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  • jQuery date calculator - show/hide IMG

    - by utopicam
    I have a problem with the following code. I tried changing many things (symbols, classes, imgs in the code) but this is killing me and I have no idea how to fix it. Sorry it's so specific, when solved I'll change the title to something more useful. I have two images. My jquery has to calculate the day and show one image or the other depending on that (using a class with display:none). My month has 24 days (it's a xmas thing). This is what I have so far: <script type="text/javascript"> $(document).ready(function(){ var currentTime = new Date() var day = currentTime.getDate(); if (day > 24){ day = 1; } $(".calDate").each(function(){ var curDate = $(this).attr("date"); if (curDate < day){ $(this).addClass("xMasPast"); } else if(curDate==day){ $(this).addClass("xMasActive"); } else { $(this).addClass("xMasInactive"); } }); $(".calDate2").each(function(){ var curDate = $(this).attr("date"); if (curDate > day){ $(this).addClass("xMasInactive"); } else if(curDate==day){ $(this).addClass("xMasActive"); } else { $(this).addClass("xMasActive"); } }); }); </script> But it's showing all the images. What am I missing? (any ideas on making the code simpler are more than welcomed). Thanks for your help! Update: simplified HTML <div><img src="day21.png" which="21"/></a></div> <img id="bola21" class="calDate2" src="day21.png"/>

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