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  • 360 snake movement

    - by Darius Janavicius
    I'm trying to do 360 degree snake game in actionscript 3. Here is my movement code: //head movement head.x += snake_speed*Math.cos((head.rotation) * (Math.PI /180)); head.y += snake_speed*Math.sin((head.rotation) * (Math.PI /180)); if (dir == "left") head.rotation -= snake_speed*2; if (dir == "right") head.rotation +=snake_speed*2; //Body part movement for(var i:int = body_parts.length-1; i>0; i--) { var angle = (body_parts[i-1].rotation)*(Math.PI/180); body_parts[i].y = body_parts[i-1].y - (25 * Math.sin(angle)); body_parts[i].x = body_parts[i-1].x - (25 * Math.cos(angle)); body_parts[i].rotation = body_parts[i-1].rotation; } With this code head moves just like I want it to move, but body parts have the same angle as head and it looks wrong. What I want to achieve is to make body parts to move like in game "Ultimate snake". Here is a link to that game: http://armorgames.com/play/387/ultimate-snake P.S. I saw similar question here "How to approach 360 degree snake" but didnt understand the answer :/

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  • Why your Netapp is so slow...

    - by Darius Zanganeh
    Have you ever wondered why your Netapp FAS box is slow and doesn't perform well at large block workloads?  In this blog entry I will give you a little bit of information that will probably help you understand why it’s so slow, why you shouldn't use it for applications that read and write in large blocks like 64k, 128k, 256k ++ etc..  Of course since I work for Oracle at this time, I will show you why the ZS3 storage boxes are excellent choices for these types of workloads. Netapp’s Fundamental Problem The fundamental problem you have running these workloads on Netapp is the backend block size of their WAFL file system.  Every application block on a Netapp FAS ends up in a 4k chunk on a disk. Reference:  Netapp TR-3001 Whitepaper Netapp has proven this lacking large block performance fact in at least two different ways. They have NEVER posted an SPC-2 Benchmark yet they have posted SPC-1 and SPECSFS, both recently. In 2011 they purchased Engenio to try and fill this GAP in their portfolio. Block Size Matters So why does block size matter anyways?  Many applications use large block chunks of data especially in the Big Data movement.  Some examples are SAS Business Analytics, Microsoft SQL, Hadoop HDFS is even 64MB! Now let me boil this down for you.  If an application such MS SQL is writing data in a 64k chunk then before Netapp actually writes it on disk it will have to split it into 16 different 4k writes and 16 different disk IOPS.  When the application later goes to read that 64k chunk the Netapp will have to again do 16 different disk IOPS.  In comparison the ZS3 Storage Appliance can write in variable block sizes ranging from 512b to 1MB.  So if you put the same MSSQL database on a ZS3 you can set the specific LUNs for this database to 64k and then when you do an application read/write it requires only a single disk IO.  That is 16x faster!  But, back to the problem with your Netapp, you will VERY quickly run out of disk IO and hit a wall.  Now all arrays will have some fancy pre fetch algorithm and some nice cache and maybe even flash based cache such as a PAM card in your Netapp but with large block workloads you will usually blow through the cache and still need significant disk IO.  Also because these datasets are usually very large and usually not dedupable they are usually not good candidates for an all flash system.  You can do some simple math in excel and very quickly you will see why it matters.  Here are a couple of READ examples using SAS and MSSQL.  Assume these are the READ IOPS the application needs even after all the fancy cache and algorithms.   Here is an example with 128k blocks.  Notice the numbers of drives on the Netapp! Here is an example with 64k blocks You can easily see that the Oracle ZS3 can do dramatically more work with dramatically less drives.  This doesn't even take into account that the ONTAP system will likely run out of CPU way before you get to these drive numbers so you be buying many more controllers.  So with all that said, lets look at the ZS3 and why you should consider it for any workload your running on Netapp today.  ZS3 World Record Price/Performance in the SPC-2 benchmark ZS3-2 is #1 in Price Performance $12.08ZS3-2 is #3 in Overall Performance 16,212 MBPS Note: The number one overall spot in the world is held by an AFA 33,477 MBPS but at a Price Performance of $29.79.  A customer could purchase 2 x ZS3-2 systems in the benchmark with relatively the same performance and walk away with $600,000 in their pocket.

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  • Oracle ZFSSA Hybrid Storage Pool Demo

    - by Darius Zanganeh
    The ZFS Hybrid Storage Pool (HSP) has been around since the ZFSSA first launched.  It is one of the main contributors to the high performance we see on the Oracle ZFSSA both in benchmarks as well as many production environments.  Below is a short video I made to show at a high level just how impactful this HSP pool is on storage performance.  We squeeze a ton of performance out of our drives with our unique use of cache, write optimized ssd and read optimized ssd.  Many have written and blogged about this technology, here it is in action. Demo of the Oracle ZFSSA Hybrid Storage Pool and how it speeds up workloads.

