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  • Network message serialization for game

    - by George R
    Exit-games make a network library product called photon, and they have and actively develop a limited mmo demo. Rather than shooting off json or XML, etc. saying "MovePlayer" (with associated params), they nut that message down to a 2 digit int, via an enum - something like Operations.MovePlayer. There's no denying that a 2 digit int is smaller than a longer string, however I really hate the idea of statically burning each and every message into an enum. Would there be an alternative way to have a MessageID property assign itself a unique 2 digit int based on a lookup table or something? Has anyone dealt with this kind of thing before?

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  • Send and receive data trough the power network

    - by luvieere
    I'm not interested in a hardware solution, I want to know about software that may "read" modulated signal received trough the power supply - some sort of a low-level driver that would access the power signal in a convenient place and demodulate it. Is there a way to receive signal from the computer's power supply? I'm interested in an API or library that would allow the computer to be seen as a node in a Power Line Communication network and receive data directly through the power cable, without the need for a converter. Is there any active research in this field? Edit: There is software that reads monitors and displays internal component voltages - DC voltage after being converted and filtered by the power supply - now I need is a method of data encoding that would be invariant to conversion and filtering, the original signal embedded in AC being present in some form within the converted DC signal.

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  • android ftp upload has stopped error

    - by Goxel Arp
    class Asenkron extends AsyncTask<String,Integer,Long> { @Override protected Long doInBackground(String... aurl) { FTPClient con=null; try ` { con = new FTPClient(); con.connect(aurl[0]); if (con.login(aurl[1], aurl[2])) { con.enterLocalPassiveMode(); // important! con.setFileType(http://FTP.BINARY_FILE_TYPE); FileInputStream in = new FileInputStream(new File(aurl[3])); boolean result = con.storeFile(aurl[3], in); in.close(); con.logout(); con.disconnect(); } } catch (Exception e) { Toast.makeText(getApplicationContext(), e.toString(), Toast.LENGTH_LONG).show(); } return null; } protected void onPostExecute(String result) {} } I AM USING THIS CLASS LIKE BELOW.THERE IS BUTTON AND WHENEVER I CLICK THE BUTTON IT SHOULD START FTP UPLOAD PROCESS IN BACKGROUND BUT I GET "PROGRAM HAS STOPPED UNFORTUNATELY" ERROR. Assume that The ftp address and username password pathfile sections are true and I get the internet and network permissions already by the way ... button1.setOnClickListener(new OnClickListener() { public void onClick(View arg0) { new Asenkron().execute("ftpaddress","username","pass","pathfileon telephone"); } }); And here is the logcat for you to analyse the potential error and help me ... 10-13 13:01:25.591: I/dalvikvm(633): threadid=3: reacting to signal 3 10-13 13:01:25.711: I/dalvikvm(633): Wrote stack traces to '/data/anr/traces.txt' 10-13 13:01:25.921: D/gralloc_goldfish(633): Emulator without GPU emulation detected. 10-13 13:01:31.441: W/dalvikvm(633): threadid=11: thread exiting with uncaught exception (group=0x409c01f8) 10-13 13:01:31.461: E/AndroidRuntime(633): FATAL EXCEPTION: AsyncTask #1 10-13 13:01:31.461: E/AndroidRuntime(633): java.lang.RuntimeException: An error occured while executing doInBackground() 10-13 13:01:31.461: E/AndroidRuntime(633): at android.os.AsyncTask$3.done(AsyncTask.java:278) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:273) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.FutureTask.setException(FutureTask.java:124) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:307) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.FutureTask.run(FutureTask.java:137) 10-13 13:01:31.461: E/AndroidRuntime(633): at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:208) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.lang.Thread.run(Thread.java:856) 10-13 13:01:31.461: E/AndroidRuntime(633): Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare() 10-13 13:01:31.461: E/AndroidRuntime(633): at android.os.Handler.<init>(Handler.java:121) 10-13 13:01:31.461: E/AndroidRuntime(633): at android.widget.Toast$TN.<init>(Toast.java:317) 10-13 13:01:31.461: E/AndroidRuntime(633): at android.widget.Toast.<init>(Toast.java:91) 10-13 13:01:31.461: E/AndroidRuntime(633): at android.widget.Toast.makeText(Toast.java:233) 10-13 13:01:31.461: E/AndroidRuntime(633): at com.example.ftpodak.ODAK$Asenkron.doInBackground(ODAK.java:74) 10-13 13:01:31.461: E/AndroidRuntime(633): at com.example.ftpodak.ODAK$Asenkron.doInBackground(ODAK.java:1) 10-13 13:01:31.461: E/AndroidRuntime(633): at android.os.AsyncTask$2.call(AsyncTask.java:264) 10-13 13:01:31.461: E/AndroidRuntime(633): at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305) 10-13 13:01:31.461: E/AndroidRuntime(633): ... 5 more By the way I changed the relevant code like that ; instead of catch (Exception e) { Toast.makeText(getApplicationContext(), e.toString(), Toast.LENGTH_LONG).show(); } I replaced with this code catch (Exception e) { HATA=e.toString(); } And I added the code to button textview1.setText(HATA); So I can see the error on the textview and it is writing that "Android java.net.UnknownHostException: Host is unresolved" But i know that the ftp server is correct and I check the ftp server from the AndFTP application. With the same address login and pass information ftp server is working.So the problem is in my code I think.Any help will be too much appreciated.Anyone who can help me I can give teamviewer to analyse what is the problem ...

