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  • Remove parameter from link

    - by goordis
    I have many links with parameter number - value is numbers between 1-1000 http://mysite.com?one=2&two=4&number=2 http://mysite.com?one=2&two=4&four=4&number=124 http://mysite.com?one=2&three=4&number=9 http://mysite.com?two=4&number=242 http://mysite.com?one=2&two=4&number=52 How can i remove from this parameter and value with PHP? I would like receive: http://mysite.com?one=2&two=4 http://mysite.com?one=2&two=4&four=4 http://mysite.com?one=2&three=4 http://mysite.com?two=4 http://mysite.com?one=2&two=4

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  • In Vim, how to swap 2 non adjacent patterns?

    - by ThG
    I have lines of text, all with the same structure, and would like to make a permutation of 2 elements on all lines: 1257654 some text (which may be long) #Foo 1543098 some other text #Barbar 1238769 whatever #Baz 2456874 something else #Quux I want to obtain : #Foo some text (which may be long) 1257654 #Barbar some other text 1543098 #Baz whatever 1238769 #Quux something else 2456874 This is where I am stuck : :%s/\(\d\{7\}\)\(#.\{-}\)/\2\1/ Where did I go wrong ?

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  • What does this statement mean ? printf("[%.*s] ", (int) lengths[i],

    - by Vivek Goel
    I was reading this page http://dev.mysql.com/doc/refman/5.0/en/mysql-fetch-row.html there is one line printf("[%.*s] ", (int) lengths[i], row[i] ? row[i] : "NULL"); from code MYSQL_ROW row; unsigned int num_fields; unsigned int i; num_fields = mysql_num_fields(result); while ((row = mysql_fetch_row(result))) { unsigned long *lengths; lengths = mysql_fetch_lengths(result); for(i = 0; i < num_fields; i++) { printf("[%.*s] ", (int) lengths[i], row[i] ? row[i] : "NULL"); } printf("\n"); } what does [%.*s] mean in that code ?

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  • Split a string by comma, quote and full-stop.. with a few exceptions

    - by dunc
    I've got a lot of text, similar to the following paragraph, which I'd like to split into words without punctuation (', ", ,, ., newline etc).. with a few exceptions. Initially considered endemic to the Chalakudy River system in Kerala state, southern India, but now recognised to have a wider distribution in surrounding drainages including the Periyar, Manimala, and Pamba river though the Manimala data may be questionable given it seems to be the type locality of P. denisonii. In the Achankovil River basin it occurs sympatrically, and sometimes syntopically, with P. denisonii. Wild stocks may have dwindled by as much as 50% in the last 15 years or so with collection for the aquarium trade largely held responsible although habitats are also being degraded by pollution from agricultural and domestic sources, plus destructive fishing methods involving explosives or organic toxins. The text refers to P. denisonii which is a species of fish. It's an abbreviation of Genus species. I would like this reference to be one word. So, for instance, this is the kind of array I'd like to see: Array ( ... [44] given [45] it [46] seems [47] to [48] be [49] the [50] type [51] locality [52] of [53] P. denisonii [54] In [55] the ... ) The only things that distinguish these species references such as P. denisonii from a new sentence like end. New are: The P (for Puntius, as in the P. in the aforementioned example) is only ever one letter, always a capital the d (as in . denisonii) is always either a lower case letter or an apostrophe (') What regexp can I use with preg_split to give me such an array? I've tried a simple explode( " ", $array ) but it doesn't do the job at all. Thanks in advance,

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  • Using RE to retrive an ID

    - by chrissygormley
    Hello, I am trying to use RE to match a changing ID and extract it. I am having some bother getting it working. The String is: m = 'Some Text That exists version 1.0.41.476 Fri Jun 4 16:50:56 EDT 2010' The code I have tried so far is: r = re.compile(r'(s*\s*)(\S+)') m = m.match(r) Can anyone help extract this string. Thanks

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  • How do we match any single character including line feed in Perl regular expression?

    - by bobo
    I would like to use UltraEdit regular expression (perl) to replace the following text with some other text in a bunch of html files: <style type="text/css"> #some-id{} .some-class{} //many other css styles follow </style> I tried to use <style type="text/css">.*</style> but of course it wouldn't match anything because the dot matches any character except line feed. I would like to match line feed as well and the line feed maybe either \r\n or \n. How should the regular expression look like? Many thanks to you all.

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  • Find Javascript Code inside String

    - by Ph.E
    Greetings friends, I am developing a web application that will allow the customer to enter a personalized message, which will then be converted to HTML. Well, the problem is that I can not allow the insertion of Javascript code. So I need a method that filters the text, searching for and remove it. I think the regular expressions to solve my problem, but I'm having difficulty building. Some of his friends could help me, or has already developed something for this. Thank you.

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  • Regular Expression - Block Spam

    - by Immanuel
    Could someone lead me on finding a regular expression that blocks a comma separated list of Spam words I already have? The regular expression needs to match a string with the spam word list I already have. Not that it matters, but I am using PHP.

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  • (.*) instead of (.*?)