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  • Why is Joomla based website that was copied off of live server into localhost not showing pictures and throwing 404 error?

    - by Darius
    I have copied Joomla based website via FTP onto my machine and I am trying to make it run on my localhost which is provided by the latest version of XAMPP. I have exported and imported the DB with no problems. I have placed all the files and folders into htdocs folder but when I go to localhost/examplesite all I get is the text that is on the front page but no pictures and it displays 404 Error. Do I need to make changes to .htaccess? If so, can some one point me to the right direction? Thanks

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  • VPN to Buffalo WHR-HP-G300N produces a Connection Error 807

    - by Darius
    My friend has modem/router from Clear and I have sent him Buffalo router to put it between his Clear device and the Network. I walked him thru establishing VPN in DD-WRT but when I try to VPN I get a VPN Connection Error 807. I am out of ideas how to solve this. Any suggestion? Clear Modem WAN: xx.xx.xx.xx Clearn Modem NAT's to: 192.168.15.XXX Clear Modem DHCP: 192.168.15.2 - 192.168.15.2 (range is limited to that of ONE ip address) Clear Modem DMZ: 192.168.15.2 the LAN of the clear modem is 192.168.15.XXX The DD-WRT IP: 192.168.4.1 Port FWD: 1723 to 192.168.4.1 PPTP server listens on 192.168.4.1 Where is the problem with this setup?

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  • Batch convert *.avi files using ffmpeg

    - by Darius
    I am trying to convert 20+ .avi files in a batch using ffmpeg. I've got the following @echo off. for file in *.avi do ffmpeg -i "$file" -s 640x480 -vcodec msmpeg4v2 "'basename "$file" .avi'.mpg'; done in my .bat file but it does not work. How can I make it work under Windows OS. Oh, and yes all the files are in the same folder. The error message I get: File was unexpected at this time

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  • Sharing internet connection from Windows XP using wi-fi router

    - by Darius
    Hi, I have an network configuration like: Ethernet cable from ISP connected to Windows XP machine, configured with static IP 192.168.0.3 Another ethernet connection from 2nd Windows XP machine's network adapter to a Wi-Fi router (D-Link Airport G+) XP set to "Share internet connection", the 2nd adapter configured as static to 192.169.0.1 D-Link Airport Wi-Fi router also configured as "static connection", it's IP set to 192.169.0.2, default gateway set to 192.169.0.1. Network mask everywhere is 24. Laptop computer connected with the router with static IP 192.169.0.3 The problems are: XP machine sees the router (it's able to ping it and access it via the web admin tool) The router somehow cannot PING the XP machine (using the tool provided by the web-based admin tool) The laptop computer cannot ping anything and cannot be pinged The router is only accessible when the ethernet cable is connected with a router's 1-4 LAN port, when I connect it via "WAN" port (which I believe is the proper one) it's not visible from the XP machine If you have similar experience with configuring a network like this I would really appreciate your help. I cannot use the Wi-Fi router with the ISP cable itself.

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  • OpenOffice with C# iterate throught all paragraphs and read text

    - by Darius Kucinskas
    How to iterate through all paragraphs in OpenOffice Writer document and output text. I have Java examples, but don't know how to convert code to C#. Java example could be found here: http://wiki.services.openoffice.org/wiki/API/Samples/Java/Writer/TextDocumentStructure My C# code: InitOpenOfficeEnvironment(); XMultiServiceFactory multiServiceFactory = connect(); XComponentLoader componentLoader = XComponentLoader)multiServiceFactory.createInstance("com.sun.star.frame.Desktop"); //set the property PropertyValue[] propertyValue = new PropertyValue[1]; PropertyValue aProperty = new PropertyValue(); aProperty.Name = "Hidden"; aProperty.Value = new uno.Any(false); propertyValue[0] = aProperty; XComponent xComponent = componentLoader.loadComponentFromURL( @"file:///C:/code/test3.doc", "_blank", 0, propertyValue); XEnumerationAccess xEnumerationAccess = (XEnumerationAccess)xComponent; XEnumeration xParagraphEnumeration = xEnumerationAccess.createEnumeration(); while ( xParagraphEnumeration.hasMoreElements() ) { // ??? // The problem is here nextElement() returns uno.Any but // I some how should get XTextContent???? uno.Any textElement = xParagraphEnumeration.nextElement(); // create another enumeration to get all text portions of //the paragraph XEnumeration xParaEnumerationAccess = textElement.createEnumeration(); //step 3 Through the Text portions Enumeration, //get interface to each individual text portion } xComponent.dispose(); xComponent = null;

