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  • Massive Google Street View Update: 250,000 Miles of Roadways, New Special Collections, and More

    - by Jason Fitzpatrick
    If you like tooling around in Google Street View to check out attractions near and far, you just got a whole lot more to look at. Street View’s new update adds in 250,000 miles of roads, increased coverage in over a dozen countries, and a whole pile of new special collections. From Russia to Taiwan to Canada, there’s thousands of new places and tens of thousands of new roads to explore. Hit up the link below to read the full announcement at the Google Maps blog. Making Google Maps More Comprehensive with Ciggest Street View Update Ever [Google Maps] HTG Explains: What is the Windows Page File and Should You Disable It? How To Get a Better Wireless Signal and Reduce Wireless Network Interference How To Troubleshoot Internet Connection Problems

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  • 62 miles up

    - by fatherjack
    RedGate are known for being a software company with a big personality and having a huge presence in the SQL Community. They run the annual Exceptional DBA competition, having held a party at the PASS summit last night to celebrate this years winner - Jeff Moden. They have also got a great attitude towards their staff as demonstrated on their website. Today, just after the PASS Summit keynote speech they made an announcement that is literally going to give one lucky winner the ride of their life....(read more)

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  • Is there a rule of thumb for what a bing map's zoom setting should be based on how many miles you want to display?

    - by Clay Shannon
    If a map contains pushpins/waypoints that span only a couple of miles, the map should be zoomed way in and show a lot of detail. If the pushpins/waypoints instead cover vast areas, such as hundreds or even thousands of miles, it should be zoomed way out. That's clear. My question is: is there a general guideline for mapping (no pun intended) Bing Maps zoom levels to a particular number of miles that separate the furthest apart points? e.g., is there some chart that has something like: Zoom level N shows 2 square miles Zoom level N shows 5 square miles etc.?

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  • How to download Miles Reid's Algebraic Geometry video on Windows and view it offline

    - by Tiez Ered
    I would really like to augment my knowledge of Algebraic Geometry from the lectures by Miles Reid which can be found here. However, since I do not have fast Internet all the time, I am searching ways to download these lectures and view them offline. This question was asked here but the answer is for Linux platform and I think this is the appropriate forum to ask for help. Can you please help me download? Thanks a lot.

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  • Finding Cities within 'X' Kilometers (or Miles)

    - by Mike Curry
    This may or may not be clear, leave me a comment if I am off base, or you need more information. Perhaps there is a solution out there already for what I want in PHP. I am looking for a function that will add or subtract a distance from a longitude OR latitude value. Reason: I have a database with all Latitudes and Longitudes in it and want to form a query to extract all cities within X kilometers (or miles). My query would look something like this... Select * From Cities Where (Longitude > X1 and Longitude < X2) And (Latitude > Y1 and Latitude < Y2) Where X1 = Longitude - (distance) Where X2 = Longitude + (distance) Where Y1 = Latitude - (distance) Where Y2 = Latitude + (distance) I am working in PHP, with a MySql Database. Open to any suggestions also! :)

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  • How toget a list of "fastest miles" from a set of GPS Points

    - by santiagobasulto
    I'm trying to solve a weird problem. Maybe you guys know of some algorithm that takes care of this. I have data for a cargo freight truck and want to extract some data. Suppose I've got a list of sorted points that I get from the GPS. That's the route for that truck: [ { "lng": "-111.5373066", "lat": "40.7231711", "time": "1970-01-01T00:00:04Z", "elev": "1942.1789265256325" }, { "lng": "-111.5372056", "lat": "40.7228762", "time": "1970-01-01T00:00:07Z", "elev": "1942.109892409177" } ] Now, what I want to get is a list of the "fastest miles". I'll do an example: Given the points: A, B, C, D, E, F the distance from point A to point B is 1 mile, and the cargo took 10:32 minutes. From point B to point D i've got other mile, and the cargo took 10 minutes, etc. So, i need a list sorted by time. Similar to: B -> D: 10 A -> B: 10:32 D -> F: 11:02 Do you know any efficient algorithm that let me calculate that? Thank you all. PS: I'm using Python. EDIT: I've got the distance. I know how to calculate it and there are plenty of posts to do that. What I need is an algorithm to tokenize by mile and get speed from that. Having a distance function is not helpful enough: results = {} for point in points: aux_points = points.takeWhile(point>n) #This doesn't exist, just trying to be simple for aux_point in aux_points: d = distance(point, aux_point) if d == 1_MILE: time_elapsed = time(point, aux_point) results[time_elapsed] = (point, aux_point) I'm still doing some pretty inefficient calculations.

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  • Groovy 1.7 changes "final"?

    - by Aaron L. Carlow
    Just started learning Groovy, got the PragProg book "Programming Groovy" and had a problem compiling one of the sample scripts: class GCar2 { final miles = 0 def getMiles() { println "getMiles called" miles } def drive(dist) { if (dist > 0) { miles += dist } } } def car = new GCar2() println "Miles: $car.miles" println 'Driving' car.drive(10) println "Miles: $car.miles" try { print 'Can I see the miles? ' car.miles = 12 } catch (groovy.lang.ReadOnlyPropertyException ex) { println ex.message GroovyCar2.groovy: 20: cannnot access final field or property outside of constructor. @ line 20, column 35. def drive(dist) { if (dist > 0) miles += dist } ^ Groovy versions prior to 1.7 do not give an error. I looked through whatever documentation I could find and did not see the issue discussed. What is going on here? Aaron

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  • Torchlight II Drops Today; New Classes and Miles of Atmospheric Dungeon Crawling Await

    - by Jason Fitzpatrick
    Torchlight II, sequel to the extremely popular Torchlight action-RPG, is available for sale today. With four new classes and a massively expanded world, you’ll have plenty to explore. The new release features extra classes, extra companion creatures, in-game weather systems, and of course: updated graphics and a massively expanded game universe. Trumping all these additions, however, is LAN/internet co-op multiplayer–by far the feature most requested and anticipated by Torchlight fans. Check out the trailer video above to take a peak at the game, read more about it at the Torchlight II site, and then hit up the link below to grab a copy on Steam–you can pre-order it any time but it won’t be officially available for download until 2PM EST, today. Torchlight II is Windows-only, $19.99 for a single copy or $59.99 for a friend 4-pack (which includes a copy of Torchlight I). Torchlight II How To Create a Customized Windows 7 Installation Disc With Integrated Updates How to Get Pro Features in Windows Home Versions with Third Party Tools HTG Explains: Is ReadyBoost Worth Using?

