Search Results

Search found 252976 results on 10120 pages for 'stack overflow'.

Page 8/10120 | < Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >

  • Problems with Android Fragment back stack

    - by DexterMoon
    I've got a massive problem with the way the android fragment backstack seems to work and would be most grateful for any help that is offered. Imagine you have 3 Fragments [1] [2] [3] I want the user to be able to navigate [1] > [2] > [3] but on the way back (pressing back button) [3] > [1]. As I would have imagined this would be accomplished by not calling addToBackStack(..) when creating the transaction that brings fragment [2] into the fragment holder defined in XML. The reality of this seems as though that if I dont want [2] to appear again when user presses back button on [3], I must not call addToBackStack in the transaction that shows fragment [3]. This seems completely counter-intuitive (perhaps coming from the iOS world). Anyway if i do it this way, when I go from [1] > [2] and press back I arrive back at [1] as expected. If I go [1] > [2] > [3] and then press back I jump back to [1] (as expected). Now the strange behavior happens when I try and jump to [2] again from [1]. First of all [3] is briefly displayed before [2] comes into view. If I press back at this point [3] is displayed, and if I press back once again the app exits. Can anyone help me to understand whats going on here? And here is the layout xml file for my main activity: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical" > <fragment android:id="@+id/headerFragment" android:layout_width="match_parent" android:layout_height="wrap_content" class="com.fragment_test.FragmentControls" > <!-- Preview: layout=@layout/details --> </fragment> <FrameLayout android:id="@+id/detailFragment" android:layout_width="match_parent" android:layout_height="fill_parent" /> Update This is the code I'm using to build by nav heirarchy Fragment frag; FragmentTransaction transaction; //Create The first fragment [1], add it to the view, BUT Dont add the transaction to the backstack frag = new Fragment1(); transaction = getSupportFragmentManager().beginTransaction(); transaction.replace(R.id.detailFragment, frag); transaction.commit(); //Create the second [2] fragment, add it to the view and add the transaction that replaces the first fragment to the backstack frag = new Fragment2(); transaction = getSupportFragmentManager().beginTransaction(); transaction.replace(R.id.detailFragment, frag); transaction.addToBackStack(null); transaction.commit(); //Create third fragment frag = new Fragment3(); transaction = getSupportFragmentManager().beginTransaction(); transaction.replace(R.id.detailFragment, frag); transaction.commit(); //END OF SETUP CODE------------------------- //NOW: //Press back once and then issue the following code: frag = new Fragment2(); transaction = getSupportFragmentManager().beginTransaction(); transaction.replace(R.id.detailFragment, frag); transaction.addToBackStack(null); transaction.commit(); //Now press back again and you end up at fragment [3] not [1] Many thanks

    Read the article

  • gdb stack strangeness

    - by aaa
    Hi I get this weird backtrace (sometimes): (gdb) bt #0 0x00002b36465a5d4c in AY16_Loop_M16 () from /opt/intel/mkl/10.0.3.020/lib/em64t/libmkl_mc.so #1 0x00000000000021da in ?? () #2 0x00000000000021da in ?? () #3 0xbf3e9dec2f04aeff in ?? () #4 0xbf480541bd29306a in ?? () #5 0xbf3e6017955273e8 in ?? () #6 0xbf442b937c2c1f37 in ?? () #7 0x3f5580165832d744 in ?? () ... Any ideas why i cant see the symbols? Compiled with debugging syms of course. The same session gives symbols at other points.

    Read the article

  • Class members allocation on heap/stack? C++

    - by simplebutperfect
    If a class is declared as follows: class MyClass { char * MyMember; MyClass() { MyMember = new char[250]; } ~MyClass() { delete[] MyMember; } }; And it could be done like this: class MyClass { char MyMember[250]; }; How does a class gets allocated on heap, like if i do MyClass * Mine = new MyClass(); Does the allocated memory also allocates the 250 bytes in the second example along with the class instantiation? And will the member be valid for the whole lifetime of MyClass object? As for the first example, is it practical to allocate class members on heap?