    - by EBAGHAKI
    Suppose we have this html content, and we are willing to get Content1, Content2,.. with regular expression. <li>Content1</li> <li>Content2</li> <li>Content3</li> <li>Content4</li> If I use the line below preg_match_all('/<li>(.*)<\/li>/', $text, $result); i will get an array with a single row containing: Content1</li> <li>Content2</li> <li>Content3</li> <li>Content4 And by using this code: preg_match_all('/<li>(.*?)<\/li>/', $text, $result); i will get an array with 4 row containing Content1, Content2, ... Why (.*) is not working since it means match any character zero or more times

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  • How to match parameter names in an expression?

    - by burak ozdogan
    Hi, I have a set of expressions representing some formula with some parameters inside. Like: [parameter1] * [parameter2] * [multiplier] And many others like this. I want to use a regular expression so that I can get a list of strings (List<string>) which will have the following inside: [paramter1] [paramter2] [multiplier] I am not using regular expressions so often; if you have already used something like this I would appreciate if you can share. Thanks!

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  • document.URL Matching in Javascript

    - by streetparade
    I have a url which looks like this https://test.high.com/people/11111111-name-firstname-_custa/deals/new Now i need to match document.URL if im on that Page if so i will alert a message. The important part is /deals/new How can i match that in Javascript?

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  • How to move many files in multiple different directories (on Linux)

    - by user1335982
    My problem is that I have too many files in single directory. I cannot "ls" the directory, cos is too large. I need to move all files in better directory structure. I'm using the last 3 digits from ID as folders in reverse way. For example ID 2018972 will gotta go in /2/7/9/img_2018972.jpg. I've created the directories, but now I need help with bash script. I know the IDs, there are in range 1,300,000 - 2,000,000. But I can't handle regular expressions. I wan't to move all files like this: /images/folder/img_2018972.jpg -> /images/2/7/9/img_2018972.jpg I will appreciate any help on this subject. Thanks!

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  • Problem with re.findall (duplicates)

    - by user559385
    Hello, I tried to fetch source of 4chan site, and get links to threads. I have problem with regexp (isn't working). Source: import urllib2, re req = urllib2.Request('http://boards.4chan.org/wg/') resp = urllib2.urlopen(req) html = resp.read() print re.findall("res/[0-9]+", html) #print re.findall("^res/[0-9]+$", html) The problem is that: print re.findall("res/[0-9]+", html) is giving duplicates. I can't use: print re.findall("^res/[0-9]+$", html) I have read python docs but they didn't help.

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  • mod_rewrite per-dir redirection returning a 400

    - by Eaterrust
    I moved my images directory to a different folder, and now I want to redirect all images requests from that folder to the new one. I do not have access to the main configuraion file, so I'm doing this in a .htaccess. I tried this, and it works:     RewriteCond %{REQUEST_URI} old_dir/.+.(jpg|png|gif)$     RewriteRule old_dir/(.+[^/]+..+)$ $1 [L,PT] But since they have permanently moved, I want to do a proper redirect, so I added the [R] flag, like this:      %{REQUEST_URI} old_dir/.+.(jpg|png|gif)$     RewriteRule old_dir/(.+[^/]+..+)$ $1 [L,PT,R] But the server gets confused, and returns a 400, so I looked at the log file, and this is what happens:     strip per-dir prefix: C:/wamp/www/natrazyle/old_dir/images/banner.jpg - old_dir/images/banner.jpg     applying pattern 'old_dir/(.+[^/]+..+)$' to uri 'old_dir/images/banner.jpg'     rewrite 'old_dir/images/banner.jpg' - 'images/banner.jpg'     add per-dir prefix: images/banner.jpg - C:/wamp/www/natrazyle/images/banner.jpg     explicitly forcing redirect with http://localhost/C:/wamp/www/natrazyle/images/banner.jpg As you can see, the full local path gets added after localhost I know I'm doing something wrong, I just can't figure it out myself. Any help would be greatly appreciated...

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  • Match Phrases (in array) in text string

    - by Tim Hanssen
    I'm using the Twitter API streaming to collect thousand of tweets every minute. They need to be matched to a list of keywords (can contain spaces). This is my current method: $text = preg_replace( '/[^a-z0-9]+/i', ' ', strtolower( $data['text'] ) ); $breakout = explode( " ", $text ); $result = array_intersect( $this->_currentTracks, $breakout ); I chop the tweet into words, and the matches them against my current keywords. This works well for all the keywords without a space ofc. If I wanted to find for example "Den Haag", It won't show up, because the string is exploded into words (based on the spaces). Any ideas about how I can do this in a quick way? Kind regards, Tim

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  • Validate a string

    - by Activist
    I'm not that good with regular expressions... I need a JavaScript regular expression that will do the following: The string can contain letters (upper and lower case), but not punctuations such as éàïç... The string can contain numbers (0..9) anywhere in the string, except on the first position. The string can contain underscores (_). Valid strings: foo foo1 foo_bar fooBar Invalid strings: 1foo -- number as first character foo bar -- space föo -- punctuation ö Many thanks!

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