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  • Prime Numbers Code Help

    - by andrew
    Hello Everybody, I am suppose to "write a Java program that reads a positive integer n from standard input, then prints out the first n prime number." It's divided into 3 parts. 1st: This function will return true or false according to whether m is prime or composite. The array argument P will contain a sufficient number of primes to do the testing. Specifically, at the time isPrime() is called, array P must contain (at least) all primes p in the range 2 p m . For instance, to test m = 53 for primality, one must do successive trial divisions by 2, 3, 5, and 7. We go no further since 11 53 . Thus a precondition for the function call isPrime(53, P) is that P[0] = 2 , P[1] = 3 , P[2] = 5, and P[3] = 7 . The return value in this case would be true since all these divisions fail. Similarly to test m =143 , one must do trial divisions by 2, 3, 5, 7, and 11 (since 13 143 ). The precondition for the function call isPrime(143, P) is therefore P[0] = 2 , P[1] = 3 , P[2] = 5, P[3] = 7 , and P[4] =11. The return value in this case would be false since 11 divides 143. Function isPrime() should contain a loop that steps through array P, doing trial divisions. This loop should terminate when 2 either a trial division succeeds, in which case false is returned, or until the next prime in P is greater than m , in which case true is returned. Then there is the "main function" • Check that the user supplied exactly one command line argument which can be interpreted as a positive integer n. If the command line argument is not a single positive integer, your program will print a usage message as specified in the examples below, then exit. • Allocate array Primes[] of length n and initialize Primes[0] = 2 . • Enter a loop which will discover subsequent primes and store them as Primes[1] , Primes[2], Primes[3] , ……, Primes[n -1] . This loop should contain an inner loop which walks through successive integers and tests them for primality by calling function isPrime() with appropriate arguments. • Print the contents of array Primes[] to stdout, 10 to a line separated by single spaces. In other words Primes[0] through Primes[9] will go on line 1, Primes[10] though Primes[19] will go on line 2, and so on. Note that if n is not a multiple of 10, then the last line of output will contain fewer than 10 primes. The last function is called "usage" which I am not sure how to execute this! Your program will include a function called Usage() having signature static void Usage() that prints this message to stderr, then exits. Thus your program will contain three functions in all: main(), isPrime(), and Usage(). Each should be preceded by a comment block giving it’s name, a short description of it’s operation, and any necessary preconditions (such as those for isPrime().) And hear is my code, but I am having a bit of a problem and could you guys help me fix it? If I enter the number "5" it gives me the prime numbers which are "6,7,8,9" which doesn't make much sense. import java.util.; import java.io.; import java.lang.*; public class PrimeNumber { static boolean isPrime(int m, int[] P){ int squarert = Math.round( (float)Math.sqrt(m) ); int i = 2; boolean ans=false; while ((i<=squarert) & (ans==false)) { int c= P[i]; if (m%c==0) ans= true; else ans= false; i++; } /* if(ans ==true) ans=false; else ans=true; return ans; } ///****main public static void main(String[] args ) { Scanner in= new Scanner(System.in); int input= in.nextInt(); int i, j; int squarert; boolean ans = false; int userNum; int remander = 0; System.out.println("input: " + input); int[] prime = new int[input]; prime[0]= 2; for(i=1; i ans = isPrime(j,prime); j++;} prime[i] = j; } //prnt prime System.out.println("The first " + input + " prime number(s) are: "); for(int r=0; r }//end of main } Thanks for the help

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  • Checking if an int is prime more efficiently