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  • Basic Spatial Data with SQL Server and Entity Framework 5.0

    - by Rick Strahl
    In my most recent project we needed to do a bit of geo-spatial referencing. While spatial features have been in SQL Server for a while using those features inside of .NET applications hasn't been as straight forward as could be, because .NET natively doesn't support spatial types. There are workarounds for this with a few custom project like SharpMap or a hack using the Sql Server specific Geo types found in the Microsoft.SqlTypes assembly that ships with SQL server. While these approaches work for manipulating spatial data from .NET code, they didn't work with database access if you're using Entity Framework. Other ORM vendors have been rolling their own versions of spatial integration. In Entity Framework 5.0 running on .NET 4.5 the Microsoft ORM finally adds support for spatial types as well. In this post I'll describe basic geography features that deal with single location and distance calculations which is probably the most common usage scenario. SQL Server Transact-SQL Syntax for Spatial Data Before we look at how things work with Entity framework, lets take a look at how SQL Server allows you to use spatial data to get an understanding of the underlying semantics. The following SQL examples should work with SQL 2008 and forward. Let's start by creating a test table that includes a Geography field and also a pair of Long/Lat fields that demonstrate how you can work with the geography functions even if you don't have geography/geometry fields in the database. Here's the CREATE command:CREATE TABLE [dbo].[Geo]( [id] [int] IDENTITY(1,1) NOT NULL, [Location] [geography] NULL, [Long] [float] NOT NULL, [Lat] [float] NOT NULL ) Now using plain SQL you can insert data into the table using geography::STGeoFromText SQL CLR function:insert into Geo( Location , long, lat ) values ( geography::STGeomFromText ('POINT(-121.527200 45.712113)', 4326), -121.527200, 45.712113 ) insert into Geo( Location , long, lat ) values ( geography::STGeomFromText ('POINT(-121.517265 45.714240)', 4326), -121.517265, 45.714240 ) insert into Geo( Location , long, lat ) values ( geography::STGeomFromText ('POINT(-121.511536 45.714825)', 4326), -121.511536, 45.714825) The STGeomFromText function accepts a string that points to a geometric item (a point here but can also be a line or path or polygon and many others). You also need to provide an SRID (Spatial Reference System Identifier) which is an integer value that determines the rules for how geography/geometry values are calculated and returned. For mapping/distance functionality you typically want to use 4326 as this is the format used by most mapping software and geo-location libraries like Google and Bing. The spatial data in the Location field is stored in binary format which looks something like this: Once the location data is in the database you can query the data and do simple distance computations very easily. For example to calculate the distance of each of the values in the database to another spatial point is very easy to calculate. Distance calculations compare two points in space using a direct line calculation. For our example I'll compare a new point to all the points in the database. Using the Location field the SQL looks like this:-- create a source point DECLARE @s geography SET @s = geography:: STGeomFromText('POINT(-121.527200 45.712113)' , 4326); --- return the ids select ID, Location as Geo , Location .ToString() as Point , @s.STDistance( Location) as distance from Geo order by distance The code defines a new point which is the base point to compare each of the values to. You can also compare values from the database directly, but typically you'll want to match a location to another location and determine the difference for which you can use the geography::STDistance function. This query produces the following output: The STDistance function returns the straight line distance between the passed in point and the point in the database field. The result for SRID 4326 is always in meters. Notice that the first value passed was the same point so the difference is 0. The other two points are two points here in town in Hood River a little ways away - 808 and 1256 meters respectively. Notice also that you can order the result by the resulting distance, which effectively gives you results that are ordered radially out from closer to further away. This is great for searches of points of interest near a central location (YOU typically!). These geolocation functions are also available to you if you don't use the Geography/Geometry types, but plain float values. It's a little more work, as each point has to be created in the query using the string syntax, but the following code doesn't use a geography field but produces the same result as the previous query.--- using float fields select ID, geography::STGeomFromText ('POINT(' + STR (long, 15,7 ) + ' ' + Str(lat ,15, 7) + ')' , 4326), geography::STGeomFromText ('POINT(' + STR (long, 15,7 ) + ' ' + Str(lat ,15, 7) + ')' , 4326). ToString(), @s.STDistance( geography::STGeomFromText ('POINT(' + STR(long ,15, 7) + ' ' + Str(lat ,15, 7) + ')' , 4326)) as distance from geo order by distance Spatial Data in the Entity Framework Prior to Entity Framework 5.0 on .NET 4.5 consuming of the data above required using stored procedures or raw SQL commands to access the spatial data. In Entity Framework 5 however, Microsoft introduced the new DbGeometry and DbGeography types. These immutable location types provide a bunch of functionality for manipulating spatial points using geometry functions which in turn can be used to do common spatial queries like I described in the SQL syntax above. The DbGeography/DbGeometry types are immutable, meaning that you can't write to them once they've been created. They are a bit odd in that you need to use factory methods in order to instantiate them - they have no constructor() and you can't assign to properties like Latitude and Longitude. Creating a Model with Spatial Data Let's start by creating a simple Entity Framework model that includes a Location property of type DbGeography: public class GeoLocationContext : DbContext { public DbSet<GeoLocation> Locations { get; set; } } public class GeoLocation { public int Id { get; set; } public DbGeography Location { get; set; } public string Address { get; set; } } That's all there's to it. When you run this now against SQL Server, you get a Geography field for the Location property, which looks the same as the Location field in the SQL examples earlier. Adding Spatial Data to the Database Next let's add some data to the table that includes some latitude and longitude data. An easy way to find lat/long locations is to use Google Maps to pinpoint your location, then right click and click on What's Here. Click on the green marker to get the GPS coordinates. To add the actual geolocation data create an instance of the GeoLocation type and use the DbGeography.PointFromText() factory method to create a new point to assign to the Location property:[TestMethod] public void AddLocationsToDataBase() { var context = new GeoLocationContext(); // remove all context.Locations.ToList().ForEach( loc => context.Locations.Remove(loc)); context.SaveChanges(); var location = new GeoLocation() { // Create a point using native DbGeography Factory method Location = DbGeography.PointFromText( string.Format("POINT({0} {1})", -121.527200,45.712113) ,4326), Address = "301 15th Street, Hood River" }; context.Locations.Add(location); location = new GeoLocation() { Location = CreatePoint(45.714240, -121.517265), Address = "The Hatchery, Bingen" }; context.Locations.Add(location); location = new GeoLocation() { // Create a point using a helper function (lat/long) Location = CreatePoint(45.708457, -121.514432), Address = "Kaze Sushi, Hood River" }; context.Locations.Add(location); location = new GeoLocation() { Location = CreatePoint(45.722780, -120.209227), Address = "Arlington, OR" }; context.Locations.Add(location); context.SaveChanges(); } As promised, a DbGeography object has to be created with one of the static factory methods provided on the type as the Location.Longitude and Location.Latitude properties are read only. Here I'm using PointFromText() which uses a "Well Known Text" format to specify spatial data. In the first example I'm specifying to create a Point from a longitude and latitude value, using an SRID of 4326 (just like earlier in the SQL examples). You'll probably want to create a helper method to make the creation of Points easier to avoid that string format and instead just pass in a couple of double values. Here's my helper called CreatePoint that's used for all but the first point creation in the sample above:public static DbGeography CreatePoint(double latitude, double longitude) { var text = string.Format(CultureInfo.InvariantCulture.NumberFormat, "POINT({0} {1})", longitude, latitude); // 4326 is most common coordinate system used by GPS/Maps return DbGeography.PointFromText(text, 4326); } Using the helper the syntax becomes a bit cleaner, requiring only a latitude and longitude respectively. Note that my method intentionally swaps the parameters around because Latitude and Longitude is the common format I've seen with