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  • Dlink DWA-556 Access point fails to start on 2.6.35-25 while 2.6.35-24 works. How can I do this with >2.6.35-24?

    - by Azendale
    I'm using hostapd to run an access point with a Dlink DWA-556 wireless N card. However, I can no longer get it to start when I use kernels greater than 2.6.35-24. Here's a log where I ran the uname -a&&hostapd -c <configfile> on the different kernel versions. Linux erikbandersen 2.6.35-24-generic #42-Ubuntu SMP Thu Dec 2 02:41:37 UTC 2010 x86_64 GNU/Linux Configuration file: hostapd.conf ctrl_interface_group=0 Opening raw packet socket for ifindex 248 BSS count 1, BSSID mask ff:ff:ff:ff:ff:ff (0 bits) SIOCGIWRANGE: WE(compiled)=22 WE(source)=21 enc_capa=0xf nl80211: Added 802.11b mode based on 802.11g information HT40: control channel: 2 secondary channel: 6 RATE[0] rate=10 flags=0x2 RATE[1] rate=20 flags=0x6 RATE[2] rate=55 flags=0x6 RATE[3] rate=110 flags=0x6 RATE[4] rate=60 flags=0x0 RATE[5] rate=90 flags=0x0 RATE[6] rate=120 flags=0x0 RATE[7] rate=180 flags=0x0 RATE[8] rate=240 flags=0x0 RATE[9] rate=360 flags=0x0 RATE[10] rate=480 flags=0x0 RATE[11] rate=540 flags=0x0 Passive scanning not supported Mode: IEEE 802.11g Channel: 2 Frequency: 2417 MHz Flushing old station entries Deauthenticate all stations Using interface wlan1 with hwaddr 1c:bd:b9:d5:e8:3c and ssid 'erikbandersen.com/freewifi' wlan1: Setup of interface done. MGMT (TX callback) ACK Malformed netlink message: len=436 left=256 plen=420 256 extra bytes in the end of netlink message MGMT (TX callback) ACK mgmt::proberesp cb MGMT (TX callback) ACK mgmt::proberesp cb MGMT (TX callback) ACK mgmt::proberesp cb mgmt::auth authentication: STA=3c:4a:92:0e:41:2f auth_alg=0 auth_transaction=1 status_code=0 wep=0 New STA wlan1: STA 3c:4a:92:0e:41:2f IEEE 802.11: authentication OK (open system) wlan1: STA 3c:4a:92:0e:41:2f MLME: MLME-AUTHENTICATE.indication(3c:4a:92:0e:41:2f, OPEN_SYSTEM) wlan1: STA 3c:4a:92:0e:41:2f MLME: MLME-DELETEKEYS.request(3c:4a:92:0e:41:2f) authentication reply: STA=3c:4a:92:0e:41:2f auth_alg=0 auth_transaction=2 resp=0 (IE len=0) MGMT (TX callback) ACK mgmt::auth cb wlan1: STA 3c:4a:92:0e:41:2f IEEE 802.11: authenticated mgmt::assoc_req association request: STA=3c:4a:92:0e:41:2f capab_info=0x421 listen_interval=10 Validating WMM IE: OUI 00:50:f2 OUI type 2 OUI sub-type 0 version 1 QoS info 0x0 HT: STA 3c:4a:92:0e:41:2f HT Capabilities Info: 0x102c handle_assoc STA 3c:4a:92:0e:41:2f - no greenfield, num of non-gf stations 1 handle_assoc STA 3c:4a:92:0e:41:2f - 20 MHz HT, num of 20MHz HT STAs 1 hostapd_ht_operation_update current operation mode=0x0 hostapd_ht_operation_update new operation mode=0x7 changes=2 new AID 1 wlan1: STA 3c:4a:92:0e:41:2f IEEE 802.11: association OK (aid 1) MGMT (TX callback) ACK mgmt::assoc_resp cb wlan1: STA 3c:4a:92:0e:41:2f IEEE 802.11: associated (aid 1) wlan1: STA 3c:4a:92:0e:41:2f MLME: MLME-ASSOCIATE.indication(3c:4a:92:0e:41:2f) wlan1: STA 3c:4a:92:0e:41:2f MLME: MLME-DELETEKEYS.request(3c:4a:92:0e:41:2f) wlan1: STA 3c:4a:92:0e:41:2f RADIUS: starting accounting session 4DAC8224-00000000 MGMT (TX callback) ACK mgmt::action cb MGMT (TX callback) ACK mgmt::proberesp cb