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  • Weblogic - Dynamic Clustering in practice by Andy Overton

    - by JuergenKress
    The latest version of Weblogic (12.1.2) includes support for Dynamic Clustering. For more details on what else is new in 12.1.2 see my previous blog post. In this blog post I will look at setting up a dynamic cluster on 2 machines with 4 managed servers (2 on each). I will then deploy an application to the cluster and show how to expand the cluster. What is a dynamic cluster? A dynamic cluster is any cluster that contains one or more dynamic servers. Each server in the cluster will be based upon a single shared server template. The server template allows you to configure each server the same and ensures that servers do not need to be manually configured before being added to the cluster. This allows you to easily scale up or down the number of servers in your cluster without the need for setting up each server manually. Changes made to the server template are rolled out to all servers that use that template. Read the complete article here. WebLogic Partner Community For regular information become a member in the WebLogic Partner Community please visit: http://www.oracle.com/partners/goto/wls-emea ( OPN account required). If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Mix Forum Wiki Technorati Tags: WebLogic 12c cluster,WebLogic,WebLogic Community,Oracle,OPN,Jürgen Kress,Andy Overton

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  • Will You Accept This Rose?

    - by user715249
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin;} Ashley, Bentley and the Masked Man. If these names mean anything to you we know where you’ll be on Monday night – planted in front of your television awaiting the villain’s return and what is sure to be the most dramatic rose ceremony yet on the Bachelorette.  If you’re the Oracle PartnerNetwork Communications Team you’ll be spending your Monday night putting the final touches on the most exciting Partner Kickoff Event yet.  Listen in as Judson tells you more. Starting at 6:00 AM PT on Tuesday, June 29th partners – and potential partners – can tune in to watch the excitement unfold at partner.oracle.com.  The storyline for FY12 will continue to unfold with a special role being outlined for our ISV partners.  SPOILER ALERT: OPN has made an investment in how we’ll go to market together – trust us - you don’t want to get this news from the highlight reel. While we won’t be sending anyone home from the show, we do promise an exciting hour which will gear you up to go to market with Oracle in the new fiscal year.  The Oracle PartnerNetwork FY12 Kickoff is being held live 5 times and will include a ‘date card’ message for each region. EMEA Kickoff - Tuesday, June 29, at 6 a.m. PT / 2 p.m. BT LAD Kickoff – Tuesday, June 29, at 8 a.m. PT / noon DT North America Kickoff – Tuesday, June 29, at 10 a.m. PT / 1 p.m. ET Japan Kickoff – Tuesday, June 29, at 6 p.m. PT / Wednesday, June 30, at 10 a.m. JT (Tokyo) APAC Kickoff– Tuesday, June 29, at 8 p.m. PT / Wednesday, June 30, at 11 a.m. SGT (Singapore) / 1 p.m. AET (Sydney) We’ll be taking your questions live throughout the show – we hope you’ll “accept our rose” and join us on this amazing journey. The OPN Communications Team

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  • My Name is Andy and I Have an Associates of Applied Science Degree

    - by andyleonard
    Introduction This post is the forty-first part of a ramble-rant about the software business. The current posts in this series can be found on the series landing page . This post is about the education requirements for job listings. Bachelor’s Degree Required I’m not qualified for any job that requires a bachelor’s degree because I don’t have one. I regularly receive email from recruiters asking if I’m available and interested in a position they have open, or a position they’ve been asked to fill...(read more)

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  • A Rose by Any Other Name..