mapping libraries (especially Google Mapping/Geolocation APIs with their LatLng type). When the context is changed the data is written into the database using the SQL Geography type which looks the same as in the earlier SQL examples shown. Querying Once you have some location data in the database it's now super easy to query the data and find out the distance between locations. A common query is to ask for a number of locations that are near a fixed point - typically your current location and order it by distance. Using LINQ to Entities a query like this is easy to construct:[TestMethod] public void QueryLocationsTest() { var sourcePoint = CreatePoint(45.712113, -121.527200); var context = new GeoLocationContext(); // find any locations within 5 kilometers ordered by distance var matches = context.Locations .Where(loc => loc.Location.Distance(sourcePoint) < 5000) .OrderBy( loc=> loc.Location.Distance(sourcePoint) ) .Select( loc=> new { Address = loc.Address, Distance = loc.Location.Distance(sourcePoint) }); Assert.IsTrue(matches.Count() > 0); foreach (var location in matches) { Console.WriteLine("{0} ({1:n0} meters)", location.Address, location.Distance); } } This example produces: 301 15th Street, Hood River (0 meters)The Hatchery, Bingen (809 meters)Kaze Sushi, Hood River (1,074 meters)   The first point in the database is the same as my source point I'm comparing against so the distance is 0. The other two are within the 5 mile radius, while the Arlington location which is 65 miles or so out is not returned. The result is ordered by distance from closest to furthest away. In the code, I first create a source point that is the basis for comparison. The LINQ query then selects all locations that are within 5km of the source point using the Location.Distance() function, which takes a source point as a parameter. You can either use a pre-defined value as I'm doing here, or compare against another database DbGeography property (say when you have to points in the same database for things like routes). What's nice about this query syntax is that it's very clean and easy to read and understand. You can calculate the distance and also easily order by the distance to provide a result that shows locations from closest to furthest away which is a common scenario for any application that places a user in the context of several locations. It's now super easy to accomplish this. Meters vs. Miles As with the SQL Server functions, the Distance() method returns data in meters, so if you need to work with miles or feet you need to do some conversion. Here are a couple of helpers that might be useful (can be found in GeoUtils.cs of the sample project):/// <summary> /// Convert meters to miles /// </summary> /// <param name="meters"></param> /// <returns></returns> public static double MetersToMiles(double? meters) { if (meters == null) return 0F; return meters.Value * 0.000621371192; } /// <summary> /// Convert miles to meters /// </summary> /// <param name="miles"></param> /// <returns></returns> public static double MilesToMeters(double? miles) { if (miles == null) return 0; return miles.Value * 1609.344; } Using these two helpers you can query on miles like this:[TestMethod] public void QueryLocationsMilesTest() { var sourcePoint = CreatePoint(45.712113, -121.527200); var context = new GeoLocationContext(); // find any locations within 5 miles ordered by distance var fiveMiles = GeoUtils.MilesToMeters(5); var matches = context.Locations .Where(loc => loc.Location.Distance(sourcePoint) <= fiveMiles) .OrderBy(loc => loc.Location.Distance(sourcePoint)) .Select(loc => new { Address = loc.Address, Distance = loc.Location.Distance(sourcePoint) }); Assert.IsTrue(matches.Count() > 0); foreach (var location in matches) { Console.WriteLine("{0} ({1:n1} miles)", location.Address, GeoUtils.MetersToMiles(location.Distance)); } } which produces: 301 15th Street, Hood River (0.0 miles)The Hatchery, Bingen (0.5 miles)Kaze Sushi, Hood River (0.7 miles) Nice 'n simple. .NET 4.5 Only Note that DbGeography and DbGeometry are exclusive to Entity Framework 5.0 (not 4.4 which ships in the same NuGet package or installer) and requires .NET 4.5. That's because the new DbGeometry and DbGeography (and related) types are defined in the 4.5 version of System.Data.Entity which is a CLR assembly and is only updated by major versions of .NET. Why this decision was made to add these types to System.Data.Entity rather than to the frequently updated EntityFramework assembly that would have possibly made this work in .NET 4.0 is beyond me, especially given that there are no native .NET framework spatial types to begin with. I find it also odd that there is no native CLR spatial type. The DbGeography and DbGeometry types are specific to Entity Framework and live on those assemblies. They will also work for general purpose, non-database spatial data manipulation, but then you are forced into having a dependency on System.Data.Entity, which seems a bit silly. There's also a System.Spatial assembly that's apparently part of WCF Data Services which in turn don't work with Entity framework. Another example of multiple teams at Microsoft not communicating and implementing the same functionality (differently) in several different places. Perplexed as a I may be, for EF specific code the Entity framework specific types are easy to use and work well. Working with pre-.NET 4.5 Entity Framework and Spatial Data If you can't go to .NET 4.5 just yet you can also still use spatial features in Entity Framework, but it's a lot more work as you can't use the DbContext directly to manipulate the location data. You can still run raw SQL statements to write data into the database and retrieve results using the same TSQL syntax I showed earlier using Context.Database.ExecuteSqlCommand(). Here's code that you can use to add location data into the database:[TestMethod] public void RawSqlEfAddTest() { string sqlFormat = @"insert into GeoLocations( Location, Address) values ( geography::STGeomFromText('POINT({0} {1})', 4326),@p0 )"; var sql = string.Format(sqlFormat,-121.527200, 45.712113); Console.WriteLine(sql); var context = new GeoLocationContext(); Assert.IsTrue(context.Database.ExecuteSqlCommand(sql,"301 N. 15th Street") > 0); } Here I'm using the STGeomFromText() function to add the location data. Note that I'm using string.Format here, which usually would be a bad practice but is required here. I was unable to use ExecuteSqlCommand() and its named parameter syntax as the longitude and latitude parameters are embedded into a string. Rest assured it's required as the following does not work:string sqlFormat = @"insert into GeoLocations( Location, Address) values ( geography::STGeomFromText('POINT(@p0 @p1)', 4326),@p2 )";context.Database.ExecuteSqlCommand(sql, -121.527200, 45.712113, "301 N. 15th Street") Explicitly assigning the point value with string.format works however. There are a number of ways to query location data. You can't get the location data directly, but you can retrieve the point string (which can then be parsed to get Latitude and Longitude) and you can return calculated values like distance. Here's an example of how to retrieve some geo data into a resultset using EF's and SqlQuery method:[TestMethod] public void RawSqlEfQueryTest() { var sqlFormat = @" DECLARE @s geography SET @s = geography:: STGeomFromText('POINT({0} {1})' , 4326); SELECT Address, Location.ToString() as GeoString, @s.STDistance( Location) as Distance FROM GeoLocations ORDER BY Distance"; var sql = string.Format(sqlFormat, -121.527200, 45.712113); var context = new GeoLocationContext(); var locations = context.Database.SqlQuery<ResultData>(sql); Assert.IsTrue(locations.Count() > 0); foreach (var location in locations) { Console.WriteLine(location.Address + " " + location.GeoString + " " + location.Distance); } } public class ResultData { public string GeoString { get; set; } public double Distance { get; set; } public string Address { get; set; } } Hopefully you don't have to resort to this approach as it's fairly limited. Using the new DbGeography/DbGeometry types makes this sort of thing so much easier. When I had to use code like this before I typically ended up retrieving data pks only and then running another query with just the PKs to retrieve the actual underlying DbContext entities. This was very inefficient and tedious but it did work. Summary For the current project I'm working on we actually made the switch to .NET 4.5 purely for the spatial features in EF 5.0. This app heavily relies on spatial queries and it was worth taking a chance with pre-release code to get this ease of integration as opposed to manually falling back to stored procedures or raw SQL string queries to return spatial specific queries. Using native Entity Framework code makes life a lot easier than the alternatives. It might be a late addition to Entity Framework, but it sure makes location calculations and storage easy. Where do you want to go today? ;-) Resources Download Sample Project© Rick Strahl, West Wind Technologies, 2005-2012Posted in ADO.NET  Sql Server  .NET   Tweet !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() { var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true; po.src = 'https://apis.google.com/js/plusone.js'; var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s); })();