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  • How can I force the server socket to re-accept a request from a client?

    - by Roman
    For those who does not want to read a long question here is a short version: A server has an opened socket for a client. The server gets a request to open a socket from the same client-IP and client-port. I want to fore the server not to refuse such a request but to close the old socket and open a new one. How can I do ti? And here is a long (original) question: I have the following situation. There is an established connection between a server and client. Then an external software (Bonjour) says to my client the it does not see the server in the local network. Well, client does nothing about that because of the following reasons: If Bonjour does not see the server it does not necessarily means that client cannot see the server. Even if the client trusts the Bonjour and close the socket it does not improve the situation ("to have no open socket" is worser that "to have a potentially bad socket"). So, client do nothing if server becomes invisible to Bonjour. But than the server re-appears in the Bonjour and Bonjour notify the client about that. In this situation the following situations are possible: The server reappears on a new IP address. So, the client needs to open a new socket to be able to communicate with the server. The server reappears on the old IP address. In this case we have two subcases: 2.1. The server was restarted (switched off and then switched on). So, it does not remember the old socket (which is still used by the client). So, client needs to close the old socket and open a new one (on the same server-IP address and the same server-port). 2.2. We had a temporal network problem and the server was running the whole time. So, the old socket is still available for the use. In this case the client does not really need to close the old socket and reopen a new one. But to simplify my life I decide to close and reopen the socket on the client side in any case (in spite on the fact that it is not really needed in the last described situation). But I can have problems with that solution. If I close the socket on the client side and than try to reopen a socket from the same client-IP and client-port, server will not accept the call for a new socket. The server will think that such a socket already exists. Can I write the server in such a way, that it does not refuse such calls. For example, if it (the server) sees that a client send a request for a socket from the same client-IP and client-port, it (server) close the available socket, associated with this client-IP and client-port and than it reopens a new socket.

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  • Conditional deserialization

    - by Yordan Pavlov
    I am still not sure whether the title of my question is correct and it most probably is not. However I have spent some time searching both the net and stackoverflow and I can not find a good description of the issue I am facing. Basically what I want to achieve is the ability to read some raw bytes and based on the value of some of them to interpret the rest in different ways. This is how TLV works in a way, you check the tag and depending on it - interpret the result. Of course I can always keep that logic in my C++ code, however I am looking for a solution which would move the logic out of the source code (maybe to some xml description). This would allow me to describe different encodings (protocols) more easily. I am familiar with Protocol Buffers and some other serialization libraries, however all of them solve different issue. They assume they are on both ends of the communication, while I want to describe the communication (sort of). Is such solution available, if no - why not? Are there some inherent difficulties I will face trying to implement it.

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  • Does all the network card use the same frequency to send signals to wire?

    - by smwikipedia
    Hi, I am comparing my cable TV wire to my network wire. In a TV cable wire, different frequencies are used by different TV channels. And since a certain channel use a fixed frequency, I think the only left way to represent different signal is with the carrier wave's amplitude. But what about the network wire? For all the network card with the same type, do they also use different frequencies to send signals just like TV cable? I vaguely remember that they use frequency adjustment to represent signals. So the frequency should not be a fixed one. So how did all the network cards that sharing the same medium differentiate their own signal from others?