    - by Geoff N. Hiten
    It is always a good start when you can steal a title line from one of the best writers in the English language.  Let’s hope I can make the rest of this post live up to the opening.  One recurring problem with SQL server is moving databases to new servers.  Client applications use a variety of ways to resolve SQL Server names, some of which are not changed easily <cough SharePoint /cough>.  If you happen to be using default instances on both the source and target SQL Server, then the solution is pretty simple.  You create (or bug the network admin until she creates) two DNS “A” records. One points the old name to the new IP address.  The other creates a new alias for the old server, since the original system name is now redirected.  Note this will redirect ALL traffic from the old server to the new server, including RDP and file share connection attempts.    Figure 1 – Microsoft DNS MMC Snap-In   Figure 2 – DNS New Host Dialog Box Both records are necessary so you can still access the old server via an alternate name. Server Role IP Address Name Alias Source 10.97.230.60 SQL01 SQL01_Old Target 10.97.230.80 SQL02 SQL01 Table 1 – Alias List If you or somebody set up connections via IP address, you deserve to have to go to each app and fix it by hand.  That is the only way to fix that particular foul-up. If have to deal with Named Instances either as a source or a target, then it gets more complicated.  The standard fix is to use the SQL Server Configuration Manager (or one of its earlier incarnations) to create a SQL client alias to redirect the connection.  This can be a pain installing and configuring the app on multiple client servers.  The good news is that SQL Server Configuration Manager AND all of its earlier versions simply write a few registry keys.  Extracting the keys into a .reg file makes centralized automated deployment a snap. If the client is a 32-bit system, you have to extract the native key.  If it is a 64-bit, you have to extract the native key and the WoW (32 bit on 64 bit host) key. First, pick a development system to create the actual registry key.  If you do this repeatedly, you can simply edit an existing registry file.  Create the entry using the SQL Configuration Manager.  You must use a 64-bit system to create the WoW key.  The following example redirects from a named instance “SQL01\SQLUtiluty” to a default instance on “SQL02”.   Figure 3 – SQL Server Configuration Manager - Native Figure 3 shows the native key listing. Figure 4 – SQL Server Configuration Manager – WoW If you think you don’t need the WoW key because your app is 64 it, think again.  SQL Server Management Server is a 32-bit app, as are most SQL test utilities.  Always create both keys for 64-bit target systems. Now that the keys exist, we can extract them into a .reg file. Fire up REGEDIT and browse to the following location:  HKLM\Software\Microsoft\MSSQLServer\Client\ConnectTo.  You can also search the registry for the string value of one of the server names (old or new). Right click on the “ConnectTo” label and choose “Export”.  Save with an appropriate name and location.  The resulting file should look something like this: Figure 5 – SQL01_Alias.reg Repeat the process with the location: HKLM\Software\Wow6432Node\Microsoft\MSSQLServer\Client\ConnectTo Note that if you have multiple alias entries, ALL of the entries will be exported.  In that case, you can edit the file and remove the extra aliases. You can edit the files together into a single file.  Just leave a blank line between new keys like this: Figure 6 – SQL01_Alias_All.reg Of course if you have an automatic way to deploy, it makes sense to have an automatic way to Un-deploy.  To delete a registry key, simply edit the .reg file and replace the target with a “-“ sign like so. Figure 7 – SQL01_Alias_UNDO.reg Now we have the ability to move any database to any server without having to install or change any applications on any client server.  The whole process should be transparent to the applications, which makes planning and coordinating database moves a far simpler task.

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  • F# and the rose-tinted reflection

