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  • Zend Framework - Zend Tool - Module error: I have error after I create module with Zend Tool

    - by Yosef
    Hi, I new in zend framework. I create zend project with zend tool and its works , but i create module and when i try access him with browser I get Error. I write my steps, please help me. Thanks, Yosef My steps: $ sudo zf create project mystore put Zend library inside library test: http://localhost/mystore/public/ (working) Add module store (not working) $ sudo zf create module store add to application.ini path to modules resources.frontController.moduleDirectory = APPLICATION_PATH "/modules" resources.modules = "" test1: http://localhost/mystore/public/store/ test2: http://localhost/mystore/public/store/public/ test3: http://localhost/mystore/public/modules/store/public/ test1+2+3 result: An error occurred Page not found Exception information: Message: Invalid controller specified (index.php) Stack trace: #0 /var/www/mystore/library/Zend/Controller/Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #1 /var/www/mystore/library/Zend/Application/Bootstrap/Bootstrap.php(97): Zend_Controller_Front->dispatch() #2 /var/www/mystore/library/Zend/Application.php(366): Zend_Application_Bootstrap_Bootstrap->run() #3 /var/www/mystore/public/index.php(25): Zend_Application->run() #4 {main} Request Parameters: array ( 'module' => 'store', 'controller' => 'index.php', 'action' => 'index', )

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  • Zend Pdf generation from an action

    - by Nisanth
    Hi all, I have a controller Employee , in that i have the action detail . The detail action prints like the attached image. Suppose there is a save pdf button, i need to print this page as .pdf.. How can i do this ? Pls help me Thanks in advance Nisanth

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  • Encoding Problem with Zend Navigation using Zend Translate Spanish in XMLTPX File Special Characters

    - by Routy
    Hello, I have been attempting to use Zend Translate to display translated menu items to the user. It works fine until I introduce special characters into the translation files. I instantiate the Zend_Translate object in my bootstrap and pass it in as a translator into Zend_Navigation: $translate = new Zend_Translate( array('adapter' => 'tmx', 'content' => APPLICATION_PATH .'/languages/translation.tmx', 'locale' => 'es' ) ); $navigation->setUseTranslator($translate); I have used several different adapters (array,tmx) in order to see if that made a difference. I ended up with a TMX file that is encoded using ISO-8859-1 (otherwise that throws an XML parse error when introducing the menu item "Administrar Applicación". <?xml version="1.0" encoding="ISO-8859-1"?> <!DOCTYPE tmx SYSTEM "tmx14.dtd"> <tmx version="1.4"> <header creationtoolversion="1.0.0" datatype="tbx" segtype="sentence" adminlang="en" srclang="en" o-tmf="unknown" creationtool="XYZTool" > </header> <body> <tu tuid='link_signout'> <tuv xml:lang="en"><seg>Sign Out</seg></tuv> <tuv xml:lang="es"><seg>Salir</seg></tuv> </tu> <tu tuid='link_signin'> <tuv xml:lang="en"><seg>Login</seg></tuv> <tuv xml:lang="es"><seg>Acceder</seg></tuv> </tu> <tu tuid='Manage Application'> <tuv xml:lang="en"><seg>Manage Application</seg></tuv> <tuv xml:lang="es"><seg>Administrar Applicación</seg></tuv> </tu> </body> </tmx> Once I display the menu in the layout: echo $this->navigation()->menu(); It will display all menu items just fine, EXCEPT the one using special characters. It will simply be blank. NOW - If I use PHP's UTF8-encode inside of the zend framework class 'Menu' which I DO NOT want to do: Line 215 in Zend_View_Helper_Navigation_Menu: if ($this->getUseTranslator() && $t = $this->getTranslator()) { if (is_string($label) && !empty($label)) { $label = utf8_encode($t->translate($label)); } if (is_string($title) && !empty($title)) { $title = utf8_encode($t->translate($title)); } } Then it works. The menu item display correctly and all is joyful. The thing is, I do not want to modify the library. Is there some kind of an encoding setting in either zend translate or zend navigation that I am not finding? Please Help! Zend Library Version: 1.11

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  • Get all model details in zend.

