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  • Finding if a Binary Tree is a Binary Search Tree

    - by dharam
    Today I had an interview where I was asked to write a program which takes a Binary Tree and returns true if it is also a Binary Search Tree otherwise false. My Approach1: Perform an inroder traversal and store the elements in O(n) time. Now scan through the array/list of elements and check if element at ith index is greater than element at (i+1)th index. If such a condition is encountered, return false and break out of the loop. (This takes O(n) time). At the end return true. But this gentleman wanted me to provide an efficient solution. I tried but I was unsuccessfult, because to find if it is a BST I have to check each node. Moreover he was pointing me to think over recusrion. My Approach 2: A BT is a BST if for any node N N-left is < N and N-right N , and the INorder successor of left node of N is less than N and the inorder successor of right node of N is greater than N and the left and right subtrees are BSTs. But this is going to be complicated and running time doesn't seem to be good. Please help if you know any optimal solution. Thanks.

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  • Binary to strings as binary? C #/.NET

    - by acidzombie24
    Redis keys are binary safe. I'd like to mess around and put binary into redis using C#. My client of choice doesn't support writing binary keys it uses keys and it make sense. However i am just fooling around so tell me how i can do this. How do i convert a raw byte[] into a string? At first i was thinking about converting a byte[] to a utf8 string however unicode has some checks to see if its valid or not. So raw binary should fail. Actually i tried it out. Instead of failing i got a strange result. My main question is how do i convert a raw byte[] to the equivalent string? My unimportant question is why did i get a 512 byte string instead of an exception saying this is not a valid UTF8 string? code var rainbow = new byte[256]; for (int i = 0; i < 256; i++) { rainbow[i] = (byte)i; } var sz = Encoding.UTF8.GetString(rainbow); var szarr = Encoding.UTF8.GetBytes(sz); Console.WriteLine("{0} {1} {2}", ByteArraysEqual(szarr, rainbow), szarr.Length, rainbow.Length); Output False 512 256

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  • apt-get update error - binary-i386, binary-amd64 [duplicate]

    - by magamig
    This question already has an answer here: How can I fix a 404 Error when updating packages? 5 answers When I run: sudo apt-get update It shows me the following error: W: Failed to fetch http://ppa.launchpad.net/directhex/ppa/ubuntu/dists/trusty/main/binary-amd64/Packages 404 Not Found W: Failed to fetch http://ppa.launchpad.net/directhex/ppa/ubuntu/dists/trusty/main/binary-i386/Packages 404 Not Found E: Some index files failed to download. They have been ignored, or old ones used instead. I have googled for solutions, but none of what I found, have worked for me. Please give me your suggestions

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  • Next Phase of ECM 11g Now Available - New UCM & URM 11g, & Updated I/PM & IRM 11g

    - by michelle.huff
    We're excited to announce that the Oracle Enterprise Content Management Suite 11g is now available! Today, Oracle announced ECM Suite 11g, a part of Fusion Middleware 11gR1 Patchset 2 release, which builds upon the Imaging and Process Management (I/PM) and Information Rights Management (IRM) 11g release earlier this year. Universal Content Management (UCM) and Universal Records Management (URM) 11g are now available with many new features and enhancements. All ECM products are localized into 27 languages, use a single repository, a single installer, centralized administration, and all run on the same Fusion Middleware tech stack. Oracle ECM Suite 11g, is better integrated to fit the way you work, with extreme performance and extreme scalability. Universal Content Management One click Web content management - brings Web content management authoring, design and presentation capabilities directly into how organizations design sites, portals, and custom Web applications. Simply take in the right amount of WCM that meets your needs - all without having to rewrite the application or port it over to a new technology stack or framework. Greater business user empowerment - with next generation desktop integrations and "smart productivity folders", new Web site "design mode" for business users, and enhanced rich media support enabling users to better work with photography, graphics, videos & podcasts created today as well as contribute content within Flash files directly from the Web. Advanced manageability with extreme performance & scalability - centralized system monitoring, installation, logging, performance metrics & diagnostics, with new built in "fast check-in" features, redesigned component management interface - all running on Fusion Middleware infrastructure. Universal Records Management Enhanced user experience: Oracle URM 11g makes records management easier for both business users and records administrators. Simplifications in the end user experience allow the creation of bookmarks into often-used part of the file plan, easy copying of categories and dispositions, and integrated folder and records search. The records management dashboard provides a consolidated view into records administrator tasks and system performance. DoD 5015.02 v3: Oracle URM is fully certified against all part of the US Department of Defense records management standard - baseline, classified, and Freedom of Information and Privacy Act. This enables Federal, state, & local governments & public agencies, as well as private companies, to maintain regulated compliance. Expanded functionality through Oracle integrations: Oracle URM 11g allows for an expanded set of functionality through integration capabilities with other Oracle products. This includes configurable records definition capabilities directly within a UCM instance. An out of the box integration with Oracle BI Publisher provides easily configured and robust reporting. Additionally, 11g offers an out of the box Oracle Secure Enterprise Search integration enabling real time full text discovery across disparate systems in an organization. Read the Press Release Watch the 3 Minute ECM 11g Video Get Up to Speed with the What's New in ECM Suite Datasheet Learn More on OTN with new tutorials, downloads and whitepapers