MGMT (TX callback) ACK mgmt::proberesp cb MGMT (TX callback) ACK mgmt::proberesp cb MGMT (TX callback) ACK mgmt::proberesp cb MGMT (TX callback) ACK mgmt::proberesp cb Signal 2 received - terminating wlan1: STA 3c:4a:92:0e:41:2f MLME: MLME-DEAUTHENTICATE.indication(3c:4a:92:0e:41:2f, 1) wlan1: STA 3c:4a:92:0e:41:2f MLME: MLME-DELETEKEYS.request(3c:4a:92:0e:41:2f) Removing station 3c:4a:92:0e:41:2f hostapd_ht_operation_update current operation mode=0x7 hostapd_ht_operation_update new operation mode=0x0 changes=2 Flushing old station entries Deauthenticate all stations . Linux erikbandersen 2.6.35-25-generic #44-Ubuntu SMP Fri Jan 21 17:40:44 UTC 2011 x86_64 GNU/Linux Configuration file: hostapd.conf ctrl_interface_group=0 Opening raw packet socket for ifindex 248 BSS count 1, BSSID mask ff:ff:ff:ff:ff:ff (0 bits) SIOCGIWRANGE: WE(compiled)=22 WE(source)=21 enc_capa=0xf nl80211: Added 802.11b mode based on 802.11g information Allowed channel: mode=1 chan=1 freq=2412 MHz max_tx_power=27 dBm Allowed channel: mode=1 chan=2 freq=2417 MHz max_tx_power=27 dBm Allowed channel: mode=1 chan=3 freq=2422 MHz max_tx_power=27 dBm Allowed channel: mode=1 chan=4 freq=2427 MHz max_tx_power=27 dBm Allowed channel: mode=1 chan=5 freq=2432 MHz max_tx_power=27 dBm Allowed channel: mode=1 chan=6 freq=2437 MHz max_tx_power=27 dBm Allowed channel: mode=1 chan=7 freq=2442 MHz max_tx_power=27 dBm Allowed channel: mode=1 chan=8 freq=2447 MHz max_tx_power=27 dBm Allowed channel: mode=1 chan=9 freq=2452 MHz max_tx_power=27 dBm Allowed channel: mode=1 chan=10 freq=2457 MHz max_tx_power=27 dBm Allowed channel: mode=1 chan=11 freq=2462 MHz max_tx_power=27 dBm Allowed channel: mode=0 chan=1 freq=2412 MHz max_tx_power=27 dBm Allowed channel: mode=0 chan=2 freq=2417 MHz max_tx_power=27 dBm Allowed channel: mode=0 chan=3 freq=2422 MHz max_tx_power=27 dBm Allowed channel: mode=0 chan=4 freq=2427 MHz max_tx_power=27 dBm Allowed channel: mode=0 chan=5 freq=2432 MHz max_tx_power=27 dBm Allowed channel: mode=0 chan=6 freq=2437 MHz max_tx_power=27 dBm Allowed channel: mode=0 chan=7 freq=2442 MHz max_tx_power=27 dBm Allowed channel: mode=0 chan=8 freq=2447 MHz max_tx_power=27 dBm Allowed channel: mode=0 chan=9 freq=2452 MHz max_tx_power=27 dBm Allowed channel: mode=0 chan=10 freq=2457 MHz max_tx_power=27 dBm Allowed channel: mode=0 chan=11 freq=2462 MHz max_tx_power=27 dBm HT40: control channel: 2 secondary channel: 6 RATE[0] rate=10 flags=0x2 RATE[1] rate=20 flags=0x6 RATE[2] rate=55 flags=0x6 RATE[3] rate=110 flags=0x6 RATE[4] rate=60 flags=0x0 RATE[5] rate=90 flags=0x0 RATE[6] rate=120 flags=0x0 RATE[7] rate=180 flags=0x0 RATE[8] rate=240 flags=0x0 RATE[9] rate=360 flags=0x0 RATE[10] rate=480 flags=0x0 RATE[11] rate=540 flags=0x0 Passive scanning not supported Mode: IEEE 802.11g Channel: 2 Frequency: 2417 MHz Could not set channel for kernel driver wlan1: Unable to setup interface. My wireless card is listed as 02:00.0 Network controller: Atheros Communications Inc. AR5008 Wireless Network Adapter (rev 01) by lspci. Am I doing it wrong and there's a new way of doing it? I'm holding off upgrading to Natty because of this. What changed between the versions that would cause this? Should I report it as a bug?

