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  • validate that URI is valid http URI

    - by Alfred
    Hi all, My problem: First of hopefully this is not a duplicate, but I could not find the right answer(right away). I would like to validate that an URI(http) is valid in Java. I came up with the following tests but I can't get them to pass. First I used getPort(), but then http://www.google.nl will return -1 on getPort(). This are the test I want to have passed Test: @Test public void testURI_Isvalid() throws Exception { assertFalse(HttpUtils.validateHTTP_URI("ttp://localhost:8080")); assertFalse(HttpUtils.validateHTTP_URI("ftp://localhost:8080")); assertFalse(HttpUtils.validateHTTP_URI("http://localhost:8a80")); assertTrue(HttpUtils.validateHTTP_URI("http://localhost:8080")); final String justWrong = "/schedule/get?uri=http://localhost:8080&time=1000000"; assertFalse(HttpUtils.validateHTTP_URI(justWrong)); assertTrue(HttpUtils.validateHTTP_URI("http://www.google.nl")); } This is what I came up with after I removed the getPort() part but this does not pass all my unit tests. Production code: public static boolean validateHTTP_URI(String uri) { final URI u; try { u = URI.create(uri); } catch (Exception e1) { return false; } return "http".equals(u.getScheme()); } This is the first test that is failing because I am no longer validating the getPort() part. Hopefully somebody can help me out. I think I am not using the right class to validate url's?? P.S: I don't want to connect to the server to validate the URI is correct. At least not yet in this step. I only want to validate scheme.

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  • Creating custom URI scheme using URI class

    - by Sorantis
    I need to create a custom URI scheme for my project. i.e urn:myprotocol:{p1}:{p2}:{p3}:{p4} - opaque representation myprotocol://{p1}/{p2}/{p3}/{p4} - hierarchical representation. How can I add my scheme to Java URI class? Or, how can I make Java URI to understand my scheme, so I could use it in my code? Concrete examples are welcome. Thanks.

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  • Invalid URI: The format of the URI could not be determined.

    - by j-t-s
    Hi ALl I keep getting this error. Invalid URI: The format of the URI could not be determined. the code I have is: Uri uri = new Uri(slct.Text); if (DeleteFileOnServer(uri)) { nn.BalloonTipText = slct.Text + " has been deleted."; nn.ShowBalloonTip(30); } What gives? How is that not a valid URI format? It's plain text.

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  • How to create a Uri instance parsed with GenericUriParserOptions.DontCompressPath

    - by Andrew Arnott
    When the .NET System.Uri class parses strings it performs some normalization on the input, such as lower-casing the scheme and hostname. It also trims trailing periods from each path segment. This latter feature is fatal to OpenID applications because some OpenIDs (like those issued from Yahoo) include base64 encoded path segments which may end with a period. How can I disable this period-trimming behavior of the Uri class? Registering my own scheme using UriParser.Register with a parser initialized with GenericUriParserOptions.DontCompressPath avoids the period trimming, and some other operations that are also undesirable for OpenID. But I cannot register a new parser for existing schemes like HTTP and HTTPS, which I must do for OpenIDs. Another approach I tried was registering my own new scheme, and programming the custom parser to change the scheme back to the standard HTTP(s) schemes as part of parsing: public class MyUriParser : GenericUriParser { private string actualScheme; public MyUriParser(string actualScheme) : base(GenericUriParserOptions.DontCompressPath) { this.actualScheme = actualScheme.ToLowerInvariant(); } protected override string GetComponents(Uri uri, UriComponents components, UriFormat format) { string result = base.GetComponents(uri, components, format); // Substitute our actual desired scheme in the string if it's in there. if ((components & UriComponents.Scheme) != 0) { string registeredScheme = base.GetComponents(uri, UriComponents.Scheme, format); result = this.actualScheme + result.Substring(registeredScheme.Length); } return result; } } class Program { static void Main(string[] args) { UriParser.Register(new MyUriParser("http"), "httpx", 80); UriParser.Register(new MyUriParser("https"), "httpsx", 443); Uri z = new Uri("httpsx://me.yahoo.com/b./c.#adf"); var req = (HttpWebRequest)WebRequest.Create(z); req.GetResponse(); } } This actually almost works. The Uri instance reports https instead of httpsx everywhere -- except the Uri.Scheme property itself. That's a problem when you pass this Uri instance to the HttpWebRequest to send a request to this address. Apparently it checks the Scheme property and doesn't recognize it as 'https' because it just sends plaintext to the 443 port instead of SSL. I'm happy for any solution that: Preserves trailing periods in path segments in Uri.Path Includes these periods in outgoing HTTP requests. Ideally works with under ASP.NET medium trust (but not absolutely necessary).

