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  • iPhone. How to get the rect of parent view?

    - by flexbyte
    Hi, My application creates two views: topView (CGRect = 0,0, 320,60) bottomView (CGRect = 0,60, 320,480) Bottom view creates UITabBarController with UIViewControllers: ListViewController etc... ListViewController has own views that are created in viewDidLoad method: background = [[UIImageView alloc] initWithFrame: rect ]; So my question is how to get the bottomView rect inside ListViewController? I want to layout all controller views without intersection with topView. Thank you.

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  • Android reset activity component state on navigation back

    - by Aure77
    I have 2 activities in my application. In activity1, I set some configuration and I modify the state of some component (ex: set button state disabled). And I navigate to activity2. In activity2 I do some stuff and at end, I finish this activity and come back to activity1. But In activity1, my components state are the same when I leave this activity. How to reset the components state with valuesdeclared in XML file (layout) ?

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  • Any wrapping viewgroup?

    - by user325737
    I am looking for Wrappable ViewGroup just like what TextView do. I need this for layout. This should be something like LinearLayout but wrappable to multiple lines. Or do I need something custom?

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  • How can I have a floating image (right aligned) with text that wraps around the image in Android Lay

    - by groomsy
    It's kind of hard to explain, but an example of what I'm wanting to accomplish is like this: Here is some text | image | that is printed | | out in a view and --------- it is wrapped around an image that is floating and right aligned. I thought about generating the layout in html and using a web view, but I need to be able to perform an action when the user clicks on the image. Does anyone have any ideas? Thanks in advance, groomsy

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  • GIT repository layout for server with multiple projects

    - by Paul Alexander
    One of the things I like about the way I have Subversion set up is that I can have a single main repository with multiple projects. When I want to work on a project I can check out just that project. Like this \main \ProductA \ProductB \Shared then svn checkout http://.../main/ProductA As a new user to git I want to explore a bit of best practice in the field before committing to a specific workflow. From what I've read so far, git stores everything in a single .git folder at the root of the project tree. So I could do one of two things. Set up a separate project for each Product. Set up a single massive project and store products in sub folders. There are dependencies between the products, so the single massive project seems appropriate. We'll be using a server where all the developers can share their code. I've already got this working over SSH & HTTP and that part I love. However, the repositories in SVN are already many GB in size so dragging around the entire repository on each machine seems like a bad idea - especially since we're billed for excessive network bandwidth. I'd imagine that the Linux kernel project repositories are equally large so there must be a proper way of handling this with Git but I just haven't figured it out yet. Are there any guidelines or best practices for working with very large multi-project repositories?

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  • How to prevent the floating layout wrapping when firefox zoom is reduced

    - by Dmitri Zhuchkov
    Given the following HTML. It display two columns: #left, #right. Both are fixed width and have 1px borders. Width and borders equal the size of upper container: #wrap. When I zoom out Firefox 3.5.2 by pressing Ctrl+- columns get wrapped (demo). How to prevent this? <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Test</title> <style type="text/css"> div {float:left} #wrap {width:960px} #left, #right {width:478px;border:1px solid} </style> </head> <body> <div id="wrap"> <div id="left"> left </div> <div id="right"> right </div> </div> </body> </html>

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  • css layout - break down

    - by Luke
    So I am trying to get the effect of having two frames inside a 750px wide frame. .news {width: 750px;} .news1 {width:550px;} .news2 {width:200px;} Very simple css at this stage. The html/php: <div class="news"> <div class="format"><a href='newspiece.php?news=<?echo $id?>'><?echo "$subject\n";?></a></div> <div class="news1"> <? echo "<div class='content'>"; echo nl2br($comment); echo "<a href='newspiece.php?news=$id'>..[read more]..</a>\n"; echo "</div>"; ?> <h5><? echo "Posted by <a href=\"userprofile.php?user=$posted\">$posted</a> on $final_date\n";?></h5> <? echo "<br />\n";?> </div> <div class="news2"> <img src="images/news/<? echo $id?>.jpg" /> </div> </div>] THe problem I am getting is that the image that should be on the right is going underneath. So in effect, news1 is above news2, rather than side by side. Any ideas?

