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  • Error: "Cannot simultaneously fetch multiple bags" when calling Configuration.BuildSessionFactory();

    - by Nick Meldrum
    We are getting this error after upgrading to NHibernate 2.1. [QueryException: Cannot simultaneously fetch multiple bags.] NHibernate.Loader.BasicLoader.PostInstantiate() +418 NHibernate.Loader.Entity.EntityLoader..ctor(IOuterJoinLoadable persister, String[] uniqueKey, IType uniqueKeyType, Int32 batchSize, LockMode lockMode, ISessionFactoryImplementor factory, IDictionary`2 enabledFilters) +123 NHibernate.Loader.Entity.BatchingEntityLoader.CreateBatchingEntityLoader(IOuterJoinLoadable persister, Int32 maxBatchSize, LockMode lockMode, ISessionFactoryImplementor factory, IDictionary`2 enabledFilters) +263 NHibernate.Persister.Entity.AbstractEntityPersister.CreateEntityLoader(LockMode lockMode, IDictionary`2 enabledFilters) +26 NHibernate.Persister.Entity.AbstractEntityPersister.CreateLoaders() +57 NHibernate.Persister.Entity.AbstractEntityPersister.PostInstantiate() +1244 NHibernate.Persister.Entity.SingleTableEntityPersister.PostInstantiate() +18 NHibernate.Impl.SessionFactoryImpl..ctor(Configuration cfg, IMapping mapping, Settings settings, EventListeners listeners) +3261 NHibernate.Cfg.Configuration.BuildSessionFactory() +87 Without stepping into the NHibernate source, it doesn't look like I can see which mapping is creating the issue. It's a very old application with a load of mappings files, lots of mappings have one-to-many bags in them, all lazy instantiated. For example: <bag name="Ownership" lazy="true" cascade="all" inverse="true" outer-join="auto" where="fkOwnershipStatusID!=6"> <key column="fkStakeHolderID"/> <one-to-many class="StakeholderLib.Ownership,StakeholderLib" /> </bag> maps to: public virtual IList Ownership { get { if (ownership == null) ownership = new ArrayList(); return ownership; } set { ownership = value; } } Has anyone seen this error before when upgrading to NHibernate 2.1?

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  • WPF-Can a XAML object be a source as well as a target for bindings?

    - by iambic77
    I was wondering if it's possible to have a TextBlock as a target and a source? Basically I have a bunch of entities which have simple relationships to other entities (like Entity1 Knows Entity3, Entity3 WorksAt Entity2 etc.) I have a Link class that stores SourceEntity, Relationship and TargetEntity details. What I want to be able to do is to select an entity then display the relationships related to that entity, with the target entities of each relationship listed underneath the relationship names. When an entity is selected, an ObservableCollection is populated with the Links for that particular entity (SelectedEntityLinks<Link>). Because each entity could have the same relationship to more than one target entity (Entity1 could know both Entity3 and Entity4 for eg.), I've created a method GetThisRelationshipEntities() that takes a relationship name as a parameter, looks through SelectedEntityLinks for relationship names that match the parameter, and returns an ObservableCollection with the target entities of that relationship. Hope I'm making this clear. In my xaml I have a WrapPanel to display each relationship name in a TextBlock: <TextBlock x:Name="relationship" Text="{Binding Path=Relationship.Name}" /> Then underneath that another Textblock which should display the results of GetThisRelationshipEntities(String relationshipName). So I want the "relationship" TextBlock to both get its Text from the binding I've shown above, but also to provide its Text as a parameter to the GetThisRelationshipEntities() method which I've added to <UserControl.Resources> as an ObjectDataProvider. Sorry if this is a bit wordy but I hope it's clear. Any pointers/advice would be great. Many thanks.

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  • Why is Core Data not persisting these changes to disk?