    - by SipSop
    I recently was part of a small java programming competition at my school. My partner and I have just finished our first pure oop class and most of the questions were out of our league so we settled on this one (and I am paraphrasing somewhat): "given an input integer n return the next int that is prime and its reverse is also prime for example if n = 18 your program should print 31" because 31 and 13 are both prime. Your .class file would then have a test case of all the possible numbers from 1-2,000,000,000 passed to it and it had to return the correct answer within 10 seconds to be considered valid. We found a solution but with larger test cases it would take longer than 10 seconds. I am fairly certain there is a way to move the range of looping from n,..2,000,000,000 down as the likely hood of needing to loop that far when n is a low number is small, but either way we broke the loop when a number is prime under both conditions is found. At first we were looping from 2,..n no matter how large it was then i remembered the rule about only looping to the square root of n. Any suggestions on how to make my program more efficient? I have had no classes dealing with complexity analysis of algorithms. Here is our attempt. public class P3 { public static void main(String[] args){ long loop = 2000000000; long n = Integer.parseInt(args[0]); for(long i = n; i<loop; i++) { String s = i +""; String r = ""; for(int j = s.length()-1; j>=0; j--) r = r + s.charAt(j); if(prime(i) && prime(Long.parseLong(r))) { System.out.println(i); break; } } System.out.println("#"); } public static boolean prime(long p){ for(int i = 2; i<(int)Math.sqrt(p); i++) { if(p%i==0) return false; } return true; } } ps sorry if i did the formatting for code wrong this is my first time posting here. Also the output had to have a '#' after each line thats what the line after the loop is about Thanks for any help you guys offer!!!

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  • C++ question on prime numbers.

    - by user278330
    Hello. I am trying to make a program that determines if the number is prime or composite. I have gotten thus far. Could you give me any ideas so that it will work? All primes will , however, because composites have values that are both r0 and r==0, they will always be classified as prime. How can I fix this? int main() { int pNumber, limit, x, r; limit = 0; x = 2; cout << "Please enter any positive integer: " ; cin >> pNumber; if (pNumber < 0) { cout << "Invalid. Negative Number. " << endl; return 0; } else if (pNumber == 0) { cout << "Invalid. Zero has an infinite number of divisors, and therefore neither composite nor prime." << endl; return 0; } else if (pNumber == 1) { cout << "Valid. However, one is neither prime nor composite" << endl; return 0; } else { while (limit < pNumber) { r = pNumber % x; x++; limit++; } if (r == 0) cout << "Your number is composite" << endl; else cout << "Your number is prime" << endl; } return 0; }

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  • C++ question on prime numbers.

    - by user278330
    Hello. I am trying to make a program that determines if the number is prime or composite. I have gotten thus far. Could you give me any ideas so that it will work? All primes will , however, because composites have values that are both r0 and r==0, they will always be classified as prime. How can I fix this? int main() { int pNumber, limit, x, r; limit = 0; x = 2; cout << "Please enter any positive integer: " ; cin >> pNumber; if (pNumber < 0) { cout << "Invalid. Negative Number. " << endl; return 0; } else if (pNumber == 0) { cout << "Invalid. Zero has an infinite number of divisors, and therefore neither composite nor prime." << endl; return 0; } else if (pNumber == 1) { cout << "Valid. However, one is neither prime nor composite" << endl; return 0; } else { while (limit < pNumber) { r = pNumber % x; x++; limit++; } if (r == 0) cout << "Your number is composite" << endl; else cout << "Your number is prime" << endl; } return 0; }

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  • Generating exactly prime number with Java

    - by Viet
    Hi, I'm aware of the function BigInteger.probablePrime(int bitLength, Random rnd) that outputs probably prime number of any bit length. I want a REAL prime number in Java. Is there any FOSS library to do so with acceptable performance? Thanks in advance!

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  • fastest calculation of largest prime factor of 512 bit number in python

    - by miraclesoul
    dear all, i am simulating my crypto scheme in python, i am a new user to it. p = 512 bit number and i need to calculate largest prime factor for it, i am looking for two things: Fastest code to process this large prime factorization Code that can take 512 bit of number as input and can handle it. I have seen different implementations in other languages, my whole code is in python and this is last point where i am stuck. So let me know if there is any implementation in python. Kindly explain in simple as i am new user to python sorry for bad english.

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  • Help with Java Program for Prime numbers