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  • when rendering the page on different browsers layout changes

    - by user1776590
    I have create a website using asp.net and when I render the the website on firefox and IE the website look the same and when rendering it on Chrome it move the button lower and changes the location of it this is my master page code <%@ Master Language="C#" AutoEventWireup="true" CodeBehind="UMSite.master.cs" Inherits="WebApplication4.UMSiteMaster" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head runat="server"> <title></title> <link href="~/Styles/UM.css" rel="stylesheet" type="text/css" /> <asp:ContentPlaceHolder ID="HeadContent" runat="server"> </asp:ContentPlaceHolder> </head> <body> <form id="Form1" runat="server"> <div class="page"> <div class="header"> <div class="title"> <h1><img alt="" src="Styles/UMHeader.png" width= "950" height= "65" /></h1> <div class="clear hideSkiplink"> <asp:Menu ID="NavigationMenu" runat="server" CssClass="menu" EnableViewState="false" IncludeStyleBlock="false" Orientation="Horizontal"> <Items> <asp:MenuItem NavigateUrl="~/Home.aspx" Text="Home"/> </Items> </asp:Menu> </div> </div> </div></h1> <div class="main" runat="server"> <asp:ContentPlaceHolder ID="MainContent" runat="server"/> </div> </form> </body> </html> the below is the css /* DEFAULTS ----------------------------------------------------------*/ body { background: #b6b7bc; font-size: .80em; font-family: "Helvetica Neue", "Lucida Grande", "Segoe UI", Arial, Helvetica, Verdana, sans-serif; margin: 0px; padding: 0px; color: #696969; height: 192px; } a:link, a:visited { color: #034af3; } a:hover { color: #1d60ff; text-decoration: none; } a:active { color: #034af3; } p { margin-bottom: 10px; line-height: 1.6em; } /* HEADINGS ----------------------------------------------------------*/ h1, h2, h3, h4, h5, h6 { font-size: 1.5em; color: #666666; font-variant: small-caps; text-transform: none; font-weight: 200; margin-bottom: 0px; } h1 { font-size: 1.6em; padding-bottom: 0px; margin-bottom: 0px; } h2 { font-size: 1.5em; font-weight: 600; } h3 { font-size: 1.2em; } h4 { font-size: 1.1em; } h5, h6 { font-size: 1em; } /* this rule styles <h1> and <h2> tags that are the first child of the left and right table columns */ .rightColumn > h1, .rightColumn > h2, .leftColumn > h1, .leftColumn > h2 { margin-top: 0px; } /* PRIMARY LAYOUT ELEMENTS ----------------------------------------------------------*/ .page { width: 950px; height:auto; background-color: #fff; margin: 10px auto 5px auto; border: 1px solid #496077; } .header { position:relative; margin: 0px; padding: 0px; background: #E30613; width: 100%; top: 0px; left: 0px; height: 90px; } .header h1 { font-weight: 700; margin: 0px; padding: 0px 0px 0px 0px; color: #E30613; border: none; line-height: 2em; font-size: 2em; } .main { padding: 0px 12px; margin: 0px 0px 0px 0px; min-height: 630px; width:auto; background-image:url('UMBackground.png'); } .leftCol { padding: 6px 0px; margin: 0px 0px 0px 0px; width: 200px; min-height: 200px; width:auto; } .footer { color: #4e5766; padding: 0px 0px 0px 0px; margin: 0px auto; text-align: center; line-height: normal; } /* TAB MENU ----------------------------------------------------------*/ div.hideSkiplink { background-color:#E30613; width: 950px; height: 35px; margin-top: 0px; } div.menu { padding: 1px 0px 1px 2px; } div.menu ul { list-style: none; margin: 0px; padding: 5px; width: auto; } div.menu ul li a, div.menu ul li a:visited { background-color: #E30613; border: 1.25px #00BFFF solid; color: #F5FFFA; display:inline; line-height: 1.35em; padding: 10px 30px; text-decoration: none; white-space: nowrap; } div.menu ul li a:hover { background-color: #000000; color: #F5FFFA; text-decoration: none; } div.menu ul li a:active { background-color: #E30613; color: #cfdbe6; text-decoration: none; } /* FORM ELEMENTS ----------------------------------------------------------*/ fieldset { margin: 1em 0px; padding: 1em; border: 1px solid #ccc; } fieldset p { margin: 2px 12px 10px 10px; } fieldset.login label, fieldset.register label, fieldset.changePassword label { display: block; } fieldset label.inline { display: inline; } legend { font-size: 1.1em; font-weight: 600; padding: 2px 4px 8px 4px; } input.textEntry { width: 320px; border: 1px solid #ccc; } input.passwordEntry { width: 320px; border: 1px solid #ccc; } div.accountInfo { width: 42%; } /* MISC ----------------------------------------------------------*/ .clear { clear: both; } .title { display: block; float: left; text-align: left; width: 947px; height: 132px; } .loginDisplay { font-size: 1.1em; display: block; text-align: right; padding: 10px; color: White; } .loginDisplay a:link { color: white; } .loginDisplay a:visited { color: white; } .loginDisplay a:hover { color: white; } .failureNotification { font-size: 1.2em; color: Red; } .bold { font-weight: bold; } .submitButton { text-align: right; padding-right: 10px; }

