Bash Array Problem
- by Deepak Prasanna
I wrote a bash script which tries to find a process and run the process if it had stopped.
This is the script.
#!/bin/bash
process=thin
path=/home/deepak/abc/
initiate=thin start -d
process_id=`ps -ef | pgrep $process | wc -m`
if [ "$process_id" -gt "0" ]; then
echo "The process process is running!!"
else
cd $path
$initiate
echo "Oops the process has stopped"
fi
This worked fine and I thought of using arrays so that i can form a loop use this script to check multiple processes. So I modified my script like this
#!/bin/bash
process[1]=thin
path[1]=/home/deepak/abc/
initiate[1]=thin start -d
process_id=`ps -ef | pgrep $process[1] | wc -m`
if [ "$process_id" -gt "0" ]; then
echo "Hurray the process ${process[1]} is running!!"
else
cd ${path[1]}
${initiate[1]}
echo "Oops the process has stopped"
echo "Continue your coffee, the process has been stated again! ;)"
fi
I get this error if i run this script.
DontWorry.sh: 2: process[1]=thin: not found
DontWorry.sh: 3: path[1]=/home/deepak/abc/: not found
DontWorry.sh: 4: initiate[1]=thin start -d: not found
I googled to find any solution for this, most them insisted to use "#!/bin/bash" instead of "#!/bin/sh". I tried both but nothing worked. What am i missing?