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  • Do dconf use EXI binary XML?

    - by Hibou57
    A question came to my mind reading an answer to the question What are the differences between gconf and dconf?. In an reply to the above question, Oli said: Binary read access is far faster than parsing XML. However, there exist a W3C recommendation for binary XML, since 2010: Efficient XML Interchange (EXI) Format 1.0. Is this what dconf uses? If Yes, where is it confirmed? If No, was there some investigations toward it at some time, and what was the conclusions? Thanks for any tracks, I'm curious to know.

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  • Binary on the Coat of Arms of the Governor General of Canada

    - by user132636
    Can you help me further this investigation? Here is about 10% of the work I have done on it. I present it only to see if there are any truly curious people among you. I made a video a few weeks ago showing some strange things about the Governor General's Coat of Arms and the binary on it. Today, I noticed something kinda cool and thought I would share. Here is the binary as it appears on the COA: 110010111001001010100100111010011 As DEC: 6830770643 (this is easily found on the web) Take a close look at that number. What do you notice about it? It has a few interesting features, but here is the one no one has pointed out... Split it down the middle and you have 68307 70643. The first digit is double the value of the last digit. The second digit is double the second last digit. The third digit is half of the third to last digit. And the middle ones are even or neutral. At first, I thought of it as energy. ++-nnnn+-- But actually you can create something else with it using the values. 221000211. See how that works. You may be asking why that is significant. Bare with me. I know 99% are rolling their eyes. 221000211 as base3 gives you this as binary: 100011101000111 100011101000111 as HEX is 4747, which converts to "GG". Initials of Governor General. GG.ca is his website. When you convert to base 33 (there are 33 digits in the original code) you get "GOV" Interesting? :D There is a lot more to it. I'll continue to show some strange coincidences if anyone is interested. Sorry if I am not explaining this correctly. By now you have probably figured out that I have no background in this. Which is why I am here. Thank you.

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  • Binary Search Tree - Postorder logic

    - by daveb
    I am looking at implementing code to work out binary search tree. Before I do this I was wanting to verify my input data in postorder and preorder. I am having trouble working out what the following numbers would be in postorder and preorder I have the following numbers 4, 3, 14 ,8 ,1, 15, 9, 5, 13, 10, 2, 7, 6, 12, 11, that I am intending to put into an empty binary tree in that order. The order I arrived at for the numbers in POSTORDER is 2, 1, 6, 3, 7, 11, 12, 10, 9, 8, 13, 15, 14, 4. Have I got this right? I was wondering if anyone here would be able to kindly verify if the postorder sequence I came up with is indeed the correct sequence for my input i.e doing left subtree, right subtree and then root. The order I got for pre order (Visit root, do left subtree, do right subtree) is 4, 3, 1, 2, 5, 6, 14 , 8, 7, 9, 10, 12, 11, 15, 13. I can't be certain I got this right. Very grateful for any verification. Many Thanks

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  • C++ find largest BST in a binary tree