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  • C two functions in one with casts

    - by Favolas
    I have two functions that do the exact same thing but in two different types of struct and this two types of struct are very similar. Imagine I have this two structs. typedef struct nodeOne{ Date *date; struct nodeOne *next; struct nodeOne *prev; }NodeOne; typedef struct nodeTwo{ Date *date; struct nodeTwo *next; struct nodeTwo *prev; }NodeTwo; Since my function to destroy each of the list is almost the same (Just the type of the arguments are different) I would like to make just one function to make the two thins. I have this two functions void destroyListOne(NodeOne **head, NodeOne **tail){ NodeOne *aux; while (*head != NULL){ aux = *head; *head = (*head)->next; free(aux); } *tail = NULL; } and this one: void destroyListTwo(NodeTwo **head, NodeTwo **tail){ NodeTwo *aux; while (*head != NULL){ aux = *head; *head = (*head)->next; free(aux); } *tail = NULL; } Since they are very similar I thought making something like this: void destroyList(void **ini, void **end, int listType){ if (listType == 0) { NodeOne *aux; NodeOne head = (NodeOne) ini; NodeOne tail = (NodeOne) ed; } else { NodeTwo *aux; NodeTwo head = (NodeTwo) ini; NodeTwo tail = (NodeTwo) ed; } while (*head != NULL){ aux = *head; *head = (*head)->next; free(aux); } *tail = NULL; } As you may now this is not working but I want to know if this is possible to achieve. I must maintain both of the structs as they are.

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  • NHibernate mapping with two special cases

    - by brainimus
    I am using NHibernate to map a class to a database table. The Part table has an ID column (primary key) and a ParentPart column (along with a few others). class Part { public virtual long ID{ get; set; } public virtual Part ParentPart { get; set; } } The ParentPart is normally another valid part in the part table but I have two special cases. I have a case where the ParentPart column can be 0 (zero) and another case where it can be -1. Neither of these cases currently represent another valid Part object. I was thinking I could make 2 subclasses of Part (ZeroPart and NegativeOnePart) that would never persist. I want the zero and -1 values to be entered in the column but not persist the entire ZeroPart or NegativeOnePart objects. I am unsure how to map this (I'm using hbm files) or if this even the correct approach. How can I map this so that normal valid parts are persisted but I can also handle the special cases? As an aside: My current hbm file has the Part.ID's unsaved value as zero but I think I can just change this in the mapping to something different and default it in the class.

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  • How to insert and call by row and column into sqlite3 python, great tutorial problem.

    - by user291071
    Lets say i have a simple array of x rows and y columns with corresponding values, What is the best method to do 3 things? How to insert, update a value at a specific row column? How to select a value for each row and column, import sqlite3 con = sqlite3.connect('simple.db') c = con.cursor() c.execute('''create table simple (links text)''') con.commit() dic = {'x1':{'y1':1.0,'y2':0.0},'x2':{'y1':0.0,'y2':2.0,'y3':1.5},'x3':{'y2':2.0,'y3':1.5}} ucols = {} ## my current thoughts are collect all row values and all column values from dic and populate table row and columns accordingly how to call by row and column i havn't figured out yet ##populate rows in first column for row in dic: print row c.execute("""insert into simple ('links') values ('%s')"""%row) con.commit() ##unique columns for row in dic: print row for col in dic[row]: print col ucols[col]=dic[row][col] ##populate columns for col in ucols: print col c.execute("alter table simple add column '%s' 'float'" % col) con.commit() #functions needed ##insert values into sql by row x and column y?how to do this e.g. x1 and y2 should put in 0.0 ##I tried as follows didn't work for row in dic: for col in dic[row]: val =dic[row][col] c.execute("""update simple SET '%s' = '%f' WHERE 'links'='%s'"""%(col,val,row)) con.commit() ##update value at a specific row x and column y? ## select a value at a specific row x and column y?