    - by Prasanth P
    Hi, I have one doubt in zend framework. I need all model details from project which i have done in zend framework. Is there any possibility to get all model details in zend framework. Please help me.. Thanks and regards, Prasanth P

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  • Installing Zend on CentOS is having dependency issues

    - by rax
    I'm trying to install PHP's Zend Server on my CentOS VPS but it's having dependency issues that I can't seem to resolve. zend-server-php-5.2-4.0-73.noarch from Zend_noarch has depsolving problems --> Missing Dependency: php-5.2-gui-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) zend-server-php-5.2-4.0-73.noarch from Zend_noarch has depsolving problems --> Missing Dependency: php-5.2-dev-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) knowledgetree-ce-3.7.0-2.noarch from KTnoarch has depsolving problems --> Missing Dependency: php-5.2-xmlrpc-zend-server is needed by package knowledgetree-ce-3.7.0-2.noarch (KTnoarch) knowledgetree-ce-3.7.0-2.noarch from KTnoarch has depsolving problems --> Missing Dependency: php-5.2-fileinfo-zend-server is needed by package knowledgetree-ce-3.7.0-2.noarch (KTnoarch) zend-server-php-5.2-4.0-73.noarch from Zend_noarch has depsolving problems --> Missing Dependency: php-5.2-zend-extensions is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) zend-server-php-5.2-4.0-73.noarch from Zend_noarch has depsolving problems --> Missing Dependency: php-5.2-common-extensions-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) Error: Missing Dependency: php-5.2-fileinfo-zend-server is needed by package knowledgetree-ce-3.7.0-2.noarch (KTnoarch) Error: Missing Dependency: php-5.2-xmlrpc-zend-server is needed by package knowledgetree-ce-3.7.0-2.noarch (KTnoarch) Error: Missing Dependency: php-5.2-gui-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) Error: Missing Dependency: php-5.2-common-extensions-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) Error: Missing Dependency: php-5.2-dev-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) Error: Missing Dependency: php-5.2-zend-extensions is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) When consulting the Google, all I get told is how to install PHP 5.2.* on CentOS. According to the output of php -v, I've done that. PHP 5.2.8 (cli) (built: Sep 28 2009 15:37:15) Copyright (c) 1997-2008 The PHP Group Zend Engine v2.2.0, Copyright (c) 1998-2008 Zend Technologies with the ionCube PHP Loader v3.1.34, Copyright (c) 2002-2009, by ionCube Ltd. How can I solve this issue?

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  • Installing Zend on CentOS is having dependency issues

    - by rax
    I'm trying to install PHP's Zend Server on my CentOS VPS but it's having dependency issues that I can't seem to resolve. zend-server-php-5.2-4.0-73.noarch from Zend_noarch has depsolving problems --> Missing Dependency: php-5.2-gui-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) zend-server-php-5.2-4.0-73.noarch from Zend_noarch has depsolving problems --> Missing Dependency: php-5.2-dev-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) knowledgetree-ce-3.7.0-2.noarch from KTnoarch has depsolving problems --> Missing Dependency: php-5.2-xmlrpc-zend-server is needed by package knowledgetree-ce-3.7.0-2.noarch (KTnoarch) knowledgetree-ce-3.7.0-2.noarch from KTnoarch has depsolving problems --> Missing Dependency: php-5.2-fileinfo-zend-server is needed by package knowledgetree-ce-3.7.0-2.noarch (KTnoarch) zend-server-php-5.2-4.0-73.noarch from Zend_noarch has depsolving problems --> Missing Dependency: php-5.2-zend-extensions is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) zend-server-php-5.2-4.0-73.noarch from Zend_noarch has depsolving problems --> Missing Dependency: php-5.2-common-extensions-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) Error: Missing Dependency: php-5.2-fileinfo-zend-server is needed by package knowledgetree-ce-3.7.0-2.noarch (KTnoarch) Error: Missing Dependency: php-5.2-xmlrpc-zend-server is needed by package knowledgetree-ce-3.7.0-2.noarch (KTnoarch) Error: Missing Dependency: php-5.2-gui-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) Error: Missing Dependency: php-5.2-common-extensions-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) Error: Missing Dependency: php-5.2-dev-zend-server is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) Error: Missing Dependency: php-5.2-zend-extensions is needed by package zend-server-php-5.2-4.0-73.noarch (Zend_noarch) When consulting the Google, all I get told is how to install PHP 5.2.* on CentOS. According to the output of php -v, I've done that. PHP 5.2.8 (cli) (built: Sep 28 2009 15:37:15) Copyright (c) 1997-2008 The PHP Group Zend Engine v2.2.0, Copyright (c) 1998-2008 Zend Technologies with the ionCube PHP Loader v3.1.34, Copyright (c) 2002-2009, by ionCube Ltd. How can I solve this issue?