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  • Asp.Net (C#) MVC Routing - Trying avoid using the same controller in different places and think rout

    - by sheefy
    Hi Guys, I'm currently building a site which has a bunch of main categories and in each category you can perform a search. Basically, I want my addresses to work like this... When the website loads (as in when someone goes to www.mySite.com) it will redirect them to the default category. www.mySite.com/Category Then when you search within a category, the results would come up in a page like the following. www.mySite.com/Category/Search I want to put everything in one controller and have one main view for the Category and one for the Search, I would then render these based on which category is currently being viewed. Can this be done, maybe with routing? I don't want to have to create a different controller for each category as it's just duplicating a lot of the code. Thanks in advance for your help.

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  • What's going on with INETA and the Regional Speakers Bureau?

    - by Chris Williams
    For those of you that have been waiting patiently (and not so patiently) I'm happy to say that we're very near completion on some changes/enhancements/improvements that will allow us to finally go live with the INETA Regional Speakers Bureau. I know quite a few of you have already registered, which is great (though some of you may need to come back and update your info) and we've had a few folks submit requests, mostly in a test capacity, but soon we'll be up and live. Here's how it breaks down. Be sure to read this, because things have changed a bit from when we initially announced it. 1. The majority of our speaker/event funding is going into the Regional Speakers Bureau.  The National Bureau still exists, but it's a good bit smaller than it was before, and it's not an "every group" benefit anymore. We'll be using the National Bureau as more of a strategic task force, targeting high impact events and areas that need some community building love from INETA. These will be identified and handled on a case by case basis, and may include more than just user group events. 2. You're going to get more events per group, per year than you did before. Not only are we focusing more resources on this program, but we're also making a lot of efforts to use it more effectively. With the INETA Regional Speakers Bureau, you should be able to get 2-3 INETA speakers per year, on average. Not every geographical area will have exactly the same experience, but we're doing the best we can. 3. It's not a farm team program for the National Bureau. Unsurprisingly, I managed to offend a number of people when I previously made the comment that the Regional Speakers Bureau program was a farm team or stepping stone to the National Bureau. It was a poor choice of words.  Anyone can participate in the Regional Speakers Bureau, and I look forward to working with all of you. 4. There is assistance for your efforts. The exact final details are still being hammered out, but expect it to look something like this: (all distances listed are based on a round trip) Distances < 120 miles = $0 121 miles - 240 miles = $50 (effectively 1 to 2 hours, each way) 241 miles - 360 miles = $100 (effectively 2 to 3 hours, each way) 361 miles - 480 miles = $200 (effectively 3 to 4 hours, each way) For those of you who travel a lot, we're working on a solution to handle group visits when you're away from home. These will (for now) be handled on a case by case basis. 5. We're going to make it as easy as possible to work with the program. In order to do this, we need a few things from you. For speakers, that means your home address. It also means (maybe) filling out a simple 1 line expense report via the INETA website. For user groups, it means making sure your meeting address is up to date as well. 6. Distances will be automatically calculated from your home of record to the user group event and back. We realize that this is not a perfect solution to every instance, but we're not paying you to speak at an event, and you won't be taxed on this money. It's simply some assistance to make your community efforts easier. Our way of saying thanks for everything you do. 7. Sounds good so far, what's the catch? There's always a catch, right? In this case there are two of them: 1) At this time, Microsoft employees are welcome to use the website to line up speaking engagements with user groups, but are not eligible for financial assistance. 2) Anyone can register and use the website to line up speaking engagements with user groups, however you must receive and maintain a net score of 3+ positive ratings (we're implementing a thumbs up / thumbs down system) in order to receive financial assistance. These ratings are provided by the User Group leaders after the meeting has taken place. 8. Involvement by the User Group leaders is a key factor in the success of this program. Your job isn't done once you request a speaker. After you've had your meeting, it's critical that you go back to the website and take a very small survey. Doing this ensures that the speaker gets rated (and compensated if eligible) and also ensures that you can make another request, since you won't be able to make a new request if you have an old one outstanding. 9. What about Canada? We're definitely working on that. Unfortunately nothing new to report on that front, other than to say that we're trying. So... this is where things stand currently. We're working very quickly to get this in place and get speakers and groups together. If you have any questions, please leave a comment below and I'll answer them as quickly as possible. If I've forgotten anything, or if things change, I'll update it here. Thanks, Chris G. Williams INETA Board of Directors