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  • How to identify multiple identical pairs in two vectors

    - by Sacha Epskamp
    In my graph-package (as in graph theory, nodes connected by edges) I have a vector indicating for each edge the node of origin from, a vector indicating for each edge the node of destination to and a vector indicating the curve of each edge curve. By default I want edges to have a curve of 0 if there is only one edge between two nodes and curve of 0.2 if there are two edges between two nodes. The code that I use now is a for-loop, and it is kinda slow: curve <- rep(0,5) from<-c(1,2,3,3,2) to<-c(2,3,4,2,1) for (i in 1:length(from)) { if (any(from==to[i] & to==from[i])) { curve[i]=0.2 } } So basically I look for each edge (one index in from and one in to) if there is any other pair in from and to that use the same nodes (numbers). What I am looking for are two things: A way to identify if there is any pair of nodes that have two edges between them (so I can omit the loop if not) A way to speed up this loop # EDIT: To make this abit clearer, another example: from <- c(4L, 6L, 7L, 8L, 1L, 9L, 5L, 1L, 2L, 1L, 10L, 2L, 6L, 7L, 10L, 4L, 9L) to <- c(1L, 1L, 1L, 2L, 3L, 3L, 4L, 5L, 6L, 7L, 7L, 8L, 8L, 8L, 8L, 10L, 10L) cbind(from,to) from to [1,] 4 1 [2,] 6 1 [3,] 7 1 [4,] 8 2 [5,] 1 3 [6,] 9 3 [7,] 5 4 [8,] 1 5 [9,] 2 6 [10,] 1 7 [11,] 10 7 [12,] 2 8 [13,] 6 8 [14,] 7 8 [15,] 10 8 [16,] 4 10 [17,] 9 10 In these two vectors, pair 3 is identical to pair 10 (both 1 and 7 in different orders) and pairs 4 and 12 are identical (both 2 and 8). So I would want curve to become: [1,] 0.0 [2,] 0.0 [3,] 0.2 [4,] 0.2 [5,] 0.0 [6,] 0.0 [7,] 0.0 [8,] 0.0 [9,] 0.0 [10,] 0.2 [11,] 0.0 [12,] 0.2 [13,] 0.0 [14,] 0.0 [15,] 0.0 [16,] 0.0 [17,] 0.0 (as I vector, I transposed twice to get row numbers).

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  • How to set size for divs with different parents

    - by user340524
    I want to create a div layout which is similiar to the following table result: <html> <head> <title>Basic</title> <style> table { border: 1px solid;} </style> </head> <body> <table style="border: 1px solid;"> <tr> <td> Asia</td> <td> <table> <tr> <td>South Asia</td> </td> <td><table> <tr> <td>Republic</td> <td><table> <tr><td>Singapore</td></tr> <tr><td>India</td></tr> </table></td> </tr> <tr> <td>Monarchy</td> <td><table> <tr><td>Bhutan</td></tr> <tr><td>Nepal</td></tr> </table></td> </tr> </table></td> </tr> <tr> <td>East Asia</td> <td><table> <tr> <td>Republic</td> <td><table> <tr><td>China</td></tr> <tr><td>South Corea</td></tr> </table></td> </tr> <tr> <td>Constitutional Monarchy</td> <td><table> <tr><td>something</td></tr> <tr><td>Japan</td></tr> </table></td> </tr> </table></td> </tr> </table></td> </tr> </table> </body> </html> I managed to replicate this with some effort. The problem is that I want the names of the countries to be in a column or if you will - the containers for the government types to be the same width so other containers will align. If I don't do it in nested containers (in the example - nested tables) the rows will get displaced. Currently rows are shown exactly how I want them - the text is in the vertical middle of the what they refer to. Only thing that comes up to my mind is to set the text in the same columns as class=column1, class=column2, etc. and then somehow define the width for the column classes. Problem is the data is defined dynamically and I can't say how much pixels or % of the page I can give to a column, I just need it to stretch with the text. This is my first time I ask about help here so if I am doing it wrong, tell me how do improve my inquiry.