    - by fonjibe
    what is your approach to have the largest BST in a binary tree? I refer to this post where a very good implementation for finding if a tree is BST or not is bool isBinarySearchTree(BinaryTree * n, int min=std::numeric_limits<int>::min(), int max=std::numeric_limits<int>::max()) { return !n || (min < n->value && n->value < max && isBinarySearchTree(n->l, min, n->value) && isBinarySearchTree(n->r, n->value, max)); } It is quite easy to implement a solution to find whether a tree contains a binary search tree. i think that the following method makes it: bool includeSomeBST(BinaryTree* n) { if(!isBinarySearchTree(n)) { if(!isBinarySearchTree(n->left)) return isBinarySearchTree(n->right); } else return true; else return true; } but what if i want the largest BST? this is my first idea, BinaryTree largestBST(BinaryTree* n) { if(isBinarySearchTree(n)) return n; if(!isBinarySearchTree(n->left)) { if(!isBinarySearchTree(n->right)) if(includeSomeBST(n->right)) return largestBST(n->right); else if(includeSomeBST(n->left)) return largestBST(n->left); else return NULL; else return n->right; } else return n->left; } but its not telling the largest actually. i struggle to make the comparison. how should it take place? thanks

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  • Join Us for the Next Quarterly Customer Update Webcast

    - by michelle.huff
    Join us for the next Oracle Content Management Quarterly Customer Update Webcast scheduled for this coming June 30 / July 1 2010. Don't miss this chance to get an overview on the latest updates to Oracle Content Management. We'll be covering the latest ECM Suite 11g release - highlighting the Universal Content Management (UCM) and Universal Records Management releases. Register Today! Americas / EMEA time zones: Customer Update June 30, 2010 9:00am US PDT / 12:00pm US EDT / 16:00 GMT Length: 1 hour *Please use your corporate email address to register. Asia-Pacific time zones: Customer Update (Repeat Webcast) July 1, 2010 12:00pm Sydney AEST, 10:00am Singapore (June 30, 2010 @ 7:00pm US PDT) Length: 1 hour *Please use your corporate email address to register Please Note: If you have attended previous Quarterly Customer Update Webcasts, we are now using a new web conference system, WebEx, to host the meeting. Missed Previous Customer Quarterly Updates? Get caught up on Oracle & ECM news. View a recording or the presentation from previous Webcasts held since June 2008 (available from My Oracle Support).

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  • Find kth smallest element in a binary search tree in Optimum way

    - by Bragaadeesh
    Hi, I need to find the kth smallest element in the binary search tree without using any static/global variable. How to achieve it efficiently? The solution that I have in my mind is doing the operation in O(n), the worst case since I am planning to do an inorder traversal of the entire tree. But deep down I feel that I am not using the BST property here. Is my assumptive solution correct or is there a better one available ?

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  • How to Serialize Binary Tree

    - by Veljko Skarich
    I went to an interview today where I was asked to serialize a binary tree. I implemented an array-based approach where the children of node i (numbering in level-order traversal) were at the 2*i index for the left child and 2*i + 1 for the right child. The interviewer seemed more or less pleased, but I'm wondering what serialize means exactly? Does it specifically pertain to flattening the tree for writing to disk, or would serializing a tree also include just turning the tree into a linked list, say. Also, how would we go about flattening the tree into a (doubly) linked list, and then reconstructing it? Can you recreate the exact structure of the tree from the linked list? Thank you/

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  • Understanding binary numbers in terms of real world objects

    - by Kaushik
    When I represent a number in the decimal system, I have an intuitive knowledge of what it amounts to. For example take the number '10': I understand that it means 10 apples or 10 people... i.e I can count in the real world. But as soon as the number is converted to any other system, this understanding no longer applies. For example 10 when converted to binary will be 1010...now what does this represent? Is there a way to understand this number 1010 in terms of counting objects in the real world?