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  • OpenOffice with .NET: how to iterate throught all paragraphs and read text

    - by Darius Kucinskas
    How to iterate through all paragraphs in OpenOffice Writer document and output text. I have Java examples, but don't know how to convert code to C#. Java example could be found here: http://wiki.services.openoffice.org/wiki/API/Samples/Java/Writer/TextDocumentStructure My C# code: InitOpenOfficeEnvironment(); XMultiServiceFactory multiServiceFactory = connect(); XComponentLoader componentLoader = XComponentLoader)multiServiceFactory.createInstance("com.sun.star.frame.Desktop"); //set the property PropertyValue[] propertyValue = new PropertyValue[1]; PropertyValue aProperty = new PropertyValue(); aProperty.Name = "Hidden"; aProperty.Value = new uno.Any(false); propertyValue[0] = aProperty; XComponent xComponent = componentLoader.loadComponentFromURL( @"file:///C:/code/test3.doc", "_blank", 0, propertyValue); XEnumerationAccess xEnumerationAccess = (XEnumerationAccess)xComponent; XEnumeration xParagraphEnumeration = xEnumerationAccess.createEnumeration(); while ( xParagraphEnumeration.hasMoreElements() ) { // ??? // The problem is here nextElement() returns uno.Any but // I some how should get XTextContent???? uno.Any textElement = xParagraphEnumeration.nextElement(); // create another enumeration to get all text portions of //the paragraph XEnumeration xParaEnumerationAccess = textElement.createEnumeration(); //step 3 Through the Text portions Enumeration, //get interface to each individual text portion } xComponent.dispose(); xComponent = null;

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  • Trying to get WCF client to work with wss 1.0 username token security

    - by darius murauskas
    I am trying to use a WCF client to call a third party web service. The web Service usses username token authentication WSS-Security 1.0 Soap Message Security Here is a sample soap authentication header for what the web service expects <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Header> <wsse:Security soap:mustUnderstand="1"> <wsse:UsernameToken namespaces> <wsse:Username>username</wsse:Username> <wsse:Password Type="type info">password</wsse:Password> <wsse:Nonce>nonce</wsse:Nonce> <wsu:Created>date created</wsu:Created> </wsse:UsernameToken> <wsse:Security> </soap:Header> <soap:Body> <WebServiceMethodName xmlns="Web Service Namespace" /> I configured the client to the following way <basicHttpBinding> <binding name="Binding1"> <security mode="TransportWithMessageCredential"> <transport clientCredentialType="Basic"/> </security> </basicHttpBinding> but recieved an error that stating that the nonce and datecreated attributes were missing in the header. Does anyone know how to configure a WCF client to work with WSS-Security 1.0 Soap Message Security username token authentication?

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  • How much of STL is too much?

    - by Darius Kucinskas
    I am using a lot of STL code with std::for_each, bind, and so on, but I noticed that sometimes STL usage is not good idea. For example if you have a std::vector and want to do one action on each item of the vector, your first idea is to use this: std::for_each(vec.begin(), vec.end(), Foo()) and it is elegant and ok, for a while. But then comes the first set of bug reports and you have to modify code. Now you should add parameter to call Foo(), so now it becomes: std::for_each(vec.begin(), vec.end(), std::bind2nd(Foo(), X)) but that is only temporary solution. Now the project is maturing and you understand business logic much better and you want to add new modifications to code. It is at this point that you realize that you should use old good: for(std::vector::iterator it = vec.begin(); it != vec.end(); ++it) Is this happening only to me? Do you recognise this kind of pattern in your code? Have you experience similar anti-patterns using STL?

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  • Switch monitor configurations on Windows 7

    - by Horst Walter
    I use one of my PCs for flight simulation as well as for home theater. In case one it has 2 monitors attached, and in case 2 (home theater) a HD TV is being used. All 3 monitors are attached at the same time to the graphics card. How could it best switch best between different configurations. In case 1 I'd like to have the configuration with monitor 1/2, alternatively I'd like quickly to switch to another config only with the HD TV as primary screen. A similar question has been asked 6 months back with no full solution yet, so I come up with it again. The comment there of Darius (Windows + P key) is the best so far.

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  • Reading input from a text file, omits the first and adds a nonsense value to the end?