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  • Qt - 2 QMainWindow glued - Size of Layout

    - by user1773603
    I have a main window that I center this way in main.cpp : int main(int argc, char *argv[]) { QApplication app(argc, argv); QMainWindow *qmain = new QMainWindow; Ui_MainWindow ui; ui.setupUi(qmain); QRect r = qmain->geometry(); r.moveCenter(QApplication::desktop()->availableGeometry().center()); qmain->setGeometry(r); qmain->show(); return app.exec(); } In this "qmain" main window, I can create another QMainWindow and I try to make stick (or glue I don't know how to say) the two windows. Actually, I would like the right-top corner of the first one to be located at the left-top of the second one. For this, I use the following Ui_MainWindow's member function : void Ui_MainWindow::generate_IC() { qmenu = new QMainWindow; DiskMenu = new Ui_DiskGalMenu; DiskMenu->setupUi(qmenu); setInitialDiskMenuPosition(qmenu, this); qmenu->show(); } and the setInitialDiskMenuPosition : void Ui_MainWindow::setInitialDiskMenuPosition(QMainWindow *MainWindow, Ui_MainWindow *parent) { QSize size = parent->widget->size(); QDesktopWidget* desktop = QApplication::desktop(); int width = desktop->width(); int height = desktop->height(); int mw = size.width(); int mh = size.height(); int right = (width/2) + (mw/2); int top = (height/2) - (mh/2); MainWindow->move(right, top); } But the problem is that I don't get exactly what I want since the centralwidget size "parent- widget-size()" only returns the size of the widget and not the whole "qmain" parent window. So I have a light shift because the borders of the "qmain" window are not taken in account like it is shown below : If I could have access to the size of the whole parent window... If anyone could help me

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  • Exchange 2007 two node cluster setup on Windows 2008 Enterprise, install error

    - by Shadow00Caster
    I am installing Microsoft Exchange 2007 x64 in a two node environment using Microsoft Windows 2008 Enterprise x64. The Failover Cluster is all setup properly and following best practices for setting up the windows clustering for use with Exchange 2007. All the validation tests pass on the cluster and all of that portion is working fine. The problem is when I go to install the first Exchange node as an Active mailbox in configuration for a two node CCR. It gets all the way through the first 3 steps (Copy Exchange Files, Management Tools, Mailbox Role) and then fails on the 4th step 'Clustered Mailbox Server' with the following error: Error: The clustered mailbox server's group 'XXXX' was not found, and should already exist. Firewalls are all disabled, DNS is all setup properly, the environment has 3 domain controllers all 2k8 ent x64, all replication works. The name I pick for the CCR cluster (XXX) does not exist in AD or in DNS. I have attempted this install from both of the two Exchange nodes and multiple times .. tried with different names. I have been banging my head against the wall for days working on this and would appreciate any feedback on the issue.

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  • Splitting Servers into Two Groups

    - by Matt Hanson
    At our organization, we're looking at implementing some sort of informal internal policy for server maintenance. What we're looking at doing is completing maintenance on our entire server pool every two months; each month we'll do half of the servers. What I'm trying to figure out is some way to split the servers into the two groups. Our naming convention isn't much to be desired (but getting better) so by name or number doesn't really work. I can easily take a list of all the servers and split them in two, but with new servers are being added constantly, and old ones retired, that list would be a headache to maintain. I'd like to look at any given server and know if it should have its maintenance done this month or next. For example, it would be nice to look at the serial number. If it started with an even number, then it gets maintenance done on even months and vice-versa. This example won't work though as a little over half of the servers are virtual. Any ideas?

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  • how to initialize two logical drives on a HP P400i controller without reboot