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  • Cannot execute binary file

    - by user291727
    I am new to Ubuntu and I'm trying to install Popcorn Time. I downloaded 32 bit version and tried to install it but that's where the problem started showing. I duble clicked the executable file and well, nothing happened. It's a official download from their web-site but it doesn't work. Maybe I'm doing something wrong.....Anyway, I found out that you can insatll it from a script, but people keep talking in ubuntu terms and I don't understand it, so I have a few questions: 1.How to make a script? (witch I'm suppose to run in terminal using bash comand), 2.Is it normal that i cannot run the installer, and if that is an installer or just files for the program. 3.If it is an installer, how do I make it work? 4.What does " Cannot execute binary file" mean? Thank you in advance, hope I'm not asking too many questions(please understand that I'm new to ubuntu) and sorry about my English. xD

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  • Include Binary Files in DEB package

    - by user22611
    I need to build a DEB package from mainly Node.js Javascript files, but it should include some binary files as well. They are listed inside debian/source/include-binaries. Otherwise I get the error message dpkg-source: error: unrepresentable changes to source The command in question is: bzr builddeb -- -us -uc After adding the file include-binaries, when running bzr builddeb -- -us -uc again, now I get a different error: It says dpkg-source: error: aborting due to unexpected upstream changes, see /tmp/mailadmin_0.0-1.diff.n6m5_6 I have no idea how to get rid of this. In the next line of output it tells me dpkg-source: info: you can integrate the local changes with dpkg-source --commit But if I run this command in the build area of my package, it gives me the unrepresentable changes to source error message again, even though debian/source/include-binaries is present in the build area as well. I am missing the way out of this... I tried deleting all files that are produced by the build process, still no success. Further details: The target directory is /opt/mailadmin. Since this directory is unusual, I listed it in the file debian/mailadmin.install (which contains one line:) opt/mailadmin opt/ The bzr builddeb process uses this file as expected.

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  • Binary Search Tree in Java

    - by John R
    I want to make a generic BST, that can be made up of any data type, but i'm not sure how I could add things to the tree, if my BST is generic. All of my needed code is below. I want my BST made up of Locations, and sorted by the x variable. Any help is appreciated. Major thanks for looking. public void add(E element) { if (root == null) root = element; if (element < root) add(element, root.leftChild); if (element > root) add(element, root.rightChild); else System.out.println("Element Already Exists"); } private void add(E element, E currLoc) { if (currLoc == null) currLoc = element; if (element < root) add(element, currLoc.leftChild); if (element > root) add(element, currLoc.rightChild); else System.out.println("Element Already Exists); } Other Code public class BinaryNode<E> { E BinaryNode; BinaryNode nextBinaryNode; BinaryNode prevBinaryNode; public BinaryNode() { BinaryNode = null; nextBinaryNode = null; prevBinaryNode = null; } } public class Location<AnyType> extends BinaryNode { String name; int x,y; public Location() { name = null; x = 0; y = 0; } public Location(String newName, int xCord, int yCord) { name = newName; x = xCord; y = yCord; } public int equals(Location otherScene) { return name.compareToIgnoreCase(otherScene.name); } }

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  • Deletion procedure for a Binary Search Tree

    - by Metz
    Consider the deletion procedure on a BST, when the node to delete has two children. Let's say i always replace it with the node holding the minimum key in its right subtree. The question is: is this procedure commutative? That is, deleting x and then y has the same result than deleting first y and then x? I think the answer is no, but i can't find a counterexample, nor figure out any valid reasoning. EDIT: Maybe i've got to be clearer. Consider the transplant(node x, node y) procedure: it replace x with y (and its subtree). So, if i want to delete a node (say x) which has two children i replace it with the node holding the minimum key in its right subtree: y = minimum(x.right) transplant(y, y.right) // extracts the minimum (it doesn't have left child) y.right = x.right y.left = x.left transplant(x,y) The question was how to prove the procedure above is not commutative.

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  • Designing binary operations(AND, OR, NOT) in graphs DB's like neo4j

    - by Nicholas
    I'm trying to create a recipe website using a graph database, specifically neo4j using spring-data-neo4j, to try and see what can be done in Graph Databases. My model so far is: (Chef)-[HAS_INGREDIENT]->(Ingredient) (Chef)-[HAS_VALUE]->(Value) (Ingredient)-[HAS_INGREDIENT_VALUE]->(Value) (Recipe)-[REQUIRES_INGREDIENT]->(Ingredient) (Recipe)-[REQUIRES_VALUE]->(Value) I have this set up so I can do things like have the "chef" enter ingredients they have on hand, and suggest recipes, as well as suggest recipes that are close matches, but missing one ingredient. Some recipes can get complex, utilizing AND, OR, and NOT type logic, something like (Milk AND (Butter OR spread OR (vegetable oil OR olive oil))) and I'm wondering if it would be sane to model this in a graph using a tree type representation? An example of what I was thinking is to create three "node" types of AND, OR, and NOT and have each of them connect to the nodes value underneath. How else might this be represented in a Graph Database or is my example above a decent representation?

