Search Results

Search found 31657 results on 1267 pages for 'php d'.

Page 100/1267 | < Previous Page | 96 97 98 99 100 101 102 103 104 105 106 107  | Next Page >

  • showing error on uploading a big file using php

    - by user1489969
    I have created a php code to display the upload option to upload multiple files as below: <?php $f_id= $_GET["id"]; ?> <title>Upload File</title> <form enctype="multipart/form-data" method="post" action="upload_hal_mult.php?id=<?php echo $f_id;?>" > <input type="hidden" name="MAX_FILE_SIZE" value="10000000"> <input id="infile" type="file" name="infile[]" multiple="true" /> <input type="submit" value="upload" name="file_uploaded" / > <br> <br> </form> So this will call "upload_hal_mult.php" when "upload" button is clicked. And the code for that is as follows: <title>Upload Results</title> <?php define("MAX_SIZE",10000000); $f_id= $_GET["id"]; $dir_name="dir_hal_".$f_id; $u=0; if (!is_dir($dir_name)) mkdir($dir_name); $dir=$dir_name."/"; $file_realname = $_FILES['infile']['name']; for ($i = 0; $i < count($_FILES['infile']['name']); $i++) { $ext = substr(strrchr($_FILES['infile']['name'][$i], "."), 1); $fname = substr($_FILES['infile']['name'][$i],0,strpos($_FILES['infile']['name'][$i], ".")); $fPath = $fname."_(".substr(md5(rand() * time()),0,4).")".".$ext"; echo "files size=".$_FILES["infile"]["size"][$i]."\n"; if($_FILES["infile"]["size"][$i]>MAX_SIZE) echo('File uploaded exceeds maximum upload size.'); if(($_FILES['infile']['error'][i]==0) && move_uploaded_file($_FILES['infile']['tmp_name'][$i], $dir . $fPath)) { $u=$u+1; ?> <!--<script type="text/javascript">setTimeout("window.close();", 1300);</script>--> <?php echo "Upload is successful\n"; } else echo "if stmt failed so error \n"; } if($u!=count($_FILES['infile']['name'])) echo "Error"; else echo "count is correct"; ?> This upload works correctly for files of size<10MB. But for files of size10MB, it's not echoing 'File uploaded exceeds maximum upload size.' as expected. Its also not uploading the file of size10MB. But the $u gets incremented. But none of the statements like "Upload is successful" or "if stmt failed so error" are being echoed as well. However the statement "count is correct" is being displayed, and this shows the $u got incremented somehow even though the echo statements didnt work! Can someone please point out the error I am doing here? I thought its simply a matter of 'if/else' statements but it seems more than that to me. Please help me out if you have any clue. Thanks

    Read the article

  • Passing $_GET or $_POST data to PHP script that is run with wget

    - by Matt
    Hello, I have the following line of PHP code which works great: exec( 'wget http://www.mydomain.com/u1.php /dev/null &' ); u1.php acts to do various types of maintenance on my server and the above command makes it happen in the background. No problems there. But I need to pass variable data to u1.php before it's executed. I'd like to pass POST data preferably, but could accommodate GET or SESSION data if POST isn't an option. Basically the type of data being passed is user-specific and will vary depending on who is logged in to the site and triggering the above code. I've tried adding the GET data to the end of the URL and that didn't work. So how else might I be able to send the data to u1.php? POST data preferred, SESSION data would work as well (but I tried this and it didn't pick up the logged in user's session data). GET would be a last resort. Thanks!

    Read the article

  • Php + mysql transactions examples

    - by Donator
    I really haven't found normal example of php file where mysql transactions are being used. Can you show me simple example of that? And one more question. I've already created a lot of programming and didn't use transaction, maybe I can put any php function or smth to header.php that if one mysql_query fails, then others too? Thank you.

    Read the article

  • header problem in php refresh

    - by basma
    hello i have this code : <?php session_start(); echo "".$_SESSION['eventnum'].""; $urlRefresh = "testremot.php"; header("Refresh: 5; URL=\"" . $urlRefresh . "\""); ?> but the header doesnt work and this warning appear when i try to run this code : Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\remot\testremot.php:3) in C:\xampp\htdocs\remot\testremot.php on line 5 can you please help me ?

