article

< Previous Page | 533 534 535 536 537 538 539 540 541 542 543 544  | Next Page >