    - by John
    What I am trying to do is initialize two logical drives on a HP P400i embedded controller without a reboot of the system here my current Array config: array A (SAS, Unused Space: 0 MB) logicaldrive 1 (17.9 GB, RAID 5, OK) logicaldrive 2 (17.9 GB, RAID 5, OK) logicaldrive 3 (75.9 GB, RAID 5, OK) logicaldrive 4 (25.0 GB, RAID 5, OK) physicaldrive 1I:1:1 (port 1I:box 1:bay 1, SAS, 72 GB, OK) physicaldrive 1I:1:2 (port 1I:box 1:bay 2, SAS, 72 GB, OK) physicaldrive 1I:1:3 (port 1I:box 1:bay 3, SAS, 72 GB, OK) array B (SAS, Unused Space: 0 MB) logicaldrive 5 (99 MB, RAID 0, OK) logicaldrive 6 (68.2 GB, RAID 0, OK) physicaldrive 1I:1:4 (port 1I:box 1:bay 4, SAS, 72 GB, OK) windows 2003 machine running the HpCISs2.sys driver version 6.20.0.32 . I have the ACU and ACU CLI tools installed version 8.28.13.0, P400i firmware version 2.74 . Now what I'd like to do is removes the physical drive 1I:1:4 and delete the two logical drives in array B. then insert a new drive in to bay 4 that contains two new logical drives and have them show up in array B again. So far after I remove the drive and delete the failed logical drives, I insert the new drive and run HPacucli rescan. I get the new drive to show up as unassinged physical drive but I cant figure out now to "for lack of a better word" mount the 2 logical drives on the new unassinged disk. If I reboot the system the array controller picks up the new fourth drive and creates Array B with the drives without problem but I'd really like to not have to reboot the server. Any ideas?

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  • How to sync two computers using new MobileMe calendar

    - by CesarGon
    I have been using MobileMe for over a year with success. I use it to sync my Outlook calendars in my work and home computers, using Windows 7 and Outlook 2007. The main Outlook calendar folder in my work computer is replicated to MobileMe as "Work", and synced to my home computer, and the main calendar folder in my home computer is replicated to MobileMe as "Home", and synced to my work computer. This means that I can see both "Work" and "Home" calendars from both computers (as well as from the web interface through me.com), which is very convenient. Yesterday I migrated to the new MobileMe calendar, accepting the suggestion that popped up on the me.com website. After the migration, the MobileMe control panel on each of Windows computers asked me to re-configure my calendar setup, and everything fell apart. The "Home" and "Work" calendar folders in Outlook are now ignored by MobileMe, and new ones named "Home in MobileMe" and "Work in MobileMe" have been created, and placed in a separate Outlook data file rather than the default. This means that now: I now have four folders, two of which are not replicated to MobileMe The two folders that are not replicated reside on a separate data file, so alarms and reminders don't work; they're basically useless to me as calendar folders In addition, the button in the MobileMe Control Panel that used to let me specify what MobileMe folder should be synced against the default Outlook folder has gone. MobileMe is now too smart. Do you have any idea how to undo this mess and go back to a situation where I have two folders, as described in the top paragraph, which keep synced? I don't want an extra data file. Thanks.

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  • Hardware needed to route between two networks over wireless

    - by AptDweller
    I recently rented an apartment about 100 yards from my brother's house. I have line of sight to his house and can pick up his home AP signal with one of my two laptops if I go out on my balcony (facing his house) or put the laptop by the window. The other laptop will sometimes see the SSID broadcast, but fails to connect, drops, etc. We would like to set up a persistent wireless connection between our homes. We would prefer each network be logically segmented as independent networks, but he will share his internet connection. I've got a bunch of tv shows saved to a NAS by my TiVO that I'd like to make available to him across the wireless link. My brother strongly prefers to not mess with his WAP at all. His network is running fine and is afraid to mess it up. I guess you could say he is "technologically declined". If we can get a reliable 11Mbps connection we will be satisfied. What hardware do I need to make this work? I was thinking a router with two wireless interfaces (external antennas) a wired interface, and a directional antenna mounted on my balcony facing his house. Can anyone recommend hardware to make this happen? Cheaper is better. I'll only be living in the area a year or two. I do have an old satellite TV antenna if that can be used to direct the signal.

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  • Extending a home wireless network using two routers running tomato

    - by jalperin
    I have two Asus RT-N16 routers each flashed with Tomato (actually Tomato USB). UPSTAIRS: Router 'A' (located upstairs) is connected to the internet via the WAN port and connected via a LAN port to a 10/100/1000 switch (Switch A). Several desktops are also attached to Switch A. Router A uses IP 192.168.1.1. DOWNSTAIRS: I've just acquired Router 'B' and set it to IP 192.168.1.2. I have a cable running from Switch A downstairs to another switch (Switch B). Tivo, a blu-ray player and a Mac are connected to Switch B. My plan was to connect Router B to Switch B so that I have improved wireless access downstairs. (The wireless signal from Router A gets weak downstairs in a number of locations.) How should I configure Router B so that all devices in the house can see and talk to one another? I know that I need to change DHCP on Router B so that it doesn't cover the same range as DHCP on Router A. Should I be using WDS on the two routers, or is that unnecessary since I already have a wired connection between the two routers? Any other thoughts or suggestions? Thanks! --Jeff