    Read the article

  • where is wrong in my php code ????

    - by user318068
    hi all, <td align="center" bgcolor="#FFFFFF"><?php echo '<label onclick="window.open('profilephp.php?member=$row['MemberID']','mywindow')">'.{$row['MemberName']}.'</label>';?><br /> <?php echo "<p align='center'><img width='100' height='100' src={$row['MemberImg']} alt='' /></p>";?></td></tr> Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in C:\xampp\htdocs\home - Copy\membercopy.php on line 141 I really don't know where it went wrong. Please help,

    Read the article

  • mysql php problem: no error message despite error_reporting(E_ALL) line

    - by herrturtur
    index.php <html> <head> <title>Josh's Online Playground</title> </head> <body> <form method="POST" action="action.php"> <table> <tr> <td>"data for stuff"</td> <td><input type="text" ?></td> </tr> <tr> <td><input type="submit"></td> </tr> </table> </form> </body> </html> action.php <?php error_reporting(E_ALL); ini_sit("display_errors", 1); $mysqli = new mysqli('localhost', 'root', 'password', 'website'); $result = $mysqli->query("insert into stuff (data) values (' .$_POST['data'] ."'); echo $mysqli->error(); if($result = $mysqli->query("select data from stuff")){ echo 'There are '.$result->num_rows.' results.'; } while ($row = $result->fetch_object()){ echo 'stuff' . $row->data; } ?> Despite the first two lines in action.php, I get no error or warning messages. Instead I get a blank page after clicking the submit button. Do I have to do something differently to insert data?

    Read the article

  • PHP Ajax not working

    - by Kostis
    I have 3 buttons on my page and depending on which one the user is clickingi want to run through ajax call a delete query in my database. When the user clicks on a button the javascript function seems to work but it doesn't run the query in php script. The html page: <?php session_start(); ?> <!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-7"> <script> function myFunction(name) { var r=confirm("Are you sure? This action cannot be undone!"); if (r==true) { alert(name); // check if is getting in if statement and confirm the parameter's value var xmlhttp; if (str.length==0) { document.getElementById("clearMessage").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("clearMessage").innerHTML= responseText; } } xmlhttp.open("GET","clearDatabase.php?q="+name,true); xmlhttp.send(); } else alert('pff'); } </script> </head> <body> <div id="wrapper"> <div id="header"></div> <div id="main"> <?php if (session_is_registered("username")){ ?> <!--<a href="#">???a????s? pa?a??? µ???µ?t??</a><br /> <a href="#">???a????s? pa?a??? s??ed????</a><br /> <a href="#">???a????s? push notifications</a><br />--> <input type="button" value="???a????s? pa?a??? µ???µ?t??" onclick="myFunction('messages')" /> <input type="button" value="???a????s? pa?a??? s??ed????" onclick="myFunction('conferences')" /> <input type="button" value="???a????s? push notifications" onclick="myFunction('notifications')" /> <div id="clearMessage"></div> <?php } else echo "Login first."; ?> </div> <div id="footer"></div> </div> </body> </html> and the php script: <?php if (isset($_GET["q"])) $q=$_GET["q"]; $host = "localhost"; $database = "dbname"; $user = "dbuser"; $pass = "dbpass"; $con = mysql_connect($host,$user,$pass) or die(mysql_error()); mysql_select_db($database,$con) or die(mysql_error()); if ($q=="messages") $query = "DELETE FROM push_message WHERE time_sent IS NOT NULL"; else if ($q=="conferences") $query = "DELETE FROM push_message WHERE time_sent IS NOT NULL"; else if ($q=="notifications") { $query = "DELETE FROM push_friend WHERE time_sent IS NOT NULL"; } $res = mysql_query($query,$con) or die(mysql_error()); if ($res) echo "success"; else echo "failed"; mysql_close($con); ?>

    Read the article

  • HttpWebRequest POST and retrieve data from php script after login

    - by KenaGT
    Hello guys i am newbie to this stuff so i'll try to explain my problem.I am building application that retrieve data after login to php script that looks like this: https://zamger.etf.unsa.ba/getrssid.php (see the page source for php scirpt definition) and definition(source) here: Korisnicko ime (UID): Šifra: After i login it shows me data that i must collect like this: RSSID: 1321B312 (this is only data that it shows and nothing else) I must do this with httpwebrequest but don't know how i tried to do it with POST(data) but it always give me the defnition of php script as response.But i need response to be like "RSSID: 1321B312" not as script definition mentioned above...please heeelp ASAP....