    Read the article

  • Android NDK Gaussian Blur radius stuck at 60

    - by rennoDeniro
    I implemented this NDK imeplementation of a Gaussian Blur, But I am having problems. I cannot increase the radius above 60, otherwise the activity just closes returning to a previous activity. No error message, nothing? Does anyone know why this could be? Note: This blur is based on the quasimondo implementation, here #include <jni.h> #include <string.h> #include <math.h> #include <stdio.h> #include <android/log.h> #include <android/bitmap.h> #define LOG_TAG "libbitmaputils" #define LOGI(...) __android_log_print(ANDROID_LOG_INFO,LOG_TAG,__VA_ARGS__) #define LOGE(...) __android_log_print(ANDROID_LOG_ERROR,LOG_TAG,__VA_ARGS__) typedef struct { uint8_t red; uint8_t green; uint8_t blue; uint8_t alpha; } rgba; JNIEXPORT void JNICALL Java_com_insert_your_package_ClassName_functionToBlur(JNIEnv* env, jobject obj, jobject bitmapIn, jobject bitmapOut, jint radius) { LOGI("Blurring bitmap..."); // Properties AndroidBitmapInfo infoIn; void* pixelsIn; AndroidBitmapInfo infoOut; void* pixelsOut; int ret; // Get image info if ((ret = AndroidBitmap_getInfo(env, bitmapIn, &infoIn)) < 0 || (ret = AndroidBitmap_getInfo(env, bitmapOut, &infoOut)) < 0) { LOGE("AndroidBitmap_getInfo() failed ! error=%d", ret); return; } // Check image if (infoIn.format != ANDROID_BITMAP_FORMAT_RGBA_8888 || infoOut.format != ANDROID_BITMAP_FORMAT_RGBA_8888) { LOGE("Bitmap format is not RGBA_8888!"); LOGE("==> %d %d", infoIn.format, infoOut.format); return; } // Lock all images if ((ret = AndroidBitmap_lockPixels(env, bitmapIn, &pixelsIn)) < 0 || (ret = AndroidBitmap_lockPixels(env, bitmapOut, &pixelsOut)) < 0) { LOGE("AndroidBitmap_lockPixels() failed ! error=%d", ret); } int h = infoIn.height; int w = infoIn.width; LOGI("Image size is: %i %i", w, h); rgba* input = (rgba*) pixelsIn; rgba* output = (rgba*) pixelsOut; int wm = w - 1; int hm = h - 1; int wh = w * h; int whMax = max(w, h); int div = radius + radius + 1; int r[wh]; int g[wh]; int b[wh]; int rsum, gsum, bsum, x, y, i, yp, yi, yw; rgba p; int vmin[whMax]; int divsum = (div + 1) >> 1; divsum *= divsum; int dv[256 * divsum]; for (i = 0; i < 256 * divsum; i++) { dv[i] = (i / divsum); } yw = yi = 0; int stack[div][3]; int stackpointer; int stackstart; int rbs; int ir; int ip; int r1 = radius + 1; int routsum, goutsum, boutsum; int rinsum, ginsum, binsum; for (y = 0; y < h; y++) { rinsum = ginsum = binsum = routsum = goutsum = boutsum = rsum = gsum = bsum = 0; for (i = -radius; i <= radius; i++) { p = input[yi + min(wm, max(i, 0))]; ir = i + radius; // same as sir stack[ir][0] = p.red; stack[ir][1] = p.green; stack[ir][2] = p.blue; rbs = r1 - abs(i); rsum += stack[ir][0] * rbs; gsum += stack[ir][1] * rbs; bsum += stack[ir][2] * rbs; if (i > 0) { rinsum += stack[ir][0]; ginsum += stack[ir][1]; binsum += stack[ir][2]; } else { routsum += stack[ir][0]; goutsum += stack[ir][1]; boutsum += stack[ir][2]; } } stackpointer = radius; for (x = 0; x < w; x++) { r[yi] = dv[rsum]; g[yi] = dv[gsum]; b[yi] = dv[bsum]; rsum -= routsum; gsum -= goutsum; bsum -= boutsum; stackstart = stackpointer - radius + div; ir = stackstart % div; // same as sir routsum -= stack[ir][0]; goutsum -= stack[ir][1]; boutsum -= stack[ir][2]; if (y == 0) { vmin[x] = min(x + radius + 1, wm); } p = input[yw + vmin[x]]; stack[ir][0] = p.red; stack[ir][1] = p.green; stack[ir][2] = p.blue; rinsum += stack[ir][0]; ginsum += stack[ir][1]; binsum += stack[ir][2]; rsum += rinsum; gsum += ginsum; bsum += binsum; stackpointer = (stackpointer + 1) % div; ir = (stackpointer) % div; // same as sir routsum += stack[ir][0]; goutsum += stack[ir][1]; boutsum += stack[ir][2]; rinsum -= stack[ir][0]; ginsum -= stack[ir][1]; binsum -= stack[ir][2]; yi++; } yw += w; } for (x = 0; x < w; x++) { rinsum = ginsum = binsum = routsum = goutsum = boutsum = rsum = gsum = bsum = 0; yp = -radius * w; for (i = -radius; i <= radius; i++) { yi = max(0, yp) + x; ir = i + radius; // same as sir stack[ir][0] = r[yi]; stack[ir][1] = g[yi]; stack[ir][2] = b[yi]; rbs = r1 - abs(i); rsum += r[yi] * rbs; gsum += g[yi] * rbs; bsum += b[yi] * rbs; if (i > 0) { rinsum += stack[ir][0]; ginsum += stack[ir][1]; binsum += stack[ir][2]; } else { routsum += stack[ir][0]; goutsum += stack[ir][1]; boutsum += stack[ir][2]; } if (i < hm) { yp += w; } } yi = x; stackpointer = radius; for (y = 0; y < h; y++) { output[yi].red = dv[rsum]; output[yi].green = dv[gsum]; output[yi].blue = dv[bsum]; rsum -= routsum; gsum -= goutsum; bsum -= boutsum; stackstart = stackpointer - radius + div; ir = stackstart % div; // same as sir routsum -= stack[ir][0]; goutsum -= stack[ir][1]; boutsum -= stack[ir][2]; if (x == 0) vmin[y] = min(y + r1, hm) * w; ip = x + vmin[y]; stack[ir][0] = r[ip]; stack[ir][1] = g[ip]; stack[ir][2] = b[ip]; rinsum += stack[ir][0]; ginsum += stack[ir][1]; binsum += stack[ir][2]; rsum += rinsum; gsum += ginsum; bsum += binsum; stackpointer = (stackpointer + 1) % div; ir = stackpointer; // same as sir routsum += stack[ir][0]; goutsum += stack[ir][1]; boutsum += stack[ir][2]; rinsum -= stack[ir][0]; ginsum -= stack[ir][1]; binsum -= stack[ir][2]; yi += w; } } // Unlocks everything AndroidBitmap_unlockPixels(env, bitmapIn); AndroidBitmap_unlockPixels(env, bitmapOut); LOGI ("Bitmap blurred."); } int min(int a, int b) { return a > b ? b : a; } int max(int a, int b) { return a > b ? a : b; }