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  • Uri for bitmap in subfolder (c# wpf)

    - by the empirical programmer
    I have a wpf app where I'm using an image. To reference the image I use: Uri uri = new Uri("pack://application:,,,/assemblyName;Component/myIcon.png"); BitmapImage(uri) If I add the png directly under the csproj file (with its properties BuildAction=Resource) then it works fine. But I want to move it to a subfolder under the csproj. Another SO question asked about bitmaps\uri's (857732) and an answer linked to this msdn. So I tried : Uri uri = new Uri("pack://application:,,,/assemblyName;Component/Icons/myIcon.png"); But that did not work. Any ideas?

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  • Change default application of a URI scheme in Google Chrome

    - by KiL
    I accidentally make Pidgin the default app for Yahoo Messenger URI scheme (ymsgr://) in Google Chrome. Now, whenever I click on a Yahoo Messenger URI scheme, instead of appearing a popup chat box, nothing happens. How can I change the default app to associate with this URI scheme back to Yahoo Messenger? I found a similar problem here. But I am using Windows 7, not Ubuntu, so the solution cannot be applied in my situation.

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  • Literal ampersands in System.Uri query string

    - by Nathan Baulch
    I'm working on a client app that uses a restful service to look up companies by name. It's important that I'm able to include literal ampersands in my queries since this character is quite common in company names. However whenever I pass %26 (the URI escaped ampersand character) to System.Uri, it converts it back to a regular ampersand character! On closer inspection, the only two characters that aren't converted back are hash (%23) and percent (%25). Lets say I want to search for a company named "Pierce & Pierce": var endPoint = "http://localhost/companies?where=Name eq '{0}'"; var name = "Pierce & Pierce"; Console.WriteLine(new Uri(string.Format(endPoint, name))); Console.WriteLine(new Uri(string.Format(endPoint, Uri.EscapeUriString(name)))); Console.WriteLine(new Uri(string.Format(endPoint, Uri.EscapeDataString(name)))); All three of the above combinations return: http://localhost/companies?where=Name eq 'Pierce & Pierce' This causes errors on the server side since the ampersand is (correctly) interpreted as a query arg delimiter. What I really need it to return is the original string: http://localhost/companies?where=Name eq 'Pierce %26 Pierce' How can I work around this behavior without discarding System.Uri entirely? I can't replace all ampersands with %26 at the last moment because there will usually be multiple query args involved and I don't want to destroy their delimiters. Note: A similar problem was discussed in this question but I'm specifically referring to System.Uri.

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  • geographic location uri scheme

    - by diciu
    I'd like to use a URI scheme to enable the users of one of my apps to share geographic locations. I don't want to invent my own URI scheme and "geo" seems the most appropriate but there are only two Internet Drafts on the subject (draft-mayrhofer-geo-uri-01, draft-mayrhofer-geo-uri-02), both expired and wildly different in the way they approach the standard. Is there an URI that's suited for encoding latitude and longitude and that made it as an RFC? Should I use a generic URI such as the tag URI scheme?

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  • How to open a file URI in C#?

    - by roshan
    Here's the code snippet String str= ??????? // I want to assign c:/my/test.html to this string Uri uri= new Uri (str); Stream src = Application.GetContentStream(uri).Stream; What's the correct way to do this? I'm getting "URI not relative" Exception thrown

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  • HAProxy reqrep remove URI on backend request