    - by scott
    I added a new entity to my model and it loads fine but no changes made in memory get persisted to disk. My values set on the car object work fine in memory but aren't getting persisted to disk on hitting the home button (in simulator). I am using almost exactly the same code on another entity in my application and its values persist to disk fine (core data - sqlite3); Does anyone have a clue what I'm overlooking here? Car is the managed object, cars in an NSMutableArray of car objects and Car is the entity and Visible is the attribute on the entity which I am trying to set. Thanks for you assistance. Scott - (void)viewDidLoad { myAppDelegate* appDelegate = (myAppDelegate*)[[UIApplication sharedApplication] delegate]; NSManagedObjectContext* managedObjectContex = appDelegate.managedObjectContext; NSFetchRequest* request = [[NSFetchRequest alloc] init]; NSEntityDescription* entity = [NSEntityDescription entityForName:@"Car" inManagedObjectContext:managedObjectContex]; [request setEntity:entity]; NSSortDescriptor* sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"Name" ascending:YES]; NSArray* sortDescriptors = [[NSArray alloc] initWithObjects:sortDescriptor, nil]; [request setSortDescriptors:sortDescriptors]; [sortDescriptors release]; [sortDescriptor release]; NSError* error = nil; cars = [[managedObjectContex executeFetchRequest:request error:&error] mutableCopy]; if (cars == nil) { NSLog(@"Can't load the Cars data! Error: %@, %@", error, [error userInfo]); } [request release]; } - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath*)indexPath { Car* car = [cars objectAtIndex:indexPath.row]; if (car.Visible == [NSNumber numberWithBool:YES]) { car.Visible = [NSNumber numberWithBool:NO]; [tableView cellForRowAtIndexPath:indexPath].accessoryType = UITableViewCellAccessoryNone; } else { car.Visible = [NSNumber numberWithBool:YES]; [tableView cellForRowAtIndexPath:indexPath].accessoryType = UITableViewCellAccessoryCheckmark; } }

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  • how to ignore ivy revision number?

    - by user315228
    Guys, I have certain jar files without revision number. But as rev is mandatory attribute for ivy dependency, i am providing the revision attribute. But i have something like (-[revision]) in url resolver. but its taking the module number instead of ignoring the revision attribute. I know it wont ignore the revision attribute as its not null. Following is the output that i get default-cache: no cached resolved revision for perltools#perltools;latest.integration [ivy:retrieve] tried [ivy:retrieve] listing all in [ivy:retrieve] using privateRepo to list all in [ivy:retrieve] ApacheURLLister found URL=[httP://myrepo/ivyRepository/perltools/jars/perltools.jar]. [ivy:retrieve] found 1 resources [ivy:retrieve] found revs: [perltools.jar] [ivy:retrieve] HTTP response status: 404 url=httP://myrepo/ivyRepository/perltools/jars/perltools.jar/perltools-perltools.jar.jar [ivy:retrieve] CLIENT ERROR: Not Found url=httP://myrepo/ivyRepository/perltools/jars/perltools.jar/perltools-perltools.jar.jar Can somebody please explain why its taking module.ext as revision where revision i specified is latest.integration and in myrepo, i dont have revision attribute. its just has [http://myrepo/ivyRepository/perltools/jars//perltools.jar] Can somebody please help me so that i can avoid revision attribute?

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  • Apache HttpClient 4.0. Weird behavior.

    - by Mikhail T
    Hello. I'm using Apache HttpClient 4.0 for my web crawler. The behavior i found strange is: i'm trying to get page via HTTP GET method and getting response about 404 HTTP error. But if i try to get that page using browser it's done successfully. Details: 1. I upload multipart form to server this way: HttpPost httpPost = new HttpPost("http://[host here]/in.php"); MultipartEntity entity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE); entity.addPart("method", new StringBody("post")); entity.addPart("key", new StringBody("223fwe0923fjf23")); FileBody fileBody = new FileBody(new File("photo.jpg"), "image/jpeg"); entity.addPart("file", fileBody); httpPost.setEntity(entity); HttpResponse response = httpClient.execute(httpPost); HttpEntity result = response.getEntity(); String responseString = ""; if (result != null) { InputStream inputStream = result.getContent(); byte[] buffer = new byte[1024]; while(inputStream.read(buffer) > 0) responseString += new String(buffer); result.consumeContent(); } Uppload succefully ends. I'm getting some results from web server: HttpGet httpGet = new HttpGet("http://[host here]/res.php?key="+myKey+"&action=get&id="+id); HttpResponse response = httpClient.execute(httpGet); HttpEntity entity = response.getEntity(); I'm getting ClientProtocolException while execute method run. I was debugging this situation with log4j. Server answers "404 Not Found". But my browser loads me that page with no problem. Can anybody help me? Thank you.

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  • How do I construct a more complex single LINQ to XML query?

    - by Cyberherbalist
    I'm a LINQ newbie, so the following might turn out to be very simple and obvious once it's answered, but I have to admit that the question is kicking my arse. Given this XML: <measuresystems> <measuresystem name="SI" attitude="proud"> <dimension name="mass" dim="M" degree="1"> <unit name="kilogram" symbol="kg"> <factor name="hundredweight" foreignsystem="US" value="45.359237" /> <factor name="hundredweight" foreignsystem="Imperial" value="50.80234544" /> </unit> </dimension> </measuresystem> </measuresystems> I can query for the value of the conversion factor between kilogram and US hundredweight using the following LINQ to XML, but surely there is a way to condense the four successive queries into a single complex query? XElement mss = XElement.Load(fileName); IEnumerable<XElement> ms = from el in mss.Elements("measuresystem") where (string)el.Attribute("name") == "SI" select el; IEnumerable<XElement> dim = from e2 in ms.Elements("dimension") where (string)e2.Attribute("name") == "mass" select e2; IEnumerable<XElement> unit = from e3 in dim.Elements("unit") where (string)e3.Attribute("name") == "kilogram" select e3; IEnumerable<XElement> factor = from e4 in unit.Elements("factor") where (string)e4.Attribute("name") == "pound" && (string)e4.Attribute("foreignsystem") == "US" select e4; foreach (XElement ex in factor) { Console.WriteLine ((string)ex.Attribute("value")); }

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  • WCF REST adding data using POST or PUT 400 Bad Request

    - by user55474
    HI How do i add data using wcf rest architecture. I dont want to use the channelfactory to call my method. Something similar to the webrequest and webresponse used for GET. Something similar to the ajax WebServiceProxy restInvoke Or do i always have to use the Webchannelfactory implementation I am getting a 400 BAD request by using the following Dim url As String = "http://localhost:4475/Service.svc/Entity/Add" Dim req As WebRequest = WebRequest.Create(url) req.Method = "POST" req.ContentType = "application/xml; charset=utf-8" req.Timeout = 30000 req.Headers.Add("SOAPAction", url) Dim xEle As XElement xEle = <Entity xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <Name>Entity1</Name> </Entity> Dim sXML As String = xEle .Value req.ContentLength = sXML.Length Dim sw As New System.IO.StreamWriter(req.GetRequestStream()) sw.Write(sXML) sw.Close() Dim res as HttpWebResponse = req.GetResponse() Sercice Contract is as follows <OperationContract()> _ <WebInvoke(Method:="PUT", UriTemplate:="Entity/Add")> _ Function AddEntity(ByVal e1 As Entity) DataContract is as follows <Serializable()> _ <DataContract()> _ Public Class Entity private m_Name as String <DataMember()> _ Public Property Name() As String Get Return m_Name End Get Set(ByVal value As String) m_Name = value End Set End Property End Class thanks

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  • How can I set the default value for a custom "Number" field in SharePoint?

    - by UnhipGlint
    I created a custom field for a content type I am creating using the XML below. <field ID="{GUID}" Required="False" DisplayName="Likes" Name="Likes" Type="Number" SourceID="http://schemas.microsoft.com/sharepoint/v3"><default>0</default></field> The field is meant to be used as a counter of sorts, and will be incremented programmatically. But, I can't get the value to default to "0" when a new item is created. However, for some reason, when I create a new column manually using the Site Collection settings page and configure it to default to "0" it works as it should. So far, I've tried the following tactics: I removed the "default" element from the field definition, and set the "DefaultValue" attribute on the content type definition. I exported a definition for the manually-created, working column (using an Imtech STSADM tool). Then, I added it to my field definitions XML and modified the IDs so that I could add it to my content type. When I did this, it still didn't work, even though it was exported from a working column! Any idea why this isn't working for me?

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  • Java Mvc And Hibernate

    - by GigaPr
    Hi i am trying to learn Java, Hibernate and the MVC pattern. Following various tutorial online i managed to map my database, i have created few Main methods to test it and it works. Furthermore i have created few pages using the MVC patter and i am able to display some mock data as well in a view. the problem is i can not connect the two. this is what i have My view Looks like this <%@ include file="/WEB-INF/jsp/include.jsp" %> <html> <head> <title>Users</title> <%@ include file="/WEB-INF/jsp/head.jsp" %> </head> <body> <%@ include file="/WEB-INF/jsp/header.jsp" %> <img src="images/rss.png" alt="Rss Feed"/> <%@ include file="/WEB-INF/jsp/menu.jsp" %> <div class="ContainerIntroText"> <img src="images/usersList.png" class="marginL150px" alt="Add New User"/> <br/> <br/> <div class="usersList"> <div class="listHeaders"> <div class="headerBox"> <strong>FirstName</strong> </div> <div class="headerBox"> <strong>LastName</strong> </div> <div class="headerBox"> <strong>Username</strong> </div> <div class="headerAction"> <strong>Edit</strong> </div> <div class="headerAction"> <strong>Delete</strong> </div> </div> <br><br> <c:forEach items="${users}" var="user"> <div class="listElement"> <c:out value="${user.firstName}"/> </div> <div class="listElement"> <c:out value="${user.lastName}"/> </div> <div class="listElement"> <c:out value="${user.username}"/> </div> <div class="listElementAction"> <input type="button" name="Edit" title="Edit" value="Edit"/> </div> <div class="listElementAction"> <input type="image" src="images/delete.png" name="image" alt="Delete" > </div> <br /> </c:forEach> </div> </div> <a id="addUser" href="addUser.htm" title="Click to add a new user">&nbsp;</a> </body> </html> My controller public class UsersController implements Controller { private UserServiceImplementation userServiceImplementation; public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ModelAndView modelAndView = new ModelAndView("users"); List<User> users = this.userServiceImplementation.get(); modelAndView.addObject("users", users); return modelAndView; } public UserServiceImplementation getUserServiceImplementation() { return userServiceImplementation; } public void setUserServiceImplementation(UserServiceImplementation userServiceImplementation) { this.userServiceImplementation = userServiceImplementation; } } My servelet definitions <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"> <!-- the application context definition for the springapp DispatcherServlet --> <bean name="/home.htm" class="com.rssFeed.mvc.HomeController"/> <bean name="/rssFeeds.htm" class="com.rssFeed.mvc.RssFeedsController"/> <bean name="/addUser.htm" class="com.rssFeed.mvc.AddUserController"/> <bean name="/users.htm" class="com.rssFeed.mvc.UsersController"> <property name="userServiceImplementation" ref="userServiceImplementation"/> </bean> <bean id="userServiceImplementation" class="com.rssFeed.ServiceImplementation.UserServiceImplementation"> <property name="users"> <list> <ref bean="user1"/> <ref bean="user2"/> </list> </property> </bean> <bean id="user1" class="com.rssFeed.domain.User"> <property name="firstName" value="firstName1"/> <property name="lastName" value="lastName1"/> <property name="username" value="username1"/> <property name="password" value="password1"/> </bean> <bean id="user2" class="com.rssFeed.domain.User"> <property name="firstName" value="firstName2"/> <property name="lastName" value="lastName2"/> <property name="username" value="username2"/> <property name="password" value="password2"/> </bean> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/jsp/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans> and finally this class to access the database public class HibernateUserDao extends HibernateDaoSupport implements UserDao { public void addUser(User user) { getHibernateTemplate().saveOrUpdate(user); } public List<User> get() { User user1 = new User(); user1.setFirstName("FirstName"); user1.setLastName("LastName"); user1.setUsername("Username"); user1.setPassword("Password"); List<User> users = new LinkedList<User>(); users.add(user1); return users; } public User get(int id) { throw new UnsupportedOperationException("Not supported yet."); } public User get(String username) { return null; } } the database connection occurs in this file <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd"> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="org.hsqldb.jdbcDriver"/> <property name="url" value="jdbc:hsqldb:hsql://localhost/rss"/> <property name="username" value="sa"/> <property name="password" value=""/> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean" > <property name="dataSource" ref="dataSource" /> <property name="mappingResources"> <list> <value>com/rssFeed/domain/User.hbm.xml</value> </list> </property> <property name="hibernateProperties" > <props> <prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect</prop> </props> </property> </bean> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory"/> </bean> <bean id="userDao" class="com.rssFeed.dao.hibernate.HibernateUserDao"> <property name="sessionFactory" ref="sessionFactory"/> </bean> </beans> Could you help me to solve this problem i spent the last 4 days and nights on this issue without any success Thanks

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  • Problem with 2 levels of inheritance in hibernate mapping

    - by Seth
    Here's my class structure: class A class B extends A class C extends A class D extends C class E extends C And here are my mappings (class bodies omitted for brevity): Class A: @Entity @Inheritance(strategy=InheritanceType.SINGLE_TABLE) @MappedSuperclass @DiscriminatorColumn( name="className", discriminatorType=DiscriminatorType.STRING ) @ForceDiscriminator public abstract class A Class B: @Entity @DiscriminatorValue("B") public class B extends A Class C: @Entity @DiscriminatorValue("C") @MappedSuperclass @DiscriminatorColumn( name="cType", discriminatorType=DiscriminatorType.STRING ) @ForceDiscriminator public abstract class C extends A Class D: @Entity @DiscriminatorValue("D") public class D extends C Class E: @Entity @DiscriminatorValue("E") public class E extends C I've got a class F that contains a set of A: @Entity public class F { ... @OneToMany(fetch=FetchType.LAZY, cascade=CascadeType.ALL) @JoinTable( name="F_A", joinColumns = @JoinColumn(name="A_ID"), inverseJoinColumns = @JoinColumn(name="F_ID") ) private Set<A> aSet = new HashSet<A>(); ... The problem is that whenever I add a new E instance to aSet and then call session.saveOrUpdate(fInstance), hibernate saves with "A" as the discrimiator string. When I try to access the aSet in the F instance, I get the following exception (full stacktrace ommitted for brevity): org.hibernate.InstantiationException: Cannot instantiate abstract class or interface: path.to.class.A Am I mapping the classes incorrectly? How am I supposed to map multiple levels of inheritance? Thanks for the help!

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  • How to provide an inline model field with a queryset choices without losing field value for inline r

    - by Judith Boonstra
    The code displayed below is providing the choices I need for the app field, and the choices I need for the attr field when using Admin. I am having a problem with the attr field on the inline form for already saved records. The attr selected for these saved does show in small print above the field, but not within the field itself. # MODELS: Class Vocab(models.Model): entity = models.Charfield, max_length = 40, unique = True) Class App(models.Model): name = models.ForeignKey(Vocab, related_name = 'vocab_appname', unique = True) app = SelfForeignKey('self, verbose_name = 'parent', blank = True, null = True) attr = models.ManyToManyField(Vocab, related_name = 'vocab_appattr', through ='AppAttr' def parqs(self): a method that provides a queryset consisting of available apps from vocab, excluding self and any apps within the current app's dependent line. def attrqs(self): a method that provides a queryset consisting of available attr from vocab excluding those already selected by current app, 2) those already selected by any apps within the current app's parent line, and 3) those selected by any apps within the current app's dependent line. Class AppAttr(models.Model): app = models.ForeignKey(App) attr = models.ForeignKey(Vocab) # FORMS: from models import AppAttr def appattr_form_callback(instance, field, *args, **kwargs) if field.name = 'attr': if instance: return field.formfield(queryset = instance.attrqs(), *kwargs) return field.formfield(*kwargs) # ADMIN: necessary imports class AppAttrInline(admin.TabularInline): model = AppAttr def get_formset(self, request, obj = None, **kwargs): kwargs['formfield_callback'] = curry(appattr_form_callback, obj) return super(AppAttrInline, self).get_formset(request, obj, **kwargs) class AppForm(forms.ModelForm): class Meta: model = App def __init__(self, *args, **kwargs): super(AppForm, self).__init__(*args, **kwargs) if self.instance.id is None: working = App.objects.all() else: thisrec = App.objects.get(id = self.instance.id) working = thisrec.parqs() self.fields['par'].queryset = working class AppAdmin(admin.ModelAdmin): form = AppForm inlines = [AppAttrInline,] fieldsets = .......... necessary register statements

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  • Protecting critical sections based on a condition in C#

    - by NAADEV
    Hello, I'm dealing with a courious scenario. I'm using EntityFramework to save (insert/update) into a SQL database in a multithreaded environment. The problem is i need to access database to see whether a register with a particular key has been already created in order to set a field value (executing) or it's new to set a different value (pending). Those registers are identified by a unique guid. I've solved this problem by setting a lock since i do know entity will not be present in any other process, in other words, i will not have same guid in different processes and it seems to be working fine. It looks something like that: static readonly object LockableObject = new object(); static void SaveElement(Entity e) { lock(LockableObject) { Entity e2 = Repository.FindByKey(e); if (e2 != null) { Repository.Insert(e2); } else { Repository.Update(e2); } } } But this implies when i have a huge ammount of requests to be saved, they will be queued. I wonder if there is something like that (please, take it just as an idea): static void SaveElement(Entity e) { (using ThisWouldBeAClassToProtectBasedOnACondition protector = new ThisWouldBeAClassToProtectBasedOnACondition(e => e.UniqueId) { Entity e2 = Repository.FindByKey(e); if (e2 != null) { Repository.Insert(e2); } else { Repository.Update(e2); } } } The idea would be having a kind of protection that protected based on a condition so each entity e would have its own lock based on e.UniqueId property. Any idea?

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  • How to automatically display relationships in logical diagram?

    - by Cliff Chaney
    Consider a Logical Model where Entity A and Entity B are connected via Relationship Z. If I create a Logical Diagram (note: not another logical MODEL), I am able to drag Entity A and Entity B onto the diagram. Since the Logical Model already "knows" that Entity A and Entity B have a relationship, I would like to be able to easily add it to my logical diagram. I am already aware of the "Show Symbols" option whereby I can select the specific relationship that I want and have it appear. That is not a solution for me. The problem is that I have a LARGE logical model consisting of HUNDREDS of Entities and their various relationships. I then need to create application-specific diagrams consisting of a subset of those entities. I can easily identify and drag the 50+ entities onto a new diagram. But identifying and selecting all the associations is an exercise in frustration. Is there an option or some sort of feature that I'm missing - or any other trick - that would allow me to add only the relationships between selected entities or all entities on a diagram?

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  • Accessing derived class members with a base class pointer

    - by LRB
    I am making a simple console game in C++ I would like to know if I can access members from the 'entPlayer' class while using a pointer that is pointing to the base class ( 'Entity' ): class Entity { public: void setId(int id) { Id = id; } int getId() { return Id; } protected: int Id; }; class entPlayer : public Entity { string Name; public: entPlayer() { Name = ""; Id = 0; } void setName(string name) { Name = name; } string getName() { return Name; } }; Entity *createEntity(string Type) { Entity *Ent = NULL; if (Type == "player") { Ent = new entPlayer; } return Ent; } void main() { Entity *ply = createEntity("player"); ply->setName("Test"); ply->setId(1); cout << ply->getName() << endl; cout << ply->getId() << endl; delete ply; } How would I be able to call ply-setName etc? OR If it's not possible that way, what would be a better way?

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  • Symfony 2 - Updating a table based on newly inserted record in another table

    - by W00d5t0ck
    I'm trying to create a small forum application using Symfony 2 and Doctrine 2. My ForumTopic entity has a last_post field (oneToOne mapping). Now when I persist my new post with $em->persist($post); I want to update my ForumTopic entity so its last_post field would reference this new post. I have just realised that it cannot be done with a Doctrine postPersist Listener, so I decided to use a small hack, and tried: $em->persist($post); $em->flush(); $topic->setLastPost($post); $em->persist($post); $em->flush(); but it doesn't seem to update my topics table. I also took a look at http://docs.doctrine-project.org/projects/doctrine-orm/en/2.1/reference/working-with-associations.html#transitive-persistence-cascade-operations hoping it will solve the problem by adding cascade: [ 'persist' ] to my Topic.orm.yml file, but it didn't help, either. Could anyone point me to a solution or an example class? My ForumTopic is: FrontBundle\Entity\ForumTopic: type: entity table: forum_topics id: id: type: integer generator: strategy: AUTO fields: title: type: string(100) nullable: false slug: type: string(100) nullable: false created_at: type: datetime nullable: false updated_at: type: datetime nullable: true update_reason: type: text nullable: true oneToMany: posts: targetEntity: ForumPost mappedBy: topic manyToOne: created_by: targetEntity: User inversedBy: articles nullable: false updated_by: targetEntity: User nullable: true default: null topic_group: targetEntity: ForumTopicGroup inversedBy: topics nullable: false oneToOne: last_post: targetEntity: ForumPost nullable: true default: null cascade: [ persist ] uniqueConstraint: uniqueSlugByGroup: columns: [ topic_group, slug ] And my ForumPost is: FrontBundle\Entity\ForumPost: type: entity table: forum_posts id: id: type: integer generator: strategy: AUTO fields: created_at: type: datetime nullable: false updated_at: type: datetime nullable: true update_reason: type: string nullable: true text: type: text nullable: false manyToOne: created_by: targetEntity: User inversedBy: forum_posts nullable: false updated_by: targetEntity: User nullable: true default: null topic: targetEntity: ForumTopic inversedBy: posts

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  • How to change Hibernate´s auto persistance strategy

    - by Kristofer Borgstrom
    I just noted that my hibernate entities are automatically persisted to the database (or at least to cache) before I call any save() or update() method. To me this is a pretty strange default behavior but ok, as long as I can disable it, it´s fine. The problem I have is I want to update my entity´s state (from 1 to 2) only if the entity in the database still has the state it had when I retrieved [1] (this is to eliminate concurrency issues when another server is updating this same object). For this reason I have created a custom NamedQuery that will only update the entity if state is 1. So here is some pseudo-code: //Get the entity Entity item = dao.getEntity(); item.getState(); //==1 //Update the entity item.setState(2); //Here is the problem, this effectively changes the state of my entity braking my query that verifies that state is still == 1. dao.customUpdate(item); //Returns 0 rows changes since state != 1. So, how do I make sure the setters don´t change the state in cache/db? Thanks, Kristofer

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  • Using classes for the first time,help in debugging

    - by kaushik
    here is post my code:this is no the entire code but enough to explain my doubt.please discard any code line which u find irrelavent enter code here saving_tree={} isLeaf=False class tree: global saving_tree rootNode=None lispTree=None def __init__(self,x): file=x string=file.readlines() #print string self.lispTree=S_expression(string) self.rootNode=BinaryDecisionNode(0,'Root',self.lispTree) class BinaryDecisionNode: global saving_tree def __init__(self,ind,name,lispTree,parent=None): self.parent=parent nodes=lispTree.getNodes(ind) print nodes self.isLeaf=(nodes[0]==1) nodes=nodes[1]#Nodes are stored self.name=name self.children=[] if self.isLeaf: #Leaf Node print nodes #Set the leaf data self.attribute=nodes print "LeafNode is ",nodes else: #Set the question self.attribute=lispTree.getString(nodes[0]) self.attribute=self.attribute.split() print "Question: ",self.attribute,self.name tree={} tree={str(self.name):self.attribute} saving_tree=tree #Add the children for i in range(1,len(nodes)):#Since node 0 is a question # print "Adding child ",nodes[i]," who has ",len(nodes)-1," siblings" self.children.append(BinaryDecisionNode(nodes[i],self.name+str(i),lispTree,self)) print saving_tree i wanted to save some data in saving_tree{},which i have declared previously and want to use that saving tree in the another function outside the class.when i asked to print saving_tree it printing but,only for that instance.i want the saving_tree{} to have the data to store data of all instance and access it outside. when i asked for print saving_tree outside the class it prints empty{}.. please tell me the required modification to get my required output and use saving_tree{} outside the class..

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  • ZF2 namespace and file system

    - by user1918648
    I have standard Application module in ZF2. It's configured by default, I didn't change anything. I just added some stuff: module/ Application/ src/ Application/ Entity/ Product/ **Product.php** Controller/ **IndexController.php** Product.php namespace Application\Entity; class Product { } IndexController.php namespace Application\Controller; use Zend\Mvc\Controller\AbstractActionController; use Zend\View\Model\ViewModel; use Application\Entity\Product; class IndexController extends AbstractActionController { public function indexAction() { $product = new Product(); } } and I get following error: Fatal error: Class 'Application\Entity\Product' not found in \module\Application\src\Application\Controller\IndexController.php on line 20 I use the same namespace, but it doesn't see it. Why? P.S: If I will change Product.php to be the following: namespace Application\Entity\Product; class Product { } then in the IndexController.php the following code will be working: namespace Application\Controller; use Zend\Mvc\Controller\AbstractActionController; use Zend\View\Model\ViewModel; use Application\Entity\Product\Product; class IndexController extends AbstractActionController { public function indexAction() { $product = new Product(); } }

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  • Is it possible to Store Enum value in String?

    - by Narasimham K
    Actally my java progrem like... public class Schedule{ public static enum RepeatType { DAILY, WEEKLY, MONTHLY; } public static enum WeekdayType { MONDAY(Calendar.MONDAY), TUESDAY(Calendar.TUESDAY), WEDNESDAY( Calendar.WEDNESDAY), THURSDAY(Calendar.THURSDAY), FRIDAY( Calendar.FRIDAY), SATURDAY(Calendar.SATURDAY), SUNDAY( Calendar.SUNDAY); private int day; private WeekdayType(int day) { this.day = day; } public static List<Date> generateSchedule(RepeatType repeatType,List<WeekdayType> repeatDays) { ----------------------------- ----------------------------//hear some logic i wrote }//Method } And i'm calling the method into my Business class like following... @RemotingInclude public void createEvent(TimetableVO timetableVO) { if ("repeatDays".equals(timetableVO.getSearchKey())) { List<Date> repeatDaysList=Schedule.generateSchedule(timetableVO.getRepeatType(),timetableVO.getRepeatDays()); } } And Finally TimetableVO is @Entity @Table(name="EC_TIMETABLE") public class TimetableVO extends AbstractVO{ ----- private RepeatType repeatType; private List<WeekdayType> repeatDays;//But in this case the method generateSchedule(-,-) was not calling. ----- } So my Question is Which one is Better Statement in the Following... private List<WeekdayType> repeatDays; (or) private String repeatDays;//if we give like this `How to Convert Enum type to String` because generateSchedule() method taking enum type value....

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  • SSL connection error during handshake on Windows Server 2008 R2

    - by Thomas
    I have a Windows 2008 R2 Server that runs a HTTPS Tunneling service. The software uses a certificate that is provided via the Windows certificate store. The certificate is located in the local computer private certificates. It supports server and client authentication with signing and keyencipherment. Cert chain The certificate chain looks fine. It's a Thawte SSL123 certificate. Thawte Premium Server CA (SHA1) [?e0 ab 05 94 20 72 54 93 05 60 62 02 36 70 f7 cd 2e fc 66 66] thawte Primary Root CA [?1f a4 90 d1 d4 95 79 42 cd 23 54 5f 6e 82 3d 00 00 79 6e a2] Thawte DV SSL CA [3c a9 58 f3 e7 d6 83 7e 1c 1a cf 8b 0f 6a 2e 6d 48 7d 67 62] Server certificate Issues Most browsers accept the certificate without any warning. But IE 7 on Windows XP SP3 and Opera 12 on OSX just report an connection error. Opera complains: Secure connection: fatal error (552) https://www.example.com/ Opera was not able to connect to the server, because the server does not communicate via any secure protocol known to Opera. A connection test using openssl s_client -connect www.example.com:443 -state says: CONNECTED(00000003) SSL_connect:before/connect initialization SSL_connect:SSLv2/v3 write client hello A 52471:error:140790E5:SSL routines:SSL23_WRITE:ssl handshake failure:/SourceCache/OpenSSL098/OpenSSL098-35.1/src/ssl/s23_lib.c:182: ssldump -aAHd host www.example.com during curl https://www.example.com/ reports: New TCP connection #1: localhost(53302) <-> www.example.com(443) 1 1 0.0235 (0.0235) C>SV3.1(117) Handshake ClientHello Version 3.1 random[32]= 50 77 56 29 e8 23 82 3b 7f e0 ae 2d c1 31 cb ac 38 01 31 85 4f 91 39 c1 04 32 a6 68 25 cd a0 c1 cipher suites Unknown value 0x39 Unknown value 0x38 Unknown value 0x35 TLS_DHE_RSA_WITH_3DES_EDE_CBC_SHA TLS_DHE_DSS_WITH_3DES_EDE_CBC_SHA TLS_RSA_WITH_3DES_EDE_CBC_SHA Unknown value 0x33 Unknown value 0x32 Unknown value 0x2f Unknown value 0x9a Unknown value 0x99 Unknown value 0x96 TLS_RSA_WITH_RC4_128_SHA TLS_RSA_WITH_RC4_128_MD5 TLS_DHE_RSA_WITH_DES_CBC_SHA TLS_DHE_DSS_WITH_DES_CBC_SHA TLS_RSA_WITH_DES_CBC_SHA TLS_DHE_RSA_EXPORT_WITH_DES40_CBC_SHA TLS_DHE_DSS_EXPORT_WITH_DES40_CBC_SHA TLS_RSA_EXPORT_WITH_DES40_CBC_SHA TLS_RSA_EXPORT_WITH_RC2_CBC_40_MD5 TLS_RSA_EXPORT_WITH_RC4_40_MD5 Unknown value 0xff compression methods unknown value NULL 1 0.0479 (0.0243) S>C TCP FIN 1 0.0481 (0.0002) C>S TCP FIN Thawte provides two Java based SSL Checkers. The Legacy Thawte SSL Certificate Installation Checker and the sslToolBox. Both validate the certificate under Windows XP but report connection errors under OSX and Windows 2008 R2.

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  • ASP.NET MVC - Pass array object as a route value within Html.ActionLink(...)

    - by Mike
    I have a method that returns an array (string[]) and I'm trying to pass this array of strings into an Action Link so that it will create a query string similar to: /Controller/Action?str=val1&str=val2&str=val3...etc But when I pass new { str = GetStringArray() } I get the following url: /Controller/Action?str=System.String%5B%5D So basically it's taking my string[] and running .ToString() on it to get the value. Any ideas? Thanks!

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  • How do I INSERT INTO from one mysql table into another table and set the value of one column?

    - by Laxmidi
    Hi, I need to insert data from table1 into table2. However, I would like to set the myYear column in table2 to 2010. But, there isn't a myYear Column in table1. So, my basic insert looks like: INSERT INTO `table2` ( place, event ) SELECT place, event FROM table1 Roughly, I'd like to do something like the following: INSERT INTO `table2` ( place, event, SET myYear='2010' ) ... Is there a way to set the column value in the insert statement? THANK YOU! -Laxmidi

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  • JQuery error: XML filter is applied to non-XML value (function (E, F) {return new (o.fn.init)(E, F);

    - by morpheous
    I am getting this slightly cryptic error message: XML filter is applied to non-XML value (function (E, F) {return new (o.fn.init)(E, F);}) when I run this code snippet function justDoIt(arg){ msg = arg.msg; if(arg.ok) jQuery.(".action-button").each(function(idx,el){jQuery(this).removeClass('enabled');} ); } arg is a JSON format response form the server. Anyone knows how to fix this?

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  • How to add a default value to an already existing column?

    - by Earlz
    I have an existing column in my SQL Server database. I have tried about everything I can think of but can not get a default value to be added to the column. What works in every other database is alter table mytable alter column mycolumn set default(now()) --mycolumn is a datetime How do I do this in SQL Server? The error I get for that exact syntax is incorrect syntax near the keyword 'set'

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