    - by Ben
    Hello everyone, I was wondering if you can help me with this program. I have been struggling with it for hours and have just trashed my code because the TA doesn't like how I executed it. I am completely hopeless and if anyone can help me out step by step, I would greatly appreciate it. In this project you will write a Java program that reads a positive integer n from standard input, then prints out the first n prime numbers. We say that an integer m is divisible by a non-zero integer d if there exists an integer k such that m = k d , i.e. if d divides evenly into m. Equivalently, m is divisible by d if the remainder of m upon (integer) division by d is zero. We would also express this by saying that d is a divisor of m. A positive integer p is called prime if its only positive divisors are 1 and p. The one exception to this rule is the number 1 itself, which is considered to be non-prime. A positive integer that is not prime is called composite. Euclid showed that there are infinitely many prime numbers. The prime and composite sequences begin as follows: Primes: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, … Composites: 1, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, … There are many ways to test a number for primality, but perhaps the simplest is to simply do trial divisions. Begin by dividing m by 2, and if it divides evenly, then m is not prime. Otherwise, divide by 3, then 4, then 5, etc. If at any point m is found to be divisible by a number d in the range 2 d m-1, then halt, and conclude that m is composite. Otherwise, conclude that m is prime. A moment’s thought shows that one need not do any trial divisions by numbers d which are themselves composite. For instance, if a trial division by 2 fails (i.e. has non-zero remainder, so m is odd), then a trial division by 4, 6, or 8, or any even number, must also fail. Thus to test a number m for primality, one need only do trial divisions by prime numbers less than m. Furthermore, it is not necessary to go all the way up to m-1. One need only do trial divisions of m by primes p in the range 2 p m . To see this, suppose m 1 is composite. Then there exist positive integers a and b such that 1 < a < m, 1 < b < m, and m = ab . But if both a m and b m , then ab m, contradicting that m = ab . Hence one of a or b must be less than or equal to m . To implement this process in java you will write a function called isPrime() with the following signature: static boolean isPrime(int m, int[] P) This function will return true or false according to whether m is prime or composite. The array argument P will contain a sufficient number of primes to do the testing. Specifically, at the time isPrime() is called, array P must contain (at least) all primes p in the range 2 p m . For instance, to test m = 53 for primality, one must do successive trial divisions by 2, 3, 5, and 7. We go no further since 11 53 . Thus a precondition for the function call isPrime(53, P) is that P[0] = 2 , P[1] = 3 , P[2] = 5, and P[3] = 7 . The return value in this case would be true since all these divisions fail. Similarly to test m =143 , one must do trial divisions by 2, 3, 5, 7, and 11 (since 13 143 ). The precondition for the function call isPrime(143, P) is therefore P[0] = 2 , P[1] = 3 , P[2] = 5, P[3] = 7 , and P[4] =11. The return value in this case would be false since 11 divides 143. Function isPrime() should contain a loop that steps through array P, doing trial divisions. This loop should terminate when 2 either a trial division succeeds, in which case false is returned, or until the next prime in P is greater than m , in which case true is returned. Function main() in this project will read the command line argument n, allocate an int array of length n, fill the array with primes, then print the contents of the array to stdout according to the format described below. In the context of function main(), we will refer to this array as Primes[]. Thus array Primes[] plays a dual role in this project. On the one hand, it is used to collect, store, and print the output data. On the other hand, it is passed to function isPrime() to test new integers for primality. Whenever isPrime() returns true, the newly discovered prime will be placed at the appropriate position in array Primes[]. This process works since, as explained above, the primes needed to test an integer m range only up to m , and all of these primes (and more) will already be stored in array Primes[] when m is tested. Of course it will be necessary to initialize Primes[0] = 2 manually, then proceed to test 3, 4, … for primality using function isPrime(). The following is an outline of the steps to be performed in function main(). • Check that the user supplied exactly one command line argument which can be interpreted as a positive integer n. If the command line argument is not a single positive integer, your program will print a usage message as specified in the examples below, then exit. • Allocate array Primes[] of length n and initialize Primes[0] = 2 . • Enter a loop which will discover subsequent primes and store them as Primes[1] , Primes[2], Primes[3] , ……, Primes[n -1] . This loop should contain an inner loop which walks through successive integers and tests them for primality by calling function isPrime() with appropriate arguments. • Print the contents of array Primes[] to stdout, 10 to a line separated by single spaces. In other words Primes[0] through Primes[9] will go on line 1, Primes[10] though Primes[19] will go on line 2, and so on. Note that if n is not a multiple of 10, then the last line of output will contain fewer than 10 primes. Your program, which will be called Prime.java, will produce output identical to that of the sample runs below. (As usual % signifies the unix prompt.) % java Prime Usage: java Prime [PositiveInteger] % java Prime xyz Usage: java Prime [PositiveInteger] % java Prime 10 20 Usage: java Prime [PositiveInteger] % java Prime 75 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199 211 223 227 229 233 239 241 251 257 263 269 271 277 281 283 293 307 311 313 317 331 337 347 349 353 359 367 373 379 % 3 As you can see, inappropriate command line argument(s) generate a usage message which is similar to that of many unix commands. (Try doing the more command with no arguments to see such a message.) Your program will include a function called Usage() having signature static void Usage() that prints this message to stderr, then exits. Thus your program will contain three functions in all: main(), isPrime(), and Usage(). Each should be preceded by a comment block giving it’s name, a short description of it’s operation, and any necessary preconditions (such as those for isPrime().) See examples on the webpage.

