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  • Why does my jQuery/YQL call not return anything?

    - by tastyapple
    I'm trying to access YQL with jQuery but am not getting a response: http://jsfiddle.net/tastyapple/grMb3/ Anyone know why? $(function(){ $.extend( { _prepareYQLQuery: function (query, params) { $.each( params, function (key) { var name = "#{" + key + "}"; var value = $.trim(this); if (!value.match(/^[0-9]+$/)) { value = '"' + value + '"'; } query = query.replace(name, value); } ); return query; }, yql: function (query) { var $self = this; var successCallback = null; var errorCallback = null; if (typeof arguments[1] == 'object') { query = $self._prepareYQLQuery(query, arguments[1]); successCallback = arguments[2]; errorCallback = arguments[3]; } else if (typeof arguments[1] == 'function') { successCallback = arguments[1]; errorCallback = arguments[2]; } var doAsynchronously = successCallback != null; var yqlJson = { url: "http://query.yahooapis.com/v1/public/yql", dataType: "jsonp", success: successCallback, async: doAsynchronously, data: { q: query, format: "json", env: 'store://datatables.org/alltableswithkeys', callback: "?" } } if (errorCallback) { yqlJson.error = errorCallback; } $.ajax(yqlJson); return $self.toReturn; } } ); $.yql( "SELECT * FROM github.repo WHERE id='#{username}' AND repo='#{repository}'", { username: "jquery", repository: "jquery" }, function (data) { if (data.results.repository["open-issues"].content > 0) { alert("Hey dude, you should check out your new issues!"); } } ); });

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