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  • More Fun With Math

    - by PointsToShare
    More Fun with Math   The runaway student – three different ways of solving one problem Here is a problem I read in a Russian site: A student is running away. He is moving at 1 mph. Pursuing him are a lion, a tiger and his math teacher. The lion is 40 miles behind and moving at 6 mph. The tiger is 28 miles behind and moving at 4 mph. His math teacher is 30 miles behind and moving at 5 mph. Who will catch him first? Analysis Obviously we have a set of three problems. They are all basically the same, but the details are different. The problems are of the same class. Here is a little excursion into computer science. One of the things we strive to do is to create solutions for classes of problems rather than individual problems. In your daily routine, you call it re-usability. Not all classes of problems have such solutions. If a class has a general (re-usable) solution, it is called computable. Otherwise it is unsolvable. Within unsolvable classes, we may still solve individual (some but not all) problems, albeit with different approaches to each. Luckily the vast majority of our daily problems are computable, and the 3 problems of our runaway student belong to a computable class. So, let’s solve for the catch-up time by the math teacher, after all she is the most frightening. She might even make the poor runaway solve this very problem – perish the thought! Method 1 – numerical analysis. At 30 miles and 5 mph, it’ll take her 6 hours to come to where the student was to begin with. But by then the student has advanced by 6 miles. 6 miles require 6/5 hours, but by then the student advanced by another 6/5 of a mile as well. And so on and so forth. So what are we to do? One way is to write code and iterate it until we have solved it. But this is an infinite process so we’ll end up with an infinite loop. So what to do? We’ll use the principles of numerical analysis. Any calculator – your computer included – has a limited number of digits. A double floating point number is good for about 14 digits. Nothing can be computed at a greater accuracy than that. This means that we will not iterate ad infinidum, but rather to the point where 2 consecutive iterations yield the same result. When we do financial computations, we don’t even have to go that far. We stop at the 10th of a penny.  It behooves us here to stop at a 10th of a second (100 milliseconds) and this will how we will avoid an infinite loop. Interestingly this alludes to the Zeno paradoxes of motion – in particular “Achilles and the Tortoise”. Zeno says exactly the same. To catch the tortoise, Achilles must always first come to where the tortoise was, but the tortoise keeps moving – hence Achilles will never catch the tortoise and our math teacher (or lion, or tiger) will never catch the student, or the policeman the thief. Here is my resolution to the paradox. The distance and time in each step are smaller and smaller, so the student will be caught. The only thing that is infinite is the iterative solution. The race is a convergent geometric process so the steps are diminishing, but each step in the solution takes the same amount of effort and time so with an infinite number of steps, we’ll spend an eternity solving it.  This BTW is an original thought that I have never seen before. But I digress. Let’s simply write the code to solve the problem. To make sure that it runs everywhere, I’ll do it in JavaScript. function LongCatchUpTime(D, PV, FV) // D is Distance; PV is Pursuers Velocity; FV is Fugitive’ Velocity {     var t = 0;     var T = 0;     var d = parseFloat(D);     var pv = parseFloat (PV);     var fv = parseFloat (FV);     t = d / pv;     while (t > 0.000001) //a 10th of a second is 1/36,000 of an hour, I used 1/100,000     {         T = T + t;         d = t * fv;         t = d / pv;     }     return T;     } By and large, the higher the Pursuer’s velocity relative to the fugitive, the faster the calculation. Solving this with the 10th of a second limit yields: 7.499999232000001 Method 2 – Geometric Series. Each step in the iteration above is smaller than the next. As you saw, we stopped iterating when the last step was small enough, small enough not to really matter.  When we have a sequence of numbers in which the ratio of each number to its predecessor is fixed we call the sequence geometric. When we are looking at the sum of sequence, we call the sequence of sums series.  Now let’s look at our student and teacher. The teacher runs 5 times faster than the student, so with each iteration the distance between them shrinks to a fifth of what it was before. This is a fixed ratio so we deal with a geometric series.  We normally designate this ratio as q and when q is less than 1 (0 < q < 1) the sum of  + … +  is  – 1) / (q – 1). When q is less than 1, it is easier to use ) / (1 - q). Now, the steps are 6 hours then 6/5 hours then 6/5*5 and so on, so q = 1/5. And the whole series is multiplied by 6. Also because q is less than 1 , 1/  diminishes to 0. So the sum is just  / (1 - q). or 1/ (1 – 1/5) = 1 / (4/5) = 5/4. This times 6 yields 7.5 hours. We can now continue with some algebra and take it back to a simpler formula. This is arduous and I am not going to do it here. Instead let’s do some simpler algebra. Method 3 – Simple Algebra. If the time to capture the fugitive is T and the fugitive travels at 1 mph, then by the time the pursuer catches him he travelled additional T miles. Time is distance divided by speed, so…. (D + T)/V = T  thus D + T = VT  and D = VT – T = (V – 1)T  and T = D/(V – 1) This “strangely” coincides with the solution we just got from the geometric sequence. This is simpler ad faster. Here is the corresponding code. function ShortCatchUpTime(D, PV, FV) {     var d = parseFloat(D);     var pv = parseFloat (PV);     var fv = parseFloat (FV);     return d / (pv - fv); } The code above, for both the iterative solution and the algebraic solution are actually for a larger class of problems.  In our original problem the student’s velocity (speed) is 1 mph. In the code it may be anything as long as it is less than the pursuer’s velocity. As long as PV > FV, the pursuer will catch up. Here is the really general formula: T = D / (PV – FV) Finally, let’s run the program for each of the pursuers.  It could not be worse. I know he’d rather be eaten alive than suffering through yet another math lesson. See the code run? Select  “Catch Up Time” in www.mgsltns.com/games.htm The host is running on Unix, so the link is case sensitive. That’s All Folks