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  • Quickly determine if a number is prime in Python for numbers < 1 billion

    - by Frór
    Hi, My current algorithm to check the primality of numbers in python is way to slow for numbers between 10 million and 1 billion. I want it to be improved knowing that I will never get numbers bigger than 1 billion. The context is that I can't get an implementation that is quick enough for solving problem 60 of project Euler: I'm getting the answer to the problem in 75 seconds where I need it in 60 seconds. http://projecteuler.net/index.php?section=problems&id=60 I have very few memory at my disposal so I can't store all the prime numbers below 1 billion. I'm currently using the standard trial division tuned with 6k±1. Is there anything better than this? Do I already need to get the Rabin-Miller method for numbers that are this large. primes_under_100 = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97] def isprime(n): if n <= 100: return n in primes_under_100 if n % 2 == 0 or n % 3 == 0: return False for f in range(5, int(n ** .5), 6): if n % f == 0 or n % (f + 2) == 0: return False return True How can I improve this algorithm?

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  • Ubuntu for Android on the ASUS Transformer Prime

    - by sola
    I would like to use Ubuntu on my Transformer Prime in parallel with Android (not as a dual booting solution, I want to be able to switch between them instantaniously). I am aware of the traditional chrooting/VNC solution but I heard that it performs very poorly so I would like to use Ubuntu For Android (UFA) which has been announced recently by Canonical. That looks like a polished, highly integrated solution for Android devices. The Prime would be the ideal device for Ubuntu For Android since it has a powerful processor (Tegra3) capable of running a lot of processes in parallel on its 4 cores. Does anyone know if Canonical or anybody else is working on supporting UFA on the ASUS Transformer Prime? As far as I understand, the X11 driver is available for Tegra3 so, the biggest hurdle may be easily overcome.

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  • Multiple Monitors using nvidia-prime or bumblebee on Ubuntu 13.10

    - by user205626
    I've been unable to get multiple monitors to work with Ubuntu 13.10 using nvidia-prime or bumblebee. Could someone point me in the right direction? With nvidia-prime, I've tried the xorg.conf here http://us.download.nvidia.com/XFree86/Linux-x86/319.12/README/randr14.html, but I boot into "low graphics" mode and have to revert to get a desktop back. Any suggestions would be appreciated. Thanks. Edit: I've given up on nvidia-prime; I missed the fact that it never turns off the discrete card... So, I'm back to trying to get VIRTUAL displays working with Bumblebee.

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  • Does Ubuntu run on current Asus Transformer Prime?

    - by Ubuntu User
    I've read instructions about dual boot Android / Transformer Prime (a significant factor in ordering one). Also about not working with /latest/ Transformer Prime (firmware / BIOS?) Also about imminent Ubuntu ARM support. Will I be able to run Ubuntu in a day or two when Transformer arrives? Also, am I right to assume I can restore Transformer to factory status if I break something in the attempt?

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  • Protected Videos not Playing Ubuntu 13.10 (Amazon Prime)

    - by Radeesh Koonichere
    Unable to play amazon prime videos with Chrome/Firefox browser. Tried deleting the Flash folder, re-installed OS. Ubuntu 13.10 Flash Version: flashplugin-installer 11.2.202.310ubuntu1 Youtube works but not Amazon Prime. Try 1 Clear Cache Flash cd ~/.adobe/Flash_Player rm -rf NativeCache AssetCache APSPrivateData2 Try 2 Install Older version of Flash /usr/lib/flashplugin-installer/Flashplayer.so Some other sites have installing HAL and running hald but that was not working either as it seems to be a deprecated. sudo apt-get install hal

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  • program logic of printing the prime numbers