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  • Creating a bootable USB drive from a distro split over two DVD ISOs

    - by Kev
    I am searching and not finding the right way to do this. Please note, I don't think I'm trying for anything strange here. I just want to make a bootable USB stick of a single OS that happens to be larger than one DVD and happens to be larger than FAT32 will allow for in a single file. On our slow connection I spent a long time downloading CentOS 5.9's two DVD ISOs: CentOS-5.9-x86_64-bin-DVD-1of2.iso (4.4 GB) CentOS-5.9-x86_64-bin-DVD-2of2.iso (718 MB) I have a USB stick that I want to somehow get these two ISOs on. Since the first one is 4.4 GB, I can't use ISO2USB because it insists on FAT32. I cannot find an alternative that lets you specify more than one ISO image--of the same distro, I'm not trying for some fancy multi-boot thing--to put on the same stick. I guess I should have downloaded the CD ISOs, but I thought I was "saving time" because then I wouldn't have as many files to run through the md5 checker. There's no IMG file of the whole thing (only a net install version, which I don't want--I want to pre-download everything) otherwise I would've gone for that. So, given that I have these two DVD ISOs, how can I get them on a stick that will boot and make use of both of them properly to install CentOS somewhere? Again, I don't think this is anything out of the ordinary, yet I can't find software/docs that seem to support this. Am I stuck re-downloading everything in CD-sized ISOs just to do this? I found this, but it doesn't run on Windows. I am using Windows to prepare the stick.

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  • Two hosts on same subnet can't see each other

    - by Joey Hewitt
    I've got two routers with two separate public IP addresses on the same subnet, but I can't get them to talk to each other. Both are connected to the internet (ISP-provided gateway) via Ethernet ports provided by the landlord, but I don't have access to or knowledge of how those are physically connected or the protocols used to get back to the ISP. I can ping either from the outside, but they can't ping each other. Traceroutes in and out look the same, and they receive the same gateway over DHCP. I can ping other IPs on the subnet, so I assume this is not any sort of intentional isolation for security/privacy. Since I'm in a setup where my landlord provides internet and we don't have contact with the ISP, I can't really ask the ISP for help (doubt the landlord would know much either.) The situation is similar to the diagram at this question, but instead of the two servers, there's another router coming off the (presumed) switch, and I don't have access to the switch. I've tried giving them static routes to each other with the ISP internet gateway as the gateway, but that's not working. One is a Linksys WRT54GL running DD-WRT, the other is a Netgear WGR614v7, although I could get something more capable if necessary. I'd like to keep them each connected directly to the ISP on their WAN ports, but I can have an ethernet cable between them if necessary - I'm wondering if there's a way without that, and if there isn't, I'd appreciate advice on how to get that working. Sorry this is so nitpicky; there are reasons for all the constraints, but they don't apply to the real question, so I left them out. ;) Thank you!

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  • Problem mirroring two monitors with different resolution

    - by quad
    Hello I am trying to put two monitors in mirror mode (Windows 7 Professional) with Ultramon 3.1.0. The two monitors: Main monitor: 24" Asus. 1680x1050 resolution (16/10). Secondary monitor: 19" LG. 1280x1024 resolution. The graphic card is a Nvidia GeForce 8600 GT. I have installed the Ultramon 3.1.0 and I have created a mirror, with the "stretch mirror image to fill monitor" and the "disable video overlays and 3D acceleration". When I start the mirroring, there are two zones in the lateral edges that are not displayed in the second monitor. I think this is because the width of the main monitor is 1680 px. and the width of the secondary monitor is 1280 px., but I have indicated "stretch mirror image to fill monitor" in the options. The same occurs in the top and the bottom edges, but the diference is minimal (1050 vs 1024 pixels). I want the same image (distortioned in the secondary monitor if is neccesary), but I don't know what is failing. Someone can help me, please? I have read Mirrored monitors of different resolution. Cloned screen on monitors with different resolutions

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