    - by CliveT
    We're already seeing increasing use of many cores on client desktops. It is a change that has been long predicted. It is not just a change in architecture, but our notions of efficiency in a program. No longer can we focus on the asymptotic complexity of an algorithm by counting the steps that a single core processor would take to execute it. Instead we'll soon be more concerned about the scalability of the algorithm and how well we can increase the performance as we increase the number of cores. This may even lead us to throw away our most efficient algorithms, and switch to less efficient algorithms that scale better. We might even be willing to waste cycles in order to speculatively execute at the algorithm rather than the hardware level. State is the big headache in this parallel world. At the hardware level, main memory doesn't necessarily contain the definitive value corresponding to a particular address. An update to a location might still be held in a CPU's local cache and it might be some time before the value gets propagated. To get the latest value, and the notion of "latest" takes a lot of defining in this world of rapidly mutating state, the CPUs may well need to communicate to decide who has the definitive value of a particular address in order to avoid lost updates. At the user program level, this means programmers will need to lock objects before modifying them, or attempt to avoid the overhead of locking by understanding the memory models at a very deep level. I think it's this need to avoid statefulness that has led to the recent resurgence of interest in functional languages. In the 1980s, functional languages started getting traction when research was carried out into how programs in such languages could be auto-parallelised. Sadly, the impracticality of some of the languages, the overheads of communication during this parallel execution, and rapid improvements in compiler technology on stock hardware meant that the functional languages fell by the wayside. The one thing that these languages were good at was getting rid of implicit state, and this single idea seems like a solution to the problems we are going to face in the coming years. Whether these languages will catch on is hard to predict. The mindset for writing a program in a functional language is really very different from the way that object-oriented problem decomposition happens - one has to focus on the verbs instead of the nouns, which takes some getting used to. There are a number of hybrid functional/object languages that have been becoming more popular in recent times. These half-way houses make it easy to use functional ideas for some parts of the program while still allowing access to the underlying object-focused platform without a great deal of impedance mismatch. One example is F# running on the CLR which, in Visual Studio 2010, has because a first class member of the pack. Inside Visual Studio 2010, the tooling for F# has improved to the point where it is easy to set breakpoints and watch values change while debugging at the source level. In my opinion, it is the tooling support that will enable the widespread adoption of functional languages - without this support, people will put off any transition into the functional world for as long as they possibly can. Without tool support it will make it hard to learn these languages. One tool that doesn't currently support F# is Reflector. The idea of decompiling IL to a functional language is daunting, but F# is potentially so important I couldn't dismiss the idea. As I'm currently developing Reflector 6.5, I thought it wise to take four days just to see how far I could get in doing so, even if it achieved little more than to be clearer on how much was possible, and how long it might take. You can read what happened here, and of the insights it gave us on ways to improve the tool.

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  • Changing font size of legend title in Python pylab rose/polar plot

    - by LaurieW
    I'm trying to change the font size of the title of an existing legend on a rose, or 'polar', plot. Most of the code was written by somebody else, who is away. I've added:- ax.legend(title=legend_title) setp(l.get_title(), fontsize=8) to add the title 'legend_title', which is a variable that the user enters a string for in a a different function that uses this code. The second line of this doesn't return an error but doesn't appear to do anything either. The complete code is below. 'Rose' and 'RoseAxes' are modules/functions written by somebody. Does anyone know of a way to change the legend title font size? I've found some examples for normal plots but can't find any for rose/polar plots. from Rose.RoseAxes import RoseAxes from pylab import figure, title, setp, close, clf from PlotGeneration import color_map_xml fig = figure(1) rect = [0.02, 0.1, 0.8, 0.8] ax = RoseAxes(fig, rect, axisbg='w') fig.add_axes(ax) if cmap == None: (XMLcmap,colors) = color_map_xml.get_cmap('D:/HRW/VET/HrwPyLibs/ColorMapLibrary/paired.xml',255) else: XMLcmap = cmap bqs = kwargs.pop('CTfigname', None) ax.box(Dir, U, bins = rose_binX, units = unit, nsector = nsector, cmap = XMLcmap, lw = 0, **kwargs ) l = ax.legend() ax.legend(title=legend_title) setp(l.get_texts(), fontsize=8) setp(l.get_title(), fontsize=8) Thanks for any help

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  • how to create a wind rose in excel 2007

    - by Patrick
    I am attempting to create a wind rose graph (i.e.- here or here). My data is wind speed and cardinal wind direction in separate columns: Wind (mph) Wind Direction 3.66 SE 2.69 SE 2.62 SW 2.76 SW 2.11 NW 3.13 NW 3.55 SW 3.62 W My final goal is to actually create the graph with a VBA macro, but I am unsure how to even create the graph manually. I can, if need be, convert the cardinal directions to degrees. Any help is greatly appreciated

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  • Survey: How's Your Economy?