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  • ACL implementation

    - by Kirzilla
    First question Please, could you explain me how simpliest ACL could be implemented in MVC. Here is the first approach of using Acl in Controller... <?php class MyController extends Controller { public function myMethod() { //It is just abstract code $acl = new Acl(); $acl->setController('MyController'); $acl->setMethod('myMethod'); $acl->getRole(); if (!$acl->allowed()) die("You're not allowed to do it!"); ... } } ?> It is very bad approach, and it's minus is that we have to add Acl piece of code into each controller's method, but we don't need any additional dependencies! Next approach is to make all controller's methods private and add ACL code into controller's __call method. <?php class MyController extends Controller { private function myMethod() { ... } public function __call($name, $params) { //It is just abstract code $acl = new Acl(); $acl->setController(__CLASS__); $acl->setMethod($name); $acl->getRole(); if (!$acl->allowed()) die("You're not allowed to do it!"); ... } } ?> It is better than previous code, but main minuses are... All controller's methods should be private We have to add ACL code into each controller's __call method. The next approach is to put Acl code into parent Controller, but we still need to keep all child controller's methods private. What is the solution? And what is the best practice? Where should I call Acl functions to decide allow or disallow method to be executed. Second question Second question is about getting role using Acl. Let's imagine that we have guests, users and user's friends. User have restricted access to viewing his profile that only friends can view it. All guests can't view this user's profile. So, here is the logic.. we have to ensure that method being called is profile we have to detect owner of this profile we have to detect is viewer is owner of this profile or no we have to read restriction rules about this profile we have to decide execute or not execute profile method The main question is about detecting owner of profile. We can detect who is owner of profile only executing model's method $model-getOwner(), but Acl do not have access to model. How can we implement this? I hope that my thoughts are clear. Sorry for my English. Thank you.

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  • ZF2 Zend\Db Insert/Update Using Mysql Expression (Zend\Db\Sql\Expression?)

    - by Aleross
    Is there any way to include MySQL expressions like NOW() in the current build of ZF2 (2.0.0beta4) through Zend\Db and/or TableGateway insert()/update() statements? Here is a related post on the mailing list, though it hasn't been answered: http://zend-framework-community.634137.n4.nabble.com/Zend-Db-Expr-and-Transactions-in-ZF2-Db-td4472944.html It appears that ZF1 used something like: $data = array( 'update_time' => new \Zend\Db\Expr("NOW()") ); And after looking through Zend\Db\Sql\Expression I tried: $data = array( 'update_time' => new \Zend\Db\Sql\Expression("NOW()"), ); But get the following error: Catchable fatal error: Object of class Zend\Db\Sql\Expression could not be converted to string in /var/www/vendor/ZF2/library/Zend/Db/Adapter/Driver/Pdo/Statement.php on line 256 As recommended here: http://zend-framework-community.634137.n4.nabble.com/ZF2-beta3-Zend-Db-Sql-Insert-new-Expression-now-td4536197.html I'm currently just setting the date with PHP code, but I'd rather use the MySQL server as the single source of truth for date/times. $data = array( 'update_time' => date('Y-m-d H:i:s'), ); Thanks, I appreciate any input!

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  • Zend Framework, Zend_Form_Element how to set custom name?