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  • GDL Presents: Van Gogh Meets Alan Turing

    GDL Presents: Van Gogh Meets Alan Turing How can art and daily life be joined together? Host Ido Green chats with creators Uri Shaked & Tom Teman about tackling this question with their "Music Room" -- a case study in the power of Android -- and with Emmanuel Witzthum on his project "Dissolving Realities," which aims to connect the virtual environment of the Internet using Google Street View. Host: Ido Green, Developer Advocate Guests: Uri Shaked and Emmanuel Witzthum From: GoogleDevelopers Views: 0 0 ratings Time: 00:00 More in Science & Technology

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  • Alan Turing Needs Your Help

    - by Chris Massey
    Well. sort of. Clearly, you are using a computer. If you are on this site, you are probably quite familiar with computers as artifacts of our modern society. Hopefully, you are also familiar with the fact that Alan Turing, logician and mathematician extraordinaire, was instrumental in laying down the foundations of modern computer science, and did a little work to help turn the tide of WWII in the Allies' favor. Hold that thought. A phenomenal collection of Turing's papers (including his first ever...(read more)

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  • What happened to Alan Cooper's Unified File Model?

    - by PAUL Mansour
    For a long time Alan Cooper (in the 3 versions of his book "About Face") has been promoting a "unified file model" to, among other things, dispense with what he calls the most idiotic message box ever invented - the one the pops up when hit the close button on an app or form saying "Do you want to discard your changes?" I like the idea and his arguments, but also have the knee-jerk reaction against it that most seasoned programmers and users have. While Cooper's book seems quite popular and respected, there is remarkably little discussion of this particular issue on the Web that I can find. Petter Hesselberg, the author of "Programming Industrial Strength Windows" mentions it but that seems about it. I have an opportunity to implement this in the (desktop) project I am working on, but face resistance by customers and co-workers, who are of course familiar with the MS Word and Excel way of doing things. I'm in a position to override their objections, but am not sure if I should. My questions are: Are there any good discussions of this that I have failed to find? Is anyone doing this in their apps? Is it a good idea that it is unfortunately not practical to implement until, say, Microsoft does it?

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  • What can Go chan do that a list cannot?

    - by alpav
    I want to know in which situation Go chan makes code much simpler than using list or queue or array that is usually available in all languages. As it was stated by Rob Pike in one of his speeches about Go lexer, Go channels help to organize data flow between structures that are not homomorphic. I am interested in a simple Go code sample with chan that becomes MUCH more complicated in another language (for example C#) where chan is not available. I am not interested in samples that use chan just to increase performance by avoiding waiting of data between generating list and consuming the list (which can be solved by chunking) or as a way to organize thread safe queue or thread-safe communication (which can be easily solved by locking primitives). I am interested in a sample that makes code simpler structurally disregarding size of data. If such sample does not exist then sample where size of data matters. I guess desired sample would contain bi-directional communication between generator and consumer. Also if someone could add tag [channel] to the list of available tags, that would be great.