    Read the article

  • How to advocate Stack Overflow at work

    - by Gordon
    I am thinking of doing a short presentation at work about using Stack Overflow as a resource for your day job. What is the experience doing this? Would you deem it a valid resource to tell you colleagues about or is it similar to telling them about Google as a resource? Is there a better way of doing it? I was leaning toward asking questions side of Stack Overflow rather than answering them to avoid you-shouldn't-be-doing-this-on-work-time argument. Just as a follow up. Originally I didn't want to make the question to specific to my own case. My presentation will only be a quick four minute talk, which I will repeat over an hour to different groups. I may ask a question before the talk on Stack Overflow and refer to it during the presentation. Hopefully I will get some activity during the hour. I am also going to talk briefly about some of the other Stack Exchange sites that would fit the audience as they are not all developers. I think Super User, Server Fault and Programmers should work well. I will not be doing the presentation for another couple of months as it has be rescheduled, but I will update on how I got on.

    Read the article

  • Create a overflow screen while a game/program is running?

    - by Dodi300
    Hello. Does anyone know how I can create a screen overflow while a program is running? Mainly while a game is running. If anyone has used xFire or Steam, these use this feature. I've created a winform which starts the game/program and then minimizes. Could the overflow be created in the same winform? Thanks for the help! :)

    Read the article

  • @CodeStock 2012 Review: Rob Gillen ( @argodev ) - Anatomy of a Buffer Overflow Attack

    Anatomy of a Buffer Overflow AttackSpeaker: Rob GillenTwitter: @argodevBlog: rob.gillenfamily.net Honestly, this talk was over my head due to my lack of knowledge of low level programming, and I think that most of the other attendees would agree. However I did get the basic concepts that we was trying to get across. Fortunately most high level programming languages handle most of the low level concerns regarding preventing buffer overflow attacks. What I got from this talk was to validate all input data from external sources.

    Read the article

  • Is INT_MIN-1 an underflow or overflow?

    - by Johannes Schaub - litb
    I seem to remember that I was reading that underflow means you have a too small magnitude that cannot be presented anymore in a type overflow means you have a too large magnitude that cannot be presented anymore in a type However, in practice I perceive that the terms are used such that underflow means you have a too small value that cannot be presented anymore in a type overflow means you have a too large value that cannot be presented anymore in a type What is the correct meaning to use here? Are the terms defined differently for integer and floating point types?

    Read the article

  • @CodeStock 2012 Review: Rob Gillen ( @argodev ) - Anatomy of a Buffer Overflow Attack

    Anatomy of a Buffer Overflow AttackSpeaker: Rob GillenTwitter: @argodevBlog: rob.gillenfamily.net Honestly, this talk was over my head due to my lack of knowledge of low level programming, and I think that most of the other attendees would agree. However I did get the basic concepts that we was trying to get across. Fortunately most high level programming languages handle most of the low level concerns regarding preventing buffer overflow attacks. What I got from this talk was to validate all input data from external sources.

    Read the article

  • When to address integer overflow in C

    - by Yktula
    Related question: http://stackoverflow.com/questions/199333/best-way-to-detect-integer-overflow-in-c-c In C code, should integer overflow be addressed whenever integers are added? It seems like pointers and array indexes should be checked at all. When should integer overflow be checked for? When numbers are added in C without type explicitly mentioned, or printed with printf, when will overflow occur? Is there a way to automatically detect when an integer arithmetic overflow?

    Read the article

  • Stack Exchange Notifier Chrome Extension [v1.2.9.3 released]

    - by Vladislav Tserman
    About Stack Exchange Notifier is a handy extension for Google Chrome browser that displays your current reputation, badges on Stack Exchange sites and notifies you on reputation's changes. You will now get notified of comments on your own posts (questions and answers) and of any comments that refer to you by @username in a comment, even if you do not own the post (aka mentions). All StackExchange sites are supported. Screenshots Access Install extensions from Google Chrome Extension Gallery Platform Google Chrome browser extension Contact Created by me (Vladislav Tserman). I'm available at: vladjan (at) gmail.com Follow Stack Exchange Notifier on twitter to get notified about news and updates: http://twitter.com/se_notifier Code Written in Java, Google Web Toolkit under Eclipse Helios. Stack Exchange Notifier uses the Stack Exchange API and is powered by Google App Engine for Java. Changelog I will be porting extension to not use app engine back-end due to some limitations. New versions of the extension will be making direct calls to Stack Exchange API right from your browser. Please do not expect new versions of the extension any time soon. Sorry. Read more about limitations here http://stackapps.com/questions/1713 and here http://stackoverflow.com/questions/3949815 Currently, you may sometimes experience some issues using extension, but most users will have no problems. You may notice too many errors in the logs, but there is nothing I can do with this now. Thanks for using my little app, thanks to all of you it still works in spite of many issues with API Version 1.2.9.3 - Thursday, October 14, 2010 - Bug fix release (back-end improvements) Version 1.2.9.2 - Thursday, October 07, 2010 - Bug fix release (high rate of occasional API errors were noticed so some fixes added to handle them were possible) Version 1.2.9.1 - Tuesday, October 05, 2010 - Mostly bug fix release, back-end performance improvements - You will now get notified of comments on your own posts (questions and answers) that are not older than 1 year and of any comments that refer to you by @username in a comment, even if you do not own the post (aka mentions). This is experimental feature, let me know if you like/need it. - New 'All sites' view displays all websites from Stack Exchange network (part of new feature that is not finished yet) Version 1.2.9 - Saturday, September 25, 2010 - Fixes an issue when some users got empty Account view. - When hovering on @Username on account view the title now displays '@Username on @SiteName' to easily understand the site name Version 1.2.7 - Wednesday, September 22, 2010 - Fixed an issue with notifications. - Minor improvements Version 1.2.5 - Tuesday, September 21, 2010 - Fixed an issue where some characters in response payload raised an exception when parsing to JSON. v1.2.3 (Sunday, September 19, 2010) - Support for new OpenID providers was added (Yahoo, MyOpenID, AOL) - UI improvements - Several minor defects were fixed v1.2.2 (Thursday, September 16, 2010) - New types of notifications added. Now extension notifies you on comments that are directed to you. Comments are expandable, so clicking on comment title will expand height to accommodate all available text. - UI and error handling improvements Future Application still in beta stage. I hope you're not having any problems, but if you are, please let me know. Leave your feedback and bug reports in comments. I'm available at: vladjan (at) gmail.com. I'm working on adding new features. I want to hear from the users and incorporate as much feedback as possible into the extension. Any suggestions for improvements/features to add?