    - by ikso
    Hello, I have form, where some fields are looks like rows, so I can add/delete them using JS. For example: Field with ID=1 (existing row) <input id="id[1]" type="text" name="id[1]" value="1" /> <input id="name[1]" type="text" name="name[1]" value="100" /> Field with ID=2 (existing row) <input id="name[2]" type="text" name="name[2]" value="200" /> <input id="name[2]" type="text" name="name[2]" value="200" /> new row created by default (to allow add one more row to existing rows) <input id="id[n0]" type="text" name="id[n0]" value="" /> <input id="name[n0]" type="text" name="name[n0]" value="" /> new row created by JS <input id="id[n1]" type="text" name="id[n1]" value="" /> <input id="name[n1]" type="text" name="name[n1]" value="" /> So than we will proceed form, we will know what rows to update and what to add (if index starts with "n" - new, if index is number - existent element). I tried subforms... but do I have to create subform for each field? If I use following code: $subForm = new Zend_Form_SubForm(); $subForm->addElement('Text', 'n0'); $this->addSubForm($subForm, 'pid'); $subForm = new Zend_Form_SubForm(); $subForm->addElement('Text', 'n0'); $this->addSubForm($subForm, 'name'); What is the best way for this? 1) Use subforms? 2) Extend Zend/Form/Decorator/ViewHelper.php to use names like name[nX]? 3) Other solutions? Thanks.

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  • How to set up Hierarchical Zend Rest Routes?

    - by Kenji Baheux
    With the Zend Framework, I am trying to build routes for a REST api on resources organized in the following pattern: http://example.org/users/ http://example.org/users/234 http://example.org/users/234/items http://example.org/users/234/items/34 How do I set up this with Zend_Rest_Route? Here is how I have setup the route for the users resource (users/:id) in my bootstrap.php file: $this->bootstrap('frontController'); $frontController = Zend_Controller_Front::getInstance(); $restRoute = new Zend_Rest_Route($frontController); $frontController->getRouter()->addRoute('default', $restRoute); [As far as I understand, this is a catch all route so users/324/items/34 would results in parameters set as id=324 and items=34 and everything would be mapped to the Users (front module) Model. From there I guess I could just test for the items parameter and retrieve the item #34 for user #324 on a get request.]<=== I just checked it and it doesn't seems to work like that: Acessing /users/234/items/43 and var_dump($this->_getAllParams()); in the get action of the rest controller results in the following output: array(4) { ["controller"]=> string(5) "users" ["action"]=> string(3) "get" [2]=> string(5) "items" ["module"]=> string(7) "default"] } Somehow both ids got lost... Anyone?

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  • Zend Form, table decorators

    - by levacjeep
    Hello, I am having an incredibly difficult time to decorate a Zend form the way I need to. This is the HTML structure I am in need of: <table> <thead><tr><th>one</th><th>two</th><th>three</th><th>four</th></thead> <tbody> <tr> <td><input type='checkbox' id='something'/></td> <td><img src='src'/></td> <td><input type='text' id='something'/></td> <td><input type='radio' group='justonegroup'/></td> </tr> <tr> <td><input type='checkbox' id='something'/></td> <td><img src='src'/></td> <td><input type='text' id='something'/></td> <td><input type='radio' group='justonegroup'/></td> </tr> </tbody> </table> The number of rows in the body is determined by my looping structure inside my form class. All ids will be unique of course. All radio buttons in the form belongs to one group. My issue really is that I am unsure how to create and then style the object Zend_Form_Element_MultiCheckbox and Zend_Form_Element_Radio inside my table. Where/how would I apply the appropriate decoraters to the checkboxes and radio buttons to have a form structure like above? My Form class so far: class Form_ManageAlbums extends Zend_Form { public function __construct($album_id) { $photos = Model_DbTable_Photos::getAlbumPhotos($album_id); $selector = new Zend_Form_Element_MultiCheckbox('selector'); $radio = new Zend_Form_Element_Radio('group'); $options = array(); while($photo = $photos->fetchObject()) { $options[$photo->id] = ''; $image = new Zend_Form_Element_Image('image'.$photo->id); $image->setImageValue('/dog/upload/'.$photo->uid.'/photo/'.$photo->src); $caption = new Zend_Form_Element_Text('caption'.$photo->id); $caption->setValue($photo->caption); $this->addElements(array($image, $caption)); } $selector->addMultiOptions($options); $radio->addMultiOptions($options); $this->addElement($selector); $this->setDecorators(array( 'FormElements', array('HtmlTag', array('tag' => 'table')), 'Form' )); } } I have tried a few combination of decoraters for the td and tr, but no success to date. Thank you for any help, very appreciated. JP Levac