    - by Greenhouse Gases
    Hi there When I input locations from a txt file I am getting a peculiar error where it seems to miss off the first entry, yet add a garbage entry to the end of the link list (it is designed to take the name, latitude and longitude for each location you will notice). I imagine this to be an issue with where it starts collecting the inputs and where it stops but I cant find the error!! It reads the first line correctly but then skips to the next before adding it because during testing for the bug it had no record of the first location Lisbon though whilst stepping into the method call it was reading it. Very bizarre but hopefully someone knows the issue. Here is firstly my header file: #include <string> struct locationNode { char nodeCityName [35]; double nodeLati; double nodeLongi; locationNode* Next; void CorrectCase() // Correct upper and lower case letters of input { int MAX_SIZE = 35; int firstLetVal = this->nodeCityName[0], letVal; int n = 1; // variable for name index from second letter onwards if((this->nodeCityName[0] >90) && (this->nodeCityName[0] < 123)) // First letter is lower case { firstLetVal = firstLetVal - 32; // Capitalise first letter this->nodeCityName[0] = firstLetVal; } while(n <= MAX_SIZE - 1) { if((this->nodeCityName[n] >= 65) && (this->nodeCityName[n] <= 90)) { letVal = this->nodeCityName[n] + 32; this->nodeCityName[n] = letVal; } n++; } //cityNameInput = this->nodeCityName; } }; class Locations { private: int size; public: Locations(){ }; // constructor for the class locationNode* Head; //int Add(locationNode* Item); }; And here is the file containing main: // U08221.cpp : main project file. #include "stdafx.h" #include "Locations.h" #include <iostream> #include <string> #include <fstream> using namespace std; int n = 0,x, locationCount = 0, MAX_SIZE = 35; string cityNameInput; char targetCity[35]; bool acceptedInput = false, userInputReq = true, match = false, nodeExists = false;// note: addLocation(), set to true to enable user input as opposed to txt file locationNode *start_ptr = NULL; // pointer to first entry in the list locationNode *temp, *temp2; // Part is a pointer to a new locationNode we can assign changing value followed by a call to Add locationNode *seek, *bridge; void setElementsNull(char cityParam[]) { int y=0, count =0; while(cityParam[y] != NULL) { y++; } while(y < MAX_SIZE) { cityParam[y] = NULL; y++; } } void addLocation() { temp = new locationNode; // declare the space for a pointer item and assign a temporary pointer to it if(!userInputReq) // bool that determines whether user input is required in adding the node to the list { cout << endl << "Enter the name of the location: "; cin >> temp->nodeCityName; temp->CorrectCase(); setElementsNull(temp->nodeCityName); cout << endl << "Please enter the latitude value for this location: "; cin >> temp->nodeLati; cout << endl << "Please enter the longitude value for this location: "; cin >> temp->nodeLongi; cout << endl; } temp->Next = NULL; //set to NULL as when one is added it is currently the last in the list and so can not point to the next if(start_ptr == NULL){ // if list is currently empty, start_ptr will point to this node start_ptr = temp; } else { temp2 = start_ptr; // We know this is not NULL - list not empty! while (temp2->Next != NULL) { temp2 = temp2->Next; // Move to next link in chain until reach end of list } temp2->Next = temp; } ++locationCount; // increment counter for number of records in list if(!userInputReq){ cout << "Location sucessfully added to the database! There are " << locationCount << " location(s) stored" << endl; } } void populateList(){ ifstream inputFile; inputFile.open ("locations.txt", ios::in); userInputReq = true; temp = new locationNode; // declare the space for a pointer item and assign a temporary pointer to it do { inputFile.get(temp->nodeCityName, 35, ' '); setElementsNull(temp->nodeCityName); inputFile >> temp->nodeLati; inputFile >> temp->nodeLongi; setElementsNull(temp->nodeCityName); if(temp->nodeCityName[0] == 10) //remove linefeed from input { for(int i = 0; temp->nodeCityName[i] != NULL; i++) { temp->nodeCityName[i] = temp->nodeCityName[i + 1]; } } addLocation(); } while(!inputFile.eof()); userInputReq = false; cout << "Successful!" << endl << "List contains: " << locationCount << " entries" << endl; cout << endl; inputFile.close(); } bool nodeExistTest(char targetCity[]) // see if entry is present in the database { match = false; seek = start_ptr; int letters = 0, letters2 = 0, x = 0, y = 0; while(targetCity[y] != NULL) { letters2++; y++; } while(x <= locationCount) // locationCount is number of entries currently in list { y=0, letters = 0; while(seek->nodeCityName[y] != NULL) // count letters in the current name { letters++; y++; } if(letters == letters2) // same amount of letters in the name { y = 0; while(y <= letters) // compare each letter against one another { if(targetCity[y] == seek->nodeCityName[y]) { match = true; y++; } else { match = false; y = letters + 1; // no match, terminate comparison } } } if(match) { x = locationCount + 1; //found match so terminate loop } else{ if(seek->Next != NULL) { bridge = seek; seek = seek->Next; x++; } else { x = locationCount + 1; // end of list so terminate loop } } } return match; } void deleteRecord() // complete this { int junction = 0; locationNode *place; cout << "Enter the name of the city you wish to remove" << endl; cin >> targetCity; setElementsNull(targetCity); if(nodeExistTest(targetCity)) //if this node does exist { if(seek == start_ptr) // if it is the first in the list { junction = 1; } if(seek != start_ptr && seek->Next == NULL) // if it is last in the list { junction = 2; } switch(junction) // will alter list accordingly dependant on where the searched for link is { case 1: start_ptr = start_ptr->Next; delete seek; --locationCount; break; case 2: place = seek; seek = bridge; delete place; --locationCount; break; default: bridge->Next = seek->Next; delete seek; --locationCount; break; } } else { cout << targetCity << "That entry does not currently exist" << endl << endl << endl; } } void searchDatabase() { char choice; cout << "Enter search term..." << endl; cin >> targetCity; if(nodeExistTest(targetCity)) { cout << "Entry: " << endl << endl; } else { cout << "Sorry, that city is not currently present in the list." << endl << "Would you like to add this city now Y/N?" << endl; cin >> choice; /*while(choice != ('Y' || 'N')) { cout << "Please enter a valid choice..." << endl; cin >> choice; }*/ switch(choice) { case 'Y': addLocation(); break; case 'N': break; default : cout << "Invalid choice" << endl; break; } } } void printDatabase() { temp = start_ptr; // set temp to the start of the list do { if (temp == NULL) { cout << "You have reached the end of the database" << endl; } else { // Display details for what temp points to at that stage cout << "Location : " << temp->nodeCityName << endl; cout << "Latitude : " << temp->nodeLati << endl; cout << "Longitude : " << temp->nodeLongi << endl; cout << endl; // Move on to next locationNode if one exists temp = temp->Next; } } while (temp != NULL); } void nameValidation(string name) { n = 0; // start from first letter x = name.size(); while(!acceptedInput) { if((name[n] >= 65) && (name[n] <= 122)) // is in the range of letters { while(n <= x - 1) { while((name[n] >=91) && (name[n] <=97)) // ERROR!! { cout << "Please enter a valid city name" << endl; cin >> name; } n++; } } else { cout << "Please enter a valid city name" << endl; cin >> name; } if(n <= x - 1) { acceptedInput = true; } } cityNameInput = name; } int main(array<System::String ^> ^args) { //main contains test calls to functions at present cout << "Populating list..."; populateList(); printDatabase(); deleteRecord(); printDatabase(); cin >> cityNameInput; } The text file contains this (ignore the names, they are just for testing!!): Lisbon 45 47 Fattah 45 47 Darius 42 49 Peter 45 27 Sarah 85 97 Michelle 45 47 John 25 67 Colin 35 87 Shiron 40 57 George 34 45 Sean 22 33 The output omits Lisbon, but adds on a garbage entry with nonsense values. Any ideas why? Thank you in advance.