    - by Vignesh Vicky
    can any body help to understand this java program it just print prime n.o ,as you enter how many you want and it works good class PrimeNumbers { public static void main(String args[]) { int n, status = 1, num = 3; Scanner in = new Scanner(System.in); System.out.println("Enter the number of prime numbers you want"); n = in.nextInt(); if (n >= 1) { System.out.println("First "+n+" prime numbers are :-"); System.out.println(2); } for ( int count = 2 ; count <=n ; ) { for ( int j = 2 ; j <= Math.sqrt(num) ; j++ ) { if ( num%j == 0 ) { status = 0; break; } } if ( status != 0 ) { System.out.println(num); count++; } status = 1; num++; } } } i dont understand this for loop condition for ( int j = 2 ; j <= Math.sqrt(num) ; j++ ) why we are taking sqrt of num...which is 3....why we assumed it as 3?

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  • Can you tell me why this generates time limit exceeded in spoj(Prime Number Generator)

    - by magiix
    #include<iostream> #include<string.h> #include<math.h> using namespace std; bool prime[1000000500]; void generate(long long end) { memset(prime,true,sizeof(prime)); prime[0]=false; prime[1]=false; for(long long i=0;i<=sqrt(end);i++) { if(prime[i]==true) { for(long long y=i*i;y<=end;y+=i) { prime[y]=false; } } } } int main() { int n; long long b,e; scanf("%d",&n); while(n--) { cin>>b>>e; generate(e); for(int i=b;i<e;i++) { if(prime[i]) printf("%d\n",i); } } return 0; } That's my code for spoj prime generator. Altought it generates the same output as another accepted code ..

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  • printing out prime numbers from array

    - by landscape
    I'd like to print out all prime numbers from an array with method. I can do it with one int but don't know how to return certain numbers from array. Thanks for help! public static boolean isPrime(int [] tab) { boolean prime = true; for (int i = 3; i <= Math.sqrt(tab[i]); i += 2) if (tab[i] % i == 0) { prime = false; break; } for(int i=0; i<tab.length; i++) if (( tab[i]%2 !=0 && prime && tab[i] > 2) || tab[i] == 2) { return true; } else { return false; } //return prime; } thanks both of you. Seems like its solved: public static void isPrime(int[] tab) { for (int i = 0; i < tab.length; i++) { if (isPrimeNum(tab[i])) { System.out.println(tab[i]); } } } public static boolean isPrimeNum(int n) { boolean prime = true; for (long i = 3; i <= Math.sqrt(n); i += 2) { if (n % i == 0) { prime = false; break; } } if ((n % 2 != 0 && prime && n > 2) || n == 2) { return true; } else { return false; } }

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  • Adobe flash player not working with Amazon Prime

    - by Alex
    I have ubuntu 12.04 64bit using Google Chrome. I had chromium from the app center then today amazon prime video stopped working. It told me to update Flash. So I uninstalled chromium and installed Google Chrome. Didn't work. Then I downloaded flash for ubuntu via apt. That one gave me a "flash version isn't supported" message. The flash version was 11. Now I tried http://apt.ubuntu.com/p/flashplugin-installer It worked, but right in the middle of the video, it popped the error message again. Sorry we are unable to stream this video. This is likely because your Flash Player needs to be updated. So I don't know what happened.

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  • Windows 7 doesnt boot after installing Ubuntu 12.10 (Asus Zenbook Prime / UEFI problem)

    - by jpdus
    Today I installed Ubuntu and since then i cannot boot into Windows anymore. I used the "standard" option (didnt change any partitions manually, just entered the size) but used the UEFI-mode. At first the GRUB entries for Windows did not work at all, after reading this thead i was able to add a new Grub entry - now i can get into the "windows-loading" screen for a few seconds but then i always see some kind of bluescreen for a fraction of a second and the laptop reboots. I can get into the windows recovery partition but the only option there is to reset everything to factory settings (+erase all data). I have no idea how to get into the Windows 7 repair mode which was mentioned here (tried everything else in this thread too - no success). My boot info can be found here: http://paste.ubuntu.com/1411573/ I have no idea what went wrong (there is even an extra page for the Zenbook Prime where no installation problems are mentioned). I would appreciate any help/ideas, many thanks!