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  • Zend Studio Intellisense + zend Framework

    - by Ilya Biryukov
    Hi. I've got a very annoying problem with my Zend studio. I have a zend framework project I am working on. The actual zend framework code is inside my project (in library folder) and then ZS seems to reference to its own version of zend framework. As the result, I get 2 versions of the same function/class in my intellisense which is annoying to say the least. Today I had the last drop of patience with zend studio when I showed 4 copies of the same class (imagine what's its like looking at a large namespace times 4!). So, how do I remove all references inside ZS to its own version of ZF? Thanks!

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  • Haproxy ACL for balance on URL request

    - by Elgreco08
    I'm usung Ubuntu with haproxy 1.4.13 version. Its load balancing two subdomains: app1.domain.com app2.domain.com now i want to be able to use ACL to send based on url request to the right backends For example: http://app1.domain.com/path/games/index.php sould be send to backend1 http://app1.domain.com/path/photos/index.php should be send to backend2 http://app2.domain.com/path/mail/index.php sould be send to backend3 http://app2.domain.com/path/wazap/index.php should be send to backend4 i did used the code the the following acl frontend http-farm bind 0.0.0.0:80 acl app1web hdr_beg(host) -i app1 # for http://app1.domain.com acl app2web hdr_beg(host) -i app2 # for http://app2.domain.com acl msg-url-1 url_reg ^\/path/games/.* acl msg-url-2 url_reg ^\/path/photos/.* acl msg-url-3 url_reg ^\/path/mail/.* acl msg-url-4 url_reg ^\/path/wazap/.* use_backend games if msg-url-1 app1web use_backend photos if msg-url-2 app2web use_backend mail if ..... backend games option httpchk GET /alive.php HTTP/1.1\r\nHost:\ app1.domain.com option forwardfor balance roundrobin server appsrv-1 192.168.1.10:80 check inter 2000 fall 3 server appsrv-2 192.168.1.11:80 check inter 2000 fall 3 backend photos option httpchk GET /alive.php HTTP/1.1\r\nHost:\ app2.domain.com option forwardfor balance roundrobin server appsrv-1 192.168.1.13:80 check inter 2000 fall 3 server appsrv-2 192.168.1.14:80 check inter 2000 fall 3 .... Since the path mail, photos...etc will be application pools on iis, i want to monitor them if they are alive, if the pool does not respond it should stop serving it. my problem is for sure in the regular expression in the ACL acl msg-url-4 url_reg ^\/path/wazap/.* What should i change in the ACL to make it work ? thanks for any hints

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  • NFS4 / ZFS: revert ACL to clean/inherited state

    - by Keiichi
    My problem is identical to this Windows question, but pertains NFS4 (Linux) and the underlying ZFS (OpenIndiana) we are using. We have this ZFS shared via NFS4 and CIFS for Linux and Windows users respectively. It would be nice for both user groups to benefit from ACLs, but the one missing puzzle piece goes thusly: Each user has a home, where he sets a top-level, inherited ACL. He can later on refine permissions for the contained files/folders iteratively. Over time, sometimes permissions need to be generalized again to avoid increasing pollution of ACL entries. You can tweak the ACL of every single file if need be to obtain the wanted permissions, but that defeats the purpose of inherited ACLs. So, how can an ACL be completely cleared like in the question linked above? I have found nothing about what a blank, inherited ACL should look like. This usecase simply does not seem to exist. In fact, the solaris chmod manpage clearly states A- Removes all ACEs for current ACL on file and replaces current ACL with new ACL that represents only the current mode of the file. I.e. we get three new ACL entries filled with stuff representing the permission bits, which is rather useless for cleaning up. If I try to manually remove every ACE, on the last one I get chmod A0- <file> chmod: ERROR: Can't remove all ACL entries from a file Which by the way makes me think: and why not? In fact, I really want the whole file-specific ACL gone. The same holds for linux, which enumerates ACEs starting with 1(!), and verbalizes its woes less diligently nfs4_setacl -x 1 <file> Failed setxattr operation: Unknown error 524 So, what is the idea behind ACLs under Solaris/NFS? Can they never be cleaned up? Why does the recursion option for the ACL setting commands pollute all children instead of setting a single ACL and making the children inherit? Is this really the intention of the designers? I can clean up the ACLs using a windows client perfectly well, but am I supposed to tell the linux users they have to switch OS just to consolidate permissions?