    - by andyleonard
    Another quick survey question, slightly off-topic: How's your economy? Have things picked up for you recently? Slowed down? Remained static? :{> Andy Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!...(read more)

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  • Errors rose when a Netbean Maven Project tries to run

    - by Zakaria
    Hi everybody, I installed NetBeans 6.8 on Vista and and I'm trying to execute a simple Maven Project. When I ran the project, I got this set of errors: WARNING: You are running embedded Maven builds, some build may fail due to incompatibilities with latest Maven release. To set Maven instance to use for building, click here. Scanning for projects... [#process-resources] [resources:resources] Using default encoding to copy filtered resources. [#compile] [compiler:compile] Nothing to compile - all classes are up to date [exec:exec] [EL Info]: 2010-04-04 18:22:54.907--ServerSession(15532856)--EclipseLink, version: Eclipse Persistence Services - 2.0.0.v20091127-r5931 [EL Severe]: 2010-04-04 18:22:54.929--ServerSession(15532856)--Local Exception Stack: Exception [EclipseLink-4003] (Eclipse Persistence Services - 2.0.0.v20091127-r5931): org.eclipse.persistence.exceptions.DatabaseException Exception in thread "main" javax.persistence.PersistenceException: Exception [EclipseLink-4003] (Eclipse Persistence Services - 2.0.0.v20091127-r5931): org.eclipse.persistence.exceptions.DatabaseException Exception Description: Configuration error. Class [org.apache.derby.jdbc.ClientDriver] not found. Exception Description: Configuration error. Class [org.apache.derby.jdbc.ClientDriver] not found. at org.eclipse.persistence.exceptions.DatabaseException.configurationErrorClassNotFound(DatabaseException.java:82) at org.eclipse.persistence.sessions.DefaultConnector.loadDriverClass(DefaultConnector.java:267) at org.eclipse.persistence.sessions.DefaultConnector.connect(DefaultConnector.java:85) at org.eclipse.persistence.internal.jpa.EntityManagerSetupImpl.deploy(EntityManagerSetupImpl.java:392) at org.eclipse.persistence.sessions.DatasourceLogin.connectToDatasource(DatasourceLogin.java:162) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.getServerSession(EntityManagerFactoryImpl.java:151) at org.eclipse.persistence.internal.sessions.DatabaseSessionImpl.loginAndDetectDatasource(DatabaseSessionImpl.java:584) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.createEntityManagerImpl(EntityManagerFactoryImpl.java:207) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryProvider.login(EntityManagerFactoryProvider.java:228) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.createEntityManager(EntityManagerFactoryImpl.java:195) at com.mycompany.chapter2_ex1.Main.main(Main.java:31) Caused by: Exception [EclipseLink-4003] (Eclipse Persistence Services - 2.0.0.v20091127-r5931): org.eclipse.persistence.exceptions.DatabaseException Exception Description: Configuration error. Class [org.apache.derby.jdbc.ClientDriver] not found. at org.eclipse.persistence.internal.jpa.EntityManagerSetupImpl.deploy(EntityManagerSetupImpl.java:368) at org.eclipse.persistence.exceptions.DatabaseException.configurationErrorClassNotFound(DatabaseException.java:82) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.getServerSession(EntityManagerFactoryImpl.java:151) at org.eclipse.persistence.sessions.DefaultConnector.loadDriverClass(DefaultConnector.java:267) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.createEntityManagerImpl(EntityManagerFactoryImpl.java:207) at org.eclipse.persistence.sessions.DefaultConnector.connect(DefaultConnector.java:85) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.createEntityManager(EntityManagerFactoryImpl.java:195) at org.eclipse.persistence.sessions.DatasourceLogin.connectToDatasource(DatasourceLogin.java:162) at com.mycompany.chapter2_ex1.Main.main(Main.java:31) at org.eclipse.persistence.internal.sessions.DatabaseSessionImpl.loginAndDetectDatasource(DatabaseSessionImpl.java:584) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryProvider.login(EntityManagerFactoryProvider.java:228) at org.eclipse.persistence.internal.jpa.EntityManagerSetupImpl.deploy(EntityManagerSetupImpl.java:368) ... 4 more [ERROR]The following mojo encountered an error while executing: [ERROR]Group-Id: org.codehaus.mojo [ERROR]Artifact-Id: exec-maven-plugin [ERROR]Version: 1.1.1 [ERROR]Mojo: exec [ERROR]brought in via: Direct invocation [ERROR]While building project: [ERROR]Group-Id: com.mycompany [ERROR]Artifact-Id: chapter2_ex1 [ERROR]Version: 1.0-SNAPSHOT [ERROR]From file: C:\Users\Charlotte\Documents\NetBeansProjects\chapter2_ex1\pom.xml [ERROR]Reason: Result of cmd.exe /X /C ""C:\Program Files\Java\jdk1.6.0_11\bin\java.exe" -classpath C:\Users\Charlotte\Documents\NetBeansProjects\chapter2_ex1\target\classes;C:\Users\Charlotte\.m2\repository\javax\persistence\persistence-api\1.0\persistence-api-1.0.jar;C:\Users\Charlotte\.m2\repository\org\eclipse\persistence\javax.persistence\2.0.0\javax.persistence-2.0.0.jar;C:\Users\Charlotte\.m2\repository\org\eclipse\persistence\eclipselink\2.0.0-RC1\eclipselink-2.0.0-RC1.jar com.mycompany.chapter2_ex1.Main" execution is: '1'. ------------------------------------------------------------------------ For more information, run with the -e flag ------------------------------------------------------------------------ BUILD FAILED ------------------------------------------------------------------------ Total time: 3 seconds Finished at: Sun Apr 04 18:22:55 CEST 2010 Final Memory: 47M/94M ------------------------------------------------------------------------ Theses exceptions rose even if I can run the database by using the console (ij) and when I connect the Database, no errors are showing. Can you help me please? Thank you very much. Regards.