    Read the article

  • OpenGL - Stack overflow if I do, Stack underflow if I don't!

    - by Wayne Werner
    Hi, I'm in a multimedia class in college, and we're "learning" OpenGL as part of the class. I'm trying to figure out how the OpenGL camera vs. modelview works, and so I found this example. I'm trying to port the example to Python using the OpenGL bindings - it starts up OpenGL much faster, so for testing purposes it's a lot nicer - but I keep running into a stack overflow error with the glPushMatrix in this code: def cube(): for x in xrange(10): glPushMatrix() glTranslated(-positionx[x + 1] * 10, 0, -positionz[x + 1] * 10); #translate the cube glutSolidCube(2); #draw the cube glPopMatrix(); According to this reference, that happens when the matrix stack is full. So I thought, "well, if it's full, let me just pop the matrix off the top of the stack, and there will be room". I modified the code to: def cube(): glPopMatrix() for x in xrange(10): glPushMatrix() glTranslated(-positionx[x + 1] * 10, 0, -positionz[x + 1] * 10); #translate the cube glutSolidCube(2); #draw the cube glPopMatrix(); And now I get a buffer underflow error - which apparently happens when the stack has only one matrix. So am I just waaay off base in my understanding? Or is there some way to increase the matrix stack size? Also, if anyone has some good (online) references (examples, etc.) for understanding how the camera/model matrices work together, I would sincerely appreciate them! Thanks!

    Read the article

  • Stack Trace Logger [migrated]

    - by Chris Okyen
    I need to write a parent Java class that classes using recursion can extend. The parent class will be be able to realize whenever the call stack changes ( you enter a method, temporarily leave it to go to another method call, or you are are finsihed with the method ) and then print it out. I want it to print on the console, but clear the console as well every time so it shows the stack horizantaly so you can see the height of each stack to see what popped off and what popped on... Also print out if a baseline was reached for recursive functions. First. How can I using the StackTraceElements and Thread classes to detect automatically whenever the stack has popped or pushed an element on without calling it manually? Second, how would I do the clearing thing? For instance , if I had the code: public class recursion(int i) { private static void recursion(int i) { if( i < 10) System.out.println('A'); else { recursion(i / 10 ); System.out.println('B'); } } public static void main(String[] argv) { recursion(102); } } It would need to print out the stack when entering main(), when entering recursion(102) from main(), when it enters recursion(102 / 10), which is recursion(10), from recursion(102), when it enters recursion(10 / 10), which is recursion(1) from recursion(10). Print out a message out when it reaches the baseline recursion(1).. then print out the stacks of reversed revisitation of function recursion(10), recursion(102) and main(). finally print out we are exiting main().