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  • Oracle Enterprise Content Management 11gR1 Patch Set 3 Released

    - by michelle.huff
    We're pleased to announce an updated patch set for Oracle Enterprise Content Management 11gR1 PS3 (11.1.1.4.0). Patch Set 3 (PS3) supports additional platforms and applications, and adds several new features to the products. Highlights include: Content Server (repository for UCM, URM & I/PM): New security capabilities, file store provider updates. Desktop Integration Suite: Windows 7 64-bit and Office 2010 (32 & 64-bit) support and new "Recent Content Items" menu. Universal Content Management (UCM): Site Studio Manager for Site Studio for External Applications, new template management options and ability to run Site Studio & Site Studio for External Applications 11g components on Content Server 10gR3. Imaging and Process Management (I/PM): Now certified with Oracle Business Process Management (BPM) 11g, Oracle Single Sign On (OSSO) 10g and Oracle Access Manager (OAM) 10g, export search results to Microsoft Excel. ECM Adapter for PeopleSoft: Support for UCM 11g Managed Attachments (support for 10g released earlier in 2010) and certification with PeopleTools 8.50. Information Rights Management (IRM): Desktop support for Microsoft Office 2010, Adobe Reader X and Microsoft SharePoint 2010. Customer Webcast We'll be covering this new release in our Quarterly Customer Update Webcast scheduled for this week, January 19/20, 2011. Register today. More Information Downloads now available on Oracle Technology Network (OTN) - it will be available via eDelivery soon. Read the updated ECM documentation for 11.1.1.4.0 Review the ECM 11.1.1.4.0 Upgrade & Patch Guides See the Release Notes

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  • Mac 10.6 Universal Binary scipy: cephes/specfun "_aswfa_" symbol not found

    - by Markus
    Hi folks, I can't get scipy to function in 32 bit mode when compiled as a i386/x86_64 universal binary, and executed on my 64 bit 10.6.2 MacPro1,1. My python setup With the help of this answer, I built a 32/64 bit intel universal binary of python 2.6.4 with the intention of using the arch command to select between the architectures. (I managed to make some universal binaries of a few libraries I wanted using lipo.) That all works. I then installed scipy according to the instructions on hyperjeff's article, only with more up-to-date numpy (1.4.0) and skipping the bit about moving numpy aside briefly during the installation of scipy. Now, everything except scipy seems to be working as far as I can tell, and I can indeed select between 32 and 64 bit mode using arch -i386 python and arch -x86_64 python. The error Scipy complains in 32 bit mode: $ arch -x86_64 python -c "import scipy.interpolate; print 'success'" success $ arch -i386 python -c "import scipy.interpolate; print 'success'" Traceback (most recent call last): File "<string>", line 1, in <module> File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/interpolate/__init__.py", line 7, in <module> from interpolate import * File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/interpolate/interpolate.py", line 13, in <module> import scipy.special as spec File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/__init__.py", line 8, in <module> from basic import * File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/basic.py", line 8, in <module> from _cephes import * ImportError: dlopen(/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/_cephes.so, 2): Symbol not found: _aswfa_ Referenced from: /Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/_cephes.so Expected in: flat namespace in /Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/_cephes.so Attempt at tracking down the problem It looks like scipy.interpolate imports something called _cephes, which looks for a symbol called _aswfa_ but can't find it in 32 bit mode. Browsing through scipy's source, I find an ASWFA subroutine in specfun.f. The only scipy product file with a similar name is specfun.so, but both that and _cephes.so appear to be universal binaries: $ cd /Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/ $ file _cephes.so specfun.so _cephes.so: Mach-O universal binary with 2 architectures _cephes.so (for architecture i386): Mach-O bundle i386 _cephes.so (for architecture x86_64): Mach-O 64-bit bundle x86_64 specfun.so: Mach-O universal binary with 2 architectures specfun.so (for architecture i386): Mach-O bundle i386 specfun.so (for architecture x86_64): Mach-O 64-bit bundle x86_64 Ho hum. I'm stuck. Things I may try but haven't figured out how yet include compiling specfun.so myself manually, somehow. I would imagine that scipy isn't broken for all 32 bit machines, so I guess something is wrong with the way I've installed it, but I can't figure out what. I don't really expect a full answer given my fairly unique (?) setup, but if anyone has any clues that might point me in the right direction, they'd be greatly appreciated. (edit) More details to address questions: I'm using gfortran (GNU Fortran from GCC 4.2.1 Apple Inc. build 5646). Python 2.6.4 was installed more-or-less like so: cd /tmp curl -O http://www.python.org/ftp/python/2.6.4/Python-2.6.4.tar.bz2 tar xf Python-2.6.4.tar.bz2 cd Python-2.6.4 # Now replace buggy pythonw.c file with one that supports the "arch" command: curl http://bugs.python.org/file14949/pythonw.c | sed s/2.7/2.6/ > Mac/Tools/pythonw.c ./configure --enable-framework=/Library/Frameworks --enable-universalsdk=/ --with-universal-archs=intel make -j4 sudo make frameworkinstall Scipy 0.7.1 was installed pretty much as described as here, but it boils down to a simple sudo python setup.py install. It would indeed appear that the symbol is undefined in the i386 architecture if you look at the _cephes library with nm, as suggested by David Cournapeau: $ nm -arch x86_64 /Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/_cephes.so | grep _aswfa_ 00000000000d4950 T _aswfa_ 000000000011e4b0 d _oblate_aswfa_data 000000000011e510 d _oblate_aswfa_nocv_data (snip) $ nm -arch i386 /Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/special/_cephes.so | grep _aswfa_ U _aswfa_ 0002e96c d _oblate_aswfa_data 0002e99c d _oblate_aswfa_nocv_data (snip) however, I can't yet explain its absence.