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  • Pass data from one form to another on a seperate page

    - by Micanio
    I am building a price/distance calculator with Google Maps API and am trying to pass the info from the calculator to a booking form on a separate page. My first form has 2 submit buttons - one to make the calculation, and one to submit the relevant data to the booking form. I'm stuck trying to make the 2nd button work. Once the API calculation has been made, I get 4 values - From, To, Cost, Distance. I am trying to pass the From, To and Cost values into my booking form by clicking the second button. But I can;t seem to get it to work. I've tried POST and GET but I think I may have been doing something wrong with both. Any help is appreciated. Code for API form: <script type="text/javascript" src="http://maps.google.com/maps?file=api&amp;v=2&amp;key=ABQIAAAAwCUxKrPl8_9WadET5dc4KxTqOwVK5HCwTKtW27PjzpqojXnJORQ2kUsdCksByD4hzcGXiOxvn6C4cw&sensor=true"></script> <script type="text/javascript"> var geocoder = null; var location1 = null; var location2 = null; var gDir = null; var directions = null; var total = 0; function roundNumber(num, dec) { var result = Math.floor(num*Math.pow(10 ,dec))/Math.pow(10,dec); return result; } function from(form) { address1=form.start.options[form.start.selectedIndex].value form.address1.value=address1 form.address1.focus() } function to(form) { address2=form.end.options[form.end.selectedIndex].value form.address2.value=address2 form.address2.focus() } function initialize() { var map = new GMap2(document.getElementById("map_canvas")); map.setCenter(new GLatLng(54.019066,-1.381531),9); map.setMapType(G_NORMAL_MAP); geocoder = new GClientGeocoder(); gDir = new GDirections(map); GEvent.addListener(gDir, "load", function() { var drivingDistanceMiles = gDir.getDistance().meters / 1609.344; var drivingDistanceKilometers = gDir.getDistance().meters / 1000; var miles = drivingDistanceMiles.toFixed(0); //var cost = (((miles - 1) * 1.9) + 3.6).toFixed(2); var meters = gDir.getDistance().meters.toFixed(1); if(miles < 70){ var cost = miles *1.75; } if(miles >70){ var cost = miles *1.2; } document.getElementById('from').innerHTML = '<strong>From: </strong>' + location1.address; document.getElementById('to').innerHTML = '<strong>To: </strong>' + location2.address; document.getElementById('cost').innerHTML = '<span class="fare"><strong>Estimated Taxi FARE:</strong>' + ' £' + cost.toFixed(2) + '</span>'; document.getElementById('miles').innerHTML = '<strong>Distance: </strong>' + miles + ' Miles'; }); } function showLocation() // start of possible values for address not recognized on google search // values for address1 { if (document.forms[0].address1.value == "heathrow" || document.forms[0].address1.value == "Heathrow" || document.forms[0].address1.value == "heathrow airport" || document.forms[0].address1.value == "Heathrow Airport" || document.forms[0].address1.value == "London Heathrow" || document.forms[0].address1.value =="london heathrow" ) { (document.forms[0].address1.value = "Heathrow Airport"); } if (document.forms[0].address2.value == "heathrow" || document.forms[0].address2.value == "Heathrow" || document.forms[0].address2.value == "heathrow airport" || document.forms[0].address2.value == "Heathrow Airport" || document.forms[0].address2.value == "London Heathrow" || document.forms[0].address2.value =="london heathrow" ) { (document.forms[0].address2.value = "Heathrow Airport"); } geocoder.getLocations(document.forms[0].address1.value + document.forms[0].uk.value || document.forms[0].start.value + document.forms[0].uk.value, function (response) { if (!response || response.Status.code != 200) { alert("Sorry, we were unable to find the first address"); } else { location1 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address}; geocoder.getLocations(document.forms[0].address2.value + document.forms[0].uk.value, function (response) { if (!response || response.Status.code != 200) { alert("Sorry, we were unable to find the second address"); } else { location2 = {lat: response.Placemark[0].Point.coordinates[1], lon: response.Placemark[0].Point.coordinates[0], address: response.Placemark[0].address}; gDir.load('from: ' + location1.address + ' to: ' + location2.address); } }); } }); } </script> <style> #quote { font-family: Georgia, "Times New Roman", Times, serif; } </style> </head> <body style="background-color: rgb(255, 255, 255);" onUnload="GUnload()" onLoad="initialize()"> <div id="sidebar"> <!--MAPS--> <div id="calc_top"></div> <div id="calc_body"> <div id="calc_inside"> <span style="font-size: 16px; font-weight: bold;">Get A Quote Now</span> <p class="disclaimer">Fares can be calculated using either Area, Exact Address or Postcode, when entering address please include both road name and area i.e. <em>Harrogate Road, Ripon</em>. You can also select a pickup point and destination from the dropdown boxes. </p> <form onSubmit="showLocation(); return false;" action="#" id="booking_form"> <p> <select onChange="from(this.form)" name="start"> <option selected="selected">Select a Pickup Point</option> <option value="Leeds Bradford Airport">Leeds Bradford Airport</option> <option value="Manchester Airport">Manchester Airport</option> <option value="Teesside International Airport">Teeside Airport</option> <option value="Liverpool John Lennon Airport">Liverpool Airport</option> <option value="East Midlands Airport">East Midlands Airport</option> <option value="Heathrow International Airport">Heathrow Airport</option> <option value="Gatwick Airport">Gatwick Airport</option> <option value="Stanstead Airport">Stanstead Airport</option> <option value="Luton International Airport">Luton Airport</option> </select> </p> <p> <input type="text" value="From" name="address1"><br> <p> <select onChange="to(this.form)" name="end"> <option selected="selected">Select a Destination</option> <option value="Leeds Bradford Airport">Leeds Bradford Airport</option> <option value="Manchester Airport">Manchester Airport</option> <option value="Teesside International Airport">Teeside Airport</option> <option value="Liverpool John Lennon Airport">Liverpool Airport</option> <option value="East Midlands Airport">East Midlands Airport</option> <option value="Heathrow International Airport">Heathrow Airport</option> <option value="Gatwick Airport">Gatwick Airport</option> <option value="Stanstead Airport">Stanstead Airport</option> <option value="Luton International Airport">Luton Airport</option> </select> </p> <input type="text" value="To" name="address2"><br> <input type="hidden" value=" uk" name="uk"> <br> <input type="submit" value="Get Quote"> <input type="button" value="Reset" onClick="resetpage()"><br /><br /> <input type="submit" id="CBSubmit" value="Confirm and Book" action=""/> </p> </form> <p id="from"><strong>From:</strong></p> <p id="to"><strong>To:</strong></p> <p id="miles"><strong>Distance: </strong></p> <p id="cost"><span class="fare"><strong>Estimated Taxi FARE:</strong></span></p> <p id="results"></p> <div class="style4" style="width: 500px; height: 500px; position: relative; background-color: rgb(229, 227, 223);" id="map_canvas"></div> </div> </div> Code for Booking Form: <form method="post" action="contactengine.php" id="contact_form"> <p> <label for="Name" id="Name">Name:</label> <input type="text" name="Name" /> <label for="Email" id="Email">Email:</label> <input type="text" name="Email" /> <label for="tel" id="tel">Tel No:</label> <input type="text" name="tel" /><br /><br /> <label for="from" id="from">Pickup Point:</label> <input type="text" name="from" value="" /><br /><br /> <label for="to" id="to">Destination:</label> <input type="text" name="to" value=""/><br /> <label for="passengers" id="passengers">No. of passengers</label> <input type="text" name="passengers" /><br /><br /> <label for="quote" id="quote">Price of journey:</label> <input type="text" name="quote" value="" /><br /><br /> <label for="Message" id="Message">Any other info:</label> <textarea name="Message" rows="20" cols="40"></textarea> <br /> Are you an account holder?<br /> <label for="account" id="yes" /> Yes:</label> <input type="radio" class="radio" value="yes" name="account"> <label for="account" id="yes" /> No:</label> <input type="radio" class="radio" value="no" name="account"> </p> <small>Non-account holders will have to pay a £5 booking fee when confirming thier booking</small> <input type="submit" name="submit" value="Submit" class="submit-button" /> </p> </form> Thanks in advance