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  • Visual Modeler in VS 6

    - by Yogi Yang 007
    Till date I have used only VB6 Professional for developing apps. But recently I have joined a company which owns VS 6 Enterprise (or some such version) I was just exploring what is available in VS 6 Ent. and I found Visual Modeler. The tutorial provided with it is not good enough. I was wondering if there is any detailed tutorial(s) for Visual Modeler? Is Visual Modeler a cut down version of Rational Rose? I have never used such a tool for developing apps. What are the benefits of developing apps like this? The document claims that one can speed up development and modifications of VB6 & VC++ 6 applications. How true is this claim? My company also has Ration Rose 6. Which is better Rational Rose 6 or Visual Modeler that comes with VS 6 Ent.?

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  • I Start!

    - by andyleonard
    I originally titled this post "I Quit!" but decided that doesn't set the proper tone and definitely does not match my feelings about the upcoming transitions in my life. "I Start!" is much more appropriate! Introduction I've tendered my resignation from the position of Manager, ETL Team, Data Management Group, Molina Medicaid Solutions effective Friday 14 Jan 2011. "There I Was..." In 2008 my consultant billable-days - the metric I use to determine how business is going - dropped from 20 / month...(read more)

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  • It's 2011-Do You Know Where Your Children Are?

    - by andyleonard
    Introduction This is not a post about children. I was feeling plucky when I wrote this post at the end of last year. Sometimes when I feel plucky I'm inspired to create awesome blog post titles and ideas. Other times, this happens. 2011 Is Here! I was born in 1963. As I child I watched Neil Armstrong and Buzz Aldrin walk on the moon while Walter Cronkite narrated. At 11, I was fortunate enough to live next door to an engineer who taught me Motorola 6800 machine code and then BASIC . I have a long...(read more)

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  • One email user keeps disconnecting from our exchange server