    Read the article

  • LAMP Stack Location

    - by Artem Moskalev
    I have installed the LAMP stack on Ubuntu 12.04 LTS using the tasksel command. I checked - it works. But I cant find the location of the installaton, I worked with WAMP - there you have a separate folder for Apache, for PHP and for mysql. Now I cant even find where to put the documents I create. Which folder is used to contain my web projects? How to start MySQL console and where to look for its installation directory? Which directories are PHP and Apache installed in? how to erase LAMP stack? I found out that some of the parts of the stack are installed in the root/var and root/etc directories: How can I install the whole LAMP stack in /home?

    Read the article

  • What's the demonym for people who use Stack Exchange or Stack Overflow? [closed]

    - by YatharthROCK
    What's the demonym† for people who use Stack Exchange and its network of sites? There's isn't a documented answer anywhere, so I'd like to know the general consensus. Suggestions and ideas are welcome too.‡ Give one answer per site: Stack Exchange Stack Overflow Super User Server Fault And any other site you think has one unique enough :) † Demonymns for or the collective noun used to refer to the people ‡ I asked it on English.SE too. Should I have done that? Would Meta.SO have been more appropriate?

    Read the article

  • How to mmap the stack for the clone() system call on linux?

    - by Joseph Garvin
    The clone() system call on Linux takes a parameter pointing to the stack for the new created thread to use. The obvious way to do this is to simply malloc some space and pass that, but then you have to be sure you've malloc'd as much stack space as that thread will ever use (hard to predict). I remembered that when using pthreads I didn't have to do this, so I was curious what it did instead. I came across this site which explains, "The best solution, used by the Linux pthreads implementation, is to use mmap to allocate memory, with flags specifying a region of memory which is allocated as it is used. This way, memory is allocated for the stack as it is needed, and a segmentation violation will occur if the system is unable to allocate additional memory." The only context I've ever heard mmap used in is for mapping files into memory, and indeed reading the mmap man page it takes a file descriptor. How can this be used for allocating a stack of dynamic length to give to clone()? Is that site just crazy? ;) In either case, doesn't the kernel need to know how to find a free bunch of memory for a new stack anyway, since that's something it has to do all the time as the user launches new processes? Why does a stack pointer even need to be specified in the first place if the kernel can already figure this out?

