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  • python getelementbyid from string

    - by matthewgall
    Hey, I have the following program, that is trying to upload a file (or files) to an image upload site, however I am struggling to find out how to parse the returned HTML to grab the direct link (contained in a ). I have the code below: #!/usr/bin/python # -*- coding: utf-8 -*- import pycurl import urllib import urlparse import xml.dom.minidom import StringIO import sys import gtk import os import imghdr import locale import gettext try: import pynotify except: print "Please install pynotify." APP="Uploadir Uploader" DIR="locale" locale.setlocale(locale.LC_ALL, '') gettext.bindtextdomain(APP, DIR) gettext.textdomain(APP) _ = gettext.gettext ##STRINGS uploading = _("Uploading image to Uploadir.") oneimage = _("1 image has been successfully uploaded.") multimages = _("images have been successfully uploaded.") uploadfailed = _("Unable to upload to Uploadir.") class Uploadir: def __init__(self, args): self.images = [] self.urls = [] self.broadcasts = [] self.username="" self.password="" if len(args) == 1: return else: for file in args: if file == args[0] or file == "": continue if file.startswith("-u"): self.username = file.split("-u")[1] #print self.username continue if file.startswith("-p"): self.password = file.split("-p")[1] #print self.password continue self.type = imghdr.what(file) self.images.append(file) for file in self.images: self.upload(file) self.setClipBoard() self.broadcast(self.broadcasts) def broadcast(self, l): try: str = '\n'.join(l) n = pynotify.Notification(str) n.set_urgency(pynotify.URGENCY_LOW) n.show() except: for line in l: print line def upload(self, file): #Try to login cookie_file_name = "/tmp/uploadircookie" if ( self.username!="" and self.password!=""): print "Uploadir authentication in progress" l=pycurl.Curl() loginData = [ ("username",self.username),("password", self.password), ("login", "Login") ] l.setopt(l.URL, "http://uploadir.com/user/login") l.setopt(l.HTTPPOST, loginData) l.setopt(l.USERAGENT,"User-Agent: Uploadir (Python Image Uploader)") l.setopt(l.FOLLOWLOCATION,1) l.setopt(l.COOKIEFILE,cookie_file_name) l.setopt(l.COOKIEJAR,cookie_file_name) l.setopt(l.HEADER,1) loginDataReturnedBuffer = StringIO.StringIO() l.setopt( l.WRITEFUNCTION, loginDataReturnedBuffer.write ) if l.perform(): self.broadcasts.append("Login failed. Please check connection.") l.close() return loginDataReturned = loginDataReturnedBuffer.getvalue() l.close() #print loginDataReturned if loginDataReturned.find("<li>Your supplied username or password is invalid.</li>")!=-1: self.broadcasts.append("Uploadir authentication failed. Username/password invalid.") return else: self.broadcasts.append("Uploadir authentication successful.") #cookie = loginDataReturned.split("Set-Cookie: ")[1] #cookie = cookie.split(";",0) #print cookie c = pycurl.Curl() values = [ ("file", (c.FORM_FILE, file)) ] buf = StringIO.StringIO() c.setopt(c.URL, "http://uploadir.com/file/upload") c.setopt(c.HTTPPOST, values) c.setopt(c.COOKIEFILE, cookie_file_name) c.setopt(c.COOKIEJAR, cookie_file_name) c.setopt(c.WRITEFUNCTION, buf.write) if c.perform(): self.broadcasts.append(uploadfailed+" "+file+".") c.close() return self.result = buf.getvalue() #print self.result c.close() doc = urlparse.urlparse(self.result) self.urls.append(doc.getElementsByTagName("download")[0].childNodes[0].nodeValue) def setClipBoard(self): c = gtk.Clipboard() c.set_text('\n'.join(self.urls)) c.store() if len(self.urls) == 1: self.broadcasts.append(oneimage) elif len(self.urls) != 0: self.broadcasts.append(str(len(self.urls))+" "+multimages) if __name__ == '__main__': uploadir = Uploadir(sys.argv) Any help would be gratefully appreciated. Warm regards,

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