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  • How can I use GPRename's regex feature to reinsert the matched-group into the 'replace'?

    - by David Thomas
    I've been using GPRename to batch-rename files; this is rather more efficient than individually correcting each file, but still seems to be less efficient than it might be, primarily because either I don't understand the regex syntax used, or because the regex implementation is incomplete1 Given a list of files of the following syntax: (01) - title of file1.avi (02) - title of file2.avi (03) - title of file3.avi I attempted to use the 'replace' (with the regex option selected, the case-sensitive option deselected): (\(\d{2}\)) The preview then shows (given that I've specified no 'replace with' option as yet): title of file1.avi title of file2.avi title of file3.avi Which is great, clearly the regex is identifying the correct group (the (01)). Now, what I was hoping to do (using the JavaScript syntax) in the 'replace with' option is use: $1 (I also tried using '$1', \1 and '\1') This was just to check that I could access the matched group, and it seems I can't, the matched group is, as I suppose might be expected, replaced with the literal replacement string. So, my question: is it possible to match a particular group of characters, in this case the numbers within the brackets, and then insert those into the replacement string? Therefore: (01) title of file1.avi (02) title of file2.avi (03) title of file3.avi Becomes: 01 title of file1.avi 02 title of file2.avi 03 title of file3.avi I absolutely suspect the former, personally.

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