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  • Removing the contents of a Chan or MVar in a single discrete step

    - by Bill
    I'm writing a discrete simulation where request values from multiple threads accumulate in a centralized queue. Every n milliseconds, a manager wakes up to process requests. When the manager wakes up, it should retrieve all of the contents of the central queue in a single discrete step. While processing these, any client threads attempting to submit to the queue should block. When processing completes, the queue reopens and the manager goes back to sleep. What's the best way to do this? The retry behavior of STM isn't really what I want. If I use a Chan or MVar, there's no way to prevent clients from enqueuing additional requests during processing. One approach is to use an MVar as a mutex on a Chan holding the queue. Are there other ways to do this?

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  • Why did Alan Kay say, "The Internet was so well done, but the web was by amateurs"?

    - by kalaracey
    OK, so I paraphrased. The full quote: The Internet was done so well that most people think of it as a natural resource like the Pacific Ocean, rather than something that was man-made. When was the last time a technology with a scale like that was so error-free? The Web, in comparison, is a joke. The Web was done by amateurs. -- Alan Kay. I am trying to understand the history of the Internet and the web, and this statement is hard to understand. I have read elsewhere that the Internet is now used for very different things than it was designed for, and so perhaps that factors in. What makes the Internet so well done, and what makes the web so amateurish? (Of course, Alan Kay is fallible, and no one here is Alan Kay, so we can't know precisely why he said that, but what are some possible explanations?) *See also the original interview*.

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  • Commémoration du centenaire d'Alan Turing, "il était l'un des premiers à établir ce qu'était un ordinateur" pour le directeur de Microsoft Research

    Commémoration du centenaire d'Alan Turing « il était l'un des premiers à établir ce qu'était un ordinateur » pour le directeur de Microsoft Research Ce samedi 23 juin 2012 marquera le centième anniversaire d'Alan Turing, un pionnier de l'informatique moderne. Considéré comme « le père de l'ordinateur », Alan Turing est un mathématicien britannique né en 1912. Il est connu pour avoir percé le code de l'encodeuse Enigma utilisée par les nazis lors de la Seconde Guerre mondiale pour chiffrer les messages. En 1950, il créa le célèbre « Test de Turing », qu'il formula dans l'article « Computing Machinery and Intelligence », dans lequel il qualifie un ordinateur d'intelligent si celui-ci...

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  • how to allocate array of channels in go

    - by eran
    Sorry for the novice syntax question. How do how create an array of channels in go? var c0 chan int = make(chan int); var c1 chan int = make(chan int); var c2 chan int = make(chan int); var c3 chan int = make(chan int); var c4 chan int = make(chan int); That is, replacing the above five lines in one array of channels of size 5? Many thanks.

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  • So what *did* Alan Kay really mean by the term "object-oriented"?

    - by Charlie Flowers
    Reportedly, Alan Kay is the inventor of the term "object oriented". And he is often quoted as having said that what we call OO today is not what he meant. For example, I just found this on Google: "I made up the term 'object-oriented', and I can tell you I didn't have C++ in mind" - Alan Kay, OOPSLA '97 I vaguely remember hearing something pretty insightful about what he did mean. Something along the lines of "message passing". Do you know what he meant? Can you fill in more details of what he meant and how it differs from today's common OO? Please share some references if you have any. Thanks.

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  • So what *did* Alan Kay really mean by the term "object-oriented"?

    - by Charlie Flowers
    Reportedly, Alan Kay is the inventor of the term "object oriented". And he is often quoted as having said that what we call OO today is not what he meant. For example, I just found this on Google: I made up the term 'object-oriented', and I can tell you I didn't have C++ in mind -- Alan Kay, OOPSLA '97 I vaguely remember hearing something pretty insightful about what he did mean. Something along the lines of "message passing". Do you know what he meant? Can you fill in more details of what he meant and how it differs from today's common OO? Please share some references if you have any. Thanks.