    Read the article

  • Neighbour table overflow on Linux hosts related to bridging and ipv6

    - by tim
    Note: I already have a workaround for this problem (as described below) so this is only a "want-to-know" question. I have a productive setup with around 50 hosts including blades running xen 4 and equallogics providing iscsi. All xen dom0s are almost plain Debian 5. The setup includes several bridges on every dom0 to support xen bridged networking. In total there are between 5 and 12 bridges on each dom0 servicing one vlan each. None of the hosts has routing enabled. At one point in time we moved one of the machines to a new hardware including a raid controller and so we installed an upstream 3.0.22/x86_64 kernel with xen patches. All other machines run debian xen-dom0-kernel. Since then we noticed on all hosts in the setup the following errors every ~2 minutes: [55888.881994] __ratelimit: 908 callbacks suppressed [55888.882221] Neighbour table overflow. [55888.882476] Neighbour table overflow. [55888.882732] Neighbour table overflow. [55888.883050] Neighbour table overflow. [55888.883307] Neighbour table overflow. [55888.883562] Neighbour table overflow. [55888.883859] Neighbour table overflow. [55888.884118] Neighbour table overflow. [55888.884373] Neighbour table overflow. [55888.884666] Neighbour table overflow. The arp table (arp -n) never showed more than around 20 entries on every machine. We tried the obvious tweaks and raised the /proc/sys/net/ipv4/neigh/default/gc_thresh* values. FInally to 16384 entries but no effect. Not even the interval of ~2 minutes changed which lead me to the conclusion that this is totally unrelated. tcpdump showed no uncommon ipv4 traffic on any interface. The only interesting finding from tcpdump were ipv6 packets bursting in like: 14:33:13.137668 IP6 fe80::216:3eff:fe1d:9d01 > ff02::1:ff1d:9d01: HBH ICMP6, multicast listener reportmax resp delay: 0 addr: ff02::1:ff1d:9d01, length 24 14:33:13.138061 IP6 fe80::216:3eff:fe1d:a8c1 > ff02::1:ff1d:a8c1: HBH ICMP6, multicast listener reportmax resp delay: 0 addr: ff02::1:ff1d:a8c1, length 24 14:33:13.138619 IP6 fe80::216:3eff:fe1d:bf81 > ff02::1:ff1d:bf81: HBH ICMP6, multicast listener reportmax resp delay: 0 addr: ff02::1:ff1d:bf81, length 24 14:33:13.138974 IP6 fe80::216:3eff:fe1d:eb41 > ff02::1:ff1d:eb41: HBH ICMP6, multicast listener reportmax resp delay: 0 addr: ff02::1:ff1d:eb41, length 24 which placed the idea in my mind that the problem maybe related to ipv6, since we have no ipv6 services in this setup. The only other hint was the coincidence of the host upgrade with the beginning of the problems. I powered down the host in question and the errors were gone. Then I subsequently took down the bridges on the host and when i took down (ifconfig down) one particularly bridge: br-vlan2159 Link encap:Ethernet HWaddr 00:26:b9:fb:16:2c inet6 addr: fe80::226:b9ff:fefb:162c/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:120 errors:0 dropped:0 overruns:0 frame:0 TX packets:9 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:5286 (5.1 KiB) TX bytes:726 (726.0 B) eth0.2159 Link encap:Ethernet HWaddr 00:26:b9:fb:16:2c inet6 addr: fe80::226:b9ff:fefb:162c/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:1801 errors:0 dropped:0 overruns:0 frame:0 TX packets:20 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:126228 (123.2 KiB) TX bytes:1464 (1.4 KiB) bridge name bridge id STP enabled interfaces ... br-vlan2158 8000.0026b9fb162c no eth0.2158 br-vlan2159 8000.0026b9fb162c no eth0.2159 The errors went away again. As you can see the bridge holds no ipv4 address and it's only member is eth0.2159 so no traffic should cross it. Bridge and interface .2159 / .2157 / .2158 which are in all aspects identical apart from the vlan they are connected to had no effect when taken down. Now I disabled ipv6 on the entire host via sysctl net.ipv6.conf.all.disable_ipv6 and rebooted. After this even with bridge br-vlan2159 enabled no errors occur. Any ideas are welcome.

    Read the article

  • 2D Grid Map Connectivity Check (avoiding stack overflow)

    - by SombreErmine
    I am trying to create a routine in C++ that will run before a more expensive A* algorithm that checks to see if two nodes on a 2D grid map are connected or not. What I need to know is a good way to accomplish this sequentially rather than recursively to avoid overflowing the stack. What I've Done Already I've implemented this with ease using a recursive algorithm; however, depending upon different situations it will generate a stack overflow. Upon researching this, I've come to the conclusion that it is overflowing the stack because of too many recursive function calls. I am sure that my recursion does not enter an infinite loop. I generate connected sets at the beginning of the level, and then I use those connected sets to determine connectivity on the fly later. Basically, the generating algorithm starts from left-to-right top-to-bottom. It skips wall nodes and marks them as visited. Whenever it reaches a walkable node, it recursively checks in all four cardinal directions for connected walkable nodes. Every node that gets checked is marked as visited so they aren't handled twice. After checking a node, it is added to either a walls set, a doors set, or one of multiple walkable nodes sets. Once it fills that area, it continues the original ltr ttb loop skipping already-visited nodes. I've also looked into flood-fill algorithms, but I can't make sense of the sequential algorithms and how to adapt them. Can anyone suggest a better way to accomplish this without causing a stack overflow? The only way I can think of is to do the left-to-right top-to-bottom loop generating connected sets on a row basis. Then check the previous row to see if any of the connected sets are connected and then join the sets that are. I haven't decided on the best data structures to use for that though. I also just thought about having the connected sets pre-generated outside the game, but I wouldn't know where to start with creating a tool for that. Any help is appreciated. Thanks!