    - by Funky Si
    I have one user who keeps reporting that Outlook keeps disconnecting from our email server. All other users are fine. Our email server is running Exchange 2010 and the client is running Outlook 2003. The disconnection only lasts a moment. I have checked for logs on the client and Exchange server and can not see any reason for the disconnect, On the Client I get EventId 26 telling me Outlook has disconnected and reconnected but no reason why. Can anyone give me some suggestions of things to try and track down where the problem could be? --Update-- I have found the following log file C:\Program Files\Microsoft\Exchange Server\V14\Logging\RPC Client Access which suggests that it is a problem with RPC sessions. Excerpt is below 2013-01-31T15:21:24.015Z,6413,15,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,,0,00:00:00,"BS=Conn:24,HangingConn:0,AD:$null/$null/0%,CAS:$null/$null/2%,AB:$null/$null/0%,RPC:$null/$null/1%,FC:$null/0,Policy:ClientThrottlingPolicy2,Norm[Resources:(Mdb)Mailbox Database 0765959540(Health:-1%,HistLoad:0),(Mdb)Public Folder Database 1945427388(Health:-1%,HistLoad:0),];GC:6/1/0;", 2013-01-31T15:21:24.015Z,6413,16,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,PublicLogoff,0,00:00:00,LogonId: 1, 2013-01-31T15:21:24.015Z,6413,16,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,,,00:00:00,"BS=Conn:24,HangingConn:0,AD:$null/$null/0%,CAS:$null/$null/2%,AB:$null/$null/0%,RPC:$null/$null/1%,FC:$null/0,Policy:ClientThrottlingPolicy2,Norm[Resources:(Mdb)Mailbox Database 0765959540(Health:-1%,HistLoad:0),(Mdb)Public Folder Database 1945427388(Health:-1%,HistLoad:0),];GC:6/1/0;", 2013-01-31T15:21:24.015Z,6417,5,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,OwnerLogoff,0,00:00:00,LogonId: 0, 2013-01-31T15:21:24.015Z,6417,5,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,,0x6BA (rpc::Exception),00:02:54.7668000,Budget Highs [AD = 0][CAS = 3][RPC = 1] Session Throttled Count = 0; SessionDropped,"RpcEndPoint: [ServerUnavailableException] Connection must be re-established - [SessionDeadException] Connection doesn't have any open logons, but has client activity. This may be masking synchronization stalls. Dropping a connection." 2013-01-31T15:21:24.015Z,6420,7,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,DelegateLogoff,0,00:00:00,LogonId: 0, 2013-01-31T15:21:24.031Z,6420,7,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,,,00:00:00.0156000,Budget Highs [AD = 0][CAS = 3][RPC = 1] Session Throttled Count = 0, 2013-01-31T15:21:24.031Z,6420,7,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,Disconnect,0,00:02:54.2364000,, 2013-01-31T15:21:24.031Z,6419,5,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,OwnerLogoff,0,00:00:00,LogonId: 0, 2013-01-31T15:21:24.031Z,6419,5,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,,,00:00:00,Budget Highs [AD = 0][CAS = 3][RPC = 1] Session Throttled Count = 0, 2013-01-31T15:21:24.031Z,6419,5,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,Disconnect,0,00:02:54.4392000,, 2013-01-31T15:21:24.031Z,6416,7,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,DelegateLogoff,0,00:00:00,LogonId: 0, 2013-01-31T15:21:24.031Z,6416,7,/o=EUROSAFEUK/ou=first administrative group/cn=Recipients/cn=andy,,OUTLOOK.EXE,11.0.8303.0,Classic,,,ncacn_ip_tcp,,,,00:00:00,Budget Highs [AD = 0][CAS = 3][RPC = 1] Session Throttled Count = 0, Can anyone help point me in the right direction for a solution?

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  • Use SECEDIT to export "Security Options" from one computer and import on another

    - by Andy Arismendi
    Can I use secedit.exe to export out the "Security Options" from the local security policy and then import them on another machine? I'm trying to do this on Windows Server 2008. Update I just tried with: secedit /export /db C:\andy.db /cfg C:\andy.inf /areas SECURITYPOLICY /log C:\andy.log But it didn't work with error: Warning 2: The system cannot find the file specified. Error opening C:\andy.db. Where do I get the DB file from?

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  • Interesting SQL Sorting Issue

    - by rofly
    It's crunch time, deadline for my most recent contract is coming in two days and almost everything is complete and working fine (knock on wood) except for one issue. In one of my stored procedures, I'm needing to return a result set as follows. group_id | name A101 | Craig A102 | Craig Z101 | Craig Z102 | Craig A101 | Jim A102 | Jim Z101 | Jim Z102 | Jim B101 | Andy B102 | Andy Z101 | Andy Z102 | Andy The names need to be sorted by the first character of the group id and also include the Z101/Z102 entries. By sorting strictly by the group id, I get a result set as follows: A101 | Craig A102 | Craig A101 | Jim A102 | Jim B101 | Andy B102 | Andy Z101 | Andy Z102 | Andy Z101 | Jim Z102 | Jim I really can't think of a solution that doesn't involve me making a cursor and bloating the stored procedure up more than it already is. I'm sure a great mind out there has an elegant solution and I'm eager to see what the community can come up with. Thanks a ton in advance.

