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  • Server-side validation in ASP.NET 2.0

    - by Zerotoinfinite
    Hi All, My application is in ASP.NET 2.0 with C#. I have a regular expression validator with the regular expression ^[0-9]*(\\,)?[0-9]?[0-9]?$, now my client don't want this validation at client side but on button click i.e. Server Side. EX: I have to check the value of txtPrice textbox Please let me know how can I put this regular expression validation on server side. Thanks in advance.

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  • Remove parameter from link

    - by goordis
    I have many links with parameter number - value is numbers between 1-1000 http://mysite.com?one=2&two=4&number=2 http://mysite.com?one=2&two=4&four=4&number=124 http://mysite.com?one=2&three=4&number=9 http://mysite.com?two=4&number=242 http://mysite.com?one=2&two=4&number=52 How can i remove from this parameter and value with PHP? I would like receive: http://mysite.com?one=2&two=4 http://mysite.com?one=2&two=4&four=4 http://mysite.com?one=2&three=4 http://mysite.com?two=4 http://mysite.com?one=2&two=4

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  • Split string on first two colons

    - by Mark Miller
    I would like to split a column of strings on the first two colons, but not on any subsequent colons: my.data <- read.table(text=' my.string some.data 12:34:56:78 -100 87:65:43:21 -200 a4:b6:c8888 -300 11:bb:ccccc -400 uu:vv:ww:xx -500', header = TRUE) desired.result <- read.table(text=' my.string1 my.string2 my.string3 some.data 12 34 56:78 -100 87 65 43:21 -200 a4 b6 c8888 -300 11 bb ccccc -400 uu vv ww:xx -500', header = TRUE) I have searched extensively and the following question is the closest to my current dilemma: Split on first comma in string Thank you for any suggestions. I prefer to use base R.

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  • Regular Expression to extract HREFS

    - by James Jeffery
    I'm looking for a regular expression that can extract the href from this: <a href="/tr/blog.php?post=3593&user=930"> There are hundreds of links on the page so I need to extract only those that contain /tr/blog.php So in the end I should be left with a list of links that start in /tr/blog Thanks for any help. It's really puzzling me.

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  • capture text, including tags from string, and then reorder tags with text

    - by Brian
    I have the following text: abcdef<CONVERSION>abcabcabcabc<2007-01-12><name1><2007-01-12>abcabcabcabc<name2><2007-01-11>abcabcabcabc<name3><2007-02-12>abcabcabcabc<name4>abcabcabcabc<2007-03-12><name5><date>abcabcabcabc<name6> I need to use regular expressions in order to clean the above text: The basic extraction rule is: <2007-01-12>abcabcabcabc<name2> I have no problem extracting this pattern. My issue is that within th text I have malformed sequences: If the text doesn't start with a date, and end with a name my extraction fails. For example, the text above may have several mal formed sequences, such as: abcabcabcabc<2007-01-12><name1> Should be: <2007-01-12>abcabcabcabc<name1> Is it possible to have a regular expression that would clean the above, prior to extracting my consistent pattern. In short, i need to find all mal formed patterns, and then take the date tag and put it in front of it, as provided in the example above. Thanks.

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  • Regular Expression to Match Specific "Values" in Isolated Group

    - by Gandarez
    If have this regular expression to test (\&TRUNC)[\(]{1,}(.+)[\)]{1,} And I have this "tester" ((((&TRUNC((1800,000 / 510)) * 510) * 920) + (2 * (510 * 700)) + ((&TRUNC((1800,000 / 510)) - 1) * 2 * 510 * 80)) / 1000000) * 85,715 My expected value is (inside the personal command "&TRUNC(command)") (1800,000 / 510) I got this value 1800,000 / 510)) * 510) * 920) + (2 * (510 * 700)) + ((&TRUNC((1800,000 / 510)) - 1) * 2 * 510 * 80)) / 1000000 How can I get only expected value in a separated group? PS:. The expressions inside the command called for me as "&TRUNC(command)" is variable.