    Read the article

  • Absolute URL Path for PHP Website

    - by kakaajee
    Hi friends, I am working on a website in a CMS site. I have provided a link in my footer file e.g blogs.php. This page is at the root like "http://www.example.com/new_cms/blogs.php" When I moves to other files link like "http://www.example.com/new_cms/forums" the footer link is changed to "http://www.example.com/new_cms/forums/blogs.php" but the blogs.php page resides at path "http://www.example.com/new_cms/" . I tried different $_SERVER[] variables but got no luck to get the above path "http://www.example.com/new_cms/" means the server name with the directory where the project is currently running from. Any one have idea how to get it done will be a great help. Thanks

    Read the article

  • Creating a session user login php

    - by user2419393
    I'm stuck on how to create a session for a user who logs in. I got the part of checking to make sure the log in information corresponds with the database information, but is stuck on how to take the email address and store into a session. Here is my php code below. <?php include '../View/header.php'; session_start(); require('../model/database.php'); $email = $_POST['username']; $password = $_POST['password']; $sql = "SELECT emailAddress FROM customers WHERE emailAddress ='$email' AND password = '$password'"; $result = mysql_query($sql, $db); if (!$result) { echo "DB Error, could not query the database\n"; echo 'MySQL Error: ' . mysql_error(); exit; } while ($row = mysql_fetch_assoc($result)) { echo $row['emailAddress']; } mysql_free_result($result); ?>

    Read the article

  • How to transition from PHP to Python Django?

    - by ggfan
    Here's my background: Decent experience with PHP/MySql. Beginner's experience with OOP Why I want to learn Python Django? I gave in, based on many searches on SO and reading over some of the answers, Python is a great, clean, and structured language to learn. And with the framework Django, it's easier to write codes that are shorter than with PHP Questions Can i do everything in Django as in PHP? Is Django a "big" hit in web development as PHP? I know Python is a great general-purpose language but I'm focused on web development and would like to know how Django ranks in terms of web development.

    Read the article

  • Rails-like console for PHP?

    - by Chad Johnson
    Every so often, things work in my local PHP development environment, while in my test environment on my server, things do not. It's a nightmare to debug this. If I had a console like Rails provides, debugging would be much much simpler. Is there anything like the Rails console but for PHP? I should mention that I am using a home-brewn PHP application.

    Read the article

  • Possible to view PHP code of a website?

    - by Camran
    Is it possible to somehow view another websites php files/codes? Or to rephrase the question, Can my php codes be viewed by anybody except for those who have access to the file? If so, how cant I best prevent this? Thanks Ps: Server OS is Ubuntu 9.10 and PHP version is 5+ (Apache2)

    Read the article

  • Having trouble with php and ajax search function

    - by Andy
    I am still quite new to php/ajax/mysql. In anycase, I'm creating a search function which is returning properly the data I'm looking for. In brief, I have a mysql database set up. A php website that has a search function. I'm now trying to add a link to a mysql database search rather than just showing the results. In my search.php, the echo line is working fine but the $string .= is not returning anything. I'm just trying to get the same as the echo but with the link to the mysql php record. Am I missing something simple? //echo $query; $result = mysqli_query($link, $query); $string = ''; if($result) { if(mysqli_affected_rows($link)!=0) { while($row = mysqli_fetch_array($result,MYSQLI_ASSOC)) { echo '<p> <b>'.$row['title'].'</b> '.$row['post_ID'].'</p>'; $string .= "<p><a href='set-detail.php?recordID=".$row->post_ID."'>".$row->title."</a></p>"; } } else { echo 'No Results for :"'.$_GET['keyword'].'"'; }

    Read the article

  • how to return value through php function when called through the anchor tag in html