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  • T-SQL Right Joins to ALL Entries inc Selected Column

    - by Pace
    Hi Experts, I have the following Query which produces the output below; SELECT TBLUSERS.USERID, TBLUSERS.ADusername, TBLACCESSLEVELS.ACCESSLEVELID, TBLACCESSLEVELS.AccessLevelName FROM TBLACCESSLEVELS INNER JOIN TBLACCESSRIGHTS ON TBLACCESSLEVELS.ACCESSLEVELID = TBLACCESSRIGHTS.ACCESSLEVELID INNER JOIN TBLUSERS ON TBLACCESSRIGHTS.USERID = TBLUSERS.USERID The output is this; 29 administrator 1 AllUsers 29 administrator 2 JobQueue 29 administrator 3 Telephone Directory Admin 29 administrator 4 Jobqueueadmin 29 administrator 5 UserAdmin 29 administrator 6 Product System 27 alan 1 AllUsers 97 andy 1 AllUsers 26 barry 1 AllUsers 26 barry 2 JobQueue 26 barry 3 Telephone Directory Admin 26 barry 4 Jobqueueadmin 26 barry 5 UserAdmin 26 barry 6 Product System 26 barry 7 Newseditor 26 barry 8 GreetingBoard What I would like to do is modify the query so I get all Access Levels regardless of weather there is an entry for that user. What I would also like to do is some sort of exist case so that I get output like the following; 29 administrator 1 AllUsers True 29 administrator 2 JobQueue True 29 administrator 3 Telephone Directory Admin True 29 administrator 4 Jobqueueadmin True 29 administrator 5 UserAdmin True 29 administrator 6 Product System True 29 administrator 7 Newseditor False 29 administrator 8 GreetingBoard False 27 alan 1 AllUsers True 27 alan 2 JobQueue False 27 alan 3 Telephone Directory Admin False 27 alan 4 Jobqueueadmin False 27 alan 5 UserAdmin False 27 alan 6 Product System False 27 alan 7 Newseditor False 27 alan 8 GreetingBoard False 97 andy 1 AllUsers True 97 andy 2 JobQueue False 97 andy 3 Telephone Directory Admin False 97 andy 4 Jobqueueadmin False 97 andy 5 UserAdmin False 97 andy 6 Product System False 97 andy 7 Newseditor False 97 andy 8 GreetingBoard False 26 Barry 1 AllUsers True 26 Barry 2 JobQueue True 26 Barry 3 Telephone Directory Admin True 26 Barry 4 Jobqueueadmin True 26 Barry 5 UserAdmin True 26 Barry 6 Product System True 26 Barry 7 Newseditor True 26 Barry 8 GreetingBoard True ......................................... So the rules are ALWAYS show ALL Entries for ACCESSLEVELS and where EXISTS in ACCESSRIGHTS produce a true / false to show this. I hope this makes sense and hopefully you dont need the table definitions as everything I need to work with is in the original Query. I just need a way of manipulating it slightly and getting the join in the right place. Thank you. Pace

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  • Counting number of children in hierarchical SQL data

    - by moontear
    Hello, for a simple data structure such as so: ID parentID Text Price 1 Root 2 1 Flowers 3 1 Electro 4 2 Rose 10 5 2 Violet 5 6 4 Red Rose 12 7 3 Television 100 8 3 Radio 70 9 8 Webradio 90 For reference, the hierarchy tree looks like this: ID Text Price 1 Root |2 Flowers |-4 Rose 10 | |-6 Red Rose 12 |-5 Violet 5 |3 Electro |-7 Television 100 |-8 Radio 70 |-9 Webradio 90 I'd like to count the number of children per level. So I would get a new column "NoOfChildren" like so: ID parentID Text Price NoOfChildren 1 Root 8 2 1 Flowers 3 3 1 Electro 3 4 2 Rose 10 1 5 2 Violet 5 0 6 4 Red Rose 12 0 7 3 Television 100 0 8 3 Radio 70 1 9 8 Webradio 90 0 I read a few things about hierarchical data, but I somehow get stuck on the multiple inner joins on the parentIDs. Maybe someone could help me out here. moon