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  • T-SQL Right Joins to ALL Entries inc Selected Column

    - by Pace
    Hi Experts, I have the following Query which produces the output below; SELECT TBLUSERS.USERID, TBLUSERS.ADusername, TBLACCESSLEVELS.ACCESSLEVELID, TBLACCESSLEVELS.AccessLevelName FROM TBLACCESSLEVELS INNER JOIN TBLACCESSRIGHTS ON TBLACCESSLEVELS.ACCESSLEVELID = TBLACCESSRIGHTS.ACCESSLEVELID INNER JOIN TBLUSERS ON TBLACCESSRIGHTS.USERID = TBLUSERS.USERID The output is this; 29 administrator 1 AllUsers 29 administrator 2 JobQueue 29 administrator 3 Telephone Directory Admin 29 administrator 4 Jobqueueadmin 29 administrator 5 UserAdmin 29 administrator 6 Product System 27 alan 1 AllUsers 97 andy 1 AllUsers 26 barry 1 AllUsers 26 barry 2 JobQueue 26 barry 3 Telephone Directory Admin 26 barry 4 Jobqueueadmin 26 barry 5 UserAdmin 26 barry 6 Product System 26 barry 7 Newseditor 26 barry 8 GreetingBoard What I would like to do is modify the query so I get all Access Levels regardless of weather there is an entry for that user. What I would also like to do is some sort of exist case so that I get output like the following; 29 administrator 1 AllUsers True 29 administrator 2 JobQueue True 29 administrator 3 Telephone Directory Admin True 29 administrator 4 Jobqueueadmin True 29 administrator 5 UserAdmin True 29 administrator 6 Product System True 29 administrator 7 Newseditor False 29 administrator 8 GreetingBoard False 27 alan 1 AllUsers True 27 alan 2 JobQueue False 27 alan 3 Telephone Directory Admin False 27 alan 4 Jobqueueadmin False 27 alan 5 UserAdmin False 27 alan 6 Product System False 27 alan 7 Newseditor False 27 alan 8 GreetingBoard False 97 andy 1 AllUsers True 97 andy 2 JobQueue False 97 andy 3 Telephone Directory Admin False 97 andy 4 Jobqueueadmin False 97 andy 5 UserAdmin False 97 andy 6 Product System False 97 andy 7 Newseditor False 97 andy 8 GreetingBoard False 26 Barry 1 AllUsers True 26 Barry 2 JobQueue True 26 Barry 3 Telephone Directory Admin True 26 Barry 4 Jobqueueadmin True 26 Barry 5 UserAdmin True 26 Barry 6 Product System True 26 Barry 7 Newseditor True 26 Barry 8 GreetingBoard True ......................................... So the rules are ALWAYS show ALL Entries for ACCESSLEVELS and where EXISTS in ACCESSRIGHTS produce a true / false to show this. I hope this makes sense and hopefully you dont need the table definitions as everything I need to work with is in the original Query. I just need a way of manipulating it slightly and getting the join in the right place. Thank you. Pace

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  • convert VB code to C# help please??

    - by ilkdrl
    var aktif=0, gosterim_adeti=5; var dizi = new Array(); $(document).ready(function(){ var boyut = $("#alan p").length; for(var i=0; i<boyut; i++) { dizi[i] = $("#alan p:eq("+i+")").html(); } $("#alan").html(""); for(var i=0; i<gosterim_adeti; i++) { $("#alan").append("<p>"+dizi[i]+"</p>"); } setInterval(degistir, 2000); function degistir() { aktif = (aktif + 1)%boyut; $("#alan").html(""); var ilk = aktif-1; if(ilk<0)ilk = ilk+boyut; $("#alan").append("<p>"+dizi[ilk]+"</p>"); for(var i=aktif; i<aktif + gosterim_adeti;i++) { $("#alan").append("<p>"+dizi[(i%boyut)]+"</p>"); } $("#alan p:first").slideUp(500); $("#alan p:last").css("height","0px").animate({height:"40px"},600);