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  • Zend Date -- day difference

    - by Nisanth
    Hi All, I have the below line of codes $day1 = new Zend_Date('2010-03-01', 'YYYY-mm-dd'); $day2 = new Zend_Date('2010-03-05', 'YYYY-mm-dd'); $dateDiff = $day2->getDate()->get(Zend_Date::TIMESTAMP) - $day1->getDate()->get(Zend_Date::TIMESTAMP); $days = floor((($dateDiff / 60) / 60) / 24); return $days; this will return 4 But if gave $day1 = new Zend_Date('2010-02-28', 'YYYY-mm-dd'); $day2 = new Zend_Date('2010-03-01', 'YYYY-mm-dd'); $dateDiff = $day2->getDate()->get(Zend_Date::TIMESTAMP) - $day1->getDate()->get(Zend_Date::TIMESTAMP); $days = floor((($dateDiff / 60) / 60) / 24); return $days; it will return -27 .. how will i get right answer

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  • Zend Framework: How to include an OR statement in an SQL fetchAll()

    - by Scoobler
    I am trying to build the following SQL statement: SELECT users_table.*, users_data.first_name, users_data.last_name FROM users_table INNER JOIN users_data ON users_table.id = user_id WHERE (users_table.username LIKE '%sc%') OR (users_data.first_name LIKE '%sc%') OR (users_data.last_name LIKE '%sc%') I have the following code at the moment: public function findAllUsersLike($like) { $select = $this-select(Zend_Db_Table::SELECT_WITH_FROM_PART)-setIntegrityCheck(false); $select-where('users_table.username LIKE ?', '%'.$like.'%'); $select-where('users_data.first_name LIKE ?', '%'.$like.'%'); $select-where('users_data.last_name LIKE ?', '%'.$like.'%'); $select-join('users_data', 'users_table.id = user_id', array('first_name', 'last_name')); return $this-fetchAll($select); } This is close, but not right as it uses AND to add the extra WHERE statements, instead of OR. Is there any way to do this as one select? Or should I perform 3 selects and combine the results (alot more overhead?)? P.S. The parameter $like that is past is sanitized so don't need to wory about user input in the code above!

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  • One-to-many relationship in the same table in zend

    - by Behrang
    I have groupTable(group_id,group_name,group_date,group_parent_id) in face each group have many group child I create groupModel and I want to begin coding is this right code to handle protected $_name = 'group'; protected $_dependentTables = array('Model_group'); protected $_referenceMap = array('Model_group' = array('columns' = array('group_parent_id') , 'refTableClass' = 'Model_group' , 'refColumns' = array('group_id') , 'onDelete' = self::CASCADE , 'onUpdate' = self::RESTRICT) );

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  • Create new framework project in Zend Studio

    - by Sadee
    I hv problem in creating New Framework project on Zend Studio.I'm new to Zend Studio. Using Zend Studio ver.7.1.0. When i'm creating new zend framwork project (Zend Server is successfully installed), It will not create 'application' & 'public' folders. In my previous test project those were created automatically. But now its create only - Javascript Resources - PHP Include Path - PHP Language Library :( Some can help me? Thanx! Sadee

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  • Giving Zend Navigation Pages Multiple ACL Privileges

    - by Sonny
    I'm using Zend_Navigation and am trying to integrate it with Zend_Acl. Each page in the navigation has a privilege attribute. What I can't determine is how to define multiple privileges for a single page. Use case: A page that is for managing users. I want to display that page (in navigation) if the current signed in user's role has add, edit, or delete privileges on the Users resource. Example entry in the navigation XML: <admin_users> <label>Users</label> <route>default</route> <controller>admin</controller> <action>users</action> <resource>Users</resource> <privilege>add,edit,delete</privilege> </admin_users> Using a comma-separated list as above doesn't lend the desired behavior.