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  • Regular expressions in java

    - by rookie
    String s= "(See <a href=\"/wiki/Grass_fed_beef\" title=\"Grass fed beef\" " + "class=\"mw-redirect\">grass fed beef.) They have been used for " + "<a href=\"/wiki/Paper\" title=\"Paper\">paper-making since " + "2400 BC or before."; In the string above I have inter-mixed html with text. Well the requirement is that the output looks like:- They have been used for paper-making since 2400 BC or before. Could some one help me with a generic regular expression that would produce the desired output from the given input? Thanks in advance!

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  • Regular Expression for exclude something that has specific word inside bracked (MySQL)

    - by bn
    This Regular expression if for MySQL query: I want to exclude this row because it has 'something' in side the bracket "bla bla bla bla bla bla (bla bla bla something)" However I want to include this row, because it does not have 'something' inside the bracket "bla bla bla (bla bla bla)" I tried this query but it didnt work. SELECT * FROM table WHERE field NOT REGEXP '((%something%))'; I think this is wrong, I just did trial and error, I like to use regular expression, but never understand it completely. is there any good tutorial/books/links for learning the detail of regular expression? Thank You

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  • What does this statement mean ? printf("[%.*s] ", (int) lengths[i],

    - by Vivek Goel
    I was reading this page http://dev.mysql.com/doc/refman/5.0/en/mysql-fetch-row.html there is one line printf("[%.*s] ", (int) lengths[i], row[i] ? row[i] : "NULL"); from code MYSQL_ROW row; unsigned int num_fields; unsigned int i; num_fields = mysql_num_fields(result); while ((row = mysql_fetch_row(result))) { unsigned long *lengths; lengths = mysql_fetch_lengths(result); for(i = 0; i < num_fields; i++) { printf("[%.*s] ", (int) lengths[i], row[i] ? row[i] : "NULL"); } printf("\n"); } what does [%.*s] mean in that code ?

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  • How to strip everything between a key phrase and an ending tag?

    - by user3620142
    I am trying to strip everything between a key phrase and ending tag but for some reason it is not working. I always get blank data. I've tried many different ways but no luck. Basically I have a script that connect to IMAP and store emails into MySQL as service tickets. It works great but I am trying to strip off everything except for user reply because currently if a user reply to an email it re-inserts the entire email into MySQL. I added a key phrase at the top of all outgoing emails . Structure is as below: --Reply below this line to respond-- ------------------------------------------------------------------------------------ Email body message... When replying to the message, it becomes: New Message reply...... --Reply below this line to respond-- old message body. I would only like to insert the new reply message only. This is what I've got so far: $message = strip_tags($message, "<br><div><p><u><hr></section>"); $message=preg_replace("</p>", "br /", $message); $message=preg_replace('#--REPLY above this line to respond--(.*?)</section>)#s', ' ', $message); $message=clean("<br/><hr><u>Received On $rep_date / $from_email</u><br><br/>$message"); It inserts the Received On date and From but $message is blank. If I remove $message=preg_replace('#--REPLY above this line to respond--(.*?)</section>)#s', ' ', $message); it inserts the entire email. Any suggestion on what i am doing wrong?

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  • How to use Regular Expression to extract information from a HTML webpage?

    - by user569248
    How to use Regular Expression to extract the answer "Here is the answer" from a HTML webpage like this? <b>Last Question:</b> <b>Here is the answer</b> ..:: Update ::.. Thanks everybody! Here is my solution by using BeautifulSoup since I'm using Python framework: response = opener.open(url) the_page = response.read() soup = BeautifulSoup(''.join(the_page)) paraText1 = soup.body.find('div', 'div_id', text = u'Last Question:') if paraText1: answer = paraText1.next

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  • How to write a regular expression for "everything between X and Y" for use with preg_replace

    - by pg
    I want to take a variable called $encoded_str and and remove cd1, CD1 and anything between the first 'l' and the last blank space. So for example "lp6 id4 STRINGcd1" would return "STRING". I'm using PHP 4 for now so I can't use str_ireplace, I have this: $encoded_str=str_replace('CD1','',$encoded_str); $encoded_str=str_replace('cd1','',$encoded_str); $encoded_str=preg_replace('X','',$encoded_str); I've RTFM for preg_replace but am a bit confused. What should I replace the X with and can you suggest a decent introductory primer for writing regular expressions?