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  • Turning Separate iPad/iPhone Targets into Universal App

    - by ckrames1234
    I, when I got my hands on the iPad SDK Beta, thought the universal binary would be to much work, so i opted for the separate targets. I realized halfway through making the iPad portion of my app, that making a universal application would be easy as pie. The issue is, I can't use Apple's option to convert my iPhone Target to Universal. The only thing that I would need to do in the Info.plist of the universal application would be to set a different MainWindow. How could I approach the problem? Is there a workaround to get Apple's way to work (maybe by deleting the existing iPad Target)? Is there a good way to do it manually? If any of you have experience on this subject, help would be much appreciated Thanks, Conrad Kramer

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  • Combining iPhone/iPad apps into one universal app

    - by user324881
    I have two apps (one for the iPhone, the other for the iPad) that I'd like to combine into one universal app. For my first attempt, I tried creating a new universal app project and added the libraries for the iPhone and iPad versions. The iPad version compiled and ran fine (as expected), but the iPhone version didn't. My hope was that I could create a universal app that would execute only the project in the iPhone library when running on the iPhone and vice versa for the iPad. It seems like this should still work. Is there a way to tell the universal app project to ignore one of the external libraries when compiling for the iPad and vice versa for the iPhone? Thanks!

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  • Join Us for the Next Quarterly Customer Update Webcast

    - by michelle.huff
    Join us for the next Oracle Content Management Quarterly Customer Update Webcast scheduled for this coming January 19 & 20, 2010. In this webcast we'll bring you up to speed on the latest updates and changes made available these past few months. Additionally, we'll cover the new features and certifications in the latest ODC & ODDC 10.1.3.5.1 release, as well as the upcoming Enterprise Content Management Suite 11gR1 PS3 (patch set 3) release. Register Today! Americas / EMEA time zones: Customer Update January 19, 2010 9:00am US PT / 12:00pm US ET / 17:00 London Length: 1 hour *Please use your corporate email address to register. Asia-Pacific time zones: Customer Update (Repeat Webcast) January 20, 2010 1:00pm Sydney AET, 10:00am Singapore (Jan 19, 2010 @ 6:00pm US PT) Length: 1 hour *Please use your corporate email address to register Missed Previous Customer Quarterly Updates? Get caught up on Oracle & ECM news. View a recording or the presentation from previous Webcasts held since June 2008 (available from My Oracle Support).

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