    - by Jim
    real quick question regarding HAProxy reqrep. I am trying to rewrite/replace the request that gets sent to the backend. I have the following example domain and URIs http://domain/web1 http://domain/web2 I want web1 to go to backend webfarm1, and web2 to go to webfarm2. Currently this does happen. However I want to strip off the web1 or web2 URI when the request is sent to the backend. Here is my haproxy.cfg frontend webVIP_80 mode http bind :80 #acl routing to backend acl web1_path path_beg /web1 acl web2_path path_beg /web2 #which backend use_backend webfarm1 if web1_path use_backend webfarm2 if web2_path default_backend webfarm1 backend webfarm1 mode http reqrep ^([^\ ]*)\ /web1/(.*) \1\ /\2 balance roundrobin option httpchk HEAD /index HTTP/1.1\r\nHost:\ example.com server webtest1 10.0.0.10:80 weight 5 check slowstart 5000ms server webtest2 10.0.0.20:80 weight 5 check slowstart 5000ms backend webfarm2 mode http reqrep ^([^\ ]*)\ /web2/(.*) \1\ /\2 balance roundrobin option httpchk HEAD /index HTTP/1.1\r\nHost:\ example.com server webtest1-farm2 10.0.0.110:80 weight 5 check slowstart 5000ms server webtest2-farm2 10.0.0.120:80 weight 5 check slowstart 5000ms If I go to http://domain/web1 or http://domain/web2 I see it in the error logs that the request on a server in each backend that the requst is for the resource /web1 or /web2 respectively. Therefore I believe there to be something wrong with my regular expression, even though I copied and pasted it from the Documentation. http://code.google.com/p/haproxy-docs/wiki/reqrep Summary: I'm trying to route traffic based on URI, however I want to strip the URI on the backend side. Go to http://domain/web1 -- backend request of / to webfarm1 Thank you! -Jim

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  • nginx configuration for URL URI paths

    - by hachiari
    I want to switch my webserver from apache to nginx however I have difficulties in converting my current htaccess to nginx configuration the conditions that I need: I want everything to be like apache, it can read file such as js, css, jpg, png ,etc I am currently using CodeIgniter PHP frameword, it uses the URI system thingy... So my htaccess configuration for CodeIgniter URI is: RewriteEngine On RewriteBase / RewriteCond %{REQUEST_URI} ^system.* RewriteRule ^(.*)$ /index.php/$1 [L] RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php/$1 [L] RewriteCond %{HTTP_HOST} ^www.domain.tld [NC] RewriteRule ^(.*)$ hxtp://domain.tld/$1 [L,R=301] I am also using minify to compress my css and js files, so the way I call my css and js is like: hxtp://domain.tld/?=css hxtp://domain.tld/?=js I tried some configurations from the net, but I could only solve problem no 2 Thank You

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  • How to supply parameters in URI schema?

    - by abhishekgarg
    I just started working with URI schema and successfully created one in Windows and Linux as well, but I am not able to parse any parameters to it. In Linux I am trying to open a file "test.py" in gedit, so for schema part I used these commands: gconftool -2 -t string /desktop/gnome/url-handlers/geditapp/command "gedit %s" gconftool -2 -t bool/desktop/gnome/url-handlers/geditapp/enabled true This is creating the URI protocol and I'm able to open the application with the Web-browser, but its not taking the parameters for the file I want to open, so I'm using the following command: <a href="geditapp:/opt/test/myfile.py">open</a> Which opens the gedit but without the file. Can someone please help me with this?

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  • php URI troube with if statement,

    - by sea_1987
    I am running an if statement, that looks like this, if($this->uri->segment(1) !== 'search' || $this->uri->segment(1) !== 'employment') { //dome something } My problem is that first condition works, if the uri segment 1 equals search then the method do not run however if I on the page employment, and the first segment of the uri is employment then the condition still runs, why is this?

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  • Finding out all about Android Uri class - use and purpose

    - by Peter vdL
    Does anyone have some helpful links to find out about Android Uri's? For example, you get a Uri back from a "take a picture" Intent. What does a URI look like and how do you use it. Why are they used instead of filenames or file handles? The Dev documentation on the Uri class is practically worthless. http://developer.android.com/reference/android/net/Uri.html It is only clear if you already know exactly what it is, and how to use it. Thanks for any links.

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  • URI Scheme, launch program in its directory

    - by ZaKlaus
    I have registered URI scheme for my app. When I open it with "Run.." or in browser, it runs in hosted directory. For ex. Ive opened url in webpage, program's working dir is in browser. What I want? I want to run program test.exe located at C:\data\test.exe and to use dir. C:\data so it could use other data in relative path. so test.exe would access file .\file.txt without using absolute path Hope I wrote it understandable, sorry for bad English.

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  • TFS 2010 SDK: Connecting to TFS 2010 Programmatically&ndash;Part 1

    - by Tarun Arora
    Technorati Tags: Team Foundation Server 2010,TFS 2010 SDK,TFS API,TFS Programming,TFS ALM   Download Working Demo Great! You have reached that point where you would like to extend TFS 2010. The first step is to connect to TFS programmatically. 1. Download TFS 2010 SDK => http://visualstudiogallery.msdn.microsoft.com/25622469-19d8-4959-8e5c-4025d1c9183d?SRC=VSIDE 2. Alternatively you can also download this from the visual studio extension manager 3. Create a new Windows Forms Application project and add reference to TFS Common and client dlls Note - If Microsoft.TeamFoundation.Client and Microsoft.TeamFoundation.Common do not appear on the .NET tab of the References dialog box, use the Browse tab to add the assemblies. You can find them at %ProgramFiles%\Microsoft Visual Studio 10.0\Common7\IDE\ReferenceAssemblies\v2.0. using Microsoft.TeamFoundation.Client; using Microsoft.TeamFoundation.Framework.Client; using Microsoft.TeamFoundation.Framework.Common;   4. There are several ways to connect to TFS, the two classes of interest are, Option 1 – Class – TfsTeamProjectCollectionClass namespace Microsoft.TeamFoundation.Client { public class TfsTeamProjectCollection : TfsConnection { public TfsTeamProjectCollection(RegisteredProjectCollection projectCollection); public TfsTeamProjectCollection(Uri uri); public TfsTeamProjectCollection(RegisteredProjectCollection projectCollection, IdentityDescriptor identityToImpersonate); public TfsTeamProjectCollection(Uri uri, ICredentials credentials); public TfsTeamProjectCollection(Uri uri, ICredentialsProvider credentialsProvider); public TfsTeamProjectCollection(Uri uri, IdentityDescriptor identityToImpersonate); public TfsTeamProjectCollection(RegisteredProjectCollection projectCollection, ICredentials credentials, ICredentialsProvider credentialsProvider); public TfsTeamProjectCollection(Uri uri, ICredentials credentials, ICredentialsProvider credentialsProvider); public TfsTeamProjectCollection(RegisteredProjectCollection projectCollection, ICredentials credentials, ICredentialsProvider credentialsProvider, IdentityDescriptor identityToImpersonate); public TfsTeamProjectCollection(Uri uri, ICredentials credentials, ICredentialsProvider credentialsProvider, IdentityDescriptor identityToImpersonate); public override CatalogNode CatalogNode { get; } public TfsConfigurationServer ConfigurationServer { get; internal set; } public override string Name { get; } public static Uri GetFullyQualifiedUriForName(string name); protected override object GetServiceInstance(Type serviceType, object serviceInstance); protected override object InitializeTeamFoundationObject(string fullName, object instance); } } Option 2 – Class – TfsConfigurationServer namespace Microsoft.TeamFoundation.Client { public class TfsConfigurationServer : TfsConnection { public TfsConfigurationServer(RegisteredConfigurationServer application); public TfsConfigurationServer(Uri uri); public TfsConfigurationServer(RegisteredConfigurationServer application, IdentityDescriptor identityToImpersonate); public TfsConfigurationServer(Uri uri, ICredentials credentials); public TfsConfigurationServer(Uri uri, ICredentialsProvider credentialsProvider); public TfsConfigurationServer(Uri uri, IdentityDescriptor identityToImpersonate); public TfsConfigurationServer(RegisteredConfigurationServer application, ICredentials credentials, ICredentialsProvider credentialsProvider); public TfsConfigurationServer(Uri uri, ICredentials credentials, ICredentialsProvider credentialsProvider); public TfsConfigurationServer(RegisteredConfigurationServer application, ICredentials credentials, ICredentialsProvider credentialsProvider, IdentityDescriptor identityToImpersonate); public TfsConfigurationServer(Uri uri, ICredentials credentials, ICredentialsProvider credentialsProvider, IdentityDescriptor identityToImpersonate); public override CatalogNode CatalogNode { get; } public override string Name { get; } protected override object GetServiceInstance(Type serviceType, object serviceInstance); public TfsTeamProjectCollection GetTeamProjectCollection(Guid collectionId); protected override object InitializeTeamFoundationObject(string fullName, object instance); } }   Note – The TeamFoundationServer class is obsolete. Use the TfsTeamProjectCollection or TfsConfigurationServer classes to talk to a 2010 Team Foundation Server. In order to talk to a 2005 or 2008 Team Foundation Server use the TfsTeamProjectCollection class. 5. Sample code for programmatically connecting to TFS 2010 using the TFS 2010 API How do i know what the URI of my TFS server is, Note – You need to be have Team Project Collection view details permission in order to connect, expect to receive an authorization failure message if you do not have sufficient permissions. Case 1: Connect by Uri string _myUri = @"https://tfs.codeplex.com:443/tfs/tfs30"; TfsConfigurationServer configurationServer = TfsConfigurationServerFactory.GetConfigurationServer(new Uri(_myUri)); Case 2: Connect by Uri, prompt for credentials string _myUri = @"https://tfs.codeplex.com:443/tfs/tfs30"; TfsConfigurationServer configurationServer = TfsConfigurationServerFactory.GetConfigurationServer(new Uri(_myUri), new UICredentialsProvider()); configurationServer.EnsureAuthenticated(); Case 3: Connect by Uri, custom credentials In order to use this method of connectivity you need to implement the interface ICredentailsProvider public class ConnectByImplementingCredentialsProvider : ICredentialsProvider { public ICredentials GetCredentials(Uri uri, ICredentials iCredentials) { return new NetworkCredential("UserName", "Password", "Domain"); } public void NotifyCredentialsAuthenticated(Uri uri) { throw new ApplicationException("Unable to authenticate"); } } And now consume the implementation of the interface, string _myUri = @"https://tfs.codeplex.com:443/tfs/tfs30"; ConnectByImplementingCredentialsProvider connect = new ConnectByImplementingCredentialsProvider(); ICredentials iCred = new NetworkCredential("UserName", "Password", "Domain"); connect.GetCredentials(new Uri(_myUri), iCred); TfsConfigurationServer configurationServer = TfsConfigurationServerFactory.GetConfigurationServer(new Uri(_myUri), connect); configurationServer.EnsureAuthenticated();   6. Programmatically query TFS 2010 using the TFS SDK for all Team Project Collections and retrieve all Team Projects and output the display name and description of each team project. CatalogNode catalogNode = configurationServer.CatalogNode; ReadOnlyCollection<CatalogNode> tpcNodes = catalogNode.QueryChildren( new Guid[] { CatalogResourceTypes.ProjectCollection }, false, CatalogQueryOptions.None); // tpc = Team Project Collection foreach (CatalogNode tpcNode in tpcNodes) { Guid tpcId = new Guid(tpcNode.Resource.Properties["InstanceId"]); TfsTeamProjectCollection tpc = configurationServer.GetTeamProjectCollection(tpcId); // Get catalog of tp = 'Team Projects' for the tpc = 'Team Project Collection' var tpNodes = tpcNode.QueryChildren( new Guid[] { CatalogResourceTypes.TeamProject }, false, CatalogQueryOptions.None); foreach (var p in tpNodes) { Debug.Write(Environment.NewLine + " Team Project : " + p.Resource.DisplayName + " - " + p.Resource.Description + Environment.NewLine); } }   Output   You can download a working demo that uses TFS SDK 2010 to programmatically connect to TFS 2010. Screen Shots of the attached demo application, Share this post :

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  • Linking to a chat room via XMPP: URI

    - by Coderer
    I found out how to link directly to a chat room on a Jabber conference server -- it took a bit of digging, and I wound up actually looking at the spec before I was sure I was doing it right. I confirmed here, so I'm pretty sure I've got it. The results, though, are puzzling. If I click a link of the style xmpp:[email protected] I get a new chat session with user "dude" at example.com, as expected. If I tack on a nonsense query (xmpp:[email protected]?foobar), it's ignored, which is what the spec says should happen. However, if I use xmpp:[email protected]?join, as in the link above, nothing happens. I dug a little deeper, and found out that on my (Linux) system, xmpp URIs are handled via purple-url-handler, so I dropped to a terminal and ran it manually. The result was that any xmpp URI ran fine except one that includes a ?join query. The ?join query results in a dbus crash, pointing specifically to line 2356 of dbus-message.c -- a little Googling suggests this probably is dbus's less-than-elegant way of telling me that somebody is using dbus incorrectly. Am I crafting my link correctly? Is this an OS or maybe application issue? Does this work on other platforms / browsers / etc? More importantly, is there any easy way to fix it?

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  • Difference between URI and URL

    - by Sarfraz
    If you read the documentation of CodeIgniter or Kohana, there is a lot of confusion about the usage of URI and URL. Sometimes they use one and other times the other. They also incorporate URI class which makes it easier working with URLs. I know that: URI stands for Uniform Resource Identifier URL stands for Uniform Resource Locator But that doesn't make much sense. What exactly is the difference? or are they same?

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  • Normalizing URI to make it work correctly with MakeRelativeUri

    - by dr. evil
    Dim x AS New URI("http://www.example.com/test//test.asp") Dim rel AS New URI("http://www.example.com/xxx/xxx.asp") Console.Writeline(x.MakeRelativeUri(rel).Tostring()) In here output is: ../../xxx/xxx.asp Which looks correct almost all web servers will process the two of the following as same request: http://www.example.com/test//test.asp http://www.example.com/test/test.asp What's the best way to fix this behaviour is there any API to do this, or shall manually create a new URI and remove all // in the path?

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  • Ruby open-uri open method loses file extension opening images

    - by Jimmy
    I'm using ruby 1.9.2 along with Rails 3.1.4 and Paperclip 2.4.5. My issue is trying to save a paperclip attachment from a URI loses the file extension and saves the file without one resulting in issues with things like fancybox that require an extension. Some example code: uri = "http://featherfiles.aviary.com/2012-06-13/bbe5f0de1/0c5a672b88ea47ecb4631ac173e27430.png" open(uri) #=> #<File:/var/folders/zc/d69gxhzx10x_bvjrkqgyjgxr0000gn/T/open-uri20120613-27204-i6cldv> Because there is no extension on the temp file paperclip is saving the file without one resulting in issues. Has anyone run into this issue? I've seen multiple answers about using paperclip to store images from a URI but none seem to address the same problem we're running

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  • Incorrect new Uri(base, relative) behaviour in .NET

    - by dr. evil
    When you create a new Uri like this: New Uri(New Uri("http://example.com/test.php"),"?x=y") it returns: http://example.com/?x=y It was supposed to return: http://example.com/test.php?x=y according to the every major browser out there (I'm not quite sure what RFC says though). Is this is a bug or is there any other function out there which behaves correctly, also what's the best way to fix it without reinventing the wheel?

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  • System.Uri can't parse when password field contains a "#"

    - by Andrew
    The following code throws System.UriFormatException: var uri = new UriBuilder("ftp://user:pass#[email protected]:21/fu/bar.zip"); System.UriFormatException: Invalid URI: A port was expected because of there is a colon (':') present but the port could not be parsed. Removing the # symbol from the password field solves the issue. Is a # symbol a valid character to have in the password field? Is there a way to escape this? Is this a known bug in the parsing routine of the Uri class? How does one get around this - assuming you can't change the password? ;-) Thanks, Andrew

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  • JavaScript: catching URI change

    - by ptrn
    I have a site where I'm using hash based parameters, eg. http://url.of.site/#param1=123 What I want When the user manually changes the URI to eg. http://url.of.site/#param1=789 When the user enters this URI, the event is caught by the JavaScript, and the appropriate functions are called. Basically, what I'm wondering about is; is there an event listener for this? Or would I have to periodically check the URI to see if it has been changed? I'm already using the current jQuery API, if that helps. _L

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  • Java File URI error ?

    - by Frank
    I need to get a file object online, and I know the file is located at : http://nmjava.com/Dir_App_IDs/Dir_GlassPaneDemo/GlassPaneDemo_2010_04_06_15_00_SNGRGLJAMX If I paste it into my browser's url, I'll be able to download this file, now I'm trying to get it with Java, my code looks like this : String File_Url="http://nmjava.com/Dir_App_IDs/Dir_GlassPaneDemo/GlassPaneDemo_2010_04_06_15_00_SNGRGLJAMX"; Object myObject=Get_Online_File(new URI(File_Url)); Object Get_Online_File(URI File_Uri) throws IOException { return readObject(new ObjectInputStream(new FileInputStream(new File(File_Uri)))); } public static synchronized Object readObject(ObjectInput in) throws IOException { Object o; ...... return o; } But I got the following error message : java.lang.IllegalArgumentException: URI scheme is not "file" at java.io.File.<init>(File.java:366) Why ? How to fix it ? Frank

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