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  • Powershell Set-Acl fails

    - by Ulrich
    While working on a little backup script I try to change the ACL of a file using Set-Acl in Powershell 1 on Vista and always get the following error message: Set-Acl : The security identifier is not allowed to be the owner of this object. This error persists even if I go a minimal script: $acl = Get-Acl $sourcepath$file $acl |format-list Set-Acl -path $sourcepath$file -AclObject $acl Does anyone know the reason for this error? Obviously I'm not changing the ownership of the file... BTW: What I ultimately want to achieve is to reduce all access rights to ReadAndExecute. Is there maybe an easier way of doing this in Powershell? Thanks for your help! Ulrich

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  • Zend Studio Debugger returns Application Error

    - by Keyne
    When I run debug for my public/index.php I got an application error as output. I've seen that it occurs at this line: foreach($feed->findFeedEntries($entriesLimit) as $entry) If I put a breakpoint before this, all works as expected, I mean, the error is after the line above. If I remove findFeedEntries() method, I can perform debugging without erros. To clarify, this method is in my row object as described bellow: This is the error <?php class Model_DbTable_FeedEntries extends Zf_Db_Table { public function fetchNewEntries($feed_id) { $Feeds = new Model_DbTable_Feeds(); $Feed = $Feeds->getById($feed_id); // ERROR IS HERE! The colum doesn't exists! // And this is only on zend-debugger!!! var_dump($Feed->link) // ... } } I'm completely lost about what's happening, once my application has no errors, the problem is with zend-debugger. The error is: An error occurred Application error Exception information: Message: Specified column "link" is not in the row Stack trace: #0 C:\Program Files\xampp\htdocs\desenvolvimentistas\application\models\DbTable\FeedEntries.php(75): Zend_Db_Table_Row_Abstract->__get('link') #1 C:\Program Files\xampp\htdocs\desenvolvimentistas\application\models\DbTable\FeedEntries.php(50): Model_DbTable_FeedEntries->fetchNewEntries('1') #2 C:\Program Files\xampp\htdocs\desenvolvimentistas\application\models\DbTable\Row\Feed.php(15): Model_DbTable_FeedEntries->getAllByFeedId('1', 1) #3 C:\Program Files\xampp\htdocs\desenvolvimentistas\application\modules\default\controllers\IndexController.php(41): Model_DbTable_Row_Feed->findFeedEntries(1) #4 C:\Program Files\xampp\htdocs\ZendFramework-1.10.0-minimal\library\Zend\Controller\Action.php(513): IndexController->indexAction() #5 C:\Program Files\xampp\htdocs\ZendFramework-1.10.0-minimal\library\Zend\Controller\Dispatcher\Standard.php(289): Zend_Controller_Action->dispatch('indexAction') #6 C:\Program Files\xampp\htdocs\ZendFramework-1.10.0-minimal\library\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #7 C:\Program Files\xampp\htdocs\ZendFramework-1.10.0-minimal\library\Zend\Application\Bootstrap\Bootstrap.php(97): Zend_Controller_Front->dispatch() #8 C:\Program Files\xampp\htdocs\ZendFramework-1.10.0-minimal\library\Zend\Application.php(366): Zend_Application_Bootstrap_Bootstrap->run() #9 C:\Program Files\xampp\htdocs\desenvolvimentistas\public\index.php(54): Zend_Application->run() #10 C:\Users\RAPOSO\AppData\Local\Temp\dummy.php(1): include('C:\Program File...') #11 {main} I've notice that when I get the row object my colums names are not right. Instead of have "title", "link", ... I have "feeds", "desenvolvimentistas" (projectname), and so on...

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  • Unable to Access Zend Server 5 CE after installation

    - by jl
    I have previously installed WAMP on my windows, and now I am trying to install Zend Server 5 CE 5.3.1 Win x86. During the installation of Zend Server, there is a step asking about: web server port : 80 zend server interface port : 10081 I kept to the default. After the installation, I tried to access http://localhost,and is able to see zend test page. But I am unable to access http://localhost:10081/ZendServer, it was stated as page not found. Is it a conflict of my WAMP and the Zend Server? I remembered stopping the apache for WAMP, before trying to access ZS. Could anyone please advise me how to fix it? Thank you.

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