    Read the article

  • Why is FxCop warning about an overflow (CA2233) in this C# code?

    - by matt
    I have the following function to get an int from a high-byte and a low-byte: public static int FromBytes(byte high, byte low) { return high * (byte.MaxValue + 1) + low; } When I analyze the assembly with FxCop, I get the following critical warning: CA2233: OperationsShouldNotOverflow Arithmetic operations should not be done without first validating the operands to prevent overflow. I can't see how this could possibly overflow, so I am just assuming FxCop is being overzealous. Am I missing something? And what steps could be taken to correct what I have (or at least make the FxCop warning go away!)?

    Read the article

  • Using CSS, how can I make overflow:visible; contents overlap adjacent <td> cells?

    - by Structure
    I have the following CSS style code for my table: td { overflow: hidden; white-space:nowrap; } td:hover { overflow: visible; } However, when I hover over a <td> element whos contents (text) are hidden, the result is that the contents become visible but are behind the content of the adjacent cell (right side). I do not think that z-index can be applied to table cell elements, so is there a CSS attribute that I can specify within my td:hover style which will make the content of my <td> tag overlap the content in adjacent cells?

    Read the article

  • When there's no TCO, when to worry about blowing the stack?

    - by Cedric Martin
    Every single time there's a discussion about a new programming language targetting the JVM, there are inevitably people saying things like: "The JVM doesn't support tail-call optimization, so I predict lots of exploding stacks" There are thousands of variations on that theme. Now I know that some language, like Clojure for example, have a special recur construct that you can use. What I don't understand is: how serious is the lack of tail-call optimization? When should I worry about it? My main source of confusion probably comes from the fact that Java is one of the most succesful languages ever and quite a few of the JVM languages seems to be doing fairly well. How is that possible if the lack of TCO is really of any concern?

    Read the article

  • Oracle Hash Cluster Overflow Blocks

    - by Andrew
    When inserting a large number of rows into a single table hash cluster in Oracle, it will fill up the block with any values that hash to that hash-value and then start using overflow blocks. These overflow blocks are listed as chained off the main block, but I can not find detailed information on the way in which they are allocated or chained. When an overflow block is allocated for a hash value, is that block exclusively allocated to that hash value, or are the overflow blocks used as a pool and different hash values can then start using the same overflow block. How is the free space of the chain monitored - in that, as data is continued to be inserted, does it have to traverse the entire chain to find out if it has some free space in the current overflow chain, and then if it finds none, it then chooses to allocate a new block?

    Read the article

  • Extra text shown on oveflow: hidden

    - by TRiG
    I'm keeping the main content area of the webpage small, so that footer navigation can be seen "above the fold". This is done by javascript setting the main content <div> thus: sec.style.height = '265px'; sec.style.overflow = 'hidden'; And then using javascript to insert a button to change the style back to normal: sec.style.height = 'auto'; The problem is that the cut-off point of 265px (dictated by the size of an image which I don't want to hide) doesn't quite match the gap between lines of text. This means that there the tops of tall letters show as funny little marks. Is there any way to hide text which is partially showing in a <div style="overflow: hidden;">? Edit to add: Full javascript var overflow = { hide: function() { var sec = app.get('content_section'); sec.style.height = '263px'; sec.style.overflow = 'hidden'; overflow.toggle(false); }, toggle: function(value) { var cnt = app.get('toggle_control'); if (value) { var func = 'hide'; cnt.innerHTML = 'Close « '; } else { var func = 'show'; cnt.innerHTML = 'More » '; } cnt.onclick = function() {eval('overflow.' + func + '();'); return false;}; cnt.style.cursor = 'pointer'; cnt.style.fontWeight = 'normal'; cnt.style.margin = '0 0 0 857px'; }, show: function() { var sec = app.get('content_section'); sec.style.height = 'auto'; overflow.toggle(true); } } if (document.addEventListener) { document.addEventListener('DOMContentLoaded', overflow.hide, false); } else { window.onload = function() {return overflow.hide();}; }

    Read the article

< Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >