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  • malloc unable to assign memory + doesnt warn

    - by sraddhaj
    char *str=NULL; strsave(s,str,n+1); printf("%s",str-n); when I gdb debug this code I find that the str value is 0x0 which is null and also that my code is not catching this failed memory allocation , it doesnt execute str==NULL perror code ...Any idea void strsave(char *s,char *str,int n) { str=(char *)malloc(sizeof(char)* n); if(str==NULL) perror("failed to allocate memory"); while(*s) { *str++=*s++; } *str='\0'; }

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