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  • Counting number of children in hierarchical SQL data

    - by moontear
    for a simple data structure such as so: ID parentID Text Price 1 Root 2 1 Flowers 3 1 Electro 4 2 Rose 10 5 2 Violet 5 6 4 Red Rose 12 7 3 Television 100 8 3 Radio 70 9 8 Webradio 90 For reference, the hierarchy tree looks like this: ID Text Price 1 Root |2 Flowers |-4 Rose 10 | |-6 Red Rose 12 |-5 Violet 5 |3 Electro |-7 Television 100 |-8 Radio 70 |-9 Webradio 90 I'd like to count the number of children per level. So I would get a new column "NoOfChildren" like so: ID parentID Text Price NoOfChildren 1 Root 8 2 1 Flowers 3 3 1 Electro 3 4 2 Rose 10 1 5 2 Violet 5 0 6 4 Red Rose 12 0 7 3 Television 100 0 8 3 Radio 70 1 9 8 Webradio 90 0 I read a few things about hierarchical data, but I somehow get stuck on the multiple inner joins on the parentIDs. Maybe someone could help me out here. moon

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  • SQL server query not showing daily date result

    - by Andrew Jahn
    I have a simple user production report where daily quotas are tracked. The sql returns a weeks worth of data for all users and for each day it tracks their totals. The problem is if they are out for a day and have a zero production for that day then the result query just skips that day and leaves it out. I want to return days even if the table has no entries for the person on that day. table: user date andy 3/22/10 andy 3/22/10 andy 3/23/10 andy 3/24/10 andy 3/26/10 result: andy 3/22/10 2 3/23/10 1 3/24/10 1 3/25/10 0 3/26/10 1 So my question is how do I get the query to return that 3/25/10 date with a count of 0. (current query I'm using): SELECT A.USUS_ID as Processor, CONVERT(VARCHAR(10),A.CLST_STS_DTM,101) as Date, COUNT(A.CLCL_ID) as DailyTotal FROM CMC_CLST_STATUS A WHERE A.CLST_STS_DTM >= (@Day) AND DATEADD(d, 5, @Day) > A.CLST_STS_DTM GROUP BY A.USUS_ID, CONVERT(VARCHAR(10),A.CLST_STS_DTM,101) ORDER BY A.USUS_ID, CONVERT(VARCHAR(10),A.CLST_STS_DTM,101)

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  • shell script redirect output

    - by Andy
    I have a shell script to monitor process due to preventing the process closed. If the process is closed, that script will restart it. BTW, when the system starts, the crontab will run the script automatically. How can I get the output of the process which started by the shell script? #!/bin/bash PATH=/bin:/sbin:/usr/bin:/usr/sbin:/usr/local/bin:/usr/local/sbin:~/bin export PATH while : do if [ -z "$(ps -ef | grep -v grep | grep 225.0.6.4)" ]; then date +"%m-%d-%y %T" >> /home/andy/log/stream.log echo "225.0.6.4 - 103 not worked and restart process" >> /home/andy/log/stream.log echo "225.0.6.4 - 103 not worked and restart process" /usr/bin/tzap -a 1 -c /home/andy/channels.conf -o - -r -p "D" | /home/andy/ffmpeg -f mpegts -i pipe:0 -c:v libx264 -preset medium -crf 23 -bufsize 3000K -minrate 1200k -maxrate 1200k -pix_fmt yuv420p -g 50 -s 1024x768 -acodec libmp3lame -b:a 128k -ac 2 -ar 44100 -f mpegts udp://225.0.6.4:50000 & fi sleep 1 done

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  • Androids development life cycle model query [closed]

    - by Andrew Rose
    I have been currently researching Google and their approach to marketing the Android OS. Primarily using an open source technique with the Open Hand Alliance and out souring through third-party developers. I'm now keen to investigate their approach using various development life cycle models in the form of waterfall, spiral, scrum, agile etc. And i'm just curious to have some feedback from professionals and what approach they think Google would use to have a positive effect on their business. Thanks for your time Andy Rose

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