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  • 9 New BizTalk Wencasts in the Light & Easy Series

    - by Alan Smith
    During the MVP summit in February I managed to catch up with a few of the BizTalk MVPs who had recorded new webcasts for the “BizTalk Light & Easy” series. The 9 new webcasts are online now at CloudCasts. ·         BizTalk 2010 and Windows Azure – Paul Somers ·         BizTalk and AppFabric Cache Part 1 – Mike Stephenson ·         BizTalk and AppFabric Cache Part 2 – Mike Stephenson ·         Integration to SharePoint 2010 Part 1 – Mick Badran ·         Integration to SharePoint 2010 Part 2 – Mick Badran ·         Better BizTalk Testing by Taking Advantage of the CAT Logging Framework – Mike Stephenson ·         Calling Business Rules from a .NET Application – Alan Smith ·         Tracking Rules Execution in a .NET Application – Alan Smith ·         Publishing a Business Rules Policy as a Service – Alan Smith The link is here. Big thanks to Paul, Mike and Mick for putting the time in. “BizTalk Light & Easy” is an ongoing project, if you are feeling creative and would like to contribute feel free to contact me via this blog. I can email you some tips on webcasting and the best formats to use.

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  • How can i call method from class but this method implamented from any interface?

    - by Phsika
    i try to call base.Alan(); in HacimBul. But base. dont give intellisense alan method public double HacimBul() { throw new Exception(); //return base..... -- how can i see base.Alan(); } namespace interfaceClass { class Program { static void Main(string[] args) { } } interface Ikenar { double kenar { get; set; } } interface Iyukseklik { double yuksekli {get; set;} } interface IAlan { double Alan(); } interface IHacim { double Hacim(); } class Alan : Ikenar, IAlan { public double kenar { get; set; } double IAlan.Alan() { return kenar * kenar; } } class Hacim : Alan, Iyukseklik { public double kenar { get; set; } public double yuksekli { get; set; } public double HacimBul() { throw new Exception(); //return base..... -- how can i see base.Alan(); } } }

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  • How can i call method from class but this method implemented from any interface?

    - by Phsika
    i try to call base.Alan(); in HacimBul. But base. dont give intellisense alan method public double HacimBul() { throw new Exception(); //return base..... -- how can i see base.Alan(); } namespace interfaceClass { class Program { static void Main(string[] args) { } } interface Ikenar { double kenar { get; set; } } interface Iyukseklik { double yuksekli {get; set;} } interface IAlan { double Alan(); } interface IHacim { double Hacim(); } class Alan : Ikenar, IAlan { public double kenar { get; set; } double IAlan.Alan() { return kenar * kenar; } } class Hacim : Alan, Iyukseklik { public double kenar { get; set; } public double yuksekli { get; set; } public double HacimBul() { throw new Exception(); //return base..... -- how can i see base.Alan(); } } }

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  • How can I send out diff's of submitted changes to the entire project whenever someone commits a chan

    - by Alex
    I'd like to be able to send all the contributors working on a project a message whenever a commit is made. This way, everyone sees the contribution, and hopefully someone will take a look and spot bugs and whatnot. Furthermore, it provides our bosses with a nice and simple, if a little incomprehensible, way to get an idea of how the project is progressing. We're using Mercurial right now.

