Testing if a list contains another list with Python
- by None
How can I test if a list contains another list. Say there was a function called contains:
contains([1,2], [-1, 0, 1, 2]) # Returns [2, 3] (contains returns [start, end])
contains([1,3], [-1, 0, 1, 2]) # Returns False
contains([1, 2], [[1, 2], 3) # Returns False
contains([[1, 2]], [[1, 2], 3]) # Returns [0, 0]
Edit:
contains([2, 1], [-1, 0, 1, 2]) # Returns False
contains([-1, 1, 2], [-1, 0, 1, 2]) # Returns False
contains([0, 1, 2], [-1, 0, 1, 2]) # Returns [1, 3]