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  • Telephone Number to Geolocation UK

    - by David Toy
    Is there a service that provides latitude and longitude for UK phone numbers? For example: Query: 0141 574 xxx, Returns: (55.8659829, -4.2602205) [Glasgow City Centre] Allow me to stress that I am not looking for a reverse-directory-enquires. I am more interested in 'local area' for things like weather by phone or "Where's my nearest Pizza Shop?" If this service doesn't exist your suggestions on how to implement it or where to get data from would also be incredibly useful. I am aware that Ofcom provides a list of area codes with a place name [1] suitable for geolocation, but I have my concerns about resolution. I see this as a particular problem in smaller towns and rural areas where an area code will cover a large geographical area. Second Example: Area Code: 01555, Ofcom: Lanark However: 01555 860xxx is Crossford (4 miles W of Lanark) 01555 77xxxx is Carluke (5 miles NW) 01555 89xxxx is Lesmahagow (5 miles SW) 01555 840xxx is Carnwath (7 miles NE) Therefore 01555 covers about ~80 sq miles. That's not particularly local. [1] Ofcom Area Code Tool: http://www.ofcom.org.uk/consumer/2009/09/telephone-area-codes-tool/

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  • Localization of Settings.bundle defaultvalues

    - by notnoop
    How can I have a localized default values in the Settings bundle? I encounter this problem for regionally sensitive defaults. Consider an option in the settings bundle to indicate whether to show distances in miles or kilometers. The default settings for en_US and en_GB is 'miles, and km for everywhere else. Does the SDK provide a settings for that? Or should I just add a third option: 'Infer metric system, miles, kms'

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  • Tomcat6 getting crashed at regular intervals installed in Ubuntu

    - by Milesh Rout
    I have installed Tomcat6 in Ubuntu OS and when I run my web application the server gets crashed at regular intervals. I have tried a lot but not getting the solution. I have increased the memory upto 2048mb but still getting such error. Following is the error I am getting. Any help would be really appreciated. org.apache.tomcat.util.http.Parameters processParametersINFO: Invalid chunk starting at byte [312] and ending at byte [312] with a value of [null] ignoredException in thread "Timer-1" Exception in thread "com.mchange.v2.async.ThreadPoolAsynchronousRunner$PoolThread-#0" Exception in thread "com.mchange.v2.async.ThreadPoolAsynchronousRunner$PoolThread-#2" Exception in thread "com.mchange.v2.async.ThreadPoolAsynchronousRunner$PoolThread-#1" Exception in thread "Timer-2" Exception in thread "http-8080-4" Exception in thread "http-8080-8" Exception in thread "http-8080-17" Exception in thread "org.hibernate.cache.StandardQueryCache.data" Exception in thread "org.hibernate.cache.UpdateTimestampsCache.data" Exception in thread "org.hibernate.cache.StandardQueryCache.data" Exception in thread "org.hibernate.cache.StandardQueryCache.data" Exception in thread "org.hibernate.cache.UpdateTimestampsCache.data" Exception in thread "org.hibernate.cache.StandardQueryCache.data" Exception in thread "org.hibernate.cache.StandardQueryCache.data" Exception in thread "org.hibernate.cache.UpdateTimestampsCache.data" Exception in thread "com.safenet.usermgmt.User.data" Exception in thread "http-8080-7" Exception in thread "http-8080-12" Exception in thread "http-8080-16" Exception in thread "http-8080-14" Exception in thread "http-8080-13" Exception in thread "http-8080-15" Exception in thread "http-8080-6" OpenJDK Client VM warning: Exception java.lang.OutOfMemoryError occurred dispatching signal SIGTERM to handler- the VM may need to be forcibly terminated

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  • What is the best database design and/or software to model a thesaurus?