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  • How to implement dual communication between server and client via http

    - by Alex Sebastiano
    I have a AJAX client which must receive messages from server. Some messages from server not like request-response type. For example, imaging game in which players can enter. Server must send to client info about player entering. But how can server send message to client via http without request from client? Only decision that i can invent: client send request to server (getNewPlayerEnter request) with big timeout, server checks state of player set, if in set new players are, then server send info to client, if not server 'sleeps' on some time, and after 'sleeping' server checks players set again. I think my desicion a little stupid(maybe not little). How implement it right? p.s. sorry for my english

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  • Local Network - Windows 7 and Vista can't see each other

    - by ca8msm
    I've got a strange issue at home that has been bugging me for weeks, but I really need to get it sorted now so I'll detail as much as I can and hopefully someone can spot what might might be wrong. I have a wireless router connected to the internet and 3 devices connected to it. They are: Name OS Network IPv4 PC1 Windows 7 WORKGROUP 192.168.2.2 LAPTOP1 Vista WORKGROUP 192.168.2.3 PS3 192.168.2.4 and they all get their IP addresses dynamically. Both PC1 and LAPTOP1 can ping PS3 and get a response. PC1 and LAPTOP1 are unable to ping each other by ip address unless I ping by their name (which bizarrely shows that it is pinging via the IPv6 address). Also, to confirm this both PC1 and LAPTOP1 can ping each other via the long IPv6 address that they both have so they can obviously see each other just not via IPv4. I've disabled the firewalls on both machines as well to rule that out. I don't really know what IPv6 is used for and I've tried disabling it on both machines but all that happens then is that neither machine can see each other at all then. Does anyone have any idea of what may be stopping them seeing each other, any ways I can look at fixing this, or any network tools that may help identify where it is failing? Thanks, Mark

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  • Mac: How to see list of running network services?

    - by Jordan
    I am writing an application that needs to connect with a running network service on a Mac. Problem is, I have no idea what the service is called or even what port it uses. Is there a way to browse all running network services on my Mac? More info: I am connecting to a MIDI network session (found under 'Audio MIDI settings', present on all OSX installs). Am I correct in thinking this is a network service? I am planning to use NSNetServiceBrowser to locate all local computers running this service. (is this the best way to go about it?) Any help is much appreciated - thanks!

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  • Is there any data missing?

    - by smwikipedia
    Hi experts, Here is some code quoted from Douglas.E.Comer's < Computer Networks and Internets 4th edition. This program will send back any data it received. ... while((len = recv(conn, buff, BUFFERSIZE,0)) >0) // receive data send(conn, buff, len, 0); // send it back ... I am wondering, what if some data arrived when the code is executing in send(..) function, will it miss that data? Because the recv() function is not being executed. If no data is missed, where is the data kept? And by whom? Thanks...

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  • Appropriate data structure for a buffer of the packets

    - by psihodelia
    How to implement a buffer of the packets where each packet is of the form: typedef struct{ int32 IP; //4-byte IP-address int16 ID; //unique sequence id }t_Packet; What should be the most appropriate data structure which: (1) allows to collect at least 8000 such packets (fast Insert and Delete operations) (2) allows very fast filtering using IP address, so that only packets with given IP will be selected (3) allows very fast find operation using ID as a key (4) allows very fast (2), then (3) within filtered results ? RAM size does matter, e.g. no huge lookup table is possible to use.

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  • How can I "interconnect" two sockets in Linux?

    - by Vi
    There are two connected sockets. How can I interconnect them? Data appeared on the one socket should be written to the other. EOF/FIN should propogate well. If one is half-closed, the other should also be half-closed. int client = get_connected_client_socket(); int proxy = get_connected_proxy_socket(); negotiate_with_proxy(proxy); iterconnect(client, proxy); // Now forgot about both client and proxy. // System should handle IO/shutdown/close. // Ideally even without any support of the user-space process. Can Linux do it? Can it be done by tricking connection tracking to change tracking status of existing connection? @related http://stackoverflow.com/questions/2673975/determine-how-much-can-i-write-into-a-filehandle-copying-data-from-one-fh-to-the

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  • How to make my Java Swing application a Client-Server application?

    - by Jonas
    I have made a Java Swing application. Now I would like to make it a Client-Server application. All clients should be notified when data on the server is changed, so I'm not looking for a Web Service. The Client-Server application will be run on a single LAN, it's a business application. The Server will contain a database, JavaDB. What technology and library is easiest to start with? Should I implement it from scratch using Sockets, or should I use Java RMI, or maybe JMS? Or are there other alternatives that are easier to start with? And is there any server library that I should use? Is Jetty an alternative?

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  • Why Fragmentation is Done at IP why not for TCP/UDP.

    - by mahesh
    I am looking for the reason Why Fragmentation is Done at IP level but why not for TCP/UDP. Suppose say my frame looks like this |MAC|IP|TCP|Payload|FCS. the whole size if say for eg: 1600. PathMTU happens here, why fragmentation is implemented @ IP level is my question and why not implemented @ TCP/UDP level/code. Thank in advance.