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  • How to match parameter names in an expression?

    - by burak ozdogan
    Hi, I have a set of expressions representing some formula with some parameters inside. Like: [parameter1] * [parameter2] * [multiplier] And many others like this. I want to use a regular expression so that I can get a list of strings (List<string>) which will have the following inside: [paramter1] [paramter2] [multiplier] I am not using regular expressions so often; if you have already used something like this I would appreciate if you can share. Thanks!

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  • Url for SEO Link

    - by k0ni
    Hi, i need a function (c#) or regular expression that makes me a nice URL out of a string. (and replaces invalid characters) Something like here on stackoverflow.. example: Short URL or long URL for SEO - short-url-or-long-url-for-seo Thanks

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  • Can you help with regular expressions in Java?

    - by Matt
    I have a bunch of strings which may of may not have random symbols and numbers in them. Some examples are: contains(reserved[j])){ close(); i++){ letters[20]=word I want to find any character that is NOT a letter, and replace it with a white space, so the above examples look like: contains reserved j close i letters word What is the best way to do this?

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  • ruby enclose selected whole words in brackets

    - by astropanic
    @string = "Sometimes some stupid people say some stupid words" @string.enclose_in_brackets("some") # => "Sometimes {some} stupid people say {some} stupid words" How should the method enclose_in_brackets look ? Please keep in mind, I want only enclose whole words, (I don't want "{Some}times {some} stupid....", the "sometimes" word should be left unchanged

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  • Apply a class to a <h1> based on the site url

    - by user1870639
    I'm new to PHP and want to apply a specific class to the title of my page depending on what part of the site the viewer is browsing. For instance, I want to apply the class "blog" to the if the viewer is at domain.com/blog OR domain.com/blog/post-1 so on and so forth BUT apply the class "pics" if they're viewing domain.com/pics or domain.com/pics/gallery-1 etc etc. I found something that could be modified to serve my needs using javascript here but I figured seeing as I'm using PHP already, it'd make more sense to keep this sort of thing server side. As I say, I'm new to PHP. I've experimented with some regular expressions, but to no avail.

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  • How to using String.split in this case?

    - by hoang nguyen
    I want to write a fuction like that: - Input: "1" -> return : "1" - Input: "12" -> return : ["1","2"] If I use the function split(): String.valueOf("12").split("") -> ["","1","2"] But, I only want to get the result: ["1","2"]. What the best way to do this? Infact, I can do that: private List<String> decomposeQuantity(final int quantity) { LinkedList<String> list = new LinkedList<String>(); int parsedQuantity = quantity; while (parsedQuantity > 0) { list.push(String.valueOf(parsedQuantity % 10)); parsedQuantity = parsedQuantity / 10; } return list; } But, I want to use split() for having an affective code

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  • Trying to match what is before /../ but after / with regular expressions

    - by tim
    I am trying to match what is before /../ but after / with regular expressions, but i want it to look back and stop at the first / I feel like I am close but it just looks at the first slash and then takes everything after it like... input is this: this/is/a/./path/that/../includes/face/./stuff/../hat and my regular expression is #\/(.*)\.\.\/# matching /is/a/./path/that/../includes/face/./stuff/../ instead of just that/../ and stuff/../ how can i adapt what i'm doing to work?

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  • Erroneous Matches with Regular Expression

    - by Ballsacian1
    $regexp = '/(?:<input\stype="hidden"\sname="){1}([a-zA-Z0-9]*)(?:"\svalue="1"\s\/>)/'; $response = '<input type="hidden" name="7d37dddd0eb2c85b8d394ef36b35f54f" value="1" />'; preg_match($regexp, $response, $matches); echo $matches[1]; // Outputs: 7d37dddd0eb2c85b8d394ef36b35f54f So I'm using this regular expression to search for an authentication token on a webpage implementing Joomla in order to preform a scripted login. I've got all this working but am wondering what is wrong with my regular expression as it always returns 2 items. Array ( [0] => [1] => 7d37dddd0eb2c85b8d394ef36b35f54f) Also the name of the input I'm checking for changes every page load both in length and name.

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