    - by Miles O'Keefe
    I would like to design a web app that functions as a simple thesaurus : a long list of words with attributes, all of which are linked to each other. Wikipedia defines it as: In Information Science, Library Science, and Information Technology, specialized thesauri are designed for information retrieval. They are a type of controlled vocabulary, for indexing or tagging purposes. Such a thesaurus can be used as the basis of an index for online material. The Art and Architecture Thesaurus, for example, is used to index the Canadian Information retrieval thesauri are formally organized so that existing relationships between concepts are made explicit. What database software, design or model would best fit this? Are PHP and MySQL good technologies to handle it?

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  • Tracking multiple subdomains and domains going to the same site, separately in Google Analytics

    - by miles
    I have a new site that has multiple top-level domains and subdomains all going to it: www.domain.com, campaign.domain.com, chicago.domain.com, domain2.com - all go to the same site/site directory. Right now I have one Google Analytics account profile set up for it, but I want to be able to track the traffic that is hitting those different URLs separately. The domains are being routed on the server-side (not .htaccess). How can I do this in Google Analytics? Do I need to create filters? Or create different profiles for each domain?

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  • How can an SQL relational database be used to model a thesaurus? [closed]

    - by Miles O'Keefe
    I would like to design a web app that functions as a simple thesaurus: a long list of words with attributes, all of which are linked to each other. This thesaurus data model can be defined as: a controlled vocabulary arranged in a known order in which equivalence, hierarchical, and associative relationships among terms are clearly displayed and identified by standardized relationship indicators. My idea so far is to have one database in which every word is a table, and every table contains all words related to that word. e.g. Thesaurus(database) - happy(table) - excited(row)|cheerful(row)|lively(row) Is there are more efficient way to store words and their relationship to other words in a relational SQL database?

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  • How to Add Date Picker To VBA UserForm

    - by user1760110
    I am looking for a control to add to userForm to enable user to pick the date.I a good one at this address Formatting MM/DD/YYYY dates in textbox in VBA from Siddharth Rout which is perfect but it generate invisible sheets which is not nessaccary for my application I tried to stop creating sheets but i couldnt figure it out. Can you please let me know how I can properly modified the Siddharth Rout code or ponit me to another application like that? Thanks for you time

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  • Unable to debug an encodded javascript?

    - by miles away
    I’m having some problems debugging an encoded javacscript. This script I’m referring to given in this link over here. The encoding here is simple and it works by shifting the unicodes values to whatever Codekey was use during encoding. The code that does the decoding is given here in plain English below:- <script language="javascript"> function dF(s){ var s1=unescape(s.substr(0,s.length-1)); var t=''; for(i=0;i<s1.length;i++)t+=String.fromCharCode(s1.charCodeAt(i)-s.substr(s.length-1,1)); document.write(unescape(t)); } </script> I’m interested in knowing or understanding the values (e.g s1,t). Like for example when the value of i=0 what values would the following attributes / method would hold s1.charCodeAt(i) and s.substr(s.length-1,1) The reason I’m doing this is to understand as to how a CodeKey function really works. I don’t see anything in the code above which tells it to decode on the basis of codekey value. The only thing I can point in the encoding text is the last character which is set to 1 , 2 ,3 or 4 depending upon the codekey selected during encoding process. One can verify using the link I have given above. However, to debug, I’m using firebug addon with the script running as localhost on my wamp server. I’m able to put a breakpoint on the js using firebug but I’m unable to retrieve any of the user defined parameters or functions I mentioned above. I want to know under this context what would be best way to debug this encoded js.

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  • SEO For A Doman Name That Is A Dictionary Work Misspell [closed]

    - by Miles
    Possible Duplicate: How should I handle search engines auto-correcting the spelling of a site's name? My domain name is radiuus.com. Since the correct spelling of the word is with one u, when I search for "radiuus" on google it thinks I'm misspelling the word, kindly lets me know, and returns results for "radius". Example: https://www.google.com/search?q=radiuus&oq=radiuus&sugexp=chrome,mod=2&sourceid=chrome&ie=UTF-8 What can I do to prevent this? And taking this one step further: what can I do to get my site to show up when someone searches for "radius" spelled the correct way? Thanks!!

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  • paypal ipn case is not calling in paypal "pay now"

    - by Ipsita Rout
    paypal ipn case is not calling in paypal "pay now". In paypal button the following is set. return : "http://localhost/paypal.php?ch=return" cancel_return : "cancel_return" value="http://localhost/paypal.php?ch=cancel" notify_url : value="http://localhost/paypal.php?ch=ipn" paypal_form.php <form name="paypal" action="https://www.sandbox.paypal.com/cgi-bin/webscr" method="post"> <input type="hidden" name="cmd" value="_xclick"> <input type="hidden" name="rm" value="2"> <input type="hidden" name="no_notes" value="1"> <input type="hidden" name="custom" value="1"> <input type="hidden" name="business" value="[email protected]"> <input type="hidden" name="return" id="return" value="http://localhost/paypal.php?ch=return"> <input type="hidden" name="cancel_return" id="cancel_return" value="http://localhost/paypal.php?ch=cancel"> <input type="hidden" name="notify_url" id="notify_url" value="http://localhost/paypal.php?ch=ipn"> <input type="image" src="https://www.sandbox.paypal.com/WEBSCR-640-20110429-1/en_GB/i/btn/btn_paynow_SM.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online."> <img alt="" border="0" src="https://www.sandbox.paypal.com/WEBSCR-640-20110429-1/en_GB/i/scr/pixel.gif" width="1" height="1"> paypal.php <? include('db_connect.php'); $choice=isset($_GET['ch'])?$_GET['ch']:''; switch($choice){ case 'return': print "Thank You For Buying this product,Please Visit Again,If is there any complements Then suggest us.."; break; case 'ipn': $sql="INSERT INTO paypal(add_date) VALUES(now())"; mysql_query($sql); $x = fopen('test1.txt','w+'); $str2 = 'post data:dfydfhgfhjg'; foreach($_POST as $k=>$v){ $str2 .= $k.'--'.$v; } fwrite($x,$str2); fclose($x); break; case 'cancel': print "Thank You for visiting this site,Please inform your friend to buy products through paypal which is easy service... "; break; } ?>

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  • create menus in command line

    - by Miles Rout
    How can one create menus in the command line program? I've tried stuff like: cin input; switch (input) { case (1): // do stuff case (2): // ... } but then I've had the problem of sub-menus, and going back to the same menu, etc. The first program I wrote (apart from exercises) that tried to use the switch idea for the menus had goto statements because the alternative was heaps of (at the time) complicated loops.

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