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  • Remote desktop get authentication dialog box not coming ?

    - by vineth
    hi, I have enabled remote desktop in my xp sp3 system, (My problem) if my friend take my system in remote with out my authentication my system is connected to him.but few day before i get authentication message(attached in the below link) but nowadays i am not receiving this dialog box... please provide help to get this authentication dialog box.. Link : http://www.freeimagehosting.net/image.php?f9f04c5e0a.jpg Thanks in advance

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  • TCP/IP RST being sent differently in different browsers.

    - by Brian
    On Mac OS X (10.6), if I start a YouTube video download and pull the Ethernet cable for 5 or so seconds, then plug it back in, I get varying results depending on the browser. With Opera and Chrome, after I plug the cable back in the video continues to load. But with Safari and Firefox, it never does. Using Wireshark to look at the traffic, I found that Opera and Chrome simply ACK the first packet from YouTube after the cable has been plugged back in, but Safari and Firefox set the RST flag (0x4) in the TCP header and no more traffic follows. I can put a HUB in between the machine and the internet connection, the problem goes away and all four browsers continue loading the video when the cable is plugged back into the HUB. Again, looking at the Wireshark logs, it's evident that the machine doesn't see the Mulitcast connection close and there is simply a delay in the packets flowing through. So it seems that if Safari and Firefox sees a Multicast connection close, and then later see data on that same connection, they will send a RST. My question is why? What is the correct course of action, and why are 2/4 browsers doing it one way, while the other 2/4 are doing it another way? Is there somewhere in the code that I can see where this is happening in Firefox, for instance? Thank you very much.

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  • Making a FTP connection in Android

    - by Elisha Khan
    i am working to make a Android application that can upload and download data from android phone to server using this link. As i am new to connection Android with server. is my local host works as a server to download and upload. i am using Uri ftpUri = Uri.parse("ftp://10.0.2.2"); But its not working help me to get out of this problem. I need your help just to sucessfullt connect to server, As i already said i aam new to connect Android Application to server. I am learning Programing myself and Internet is my teacher. Thank You Very Much

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  • UDP traffic effect on network performance

    - by user314536
    well, i have network that each proxy (lets assume we have 200 proxies), send UDP packages every constant amount of time. (let assume 10 seconds) to constant amount of hosts (lets assume 10) my question is how will 6 * 10 seconds * 200 proxies * 10 target hosts = 120,000 UDP roundtrip communication per minute will affect my network, in terms of available connections, speed, stability, UDP package loss rate etc... can anyone please refer me to some links on this issue ? thanks

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  • Does Socket open another thread? Does it return something?

    - by Roman
    In the client application I call new Socket(serverIP,serverPort). As a result the client application sends a request to the server application to open a socket. Does it start a new thread? I mean which of the following is true? Client application sends a request and immediately starts to execute following commands (not weighting for the answer). Client sends the request and weights for the answer. As soon as the answer is obtained, the client application continues to execute following commands. The second case seems to be more realistic and logical for me. However, I do not understand what happens if the server does not open a socket and it does not say that it does not "want" to open the second (it can happen if the server does not exist or network is broken). What will happen in this case? Will server weight forever? In general it would be nice for the client to know what is the result of its request for the socket. For example I can imagine the following situations: The socket is opened by the server. The server refuses to open a socket. So, server exists, it got the request from the client but it says "no". There is no response from the server. I know that new Socket(serverIP,serverPort) does not "return" this kind of information. But it throws exceptions. One of them is "UnkownHostException". When it is thrown? When the server is not responding for a while (for how long)? ADDED: I just found out that UnknownHostException is thrown to indicate that the IP address of a host could not be determined. So, it is unrelated with the above described situations (server is not responding, server refuses to open a socket).

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  • Can a MAC address be used as a reliable part of a rights management (DRM) scheme?

    - by Jarrod Mosen
    We're currently writing some software that we want to protect. We thought that registering a user's MAC address in a database upon activation of the software seemed viable; we can profile and grab that with a Java applet, (is there a better way?) so getting it isn't too much of a problem. However, we want their computer to only run the application, and download application files/updates from the server when their MAC address has been verified with their one on-file. We understand that this means a lockdown to one computer, but special changes can be made on request. What would be the best way to verify their MAC address, to see if it exists in the database, and then serve them the files to run the application? (And to simply run it on subsequent requests, to prevent re-downloading.)

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