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  • User Input That Involves A ' ' Causes A Substring Out Of Range Error

    - by Greenhouse Gases
    Hi Stackoverflow people. You have already helped me quite a bit but near the end of writing this program I have somewhat of a bug. You see in order to read in city names with a space in from a text file I use a '/' that is then replaced by the program for a ' ' (and when the serializer runs the opposite happens for next time the program is run). The problem is when a user inputs a name too add, search for, or delete that contains a space, for instance 'New York' I get a Debug Assertion Error with a substring out of range expression. I have a feeling it's to do with my correctCase function, or setElementsNull that looks at the string until it experiences a null element in the array, however ' ' is not null so I'm not sure how to fix this and I'm going a bit insane. Any help would be much appreciated. Here is my code: // U08221.cpp : main project file. #include "stdafx.h" #include <_iostream> #include <_string> #include <_fstream> #include <_cmath> using namespace std; class locationNode { public: string nodeCityName; double nodeLati; double nodeLongi; locationNode* Next; locationNode(string nameOf, double lat, double lon) { this->nodeCityName = nameOf; this->nodeLati = lat; this->nodeLongi = lon; this->Next = NULL; } locationNode() // NULL constructor { } void swapProps(locationNode *node2) { locationNode place; place.nodeCityName = this->nodeCityName; place.nodeLati = this->nodeLati; place.nodeLongi = this->nodeLongi; this->nodeCityName = node2->nodeCityName; this->nodeLati = node2->nodeLati; this->nodeLongi = node2->nodeLongi; node2->nodeCityName = place.nodeCityName; node2->nodeLati = place.nodeLati; node2->nodeLongi = place.nodeLongi; } void modify(string name) { this->nodeCityName = name; } void modify(double latlon, int mod) { switch(mod) { case 2: this->nodeLati = latlon; break; case 3: this->nodeLongi = latlon; break; } } void correctCase() // Correct upper and lower case letters of input { int MAX_SIZE = 35; int firstLetVal = this->nodeCityName[0], letVal; int n = 1; // variable for name index from second letter onwards if((this->nodeCityName[0] >90) && (this->nodeCityName[0] < 123)) // First letter is lower case { firstLetVal = firstLetVal - 32; // Capitalise first letter this->nodeCityName[0] = firstLetVal; } while(this->nodeCityName[n] != NULL) { if((this->nodeCityName[n] >= 65) && (this->nodeCityName[n] <= 90)) { if(this->nodeCityName[n - 1] != 32) { letVal = this->nodeCityName[n] + 32; this->nodeCityName[n] = letVal; } } n++; } } }; Here is the main part of the program: // U08221.cpp : main project file. #include "stdafx.h" #include "Locations2.h" #include <_iostream> #include <_string> #include <_fstream> #include <_cmath> using namespace std; #define pi 3.14159265358979323846264338327950288 #define radius 6371 #define gig 1073741824 //size of a gigabyte in bytes int n = 0,x, locationCount = 0, MAX_SIZE = 35 , g = 0, i = 0, modKey = 0, xx; string cityNameInput, alter; char targetCity[35], skipKey = ' '; double lat1, lon1, lat2, lon2, dist, dummy, modVal, result; bool acceptedInput = false, match = false, nodeExists = false;// note: addLocation(), set to true to enable user input as opposed to txt file locationNode *temp, *temp2, *example, *seek, *bridge, *start_ptr = NULL; class Menu { int junction; public: /* Convert decimal degrees to radians */ public: void setElementsNull(char cityParam[]) { int y=0; while(cityParam[y] != NULL) { y++; } while(y < MAX_SIZE) { cityParam[y] = NULL; y++; } } void correctCase(string name) // Correct upper and lower case letters of input { int MAX_SIZE = 35; int firstLetVal = name[0], letVal; int n = 1; // variable for name index from second letter onwards if((name[0] >90) && (name[0] < 123)) // First letter is lower case { firstLetVal = firstLetVal - 32; // Capitalise first letter name[0] = firstLetVal; } while(name[n] != NULL) { if((name[n] >= 65) && (name[n] <= 90)) { letVal = name[n] + 32; name[n] = letVal; } n++; } for(n = 0; targetCity[n] != NULL; n++) { targetCity[n] = name[n]; } } bool nodeExistTest(char targetCity[]) // see if entry is present in the database { match = false; seek = start_ptr; int letters = 0, letters2 = 0, x = 0, y = 0; while(targetCity[y] != NULL) { letters2++; y++; } while(x <= locationCount) // locationCount is number of entries currently in list { y=0, letters = 0; while(seek->nodeCityName[y] != NULL) // count letters in the current name { letters++; y++; } if(letters == letters2) // same amount of letters in the name { y = 0; while(y <= letters) // compare each letter against one another { if(targetCity[y] == seek->nodeCityName[y]) { match = true; y++; } else { match = false; y = letters + 1; // no match, terminate comparison } } } if(match) { x = locationCount + 1; //found match so terminate loop } else{ if(seek->Next != NULL) { bridge = seek; seek = seek->Next; x++; } else { x = locationCount + 1; // end of list so terminate loop } } } return match; } double deg2rad(double deg) { return (deg * pi / 180); } /* Convert radians to decimal degrees */ double rad2deg(double rad) { return (rad * 180 / pi); } /* Do the calculation */ double distance(double lat1, double lon1, double lat2, double lon2, double dist) { dist = sin(deg2rad(lat1)) * sin(deg2rad(lat2)) + cos(deg2rad(lat1)) * cos(deg2rad(lat2)) * cos(deg2rad(lon1 - lon2)); dist = acos(dist); dist = rad2deg(dist); dist = (radius * pi * dist) / 180; return dist; } void serialise() { // Serialize to format that can be written to text file fstream outfile; outfile.open("locations.txt",ios::out); temp = start_ptr; do { for(xx = 0; temp->nodeCityName[xx] != NULL; xx++) { if(temp->nodeCityName[xx] == 32) { temp->nodeCityName[xx] = 47; } } outfile << endl << temp->nodeCityName<< " "; outfile<<temp->nodeLati<< " "; outfile<<temp->nodeLongi; temp = temp->Next; }while(temp != NULL); outfile.close(); } void sortList() // do this { int changes = 1; locationNode *node1, *node2; while(changes > 0) // while changes are still being made to the list execute { node1 = start_ptr; node2 = node1->Next; changes = 0; do { xx = 1; if(node1->nodeCityName[0] > node2->nodeCityName[0]) //compare first letter of name with next in list { node1->swapProps(node2); // should come after the next in the list changes++; } else if(node1->nodeCityName[0] == node2->nodeCityName[0]) // if same first letter { while(node1->nodeCityName[xx] == node2->nodeCityName[xx]) // check next letter of name { if((node1->nodeCityName[xx + 1] != NULL) && (node2->nodeCityName[xx + 1] != NULL)) // check next letter until not the same { xx++; } else break; } if(node1->nodeCityName[xx] > node2->nodeCityName[xx]) { node1->swapProps(node2); // should come after the next in the list changes++; } } node1 = node2; node2 = node2->Next; // move to next pair in list } while(node2 != NULL); } } void initialise() { cout << "Populating List..."; ifstream inputFile; inputFile.open ("locations.txt", ios::in); char inputName[35] = " "; double inputLati = 0, inputLongi = 0; //temp = new locationNode(inputName, inputLati, inputLongi); do { inputFile.get(inputName, 35, ' '); inputFile >> inputLati; inputFile >> inputLongi; if(inputName[0] == 10 || 13) //remove linefeed from input { for(int i = 0; inputName[i] != NULL; i++) { inputName[i] = inputName[i + 1]; } } for(xx = 0; inputName[xx] != NULL; xx++) { if(inputName[xx] == 47) // if it is a '/' { inputName[xx] = 32; // replace it for a space } } temp = new locationNode(inputName, inputLati, inputLongi); if(start_ptr == NULL){ // if list is currently empty, start_ptr will point to this node start_ptr = temp; } else { temp2 = start_ptr; // We know this is not NULL - list not empty! while (temp2->Next != NULL) { temp2 = temp2->Next; // Move to next link in chain until reach end of list } temp2->Next = temp; } ++locationCount; // increment counter for number of records in list } while(!inputFile.eof()); cout << "Successful!" << endl << "List contains: " << locationCount << " entries" << endl; inputFile.close(); cout << endl << "*******************************************************************" << endl << "DISTANCE CALCULATOR v2.0\tAuthors: Darius Hodaei, Joe Clifton" << endl; } void menuInput() { char menuChoice = ' '; while(menuChoice != 'Q') { // Menu if(skipKey != 'X') // This is set by case 'S' below if a searched term does not exist but wants to be added { cout << endl << "*******************************************************************" << endl; cout << "Please enter a choice for the menu..." << endl << endl; cout << "(P) To print out the list" << endl << "(O) To order the list alphabetically" << endl << "(A) To add a location" << endl << "(D) To delete a record" << endl << "(C) To calculate distance between two points" << endl << "(S) To search for a location in the list" << endl << "(M) To check memory usage" << endl << "(U) To update a record" << endl << "(Q) To quit" << endl; cout << endl << "*******************************************************************" << endl; cin >> menuChoice; if(menuChoice >= 97) { menuChoice = menuChoice - 32; // Turn the lower case letter into an upper case letter } } skipKey = ' '; //Reset skipKey so that it does not skip the menu switch(menuChoice) { case 'P': temp = start_ptr; // set temp to the start of the list do { if (temp == NULL) { cout << "You have reached the end of the database" << endl; } else { // Display details for what temp points to at that stage cout << "Location : " << temp->nodeCityName << endl; cout << "Latitude : " << temp->nodeLati << endl; cout << "Longitude : " << temp->nodeLongi << endl; cout << endl; // Move on to next locationNode if one exists temp = temp->Next; } } while (temp != NULL); break; case 'O': { sortList(); // pass by reference??? cout << "List reordered alphabetically" << endl; } break; case 'A': char cityName[35]; double lati, longi; cout << endl << "Enter the name of the location: "; cin >> cityName; for(xx = 0; cityName[xx] != NULL; xx++) { if(cityName[xx] == 47) // if it is a '/' { cityName[xx] = 32; // replace it for a space } } if(!nodeExistTest(cityName)) { cout << endl << "Please enter the latitude value for this location: "; cin >> lati; cout << endl << "Please enter the longitude value for this location: "; cin >> longi; cout << endl; temp = new locationNode(cityName, lati, longi); temp->correctCase(); //start_ptr allignment if(start_ptr == NULL){ // if list is currently empty, start_ptr will point to this node start_ptr = temp; } else { temp2 = start_ptr; // We know this is not NULL - list not empty! while (temp2->Next != NULL) { temp2 = temp2->Next; // Move to next link in chain until reach end of list } temp2->Next = temp; } ++locationCount; // increment counter for number of records in list cout << "Location sucessfully added to the database! There are " << locationCount << " location(s) stored" << endl; } else { cout << "Node is already present in the list and so cannot be added again" << endl; } break; case 'D': { junction = 0; locationNode *place; cout << "Enter the name of the city you wish to remove" << endl; cin >> targetCity; setElementsNull(targetCity); correctCase(targetCity); for(xx = 0; targetCity[xx] != NULL; xx++) { if(targetCity[xx] == 47) { targetCity[xx] = 32; } } if(nodeExistTest(targetCity)) //if this node does exist { if(seek == start_ptr) // if it is the first in the list { junction = 1; } if(seek->Next == NULL) // if it is last in the list { junction = 2; } switch(junction) // will alter list accordingly dependant on where the searched for link is { case 1: start_ptr = start_ptr->Next; delete seek; --locationCount; break; case 2: place = seek; seek = bridge; seek->Next = NULL; delete place; --locationCount; break; default: bridge->Next = seek->Next; delete seek; --locationCount; break; } cout << endl << "Link deleted. There are now " << locationCount << " locations." << endl; } else { cout << "That entry does not currently exist" << endl << endl << endl; } } break; case 'C': { char city1[35], city2[35]; cout << "Enter the first city name" << endl; cin >> city1; setElementsNull(city1); correctCase(targetCity); if(nodeExistTest(city1)) { lat1 = seek->nodeLati; lon1 = seek->nodeLongi; cout << "Lati = " << seek->nodeLati << endl << "Longi = " << seek->nodeLongi << endl << endl; } cout << "Enter the second city name" << endl; cin >> city2; setElementsNull(city2); correctCase(targetCity); if(nodeExistTest(city2)) { lat2 = seek->nodeLati; lon2 = seek->nodeLongi; cout << "Lati = " << seek->nodeLati << endl << "Longi = " << seek->nodeLongi << endl << endl; } result = distance (lat1, lon1, lat2, lon2, dist); cout << "The distance between these two locations is " << result << " kilometres." << endl; } break; case 'S': { char choice; cout << "Enter search term..." << endl; cin >> targetCity; setElementsNull(targetCity); correctCase(targetCity); if(nodeExistTest(targetCity)) { cout << "Latitude: " << seek->nodeLati << endl << "Longitude: " << seek->nodeLongi << endl; } else { cout << "Sorry, that city is not currently present in the list." << endl << "Would you like to add this city now Y/N?" << endl; cin >> choice; /*while(choice != ('Y' || 'N')) { cout << "Please enter a valid choice..." << endl; cin >> choice; }*/ switch(choice) { case 'Y': skipKey = 'X'; menuChoice = 'A'; break; case 'N': break; default : cout << "Invalid choice" << endl; break; } } break; } case 'M': { cout << "Locations currently stored: " << locationCount << endl << "Memory used for this: " << (sizeof(start_ptr) * locationCount) << " bytes" << endl << endl << "You can store " << ((gig - (sizeof(start_ptr) * locationCount)) / sizeof(start_ptr)) << " more locations" << endl ; break; } case 'U': { cout << "Enter the name of the Location you would like to update: "; cin >> targetCity; setElementsNull(targetCity); correctCase(targetCity); if(nodeExistTest(targetCity)) { cout << "Select (1) to alter City Name, (2) to alter Longitude, (3) to alter Latitude" << endl; cin >> modKey; switch(modKey) { case 1: cout << "Enter the new name: "; cin >> alter; cout << endl; seek->modify(alter); break; case 2: cout << "Enter the new latitude: "; cin >> modVal; cout << endl; seek->modify(modVal, modKey); break; case 3: cout << "Enter the new longitude: "; cin >> modVal; cout << endl; seek->modify(modVal, modKey); break; default: break; } } else cout << "Location not found" << endl; break; } } } } }; int main(array<System::String ^> ^args) { Menu mm; //mm.initialise(); mm.menuInput(); mm.serialise(); }

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