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  • Is 12.10 ready from prime time?

    - by Mikey
    I recently installed 12.10 - dual boot using Wubi. I had numerous stability problems: many sporadic, unaccounted for system errors, software that was installed and then seemed to disappear from App Launcher, etc. Machine is new HP quad with 4 gig memory - wonderful piece of hardware - definitely no hardware problems there. I went back to 12.04 (installed from ISO image, not Wubi) and it's rock solid - never any issues at all. Is 12.10 not ready for prime time? Are there fixes-updates in the pipe? Should I get a DVD disc and install 12.10 from ISO instead of Wubi? New to Linux/Ubuntu after 20 years on MS/Windows and loving it - I develop in C++ and Python - maybe will try Lazarus since I know Delphi. Would like to use the latest and greatest Ubuntu but I will not sacrifice stabilty. Are there known problems with 12.10? Would using the standard install instead of Wubi help? Seems a lot of users are voting down this question - not sure why since other users have confirmed problems.

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  • Recommended Method to Watch Amazon Prime using Ubuntu 14.04 LTS

    - by Kurt Sanger
    I realize that Hal is no longer in the Ubuntu Software Center for Ubuntu 14.04 and it is only available from a third party at this time. But I would like to know what Ubuntu's plans are for integrating DRM into Linux? Especially with Amazon's integration into the search tool, one would hope that they would make it easier for their Amazon Prime customers to watch Instant Videos. Is the repository for getting Hal for 13.10 safe for use? What will that break if I install it onto 14.04? Or do we need to find another OS that has DRM built into it? If Hal is okay to add to the OS using a third party repo, then why doesn't Ubuntu Software Center support it too? I imagine that Amazon's contract with the video copyright holders requires that they have some protection on electronically distributed media. I also imagine that getting Amazon to change is much harder than getting a bunch of software engineers to fix Ubuntu. Unless they don't want too. At which point Ubuntu isn't really a complete OS. Very disappointing. In general the ease of use of Ubuntu, the software center, and the large variety of applications was alluring. But breaking DRM wasn't a great idea. Can't wait to see what fails in our next update. Please tell us that there is a plan that is going to work in our future.

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  • Is event sourcing ready for prime time?

    - by Dakotah North
    Event Sourcing was popularized by LMAX as a means to provide speed, performance scalability, transparent persistence and transparent live mirroring. Before being rebranded as Event Sourcing, this type of architectural pattern was known as System Prevalence but yet I was never familiar with this pattern before the LMAX team went public. Has this pattern proved itself in numerous production systems and therefore even conservative individuals should feel empowered to embrace this pattern or is event sourcing / system prevalence an exotic pattern that is best left for the fearless?

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  • Is Scala ready for prime time?

    - by jayraynet
    Now that I've done a few trivial things with Scala (which I love for "hello world" and contrived applications!) I am left wondering.. part about maturity of the tools to support development, and part about general applicability. Are the toolsets ready? Is Scala appropriate for use on enterprise / business applications? Would "you" use it on a non-trivial project? Some of my (possibly unfounded) concerns would be: are the IDE and toolsets as rich as what we have to develop .net and java applications (eclipse for Scala seems limited compared to eclipse for java)? are the build / CI / testing toolsets able to effectively deal with Scala? how maintainable is the concise code that can be (encouraged?) written in the language? is it possible to find developers with Scala experience? is there enough critical mass to get help through on-line reference and books that are more than "intro" to the language? So bottom line - is the ecosystem mature enough to use now, or better off waiting to see how it evolves? EDIT: let's say "non-trivial" is a multi-year, multi-release, 10-20 developers project.

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  • assembly language programming (prime number)

    - by chris
    Prompt the user for a positive three digit number, then read it. Let's call it N. Divide into N all integer values from 2 to (N/2)+1 and test to see if the division was even, in which case N is instantly shown to be non-prime. Output a message printing N and saying that it is not prime. If none of those integer values divide evenly (remainder never is zero), then N is shown to be prime. Output a message printing N and saying that it is prime. Ask the user if he or she wants to test another number; if the user types "n" or "N", quit. If "y" or "Y", jump back and repeat. Comments in your code are essential. Hi. I am kinda in rush to do this.. please help me doing it. I'll be much appreciated. thank you

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