    - by sumit
    Look at my code below <a href="https://secure.gate2shop.com/ppp/purchase.do?merchant_id=234555454545433&merchant_site_id=54443¤cy=USD&total_amount=39.99&item_name_1=IncidentSupportTier1&item_amount_1=39.99&item_quantity_1=1&checksum=**call php function to get the checksum value**&time_stamp=2010-06-14.14:34:33&version=3.0.0" onmouseover="document.myform.sub_but.src='checkout02.jpg'" onmouseout="document.myform.sub_but.src='butup.gif'" onclick="return val_form_this_page()"> <img src="http://www.techvedic.com/gifs/checkout02.jpg" width="143" height="39" border="0" alt="Submit this form" name="sub_but" /> On button click the href link will open. But before opening the link I need to calculate the cheksum. I know how to calculate it in PHP script. But please tell me how can I call the PHP function which will return the checksum value. Don’t worry about the code in PHP script.

    Read the article

  • html embeded php code not executing when hosted on iis

    - by Jack
    <HTML> <HEAD> <META NAME="GENERATOR" Content="Microsoft Visual Studio .NET 7.1"> <TITLE></TITLE> </HEAD> <BODY> <?php echo '<p>Hello World</p>'; ?> </BODY> When I run the above code in browser, firefox render it like this Hello World '; ? I am doing my coding in Windows XP/IIS 5.1. I have PHP setup correctly because i have no problem running .php file. The problem seem to me that IIS can't render php code embedded inside html. Does anyone know how to fix this problem or should i switch to Apache?

    Read the article

  • Access PHP var from external javascript file

    - by FFish
    I can access a PHP var with Javascript like this: <?php $fruit = "apple"; $color = "red"; ?> <script type="text/javascript"> alert("fruit: " + "<?php echo $fruit; ?>"); // or shortcut "<?= $fruit ?>" </script> But what if I want to use an external JS file: <script type="text/javascript" src="externaljs.js"></script> externaljs.js: alert("color: " + "<?php echo $color; ?>");

    Read the article

  • html-embedded php code not executing when hosted on iis

    - by Jack
    <HTML> <HEAD> <META NAME="GENERATOR" Content="Microsoft Visual Studio .NET 7.1"> <TITLE></TITLE> </HEAD> <BODY> <?php echo '<p>Hello World</p>'; ?> </BODY> </HTML> When I run the above code in a browser, firefox renders it like this: Hello World '; ?> I am doing my coding in Windows XP/IIS 5.1. I have PHP set up correctly because I have no problem running .php files. The problem, it seems to me, is that IIS can't render php code embedded inside html. Does anyone know how to fix this problem or should i switch to Apache?

    Read the article

  • Disable globbing in PHP exec()

    - by wxs
    I have a PHP script which calls another script in order to add IP addresses to a whitelist. I sometimes want to whitelist all addresses, in which case I have it call exec("otherscript *.*.*.*", output, retval); This worked fine, adding the string "*.*.*.*" to the whitelist until I happened to have another file in the directory of the php script that matched that pattern ("foo.1.tar.gz"), at which point the wildcards were expanded, and I ended up with the filename in my whitelist. Is there some way to disable globbing in php's exec? It isn't mentioned in the PHP docs as far as I can tell.

    Read the article

  • php class crash course

    - by rabidmachine9
    Hello people, I'm sorry for this question but I'm getting crazy trying to write my first php clash, it is supposed to connect me to server and to a database but I'm always getting this error: Parse error: syntax error, unexpected ',', expecting T_PAAMAYIM_NEKUDOTAYIM in /Applications/XAMPP/xamppfiles/htdocs/classTest/test.php on line 9 thanks in advance, here is the code: <?php // include 'DBConnect.php'; class DBConnect { function connection($hostname = "localhost", $myname = "root", $pass = ''){ mysql_connect(&hostname, &myname, &pass) or die("Could not connect!"); //Connect to mysql } function choose($dbnam){ mysql_select_db(&dbnam) or die("Couldn't find database!"); //fnd specific db } } $a = new DBConnect(); $connect = $a->connection("localhost", "root"); $a->choose('mydb'); ?>

    Read the article

< Previous Page | 96 97 98 99 100 101 102 103 104 105 106 107  | Next Page >