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  • J2SE Proxy Authentication

    - by Alan
    We use 2 SIMILAR Microsoft ISA Proxy Server 2003 to connect to internet. Each Proxy has different Login style, as below : Server-1 : nt-domain\alan Server-2 : [email protected] Logon in IE, Firefox and my Phonecell via Wifi all are fine. But, a problem appears when we run a java application J2SE Ver 4, 5 and 6, where it needs internet authentication. Logon to Server-2 is OK, but FAIL for Server-2 (style : [email protected]). Note : Both proxy seen using Windows authentication, type : negotiate NTLM Appreceate if you can help or for any suggest. Thank you, Alan L

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  • 'schema' design for a social network

    - by Alan B
    I'm working on a proof of concept app for a twitter style social network with about 500k users. I'm unsure of how best to design the 'schema' should I embed a user's subscriptions or have a separate 'subscriptions' collection and use db references? If I embed, I still have to perform a query to get all of a user's followers. e.g. Given the following user: { "username" : "alan", "photo": "123.jpg", "subscriptions" : [ {"username" : "john", "status" : "accepted"}, {"username" : "paul", "status" : "pending"} ] } to find all of alan's subscribers, I'd have to run something like this: db.users.find({'subscriptions.username' : 'alan'}); from a performance point of view, is that any worse or better than having a separate subscriptions collection? also, when displaying a list of subscriptions/subscribers, I am currently having problems with n+1 because the subscription document tells me the username of the target user but not other attributes I may need such as the profile photo. Are there any recommended practices for such situations? thanks Alan

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  • Cannot create file in directory even though it's writable by a group I belong to

    - by Alan Berndt
    I have a directory structure owned by a certain group, and I am a member of the group that owns these directories. I am able to create files in one directory, but not in another, even though the permissions are the same. alan@bricky:/mnt/storage/media$ stat Music Music\ \(Lossy\)/ File: `Music' Size: 34 Blocks: 8 IO Block: 4096 directory Device: fb00h/64256d Inode: 4215424 Links: 3 Access: (2775/drwxrwsr-x) Uid: ( 1001/ media) Gid: ( 1001/ media) Access: 2011-08-19 11:45:03.182586898 -0700 Modify: 2011-08-19 11:44:01.412840027 -0700 Change: 2011-08-19 11:45:02.734603240 -0700 File: `Music (Lossy)/' Size: 6 Blocks: 8 IO Block: 4096 directory Device: fb00h/64256d Inode: 1512056832 Links: 2 Access: (2775/drwxrwsr-x) Uid: ( 1001/ media) Gid: ( 1001/ media) Access: 2011-08-19 11:45:03.190586606 -0700 Modify: 2011-08-19 10:34:46.526530313 -0700 Change: 2011-08-19 11:45:02.738603094 -0700 alan@bricky:/mnt/storage/media$ touch Music/test alan@bricky:/mnt/storage/media$ touch Music\ \(Lossy\)/test touch: cannot touch `Music (Lossy)/test': Permission denied

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  • How to implement a counter when using golang's goroutine?

    - by MrROY
    I'm trying to make a queue struct that have push and pop functions. I need to use 10 threads push and another 10 threads pop data, just like i did in the code below. Questions : 1. I need to print out how much i have pushed/popped, but i don't know how to do that. 2. Is there anyway to speed up my code ? the code is too slow for me. package main import ( "runtime" "time" ) const ( DATA_SIZE_PER_THREAD = 10000000 ) type Queue struct { records string } func (self Queue) push(record chan interface{}) { // need push counter record <- time.Now() } func (self Queue) pop(record chan interface{}) { // need pop counter <- record } func main() { runtime.GOMAXPROCS(runtime.NumCPU()) //record chan record := make(chan interface{},1000000) //finish flag chan finish := make(chan bool) queue := new(Queue) for i:=0; i<10; i++ { go func() { for j:=0; j<DATA_SIZE_PER_THREAD; j++ { queue.push(record) } finish<-true }() } for i:=0; i<10; i++ { go func() { for j:=0; j<DATA_SIZE_PER_THREAD; j++ { queue.pop(record) } finish<-true }() } for i:=0; i<20; i++ { <-finish } }

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